[tex]\int\limits^a_b {(1-x^{2} )^{3/2} } \, dx[/tex]

Answers

Answer 1

First integrate the indefinite integral,

[tex]\int(1-x^2)^{3/2}dx[/tex]

Let [tex]x=\sin(u)[/tex] which will make [tex]dx=\cos(u)du[/tex].

Then

[tex](1-x^2)^{3/2}=(1-\sin^2(u))^{3/2}=\cos^3(u)[/tex] which makes [tex]u=\arcsin(x)[/tex] and our integral is reshaped,

[tex]\int\cos^4(u)du[/tex]

Use reduction formula,

[tex]\int\cos^m(u)du=\frac{1}{m}\sin(u)\cos^{m-1}(u)+\frac{m-1}{m}\int\cos^{m-2}(u)du[/tex]

to get,

[tex]\int\cos^4(u)du=\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{4}\int\cos^2(u)du[/tex]

Notice that,

[tex]\cos^2(u)=\frac{1}{2}(\cos(2u)+1)[/tex]

Then integrate the obtained sum,

[tex]\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int\cos(2u)du+\frac{3}{8}\int1du[/tex]

Now introduce [tex]s=2u\implies ds=2du[/tex] and substitute and integrate to get,

[tex]\frac{3\sin(s)}{16}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int1du[/tex]

[tex]\frac{3\sin(s)}{16}+\frac{3u}{4}+\frac{1}{4}\sin(u)\cos^3(u)+C[/tex]

Substitute 2u back for s,

[tex]\frac{3u}{8}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\sin(u)\cos(u)+C[/tex]

Substitute [tex]\sin^{-1}[/tex] for u and simplify with [tex]\cos(\arcsin(x))=\sqrt{1-x^2}[/tex] to get the result,

[tex]\boxed{\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C}[/tex]

Let [tex]F(x)=\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C[/tex]

Apply definite integral evaluation from b to a, [tex]F(x)\Big|_b^a[/tex],

[tex]F(x)\Big|_b^a=F(a)-F(b)=\boxed{\frac{1}{8}(a\sqrt{1-a^2}(5-2a^2)+3\arcsin(a))-\frac{1}{8}(b\sqrt{1-b^2}(5-2b^2)+3\arcsin(b))}[/tex]

Hope this helps :)

Answer 2

Answer:[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]General Formulas and Concepts:

Pre-Calculus

Trigonometric Identities

Calculus

Differentiation

DerivativesDerivative Notation

Integration

IntegralsDefinite/Indefinite IntegralsIntegration Constant C

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                    [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

U-Substitution

Trigonometric Substitution

Reduction Formula:                                                                                               [tex]\displaystyle \int {cos^n(x)} \, dx = \frac{n - 1}{n}\int {cos^{n - 2}(x)} \, dx + \frac{cos^{n - 1}(x)sin(x)}{n}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx[/tex]

Step 2: Integrate Pt. 1

Identify variables for u-substitution (trigonometric substitution).

Set u:                                                                                                             [tex]\displaystyle x = sin(u)[/tex][u] Differentiate [Trigonometric Differentiation]:                                         [tex]\displaystyle dx = cos(u) \ du[/tex]Rewrite u:                                                                                                       [tex]\displaystyle u = arcsin(x)[/tex]

