Given :
The acceleration due to gravity on or near the surface of Earth is 32 ft/s/s
To Find :
From what height must a stone be dropped on Earth to strike the ground with a velocity of 136 ft/s.
Solution :
Initial velocity of stone, u = 0 ft/s.
Now, by equation of motion :
[tex]2as = v^2 -u^2 \\\\2\times 32 \times s = 136^2 -0^2\\\\s = \dfrac{136^2}{2\times 32}\ ft\\\\s = 289 \ ft[/tex]
Therefore, height from which stone is thrown is 289 ft.
9) If, after viewing a specimen at low power, you switch to high-dry power and, after using fine focus, cannot find the specimen, what things could you do to help yourself (before asking the instructor to assist you
Answer:
See the answer below
Explanation:
The best thing one can do in this case would be to return the microscope's objective to low power and then re-center the specimen before switching back to high-dry power.
Most of the time, what makes the specimen under the microscope to be out of focus at higher objective powers after being in focus at low power is because they are not properly centered on the stage. Hence, before calling on the instructor, it would be wise to first return to low power, re-center the specimen and bring it into focus after which the high power objective can be returned to and the fine focus adjusted to bring the image back to focus.
After doing the above and the specimen still does not come into focus, then the instructor can be called upon.
NEED HELP ASAP!!!!
A car drives around a racetrack for 30 seconds. What do you need to know to
calculate the average velocity of the car?
O A. The slope of the car's velocity-time graph
O B. The total displacement of the car
O C. The area under the position-time graph
O D. The slope of the car's position-time graph
A car drives around a racetrack for 30 seconds. To calculate the average velocity of the car we need to know about distance. from option B and D we can calculate velocity. Therefore option B and D is correct.
What is velocity ?Velocity is "rate of change of displacement with respect to time".
i.e. v= dx/dt. it is also defined as displacement over time.
i.e. v=Displacement/Time. Velocity shows how much distance can be covered in unit time. It's SI unit m/s. Dimension of velocity is [M⁰ L¹ T⁻¹].
Option A) The slope of the car's velocity-time graph.
it gives Velocity/time. we can not find average velocity with this data.
Option B) The total displacement of the car.
when we know displacement and time, we can calculate velocity. therefore this option is correct.
Option C) The area under the position-time graph.
This gives position×time, which is useless to find velocity.
Option D) The slope of the car's position-time graph.
this gives velocity of the car. Therefore this option is correct.
Hence option B and D is correct, we can calculate average velocity from them.
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Daisy walks across a force platform and the forces exerted by her foot during a step are recorded. The peak vertical reaction force is 1200 N (this force acts upward on Daisy). At the same instant, the braking frictional force is 200 N (this force acts backward on Daisy). How large is the resultant of these two forces? What is the direction of the resultant force?
Answer:
The direction of the resultant force is approximately 189.462º.
The magnitude of the resultant force is approximately 1216.553 newtons.
Explanation:
Let consider postive the direction of motion of Daisy's foot and the upward direction (perpendicular to direction of motion). Friction ([tex]f[/tex]), measured in newtons, is directed against motion, whereas normal force from ground to the foot ([tex]N[/tex]), measured in newtons, is in the upward direction. Then, resulting direction must be greater than 180º but less than 270º with respect to the axis of the direction of motion, which is found by the following formula:
[tex]\theta = 270^{\circ}-\tan^{-1} \frac{N}{f}[/tex] (1)
Where [tex]\theta[/tex] is the direction of the resultant force, measured in sexagesimal degrees.
If we know that [tex]N = 1200\,N[/tex] and [tex]f = 200\,N[/tex], then the direction of the resultant force is:
[tex]\theta = 270^{\circ}-\tan^{-1} \frac{1200\,N}{200\,N}[/tex]
[tex]\theta \approx 189.462^{\circ}[/tex]
The direction of the resultant force is approximately 189.462º.
The magnitude of the resultant force ([tex]F[/tex]), measured in newtons, is determined by Pythagorean Theorem:
[tex]F = \sqrt{f^{2}+N^{2}}[/tex]
[tex]F =\sqrt{(200\,N)^{2}+(1200\,N)^{2}}[/tex]
[tex]F \approx 1216.553\,N[/tex]
The magnitude of the resultant force is approximately 1216.553 newtons.
