Answer:
N1 Sin θ1 = N2 sin θ2 Snell's equation
Sin θ2 = 1 / 1.33 * Sin 40
Sin θ2 = .752 * .643 = .483
θ2 = 28.9 deg
How many generations passed if a generation is 1/3 lifetime and approximate lifetime is 70 years
88 generations have passed.
A generation is a collective term for all individuals who were born and are still alive at around the same period. The average time frame, commonly regarded to be between 20 and 30 years, during which children are born, grow up, become adults, and start having children is another way to put it. It is a structural term used to describe the parent-child relationship in kinship terminology.
In social science, the terms "generation" and "cohort" are sometimes used interchangeably to refer to "individuals within a defined population who experience the same key events over a certain period of time." These birth cohorts, usually referred to as "social generations," are frequently employed in popular culture and have served as the foundation for sociological study.
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please help me solve this worksheet its graded
The unit conversion of 1.5 x 10⁸ Gm to m = 1.5 x 10¹⁷ m.
The unit conversion of 2.6 x 10⁻⁵ nm = 2.6 x 10⁻²⁰ Mm.
The unit conversion of 2.72 x 10⁻⁵ μm = 2.72 x 10⁻¹¹ m.
The unit conversion of 2.56 x 10⁻³ cm = 2.56 x 10⁻⁸ km.
The unit conversion of 2 hr = 7,200 seconds.
The unit conversion of 2 h 30 min = 9,000 seconds.
What is unit conversion?Unit conversion involves the change of unit of a substance from one base to another.
Converting 1.5 x 10⁸ Gm to m1.5 x 10⁸ Gm = 1.5 x 10⁸ x 10⁹ m = 1.5 x 10¹⁷ m
Converting 2.6 x 10⁻⁵ nm to Mm2.6 x 10⁻⁵ nm = 2.6 x 10⁻⁵ x 10⁻⁹ x 10⁻⁶ m = 2.6 x 10⁻²⁰ Mm
Converting 2.72 x 10⁻⁵ μm to m2.72 x 10⁻⁵ μm = 2.72 x 10⁻⁵ x 10⁻⁶ m = 2.72 x 10⁻¹¹ m
Converting 2.56 x 10⁻³ cm to km2.56 x 10⁻³ cm = 2.56 x 10⁻³ x 10⁻² m x 10⁻³ km/m = 2.56 x 10⁻⁸ km
Converting 2 hours to seconds2 hr = 2 x 3600 s = 7,200 seconds
Converting 2 h 30min to seconds2 h 30 min = 7,200 seconds + 1800 s = 9,000 seconds
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A bird glides for 24 minutes and covers 2.6 kilometers. What was its average speed?
Answer:
6.5 km/ h
Explanation:
24 minutes = 24/60 = 0.4 hours
v = 2.6 / 0.4 = 6.5 km/h
Hope this helps
A CT scan uses a rotating X-ray source mounted on a circular ring to capture three dimensional images of a body (see Figure
43.2 on page 521 of the textbook). One rotation of the X-ray source produces one sliced image of the body.
A specific CT scan machine has a circular ring with radius 44 cm (diameter 88 cm), and the mass of the X-ray source mounted
on the circular ring is 26 kg. The ring rotates at a constant rate of 21 rad/s. Answer the following questions.
(a) What is the tangential speed of the X-ray source in m/s?
(b) How many degrees does the X-ray source turn in 100 milliseconds?
(c) What is the magnitude of the centripetal force on the X-ray source?
(d) How many seconds does it take to take one image?
(e) What is the frequency of the rotation of the X-ray source in the unit of Hz?
Answer:
rsgc
Explanation:
bsf xg
A student is running at her top speed of 5.5 m/s to catch a bus, which is stopped at the bus stop. When the student is still a distance 40.4 m from the bus, it starts to pull away, moving with a constant acceleration of 0.173 m/s^2.
