d. radar imaging by the Magellan spacecraft
The surface features of venus were mapped with radar imaging by the Magellan spacecraft.
What was used to map Venus's surface features?Radar was used to scan the scorching surface by NASA's Magellan probe, which completed a five-year mission to Venus in 1994. Magellan observed a region with intense volcanism. The orbiter observed a surface that was geologically speaking quite young, recently altered, and dotted with long chains of high mountains.
What person or thareg is the names of the features on Venus' surface?Venus has "paterae," or craters and volcanic calderas, that are named after notable, real women. All of Venus' features—there are just three exceptions—have female names. They are Maxwell Montes, Alpha Regio, and Beta Regio, named for the early radar pioneer James Maxwell.
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Which type of energy is transferred between the two objects due to the temperature difference between them?
The type of energy transferred between the two objects due to the temperature difference between them is known as heat energy.
The heat energy transfers from the object at higher temperature to the object at lower temperature.
The exchange of thermal energy between two objects is referred to as heat. The amount of thermal energy a thing possesses may be determined by its temperature; the higher the temperature, the faster the molecules inside the object move. The transfer of heat therefore occurs from the item at higher temperature to the object at lower temperature because an object at higher temperature has more thermal energy than an object at lower temperature.
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a car is safely negotiating an unbanked circular turn at a speed of 26 m/s. the road is dry, and the maximum static frictional force acts on the tires. suddenly a long wet patch in the road decreases the maximum static frictional force to one-fourth of its dry-road value. if the car is to continue safely around the curve, to what speed must the driver slow the car?
The speed of the car must be reduced to 13 m/sec to continue safely around the curve. if the value of maximum static friction constant reduced to 1/4th of the original value on the dry road.
The speed of the car, v = 26 m/s
Mass of the car =m
Radius of the curve = R
Coefficient of static frictional = μ
μ×mg = mv²/R
v² = μgR
v = √(μgR) = 26 m/s
If the static friction constant reduced to 1/4th of the original value, then
μ₁ = μ/4
v₁ = √(μ₁gR)
v₁ = √(μ/4×gR)
v₁ = 1/2×√(μgR)
v₁ = 1/2 × v
v₁ = 1/2 × 26 = 13 m/s
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Look at the equation below. What does
the u represent?
a=V-U/t
U is represent is Speed .
What is Speed?
Measuring is the most important scientific concept. Many different types of quantifiable quantities can be measured using base or physical fundamental units. One such quantifiable quantity is speed, which computes the proportion of a moving object's distance travelled to its travel time. In this session, let's examine speed in further detail. An object is considered to be moving at uniform speed if it covers the same distance in the same period of time.
An object is considered to be moving at variable speed when it covers a varying distance at regular intervals of time.
Typical speed: The consistent speed determined by the ratio of the overall distance travelled by an object to the total amount of time it takes to go is known as average speed.
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A sample of neon effuses from a container in 74 seconds. The same amount of an unknown noble gas requires 151 seconds.(a) Identify the gas.
The unknown noble gas is argon. Argon is the third most abundant gas in Earth's atmosphere, making up around 0.94% of the total atmosphere.
It is also the most abundant noble gas, making up around 1.3% of the atmosphere. Argon is an odorless, colorless, and tasteless gas that is slightly heavier than air.
It is nontoxic and nonflammable. Argon has a low thermal conductivity, so it is often used as an inert gas shield in welding and other high-temperature processes. In this case, it took 151 seconds for the same amount of argon to effuse from the container, compared to 74 seconds for neon.
This indicates that argon has a much lower effusion rate than neon and is therefore a different gas.
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suppose you throw a ball against a wall and catch it on the rebound. how many impulses were applied to the ball? which impulse was the greatest?
Answer: <3
Explanation: ):
Suppose the distance from the lens system of the eye (cornea + lens) to the retina is 16 mm.
(a) What must the power of the lens be when looking at distant objects?
