Test the series for convergence or divergence. − 2 8 4 9 − 6 10 8 11 − 10 12 identify bn. (assume the series starts at n = 1. )

Answers

Answer 1

The given series 2/8 + 4/9 + 6/10 + 8/11 + 10/12 + ..... is a divergent series.

The given series is:

2/8 + 4/9 + 6/10 + 8/11 + 10/12 + .....

Here,

t₁ = 2/8 = (2*1/(1 + 7))

t₂ = 4/9 = (2*2/(2 + 7))

Proceeding in this manner we get the n th term of the given series,

tₙ = (2*n)/(n + 7)

So, now the limit of n th term of the series is given by,

[tex]\lim_{n \to \infty}[/tex] tₙ = [tex]\lim_{n \to \infty}[/tex] (2*n)/(n + 7)) = [tex]\lim_{n \to \infty}[/tex] 2/(1 + 7/n)

Since n tends to infinity

So, 1/n tends  to 0. Let 1/n = y

So, 'y' tends to 0.

= [tex]\lim_{y \to 0}[/tex] 2/(1 + 7y) = 2 ≠ 0

Now, difference between (n+1)th and n th term is

= [tex]b_{n+1} - b_n[/tex]

= 2(n+1)/(n +1 +7) - 2n/(n + 7)

= (2(n + 1 + 7) - 14)/(n +1 +7) - (2(n + 7) - 14)/(n + 7)

= 2 - 14/(n + 8) - 2 + 14/(n +7)

= 14/(n +7) - 14/(n +8)

= 14(n + 8 - n - 7)/(n +7)(n +8)  

= 14/(n + 7)(n+8) > 0

So, [tex]b_{n+1}\geq b_n[/tex]

Hence the given series diverges.

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Related Questions

The file P02_56.xlsx contains monthly values of indexes that measure the amount of energy necessary to heat or cool buildings due to outside temperatures. (See the explanation in the Source sheet of the file.) These are reported for each state in the U.S. and also for several regions, as listed in the Locations sheet, from 1931 to 2000.
a. For each of the Heating Degree Days and Cooling Degree Days sheets, create a new Season variable with values "Winter," "Spring," "Summer," and"Fall." Winter consists of December, January, and February; Spring consists of March, April, and May; Summer consists of June, July, and August; and Fall consists of September, October, and November.
b. Use StatTools to find the mean, median, and standard deviation of Heating Degree Days (HDD), broken down by Season, for the 48 contiguous states location (code 5999). (Ignore the first and last rows for the given location, the ones that contain -9999, the code for missing values.) Also, create side-by-side box plots of HDD, broken down by season. Comment on the results. Do they go in the direction you would expect? Do the same for Cooling Degree Days (which has no missing data). c. Repeat part b for California (code 0499). d. Repeat part b for the New England group of states (code 5801).

Answers

The results show a different pattern than for the contiguous states

a. To create a new Season variable with values "Winter," "Spring," "Summer," and "Fall," we need to use the MONTH function in Excel to extract the month from the date, and then use a series of IF statements to assign each month to its corresponding season. Here are the formulas to use:

For the Heating Degree Days sheet:

=IF(OR(MONTH(A2)=12,MONTH(A2)=1,MONTH(A2)=2),"Winter",IF(OR(MONTH(A2)=3,MONTH(A2)=4,MONTH(A2)=5),"Spring",IF(OR(MONTH(A2)=6,MONTH(A2)=7,MONTH(A2)=8),"Summer",IF(OR(MONTH(A2)=9,MONTH(A2)=10,MONTH(A2)=11),"Fall",""))))

For the Cooling Degree Days sheet:

=IF(OR(MONTH(A2)=12,MONTH(A2)=1,MONTH(A2)=2),"Winter",IF(OR(MONTH(A2)=3,MONTH(A2)=4,MONTH(A2)=5),"Spring",IF(OR(MONTH(A2)=6,MONTH(A2)=7,MONTH(A2)=8),"Summer",IF(OR(MONTH(A2)=9,MONTH(A2)=10,MONTH(A2)=11),"Fall",""))))

b. To find the mean, median, and standard deviation of Heating Degree Days (HDD), broken down by season, for the 48 contiguous states location (code 5999), we need to use StatTools. Here are the steps:

Open the StatTools Descriptive Statistics dialog box by clicking on the Descriptive Statistics button on the StatTools toolbar.

In the Input Range field, select the range of HDD values for location 5999 (excluding the first and last rows that contain missing values).

In the Group By field, select the Season variable we created in part a.

Check the Mean, Median, and Standard Deviation checkboxes under Statistics.

Click OK to generate the results.

To create side-by-side box plots of HDD, broken down by season, we can use the Box Plot dialog box in StatTools:

Click on the Box Plot button on the StatTools toolbar to open the Box Plot dialog box.

In the Input Range field, select the range of HDD values for location 5999 (excluding the first and last rows that contain missing values).

In the Group By field, select the Season variable we created in part a.

Check the Side-by-Side box to create a side-by-side box plot.

Click OK to generate the plot.

Comment on the results:

The mean and median HDD values are highest in Winter and lowest in Summer, which is what we would expect. The standard deviation is also highest in Winter, indicating greater variability in heating needs during that season. The box plots confirm these findings, with Winter showing the greatest spread of values and a higher median than the other seasons. Summer has the narrowest spread of values and the lowest median.

c. To repeat part b for California (code 0499), we simply need to change the location code in the formulas and dialog boxes:

In the formulas for the Season variable, replace "A2" with the appropriate cell reference for the date column in the California sheet.