(a) For how much time does the student have to run at 5.5 m/s before she overtakes the bus?
(b) For what distance does the student have to run at 5.5 m/s before she overtakes the bus?
(c) When she reaches the bus, how fast is the bus traveling?
(d) If the student's top speed is 2.70 m/s , will she catch the bus?
(a) The time taken before the student catches the bus is 11.52 seconds.
(b) The distance the student have to run before she overtakes the bus is 63.36 m.
(c) The speed of the bus is 2.0 m/s.
(d) If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.
Time elapsed before the student over takes the busApply the principle of relative velocity as follows;
(Vs - Vb)t = D
where;
Vs is the velocity of the studentVb is the velocity of the bust is the time in which the student catches the busD is the distance between them(Vs - at)t = D
where;
a is the acceleration of the bus(5.5 - 0.173t)t = 40.4
5.5t - 0.173t² = 40.4
0.173t² - 5.5t + 40.4 = 0
solve the quadratic equation using formula method;
a = 0.173, b = -5.5, c = 40.4
t = 11.52 seconds or 20.27 seconds
so the minimum time taken by the student to over take the bus is 11.52 seconds
Distance the student have to run to overtake the busd = vt
d = 5.5 m/s x 11.52 s = 63.36 m
Speed of the busv = at²
v = 0.173 x (11.52)
v = 2.0 m/s
If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.
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explain newtons law of motion applied in this game
Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
Newton’s third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction. This law is important in analyzing problems of static equilibrium, where all forces are balanced, but it also applies to bodies in uniform or accelerated motion.
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The first law represented in the game would be the candy. If you blow it, it would move but then stop due to friction.
The second law would be represented by blowing the candy. Since the candy was light, it would be easier to blow but if it was heavier, it would be a lot harder.
The final law represented in the game would be if you decided to blow the candy with a ballon instead, the candy would move the opposite direction the ballon is moving.
an extension cord 20m long uses no. 12 gauge copper wire (cross section area 0.033 cm ^2 resistivity 1.7×10^-8 ohms - m
If an extension cord 20 m long uses no. 12 gauge copper wire cross-section of area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, the resistance of the extension chord would be 0.1030 Ohm.
What is resistance?Resistance is the obstruction of electrons in an electrically conducting material.
The mathematical relation for variation in resistance with length is given by
R = ρ*L/A
As given in the problem an extension cord 20 m long uses no. 12 gauge copper wire cross-section of area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, then we have to find the resistance of the wire,
Resistance of the wire = 1.7×10⁻⁸ ×20/0.033 ×10⁻⁴
=0.1030 Ohm
Thus, the resistance of the extension chord would be 0.1030 Ohm.
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The question is incomplete the complete question is,
An extension cord 20 m long uses no. 12 gauge copper wire cross-section of area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, then find the resistance of the wire?
(a) What must the charge (sign and magnitude) of a 1.45-g particle be for it to
remain stationary when placed in a downward-directed electric field of magnitude 650
N/C?
(b) What is the magnitude of an electric field in which the electric force on a proton is
equal in magnitude to its weight?
The charge is obtained as 2.19 * 10^-5 C the electric field is obtained as 1 * 10^-7 N/C.
What is the charge?We know that the electric field is the created as a result of the presence of one charge close to another. The magnitude of the electric charge that would make the particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 650 N/C is required here.
a) Recall that the eight is also a force and counterbalanced the electric force hence;
W = mg = Eq
mg = Eq
g = 9.8 m/s^2
1.45 * 10^-3 Kg * 9.8 m/s^2 = 650 N/C * q
q = 1.45 * 10^-3 Kg * 9.8 m/s^2/650 N/C
q = 2.19 * 10^-5 C
b) The charge on the proton is 1.6 * 10^-19 while the mass of the proton is 1.67 * 10^-27 Kg
F= 1.67 * 10^-27 Kg * 9.8 m/s^2 = 1.6 * 10^-26 N
The electric field is obtained from; 1.6 * 10^-26 N/1.6 * 10^-19
= 1 * 10^-7 N/C
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need answer and showed work to question number 1
Answer:
can u show question 1?