(b) What must the power of the lens be when looking at an object 18.2 cm from the eye?
(c) Suppose that the eye is farsighted; the person cannot see clearly objects that are closer than 1.0 m. Find the power of the contact lens you would prescribe so that objects as close as 18.2 cm can be seen clearly.
The power of the lens be when looking at distant objects are found to be +62.5 D and + 0.67D
What is the lens's power?The power of a lens is its capacity to cause the light rays falling on it to converge or diverge. The reciprocal of a lens's focal length is the lens's power. The SI power unit is the dioptre (D).
focal length = 16mm
power of lens = 1/f => 1/16 x 10^-3
=> +62.5 D
object distance = u = -18.2 cm
image distance = v = 16mm = 1.6cm
1/f = 1/v - 1/u
=> 1/f = 1/1.6 + 1/18.2
=> Power = 1/f => + 0.67D
What does a lens' focal length mean?When a lens is focused to infinity, its focal length can be calculated. The focal length of the lens indicates the amount of the scene that will be captured from an angle of view as well as the size of individual elements under magnification. The angle of view is narrower and the magnification is higher the longer the focal length.
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a 60 kg person drives a 2000 kg car at 100 km/h over the top of a hill that has a radius of curvature of 100 m. find the normal force that the seat exerts on the person in the car as it tops the hill.
The normal force that the seat exerts on the person in the car is approximately 206000 N.
What do you mean by force?An interaction between objects is referred to as a force. It is called an interaction because when one object acts on another, the other object responds in kind.
To find the normal force that the seat exerts on the person in the car as it tops the hill, we can use the formula for centripetal force:
F = m * a, where F is the force, m is the mass, and a is the centripetal acceleration.
The centripetal acceleration is given by the formula: a = v² / r, where v is the velocity and r is the radius of curvature of the hill.
Plugging in the given values, we get:
a = (100,000 m/h)² / 100 m = 10^8 m/s²
To find the normal force, we need to use the weight of person and the car as the mass and the centripetal acceleration we just calculated.
F = (60 kg + 2000 kg) * 10^8 m/s²
F = 2.06 * 10^5 N or 206000 N
So, the normal force that the seat exerts on the person in the car is approximately 206000 N.
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An aerobatic airplane pilot experiences
weightlessness as she passes over the top of
a loop-the-loop maneuver.
The acceleration of gravity is 9.8 m/s^2.
If her speed is 450 m/s at this time, find the radius of the loop.
Answer in units of km.
Two cars each have a mass of 1050 kg. if the gravitational force between
them is 2.27 x 10-7n, how far apart are they? g = 6.67 x 10-11 n. (m/kg)2
The distance between the two cars each have the distance of 1050 kg is 17.99 x 10⁴ m
The mass of two cars = 1050 kg
The gravitational force between the two cars = 2.27 x 10⁻⁷ N
The distance between the two cars can be found using the formula,
F = g m₁m₂/r²
where F is the gravitational force
g is the gravitational constant
m₁,m₂ is the masses of the two cars
r is the distance between the two cars
Let us rearrange the above equation,
r² = g m₁m₂/F
Let us substitute the known values in the above equation, we get
r² = 6.67 x 10⁻¹¹ x 1050 x 1050 / 2.27 x 10⁻⁷
= 7353675 x 10⁻¹¹ / 2.27 x 10⁻⁷
= 3239504.41 x 10⁴
r = √3239504.41 x 10⁴
= 1799.86233 x 10²
= 17.99 x 10⁴ m
Therefore, the distance between the two cars is 17.99 x 10⁴ m
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A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. what is the tangential acceleration of a point on the edge of the wheel?
The tangential acceleration of a point on the edge of the wheel is calculated to be 2.1 m/s².