In the StatTools dialogs, select the range of HDD values and the Season variable for location 0499 instead of 5999.

The results show a different pattern than for the contiguous states. HDD values in California are highest in Winter and Spring, and lowest in Fall and Summer. This is likely due to the mild climate in California

The mean (average) of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set. The median is the middle value when a data set is ordered from least to greatest.

There are several kinds of mean in mathematics, especially in statistics. Each mean serves to summarize a given group of data, often to better understand the overall value of a given data set. Pythagorean means consist of arithmetic mean, geometric mean, and harmonic mean.

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Think about if you solve an equation and at the end you are left with the equaton 9=15 What does this mean?

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When you are left with the equation "9=15" after solving an equation, it means that there is no solution that satisfies the equation.

Now, if you have solved an equation and ended up with the statement "9=15," this means that the equation is not true. In mathematical terms, the equation "9=15" is a contradiction or an inconsistent equation. This is because it is impossible for the value of 9 to be equal to the value of 15.

When solving an equation, it is important to check the solution by substituting the value back into the original equation to ensure that it satisfies the equation. If the solution leads to a contradiction like "9=15," then the solution is invalid and does not satisfy the equation.

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(Q1) The _____ will lie at the vertex of the right angle in a right triangle.

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In a right triangle, one of the interior angles measures exactly 90 degrees, which is called the right angle.

This right angle is formed by the intersection of the two non-hypotenuse sides of the triangle, and it is located at the vertex where these sides meet. The "right angle vertex" or "vertex of the right angle" are other names for this vertex. The right angle vertex is an important feature of right triangles, and it is used in many geometric and trigonometric calculations. For example, the Pythagorean Theorem, which relates the lengths of the sides of a right triangle, depends on the location of the right angle vertex.

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Find the degree, leading coefficients, and the maximum number o real zeros of the polynomial. f(x) = -x^8 - 3x^7 + 3x^5 - 4 Degree = Leading Coefficient = Maximum number of real zeros =

Answers

The degree of the polynomial is 8, which is the highest exponent of the variable x.

The leading coefficient is -1.

To find the maximum number of real zeros, we can use Descartes' rule of signs. First, we count the number of sign changes in the coefficients of the polynomial.

- from -1x⁸ to -3x⁷ (change from negative to negative)

- from -3x⁷ to +3x⁵ (change from negative to positive)

- from +3x⁵ to -4 (change from positive to negative)

Therefore, there are either 3 or 1 positive real zeros.

Next, we count the number of sign changes in the coefficients of f(-x), which is the polynomial with its terms reversed in order.

- from -1(-x)⁸ to -3(-x)⁷ (change from negative to negative)

- from -3(-x)⁷ to +3(-x)⁵ (change from negative to positive)

Therefore, there are either 2 or 0 negative real zeros.

Since the number of positive real zeros is either 3 or 1, and the number of negative real zeros is either 2 or 0, the maximum number of real zeros is 3.

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Due Friday, March 19 at midnight The following is the partial printout of problem 15. 14 (The Fresh Detergent Case). Enterprise Industries produces Fresh, a brand of liquid laundry detergent. In order to manage its inventory more effectively and make revenue projections, the company would like to better predict demand for Fresh. To develop a prediction model, the company has gathered data concerning demand for Fresh over the last 30 sales periods (each sales period is defined to be a four-week period). The demand data are in your Bowerman data folder on the files page. Here are the variables that will be in the model: Y= the demand for the large size bottle of Fresh (in hundreds of thousands of bottles) in the sales period. X1=the price in dollars) of Fresh as offered by Enterprise Industries in the Sales period. X2-the average industry price in dollars) of competitors' similar detergents in the sales period. X3=Enterprise Industries' advertising expenditure (in hundereds of thousands of dollars) to promote Fresh in the sales perios. 1. What is the predicted demand for Fresh if the price is 3. 5, IndPrice is 3. 9, and the average expenditure is 6. 5?

2. From the output provided, calculate R-squared.

3. From the output provided, calculate the F-ratio.

4. From the output provided, calculate the t ratio for the independent variable Price.

5. From the output provided, does it appear that Price is a significant contributor to the variation in Demand? Why?

Answers

When the Price increases by 1 dollar and the other variables hold constant values, the demand for the large size bottle decreases by 235800 bottles

How to solve

12)

True

Adjusted R2 helps us find the more suitable variable for the prediction.

13)

Regression equation is

yhat = 7.589 - 2.358*Price + 1.612*IndPrice + 0.501*AdvExp

If Price = 3.5

IndPrice = 3.9

AdvExp = 6.5

Predicted demand is

yhat = 7.589 - 2.358*3.5 + 1.612*3.9 + 0.501*6.5

yhat = 8.879

14)

Interpretation :

When the Price increases by 1 dollar and the other variables hold constant values, the demand for the large size bottle decreases by 235800 bottles.

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1 a survey firm wants to ask a random sample of adults in ohio if they support an increase in the state sales tax from 5% to 6%, with the additional revenue going to education. let p^ denote the proportion in the sample who say that they support the increase. suppose that 40% of all adults in ohio support the increase. how large a sample would be needed to guarantee that the standard deviation of p^ is no more than 0.01?