The charges on the proton and electron are typically measured in: Select the correct answer below: volts amperes coulombs daltons
Answer: columbs
Explanation:
Electrical charge are measured in columbs, usually demoted as C. Hence, the charges on proton and electron will be measured in Coloumbs. It typically measures the amount of electricity conveyed per second by a current of 1 ampere. The other units Given such as ; Volt is used for measuring voltage, which is the pressure in an electrical source. AMPERE is used for measuring the current flowing through an electrical circuit.
Dalton is a unit of mass and is about 1.660 * 10^-27 kg
A string has its 4th harmonic at 31.5 Hz. What is the fundamental frequency?
Unit= Hz
Answer:
7.9Hz
Explanation:
Step one:
given data
We are told that the fourth harmonic is at 31.5 Hz
We know that harmonics are a multiple of the fundamental frequency, such that if the fundamental frequency is 25Hz, then the second harmonic is
2nd= 2*25= 50Hz
3rd= 3*25= 75Hz........and so on
Step two:
In this problem, we are told that the 4th harmonic is 31.5Hz, that is
4th= 4*f= 31.5
Divide both sides by 4 to get f
f= 31.5/4
f= 7.9 Hz
Hence the first/fundamental frequency is 7.9Hz
Answer:
its 7.9 tried it on acellus
Explanation:
What is force? In physics class eleven
Answer:
Explanation:
In Physics, force is defined as: The push or pull on an object with mass that causes it to change its velocity. Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a directionForce is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction. The direction towards which the force is applied is known as the direction of the force and the application of force is the point where force is applied.
The Force can be measured using a spring balance. The SI unit of force is Newton(N).
A 0.049 kg bullet moving at 421 m/s strikes a stationary 4.7 kg wooden block. The bullet passes through the block and leaves with a velocity of 301 m/s. If the block was originally at rest, how fast does it move after being hit by the bullet? ANSWER ASAP
Answer:
The block moves at 1.25 m/s
Explanation:
Law Of Conservation Of Linear Momentum
It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of two bodies, then the total momentum is the sum of the individual momentums:
[tex]P=m_1v_1+m_2v_2[/tex]
If a collision occurs and the velocities change to v', the final momentum is:
[tex]P'=m_1v'_1+m_2v'_2[/tex]
Since the total momentum is conserved, then:
P = P'
Or, equivalently:
[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]
The bullet of m1=0.049 kg moves at v1=421 m/s. Then it strikes a wooden block of m2=4.7 kg originally at rest (v2=0).
After the collision, the bullet continues at v1'=301 m/s. The speed of the block can be calculated by solving for v2':
[tex]\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}[/tex]
[tex]\displaystyle v'_2=\frac{0.049*421+0-0.049*301}{4.7}[/tex]
Calculating:
[tex]\displaystyle v'_2=\frac{5.88}{4.7}=1.25\ m/s[/tex]
The block moves at 1.25 m/s
For this question you will be designing an investigation Carefully read the information below and respond to the prompt
Does the temperature of a liquid affect the amount of sugar it will dissolve? In other words, if you change the temperature of a liquid, is there a
relationship between the temperature and how much sugar can dissolve at that specific temperature?
Tell how you would test this question, being as scientific as possible (including the different variables, constants, hypothesis, safety considerations, data
tables, etc.) when you write about your test. Write down the steps you would take to find out if the temperature of a liquid affects the amount of sugar it
can dissolve
Answer:
See Explanation
Explanation:
Temperature affects the amount of sugar that will be dissolved in a liquid. It is general knowledge in chemistry that solutes tend to dissolve in hot solvents compared to cold solvents.
Hence, there is a positive relationship between dissolution of sugar in a liquid and increase in temperature.
To test this hypothesis, the variables are temperature and amount of solute. The volume of solvent and type of solvent must be held constant.
Different amounts of solute are dissolved in the same volume of solvent and heated to a constant temperature and the extent of dissolution of the sugar is observed for each experimental unit.
A control experiment is also set up in which different amount of sugar is dissolved in the same volume of solvent as above without heating and the results are compared.
Describe what a homogeneous electric field is, and where we find such
Answer:
no one really answers on here anymore but can u click on my profile and help me with my question
Explanation:
the answer is A homogeneous electric field has the same magnitude and direction at any place. A good example of a homogeneous field is the field between two charged metal plates. The field strength depends on the voltage U and the plate distance d.