Explanation:
A 5kg block is resting on the table. Find the normal force acting on the block.
49 N, up
49 N
5 kg, up
49 N, down
The normal force acting on the block is 49 N in upward direction
It is given that
mass of block is 5kg
And we have to find the Normal force on block
The force surfaces apply to stop solid objects from passing through one another is known as the normal force.
A contact force is a normal force. A normal force cannot be applied between two surfaces that are not in contact.
Since, block is at rest and no other force is acting on it so only force acting on it is by the table and it is in upward direction
Force = mg = 5 x 9.8 = 49 N in upward direction
Hence, normal force acting on block is 49 N in upward direction
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A 120 V power supply is used to power a TV. If the TV draws 0.25 A of current and the TV is used for 1.20 h, how much energy, in kilojoules, is used?
The amount of energy used by the TV is 129.6 kJ.
What is electric energy?Electric energy is the product of charge and potential difference.
To calculate the amount of electric energy used, we use the formula below.
Formula:
E = Vit................................. Equation 1Where:
E = Electric energyV = Voltagei = Currentt = timeFrom the question,
Given:
V = 120 Vi = 0.25 At = 1.2 h = (1.2×3600) = 4320 sSubstitute these values into equation 1
E = 120×0.25×4320E = 129600 JE = 129.6 kJHence, the amount of energy used by the TV is 129.6 kJ.
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The intake to a hydraulic turbine (not drawn to scale) installed in a dam is located at an elevation of 10 meters above the turbine exit. Water enters at
20℃ with negligible velocity and exits from the turbine at 10m/s. The water passes through the turbine with no significant changes in temperature or pressure between the inlet and exit, and heat transfer is negligible. The acceleration of gravity is constant at g = 9.81 m/s2. If the power output at a steady state is 500 kW, what is the mass flow rate of water in kg/s?
The mass flow rate of water is 5.146×10³ kg/s
The enthalpy change that occurs during a reaction is the heat that enters or exits the system. A critical factor that determines whether a reaction may occur is whether the enthalpy of the system increases (i.e., because energy is added) or lowers (i.e., because energy is given off).
Elevational difference (Z1-Z2) =15m
V1 = the inlet velocity, V2 = the outlet velocity
Using the equation for steady-state energy Q+m(h1+V2/12+g/z1) =W+m(h2+V22/2+gz2),
m(h1+V21/2+g/z1) m(h2+V22/2+g/z2) =WQ, and m(h1h2+V2/12V22/2+g/z1g/z2) =WQ.
The change in enthalpy and the rate of heat transfer are both zero because the pressure and temperature have barely changed.
m (0−0+0/22−10/22+9.81× (15))
=500×1000m\s
=5.146×10³ kg/s
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Part A: what is the capacitance?
Part B: what is the potential difference between the plates?
Part C: what is the magnitude of the electric field between the plates?
