(a) The compression of the spring is 7.4 cm.
(b) When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
Compression of the spring [ x ]
The compression of the spring is calculated by applying Hooke's law as follows;
F = kx
x = F/k
x = (mg)/k
x = (3 x 9.8)/400
x = 0.074 m
x = 7.4 cm
When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
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what is the formula for finding balance length
Answer:
Case 1: Balancing length when cell is shunted l1 = 150 cm = 1.5 m, Value of shunt = R = 5 ohm. Case 2: Balancing length when cell is shunted l1 = 175 cm = 1.75 m, Value of shunt = R = 10 ohm. Example 06: A cell balances against a length of 250 cm on potentiometer wire when it is shunted by a resistance of 10 ohms
2. A man pushes on a piano with mass 180 kg; it slides at constant velocity down a ramp that is inclined at 19.0° above the horizontal floor. Neglect any friction acting on the piano. Calculate the magnitude of the force applied by the man if he pushes (a) parallel to the incline and (b) parallel to the floor.
Answer: See below
Explanation:
Part (a):
As the velocity of the piano is constant, the net force on the piano is zero. The friction is also zero.
Here, F is the force applied by the man towards the inclined plane, mg is the weight of the piano and N is the normal force.
Applying Newton's law we get,
[tex]F = mg\sin \theta[/tex]
Substituting we get,
[tex]F &= \left( {180\;{\rm{kg}}} \right) \times \left( {9.8\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}} \right) \times \sin 19.0^\circ \\ &= 574.3\;{\rm{N}}[/tex]
Therefore, the force is 574.3 N
Part (b)
Here, the force F is applied parallel to the floor.
The friction is zero.
Applying Newton's law we get,
[tex]F\cos \theta &= mg\sin \theta \\ F &= mg\tan \theta[/tex]
Substituting we get,
[tex]F &= \left( {180\;{\rm{kg}}} \right) \times \left( {9.8\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}} \right) \times \tan 19.0^\circ \\ &= 607.4\;{\rm{N}}[/tex]
Therefore, the force is 607.4 N
A satellite circles the Earth in an orbit whose radius is twice the Earth’s radius. The Earth’s mass is 5.98 x 1024 kg, and its radius is 6.38 x 106 m. What is the period of the satellite?
Hello!
Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:
[tex]d = 2\pi r[/tex] ← The circumference of the orbit
speed = orbital speed, we will solve for this later
time = period
Therefore:
[tex]T = \frac{2\pi r}{v}[/tex]
Where 'r' is the orbital radius of the satellite.
First, let's solve for 'v' assuming a uniform orbit using the equation:
[tex]v = \sqrt{\frac{Gm}{r}}[/tex]
G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)
m = mass of the earth (5.98 × 10²⁴ kg)
r = radius of orbit (1.276 × 10⁷ m)
Plug in the givens:
[tex]v = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{(1.276*10^7)}} = 5590.983 m/s[/tex]
Now, we can solve for the period:
[tex]T = \frac{2\pi (1.276*10^7)}{5590.983} =\boxed{ 14339.776 s}[/tex]
The answer is not B.
Answer:
D
Explanation:
15m/ s
i hope this helps
The wavelength of the wave pictured below is... Select one: a. 1 cm b. 1.5 cm c. 2 cm d. 3 cm
Answer:
D. 3 cm
Wavelength is the distance between two crests or two troughs.
In the given picture, the distance between two adjacent crests is 3 cm.
Hence, the wavelength is 3 cm.
What can a line graph be used to do?
A. Make predictions
B. Make comparisons
C. Identify positive correlation
D. Identify negative correlation
Answer:
B
Explanation:
i's 100% paset bro.....
Wavelength is determined by dividing a wave's speed by its frequency. If a wave has a frequency of 1 hertz and a speed of 20 m/s, what is its wavelength?
Select one:
a. 80 m
b. 5 m
c. 0.05 m
d. 20 m
Answer:
D. 20m
Explanation:
this answer is 20 m.
wavelength = velocity / frequency
A car traveling at 120km/h towards west makes a right turn and travel north without changing its speed .120km/h120km/h.Using a vector diagram.Finding the magnitude and direction of the resultant velocity of the car
The magnitude and direction of the resultant velocity of the car will be 169.70 km/h and 45°.
What is a vector?The quantity which has magnitude, direction and follows the law of vector addition is called a vector.
A car traveling at 120 km/h towards west makes a right turn and travel north without changing its speed.
