The advisor of a school club wants to select 4 of its 25 members to raise and lower the flag each day this week. She assigns a two-digit number from 01 to 25 to each student. What are the numbers that correspond to the members who will raise and lower the flag? Use the random number table below.
97836 74547 79986 58820 36071 17996 59066 36220 46340 66069 51761 41740 39326 52760
The numbers that correspond to the students are (Use a comma to separate answers as needed.)​

Answers

Answer 1

The numbers that correspond to the members who will raise and lower the flag are 97836, 74547, 79986, and 58820.

To select 4 members from a group of 25, we can use the random number table provided to assign numbers to each student and choose the corresponding numbers to identify the members who will raise and lower the flag. Let's go through the process step by step:

Step 1: Assign a two-digit number from 01 to 25 to each student.

We have 25 students, so we can assign each student a number from 01 to 25. Let's match the given numbers with the students:

97836 - Student 1

74547 - Student 2

79986 - Student 3

58820 - Student 4

36071 - Student 5

17996 - Student 6

59066 - Student 7

36220 - Student 8

46340 - Student 9

66069 - Student 10

51761 - Student 11

41740 - Student 12

39326 - Student 13

52760 - Student 14

Note: The remaining students from 15 to 25 are not provided in the given random number table, so we cannot assign numbers to them based on the given information.

Step 2: Choose the corresponding numbers to identify the members who will raise and lower the flag.

Since we need 4 members, we can select any four numbers from the given list that correspond to the assigned numbers of the students. Let's say we choose the first four numbers:

97836 - Student 1 (Will raise and lower the flag)

74547 - Student 2 (Will raise and lower the flag)

79986 - Student 3 (Will raise and lower the flag)

58820 - Student 4 (Will raise and lower the flag)

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Related Questions

a school dance committee consists of 2 freshmen, 3 sophomores, 4 juniors, and 5 seniors. If 7 freshmen, 7 sophomores, 7 juniors, and 9 seniors are eligible to be on the committee, in how man ways can the committee be chosen?

Answers

The committee can be chosen in 3,241,350 ways.

How many ways can the school dance committee be chosen?

Number of ways to choose freshmen committee members:

7 choose 2 (C(7, 2)) = 7! / (2! * (7-2)!)

= 21

Number of ways to choose sophomore committee members:

7 choose 3 (C(7, 3)) = 7! / (3! * (7-3)!)

= 35

Number of ways to choose junior committee members:

7 choose 4 (C(7, 4)) = 7! / (4! * (7-4)!)

= 35

Number of ways to choose senior committee members:

9 choose 5 (C(9, 5)) = 9! / (5! * (9-5)!)

= 126

Total number of ways = 21 * 35 * 35 * 126

= 3,241,350  ways.

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Please help I need help urgently

Answers

For the equation g(x) = 6 - 1, the graph of g(x) differs from the graph of f(x) by translating down 1 unit.

For the equation g(x) = 2 + 1, the graph of g(x) differs from the graph of f(x) by translating up 1 unit.

In the Desmos Graphing Calculator, when entering the equation f(x) = 6 and g(x) = 6-1, we can observe the difference between the graphs of f(x) and g(x).

The equation f(x) = 6 represents a horizontal line at y = 6. The graph of f(x) is a straight line parallel to the x-axis, passing through the y-coordinate 6.

On the other hand, the equation g(x) = 6 - 1 represents a line that is one unit below the line represented by f(x). The graph of g(x) is a parallel line to the graph of f(x), but shifted downward by one unit.

Therefore, the correct answer is:

The graph of g(x) differs from the graph of f(x) by translating down 1 unit.

Similarly, when entering the equation f(x) = 2 and g(x) = 2 + 1, we can observe the difference between the graphs of f(x) and g(x).

The equation f(x) = 2 represents a horizontal line at y = 2. The graph of f(x) is a straight line parallel to the x-axis, passing through the y-coordinate 2.

The equation g(x) = 2 + 1 represents a line that is one unit above the line represented by f(x). The graph of g(x) is a parallel line to the graph of f(x), but shifted upward by one unit.

Therefore, the correct answer is:

The graph of g(x) differs from the graph of f(x) by translating up 1 unit.

