The mean and the standard deviation are 233 and 208.95 respectively.
The mean of a distribution is its average, while the standard deviation is the summary of how far each data in the dataset, is to the mean.
First, we calculate the class midpoint (x) from the given intervals.
The class midpoint is the average of the intervals. So, we have:
X1 = (0+199)/2 = 99.5
X2 = (200+399)/2 = 299.5
X3 = (400+599)/2 = 499.5
X4 = (600+799)/2 = 699.5
X5 = (800+999)/2 = 899.5
X6 = (1000+1199)/2 = 1099.5
X7 = (1200+1399)/2 = 1299.5
So, the table becomes:
X values Frequency (f)
99.5 345
299.5 97
499.5 52
699.5 21
899.5 9
1099.5 8
1299.5 3
The mean of the distribution is:
This gives:
Mean = (99.5*345)+(299.5*97)+(499.5*52)+(699.5*21)+(899.5*9)+(1099.5*8)+(1299.5*3)/(345+97+52+21+9+8+3)
Mean = 124832.5/535 = 233
Therefore, Mean = 233
The standard deviation is calculated as follows:
So, we have:
Б =
√(99.5*(345-233)²+((299.5-233)² * 97)+((499.5-233)² * 52)+((699.5-233)² * 21)+((899.5-233)² * 9)+((1099.5-233)² * 8)+((1299.5- 233)² * 3)/ (345+97+52+21+9+8+3)
Standard Deviation = √(23357155.5)/535
= √43658.23
= 208.95
Б = 208.95
Hence, the mean and the standard deviation are 233 and 208.95 respectively.
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solve for a
(log(a-1))^2 =log10
A function assigns the values. The value a is 11.
What is a Function?A function assigns the value of each element of one set to the other specific element of another set.
The given logarithmic function can be solved as shown below.
[tex](\log(a-1))^2 =\log10\\\\(\log(a-1))^2 =1\\\\(\log(a-1)) =\sqrt1\\\\\log(a-1) = 1\\\\10^1 = a-1\\\\a = 11[/tex]
Hence, the value a is 11.
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Find the value of d.
Answer:
Step-by-step explanation:
Comment
The rule that governs this situation is the average of arc d and 94 = the angle where the chords cross.
Givens
Arc 1 = 94
Arc2 = d
interior angle = 75
Formula
(d + 94)/2 = interior angle/1
Solution
(d + 94)/2 = interior angle/1 Cross Multiply
1*(d + 94) = 75 *2 Combine
d + 94 = 150 Subtract 94 from both sides
d + 94 - 94 = 150 - 94 Combine
d = 56
Answer: d = 56
Which of the function correctly expresses the exponential model f(x)=6(14)^x with base of e
The exponential equation with a base of e is:
[tex]f(x) = 6*e^{2.639*x}[/tex]
How to change the base?
We start with:
[tex]f(x) = 6*(14)^x[/tex]
We want to rewrite this to:
[tex]f(x) = 6*(e^n)^x[/tex]
So we only need to find the value of n such that:
[tex]e^n = 14[/tex]
If we apply the natural logarithm to both sides:
[tex]ln(e^n) = ln(14)\\n = ln(14) = 2.639[/tex]
Then the exponential equation with base of e is:
[tex]f(x) = 6*e^{2.639*x}[/tex]
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Mark divided a basket of apples evenly into small bags. The number of bags was equal to the number of apples in each bag. Which could be the total number of apples?
A. 25 B. 27 C. 20 D. 18
There are 5 bags and each bag has 5 apples and total there are 25 apples , Option A is the correct answer.
What is a Perfect Square ?A perfect square is a number which can be written as the product of an integer with itself.
It is given that Mark divided a basket of apples evenly into small bags.
Let there be n no. of bags and therefore n number of apples in each bag
Then the total number of apples will be
n * n
n²
The value of total number of apples should be a perfect square,
In the option given only 25 is the perfect square
Therefore the equation can be made as
n² = 25
n = 5
There are 5 bags and each bag has 5 apples and total there are 25 apples.
