the 3kg object in figure is released from rest at height of 5m on curved frictionless ramp.at the foot of the ramp is a spring of force constant 400N/m.the object slide down the ramp and into the spring, compressing it a distance x before coming momentarily to rest. a) find x
b)describe the motion of the object (if any) after the block momentarily comes to rest?

Answer:

r= 1.09×10^-4

Explanation:

Given

V=speed=4.0×10^5 m/s

B= magnetic field= 0.040 T

©=angle= 35°

m= mass of electron= 9.11×10^-31

q= charge of electron= 1.60×10^-19

solution

qv×B= mv²/r

qvBsin©=mv²/r

qBsin©=mv/r

r=mv/qBsin©

r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)

r= 1.09×10^-4 m

a) r = 1.09 * [tex]10^{-4}[/tex] m

b) Distance travelled : 6.845 *  [tex]10^{-4}[/tex] m    

An electron is a  stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

given

charge of electron : 1.6 * [tex]10^{-19}[/tex] C

mass of electron = 9.11 * [tex]10^{-31}[/tex] kg

v = 4.0 x 10 m/s

B =  0.040 T

theta = 35 degrees

since ,

force in magnetic field on electron = centripetal force

a) q(v*B) = m [tex]v^{2}[/tex] / r

q v B sin(theta) =  m [tex]v^{2}[/tex] / r

r =m v /q B sin(theta)

r =  9.11 * [tex]10^{-31}[/tex] * 4.0 x [tex]10^{5}[/tex]/ 1.6 * [tex]10^{-19}[/tex] sin (35)

r = 1.09 * [tex]10^{-4}[/tex] m

b)  far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr

 = 2 * 3.14 * 1.09 * [tex]10^{-4}[/tex] m  = 6.845 *  [tex]10^{-4}[/tex] m  

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Answer:

A

Explanation:

As you go deeper, the pressure increases because the water is going farther away from the air and atmosphere

The estimated density of the golf ball is  170  kg/m³

What is density?

Density is the ratio as Mass per unit Volume.

In displacement method,  

First , we measuring the volume of water displaced by an object which tell us the volume of the object then we will use the physical balance to determine its mass.

Then calculate the density by dividing the mass by the volume.

Here,  D = m/V

By displacement method , the estimated volume of golf ball is 100 cm³  and estimated mass is 600 g

Then ,

Density =  100 cm³ / 600 g = 0. 17 g/ cm³ = 170  kg/m³

So the estimated density of golf ball is  170  kg/m³

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Answer:

Magnification= -image distance/object distance

.253=image distance/33.5

image distance= 8.48 cm

Answer:

Their common velocity after the collision will be 5.5m/s

Explanation:

look at the attachment above ☝️

R=√20²+40²+2.20.40 cos 50

R=55 N

R/sin β = F/sin α

55/sin 50 = 40/sin α

α = 33°

The term temperature has to do with the  measure of an object's "hotness".

The term temperature has to do with how hot or cold a body is. In other words, the word temperature brings us to call to mind the degree of hotness or coldness of a body.

Succinctly put, the term temperature has to do with the  measure of an object's "hotness".

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So, the complete sentence is If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.

When the mass of the sun is larger, Earth moves around the sun at a faster pace and When the mass of the sun is smaller, Earth moves around the sun at a slower pace.

When Earth is closer to the sun, its orbit becomes faster and When Earth is farther from the sun, its orbit becomes slower.

When Earth is closer to the sun, there will be a hotter climate. A little movement that takes one closer to the sun could lead to a huge impact, as the sun is very hot.

So, it can be concluded that If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully for the best conditions.

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The distance from the rounded tip of the plate to the center of mass is 1.87 m.

The center of mass is a point inside or outside the mass where all of the mass is concentrated.

The y-coordinate of the centroid is given by the ratio of two definite integrals;

Yc = ∫ydm/∫dm,

where dm is a density function

For the uniform plate, δ does not change with position in the plate.

Yc = ∫yδdA/∫δdA

Yc = ∫ydA/∫dA.

dA is a horizontal slice of the plate with dimensions xdy.

Solving the parabola for x,

y = 0.5x²

x = ± √(y/0.50), where the negative value corresponds to the left half of the parabola and the positive to the right half.

dA = (√(y/0.50)

     = √(y/0.50))dy

     = 2(√(y/0.50))dy

The limits of integration are from zero to 1.870, the top of the plate.