Then the magnitude (R) will be
R² = 120² + 120²
R² = 28800
R = 169.70 km / h
Then the direction of the resultant velocity will be
tan θ = 120 / 120
tan θ = 1
tan θ = tan 45°
θ = 45°
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Particles q1, 92, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C,
and q3= -2.50 x 10-6 C. Particles q1 and q2 are
separated by 0.500 m. Particles q and q3 are
separated by 0.250 m. What is the net force on q2?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-6 C
91
0.500 m
+2.50 x 10-6 C
+92
-2.50 x 10-6 C
93
0.250 m
Answer:
-1.35 N
Explanation:
Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²F = 450 × 10⁻³F = 0.45 N (+)Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²F = 1800 × 10⁻³F = 1.8 N (-)Net Force
0.45 - 1.8-1.35 NWhich of the following causes a car's passenger to lean in the direction
opposite the direction in which the car is turning?
OA. Friction
OB. Inertia
OC. Centripetal acceleration
OD. Centripetal force
Explanation:
This case is inertia.
Mass is directly proportional to inertia
Lester plays middle linebacker for dices football team. During one play, he made the following movements. First, he back-pedaled in the southern direction for 2.6 meters
Answer:
Explanation:
missing info .....
HELP!! ASAP!!
2. Describe the difference between polar covalent bonds and nonpolar covalent bonds using these two molecules - H2 and HCl. Which molecule contains a polar covalent bond and which molecule contains a nonpolar covalent bond? Explain your reasoning alongside describing the differences between the types of bonds.
3. How is the metallic bonding different than ionic or covalent bonding? What are some properties of metals that result from this type of bonding? Explain/connect how the nature of the bonding leads to the properties of metallic substances.
Answer:
The difference between polar covalent bonds and nonpolar covalent bonds using these two molecules - H2 and HCl are HCl is a polar covalent compound because the chloride ion is extra electronegative than the hydrogen ion.
Why HCl is polar and H2 is now no longer?HCl is a polar molecule. This is due to the fact the Chlorine (Cl) atom withinside the HCl molecule is extra electronegative and does now no longer proportion the bonding electrons similarly with Hydrogen (H). But H2 And Cl2 are nonpolar because of comparable electronegativity of each the atoms withinside the molecule H2 And Cl2 .
Hydrogen chloride is a diatomic molecule, such as a hydrogen atom H and a chlorine atom Cl related with the aid of using a polar covalent bond. The chlorine atom is an awful lot extra electronegative than the hydrogen atom, which makes this bond polar.
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Which refers to a material that causes a wave to bounce off of it?
A. absorber
B. reflector
C. conductor
D. insulator
Answer:
the answer to the question is a reflector
The glucometer applies a potential difference of 0.90 volts across a blood sample. The glucose concentration of the blood sample is 0.98 grams/litre. Determine the current in the blood sample.
The amount of current in the blood sample is determined as 0.12 A.
Current in the blood
The current in the blood is calculated by applying Ohm's law as shown below;
V = IR
where;
V is voltageI is currentR is resistanceFrom resistivity chart corresponding to 0.98 g/L, resistance, R = 7.4
I = V/R
I = 0.9 /7.4
I = 0.12 A
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Which object has the least thermal energy?
Answer:
2kg brick
Explanation:
2kg brick at 25 degrees.
Answer: A 2kg brick at 20*C
Explanation:
Particles q1, q2, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C,
and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.250 m. What is the net force on q2?
The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
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For a physics experiment, a solid cube is suspended from a spring scale. The gravitational force exerted on the cube is 0.714 N as measured when the object is suspended from a spring scale. When the suspended cube is submerged in water (ρ = 1000 kg/m3), the scale reads 0.450 N. What is the side of this cube in cm
The side of this cube will be 2.9996 cm. The net force on the solid cube is acting upward.
What is buoyancy force?
A fluid exerts an upward force against the weight of a partly or completely submerged item. The weight of the overlying fluid causes pressure to rise with depth in a column of fluid.
Given data;
Actual weight.W=0.714 N
Apparent weight,W'=0.450 N
The density of water,ρ=1000 kg/m³
The net force on the solid cube is;
Apparent weight = actual weight - buoyancy force
Buoyancy force = Actual weight - apparent weight
F=W-W'
F = 0.714 - 0.450
F= 0.264 N
The buoyancy force(F) is found as;
F = ρgV
0.264 = 1000 × 9.81 × V
V=2.69 × 10⁺⁵
The volume of a cube is found as;
V=a³
2.69 × 10⁺⁵ m³=a³
a=0.02996 m
As we know that 1 m = 100 cm
a=2.996 cm
Hence, the side of this cube will be 2.9996 cm.
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. Two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as u(r) = − Gm R1 −r − Gm R2 −r . This problem takes place far out in space and there are no other massive objects in the vicinity of the two planets. (a) Draw a graph of u as a function of position (r) along the line between the two planets. (b) There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2. What is the minimum speed v which will permit the projectile to reach station Beta?