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Many doctors rely on the use of intravenous medication administration in order to achieve an immediate response of a particular drug's effects. The concentration, C, in mg/L, of a particular medication after being injected into a patient can be given by the function G(t) = (- 8t ^ 2 + 56t)/(t ^ 2 + 3t + 2) where the time, t, is hours after injection. Part A: What is the domain of the function C(t) based on the context of the problem? Show all necessary calculations. Part B: Graph the function to determine the greatest concentration of the medication that a patient will have in their body.
Graphs are used to show the relationship between variables, where the variables are represented by a pair of axes.
The domain of the function is t ≥ 0
The greatest concentration of the medication is 5mg/L
Given that:
C(t) = [tex]\frac{-8t^2 + 56t}{t^2 +3t + 2}[/tex]
(a): The domain of the function
Because the medication concentration C(t) is a function of time (t), the domain is the possible values t can take.
t, cannot take negative values (i.e. it is not possible to have a negative time).
The least possible value of t is 0
So, the domain of the function based on the context is: t ≥ 0
(b) The greatest concentration of the medication
From the graph (see attachment), the maximum y-value is 5.
Hence, the greatest concentration of the medication is 5 mg/L
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ary
S
Homework: Homework Chapter
7 Section C
h
In a large casino, the house wins on its blackjack tables with a probability of 50.4%. All bets at blackjack are 1 to 1, which means that if you win, you gain the amount
you bet, and if you lose, you lose the amount you bet
a. If you bet $1 on each hand, what is the expected value to you of a single game? What is the house edge?
a. The expected value to you of a single game is $ -0.008
(Type an integer or a decimal)
The house edge is $ 0.008
(Type an integer or a decimal)
b. If you played 150 games of blackjack in an evening, betting $1 on each hand, how much should you expect to win or lose?
c. If you played 150 games of blackjack in an evening, betting $5 on each hand, how much should you expect to win or lose?
d. If patrons bet $4,000,000 on blackjack in one evening, how much should the casino expect to earn?
b. You should expect to lose $1.2
(Type an integer or a decimal)
c. You should expect to lose $6.00
(Type an integer or a decimal.)
d. The casino should expect to earn $ 32,000
ere to search
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Answer:
the answer is D
Step-by-step explanation:
Find the value of the function f(x) = x2 + 9x + 10, for x = -1.
Answer:
this is pretty easy we just replace the x with -1 so
(-1)^2+(-1)9+10
-1*-1=1
-1*9=-9
1+-9=-8
-8+10=2
f(-1)=2
Hope This Helps!!!
Another quick geometry question! Thanks!
only 1st main ,please do solve this asap
Answer:
(i) 8b-32
(ii) 7z^3+12z^2-20z
(iii) –q+p
(iv) a+ab
(v) 8x^2y+8xy^2-4x^2-7y^2
(vi) 4y^2-3y
Step-by-step explanation:
How much for $100 invested in 6% interest compounded monthly be worse after 20 years
Answer:
$331.02
Step-by-step explanation:
compound interest formula
A = P ( 1 + r/n)^nt
P = principal amount
r = rate decimal
n = number of times interest is compounded
t = time
A = 100 * (1 + .06/12)^(12*20)
A = 331.02
The following confidence interval is'obtained for a population proportion p: 0.87 < p < 0.93 What is the margin error E. The following confidence interval is'obtained for a population proportion p : 0.87 < p < 0.93 What is the margin error E.
The margin error of the confidence interval 0.87<p<0.93 is 0.03.
Given confidence interval 0.87<p<0.93.
We have been given the confidence interval 0.87<p<0.93 and we have to find out the margin error E. The margin error is a statistic expressing the amount of random sampling error in the results of a survey. The margin error depends on whether the problem is two tailed or half tailed but in this question we have not given whether it is two tailed or one tailed. The margin error is the half of the width of the confidence interval.
Confidence interval is 0.87<p<0.93.
Width of the interval= 0.93-0.87
=0.06
=0.03
Hence the margin of error is equal to 0.03.
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Use the point-slope formula to write an equation of the line that passes through (4,10) and has a slope of m= 3. Write the
answer in slope-intercept form (if possible).
The equation of the line is
Find the degree of a polynomial.
Answer:
What is Poly in gender. Gender is Gender "Female" "Non-binary" "Male". Poly is Triangle gender which means random gender.