*} The specipe heat capacity of body depends up on
(c mass of body
b) Tempreature rises (d) Nature of body
(а
(a Heat
given
Answer:
heat given , nature of body, and temperature rise
A tennis player's racket applies an average force of 200. newtons to a tennis ball for 0.025 second. The average force exerted on the racket by the tennis ball
is
Answer:
200N
Explanation:
The average force exerted on the racket by the tennis ball is equal to 200 Newton.
Given the following data:
Average force = 200 NewtonTime = 0.025 secondsTo determine the average force exerted on the racket by the tennis ball, we would apply .Newton's Third Law of Motion.
Newton's Third Law of Motion states that for every action there must exist an equal but opposite reaction. Thus, Newton's Third Law of Motion is a law based on action-reaction force pairs.
In this scenario, the tennis ball would exert the same magnitude of average force on the racket in accordance with Newton's Third Law of Motion.
Average force = 200 Newton
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27. The pressure at A is 9.5 atm and the water velocity is 10 m/s. What is the water velocity at point C
Answer:
10 m/s
Explanation:
A person on a bridge 25m above the water throws a rock straight downwards at 20m/s.
a. How long does it take to hit the water?
B how fast is it going when it hits?
Answer:
a) Δd=v₂Δt+[tex]\frac {1}{2}[/tex]aΔt²
v₂=0 (hits ground)
Δd=[tex]\frac {1}{2}[/tex]aΔt²
Δt²=Δd÷[tex]\frac {1}{2}[/tex]a
t=√25÷[tex]\frac {1}{2}[/tex](9.8) 9.8m/s²=gravity
t=5÷4.8
t=1.04s
b) a=[tex]\frac{v_2-v_{1} }{t}[/tex]
a×t=v₂-v₁
v₂=(a×t)+v₁
v₂=(9.8×1.04)+20
v₂=10.192 + 20
v₂=30.192
v₂=30.2m/s rounded
Who were the sepoys?
A.Indians who were part of the East India Company’s private army
B.members of the British army who were stationed in India
C.troops who were loyal to regional princes in India
D.mercenary forces who sold their services to the highest bidder in south Asia
Answer:
A. Indians who were part of the East India Company’s private army.
Explanation:
The sepoys were Indian soldiers who were recruited into the Company's army. Just before the rebellion, there were over 300,000 sepoys in the army, compared to about 50,000 British. The forces were divided into three presidency armies: Bombay, Madras, and Bengal.
Answer:
A-Indians who were part of the East India Company’s private army
Explanation:
4.5. During a snowball fight, your opponent distracts you by throwing a snowball at you with a high arc. She throws snowballs with a speed of 23.3 m/s and the first is thrown at 70.0 degrees. As you are watching the first snowball, she throws a second at a lower angle. (a) If both snowballs cover the same horizontal distance, at what angle (degrees) should the second be thrown? (b) If the second snow ball is going to hit you while your attention is still focused on the first snowball, how soon (s) after the first snowball is thrown must the second be thrown? In other words, what is the delay between the two throws that will have both arriving at the same time?
Answer:
(a) θ = 20°
(b) Time Delay = 2.84 s
Explanation:
(a)
This is the case of the projectile motion. In projectile motion, for the same launch speed, the range of a projectile is the same for the complimentary launch angles. Hence, the snowball will have the same range when launched at 70°, at an angle of:
[tex]\theta = 90^{0} - 70^{0}[/tex]
θ = 20°
(b)
The time of flight of snowball can be found by the following formula:
[tex]T = \frac{2\ u\ Sin \theta}{g}[/tex]
where,
T = Time of flight = ?