By definition, the angular acceleration, is equal to the rate of change of the angular velocity, ω:
α = Δω / Δt ----(1)
The linear velocity, v, can be expressed as follows using the definition of the angular velocity,
v = ω × r
⇒ Δv = Δω × r ----(2)
Putting Δω, in place of (1) in (2) gives us,
Δv = α × Δt × r
⇒ Δv/Δt = α × r ----(3)
Expression of linear acceleration, can be written as,
a = α × r
For a point on the edge of the wheel, the linear acceleration is tangent to the rim, and is equal to the product of the angular acceleration times the distance to the centre, which for a point on the edge of the wheel, is just the radius,
⇒ a = 7 rad/sec² × 0.3 m = 2.1 m/s²
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if a ring particle survived for the age of the solar system, how many collisions would it undergo, given that each ring particle in the densest part of Saturn's rings collides with another about every 5 hours?
If a ring particle survived for the age of the solar system, the collisions would it undergo, given that each ring particle in the densest part of Saturn's rings collides with another about every 5 hours is 4.03 x 10¹³.
The solar system can be defined as the system including the Sun and all other objects that are gravitationally connected to the Sun. All the solar system objects rotate in the identical direction about the Sun. There are many planetary systems like ours in the universe, with planets orbiting a host star. Our planetary system is named the "solar" system because our Sun is named Sol, after the Latin word for Sun, "solar," and anything related to the Sun we call "solar." by this primary information, we can firmly conclude that if a ring particle survived for the age of the solar system, the collisions would it undergo, given that each ring particle in the densest part of Saturn's rings collides with another about every 5 hours is 4.03 x 10¹³.
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of the charge q initially on a tiny sphere, a por tion q is to be transferred to a second, nearby sphere. both spheres can be treated as particles and are fixed with a certain separation. for what value of q/q will the electrostatic force between the two spheres be maximized?
The value of q/Q for which the electrostatic force between the two spheres will be maximized is 0.5 .
What is called electrostatics?Electrostatics is a branch of physics that deals with the phenomena and properties of stationary or slow-moving electric charges. Electrostatic phenomena arise from the forces that electric charges exert on each other and are described by Coulomb's law.
What is electrostatic charge?Electrostatic charges. Static electricity or an electrostatic charge is a deficiency or excess of electrons which occurs on ungrounded or insulating surfaces. It is produced by triboelectric charges, charges that are generated by friction between two surfaces, such as the movement of paper through a copier or printer
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The density of a liquid can be determined by weighing a known volume of the liquid in a graduated cylinder. The data from the experiment is as follows: weight of cylinder 10 grams; weight of cylinder and liquid 11.8 grams; reading from cylinder 7.5 mL. Calculate the density of this liquid using the
The density of the liquid is 0.24 g/mL or 240 kg/m³. The density of a liquid can be determined by weighing a known volume of the liquid in a graduated cylinder
What is the density of the liquid?The density of a substance is a measurement of its mass per unit volume. Density is commonly expressed in terms of grammes per millilitre (g/mL) or kilogrammes per litre (kg/L) for liquids. Although conditions like temperature and pressure can affect a liquid's density, it is typically thought of as a constant feature of a substance. For the same volume, a liquid with a higher density will weigh more than a liquid with a lower density.
To calculate the density of the liquid, use the formula: density = mass/volume.
Mass of liquid = 11.8 g - 10 g = 1.8 g
Volume of liquid = 7.5 mL
So, density = 1.8 g / 7.5 mL = 0.24 g/mL or 240 kg/m³
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002 10.0 points
A figure skater begins spinning counterclockwise at an angular speed of 4.0 π rad/s. During a 4.4 s interval, she slowly pulls her arms inward and finally spins at 7.8 T rad/s. What is her average angular acceleration
during this time interval?
Answer in units of rad/s².
Answer:
0.86 rad/s² counterclockwise
Explanation:
Average angular acceleration is change in angular velocity over time.
α = (ω − ω₀) / t
α = (7.8π rad/s − 4.0π rad/s) / 4.4 s
α = (3.8π / 4.4) rad/s²
α = 0.86 rad/s²
A car drives over the top of a hill that has a radius of 50 m. What maximum speed can the car have at the top without flying off the road?