Step 3: Integrate Pt. 2

[Integral] Trigonometric Substitution:                                                           [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[1 - sin^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Rewrite:                                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[cos^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Simplify:                                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos^4(u)} \, du[/tex][Integral] Reduction Formula:                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{4 - 1}{4}\int \limits^a_b {cos^{4 - 2}(x)} \, dx + \frac{cos^{4 - 1}(u)sin(u)}{4} \bigg| \limits^a_b[/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4}\int\limits^a_b {cos^2(u)} \, du[/tex][Integral] Reduction Formula:                                                                          [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg|\limits^a_b + \frac{3}{4} \bigg[ \frac{2 - 1}{2}\int\limits^a_b {cos^{2 - 2}(u)} \, du + \frac{cos^{2 - 1}(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}\int\limits^a_b {} \, du + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Reverse Power Rule:                                                                     [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}(u) \bigg| \limits^a_b + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3cos(u)sin(u)}{8} \bigg| \limits^a_b + \frac{3}{8}(u) \bigg| \limits^a_b[/tex]Back-Substitute:                                                                                               [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(arcsin(x))sin(arcsin(x))}{4} \bigg| \limits^a_b + \frac{3cos(arcsin(x))sin(arcsin(x))}{8} \bigg| \limits^a_b + \frac{3}{8}(arcsin(x)) \bigg| \limits^a_b[/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x)}{8} \bigg| \limits^a_b + \frac{x(1 - x^2)^\Big{\frac{3}{2}}}{4} \bigg| \limits^a_b + \frac{3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Rewrite:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x) + 2x(1 - x^2)^\Big{\frac{3}{2}} + 3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:              [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e


Related Questions

A positive real number is 2 less than another. When 4 times the larger is added to the
square of the smaller, the result is 16. Find the numbers.

Answers

Answer:

by how i was taught its 2

Step-by-step explanation:

Kathryn is 1.4 meters tall. Convert her height to feet. Round to the nearest tenth.

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Answer:

4.59318

Step-by-step explanation:

I think you would have to round to the nearest tenth or something so i dont know but this is the exact answer.

MARKING AS BRAINLIEST!! Starr if given functions are inverse)!

Answers

Answer: They are inverses of each other

==========================================================

Explanation:

We'll need to compute h(f(x)) and f(h(x)) to see if we get x each time.

[tex]h(x) = 9x-4\\\\h(f(x)) = 9(f(x))-4\\\\h(f(x)) = 9\left(\frac{x+4}{9}\right)-4\\\\h(f(x)) = x+4-4\\\\h(f(x)) = x\\\\[/tex]

and,

[tex]f(x) = \frac{x+4}{9}\\\\f(h(x)) = \frac{h(x)+4}{9}\\\\f(h(x)) = \frac{9x-4+4}{9}\\\\f(h(x)) = \frac{9x}{9}\\\\f(h(x)) = x\\\\[/tex]

Both composite functions lead to x each time.

The equations h(f(x)) = x and f(h(x)) = x being true means each function is the inverse of the other.

Ok done. Thank to me:>

5. Which of the following linear expressions is a factor of the cubic polynomial x^3 + 9x² +16x-12?
(1) x+6
(3) r-3
(2) x-1
(4) x+2

Answers

Answer:

(1) x+6

Step-by-step explanation:

Possible rational zeroes include ±1, ±2, ±3, ±4, ±6, ±12

Check each answer choice with synthetic division:

1 | 1 9 16 -12

 __1_10_26

    1 10 26 | 14

-2 | 1  9   16 -12

   __-2_-14_-4

      1  7   2  | -16

-6 | 1 9     16 -12

    __-6_-18_12

      1  3   -2  | 0

Therefore, x+6 is a factor of the polynomial

Answer:

(1) x+6

Step-by-step explanation:

Add. 34.700 + 98.428 98.775 132.435 132.980 133.128

Answers

Answer:

34.700+98.42+98.775+132.435+132.980+133.128

What’s 12.71 divided 6.2?

Answers

Answer:

2.05

Step-by-step explanation:

12.71/6.2=2.05

The value of the expression 12.71 ÷ 6.2 using the division property will be 2.05.

What is Algebra?

Algebra is the study of algebraic expressions, while logic is the manipulation of those concepts.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to answer the problem correctly and precisely.

The numbers are given below.

12.71 and 6.2

Then the division of the decimal numbers 12.71 and 6.2 will be given by putting a divide sign between them. Then we have

⇒ 12.71 ÷ 6.2

⇒ 12.71 / 6.2

⇒ 2.05

The worth of the articulation 12.71 ÷ 6.2 utilizing the division property will be 2.05.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ2

Desde los extremos A y B de un tendedero de 240 cm de largo partes dos hormigas simultáneamente. La hormiga que sale de A avanza a 10 cm/s, y la que se mueve desde el extremo B lleva una carga, por lo que se desplaza a 6 cm/s. ¿A qué distancia del punto A se encontrarán y en cuánto tiempo? Traza una recta que represente el desplazamiento de cada una de las hormigas.