Answer: Explanation: To find the degree of the polynomial, add up the exponents of each term and select the highest sum.
Step-by-step explanation:
forty percent of participants in a math contest were boys. fifty percent of the boys revived medals. the number of boys who received the medals was equal to the number of girls who received the medals. what percent of the participants were girls who received medal?
20% of the participants are girls and got a medal, and 33% of the girls got a medal.
What percent of the participants were girls who received medal?
First, we know that 40% of the participants were boys, so the other 60% were girls.
We know that 50% of the boys got a medal, so the percentage (in decimal form) of participants that are boys and got a medal is:
P = (0.4)*(0.5) = 0.2
So, 20% of the participants are boys and got a medal.
We know that the number of girls that got a medal is the same as the number of boys, then we also have that 20% of the participants are women who got a medal.
Then if the percentage of girls that got a medal is x (in decimal form), we must have that:
Q = (0.6)*(x) = 0.2
x = 0.2/0.6 = 0.33
x = 0.33
This means that 33% of the girls got a medal.
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Which standard form of the equation of the hyperbola has vertices at (0, 5) and (0, –5), and asymptotes y equals plus or minus five twelfths times x question mark
y squared over 25 minus x squared over 144 equals 1
y squared over 144 minus x squared over 25 equals 1
x squared over 25 minus y squared over 144 equals 1
x squared over 144 minus y squared over 25 equals 1
The equation first represents the hyperbola has vertices at (0, 5) and (0, –5), and asymptotes y = ±(5/12)x option first is correct.
What is hyperbola?It's a two-dimensional geometry curve with two components that are both symmetric. In other words, the number of points in two-dimensional geometry that have a constant difference between them and two fixed points in the plane can be defined.
We have:
Vertices of the hyperbola = (0, 5) and (0, -5)
Asymptotes: y = ±(5/12)x
The equations we have:
[tex]\rm \dfrac{y^{2}}{25}-\dfrac{x^{2}}{144}=1[/tex]
[tex]\rm \dfrac{y^{2}}{144}-\dfrac{x^{2}}{25}=1[/tex]
[tex]\rm \dfrac{x^{2}}{25}-\dfrac{y^{2}}{144}=1[/tex]
[tex]\rm \dfrac{y^{2}}{144}-\dfrac{x^{2}}{25}=1[/tex]
From the equation first:
[tex]\rm \dfrac{y^{2}}{25}-\dfrac{x^{2}}{144}=1[/tex]
The value of a and b are:
a = 12
b = 5
Vertices of the hyperbola = (0, b) and (0, -b)
Vertices of the hyperbola = (0, 5) and (0, -5)
Asymptotes: y = ±(b/a)x
Asymptotes: y = ±(5/12)x
Thus, the equation first represents the hyperbola has vertices at (0, 5) and (0, –5), and asymptotes y = ±(5/12)x option first is correct.
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Answer:
A
Step-by-step explanation:
which law would you use to simplify the expression...
Answer:
Power of a quotient
50% of 42 students are girls. How many of the students are girl's
Answer:
21 girls.
Step-by-step explanation:
50% of 42 students are girls.
So 42/2 = 21.
Therefore 21 of the students are girls.
Hope I helped
what figure was rotated
Answer: Rectangles
Step-by-step explanation:
Whenever rectangles are rotated about an axis, a cylinder is formed.
The following table shows the probability distribution for a discrete random
variable.
13
16
17
21
23
25
26
31
P(X) 0.07 0.21 0.17 0.25 0.05 0.04 0.13 0.08
What is the mean of this discrete random variable? (That is, what is E(X), the
expected value of X?)
A. 21.5
B. 22
) C. 21
D. 20.42
least common denominator of 1
[tex] \frac{1}{6} \: and \: \frac{7}{9} [/tex]
Need number 8 please!!
Using translation concepts, the graph of function g(x) = f(x) - 2 = x² - 2 is given at the end of the question.
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
In this problem, the functions are given as follows:
f(x) = x².g(x) = f(x) - 2 = x² - 2.Which means that g(x) is a shift down of 2 units of f(x), as given by the graph in the end of the question.