∫ydA = ∫2y√(y/0.50)dy = 7.232 m³

∫dA = ∫2√(y/0.50)dy = 3.868 m²

∫ydA/∫dA =  7.232 m³/3.868 m²

∫ydA/∫dA =  1.869700 m

∫ydA/∫dA =   1.87 m

Thus, the distance from the rounded tip of the plate to the center of mass is 1.87 m.

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The speed of the first car just before the collision is 26.73 km/h.

When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.

m₁u₁ +m₂u₂ =(m₁ +m₂) v

Given a 808 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 632 kg. The two cars lock up and slide together with a speed of 15.0 km/h.

Second car is parked, so its velocity will be zero.

808 x u +632 x 0 = (808 +632 ) x 15

u  = 26.73 km/h

Thus, the speed of the first car just before the collision is 26.73 km/h

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Answer:horse

Explanation:

Greek terms psyche, which means "soul" or "mind," and logos, which means "the study of," are combined to form the english word psychology. The assertion is true.

Psychology is the name given to the scientific study of the mind and behavior. Psychologists are actively interested in researching and comprehending how the mind, the brain, and behavior work.

Psychology is a combination of the Greek words psyche, which means “soul” or “mind,” and logos, which means “the study of.”The given statement is corect.

Hence the best answer from the choices provided will be true.

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(a)  The charge stored in the 5.00-μF capacitor is 37.2  μC.

(b) The potential difference across the 10.0-μF capacitor is 3.72 V.

The capacitance of a capacitor is defined as the ratio of the charge stored and the potential difference between the capacitor.

The capacitance of a capacitor is denoted by C and expressed as

C = Q/V

Given, 5.00 μF, 10.0 μF, and 50.0 μF capacitors are connected in series across a 12.0-V battery.

(a) The equivalent capacitance is

1 / Ceq = 1 / C₁ +1 / C₂ + 1/ C₃

Substitute the values, we get

Ceq = 3.1  μF

The charge stored in 5.00-μF capacitor is

Q  = Ceq x V

Q = 3.1  μF x 12 V

Q = 37.2  μC

Thus, the charge stored in the 5.00-μF capacitor is 37.2  μC

(b) The potential difference across the 10.0-μF capacitor is given by

V = Q/C₂

Put the values, we get

V = 37.2 / 10

V = 3.72 V

Thus, the potential difference across the 10.0-μF capacitor is 3.72 V.

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The answer to this question is Initial velocity of plane will be 34236 m/s and 92437.2 Km is the distance travelled by it.

Three equation of motion are:-

Where v is final velocity, u in initial velocity, s is the displacement by the object, a is the acceleration and t denotes the time.

In question we have given deceleration as 6.34 m/s² and time as 1.5 hour which is equal to 5400 seconds.

Applying equation 1 to find the initial speed of plane

v = u + at

0 = u + (-6.34 × 5400)   {v=0 as plane will stop after 5400 sec}

u =  6.34 × 5400

u = 34236 m/s

Initial velocity of plane is 34236 m/s

Applying equation 2 to find the displacement of plane in that time period

s = ut + (1/2)at²

s = ( 34236 × 5400 )  - ( (1/2) × 6.34 × 5400² )

s = 5400 × ( 34236 - ((1/2) × 6.34 × 5400) )

s = 5400 × ( 34236 - 17118 )

s = 5400 × 17118 metres

s = 5.4 × 17118 Km

s = 92437.2 Km

Distance travelled by plane is 92437.2 Km

So, the initial velocity of plane will be 34236 m/s and the displacement of plane in that time period will be 92437.2 Km.

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Answer:

12.9m/s^2

Explanation:

As, a=(v^2)/r

=(58^3)/260

=12.9

The is organic compound with the correct chemical formula C4H9O2.

A model is a representation of reality. A model serves the purpose of prediction as well as explanation.

Looking at the model of the molecule we can see that it is the organic compound with the correct chemical formula C4H9O2. The molecule is shown in the image attached to this answer.

Missing parts:

There are several ways to model a compound. One type of model is shown.

What is the chemical formula for the molecule represented by the model?

CHO

C4H9O2

C4H8O

C3H8O2

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The loops must the coil have to generate a maximum emf of 2500 will be 439.

According to  Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.