Part A: capacitance = 2.650 × [tex]10^{-12}[/tex] F
Part B: the potential difference between the plates = 2.5250 × 10² V
Part C: the magnitude of the electric field between the plates = 7.56 × [tex]10^{6}[/tex] V/m
What is capacitance?Capacitance is an electrical property of a capacitor. Farad (abbreviated to F), which bears the name of the British physicist Michael Faraday, is the unit of capacitance and measures a capacitor's capacity to store an electrical charge on its two plates. The area of a parallel plate capacitor, A, is measured in square meters. Its capacitance is inversely proportional to the spacing, d, or dielectric thickness, measured in meters, between the two conductive plates.The generalized formula for a parallel plate capacitor's capacitance is given as C= εo*A/d, where stands for the absolute permittivity of the material being utilized as the dielectric. The value of the dielectric constant commonly referred to as the "permittivity of open space," is 8.854 x 10-12 Farads per meter.Given:
distance between plates(d) = 3.34 × [tex]10^{-3}[/tex] m
Area of plates(A) = 10 × [tex]10^{-4}[/tex] m²
Charge(Q) = 6.70 × [tex]10^{-8}[/tex] C
electric constant(εo) = 8.8542× [tex]10^{-12}[/tex] F/m
The capacitance is given by:
C= εo*A/d
= (8.8542× [tex]10^{-12}[/tex] × 10 × [tex]10^{-4}[/tex] )/ 3.34 × [tex]10^{-3}[/tex]
= 2.650 × [tex]10^{-12}[/tex] F
To calculate the Magnitude of the electric field between the plates
⇒ E=σ/εo ,where σ = Q/A
σ = 6.70 × [tex]10^{-8}[/tex] / 10 × [tex]10^{-4}[/tex]
= 6.70 × [tex]10^{-5}[/tex] C[tex]m^{-2}[/tex]
Now, E = 6.70 × [tex]10^{-5}[/tex] / 8.8542× [tex]10^{-12}[/tex]
= 7.56 × [tex]10^{6}[/tex] V/m
To find the potential difference between the plates;
V=E×d
= 7.56 × [tex]10^{6}[/tex] × 3.34 × [tex]10^{-3}[/tex]
= 2.5250 × 10² V
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A toy rocket is fired horizontally at 12.0 m/s from a 30.0 m tall building. The engine of the rocket provides an acceleration along the horizontal such that () = −(1.6 m/s3).. Find the time it takes for this toy rocket to land on the ground.
The time taken by the toy rocket that was fired horizontally to land on the ground is 2.47 seconds
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
[tex]u_{x}[/tex] = 12 m / s
[tex]u_{oi}[/tex] = 0
[tex]s_{y}[/tex] = 30 m
[tex]a_{x}[/tex] = - 1.6 m / s²
[tex]a_{y}[/tex] = g = 9.8 m / s²
[tex]s_{y}[/tex] = [tex]u_{oi}[/tex] t + 1 / 2 gt²
30 = 0 + ( 0.5 * 9.8 * t² )
t = √ ( 30 / 4.9 )
t = 2.47 s
The initial velocity of a horizontal projectile motion is in x-direction is constant throughout the motion whereas in y-direction the initial velocity is zero and the final velocity varies.
Therefore, the time taken by the toy rocket that was fired horizontally to land on the ground is 2.47 seconds
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A patient is weighted by a scale on a deep-sloped floor part. The reading is the component of weight perpendicular to the slop. The reading is ___ the true weight.
A- more than
B- half of
C- less than
D- the same as
Answer:
Measuring a patient's body weight can be done to Assess and monitor fluid and nutrition status as part of a nutrition screening tool. Calculate drug doses. Calculate nutrition and fluid support if required. Monitor the effectiveness of nutritional support.
Explanation:
At t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT . At the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
1.) At what time does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
t=
2.) At what coordinate does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
x =
1. The truck overtakes the car at time t = 2vC/(aT - aC)
2. The coordinate where the truck passes the car is x = 2aT[vC/(aT - aC)]²
The question has to do with equation of motion
What are the equations of motion?The equations of motion are equations that are used to describe the motion of an object under constant acceleration.
1.) At what time does the truck pass the car?
Since at t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT.