Answers

A sample of 2400 adults in Ohio would be needed to guarantee that the standard deviation of the proportion who support the increase in the state sales tax (p^) is no more than 0.01.

To determine the sample size needed to guarantee that the standard deviation of p^ is no more than 0.01, we need to use the formula:

n = (Zα/2)^2 * p(1-p) / (d^2)

where n is the sample size, Zα/2 is the critical value of the standard normal distribution for a confidence level of α/2, p is the proportion of adults in Ohio who support the increase (0.4 in this case), and d is the maximum margin of error (0.01 in this case).

Assuming a 95% confidence level (α = 0.05), the critical value of Zα/2 is 1.96. Substituting these values into the formula, we get:

n = (1.96)^2 * 0.4(1-0.4) / (0.01)^2
n = 1536.16

Therefore, we would need a sample size of at least 1537 adults in Ohio to guarantee that the standard deviation of p^ is no more than 0.01.
To calculate the required sample size for a given standard deviation of the sample proportion (p^), we can use the formula:

σ(p^) = √(pq/n)

where σ(p^) is the desired standard deviation, p is the proportion of support (0.40), q is the proportion of non-support (1-p, which is 0.60), and n is the sample size.

We want to guarantee that the standard deviation of p^ is no more than 0.01. Therefore, we set σ(p^) to be 0.01:

0.01 = √(0.40 * 0.60 / n)

Squaring both sides:

0.0001 = 0.24 / n

Now, solve for n:

n = 0.24 / 0.0001

n = 2400

So, a sample of 2400 adults in Ohio would be needed to guarantee that the standard deviation of the proportion who support the increase in the state sales tax (p^) is no more than 0.01.

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4-3
Write a program that prompts the user to input an integer between 0 and 35. The prompt should say Enter an integer between 0 and 35:.
If the number is less than or equal to 9, the program should output the number; otherwise, it should output:
A for 10
B for 11
C for 12
. . .
and Z for 35.
(Hint: For numbers >= 10, calculate the ACSII value for the corresponding letter and convert it to a char using the cast operator, static_cast().)

Answers

Here's a sample program in C++ that satisfies your requirements:

```
#include
using namespace std;

int main() {
 int num;
 cout << "Enter an integer between 0 and 35: ";
 cin >> num;

 if (num <= 9) {
   cout << num << endl;
 } else if (num >= 10 && num <= 35) {
   char letter = static_cast('A' + num - 10);
   cout << letter << endl;
 } else {
   cout << "Invalid input." << endl;
 }

 return 0;
}
```

- The program prompts the user to input an integer between 0 and 35 using the `cout` and `cin` statements.
- The `if` statement checks whether the number is less than or equal to 9. If it is, it outputs the number using the `cout` statement.
- The `else if` statement checks whether the number is between 10 and 35 (inclusive). If it is, it calculates the corresponding letter using the ASCII value for 'A' and the given number. The `static_cast` statement converts the calculated value to a character. Finally, the program outputs the letter using the `cout` statement.
- The `else` statement handles the case when the input is outside the range of 0 to 35. It outputs an error message using the `cout` statement.
- The program ends with the `return 0` statement.

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the trading post sells 7 pencils and 8 notebooks for $4.15. it also sells 5 pencils and 3 notebooks for $1.77. how much do 16 pencils and 10 notebooks cost?

Answers

The calcuulated cost of 16 pencils and 10 notebooks is $5.84

How much do 16 pencils and 10 notebooks cost?

From the question, we have the following parameters that can be used in our computation:

7 pencils and 8 notebooks for $4.15. 5 pencils and 3 notebooks for $1.77

As a system of equations, we have

7x + 8y = 4.15

5x + 3y = 1.77

Where

x = pencils

y = notebooks

When solved graphically, we have

x = 0.09 and y = 0.44

This means that

x = pencils = 0.09

y = notebooks = 0.44

So, we have

16 pencils and 10 notebooks = 16 * 0.09 + 10 * 0.44

Evaluate

16 pencils and 10 notebooks = 5.84

Hence, the cost of 16 pencils and 10 notebooks is $5.84

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PLEASE HELP, I NEED THIS TO BE DONE BY TODAY

Answers

Based on the given data, the height of a plant from Variety A is likely to be closer to the mean. So, correct option is C.

Based on the given data, we can make the following observations:

The mean height of plants from Variety A is 19 inches, while the mean height of plants from Variety B is 13 inches.

The mean absolute deviation (MAD) for Variety A is 1.2 inches, while the MAD for Variety B is 2.4 inches. This means that the heights of plants from Variety A are less variable than the heights of plants from Variety B.

Option A cannot be concluded from the given data as we do not have information on the maximum height of plants from either variety.

Option B cannot be concluded from the given data as there is overlap in the height ranges of the two varieties.

Option C is likely to be true as the MAD for Variety A is smaller, indicating that the heights of plants from this variety are more tightly clustered around the mean of 19 inches.

Option D is unlikely to be true as the MAD for Variety B is larger, indicating that the heights of plants from this variety are more spread out and farther away from the mean of 13 inches.

In conclusion, based on the given data, we can say that the height of a plant from Variety A is likely to be closer to the mean, and the height of a plant from Variety B is likely to be farther away from the mean.

So, correct option is C.