Answers

Ambas hormigas se encontraran a 15 segundos, y a 150 centímetros del punto A.

Dado que desde los extremos A y B de un tendedero de 240 cm de largo partes dos hormigas simultáneamente, y la hormiga que sale de A avanza a 10 cm/s, y la que se mueve desde el extremo B lleva una carga, por lo que se desplaza a 6 cm/s, para determinar a qué distancia del punto A se encontrarán y en cuánto tiempo se debe realizar el siguiente cálculo:

10 x 15 = 1506 x 15 = 90150 + 90 = 240

Por lo tanto, ambas hormigas se encontraran a 15 segundos, y a 150 centímetros del punto A.

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Mrs. Nisbet had 97 books in her classroom library. She received a grant to expand her classroom library. After spending the money, she had 213 books. What is the percent increase? *

Answers

Answer: 219

Step-by-step explanation:

Pleaseeeeeeeeeee help me

Answers

Answer:

[tex]\huge\boxed{6x-7y=21}[/tex]

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

[tex]m[/tex] - slope

[tex]b[/tex] - y-intercept (0, b)

We have:

[tex]y=\dfrac{2}{3}x-3\to m=\dfrac{2}{3};\ b=-3[/tex]

From answers:

[tex]6x-7y=21\qquad|-6x\\\\-7y=-6x+21\qquad|:(-7)\\\\y=\dfrac{6}{7}x-3\to m=\dfrac{6}{7};\ \boxed{b=-3}[/tex]

[tex]-\dfrac{2}{3}x+3y=6\qquad|+\dfrac{2}{3}x\\\\3y=\dfrac{2}{3}x+6\qquad|:3\\\\y=\dfrac{2}{9}x+2\to m=\dfrac{2}{9};\ b=2[/tex]

[tex]\dfrac{2}{3}x+3y=-3\qquad|-\dfrac{2}{3}x\\\\3y=-\dfrac{2}{3}x-3\qquad|:3\\\\y=-\dfrac{2}{9}x-1\to m=-\dfrac{2}{9};\ b=-1[/tex]

[tex]x+4y=12\qquad|-x\\\\4y=-x+12\qquad|:4\\\\y=-\dfrac{1}{4}x+3\to m=-\dfrac{1}{4};\ b=3[/tex]

Answer:

6x-7y=21

Step-by-step explanation: :)

we laid out strands of lights to decorate the school each strand was 12 feet long how many strands did we need if we needed at least 70 feet of lights

Answers

6 strands
70/12=5.83
Because you can’t have .8 of a strand, you would need to round up to the next whole number (6)

−x + 2y − z = 0
−x − y + 2z = 0
2x − z = 8

Answers

Step-by-step explanation:

several possibilities to solve this.

let's start with subtracting the second equation from the first

-x + 2y - z = 0

- -x - y +2z = 0

-------------------------

0 3y - 3z = 0

y - z = 0

y = z

now we use this in e.g. the first equation :

-x + 2z - z = 0

-x + z = 0

z = x (therefore, also x = y)

now we use this in the third equation :

2x - x = 8

x = 8 = y = z

What is -6(-3+5r)=-5-7r

Answers

Answer:

r = 1

Step-by-step explanation:

Use the distributive property to multiply −6 by −3+5r.

18−30r=−5−7r

Add 7r to both sides.

18−30r+7r=−5

Add −30r and 7r to get −23r.

18−23r=−5

Subtract 18 from both sides.

−23r=−5−18

Subtract 18 from −5 to get −23.

−23r=−23

Divide both sides by −23.

r=−23/−23​

Divide −23 by −23 to get 1.

r=1

Please answer I need step by step explanation

Answers

Answer:

10 cm

Simplified explanation/tl;dr: the small triangle is two thirds the size of the big triangle, so the missing side on the small triangle is two thirds the size of the same side on the big triangle

Long explanation/step by step:

It looks scary, but don't worry; for questions like this just find the ratio then multiply it by the similar side to find the missing side.