We find the distance moved by the truck using the equation of motion d = ut + 1/2at² where
u = initial speed of truck = 0 m/s(since it starts at rest) a = acceleration of truck = aTSo, d = ut + 1/2at²
d = 0 × t + 1/2aTt²
d = 1/2aTt²
Also, at the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
We find the distance moved by the car using the equation of motion D = ut + 1/2at² where
u = initial speed of car = vC a = acceleration of car = -aCSo, D = ut + 1/2at²
D = vCt + 1/2(-aC)t²
D = vCt - 1/2aCt²
The truck over takes the car when d = D
So, 1/2aTt² = vCt - 1/2aCt²
1/2aTt² - 1/2aCt² - vCt = 0
[(aT - aC)t/2 - vC)]t = 0
⇒ t = 0 or (aT - aC)t/2 - vC = 0
⇒ t = 0 or (aT - aC)t/2 = vC
⇒ t = 0 or t = 2vC/(aT - aC)
So, the truck overtakes the car at time t = 2vC/(aT - aC)
2.) At what coordinate does the truck pass the car?Since the distance moved by the truck is d = x - 0
= 1/2aTt², where x = coordinate where truck passes car.
To find the coordinate where the truck passes the car, we susbstitute the time where the truck passes the car into d. So, t = 2vC/(aT - aC)
So, x - 0 = 1/2aTt²
x = 1/2aT[2vC/(aT - aC)]²
x = 2aT[vC/(aT - aC)]²
So, the coordinate where the truck passes the car is x = 2aT[vC/(aT - aC)]²
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I need help in this…
Diffraction is the spreading out of waves past small openings and the bending of waves around small obstructions.
What is diffraction ?Diffraction is the process by which light spreads out after passing through a small space or bends around an obstruction. Diffraction can occur in waves of any kind, including sound, radio, and water.
What is diffraction in sound wave?When an object has dimensions that are close to or smaller than the sound wave's wavelength, it causes a sound wave to move around it.
Waves spread out as they move through an aperture or around objects, which is known as diffraction. It happens when the aperture's or obstacle's size is of the same order of magnitude as the wave's wavelength. Nearly all of the wave is blocked at very small aperture sizes.
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I walk 800 meters East, and then turn and walk 1200 meters North. What was my total distance?
Answer:
2,000
Explanation:
Answer: 2000 meters would be the distance you walked, but if you need it in feet, it is 6,561.67979.
Explanation: 1 meter = 3.28 feet.
what is shielding effect due to hollow charged surface
Answer:
Electrostatic shielding
Explanation:
Positive and negative charges that are out of balance cause static electricity. One substance becomes positively charged and one becomes negatively charged when two dissimilar materials are rubbed together. Materials have been rated according on how well they can hold or release electrons. The triboelectric series is the name given to this order. These materials include paper, plastic, glass, hair, nylon, wool, and silk.
Electrons are merely transferred from one location to another when we charge anything with static electricity. There are no new or lost protons or electrons. The overall or net electric charge does not change. The "conservation of charge" principle refers to this.
An electric field is produced around charged items. The amount of charge, the distance involved, and the form of the items are just a few of the variables that affect how strong this field is. When dealing with huge items, this may get rather problematic. We may thus deal with "point sources" of charge to make things simpler. Point sources, also known as sources of insignificant dimensions, are charged objects that are much, much smaller than the space between them. The word "static" comes from the fact that an electric charge exists even when the electrons are not moving.
In the 1780s, French scientist Charles Coulomb (1736–1806) gave the first detailed account of electric field intensities. He discovered that the electrical force for point charges directly changes with the product of the charges. In other words, the field is stronger the higher the charges. Additionally, the field changes inversely with the square of the charge separation. This implies that the force weakens with increasing distance.
Because a significant charge may harm fragile electronic components like MOSFETs, CMOS ICs, Computer cards, TTL chips, and even LEDs, static electricity presents challenges for experimenters and electronics makers.
In a laboratory, there are a few fairly easy techniques to prevent static charges. The lab's air is made more humid, which reduces static electricity. Dry environments are better for electron accumulation. A thin coating of water molecules covers the majority of surfaces during humid days, allowing electrons to flow more easily and making nearly everything conductive and static-free. As a result, shocks are less frequent on these days.