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imagine you are drawing from a deck of 52 cards (the 52 standard cards). determine the number of ways you can achieve the following 5-card hands drawn from the deck without repeats. discrete math

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To determine the number of ways you can achieve a 5-card hand without repeats from a deck of 52 cards, we can use the formula for combinations:

C(52, 5) = 52! / (5! * (52-5)!) = 2,598,960

This means that there are 2,598,960 ways to draw a 5-card hand without repeats from a standard deck of 52 cards.

In order to find the number of ways you can achieve a specific 5-card hand from a standard deck of 52 cards, you'll need to use combinations in discrete math. Combinations are used to calculate the number of ways to choose a certain number of items from a larger set, without considering the order of the items.

In this case, you want to choose 5 cards from a deck of 52 cards. Using the combination formula, you can determine the number of ways to do this:

C(n, k) = n! / (k!(n-k)!)

Where n is the total number of items (52 cards), k is the number of items you want to choose (5 cards), and ! represents the factorial function (e.g., 5! = 5 x 4 x 3 x 2 x 1).

Using the formula for your situation:

C(52, 5) = 52! / (5!(52-5)!)
C(52, 5) = 52! / (5!47!)

Calculating the factorials and dividing, you get:

C(52, 5) = 2,598,960

So, there are 2,598,960 ways to draw a 5-card hand from a standard deck of 52 cards without repeats.

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a fruit company delivers fruit in two different size boxes: large and small. a delivery of 3 large boxes and 4 small boxes has a total weight of \69\) kilograms. a delivery of 5 large boxes and small boxes has a total weight of 73 kilograms. how much does each type of box weigh?

Answers

In the equation, the large book weight is 11kg and small book weight is

9 kg.

What is equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

Here let us take weight of large book as x and weight of small book as y.

Then,  3 large boxes and 4 small boxes has a total weight of 69 then,

=> 3x+4y = 69 --------> 1

And 5 large boxes and  2 small boxes has a total weight of 73kg then,

=> 5x+2y = 73 ----------> 2

Now multiply second equation by 2 then,

=> 10x+4y = 146 ----------> 3

Now 3 -1 then,

=>    10x+4y =   146

  (-)    3x+4y =    69

-------------------------------

     7x          =     77

=>  x = 77/7 = 11kg.

put x=11 kg into 1 then,

=> 3(11)+4y=69

=> 4y = 69-33

=> 4y = 36

=> y = 36/4 = 9 kg.

Hence the large book weight is 11kg and small book weight is 9 kg.

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The circle graph shows what quality business owners value most in an employee What is the measure of arc AD?

a.) 35°
b.) 63°
c.) 97.2°
d.) 126°

Answers

The answer is A.) 35

a card is randomly selected from standard deck find probability card is between 5 and 9 inclusively or quen

Answers

The probability of selecting a card that is between 5 and 9 inclusively or a queen is 6/13, or approximately 0.46.

There are 16 cards in a standard deck that are either between 5 and 9 inclusively (5, 6, 7, 8, and 9 of each suit) or queens (4 queens in total).

To find the probability of selecting a card that satisfies the given condition, we need to divide the number of cards that meet the condition by the total number of cards in the deck.

So, the probability of selecting a card that is between 5 and 9 inclusively or a queen is:

P = (number of cards between 5 and 9 inclusively) + (number of queens) / (total number of cards)

P = (20 + 4) / 52

P = 24 / 52

P = 6 / 13

Therefore, the probability of selecting a card that is between 5 and 9 inclusively or a queen is 6/13, or approximately 0.46.

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Suppose you are going to test the hypothesis that two populations have the same mean. What is the test statistic for this test when the sample averages are 6 and 7. 5 and sample 1 has a standard deviation of 16 and sample 2 has a standard deviation of 15 and both samples have 32 observations?.

Answers

The test statistic for this test is -0.213.

To test the hypothesis that two populations have the same mean, we can use a two-sample t-test. The test statistic for this test is calculated by taking the difference between the sample means and dividing it by the standard error of the difference.

In this case, the sample averages are 6 and 7, and the standard deviations for the two samples are 16 and 15, respectively. Both samples have 32 observations.

To calculate the test statistic, we first need to calculate the standard error of the difference. This is given by:

SE = sqrt[(s1^2/n1) + (s2^2/n2)]

where s1 and s2 are the standard deviations for the two samples, and n1 and n2 are the sample sizes. Plugging in the values we have, we get:

SE = sqrt[(16^2/32) + (15^2/32)]
  = 4.698

Next, we calculate the t-statistic:

t = (x1 - x2) / SE

where x1 and x2 are the sample means. Plugging in the values we have, we get:

t = (6 - 7) / 4.698
 = -0.213

The test statistic for this test is -0.213.

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Jacobian Problem Linearize the nonlinear system about the equilibrium point (0, 0) using the Jacobian and determine its eigenvalues dx1 dt = 3x1x2 + 3x2 dx1 d3x+5x2 dt Is the linearized system stable or unstable?

Answers

The Jacobian problem requires us to linearize the given nonlinear system about the equilibrium point (0, 0) using the Jacobian and determine its eigenvalues.

To do this, we need to calculate the partial derivatives of the system with respect to x1 and x2 and form the Jacobian matrix. The Jacobian matrix for the given system is: J(x1,x2) = [3x2 3x1+3x2; 0 5], Evaluating the Jacobian matrix at (0,0), we get: J(0,0) = [0 0; 0 5].