The centripetal acceleration is given by the formula: a = v^2 / r
where v is the speed of the car and r is the radius of the hill.
To calculate the maximum speed: v = sqrt(rgµ)
where g is the acceleration due to gravity (9.8 m/s^2) and µ is coefficient of friction.
v = (50 x 9.8 x 0.7) = 37.9 m/s or 135.8 km/h
What is centripetal acceleration?Centripetal acceleration also known as radial acceleration is the acceleration indicated towards the centre of any curved path and perpendicular to the velocity of the object. It causes an object to change its direction but doesn't alter its speed along a circular pathway.
Does speed change in centripetal force?The force can definitely accelerate the object but it cannot alter its speed. Whenever the unbalanced centripetal force acts perpendicular to the direction of motion, the speed of the object will remain constant.
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a 10cm×10cm×10cm wood block with a density of 720 kg/m3 floats in water.
PART A
What is the distance from the top of the block to the water if the water is fresh?
PART B
If it's seawater? Suppose that rho=1030kg/m3.
The distance from the top of the block to the water will be 3.6 cm, which is the volume displaced by the block divided by the area of the top of the block, which is 10cm x 10cm.
What is distance?Distance is a numerical measurement of how far apart two objects, places, or points are in space. It is often measured in units like kilometers, miles, meters, or feet. Distance can also be conceptualized in terms of time, as in the distance between two points in time.
PART A
If the water is fresh, the distance from the top of the block to the water is 3.6cm. This is because the block's density is 720 kg/m3, while the density of fresh water is 1000 kg/m3. Therefore, the block is lighter than the water and will float. The block will displace a volume of 1000 kg/m3, which is equal to 10 cm3. Thus, the distance from the top of the block to the water will be 3.6 cm, which is the volume displaced by the block divided by the area of the top of the block, which is 10cm x 10cm.
PART B
If the water is seawater, the distance from the top of the block to the water is 2.7cm. This is because the block's density is still 720 kg/m3, while the density of seawater is 1030 kg/m3. Therefore, the block is still lighter than the water and will still float. The block will displace a volume of 1030 kg/m3, which is equal to 10.3 cm3. Thus, the distance from the top of the block to the water will be 2.7 cm, which is the volume displaced by the block divided by the area of the top of the block, which is 10cm x 10cm.
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7 The diagram shows a beam lying on the ground. End Q is lifted from the ground by the force F.
End P of the beam remains on the ground.
The length of the beam is 3.0m and its weight is 600 N.
The centre of mass of the beam at G is 1.0 m from end P.
What is the size of the force F when it just raises end Q from the ground?
A 200 N
B 300 N
C 400 N
D 600N
With solution.
When the beam just raises end Q from the ground, the magnitude of force F will be 300 N.
What is center of mass?The unique location where the weighted relative position of the distributed mass adds to zero at any given time is known as the center of mass in physics.
At equilibrium, net torque = 0
Take forces acting anti-clockwise direction as positive:
so, - 600 N × (1.0 m) + F ×(2.0 m) = 0
F = 600 N × (1.0m ÷ 2.0 m)
F = 300 N.
Hence, when it just raises end Q from the ground, the magnitude of force F will be 300 N.
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A police officer parked at the curb turns on his lights and siren, waits for traffic to clear, then pulls out and heads down the street. for an observer down the street, which is true?
a. the frequency of the siren is higher and the wavelength is shorter than it was at first.
b. the wavelength of the siren is shorter than it was at first, but the frequency is the same.
c. the wavelength of the siren is shorter and the frequency is lower than it was at first.
d. the frequency of the siren is higher than it was at first, but the wavelength is the same.
If a police officer is indeed parked near the curb, they can inspect it with the red light without risking damaging their night vision. waits for the traffic to clear before pulling out and moving down the road.
Can police run red lights without cause?
