Hello!
Begin by plugging in the values for m and n. We get the equation for the velocity of the particle to be:
[tex]v(t) = 10 + 2t^2[/tex]
A.
To find the change in velocity over the interval (2s ≤ t ≤ 5s), we can simply find the difference in the velocities at these times.
[tex]\Delta v= v_f - v_i[/tex]
For this situation:
[tex]\Delta v = v(5) - v(2)[/tex]
Substitute these times for 't' into the equation and solve.
[tex]v(5) = 10 + 2(5^2) = 60 \frac{cm}{s}\\\\v(2) = 10 + 2(2^2) = 18 \frac{cm}{s}\\\\\Delta v = 60 - 18 = \boxed{42 \frac{cm}{s}}[/tex]
B.
To find the average acceleration, we must take the SLOPE of the velocity function over this interval using the slope formula:
[tex]a_{avg} = \frac{v_f - v_i}{\Delta t}[/tex]
Plug in the values for the particle's velocity at t = 2 s and 5 s that we solved for above.
[tex]a_{avg} = \frac{60- 18}{5 - 2}\\\\a_{avg} = \frac{42}{3} = \boxed{ 14 \frac{cm}{s^2}}[/tex]
C.
The instantaneous acceleration can be found by taking the derivative of the v(t) function using the power rule. Recall:
[tex]\frac{dy}{dx} x^n = nx^{n-1}[/tex]
Using this rule:
[tex]a(t) = v'(t) = 2(2t) = 4t[/tex]
Substituting in t = 2 s:
[tex]a(2) = 4(2) = \boxed{8 \frac{cm}{s^2}}[/tex]
1. If the amplitude of a vibrating mass attached to the free end of an ideal spring is
25 cm, then the mass in one period travels 'a distance:
a) 1m
b) 0
c) 25m
The mass in one period travels 'a distance less than 25 cm which will be 0.
What is amplitude of a pendulum?
The amplitude of a pendulum is the maximum displacement of the pendulum.
If the maximum displacement of the pendulum is 25 cm, the mass in one period travels a distance less that 25 cm.
Thus, then the mass in one period travels 'a distance less than 25 cm which will be 0.
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In infrared satellite images, land appears _________ and clouds appear _________. A. red, yellow B. white, black C. black, white D. yellow, red
In infrared satellite images, land appears black and clouds appear white. C
What are infrared satellite images?Infrared satellite images are images produced as a result of electromagnetic radiations reflected or emitted from a target surface in the infrared position of the electromagnetic spectrum.
On infrared images, the clouds emit very bright white color because of the low temperature and the land appears to be black because of the hot temperature.
Therefore, in infrared satellite images, land appears black and clouds appear white. C
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You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, it accelerates because the engines are at full throttle and because there is a catapult that propels the jet forward. You begin to wonder how much force is supplied by the catapult. You look on the Web and find that the flight deck of an aircraft carrier is about 90.0 m long, that an F-14 has a mass of 24800 kg, that each of the two engines supplies 27000 lb of thrust, and that the takeoff speed of such a plane is about 158 mi/h. Estimate the average force on the jet due to the catapult.
You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, the average force on the jet is due to the catapult is mathematically given as
What is the average force on the jet is due to the catapult?
Generally, the equation for acceleration is mathematically given as
[tex]a=\frac{vf^2-vi^2}{2s}\\\\\Therefore\\\\a=\frac{69.29^2-0^2}{2(90}\\\\a=26.673m/s^2[/tex]
In conclusion, The force
F=m*a
F=15100*26.673
F=40272.3N
F 402 KN
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Given the following specific heat capacities, which material was have the largest change in temperature if 10 grams of each substance absorbs 100 calories of heat?
Substance Heat Capacity - Cal / (g oC)
aluminum 0.22
copper 0.093
lead 0.0305
silver 0.056
Answer:
Explanation:
Comment
You could calculate it out by assuming the same starting temperature for each substance. (You have to assume that the substances do start at the same temperature anyway).
That's like shooting 12 with 2 dice. It can be done, but aiming for a more common number is a better idea.
Same with this question.
You should just develop a rule. The rule will look like this
The greater the heat capacity the (higher or lower) the change in temperature.
The greater the heat capacity the lower the change in temperature
That's not your question. You want to know which substance will have the greatest temperature change given their heat capacities.
Answer
lead. It has the smallest heat capacity and therefore it's temperature change will be the greatest.