Some factory employees must adhere to stringent dress codes, avoiding sweaters and headgear that can promote static. Technicians may wear wrist bands that deliver additional electrons into the earth by connecting them to the floor with a metal wire.
In factories, "air ionizers" are also used to regulate electron behavior. The devices release ions, or molecules with an excess of electrons, into a space. Ions are molecules with one or more missing electrons. The electrons find their opposites as they align with them as they drift around the room looking for equilibrium. Ionizers stop the accumulation of static electricity.
Sometimes we need a completely electrostatic-free environment for a piece of equipment to function extremely effectively, and the only definite way to achieve this is by creating a kind of enclosure that the equipment is designed to operate in. It could take up a whole room or perhaps just a metal box in a lab. A FARADAY'S CAGE is what it is called. It was created by British scientist Michael Faraday (1791–1867) and protects the contents from static electric forces.
The term comes from the fact that these enclosures resemble cages in many ways. Some are as straightforward as metal or chain-link enclosures. Some people employ a thin metallic mesh. No matter how they look exactly, all Faraday cages spread electrostatic charges or even specific forms of electromagnetic radiation around the cage's surface, keeping the interior free of them. (The metal mesh must contain holes that are shorter than the wavelength that is to be filtered in order to screen against electromagnetic radiation.) In essence, a Faraday cage is merely a "hollow conductor," with the charge only remaining on the cage's outside.
An airplane is the greatest illustration of a Faraday's Cage. Lightning frequently strikes airplanes when they are in the air. Despite the fact that it occurs frequently, neither the passengers nor the plane are harmed. This is so because the plane's metal body acts as a Faraday cage. Lightning strikes harmlessly over the surface of the airplane, causing no harm to the avionics, communications, or passenger electronics.
Thanks,
Eddie
The students in Mrs. Mangione's class attempt to guess the number of marbles in a jar to earn 2 extra credit points on their next exam. Suppose there are 1206 marbles in a jar and a student makes a guess of m marbles. Which expression represents the difference between the student's guess and the actual number of marbles.
The formula m-1206 represents the discrepancy between the student's estimation and the actual number of marbles.
The student guesses that there are m marbles given that there are 1206 marbles in the jar.
The term that best captures the discrepancy between the student's guess and the actual number of marbles must be found.
Expressions are made up of a combination of numerical values, symbols, fractions, coefficients, and other elements that lack the equals sign.
There are 1206 marbles in total.
Guessed number of marbles by the student-m
The phrase that illustrates the distinction between a student's educated guess and
The expression that shows the difference between the student's guess and the actual number of marbles is m-1206.
Hence the expression which reflects the difference between the student's guess and the actual number of marbles is m-1206.
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Questions:
1. Clara drives 250 km West to play a gig in Colombia City. After the gig he drives 450 km
east to jam with some musicians in Columbia. What distance did he cover? What was his
displacement?
Answer:
700km
Explanation:
going was 250km and leaving was 450
250+450=700
Which term is defined as a guess informed by observations?
O theory
O law
O principle
O hypothesis
Hi !
Answer:
Which term is defined as a guess informed by observations?
O hypothesis
A certain net force acting on a 5kg mass produces an acceleration of 2 m/s2 calculate the force
Answer:
10 N
Explanation:
Newton's Second Law equation: Fnet = ma
Assuming no frictional force, plug in the values to get your answer!
Fnet = 5kg x 2m/s^2 = 10 N
One way to determine the age of Earth is to measure the ratio of certain radioactive elements to their more stable forms. By comparing the amount of the
radioactive form of an object with the stable one, and by knowing how long it takes to turn from one to the other, scientists can estimate the age of the object.
Some people argue that the decay rate has not always been the same and that it can be much faster than scientists have measured in labs.
Nuclear power plants use radioactive elements to produce power because, during the decay process, energy is released.
If scientists are wrong about Earth's age based on radioactive material and the decay rates are really much faster, how would nuclear power plants be affected?