No, although they could if they were contacted in an emergency. For instance, it would be illegal for a police officer to switch on their lights and siren only to pass a red light if they were stuck in traffic behind a lot of automobiles and were impatient.
What do police lights that are not flashing mean?
"Police officers will turn this on while they are at a situation that is not particularly busy. Without the extra flash patterns and needless attention, this signals the presence of law enforcement. This is a common occurrence in densely populated areas
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a 2.00 c charge moves from a 50.0 v equipotential line to a 40.0 v equipotential line. what is the change in the electric potential energy of the charge field system?
The charge field system's electric potential energy changed by 20J.
What is the most accurate way to define potential energy?Potential energy's definition is quite simple: It is a type of energy that can exert force on other objects but is not now exerting any force on them. In other words, available energy concerns object positions rather than object motion.
What are five examples of potential energy?Potential energy can be transformed into kinetic energy by being stored. Potential energy can take on a variety of shapes, such as gravitational, magnetic, electrical, molecular, and elastic potential energy.
Change in electric potential energy
= charge x potential difference
= 2 x ( 50 - 40)
= 20 J
Potential will be decreased by this amount.
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Newtonís third law states that for every action, there is a reaction. Which of the following accurately restates this law?
A.If object A exerts a force on object B, then object B always exerts a force back on A. The object with the greater mass exerts a greater force
B.If object A exerts a force on object B, then object B always exerts a force back on A. The object with the greater acceleration exerts a greater force
C.If object A exerts a force on object B, then object B always exerts a force back on A The two forces are equal in magnitude, but opposite in direction to each other.
D.If object A exerts a force on object B, then object B always exerts a force back on A. The object with the greater mass and acceleration exerts a greater force.
Answer:B
Explanation:
The answer would be B because Answer B exerts a force which has a reaction.
the density of osmium (the densest metal) is 22.57 g/cm3. what volume would be occupied by 4.42 kg of osmium?
Osmium has a density of 22.57 g/cm³, therefore 100.55 ml of space would be taken up by 1.50 kg with osmium.
Why is density important?The density of a place refers to the number of things there, which may include inhabitants, animal, trees, or artefacts. The density is calculated by dividing the number of objects by the breadth of the area. A country's population density is calculated by dividing the entire person by the area, expressed in square kilometres or miles.
The following formula can be used to determine density:
Density is calculated as mass divided by volume in litres.
Density = 22.57 g/cm³
Mass = 4.42 kg
In the equation, the value is replaced,
22.57 g/cm³ = 4.42 kg / volume
Volume = 22.75 g/cm³ × 4.42 kg
Volume = 100.55 ml
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you weigh 610 n. what would you weigh if the earth were seven times as massive as it is and its radius were six times its present value? answer in units of n.
You would weigh 118.6 N. The result is obtained using the formula for acceleration due to gravity.
What is the formula for acceleration due to gravity?The acceleration due to gravity can be counted by the following formula.
g = F/m = GM/R²
Where
g = acceleration due to gravitym = mass of test objectF = gravitational force or weight (W)G = universal gravitational constantM = mass of an objectR = distance from the center of mass of objectYou weigh 610 N. Find your weight if the earth's mass were seven times and its radius were six times its present value!
Let's say
g₁ = acceleration due to gravity 1g₂ = acceleration due to gravity 2M₂ = 7M₁R₂ = 6R₁The ratio of the accelerations due to gravity is
g₁/g₂ = (GM₁/R₁²)/(GM₂/R₂²)
g₁/g₂ = (M₁/R₁²)/(7M₁/(6R₁)²)
g₁/g₂ = (M₁/R₁²)/(7M₁/36R₁²)
g₁/g₂ = (36M₁R₁²)/(7M₁R₁²)
g₁/g₂ = 36/7
Your weight now would be
m = W/g
W₁/g₁ = W₂/g₂
610/36 = W₂/7
W₂ = (610×7)/36
W₂ = 118.6 N
Hence, your weight would be 118.6 N on the new earth.
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What type of telescope is the hubble space telescope?