Find the relationship
[tex]\\ \rm\Rrightarrow Q=mc\Delta T[/tex]
[tex]\\ \rm\Rrightarrow 100=10c\Delta T[/tex]
[tex]\\ \rm\Rrightarrow 10=c\Delta T[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{10}{c}=\Delta T[/tex]
[tex]\\ \rm\Rrightarrow \Delta T\propto \dfrac{1}{c}[/tex]
So lower the c higher ∆T
Lead has the largest change in T as it has least capacity
In the following word completion task: carrot, peas, corn, b_____, most people would answer “beans” (instead of “beetle” for example) even though there were no instructions on how to do this task. The psychological reason we made the assumption that the blank word was related to the previous words is due to
Answer:
Explanation:
Wow, I said 'beets'..... I must be weird.
Where is the body or mass in the water when the buoyant force is equal to the weight of the mass? Does it float up, or down or in the middle?
Answer:
it will float
Explanation:
according to Archimedes' principle, if the buoyant force is equal to the weight of the mass of the object, the object will float
What is the magnetic force on a proton that is moving at 5.2 x 107 m/s to the
right through a magnetic field that is 1.4 T and pointing away from you? The
charge on a proton is 1.6 × 10-19 C. Use F = qvx B sin(e)
Hello!
We can use the following equation for magnetic force on a charged particle:
[tex]F_B = qv \times B[/tex]
[tex]F_B[/tex] = Magnetic force (N)
q = Charge of particle (1.6 × 10⁻¹⁹ C)
v = velocity of particle (5.2 × 10⁷ m/s)
B = Magnetic field strength (1.4 T)
This is a cross-product, so the equation can be rewritten to F = qvBsinφ where φ is the angle between the magnetic field and particle velocity vectors.
Since the proton's velocity vector and the magnetic field vector are perpendicular, sin(90) = 1. We can reduce the equation to:
[tex]F_B = qvB[/tex]
Plug in the known values.
[tex]F_B = (1.6*10^{-19})(5.2*10^7)(1.4) = \boxed{1.1648 *10^{-11} N}[/tex]
The flux through the coils of a solenoid changes from 2.57.10-5 Wb to 9.44.10-5 Wb in 0.0154 s. If 4.08 V of EMF is generated, how many loops does the solenoid have? (No unit)
Hello!
We can use Faraday's Law of Electromagnetic Induction to solve.
[tex]\epsilon = -N \frac{d\Phi_B}{dt}[/tex]
ε = Induced emf (4.08 V)
N = Number of loops (?)
[tex]\Phi_B[/tex] = Magnetic Flux (Wb)
t = time (s)
**Note: The negative sign can be disregarded for this situation. The sign simply shows how the induced emf OPPOSES the current.
Now, we know that [tex]\frac{d\Phi_B}{dt}[/tex] is analogous to the change in magnetic flux over change in time, or [tex]\frac{\Delta \Phi_B}{\Delta t}[/tex], so:
[tex]\epsilon = N \frac{\Delta \Phi_B}{\Delta t}\\\\\epsilon = N \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}[/tex]
Rearrange the equation to solve for 'N'.
[tex]N = \frac{\epsilon}{ \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}}[/tex]
Plug in the given values to solve.
[tex]N = \frac{4.08}{ \frac{9.44*10^{-5} - 2.57*10^{-5}}{0.0154}} = 914.585 = \boxed{915 \text{ coils}}[/tex]
**Rounding up because we cannot have a part of a loop.
A uniform electric field exist between two parallel plate seperated by 1.2 cm. The intensity of the field is 23 KN/C. What is the potential difference between the plates
Explanation:
this is the answer 276 volts
A diver shines a light up to the surface of a flat glass-bottomed boat at an angle of 37◦ relative to the normal. If the indices of refraction of air, water, and glass are 1.0, 1.33, and 1.4 respectively, at what angle does the light leave the glass (relative to its normal)? Answer in units of ◦ .
Answer:
Approximately [tex]53^{\circ}[/tex], assuming that the upper and lower surfaces of the glass on this boat are parallel.
Explanation:
Assume that the upper and lower surfaces of the glass at the bottom of this ship are parallel. Refer to the diagram attached. The two normals would also be parallel to each other.
The following angles would be alternate interior angles between the two normals:
The angle at which the light enters the glass, andThe angle at which the light leaves the glass.Since the two normals are parallel to each other, these two angles would have the same value. Let [tex]\theta_{\text{glass}}[/tex] denote the value of both of these angles.