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help please
what is
Answer:
sure how can I help you? please tell me
n studying the sampling distribution of the mean, you were asked to list all the different possible samples from a small population and then find the mean of each of them. Consider the following: Personal phone calls received in the last three days by a new employee were 2, 4, and 7. Assume that samples of size 2 are randomly selected with replacement from this population of three values. What different samples could be chosen? What would be their sample means?
The Total outcome with replacement will be given by ,3² = 9, the mean of the samples will be 2 , 4.5 , 3 , 7 , 4
What is Mean ?Mean predicts the central tendency of a data set , It is determined by the ratio of sum of all the numbers to the total numbers in the data set.
On the basis of given data
The number given is 2,4,7
Size of the sample = 2 with replacement
The Total outcome with replacement will be given by
3² = 9
Possible outcome can be
2,2 2,4 2,7 4,4 4,2 4,7 7,7 7,2 7,4
The sample mean can be calculated as
(a+b)/2
(2+2)/2 = 2
similarly the mean of the samples will be 2 , 4.5 , 3 , 7 , 4
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What are m and b in the linear equation y=16+6x
Answer: B=16 and m=6
Step-by-step explanation:
in y=mx+b the number next to x is always the m/slope and the number without a variable is always the b.
If x=3 y=4 z=6 then 4x+8yz+3y equals
Answer:
216
Step-by-step explanation:
4x+8yz+3y
Let x=3 y=4 z=6
Substitute the values into the expression
4(3)+8(4)(6)+3(4)
Multiply first
12+192+12
Then add
216
What is the sum?
2/x^2+4/x^2
Answer:
6/x2
Step-by-step explanation:
Answer:
[tex]\mathsf {\frac{6}{x^{2}}}[/tex]
Step-by-step explanation:
[tex]\mathsf {\frac{2}{x^{2}} + \frac{4}{x^{2}} }[/tex]
[tex]\mathsf {\frac{2+4}{x^{2}}}[/tex]
[tex]\mathsf {\frac{6}{x^{2}}}[/tex]
segment CD has endpoints at C(0, 3) and D(0, 7). If the segment is dilated by a factor of 3 about point C, what is the length of the image of segment CD question mark (1 point)
The length of CD is 7-3=4.
Therefore, if we dilate by a scale factor of 3, the length is 4(3) = 12
Answer:
b) 12
Step-by-step explanation:
the length of the image is 12. i just know. trust me.
Find dy/dx if y =x^3+5x+2/x²-1
How would I go about finding this? I would appreciate if you could be as detailed as possible!
Differentiate using the Quotient Rule –
[tex]\qquad[/tex][tex]\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\[/tex]
According to the given question, we have –
f(x) = x^3+5x+2 g(x) = x^2-1Let's solve it!
[tex]\qquad[/tex][tex]\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\[/tex]
[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\[/tex]
[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\[/tex]
[tex]\qquad[/tex][tex] \pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\[/tex]
[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\[/tex]
[tex]\qquad[/tex][tex]\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\[/tex]
[tex]\qquad[/tex][tex]\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\[/tex]
[tex]\qquad[/tex][tex]\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\[/tex]
find the area for this pls
Answer:
3,36 in^2
Step-by-step explanation:
The geometric shape shown in image is called a trapezoid
to calculate the area of a trapezoid we use the following formula:
1/2*(a+b)*h (a and b are bases, h: height)
bases are 1.3 and 3.5 and height is 1.4
1/2(1.3 + 3.5)*(1.4) = 3,36 the area is stated in square units so the answer is
3,36 in^2
The table displays the scores of students on a recent exam. Find the mean of the
scores to the nearest 10th.
Score Number of Students
70
7
75
5
80
4
85
1
90
6
Answer:
78.7
Step-by-step explanation:
To find the mean, we can do the sum of all scores divided by the total amount of scores.
We see that there are 7 scores of 70, and 70*7=490.
We see that there are 5 scores of 75, and 75*5=375.
We see that there are 4 scores of 80, and 80*4=320.
We see that there is 1 score of 85, and 85*1=85.
We see that there are 6 scores of 90, and 90*6=540.
Now we can do [tex]\frac{490+375+320+85+540}{7+5+4+1+6} =\frac{1810}{23} =78.7[/tex]