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NO LINKS!!! URGENT HELP PLEASE!!​

Answers

In a right triangle ABC, where angle C is the right angle, the cosine of angle A is equal to option C: cos B.

How to Find Cosine of an Angle of a Right Triangle?

Using the definition of cosine, we can express the cosine of angle A in the right triangle as cos(A) = adjacent side / hypotenuse, which is BC / AC.

Considering angle B, it is the complementary angle to angle A. Since the sum of the angles in a triangle is 180 degrees, we have angle A + angle B + angle C = 180 degrees.

Angle C is 90 degrees, we can rewrite it as angle A + angle B + 90 degrees = 180 degrees, which simplifies to angle A + angle B = 90 degrees.

By rearranging the equation, we get angle B = 90 degrees - angle A.

Now, we can substitute angle B in the cosine expression: cos(A) = adjacent side / hypotenuse = BC / AC = cos(B).

Therefore, cos(A) is equal to cos(B), corresponding to option C.

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Answer:

B)  sin (90° - A)

Step-by-step explanation:

In a right triangle ABC, we are told that angle C is the right angle.

As C = 90°, and since the interior angles of a triangle sum to 180°, the other two angles, A and B, are complementary angles (sum to 90°). Therefore:

A = 90° - BB = 90° - A

The sine and cosine of complementary angles have a special relationship. For two complementary angles, the cosine of one equals the sine of the other. So for our right triangle ABC, the cosine of A equals the sine of B, and the cosine of B equals the sine of A:

cos A = sin Bcos B = sin A

Substituting B = 90° - A, we can say that:

[tex]\large\boxed{\cos A = \sin (90^{\circ} - A)}[/tex]

[tex]\hrulefill[/tex]

This can be proven by using the sine and cosine trigonometric ratios.

[tex]\boxed{\begin{minipage}{9.4 cm}\underline{Trigonometric ratios} \\\\$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf O$ is the side opposite the angle. \\\phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}[/tex]

In right triangle ABC:

Side AB is opposite angle C, so it is the hypotenuse.Side BC is opposite angle A and adjacent angle B.Side AC is opposite angle B and adjacent angle A.

Therefore, using the trigonometric ratios:

[tex]\cos A=\dfrac{AC}{AB}[/tex]                    [tex]\sin B=\dfrac{AC}{AB}[/tex]

[tex]\cos B=\dfrac{BC}{AB}[/tex]                    [tex]\sin A=\dfrac{BC}{AB}[/tex]

Thus proving that cos A = sin B, and so cos A = sin (90° - A).

please help me, i literally have 0 clue what any of this means

Answers

a. The function, (A + N) (t)  = 5. 31t² -102t + 1338

b. The total number of Army personnel and Navy personnel from 1990 to 2002 is given by the function 5. 31t² -102t + 1338

c. (A + N)(4) = 1014.96

d.  The total number of Army personnel and Navy personnel from 1990 to 2002 is 1014.96

How to determine the values

We need to know that functions are described as expressions, rules or laws showing the relationship between two variables.

These variables are the dependent and independent variables.

From the information given, we have;

A(t) = 3.36t² - 59. 8t + 735

N(t) = 1.95t² - 42.2t + 603

Then, we have;

a. (A + N) (t)

Add the functions, we get;

3.36t² - 59. 8t + 735 + 1.95t² - 42.2t + 603

collect the like terms, we have;

5. 31t² -102t + 1338

c. (A + N)(4) = 5.31(4)² - 102(4) + 1338

expand the bracket, we have;

(A + N)(4) = 84.96 - 408 + 1338 = 1014.96

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Please help me please

Answers

$1600 is the correct answer…………
1600 is the answer ……

Question 1 of 10
What is the location of the point on the number line that is
A = 2 to B = 17?
OA. 11
OB. 9
O C. 12
O D. 10
of the way from

Answers

The location of the point on the number line that is of the way from A = 2 to B = 17 is 9.5, which is option E. None of the above.