Let [tex]\theta_{\text{src}}[/tex] denotes the angle at which a beam of light leaves the original medium (angle of incidence.) Let [tex]\theta_{\text{dst}}[/tex] denote the angle at which this beam of light enters the new medium.
Let [tex]n_\text{src}[/tex] and [tex]n_\text{dst}[/tex] denote the refractive indices of the original and the new medium, respectively. By Snell's Law:
[tex]\begin{aligned}\frac{\sin(\theta_{\text{dst}})}{\sin(\theta_{\text{src}})} = \frac{n_{\text{src}}}{n_{\text{dst}}}\end{aligned}[/tex].
Let [tex]\theta_{\text{water}}[/tex] denote the angle at which the beam of light in this question leaves the water. Let [tex]\theta_{\text{air}}[/tex] denote the angle at which this beam of light enters the air. It is given that [tex]\theta_{\text{water}} = 37^{\circ}[/tex], while [tex]\theta_{\text{air}}[/tex] is the value that needs to be found.
Let [tex]n_{\text{air}}[/tex], [tex]n_{\text{water}}[/tex], and [tex]n_{\text{glass}}[/tex] denote the refractive index of air, water, and glass, respectively. By Snell's Law:
[tex]\begin{aligned}\frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})} = \frac{n_{\text{water}}}{n_{\text{glass}}}\end{aligned}[/tex].
[tex]\begin{aligned}\frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} = \frac{n_{\text{glass}}}{n_{\text{air}}}\end{aligned}[/tex].
Thus:
[tex]\begin{aligned} & \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})}\times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} \\ =\; & \frac{n_{\text{water}}}{n_{\text{glass}}}\times \frac{n_{\text{glass}}}{n_{\text{air}}} \\ =\; & \frac{n_{\text{water}}}{n_{\text{air}}}\end{aligned}[/tex].
Since [tex]\theta_{\text{water}} = 37^{\circ}[/tex]:
[tex]\begin{aligned} & \sin(\theta_{\text{air}})\\ =\; & \sin(\theta_{\text{water}}) \times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \sin(\theta_{\text{water}})\times \frac{n_{\text{water}}}{n_{\text{air}}} \\ =\; & \sin(37^{\circ}) \times \frac{1.33}{1.0} \\ \approx \; & 0.800 \end{aligned}[/tex].
Therefore:
[tex]\begin{aligned}\theta_{\text{air}} &= \arcsin(\sin(\theta_{\text{air}})) \\ & \approx \arcsin(0.800) \\ &\approx 53^{\circ} \end{aligned}[/tex].
In other words, this beam of light would leave the glass at approximately [tex]53^{\cic}[/tex] from the normal.
Why is it important to remember "association, not
causation" when discussing correlations?
It is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.
What is the value of associations in science?The associations among variables have a fundamental value in science because they can determine how such variables behave in hypothetical situations.
Moreover, correlation only indicates a type of association between variables and therefore it is less informative.
In conclusion, it is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.
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Please help me!!
1. For objects like insulators (plastics), they can get charged by ___.
2. For metals, where there are more loosely bound electrons, they can get charged without contact by ___.
3. For metals, they can also be charged by direct contact by ___.
A car headed north at 15.0 m/s experiences an acceleration of 2.50 m/s2 for 3.00 s. What is the final velocity of the car?
Answer:
i dond no can you put another question
You turn on a cars radio, what energy transformation is taking place?
Answer:
C probably
Explanation:
think c because when you first start the car the first thing you hear electrical sound.
a highway curve has a radius of 300 m. at what angle should it be banked for a traffic speed of 100 km/h
The angle at which it should be banked for a traffic speed of 100 km/h is
14.57°.
How do find the angle of Banking of road?Banking of roads is the practice of raising the outer borders of curving roads over the inner edge in order to give vehicles the necessary centripetal force to make a turn safely.Skidding can be prevented by banking.The banking of roadways aids in preventing toppling or overturning.To find the angle of banking following formula can be used,
[tex]tan \alpha = v^{2} /rg[/tex]
Given v = 100km/h or
= 100 x 1000 / 3600
= 27.7 m/s
Hence,
[tex]tan \alpha = (27.7)^{2} / 300 * 9.81[/tex]
[tex]tan\alpha = 0.26[/tex]
[tex]\alpha = tan^{-1} 0.26[/tex]
[tex]\alpha = 14.57[/tex]°
Hence, the angle of banking of the road will be 14.57°
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If a cup of coffee is at 90°C and a person with a body temperature of 36°C touches it, how will heat flow between
them?