u = launch speed = 23.3 m/s
g = acceleration due to gravity = 9.81 m/s²
For θ = 70° :
[tex]T_{70} = \frac{(2)(23.3\ m/s)Sin70^{0}}{9.81\ m/s^{2}}[/tex]
T₇₀ = 4.46 s
For θ = 20° :
[tex]T_{20} = \frac{(2)(23.3\ m/s)Sin20^{0}}{9.81\ m/s^{2}}[/tex]
T₂₀ = 1.62 s
Therefore, the time delay can be calculated as follows:
[tex]Time\ Delay = T_{70} - T_{20}\\Time\ Delay = 4.46\ s - 1.62\ s\\[/tex]
Time Delay = 2.84 s
A. The angle at which the second ball should be thrown is 20°
B. The delay time between the two throws is 2.83 s
A. Determination of the angle at which the second ball should be thrown
From the question given above, we were told that:
The first ball is thrown at angle of 70°. Both balls covers the same range.From the above data, the angle at which the second ball should be thrown will be = 90 – 70 = 20°
B. How to determine the delay time between the two throws I. Determination of the time of flight at angle 70°Initial velocity (u) = 23.3 m/sAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = 70°Time of flight (T) =?T = 2uSineθ / g
T = (2 × 23.3 × Sine 70) / 9.8
T = 4.45 s
II. Determination of the time flight at angle 20°Initial velocity (u) = 23.3 m/sAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = 20°Time of flight (T) =?T = 2uSineθ / g
T = (2 × 23.3 × Sine 20) / 9.8
T = 1.62 s
III. Determination of the delay time Time of flight for 70° = 4.45 sTime of flight for 20° = 1.62 sDelay time =?Delay time = 4.45 – 1.62
Delay time = 2.83 s
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A spring has an elastic constant of 8.75 x 103 N/m. What is the magnitude of the force required to stretch this spring a distance of 28.6 cm from its equilibrium position?
Given :
A spring has an elastic constant of 8.75 x 10³ N/m.
To Find :
The magnitude of the force required to stretch this spring a distance of 28.6 cm from its equilibrium position.
Solution :
We know, force required to stretch a spring of spring constant k and distance x is given by :
[tex]F = \dfrac{kx^2}{2}[/tex]
Putting all given values, we get :
[tex]F = \dfrac{8.75\times 10^3 \times 0.286^2}{2}\\\\F = 357.86\ N[/tex]
Hence, this is the required solution.
Choose all the answers that apply.
Which of the following characteristics are found in flowering plants?
1. seeds
2. cones
3. reproduction by spores
4. vascular tissue
5. fruit
Answer:
Seeds And Reproduction By Spores
Explanation:
Did on Odyssey
5.38 An ideal spring has the spring constant k = 440 N/m. Calculate the
distance this spring must be stretched from its equilibrium position for
25 J of work to be done.
The spring stretched 0.476 meter from equilibrium position.
The work done is given as,
[tex]workdone=\frac{1}{2}kx^{2}[/tex]
Where x is the distance stretched from equilibrium position.
Given that, [tex]k=440N/m,W=25J[/tex]
[tex]25=\frac{1}{2}*440*x^{2} \\\\x^{2} =\frac{100}{440}=0.227\\\\x=\sqrt{0.227}=0.476m[/tex]
Therefore, the spring stretched 0.476 meter from equilibrium position.
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g 2. _______The property(ies) of a thermal system is (are)(A) temperature or (B) internal energy or (C) work.
Answer:
(A) temperature
Explanation:
Given that thermal properties of a material are those properties that can be observed or felt when the heat is added to the material.
Hence, in this case, the correct answer is "Temperature."
On the other hand, the internal energy is not a thermal property but rather an extensive property that cannot be assessed directly.
Also, work is not a thermal property but rather a process quantity.
Calculate the work needed to lift a block weighing 4 Newton’s a distance of 10 meters. Help me please.
Answer:
W = 40 J
Explanation:
The work done by a force is defined as the dot product of the force and displacement of the object. Therefore, the following formula can be used to find the work done:
[tex]W = F.d = Fd Cos\theta\\[/tex]
where,
W = Work Done = ?
F = Force = Weight of Block = 4 N
d = distance lifted = 10 m
θ = angle between force and displacement = 0°
Therefore,
[tex]W = (4\ N)(10\ m)(Cos\ 0^{0})[/tex]
W = 40 J
What is actually responsible for the "sensation of force" that causes concussions for many professional football
players?
Answer:
Acceleration.
Explanation:
American football is one of the sports with the highest physical contact, along with boxing, mixed martial arts and rugby. Therefore, the risk of injury for players who play the sport is higher. However, many injuries in this sport have to do with blows to the head, where concussions occur that generate small neuronal short circuits due to the impact, which can cause fainting, amnesia and even vomiting.
This type of injury occurs due to the acceleration of the players when impacting their rival, which increases their strength (since it is known that the greater the acceleration the weight acquires a greater impact force).
Answer:
Acceleration causes the force of concussions for many professional football players.