   This is what I mean: 8/12 simplified is 2/3 (4 is the common factor and 8/4 = 2 and 12/4 = 3). That's your fraction to multiply by.

   I chose 8 and 12 because look how the triangles are the same shape just different sizes, that means they're similar. the similar sides are just the same side on both triangles. (for this one, BC and GH are similar). to find how much smaller it is in fraction form, you just take two of the same sides and divide the small one by the big one. (big number becomes top, small becomes bottom)

   now just multiply 15 by 2/3 by using fraction multiplication. 15/1 x 2/3 = 30/3. Simplify that to 10/1 (3 is the common factor and 30/3 = 10 and 3/3 = 1). 10/1 = 10.

i need help with this question

Answers

Answer:

check online for more information

Write the equation of the line in slope intercept form that goes through points (-2, 5) and (3, 3)

Answers

Answer:

y=-2/5x+21/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-5)/(3-(-2))

m=-2/(3+2)

m=-2/5

y-y1=m(x-x1)

y-5=-2/5(x-(-2))

y-5=-2/5(x+2)

y=-2/5x-4/5+5

y=-2/5x-4/5+25/5

y=-2/5x+21/5

In two or more complete sentences, describe the transformation(s) that take place on the parent function f(x) = 3x to obtain the graph of f(x) = 3-x + 1 - 5.

Answers

Answer:

Logarithmic functions are the inverses of exponential functions.The logarithmic function y=loga(x)  is called the logarithmic function with base a .

When a constant c is added to the input of the parent function f(x)=loga(x), the result is a horizontal shift c units in the opposite direction of the sign on c. Our function is shifted 3 units to the right.

It is shifted 2 units vertical.(2 units down).

Answer:

Logarithmic functions are the inverses of exponential functions.The logarithmic function y=loga(x)  is called the logarithmic function with base a .

When a constant c is added to the input of the parent function f(x)=loga(x), the result is a horizontal shift c units in the opposite direction of the sign on c. Our function is shifted 3 units to the right.

It is shifted 2 units vertical.(2 units down).

Step-by-step explanation:

6. Kendrick bought 4 bags of bagels. Every bag had a dozen bagels. How many bagels did Kendrick buy?​

Answers

Answer:

Kendrick bought 48 bagels.

Step-by-step explanation:

For this question, you would simply have to multiply 4 by 12.

Dozen means 12.

4x12=48

48 bagels.

A swim teacher sells lesson packages. The best deal has the highest ratio of lessons to total cost.
Swim Lesson Packages
Number of Total Cost
Lessons
1
$10
5
$40
10
$80
15
$80
Which package is the best deal?
0 1 lesson for $10
O 5 lessons for $40
ОООО
10 lessons for $80
O 15 lessons for $80

Answers

Answer:

15 lessons for $ 80

Step-by-step explanation:

In case 1

Cost of 1 lesson = $10

In case 2

Cost of 1 lesson = 40/5 = $8

In case 3

Cost of 1 lesson = 80/10 = $8

In case 4

Cost of 1 lesson = 80/15 = $ 5.33

Hence,

The best deal is case 4 i.e 15 lessons for $ 80

What is the Area of this triangle? WILL MARK BRAINLIEST

Answers

Answer= 18

Explanation: you have to graph it on a grid paper first then make. Also trust me it’s the answer

Find the next three terms in the arithmetic sequence.
6, 12,18, 24,...

Answers

30, 36, 42

Hope this helped :)

Which of the following numbers can be expressed as a decimal that terminates? 3/2,2/3,3/4,5/7


Answers

Answer:

Step-by-step explanation:

An example of one fraction that does NOT terminate is 2/3.

2/3 = 0.666666666666666 ....  That's the easy way to tackle the problem. Pick out the ones that don't terminate.

5/7 is the other one. It does not terminate either. It has 6 digits in a block that keeps on repeating itself forever.

5/7 = .571428 571428 which goes on forever.