Given data;

Area,A = 0.239 m²

Angular velocity,ω=373 rad/sec

Magnetic field,B=0.0639 T

Maximum emf,E= 2500V

The formula for the maximum induced voltage is;

E{max} = N ×  B × A × ω

2500 = N × 0.639 × 0.0239 × 373

N = 438.66

N = 439 \ turns

Hence, loops must the coil have to generate a maximum emf of 2500  will be 439.

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Answer: 11392.99

Explanation: I had the same problem and here are the steps:

Values:

N (Number of loops) = 2000

A (area) = 0.239

ω (angular velocity) = 373

B (magnitude) = 0.0639

ε = NABω

= (2000)(0.239)(373)(0.0639)

ε = 11392.99 (FINAL ANSWER)

The steel would expand by 4. 8 * 10^-3 cm

The change in length  ΔL is proportional to length  L. It is dependent on the temperature, substance, and length.

Using the formula:

ΔL= α LΔT

where  ΔL  is the change in length  L = 10cm

ΔT  is the change in temperature = 60° - 20° = 40° C

 α  is the coefficient of linear expansion = 1.2 x 10^-5 °C

Substitute into the formula

ΔL = [tex]1.2 * 10^-5 * 10 * 40[/tex]

ΔL = [tex]4.8 * 10 ^-3[/tex] cm

Therefore, the steel would expand by 4. 8 * 10^-3 cm

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Here, the calculated Magnitude of the load P is 2945.2 kN, the Longitudinal strain produced is 0.0005 and the decrease in length is 2 mm.

Given,

Length, L = 4 m

Outer diameter, D = 300mm, D= 0.3 m

Thickness, t = 50 mm, t = 0.05 m

Stress produced, σ = 75000 kN/m²

Young's modulus for cast iron, E = 1.5 x 10⁸ kN/m²

Calculating the diameter of the cylinder,

Diameter of cylinder, d = (D) – (2t) = 0.3 –( 2 × 0.05)

d= 0.2 m

(i) Magnitude of the load P:

Using the relation, σ =P/A

P = σ × A = 75000 × π /4 (D² – d² )

P= 75000 × π/4 (0.3² – 0.2²)

P= 75000 × π/4 (0.09 – 0.04)

P = 2945.2 kN

Hence, Magnitude of the load P is 2945.2 kN.

(ii) Longitudinal strain produced, e :

Using the relation, Strain, (e) = stress/E

e= 75000/(1.5 x 10⁸)= 0.0005

Hence, the Longitudinal strain produced is 0.0005.

(iii)Total decrease in length, dL:

The total decrease in length can be calculated using the strain as the ratio of change in length to the original length is known as Strain.

Strain = change in length/original length

e= dL/L

0.0005 = dL/4

dL = 0.0005 × 4m = 0.002m=2mm

Hence,the decrease in length is 2 mm.

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The first law states that the internal energy change of that system is given by Q − W . Since added heat increases the internal energy of a system, Q is positive when added to the system and negative when removed from the system.

The value of the electric current for the given conditions willl be  1939.02 A.

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

Ohm's law claims that the voltage across a conductor is direct to the current flowing through it. This current-voltage connection may be expressed mathematically as,

V=IR

15.9 V = I × 8.2 × 10³ Ω

I = 1939.02 A

Hence, the value of the electric current for the given conditions willl be  1939.02 A.

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a. The spring is compressed  by  0.174 m.

b.  The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.

c. The horizontal velocity of the dart at that time is  13.74 m/s.

d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.

The energy by virtue of its position is called the potential energy.

a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.

PE  of spring = 1/2 kx²

Put the values, we get

P.E = 0.940 = 1/2 x 62 x²

x = 0.174 m

Thus, the spring is compressed by 0.174 m.

b. Given is a 0.010 kg dart is fired straight up.

The vertical height is find out by

0.940 J = (0.010 kg) (9.8 m/s²) h

h = 9.6 m

Thus, the vertical distance the dart travels from its position is 9.6 m

c. From the conservation of energy principle, total mechanical energy is conserved.

1/2 mv² =mgh

v = √2gh

Plug the values, we get

v = √2 x 9.8x 9.6

v = 13.74 m/s

Thus, the horizontal velocity is  13.74 m/s.

d.  Time that dart spends in air, t = √2h/g

t = √(2x9.6)/9.81

t = 1.4 s

The horizontal distance from the equilibrium position at which the dart hits the ground.

Horizontal distance = (Velocity on x direction) x time

Horizontal distance = 13.74 m/s x 1.4s

Horizontal distance = 19.236 m

Thus, the horizontal distance is 19.236 m.