(a) A graph of u as a function of position (r) along the line between the two planets is attached below.
(b) The minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]
What is gravitational potential energy?If an object is lifted, work is done against gravitational force. The object gains energy.
Given are two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as
u(r) = − (Gm /R1 −r) − (Gm / R2 −r) .
This problem takes place far out in space and there are no other massive objects in the vicinity of the two planets
(a) A graph of u (r) versus position (r) along the line between the two planets is attached in answer.
(b) There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2.
The range of the projectile is given by R = v²sin2θ / g
g = gravitational acceleration of Earth
If g = g(p) for planet , range R = v²sin2θ / g(p)..................(1)
The gravitational force of attraction = weight force
Gm² /d² = m g(p)
g(p) = Gm/d².........................(2)
For R = d/3, from equation (1), we have
d/3 = v²sin2θ / g(p)
Plug the expression for g(p) , we get
v = √ [Gm/3dsin2θ ]
For velocity to be minimum, sin2θ =1
So, the minimum velocity will be
v = √ [Gm/3d]
Thus, the minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]
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Waves can carry either ____ or __________ energy?
Answer:
ways can carry either __machanical___ or electromagnetic energy
Angel hits a ball with a ball. The action is the ball . What what is reaction force?
When Angel hits a ball with the ball. As the action is a ball as it is hitted. The reaction force is the force exerted on another ball.
Newton’s third law of motion describes the two forces, action and reaction forces. This states that for every action force, there is an equal and opposite reaction force.
As Angel hits a ball with another ball, the action is the ball as it is hit. The ball exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat, which is known as the reaction force.
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A spaceprobe in outer space is flying with a constant speed of 1.795 km/s. The probe has a payload of 1635.0 kg and it carries 4092.0 kg of rocket fuel. The rocket engines of the probe are capable of expelling propellant at a speed of 4.161 km/s. Then the rocket engines are fired up. How fast will the spaceprobe travel when all the rocket fuel is used up?
The speed by which the spaceprobe travels when all the rocket fuel is used up will be 29.262 m/sec.
What is the law of conservation of linear momentum?
According to the law of conservation of linear momentum before the collision is equal to the momentum after the collision. These laws state how momentum gets conserved.
Unit conversion;
1 km/sec = 1000 m/sec
Given data;
Spaceprobe speed = 1.795 km/s = 1795 m /sec
Probe mass = 635.0 kg
Fuel mass = 4092.0 kg
Expelled propellent velocity = 4.161 km/s = 41461 m/sec
From the momentum conservation principle;
[tex]\rm P_i = P_f \\\\ (m_p+m_f)v_i = m_pV - m_fv_p \\\\ V = \frac{(635+4092)1795+4092 \times 41461}{635} \\\\ V = 280540.7 \ m/sec \\\\ V = 28.05 m/sec[/tex]
Hence, the speed by which the spaceprobe travels when all the rocket fuel is used up will be 29.262 m/sec.
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A projectile is fired at an upward angle of 45.0º from the top of a 265-m cliff with a speed of .sm 185 What will be its speed when it strikes the ground below? (Use conservation of energy.)
The final velocity of the projectile when it strikes the ground below is 198.51 m/s.
Time of motion of the projectileThe time taken for the projectile to fall to the ground is calculated as follows;
h = vt + ¹/₂gt²
where;
h is height of the cliffv is velocityt is time of motion265 = (185 x sin45)t + (0.5)(9.8)t²
265 = 130.8t + 4.9t²
4.9t² + 130.8t - 265 = 0
solve the quadratic equation using formula method,
t = 1.89 s
Final velocity of the projectilevyf = vyi + gt
where;
vyf is the final vertical velocityvyi is initial vertical velocityvyf = (185 x sin45) + (9.8 x 1.89)
vyf = 149.322 m/s
vxf = vxi
where;
vxf is the final horizontal velocityvxi is the initial horizontal velocityvxf = 185 x cos(45)
vxf = 130.8 m/s
vf = √(vyf² + vxf²)
where;
vf is the speed of the projectile when it strikes the ground belowvf = √(149.322² + 130.8²)
vf = 198.51 m/s
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One support of the behavioral perspective is how B. F. Skinner’s ideas have brought to light how the __________ and __________ influence personality.
One support of the behavioral perspective is how B. F. skinner’s ideas have brought to light how the environment and learning influence personality.
What is the behavioral perspective?The behavioral perspective on personality and individual variations places an emphasis on quantifiable behaviors influenced by the environment and the results that follow.
The theoretical aim of behaviorism is the prediction and control of behavior given its natural science methodology.
Skinner's theories have made it clear how learning and the environment affect personality, which is one argument in favor of the behavioral approach.