To find the location of the point on the number line that is of the way from A = 2 to B = 17, we use the formula:

Midpoint = (A + B) / 2

Where A = 2, B = 17

Midpoint = (2 + 17) / 2

= 19/2

= 9.5

To find the location of the point on the number line that represents a particular fraction of the distance from A to B, we can use the following formula:

point = A + (fraction * (B - A))

where A = 2 and B = 17. Let's put these values ​​into the formula and calculate the position:

Point = 2 + (Fraction * (17 - 2))

We need to determine the value of Fraction. represents a fraction. Represents the distance from A to B.

Answer choices are given as decimals, not fractions, so convert to fractions.

OA: 11 = 11/20

OB: 9 = 9/20

OC: 12 = 12/20

OD: 10 = 10/20

Then plug each fraction into the formula to see which option is Make sure you give the correct position.

OA: point = 2 + (11/20 * (17 - 2)) = 2 + (11/20 * 15) = 2 + 8.25 = 10.25

OB: point = 2 + (9/20 * (17 - 2)) = 2 + (9/20 * 15 ) = 2 + 6.75 = 8.75

OC: Points = 2 + (12/20 * (17 - 2))

= 2 + (12/20 * 15)

= 2 + 9

= 11 44​​44

D: points = 2 + (10/ 20 * ( 17 - 2))

= 2 + (10/20 * 15)

= 2 + 7.5

= 9.5 of 2 passes after 17

The point representing (11/20) is at position 11.

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A company is tracking a number of complaints received on its website. During the first 4 months, they
record the following numbers of complaints: 18, 22, 26, 30. What is the explicit rule for the number of
complaints they will received in the nth month? After how many months will the complaints reach 126?

Answers

To find the explicit rule for the number of complaints received in the nth month, we can observe the pattern in the given data. The number of complaints increases by 4 each month.

So, we can write the explicit rule as follows:

Number of complaints (n) = 18 + 4(n - 1)

To find the number of months it will take for the complaints to reach 126, we can set up an equation:

18 + 4(n - 1) = 126

Simplifying the equation:

4(n - 1) = 126 - 18

4(n - 1) = 108

n - 1 = 27

n = 28

Therefore, it will take 28 months for the number of complaints to reach 126.

How many feet of fencing will George need for the dog run?
22 feet
68 feet
76 feet
82 feet


HELP

Answers

the answer to the question  is 76

Which equation has no solution?

Answers

helloos, i think the answer is the last option "4 + 6(2 + x) = 2(3x + 8)" because 4 + 6(2+x) = 6x + 16 and 2(3x + 8) = 6× + 16 as well. so, 6x + 16 = 6x + 16 has no solution because 0x = 0. therefore, x has no solution. I hope this helps you to understand it a little

What conclusion can be drawn from the following? State the property used (transitive, symmetry, contrapositive, etc.).
~ c ~ f, gb, pf, c~b

Answers

The property used here is the negation of equality.

The statement, “c ~ f, gb, pf, c~b” shows that c is not equal to f, and c is not equal to b. There is no conclusion that can be drawn from gb and pf, as there is no information given about their relationship. Hence, the property used here is the negation of equality (the tilde symbol ‘~’ represents negation of equality).Negation of Equality:When two objects or quantities are not equal to one another, we use the symbol ‘~’. The negation of equality means that two given things are not equal to each other. For example, if a ≠ b, then we can write it as a~b. Similarly, if c ≠ d, then we can write it as c~d.The given statement c~f, gb, pf, c~b shows that c is not equal to f and c is not equal to b. However, there is no conclusion that can be drawn from gb and pf.

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I need help with this

Answers

Answer:

y=(x-1)(x-6)

so x=1 or x=6

Calculate the area of the trapezium.
10 cm
9 cm
8 cm
Not to scale

Answers

Answer:To calculate the area of a trapezium, we need the lengths of its parallel sides (the bases) and the distance between them (the height). Given that the trapezium is not to scale, we assume the 10 cm, 9 cm, and 8 cm measurements refer to the lengths of the three sides.

Let's label the trapezium as ABCD, where AB is the longer base, CD is the shorter base, and AD and BC are the non-parallel sides.

Given:

AB = 10 cm (longer base)

CD = 8 cm (shorter base)

AD = 9 cm (non-parallel side)

To calculate the area of the trapezium, we can use the formula:

Area = (1/2) * (AB + CD) * height

However, the height is not given directly. We can calculate it using the Pythagorean theorem by considering triangle ADB.