To find the eigenvalues of J(0,0), we need to solve the characteristic equation: det(J(0,0)-λI) = 0, where I is the identity matrix. Solving this equation, we get: (0-λ)(5-λ) = 0, which gives us two eigenvalues: λ1 = 0, λ2 = 5



Since one of the eigenvalues is zero, the linearized system is nonlinear. To determine whether the linearized system is stable or unstable, we need to look at the sign of the real part of the eigenvalues. If the real part of all the eigenvalues is negative, then the system is stable, otherwise it is unstable.



In this case, since one of the eigenvalues is zero, the linearized system is not stable. The other eigenvalue is positive, which means that the linearized system is unstable. Therefore, we can conclude that the nonlinear system is also unstable at the equilibrium point (0,0).

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the mean iq of statistics teachers is greater than 140. state this claim mathematically.write the null and alternative hypotheses. identify which hypothesis is the claim.

Answers

In the hypothesis testing, the null and alternative for the claim that mean iq of statistics teachers is greater than 140, are

[tex]H_0 :\mu \leqslant 140[/tex]

[tex]H_a : \mu > 140[/tex]

and the alternative hypothesis is the hypothesis of this claim.

Hypothesis testing in statistics is a process where you to test the results of a survey or experiment based sample to look if you have meaningful results. It is based on hypothesis. The null hypothesis of a test always shows no effect or no relationship between variables, while the alternative hypothesis states your research prediction of an effect or relationship. The null hypothesis is the fact that should be tested and the alternative is everything else.

We have mean iq of statistics teachers is greater than 140. We have to identify the hypothesis for which this claim is true. Now, the null and alternative hypothesis are defined as in this case, [tex]H_0 :\mu ≤ 140[/tex]

[tex]H_a : \mu > 140[/tex]

where μ --> mean iq of statistics

From above, the hypothesis which identify the claim that mean iq of statistics teachers is greater than 140 is alternative hypothesis. Hence, the required answer is alternative hypothesis.

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Mathematically, the claim can be expressed as follows:

µ > 140

where µ represents the population mean IQ score of statistics teachers.

The null hypothesis (H0) is that the population mean IQ score of statistics teachers is not greater than 140:

H0: µ ≤ 140

The alternative hypothesis (Ha) is that the population mean IQ score of statistics teachers is greater than 140:

Ha: µ > 140

Note that the claim corresponds to the alternative hypothesis, Ha.

Null hypothesis (H0): The mean daily attendance at the park is μ = people.

Alternative hypothesis (Ha): The mean daily attendance at the park is not equal to μ ≠ people.

The claim is represented by the alternative hypothesis (Ha), which states that the mean daily attendance at the park is different from the claimed value of people.

Note that the value of μ is not specified in the claim, but it is assumed to be equal to people. The null hypothesis (H0) reflects this assumption, and the alternative hypothesis (Ha) challenges it by stating that the true mean attendance may be different from this value.

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HELP PLEASE
A spinner with repeated colors numbered from 1 to 8 is shown. Sections 1 and 8 are purple. Sections 2 and 3 are yellow. Sections 4, 5, and 6 are blue. Section 7 is orange.

spinner divided evenly into eight sections with three colored blue, one colored orange, two colored purple, and two colored yellow

Determine P(not yellow) if the spinner is spun once.

75%
37.5%
25%
12.5%

Answers

Probability of getting a non-yellow section on the spinner is 75%. The Option A.

What is the probability of getting non-yellow?

Probability deals with finding out likelihood of the occurrence of an event. Its measures chance of an event happening.

We have a total of 8 sections on the spinner, with 2 yellow sections and 6 non-yellow sections.

Number of possibility = 8

Number of sample case= 6 (8 - 6)

The probability of getting a non-yellow section on the spinner is:

P(not yellow) = 6/8

P(not yellow) = 3/4

P(not yellow) = 0.75

P(not yellow) = 75%

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a classroom of children has 10 boys and 12 girls in which five students are chosen at random to do presentations. what is the probability that more boys than girls are chosen?

Answers

The probability that more boys than girls are chosen is approximately 39.67%.

To determine the probability that more boys than girls are chosen from a classroom with 10 boys and 12 girls, we need to consider the possible ways this can happen. There are two scenarios:

1. 3 boys and 2 girls are chosen.
2. 4 boys and 1 girl are chosen.

First, calculate the total number of ways to choose 5 students from 22 (10 boys + 12 girls) using the combination formula: C(n, k) = n! / (k! * (n-k)!)

C(22, 5) = 22! / (5! * 17!) = 26,334

Now, calculate the probabilities for the two scenarios:

1. 3 boys and 2 girls are chosen:
C(10, 3) = 10! / (3! * 7!) = 120
C(12, 2) = 12! / (2! * 10!) = 66
Total combinations: 120 * 66 = 7,920

2. 4 boys and 1 girl are chosen:
C(10, 4) = 10! / (4! * 6!) = 210
C(12, 1) = 12! / (1! * 11!) = 12
Total combinations: 210 * 12 = 2,520

Add the combinations for both scenarios: 7,920 + 2,520 = 10,440

Now, calculate the probability:

P(more boys than girls) = Number of favorable outcomes / Total possible outcomes = 10,440 / 26,334 ≈ 0.3967 or 39.67%

So, the probability that more boys than girls are chosen is approximately 39.67%.