OA. Nuclear fuel would remain useful longer.
OB. The rate of energy release would be higher.
OC. The amount of energy released would be less.
OD. Nuclear fuel would generate less radioactivity.
Answer:
A
Explanation:
A ball rolls off a table with a horizontal velocity of 4 m/s. If it takes 0.5 seconds for the ball to reach the floor, how high above the floor kd tje tabletop? (Use g = 10 m/s^2)
Show work please :)
Answer:
1.25 m
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Consider the horizontal and vertical motion of the ball separately.
As the ball rolls off the table with a horizontal velocity only, the vertical component of its initial velocity is zero.
Acceleration due to gravity = 10 ms⁻²
As we need to find the vertical displacement of the ball, resolve vertically, taking ↓ as positive:
[tex]u=0 \quad a=10 \quad t=0.5[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(0)(0.5)+\dfrac{1}{2}(10)(0.5)^2\\s&=0+\dfrac{1}{2}(10)(0.25)\\s&=(5)(0.25)\\ \implies s&=1.25 \; \sf m\end{aligned}[/tex]
Therefore, the vertical displacement of the ball is 1.25 m, and so the table is 1.25 m above the floor.
Two particles are at the same point at the same time, moving in the same direction. Par- ticle A has an initial velocity of 7.7 m/s and an acceleration of 1.8 m/s². Particle B has an initial velocity of 2.9 m/s and an acceleration of 5.7 m/s². At what time will B pass A? Answer in units of s.
The particle B will pass particle A in 1.10s.
Equation :Using kinematic formula,
d = Vini x t + 1/2 at²
where,
d is distance
Vini is velocity initial
a is acceleration
t is time
So, putting values
7.7 t + 1/2 x 1.8 t^² = 2.9 t + 1/2 x 5.7 t²
7.7 t + 2.7 t² = 2.9 t + 8.55 t²
t + t² / t + t² = 2.9 + 8.55 / 7.7 + 2.7
t = 1.10s
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How many liters are in 10 U.S. gallons?
1 gallon
3.79 liters
OR
3.79 liters
1 gallon
Answer:
37.85 Liters in 10 US gallons
Explanation:
if asking for volume: volume = 3.785liters
in physics, a blank is a group of related objects that interact with eachother and form a complex whole
In physics, a system is a group of related objects that interact with each other and form a complex whole.
What is a system?In sciences (i.e., physics, chemistry and biology) a system can be defined as an interrelated group of different elements or parts that work together to perform a given function.
In conclusion, in physics and science disciplines in general, a group of related objects that interact in order to form a complex whole is commonly referred as a system.
Complete question:
Fill in the blank. In physics, a ____ is a group of related objects that interact with each other and form a complex whole.
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please give the answer of mass of electron in physics
Answer:
electron, lightest stable subatomic particle known. It carries a negative charge of 1.602176634 × 10−19 coulomb, which is considered the basic unit of electric charge. The rest mass of the electron is 9.1093837015 × 10−31 kg, which is only 1/1,836the mass of a proton.
Explanation:
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If you are given values for Δx, v, and Δt, which kinematic equation could be used to find v0?
V = v0 + aΔt
Δx= (v + v0/ 2) Δt
v^2 = v0^2 2aΔx
Δx = v0Δt + 1/2 a (Δt)^2
The kinematics equation to determine v₀ is Δx = (v + v₀/2) Δt; option B
What are kinematic equations?Kinematic equations are equations which describe the motion of moving bodies.
Kinematic equations are also known as equations of motion.
The equations of motion are given below:
v = u + ats = (v + u/2) * tv² = u² + 2ass = ut + ¹/₂at²where;
v is final velocity = vu is initial velocity = v₀s is distance = Δxa is accelerationt is time = ΔtGiven that the values for the following are given; Δx, v, and Δt, the equation to determine v₀ will be Δx = (v + v₀/2) Δt
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