Using the Pythagorean theorem, we have:

AD^2 = AB^2 - BD^2

Rearranging the equation to solve for BD:

BD^2 = AB^2 - AD^2

BD^2 = 10^2 - 9^2

BD^2 = 100 - 81

BD^2 = 19

BD = √19 cm (approx.)

Now that we have BD, we can use it as the height of the trapezium.

Area = (1/2) * (AB + CD) * height

Area = (1/2) * (10 + 8) * √19

Area = (1/2) * 18 * √19

Area = 9 * √19 cm² (approx.)

Therefore, the area of the trapezium is approximately 9√19 cm².

Step-by-step explanation:

Determine values that would make f ( x ) = 3 − x x 2 − 4 equal 0.

Answers

The value x = 3 would make the function f(x) equal to 0.

How to determine the values that would make f ( x ) = 3 − x x 2 − 4 equal 0.

To determine the values that would make the function f(x) = (3 - x)/(x^2 - 4) equal to 0, we set the numerator equal to 0 since a fraction is equal to 0 when its numerator is equal to 0.

So we solve the equation:

3 - x = 0

Solving for x, we find:

x = 3

Therefore, the value x = 3 would make the function f(x) equal to 0.

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2tablets 3times a day 14 day supply 15 tablets per bottle what is the quantity needed

Answers

6 bottles are required for a 14 day supply.

One bottle contains 15 tablets and the dosage is two tablets thrice daily for 14 days, we need to find the quantity of tablets required. Let's calculate it. Quantity needed We know,

Total tablets required=Tablets required

per day x Days

To find the total tablets required, we first need to find the tablets required per day. Tablets required per day Given that,2 tablets are taken thrice daily,

Therefore the tablets required

per day= 2 x 3 = 6 tablets Per day, 6 tablets are required.

Total tablets required Now we can find the total tablets required by multiplying the tablets required per day by the number of days. Hence,

Total tablets required = Tablets required per day x Days= 6 tablets/day x 14 days= 84 tablets14 day supply has to be made with the given 15 tablets per bottle.

Hence, Quantity needed = Total tablets required/ Tablets per bottle= 84/15 = 5.6 or 6 bottles

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Use a calculator to find the following:
Round your answers to the nearest tenth.

Answers

The answers that are rounded to the nearest tenth are:

(a) [tex]\sin^{-1}(.4590)=\bold{0.5}[/tex](b) [tex]\cos^{-1}(.8992)=\bold{0.5}[/tex](c) [tex]\tan^{-1}(1.0456)=\bold{0.8}[/tex]

What are Trigonometric Functions?

Trigonometric functions are also known as Circular Functions can be simply defined as the functions of an angle of a triangle. It means that the relationship between the angles and sides of a triangle are given by these trig functions.

The basic trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant.

(a)

[tex]\sin^{-1}(.4590)[/tex]

Apply rule: (a) = a

[tex](0.459)\thickapprox\bold{0.5}[/tex]

[tex]=\arcsin(\text{x})=0.5[/tex]

(b)

[tex]\cos^{-1}(.8992)[/tex]

Apply rule: (a) = a

[tex]\left(0.453\right)\thickapprox\bold{0.5}[/tex]

[tex]=\arccos(\text{x})=0.5[/tex]

(c)

[tex]\tan^{-1}(1.0456)[/tex]

Apply rule: (a) = a

[tex]\left(0.808\right)\thickapprox\bold{0.8}[/tex]

[tex]=\arctan(\text{x})=0.8[/tex]

Hence, this has been proved.

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Find the sum of the first 9 terms of the following series, to the nearest integer.
3, 15/4 , 75/16

Answers

The sum of the first 9 terms of the series is approximately

11

How to find the sum of the first 9 terms

Given data

3, 15/4, 75/16, ...

To find the sum of the first 9 terms of the series, we'll need to find a pattern and then use the formula for the sum of a geometric series. The series you provided seems to be a geometric series with a common ratio of 5/4.

The first term (a₁) is 3, and the common ratio (r) is 5/4.