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try and find what sides (in integers only) a rectangle must have if its area and perimeter are to be equal

Answers

Let's say the sides of the rectangle are represented by integers a and b. The area of the rectangle is a * b, and the perimeter is 2 * (a + b).

To make a * b equal to 2 * (a + b), we must determine the values of a and b. The equation is rearranged to give us: a * b - 2 * a - 2 * b = 0.

Adding 4 to both sides, we can factorize the left-hand side of the equation using the distributive property: we need to find pairs of integers whose difference is 4. These pairs are:

a - 2 = 4 and b - 2 = 1, which gives a = 6 and b = 3

a - 2 = 2 and b - 2 = 2, which gives a = 4 and b = 4

a - 2 = 1 and b - 2 = 4, which gives a = 3 and b = 6

So the sides of the rectangle could be 6 and 3, 4 and 4, or 3 and 6.

Now we need to find pairs of integers whose difference is 4. These pairs are:

a - 2 = 4 and b - 2 = 1, which gives a = 6 and b = 3

a - 2 = 2 and b - 2 = 2, which gives a = 4 and b = 4

a - 2 = 1 and b - 2 = 4, which gives a = 3 and b = 6

So the sides of the rectangle could be 6 and 3, 4 and 4, or 3 and 6

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Anthony bought a 5 year life insurance policy on June 5, 2010. The face value of this policy was $350,000, and his monthly premium was $1,256. Sadly, he passed away on March 22, 2015. How much money did his family receive from the insurance company?

Answers

Anthony's family received $422,848 from the insurance company.

How much money did Anthony's family receive?

The policy was bought on June 5, 2010 and Anthony passed away on March 22, 2015.

The policy was active for:

= (5 years + 9.5 months)

= 58 months.

The total amount of premiums paid during this time was:

= $1,256/month x 58 months

= $72,848

The face value of the policy was $350,000. The total amount paid out to Anthony's family was:

= $350,000 + $72,848

= $422,848.

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the refers to the strength of association between variables. a) statistical index b) effect size c) standard deviation d) linear degree

Answers

The term that refers to the strength of association between variables is b) effect size. Effect size is a quantitative measure that describes the magnitude of the relationship between two or more variables. It is particularly useful in comparing the results of different studies or experiments, as it provides a standardized measure of the strength of the association, regardless of the specific context or sample size.

In contrast, a) statistical index is a broader term that refers to any statistic used to measure a particular characteristic or attribute, such as the mean or median. c) Standard deviation is a measure of the dispersion or spread of data points around the mean, and while it may provide some context for the strength of the relationship, it does not directly measure the association between variables. d) Linear degree refers to the degree of a linear equation, which is unrelated to the strength of association between variables.

In summary, effect size is the most appropriate term to describe the strength of association between variables, as it provides a standardized measure of the magnitude of the relationship that can be used to compare different studies or experiments. It is an important concept in research and data analysis, as it allows researchers to understand the practical significance of their findings and make informed decisions about their work.

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another accountant who works at the same tax prep center thinks people are getting a higher refund. this accountant would like to carry out a hypothesis test and test the claim that the average amount of a tax refund is more than 500 dollars. why is their hypothesis test right-tailed? select the correct answer below: this is a right-tailed test because a direction is not specified. this is a right-tailed test because a direction is specified. the population parameter is greater than the specified value. this is a right-tailed test because a direction is specified. the population parameter is less than the specified value. more information is needed.

Answers

The hypothesis test is right-tailed and direction is specified, and the given population parameter is greater than the specified value (more than $500). So, the correct answer from given options is B).

The hypothesis test is right-tailed because a direction is specified. The null hypothesis assumes that the average tax refund is equal to or less than $500, while the alternative hypothesis assumes that the average tax refund is greater than $500.

Therefore, the test is designed to detect if the population parameter is greater than the specified value, making it a right-tailed test. So, the correct option is B).

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which of the following eliminates the drawback of having the measure of dispersion in squared units rather than in the original measurement units? a. standard deviation b. mean c. variance d. deviation

Answers

The standard deviation eliminates the drawback of having the measure of dispersion in squared units rather than in the original measurement units. This is because the standard deviation is calculated by taking the square root of the variance, which is in squared units. So, the standard deviation gives a measure of dispersion in the same units as the original measurements.
Hi! The option that eliminates the drawback of having the measure of dispersion in squared units rather than in the original measurement units is a. standard deviation. This is because standard deviation is the square root of variance, which brings the measurement back to the original units.

The option that eliminates the drawback of having the measure of dispersion in squared units rather than in the original measurement units is the standard deviation. option A

How to determine the measure of dispersion

Scattering alludes to the spread or changeability of information focuses in a dataset.

Variation could be a degree of scattering, but it is calculated by squaring the contrasts between each information point and the cruel. As a result, the variation is communicated in squared units, which may not be straightforwardly interpretable or significant within the setting of the initial estimation units.

The standard deviation, on the other hand, is the square root of the change. By taking the square root, it brings the degree of dispersion back to the initial estimation units, making it more effortlessly interpretable and comparable to the first information.

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A researcher was interested in the relationship between a swimmer’s hand length and corresponding time to complete the 100-meter freestyle. The researcher selected a random sample of twenty swimmers from all participants in a swim competition. Assuming all conditions for inference are met, which of the following significance tests should be used to investigate whether there is convincing evidence, at a 5 percent level of significance, that a longer hand length is associated with a decrease in the time to complete the 100-meter freestyle?.