O from the hand to the cup
from the cup to the hand
from the cup to the surrounding air
from the hand to surrounding air
Mark this and return
Save and Exit
ext
Submit
Answer:
if you pick it up the heat will flow to the hand until the Temperature of both evens out
A 2.0-V battery is connected in a circuit with an ammeter and an unknown resistor, P. The current is observed to be 0.70 A. What would be the current in the circuit if a 12-V battery replaces the 2.0-V battery?
Answer:
4.2 A
Explanation:
V=IR
V= voltage
I= Current
R= resistance
so you will find the resistance in the circuit so
R= V/I
R=2V/0.70A
R=2.857 ohms ( TO THE NEAREST THOUSANDTH)
then you will find the current of the 12V battery using the resistance in the circuit
I=V/R
I=12/2.857
I=4.2A (TO THE NEAREST TENTH)
An appliance draws 3 amperes at 120 V (plugged into the wall). If the same appliance is run with a 12 V car battery, how many amperes will it need?
The appliance is run with a 12 V car battery and the value of the electric current will be 0.3A.
What is electric current?The pace at which electrons travel through a conductor is known as electric current. The ampere is the SI unit for electric current.
From ohm's law;
Case 1;
V=IR
120 V = 3 A × R
R = 40 ohm
For the same appliances, the value of the resistance is the same;
Case 2;
V=IR
12 V = I × 40 ohm
I = 0.3 A
Hence the value of the current for case 2 will be 0.3 A.
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Joe runs 10 m north, 20 m south, 9m south, and then 15 m north. What is Joe's
displacement?
Answer:
Joes displacement is 54m
Select the correct answer.
What is the average velocity of the particle from rest to 9 seconds?
The average velocity of the particle from rest to 9 seconds would be 2 meters/sec.
How to find the average velocity?This average velocity can be calculated with the following equation:
v = dx / dt
where:
dx = displacement = 18 meters
dt = interval of time = 9 seconds
Substitute;
v = dx / dt
v = 18 / 9
v = 2 meters/sec
Hence, the average velocity of the particle from rest to 9 seconds would be 2 meters/sec.
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The high point of the ripple seen in a pond after throwing in a pebble is the...
Select one:
a. crest.
b. trough.
c. wavelength.
d. A & B
The crest is the highest point of a pebble-induced ripple in a body of water. Option a is correct.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength. The highest point of the wave is the crest, while the trough is the lowest.
The high point of the ripple seen in a pond after throwing in a pebble is the crest.
Hence option a is correct.
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A stone is dropped from the top of a tower which touches the ground after 2 seconds. Calculate the speed of the stone hitting the ground surface. (g = 9.8 m/s²)
Answer:
19.6 m/s
Explanation:
The velocity is the product of acceleration and time.
__
Here, the acceleration is due to gravity.
v = at
v = (9.8 m/s²)(2 s) = 19.6 m/s
The stone hits the ground with a speed of 19.6 m/s.
A stone is dropped from the top of a tower which touches the ground after 2 seconds.
Calculate the speed of the stone hitting the ground surface. (g = 9.8 m/s²).[tex] \mathbb{SOLUTION:} [/tex][tex]v = u + at[/tex][tex]v = 9.8 m/s² x 2sec[/tex][tex]v = 19.6 \: m/ {s}^{2} [/tex]••••••••••••••••••••••••••••••••••••••••••••Hence, The stone hit the ground with the velocity speed of 19m/s².
- When you're solving velocity, you're determining how fast an object moves from its original position, with respect to a frame of reference, and a function of time.
- That means an object's velocity will be equal to the object's speed and direction of motion.
"Problem has been solve"
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What is the magnitude of the force exerted on an electron in an electric field with a strength of 6.5 *10^ 8 N/C? Remember, the charge on an electron is 1.6 * 10 ^ - 19 * C
All work must be shown to earn credit
The field exerts 6.5 x 10⁸ Newton of force on EACH COULOMB of charge in the field.
We're putting 1.6 x 10⁻¹⁹ Coulomb of charge into the field.
The force on it will be
(1.6 x 10⁻¹⁹ Coulomb) x (6.5 x 10⁻⁸ Newton/Coulomb).
That's 1.04 x 10⁻¹⁰ Newton.
An arrow is shot horizontally from the top of a building and it lands 200m from the foot of the building after 10s.Assuming air resistance is negligible,calculate the initial velocity of the arrow and the height of the building?