If a man weighs 720 N on the Earth, what would he weigh on Jupiter, where the free-fall acceleration is 25.9 m/s2
Answer:
On Jupiter, the man would weigh 1.903 kN
Explanation:
Given that;
a mans weight is 720 N
on earth, g = 9.8 m/s²
so mass on earth will be;
m = F/g = 720 / 9.8 = 73.4693 kg
In Jupiter, g = 25.9 m/s²
so the man's weight in Jupiter will be;
F = mg
F = 73.4693 × 25.9
F = 1902.8549
F = 1.903 kN
Therefore, on Jupiter, the man would weigh 1.903 kN
4
Do not with
02
A scientist cooled the air inside a container.
outside the
box
02
1
The temperature of the air changed from 20 °C to 0 °C
The volume of the container of air stayed the same.
Explain how the motion of the air molecules caused the pressure in the container to
change as the temperature decreased.
[3 marks]
Answer:
See answer below
Explanation:
As the temperature of the air decreased, its particles lose kinetic energy, and there is a reduction in the average speed of the particles which collide with each other, and with the walls of the container which in turn reflects into the reduction of the air pressure in the container.
PLEASEEEEE HELP TIMED TEST!!!! Which of following correctly shows the part of the wave that represents the wavelength
Answer:
the 2nd one is the right one
Explanation:
wave length is on top
The figure 2 correctly shows the part of the wave that represents the wavelength.
What is wave?A wave is a dynamic disturbance that propagates and causes a change in equilibrium of one or more parameters in physics, mathematics, and related subjects. Quantities may oscillate regularly around an equilibrium (resting) value at certain frequency if a wave is periodic.
A travelling wave is one in which the entire waveform moves in one direction; in contrast, a standing wave is one in which two periodic waves are overlaid and move in the opposing directions.
In a standing wave, there are some points where the wave amplitude seems reduced or even zero, and these positions have null vibration amplitudes. A wave equation (standing wave field comprising two opposing waves) or a one-way wave equation (for single wave propagation in a certain direction) is frequently used to describe waves.
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Maria began riding her bike, from rest, at 6 m/s. If she traveled 500 m, how
long was she riding?
Answer:
she rode for 166.66 seconds , which is about 2 minutes and 47 seconds
Explanation:
We use the kinematic equation that relates initial and final velocities with time and distance travelled that is shown below:
[tex]distance=\frac{(v_i+v_f)*t}{2}[/tex]
which in our case gives:
[tex]distance=\frac{(v_i+v_f)*t}{2}\\500=\frac{(0+6)*t}{2}\\500=3*t\\t=\frac{500}{3} \,s\\t\approx 166.66\,sec[/tex]
which reduced to minutes gives 2 minutes and approximately 47 seconds
What happens to the resistance of a wire as it gets wider
Answer:
it snaps
Explanation:
the more force you put on it, the wired out it gets than it snaps. I think
17. Calculate the amount of gravitational potential energy at the top of one 4 points hill. The mass of the coaster is 500 kg. The height from the hill to the valley is 59.6 m. Use 9.81 m/s^2 as the acceleration due to gravity. Record your calculations in joules. (Hint: Gravitational PE = mgh)
A. 292.338 m/s^2
B. 3037 J
C. 82.3 kg
D. 292,338 J
Answer: D. 292,338 J
This is the correct answer :)
g While driving down a highway, the air flow over an automobile establishes an overall heat transfer coefficient of 18 W/m2K. The passenger cabin of this automobile exposes 9 m2 of surface to the moving ambient air. One day when the ambient temperature is 33oC, how much cooling must the air conditioning system supply to maintain a temperature of 20oC in the passenger cabin
Answer:
2106 W
Explanation:
Given that
The coefficient of heat transfer, h = W/m².K
Area of cabin exposed to air, A = 9 m²
Initial ambient temperature, T1 = 33 °C
Final system temperature, T2 = 20 °C
To find the cooling rate needed, we use the formula
Q = h * A * ΔT
where, ΔT = T1 - T2
ΔT = 33 - 20
ΔT = 13 °C
Cooling rate, Q = 18 * 9 * 13
Cooling rate, Q = 2106 W
This means that the cooling rate needed is 2106 W
Describe a grand challenge in today's society?
1. The directional movement of ions by facilitated diffusion through protein channels is determined by
Answer:
The electrochemical gradient of the ion that is being transported.
Explanation:
Facilitated diffusion through protein is defined as a form of facilitated transport whereby passive movement of ions along concentration gradients are guided by the presence of other ions.
Thus, the electrochemical gradient of the ion being transported is what facilitates it