Answers

To investigate whether there is convincing evidence, at a 5 percent level of significance, that a longer hand length is associated with a decrease in the time to complete the 100-meter freestyle, the researcher should use a linear regression t-test.


1. The researcher collects data on hand length and 100-meter freestyle completion time for twenty randomly selected swimmers.
2. Calculate the correlation coefficient (r) to measure the strength and direction of the relationship between hand length and freestyle completion time.
3. Perform a linear regression analysis to obtain the slope (b) and the y-intercept (a) of the best-fit line.
4. Conduct a linear regression t-test to determine if the slope (b) is significantly different from zero at a 5 percent level of significance.
5. If the t-test results in a p-value less than 0.05 (5 percent level of significance), there is convincing evidence that a longer hand length is associated with a decrease in the time to complete the 100-meter freestyle.

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this is an example of this is an example of a quantitative forecast. a qualitative forecast. a probability forecast. an analog forecast.

Answers

The Delphi method is not a quantitative forecasting method.

What is statistics?

Statistics is the branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of data. It involves the use of mathematical methods to gather, summarize, and interpret data, which can be used to make decisions or draw conclusions about a population based on a sample of that population.

The Delphi method is a qualitative forecasting technique that involves obtaining expert opinions through a series of structured questionnaires or interviews.

It is often used in situations where there is a lack of historical data or when the future is uncertain.

The Delphi method is particularly useful when forecasting complex or novel events or when multiple sources of information need to be synthesized.

In contrast, the moving average model, classical decomposition, and simple regression are all quantitative forecasting methods that rely on historical data and statistical analysis to make predictions.

The moving average model uses a rolling average of past data to make predictions, while classical decomposition breaks down a time series into its components (such as trend, seasonality, and irregularity) to model each component separately.

Simple regression, on the other hand, uses a linear equation to model the relationship between two variables and make predictions based on that relationship.

Hence, The Delphi method is not a quantitative forecasting method.

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Nico and Karina wrote these statements in their math journals. Nico’s Statement Karina’s Statement A 4-sided polygon with at least one pair of parallel sides must be a parallelogram. A 4-sided polygon with at least one pair of parallel sides must be a trapezoid. Which describes the accuracy of their statements and why? Nico is correct because if one pair of sides in a quadrilateral is parallel, the other pair must be also. Karina is correct because a trapezoid has exactly one pair of parallel sides. Both are correct because a 4-sided polygon with at least one pair of parallel sides must be both a parallelogram and a trapezoid. Neither is correct because a 4-sided polygon with at least one pair of parallel sides could be either a parallelogram or a trapezoid.

Answers

The best description of the accuracy of the statements made by Nico and Karina is: Karina is correct because a trapezoid has exactly one pair of parallel sides.

Why Nico is not correct

Nico made the statement:

"A 4-sided polygon with at least one pair of parallel sides must be a parallelogram."

This statement is not right given that a 4-sided polygon with at least one pair of parallel sides could be either a parallelogram or a trapezoid (if only 1 pair of sides is parallel).

Karina made the  statement:

"A 4-sided polygon with at least one pair of parallel sides must be a trapezoid."

This statement is a right sentence because by definition, a trapezoid has exactly one pair of parallel sides.

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An electric toothbrush costs $69, including a 50% price markup. What was the cost for the store to purchase the electric toothbrush?

$19.00
$23.00
$34.50
$46.00

Answers

If the $69 cost of electric-toothbrush includes 50% "price-markup", then the cost for the store to purchase it was (d) $46.

Let the cost for the store to purchase the electric toothbrush be = "C".

We know that the "final-price" of the toothbrush, includes the 50% markup, which is = $69,

The price with the 50% markup is calculated by adding 50% of the original cost to the original cost.

So, we have :

⇒ Final price = Original cost + 50% of original cost,

Substituting the value of "final-price" as $69,

We get,

⇒ $69 = C + 0.5C,

⇒ $69 = 1.5C,

⇒ C = $46;

Therefore, the correct option is (d).

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The given question is incomplete, the complete question is

An electric toothbrush costs $69, including a 50% price markup. What was the cost for the store to purchase the electric toothbrush?

(a) $19.00

(b) $23.00

(c) $34.50

(d) $46.00

Show that if n is a positive integer, then (2n 2 ) = 2 (n 2 ) n2 a) using a combinatorial argument. B) by algebraic manipulation

Answers

It is proved by both combinatorial argument and algebraic argument that C(2n, 2) = 2 C(n, 2) + n².

The given statement is: C(2n, 2) = 2C(n, 2) + n²

Combinatorial argument:

Suppose we have to choose 2 balls from a bag consists of 2n balls.

So the number of ways to choose that 2 balls = C(2n, 2)

Now in order to do the same thing we take another process. We divide 2n balls in to equal n balls bags. Now we can choose 2 balls in following ways.

(i) 2 balls from first n ball bag and number of ways to do that = C(n, 2).

(ii) 2 balls from second n ball bag and number of ways to do that = C(n, 2) too.

(iii) 1 ball from first n ball bag and another ball from second n balls bag. The number of ways to do this = n*n = n²

So the number of ways to choose 2 balls from 2n balls by dividing the balls in equal two n balls bag is = C(n, 2) + C(n, 2) + n² = 2C(n, 2) + n².

But the event is same just the process to do the work is different so the number of ways to do the work will be equal.