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a. The magnitude of the impulse which the player must impart to the ball is 17.25 kg.m/s.

b. The magnitude of average acceleration of the player's head during the impact is   195.66 m/s².

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

Impulse F. t = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

Given, a soccer player 'heads' a size 3 ball deflecting it by 40.0°, and keeps its speed of 13.20 m/s constant. A size 3 ball has a mass of approximately 2.000 kg.

a. Substitute the values into the expression, we get

Impulse (x) = 2 x (13.20 - 13.20cos40°)

Impulse  (x) = 3.088 kg.m/s

Impulse in y direction, is

Impulse (y) = 2 x  13.20sin40°

Impulse (y)  = 16.97 kg.m/s

so, the magnitude of impulse is

I = sq rt(Ix² + Iy²)

Put the values, we get

I = 17.25 kg.m/s

Thus, the magnitude of the impulse which the player must impart to the ball is 17.25 kg.m/s

b. The player's head has a mass of 2.90 kg. The brief time of the impact, 30.40 ms,

F.t = I

Put the given values, we have

F = 17.25 / 30.40 x 10⁻³

F = 567.434 N

From the Newtons second law of motion,

F = ma

Plug the values from the question, we have

567.434 N =  2.90 x a

a = 195.66 m/s²

Thus the magnitude of average acceleration of the player's head during the impact is  195.66 m/s².

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The mass and tension due to the system are as follows:

Tension is a type of pulling force due transmitted by means of a string or cable.

a) The mass of the child and scale = 104/9.81 = 10.6 kg

b) The tension T, in the cord attaching the child to the scale = scale reading = 104N

c) The tension T', in the cord attaching the scale to the ceiling = scale reading + weight of scale

T' = 104 + (0.5 * 9.81)

T' = 108.9 N

d) The sketch is attached in the picture

In conclusion, the tension is force exerted on the cord due to the weight of the scale and the baby.

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Answer:

i think the answer is 20.......

In the opposite figure, the work done by the force F to push the box upwards from the ground to the top of the inclined plane is 600 J.Option c is correct.

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

The displacement value from the triangle is;

[tex]\rm sin 30^0 = \frac{P}{H} \\\\ H=S =\frac{3 \ m}{sin 30^0} \\\\ S = 6\ m[/tex]

The work done is found as ;

[tex]\rm W= Fd \\\\ W = 100 \ N \times 6 \\\\ W= 600 \ J[/tex]

The force F in the opposing figure does 600 J of effort to lift the box from the ground to the top of the inclined plane.

Hence option c is correct.

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[tex]\large\boxed{Formula: I= \frac{Q}{t}}[/tex]

Let's solve!

The formula is given above.

Let's substitute the values according to the formula.

We'll have to divide the measure of charge by the given time.

[tex]I= \frac{40}{10}[/tex]

Final answer:

[tex]\large\boxed{= 4 \: Amps \: (A)}[/tex]

Hence, the current is 4 amps.

This is a uniform rectilinear motion (MRU) exercise.

To start solving this exercise, we obtain the following data:

To calculate distance, speed is multiplied by time.

We apply the following formula: d = v * t.

We substitute the data in the formula: the speed is equal to 4.6 m/s, the time is equal to 10 s, which is left as follows:

[tex]\bf{d=4.6\dfrac{m}{\not{s}}*10\not{s} }[/tex]

[tex]\bf{d=46 \ m}[/tex]

Therefore, the speed at 10 seconds is 46 meters.

[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

At 11.3°C the rod will just come into contact

Coefficient of linear expansion of aluminium [tex]\alpha_{Al}[/tex] = [tex]23*10^-^6[/tex] °[tex]C[/tex]

Coefficient of linear expansion of Brass [tex]\alpha_{B} =19*10^-^6[/tex] °[tex]C[/tex]

[tex]\alpha = \Delta{L}/Lo(T2-T1)[/tex]

For aluminium

[tex]\alpha_{Al} = \Delta{L}/Lo(T-0)[/tex]

[tex]\Delta{L_{1}} = (23*10^-^6*50*T)[/tex]

For Brass

[tex]\alphaB = \Delta{L_{2}/Lo(T-0)[/tex]

[tex]\Delta{L_{1} +\Delta{L_{2} =0.024cm(23*10^-^6*50*T)+(19*10-6*50*T) =0.024[/tex]

T =11.43 °C

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