The Hubble space telescope is a reflecting telescope.
Mirrors are used by reflecting telescopes, also called reflectors, to collect and concentrate light. The HST features an eight-foot diameter primary mirror and a secondary mirror that focuses the light collected by the primary mirror onto the telescope's scientific equipment. The HST is a Cassegrain telescope, allowing for a compact design due to its concave primary mirror and convex secondary mirror.
Reflecting telescopes are frequently chosen over lens-based ones for space-based telescopes because lenses are more susceptible to distortion and poor image quality caused by thermal expansion and contraction than mirrors are. The HST was put into orbit in the year 1990 and has since been utilised to produce a number of ground-breaking astronomical discoveries.
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Two small spheres spaced 20.0 cm apart have equal charge.
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57 x 10-21 N?
Number of Electrons = ?
The electrons that must be present on each sphere if the magnitude of the force of repulsion between them is calculated to be 894 electrons.
Given that,
Force of repulsion = 4.57 × 10⁻²¹ N
The electrostatic force between the two charges is given by,
F = k q₁ q₂/r²
where,
k is the Coulomb's constant
q₁ = q₂ = q is the magnitude of the charge on each sphere
r = 20 cm = 0.20 m is the distance between the two spheres
We get the charge on each sphere by substituting and solving for q,
q = √(F r²/k) = √(4.57 × 10⁻²¹) (0.2)²/(9 × 10⁹) = 1.43 × 10⁻¹⁶ C
And since each electron has a charge of e = 1.6 × 10⁻¹⁹ C
Each sphere's net charge will be provided by,
q = N e
where,
N is the number of excess electrons
N = q/e = (1.43 × 10⁻¹⁶)/(1.6 × 10⁻¹⁹) = 894
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Rank these throws based on the amount of time it takes the ball to hit the ground.
Rank from largest to smallest. To rank items as equivalent, overlap them.
10 m/s 60 degree angle
15 m/s 45 degree angle
20 m/ s 0 degree
10 m/s 90 degree angle
15 m/s 30 degree angle
15 m/s 60 degree angle
The order of projectile motion of the amount of times from largest to smallest is, (6)>(2)>(4)>(1)>(5)>(3).
The projectile motion is a free fall motion of the body (or an object) in the horizontal path with constant velocity. In the projectile motion, the horizontal velocity of an object remains constant but the vertical velocity of an object changes along its path.
Total time taken by the object between the point of projection and the point where the ball touches the ground is called time of flight. The time of flight is the sum of time of ascent and time of decent.
The concept required to solve this question is projectile motion of an object. Initially, calculate the time taken by the ball to hit the ground in each case. Finally, determine the order of the amount of time from largest to smallest by using the resultant values of the time taken by the ball to hit the ground in all cases.
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what advantages do fiber optic cables offer over twisted pair cables and other media choices? what are the disadvantages of implementing fiber optic cables?
The main advantage of using optical fibre cable over unshielded twisted pair cable is its huge bandwidth. But even so, we use twisted pair cable at the consumer end on occasion.
The following are some advantages of using optical fibre cable: 1. Access to the internet Twisted pair cable's diameter is greater than that of optical fibre cable. Optical fibre cable has a tiny diameter due to its flexibility and thinness. 4. In twisted-pair cables, attenuation is very high. In optical fibre cables, attenuation is extremely low. More cable is allowed with fibre optic cables compared to copper twisted pair lines. Compared to copper twisted pair connections, fibre optic cables have a wider bandwidth. Installing the cables is affordable.