Hence, C(2n, 2) = 2C(n, 2) + n².

Algebraic argument,

We know that C(n, k) = n!/(k!(n - k)!)

So, left hand side is,

C(2n, 2) = 2n!/(2!(2n - 2)!) = 2n(2n - 1)/2 = 2n² - n.

The right hand side is,

2C(n, 2) + n² = 2n!/(2!(n - 2)!) + n² = n(n - 1) + n² = 2n² - n.

Since Left Hand Side = Right Hand Side. So the statement is true by algebraic way too.

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Consider a standard set of 52 cards. How many combinations of 5 cards give you 1. a straight (five cards with ranks in a sequence and which are not all in the same suit. A, 1, 2, 3, 4, 5 and 10, J, Q, K, A both count)? 2. a flush (five cards of the same suit which are not in sequential order)? 3. a full-house (three cards with the same rank and two other cards with another common rank)?

Answers

The total number of combinations of 5 cards that give a full house is 3,744.

What is the combination?

Combinations are a way to count the number of ways to choose a subset of objects from a larger set, where the order of the objects does not matter.

To get a straight, we need to select five cards that are in a sequence and not all in the same suit.

There are 10 possible sequences of five cards (A-2-3-4-5, 2-3-4-5-6, ..., 10-J-Q-K-A), and for each sequence, there are four suits to choose from for each card.

However, we have to subtract the 10 combinations that include all five cards of the same suit (since we want the cards to be not all in the same suit).

Therefore, the total number of combinations of 5 cards that give a straight is:

4 x (10 - 1) - 10 = 36.

To get a flush, we need to select five cards that are all of the same suit and not in sequential order. There are four suits to choose from, and once we choose the suit, we need to select any five cards from that suit. The number of ways to select 5 cards from a set of 13 cards is given by the combination formula:

C(13, 5) = 1,287.

Therefore, the total number of combinations of 5 cards that give a flush is:

4 x 1,287 = 5,148.

To get a full house, we need to select three cards of the same rank and two cards of another common rank.

There are C(13, 1) ways to choose the rank for the three cards, and C(4, 3) ways to choose the suits for those three cards.

For the remaining two cards, we need to choose a different rank, so there are C(12, 1) ways to choose the rank for those cards, and C(4, 2) ways to choose the suits for those cards.

Therefore, the total number of combinations of 5 cards that give a full house is:

C(13, 1) x C(4, 3) x C(12, 1) x C(4, 2) = 3,744.

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Which of these relations on the set of all functions from Z to Z are equivalence relations?
Determine the properties of an equivalence relation that the others lack.
a) {(f, g) If (1) = 9 (1)}
b) {(f,g) If (0) = 9 (0) or f (1) = 9 (1)}
c) {(f,g) If (x) - g (x) = 1 for allx ⬠Z}
d) {(f,g) I for some C ⬠Z, for allx ⬠Z, f(x) - g (x) = C}
e) {(f,g) I f (0) = g (1) and f (1) = g (0)}

Answers

For the relations on the set of all functions from Z to Z, the relations out of these are equivalence relations are (a), (c). The relation (b) lack of transitive, (d) and (e) does not hold any property.

A reflexive, symmetric and transitive relation on a set is called an equivalence relation. Now, we have to check all relations on the set of all functions from Z to Z.

a) Set is defined as {(f, g) | f (1) = g(1)}, we check all three properties hold or not,

reflexive: f (1) = f(1)symmetric: if f(1) = g(1) => g(1) = f(1)transitive: if f (1) = g(1) and g(1) = h (1) from above two implies, f(1) = h(1).

So, it is equivalence relation.

b) Set is [tex]{(f, g) |f (0) = g(0) or f(1) = g(1)}[/tex]

Reflexive property: f (0) = f(0) or f (1) = f(1)Symmetric property: if f(0) = g(0) or f (1) = g(1) implies g(0) = f(0) or g(1) = f(1).transitive property : If f(0) = g(0) and g(1) = h(1) does not implies f(0) = h(0).

So, it not equivalence relation.

c) Set is defined [tex]{(f, g) | f (x) − g(x) = 1 for all x ∈ Z}[/tex].

Reflexive: f(x)−f(x) = 0 ≠ 1, symmetric property : if f(x)−g(x) = 1, then g(x)−f(x) = −1 ≠ 1.Transitive property : here, f(x) − g(x) = 1 and g(x) − h(x) = 1, implies f(x) − h(x) = 2

It is not equivalence relation, because not reflexive and not symmetric.

d) Set is defined as [tex]{(f, g) | for some C ∈ Z, for all x ∈ Z, f (x) − g(x) = C}[/tex].

Reflexive property : f (x) − f(x) = 0 (const)symmetric property : if f (x) − g(x) = C then g(x) − f(x) = -C = consttransitive property: if f (x) − g(x) = C₁ and g(x) − h(x) = C₂ implies f(x) − h(x) = C₁+C₂ = const.

It is an equivalence relation.

e) Set is [tex](f, g) | f (0) = g(1) and f (1) = g(0)[/tex].

Reflexive property: f(0) = f(1) is n’t always true.Symmetric property: if f(0) = g(1) and f (1) = g(0) then not g(0) = f(1) and g(1) = f(0)Transitive property : let f(x) = h(x) = x and g(x) = 1−x. Then f ≡ g and g ≡ h, but not f ≡ h.

It is not equivalence relation because no one properties are hold here.

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