The formula for the sum of a geometric series is given by:

Sum = a₁ * (1 - rⁿ) / (1 - r),

where n is the number of terms.

Plugging in the values, we have:

Sum = 3 * (1 - (5/4)⁹) / (1 - 5/4).

Sum ≈ 3 * (1 - 1.953125) / (1 - 1.25)

≈ 3 * (-0.953125) / (-0.25)

≈ 3 * 3.8125

≈ 11.4375.

Rounding to the nearest integer = 11

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Which steps can be taken to translate the phrase “the difference in the number of servings and four”? Check all that apply. Replace “the difference” with subtraction. Replace “the number of servings” with a variable, x. Replace “four” with 4. Replace “the difference” with addition. Write the expression x minus 4. Write the expression 4 minus x.

Answers

The correct steps to translate the phrase "the difference in the number of servings and four" are:

Replace "the difference" with subtraction.

Replace "the number of servings" with a variable, x.

Write the expression x minus 4.

The steps that can be taken to translate the phrase "the difference in the number of servings and four" depend on how the phrase is intended to be expressed mathematically. Let's examine each option:

A) Replace "the difference" with subtraction.

This step is correct since "the difference" implies subtraction. However, it doesn't address the other parts of the phrase.

B) Replace "the number of servings" with a variable, x.

This step is also correct since "the number of servings" can be represented by a variable, such as x. This allows for a more general representation.

C) Replace "four" with 4. Replace "the difference" with addition.

This step is incorrect. "The difference" does not imply addition but rather subtraction. Additionally, replacing "four" with 4 changes the meaning of the phrase. If we want to express the difference between the number of servings and four, we need to subtract four from the number of servings.

D) Write the expression x minus 4.

This step is correct. By replacing "the number of servings" with the variable x and expressing the difference as subtraction, we get the expression x minus 4. This accurately represents the phrase mathematically.

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What is an equivalent to b(little 3) x (b(little 3)?

Answers

Answer:

[tex] b^6 [/tex]

Step-by-step explanation:

To multiply powers with the same base, add the exponents.

[tex] b^3 \times b^3 = b^{3 + 3} = b^6 [/tex]

26
Order Of Operations 1
Use tiles to create an expression that is equal to 26.4
4
7
5
X
6
9
7
8
I
9
3
Do
X

Answers

The expression (4 + 7) × 5 - X × 6 ÷ 9 + 7 × 8 - I ÷ 9 + 3 equals 26.4.

To create an expression equal to 26.4 using the given tiles, we can use the following mathematical operations:

(4 + 7) × 5 - X × 6 ÷ 9 + 7 × 8 - I ÷ 9 + 3

how the expression breaks down:

1. (4 + 7) = 11

2. 11 × 5 = 55

3. 55 - X × 6 = 26.4 (solve for X)

  Solving the equation, we find that X = 6.1

4. 55 - 6.1 × 6 = 18.6

5. 18.6 ÷ 9 = 2.0667 (rounded to four decimal places)

6. 2.0667 + 7 × 8 = 58.0667

7. 58.0667 - I ÷ 9 = 26.4 (solve for I)

  Solving the equation, we find that I = 3

8. 58.0667 - 3 ÷ 9 = 26.4

Therefore, the expression (4 + 7) × 5 - X × 6 ÷ 9 + 7 × 8 - I ÷ 9 + 3 equals 26.4.

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How do I find the measure of AC?

Answers

The measure of AC is 8 units.

How to find the side of a secant?

If two secant segments are drawn to a circle from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.

Therefore,

10(10 + 2x) = 9(9 + 2x + 3)

100 + 20x = 9(12 + 2x)

100 + 20x  =  18x + 108

100 - 108 = 18x - 20x

-8 = -2x

divide both sides by -2

x = -8 / -2

x = 4

Therefore,

AC = 2(4)

AC = 8 units

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whats the range and funcion

Answers

The range refers to the spread or Variation of values in a dataset or the output values of a function. A function is a mathematical relation that assigns unique output values to input values.

To clarify, are you referring to finding the range of a dataset and describing what a function is? If so, I can provide an explanation for both.