So the two that do terminate are

3/2 which = 1.5

3/4 which = 0.75

Write the expression in standard form,
(9+2i)(5-3i)

Answers

[tex](9+2i)(5-3i)\\\\=45-27i+10i-6i^2\\\\=45-17i+6~~~~~;[i^2 =-1]\\\\=51-17i[/tex]

[tex] \: \: \: \: \: \: [/tex]

[tex] = \: \: \: \: 51 - 17i[/tex]

refer to the attachment for explanationhope it helps

What is the slope of y = 4 – 2x
?

Answers

Answer:

m = -2

Step-by-step explanation:

Use the slope intercept formula y = mx + b

You would switch the order to get y = -2x + 4 to get it in the correct format.

You can then see that -2 is the slope based off the slope intercept formula

(b = y intercept)

(m = slope)

Solve each absolute value equation
1. [n - 3]= 5

Answers

Answer:

n=8

n=-2

Step-by-step explanation:

or,n-3=5

or,n=5+3

or,n=8

Now consider,

or,n-3=-5

or,n=3-5

or,n=-2

22. PLEASE HELP PLEASSSSSSEEEEEEEEEEEEEEE
15 points

Answers

Answer:

Step-by-step explanation:

2

6.
In a decorative figurine shop, it takes of an hour to paint 8
identical ceramic figurines. How long does it take to paint one
figurine? At the same rate, how long would it take to paint 12
figurines?

Answers

The time it would take to paint one figurine is 0.125 hour.

The time it would take to paint 8 figurine is 1.5 hours.

The first step is to determine the average rate. Average rate is the total ceramic figurines painted divided by the total time.

Average rate = 8 /1 = 8 figurines / hour

In order to determine how long it would take to paint 8 figurines, divide 12 by the  average rate.

1 / 8 = 0.125 hour

In order to determine how long it would take to paint 8 figurines, divide 12 by the  average rate.

12 / 8 = 1.5 hours

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(3x+14)= (7x+4)
Find X

Answers

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x=5/2

Decimal Form:

x=2.5

Mixed Number Form:

x=2 1/2

Step-by-step explanation:

x= 5/2 or the alternative form is x= 2 1/2 and/or x= 2.5

PLEQSE ANSWER ASAP!!!!!!!!!!!!!!!!

Answers

Answer: (a) identity

Step-by-step explanation:

Anything multiplied by 1 will be considered an equation that is identity property.

(b) A sum of money was to be shared among three friends Keisha, Tracey, and Kerry-Ann, in the
ratio 7:9:11 respectively. If Kerry-Ann received $3,300.00, find the sum of money that was
between the three friends.

Answers

The sum of the money that was  between the three friends is $8100.

Let x represent the amount of money given to the three friends to share.

Keisha, Tracey, and Kerry-Ann shared the money in the  ratio 7:9:11 respectively.

Since Kerry-Ann received $3300, hence:

(11/27) * x = 3300

11x/27 = 3300

x = $8100

The sum of the money that was  between the three friends is $8100.

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The average playing time of compact discs in a large collection is 35 minutes, and the standard deviation is 5 minutes.
a. What value is 1 standard deviation above the mean? 1 standard deviation below the mean? What values are 2 standard deviations away from the mean?
b. Without assuming anything about the distribution of times, at least what percentage of the times is between 25 and 45 minutes?
c. Without assuming anything about the distribution of times, what can be said about the percentage of times that are either less than 20 minutes or greater than 50 minutes?
d. Assuming that the distribution of times is approximately normal, about what percentage of times are between 25 and 45 minutes? less than 20 minutes or greater than 50 minutes? less than 20 minutes?

Answers

68% are within 30 minutes to 40 minutes, 95% are within 25 minutes to 45 minutes and 99.7% are within 20 minutes to 50 minutes

The three sigma rule states that 68% are within one standard deviation of the mean, 95% are within two standard deviation from the mean and 99.7% are within three standard deviation from the mean.

Given that μ = 35, σ = 5

68% are within one standard deviation = μ ± σ = 35 ± 5 = (30, 40)

95% are within two standard deviation = μ ± 2σ = 35 ± 2*5 = (25, 45)

99.7% are within three standard deviation = μ ± 3σ = 35 ± 3*5 = (20, 50)

`Find out more on three sigma rule at: https://brainly.com/question/25966249

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