One support of the behavioral perspective is how B. F. skinner’s ideas have brought to light how the environment and learning influence personality.
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The volume of the water in the graduated cylinder rose as some of the water was displaced by the table tennis ball. Find the volume of the ball using the formula
Vb = Vf – Vi
where Vb is the volume of the ball, Vf is the final volume of the water, and Vi is the initial volume of the water. Record the volume of the ball in Table A of your Student Guide.
What is the volume of the table tennis ball?
cm3
The approximate volume of table tennis ball is 80 cm³
What is volume?Volume is defined as the amount of space occupied by the three dimensional object. S I unit of volume is m³ or cm³.
To find the volume of tennis ball using graduated cylinder.
Step 1 - Fill the graduated cylinder half or full.
Step 2 - Mark the initial volume of the water i.e. 100 cm³ (Vi)
Step 3 - Put the tennis ball in the graduated cylinder. Some of the water was displaced by the table tennis ball.
Step 4 - Mark the Final volume of the water (Vf) i.e. 180 cm³
Step 5 = Calculate the volume by using Formula
Vb = Vf – Vi = 180 cm³ - 100 cm³ = 80 cm³
Hence the volume of tennis ball (Vb) is 80 cm³
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Answer:
40
Explanation:
A 3.42 kg steel ball strikes a massive wall at 14.3 m/s at an angle of α = 61.5° with respect to the plane of the wall. It bounces off with the same speed and angle as seen in the figure.
If the ball is in contact with the wall for 0.207 s, what is the average force exerted on the ball by the wall?
The magnitude of the average force exerted on the ball by the wall is 225.469 N.
What is impulse?The change in momentum is equal to the product of impact force applied while colliding and time for that impact.
Impulse F. t = m (Vf -Vi)
where, Vf is the final velocity and Vi is the initial velocity.
Given is a 3.42 kg steel ball strikes a massive wall at 14.3 m/s at an angle of α = 61.5° with respect to the plane of the wall. It bounces off with the same speed and angle. The ball is in contact with the wall for 0.207 s
Substitute the values into the expression, we get
Impulse = 2 x mvcosθ
Impulse= 2 x 3.42 x 14.3 x cos 61.5°
Impulse = 46.672 kg.m/s
The impact force can be written as
F.t = I
Put the given values, we have
F = 46.672 / 0.207
F = 225.469 N
Thus, the magnitude of force exerted by the wall is 225.469 N
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What is the current in a circuit that is powered by a 6.0 V battery and
connected in series by a 2.0 Ω resistor and a 12.0 Ω resistor?
A. 0.50 A
B. 3.0 A
C. 84.0 A
D. 0.43 A
Answer:
D. 0.43 A
Explanation:
First you will find the total resistance which is
R=R¹+R²
R=2+12
R= 14 ohms
I = V/R
I = CURRENT
V= VOLTAGE
R = RESISTANCE
I= 6/14
I =0.43 A
Which picture shows a boat riding on a trough?
Select one:
a. A
b. B
c. C
d. D
Answer:
B
Explanation:
Becky races Tom down the street .Becky , initially at a stop,takes 5.5 s to reach 30 m/s . What accelerated?
Becky's acceleration is 5.45 [tex]ms^2[/tex].
Acceleration = [tex]\frac{v-u}{t}[/tex]
where v= final velocity , u= initial velocity , t= time taken
according to the question :
initial veocity = 0 (it is at stop initially)
final velocity = 30m/s
time taken = 5.5 s
according to the formula acceleration = [tex]\frac{30-0}{5.5}[/tex]=[tex]5.45[/tex]
Hence Becky's acceleration is 5.45 [tex]ms^2[/tex].
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velocity and distance of free falling object dropped from rest
The diagram shows the speed and distance of a free-falling item dropped from rest. In the attachment, there is a graph.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The velocity and the time at the different points are;
A(0 sec ,0 m/sec)
B(1,9.8)
C(2,19.6)
D(3,29.4)
E(4,39.2)
F(5,49.0)
The point is plotted on the graph and get the graph.
The graph is attached in the attachment.
The complete question is;
Velocity and distance of free-falling object dropped from rest are given in the digrame. Draw the velocity-time graph for the given conditions.
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1. List some environmental challenges identified by the Brundtland Commission's overview, as well as a key strategy for addressing them. Identify urgencies that the Commission sees as necessary for an optimistic environmental future.
The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.
What is the Brundtland Commission?The Brundtland Commission was set up with the intention to achieve sustainable development. The tenure of the commission lasted from 1984 to 1987.
The commission identified the pillars of sustainable growth as economic growth, environmental protection, and social equality. The committee opined that environmental problem emanates from poverty in the southern region and reckless consumption of resources in the northern region.
The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.
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