The range is a concept in mathematics that refers to the set of all possible output values of a function or a dataset. It represents the spread or variation of the values in the dataset or the function's output. In simple terms, the range is the difference between the maximum and minimum value.

For example, let's say we have a dataset {2, 4, 6, 8, 10}. The minimum value in this dataset is 2, and the maximum value is 10. Therefore, the range would be 10 - 2 = 8. So, the range of this dataset is 8.

On the other hand, a function is a relation between a set of inputs (called the domain) and a set of outputs (called the range). It assigns each input value to a unique output value. Functions are often represented by equations or formulas. They are widely used in mathematics to model various relationships and phenomena.

For instance, consider the function f(x) = 2x + 3. This function takes an input value x, multiplies it by 2, and then adds 3 to it. The output value, represented as f(x), is the result of this operation. So, if we input x = 2 into the function, we get f(2) = 2(2) + 3 = 7.

Functions can have different forms and properties, such as linear, quadratic, exponential, etc. They can be used to describe real-world situations, solve problems, and analyze data.

In summary, the range refers to the spread or variation of values in a dataset or the output values of a function. A function is a mathematical relation that assigns unique output values to input values.

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Prompt: The following four images show several steps in a visual proof of the Pythagorean Thoerem.
1. Choose an image (2,3, or 4) and answer the questions.
A. How does this image change from the previous image?

For example, if you choose image three, describe what transformations were used to get image two.
B. Choose one to figure in your image, and explain how the length of the figure are related to the figure in image one. For example, if you choose figure 5 in image three, describe how its lengths are related to the figure in image one.
C. How does the length of the figure you describe in 1b relate to the Pythagorean Theorem? For example, if you describe figure 5 in image three, explain how it’s links, relate to a^2+b^2 = c^2.
2. How does the visual proof demonstrate the Pythagorean Theorem? Hint: describe how the figures labeled 5 through 9 related to figures two and 10 an image 4.

Answers

The area of the larger square is equal to the sum of the areas of the two smaller squares. In image 3, the smaller squares are replaced by rectangles with the same areas, and in image 4 these rectangles are rearranged to form the same square as in image 2.

1. Image 2A. Image 2 is formed by rotating image 1, that is, the angle and lengths of the legs stay the same, only the position of the triangle changes.

Image 2 is formed from image 1 by rotating the right-angled triangle clockwise about point B through the angle of 90°. B. The lengths of the triangle in image 2 are related to the lengths of the triangle in image 1 through the Pythagorean Theorem.

In image 1, a = 4 and b = 3, so [tex]c^2 = a^2 + b^2 = 4^2 + 3^2 = 16 + 9 = 25[/tex]. Thus, c = 5.

Since image 2 is just a rotation of image 1, the lengths of the sides remain the same, that is, a = 4, b = 3, and c = 5. C. The length of the hypotenuse of the triangle in image 2 is c = 5, which is the same as the hypotenuse of the triangle in the image.

1. This verifies the Pythagorean Theorem, which states that the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse.

That is, [tex]a^2 + b^2 = c^2[/tex]; where a, b, and c are the lengths of the legs and hypotenuse of the triangle.

2. The visual proof demonstrates the Pythagorean Theorem by showing that the sum of the areas of the squares constructed on the legs of a right triangle is equal to the area of the square constructed on the hypotenuse of the triangle.

Image 2 shows a right triangle with legs of length 3 and 4 units and a hypotenuse of length 5 units. Squares are constructed on each of the sides of the triangle, and the areas of these squares are compared.

The smaller squares on the legs of the triangle have areas of 9 and 16 square units, respectively, while the larger square on the hypotenuse of the triangle has an area of 25 square units.

Thus, the area of the larger square is equal to the sum of the areas of the two smaller squares. In image 3, the smaller squares are replaced by rectangles with the same areas, and in image 4 these rectangles are rearranged to form the same square as in image 2. This demonstrates that the Pythagorean Theorem holds true for all right triangles.

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The triangle and the rectangle have the same area.
All lengths are in cm.
7x + 2
a Form an equation in x.
b Solve your equation to find x.
c Work out the area of the shapes.
1
2x + 7

Answers

The length of one side of the equilateral triangle in terms of x is 6x.