Need an answer urgently please
The initial velocity of the arrow and the height of the building will be 29.05 m/s² and 781 m respectively.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is;
u is the initial velocity of fall = ? m/sec
h is the distance of fall = 200 m
g is the acceleration of free fall = 9.81 m/sec²
H is the height of the building
t is the time period = 10 second
According to Newton's second equation of motion,
[tex]\rm h= ut+\frac{1}{2} gt^2 \\\\\ h-\frac{1}{2} gt^2 =ut \\\\ 200 - 0.5 \times(9.81) \times 10^2 = 10 u \\\\ u = - 29.05 \ m/sec[/tex]
- ve shows the direction is downward.The magnitude of the initial velocity is found as;
u = 29.05 m/sec
The height of the building
[tex]\rm H= ut+\frac{1}{2} gt^2 \\\\\ H = 29.05 \times 10 + 0.5 \times 9.81 \times 10^2 \\\\ H = 781 \ m[/tex]
Hence the initial velocity of the arrow and the height of the building will be 29.05 m/s² and 781 m respectively.
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Consider an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.
1.What is the electric flux through the cylinder due to this infinite line of charge?
2.What is the flux through the cylinder if its radius is increased to r= 0.600 m ?
3.What is the flux through the cylinder if its length is increased to l= 0.990 m ?
The electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C
Given an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.
Solve for the electric flux through the cylinder due to this infinte line:
As below equation mentions, the electric flux for a uniform electric filed is given by:
Фₓ = EA cosΦ
Φₓ = λLcosΦ)/ε
Φₓ = (3 x 10^(-6) x 0.4 x cos0)/(8.854 x 10^(-12))
Φₓ = 1.355 x 10^(5) Nm²/C
Hence the electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C
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Injuries occur from muscle imbalances which result from the body's inability to ....................... these types of stress.
Answer:
Tolerate
Explanation:
5, the following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
The average velocity is 4i m/sec
The average acceleration is 4i
What is a average velocity ?Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs. T
According to the question,
x=at²i + btj ( t is in second and x is in meter).
Average velocity = [tex]\frac{dx}{dt}[/tex]
[tex]\frac{dx}{dt} = 2at i + b j\\\\\frac{dx}{dt} = 2 * 2 * t i +1 j\\\\\frac{dx}{dt} = 4t i +j[/tex]
[tex]\frac{dx}{dt}[/tex] in the time interval of 2 to 3 sec is
at 2 sec,
[tex]\frac{dx}{dt} = 4 * 2 i +j = 8i +j[/tex]
at 3 sec ,
[tex]\frac{dx}{dt}[/tex] = 4 * 3 i + j = 12i+j
Therefore the average velocity is
[tex]\frac{(12i +j - 8i -j)}{(3-2)} = 4i[/tex]
The velocity at any given time is [tex]\frac{dx}{dt} = 4t i +j[/tex]
The acceleration at any given time is [tex]\frac{dx^2}{dt^2}[/tex]
[tex]\frac{dx^2}{dt^2} = 4 i[/tex]
The average acceleration in the time interval t₁=2sec and t₂=3sec
Average Acceleration = 4i
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Which of the following can be contracted from contact with bloodborne pathogens?
HIV can be contracted from contact with bloodborne pathogens.
Other bloodborne diseases are HBV, malaria, syphilis and brucellosis
What are bloodborne pathogens?Bloodborne pathogens can be defined as those microorganisms or pathogenic organisms that cause disease and are present in human blood.
Blood borne pathogens can also be contacted through the following means
Se- xual contactNeedle contactIn conclusion; HIV can be contracted from contact with bloodborne pathogens.
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6. A metal block increases in temperature from 15 °C to 60 °C when supplied with 13 500 J of heat energy.
a) Calculate the heat capacity of the metal.
b) Calculate the specific heat capacity of the metal, if this sample has a mass of 0.75 kg.
Answer:
Since 1 cal = 4.19 J the heat Q received by the metal is
Q = 13,500 J * 1 C / 4.19 J = 3,222 calories
S = ΔQ / (ΔT * ΔM) = 3222 cal / (45 deg C / 750 gm)
S = .095 cal / gm deg C
Note that specific heat capacity for Cu is .093 cal / gm deg C
A spoon inserted in a half-filled cup of water appears crooked because as light travels into a substance with a lower index of refraction, it... Select one: a. does not bend. b. bends away from the normal. c. bends toward the normal. d. is reflected.
Explanation:
The light is bent away from the normal