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A Venturi meter is a simple device for measuring fluid velocity in a gas such as air. When gas passes from left to right through the horizontal pipe, it speeds up as it passes through the constriction at point 2. Bernoulli's principle tells us that the gas pressure must be lower at point 2 than at point 1, and the pressure difference causes the liquid in the U-tube to drop on the left-hand side and rise on the right-hand side. Suppose the gas is air (density 1.20 kg/m3) that enters the left-hand side of the Venturi meter at 25.0 m/s. The horizontal tube has cross-sectional area 2.00 cm2 at point 1 and cross-sectional area 1.00 cm2 at point 2. If the liquid in the U-tube is water, what is the difference in height between the water columns on the left-hand and right-hand sides of the tube
The difference in height between the water columns on the left-hand and right-hand sides of the tube can be found using the principle of continuity of fluid flow. Applying this principle to the two points in the tube, we can write the following equation: A1 * v1 = A2 * v2
Where A1 is the cross-sectional area at point 1, v1 is the velocity of the fluid at point 1, A2 is the cross-sectional area at point 2, and v2 is the velocity of the fluid at point 2.
Since the fluid is water and is at rest, we can assume that the velocity of the fluid at both points is zero and the equation becomes:
A1 = A2 * h2 / h1
Therefore:
h2 = (A1 * h1) / A2
h2 = (2.00 cm2 * h1) / 1.00 cm2
h2 = 2h1
What is the principle of continuity of fluid flow?The principle of continuity of fluid flow states that what flows into a defined volume in a defined time, minus what flows out of that volume in that time, must accumulate in that volume.
What is a symbol of continuity?The continuity mode has a diode symbol, which is a triangle with a line on the right side.
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a car can round an 80-meter radius curve at a maximum speed of 20 m/s. find the maximum speed the car can travel on the same surface if the radius of the curve is increased to 320 meters.
A car can travel at a top speed of 20 m/s around a curve with an 80-meter radius. r=0.52 and v=40.4 m/s.
What is speed and what is its unit in physics?The pace at which a distance changes over time is referred to as speed. It has a dimension of time-distance. As a result, the fundamental unit of time and or the basic unit od height are combined to form new SI unit of speed.
How does physics define speed?Knowing the variables for both distance and time is necessary to calculate the units for speed. Here, the distance is measured in meters and the time is measured in seconds.
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A van traveling 110 km/h runs into a concrete wall. The front of the van crushes such that the driver, who is wearing seat belts and shoulder straps, comes to rest after traveling 0.60 m following the impact. a. Assuming constant acceleration, how much time passes between impact and rest? b. How large is the negative acceleration experienced by the driver? c. How many "g"s did the driver experience?
a) Assuming constant acceleration, the time passes between impact and rest is about 3.927×10⁻²s.
b) The negative acceleration experienced by the driver |a| is 778m/s².
c) 79.39g's the driver will experience.
What is the straightforward meaning of velocity?A vectorial representation of velocity is the displacement in space-time that an object or particle experiences. The standard unit for measuring velocity magnitude is the metre per second (m/s) (also known as speed).
a) [tex]V_{i}[/tex] = 110km/h = 30.56m/s
[tex]V_{f}[/tex] = 0
[tex]V^{2} _{f}[/tex] = [tex]V^{2} _{i}[/tex] +2as
0 = (30.56)² + 2a(0.6)
a = -778m/s²
Now [tex]V_{f}[/tex] = [tex]V_{i}[/tex] + at
0 = 30.56 + -778 t
t = 3.927×10⁻²s
b) The negative acceleration experienced by the driver |a| = 778m/s²
c) g = |a|/9.8m/s² = 79.39g's
79.39g's the driver will experience.
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The work done in pushing a TV set a distance of 2 m with an average force of 20 N is
A) 2 J. B) 10 J. C) 20 J. D) 40 J. E) 800 J.
"The work done in pushing a TV set a distance of 2 m with an average force of 20 N is calculated to be 40 J."
The force used to move an object a specific distance is referred to as work in physics. It is determined by multiplying the force times the distance. It is the transfer of energy that occurs during movement.
Mathematically, W = F × s
Given that,
Distance in pushing a TV set = 2 m
Average force = 20 N
Work done while pushing a TV set = ?
Putting the above given values, we have,
W = F × s = 20 × 2 = 40 N-m = 40 J
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