To find the length of one side of the equilateral triangle in terms of x, we need to consider the perimeter of both the rectangle and the equilateral triangle.

The perimeter of a rectangle is given by the formula:

Perimeter of rectangle = 2(length + width)

In this case, the length of the rectangle is 7x cm, and the width is 2x cm. Substituting these values into the formula, we have:

Perimeter of rectangle = 2(7x + 2x) = 2(9x) = 18x

We are told that the equilateral triangle has the same perimeter as the rectangle.

Since an equilateral triangle has all sides equal, the perimeter can be calculated by multiplying the length of one side by 3.

Therefore, we have:

Perimeter of equilateral triangle = 3(side length)

Since the perimeter of the equilateral triangle is equal to the perimeter of the rectangle (18x), we can set up the equation:

3(side length) = 18x

Dividing both sides of the equation by 3, we get:

side length = 6x

Hence, the length of one side of the equilateral triangle in terms of x is 6x.

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The complete question may be like: A rectangle measures 2x cm by 7x cm. An equilateral triangle has the same perimeter as the rectangle. What is the length of one side of the triangle in terms of x?

I dont know how the answer

Answers

The median from the histogram is 5

What is histogram?

A histogram is a graph used to represent the frequency distribution of a few data points of one variable.

The median is the value in the middle of a data set.

The total frequency of the distribution is

1+4+5+4+2+1+1+1+1

= 20

The median term will be on

20+1)/2

= 10.5th

Therefore form the graph the 10.5 th term falls in the class of 5

This means that the median class is 5.

Therefore the median from the histogram is 5

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a circular wheel of diameter 35 cm makes 100 revolutions in 1 min. calculate the distance covered by the wheel in half an hour. Answer in km

Take pie= 22/7

Answer ASAP

Answers

Answer: To calculate the distance covered by the wheel in half an hour, we need to determine the total number of revolutions the wheel makes in that time and then convert it to the distance covered.

Given:

Diameter of the wheel = 35 cm

Radius of the wheel = Diameter/2 = 35/2 = 17.5 cm = 0.175 m (converting to meters)

Number of revolutions in 1 minute = 100

First, let's calculate the circumference of the wheel:

Circumference = 2 * π * radius

Using the value of π as 22/7:

Circumference = 2 * (22/7) * 0.175

Circumference = 1.1 m

Now, we can find the number of revolutions the wheel makes in half an hour:

Number of revolutions in 30 minutes = 100 revolutions/minute * 30 minutes

Number of revolutions in 30 minutes = 3000 revolutions

Finally, we can calculate the distance covered by the wheel:

Distance covered = Circumference * Number of revolutions

Distance covered = 1.1 m * 3000

Distance covered = 3300 m

Converting the distance to kilometers:

Distance covered = 3300 m / 1000 = 3.3 km

Therefore, the wheel covers a distance of 3.3 km in half an hour.

Step-by-step explanation:

MNPQ ~ RSTU. What are the values of c,y and z. Please show work too.

Answers

Answer:

x = 15 , y = 9 , z = 115°

Step-by-step explanation:

since the figures are similar then the ratios of corresponding sides are in proportion, that is

[tex]\frac{NP}{ST}[/tex] = [tex]\frac{MN}{RS}[/tex] ( substitute values )

[tex]\frac{x}{25}[/tex] = [tex]\frac{18}{30}[/tex] ( cross- multiply )

30x = 450 ( divide both sides by 30 )

x = 15

and

[tex]\frac{TU}{PQ}[/tex] = [tex]\frac{MN}{RS}[/tex] ( substitute values )

[tex]\frac{y}{15}[/tex] = [tex]\frac{18}{30}[/tex] ( cross- multiply )

30y = 270 ( divide both sides by 30 )

y = 9

the corresponding angles in similar figures are congruent , so

∠ M = ∠ R , that is

z = 115°

Jane is fencing in her backyard. The yard is a rectangular area where one side is the back of her house. The fence will go around only the other 3 sides. The side opposite the house is the same length as the house, which is 25 feet. Jane will use 120 feet of fencing.
Which equation can Jane use to decide how long each of the other two sides of her fence can be?

Answers

Answer: Jane can use the equation x = 47.5.

Step-by-step explanation:

From the given information, we know that one side opposite the house is 25 feet, and Jane will use a total of 120 feet of fencing. Since the fence goes around the other three sides of the yard, the combined length of the other two sides will be equal to 120 - 25 = 95 feet.

To determine the length of each of the other two sides, we can set up an equation:

2x = 95

The factor of 2 appears because there are two sides of equal length. By summing up the lengths of the other two sides, we obtain 2x.

Simplifying the equation, we have:

x = 95 / 2


x = 47.5

X=47.5 is the answer

A(-1, 2), B(3, 5) and C(4, 8) are the vertices of triangle ABC. Forces whose magnitudes are 5N and 3√10N act along vectors AB and CB respectively. Find the direction of the resultant of the forces.​​

Answers

The direction of the resultant of A(-1, 2), B(3, 5) and C(4, 8) are the vertices of triangle ABC, forces is [tex]$2\sqrt{3}$[/tex] radians.

Given, A(-1, 2), B(3, 5) and C(4, 8) are the vertices of triangle ABC, and forces whose magnitudes are 5N and 3√10N act along vectors AB and CB respectively.

We need to find the direction of the resultant of the forces.

Therefore, let's solve this by using the parallelogram law of forces which states that:

If two forces acting simultaneously at a point are represented in magnitude and direction by the adjacent sides of a parallelogram drawn from the point, then their resultant is represented in magnitude and direction by the diagonal of the parallelogram passing through that point.

From the above, the adjacent sides of a parallelogram drawn from point B can be represented as `AB` and `BC`.

Therefore, the diagonal of the parallelogram passing through B represents the magnitude and direction of the resultant of the two forces acting at point B.

Therefore, we first need to determine the position vector of points A, B, and C.

i.e. position vector of point A:

[tex]\vec{A} = \begin{bmatrix}-1\\2\end{bmatrix}$$Position vector of point `B`:$$\vec{B} = \begin{bmatrix}3\\5\end{bmatrix}$$[/tex]

Position vector of point C:

[tex]$$\vec{C} = \begin{bmatrix}4\\8\end{bmatrix}$$[/tex]

We know that the force acting along vector `AB` is 5 N and along vector `CB` is `3√10` N.

Let the angle between the vectors `AB` and `BC` be `θ`.

We know that,

[tex]$$\text{Magnitude of the resultant of the forces} = \sqrt{(5)^2 + (3√10)^2 + 2(5)(3√10)\cos(θ)}$$[/tex]

And direction of the resultant of the forces `θ` can be given by

[tex]$$\tan(θ) = \frac{5(3√10)\sin(θ)}{5^2 + (3√10)^2 + 2(5)(3√10)\cos(θ)}$$[/tex]

Substitute the values of the magnitude of the resultant of the forces and find the value of θ.

The resultant of the forces can be represented in the magnitude and direction as:

[tex]$$\vec{R} = \begin{bmatrix}3\\5\end{bmatrix} - \begin{bmatrix}-1\\2\end{bmatrix} + \begin{bmatrix}4\\8\end{bmatrix} = \begin{bmatrix}6\\11\end{bmatrix}$$[/tex]

Therefore, the direction of the resultant of the forces is [tex]$2\sqrt{3}$[/tex] radians.

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Lesson 1: What Is a Function?

A. Distinguish between relations and functions.
B. Calculate domain and range of functions algebraically.
C. Identify domain and range of functions graphically

Answers

The answer is B. Calculate domain and range of functions algebraically

Select the correct answer from each drop-down menu.
Which term describes the surrounding area of this image?
4

Answers

The surrounding area of this image is a called a Background. Option C

This area is also called a negative shape. Option A

How to determine the area

From the information given, we have to determine the area of the image shown, we can see that image is made up of two horses racing.

The horses are inserted on a plane surface which is called a background.

Also, we can see that the background is a negative space.

Note that a solid piece of sculpture occupies space, and makes the space around it come to life.

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The complete question:

Which term describes the surrounding area of this image?

The surrounding area of this image is called

Surroundings

Foreground

Background

This area is also called a

Negative

Positive

Neutral

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