The context clues show that the author of passage 1 uses the phrase that’s right in order to convey the main idea.
What are context clues?Context clues help to find the meaning of a word taking into account the words that surround the unknown word that make us infer the meaning.
Also called visual indices, these words are described or defined by other words that appear in the same sentence.
Here, the context clues show that the author of passage 1 uses the phrase that’s right in order to convey the main idea.
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448randomly selected light bulbs were tested in a laboratory,164lasted more than 500 hours. Find a pointestimate of the proportion of all light bulbs that last more than 500 hours.
Based on the information provided, the proportion of light bulbs that last more than 500 hours is 36.61%.
How to find the proportion in this case?A proportion refers to the relationship of one variable or element to another. In this case, we need to know the proportion of light bulbs that last more out of the total light bulbs selected. The process is shown below:
Light bulbs that lasted/ total selected
164/448 = 0.3661 x 100 = 36.61%.
Based on this, the point estimate of the proportion of all light bulbs that last more than 500 hours is approximately 0.3661 or 36.61%.
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A die is tossed three times. What is probability that a 6 will show in the upward face at least once?
Answer:
1/216.
Explanation:
The probability of a 6 appearing on any single roll of a fair die is 1/6. Since the rolls are independent, the probability of a 6 appearing on all three rolls is (1/6) x (1/6) x (1/6) = 1/216. Therefore, the probability that a 6 will not appear in any of the three rolls is 1 - 1/216 = 215/216. Finally, the probability that a 6 will appear at least once in the three rolls is 1 - 215/216 = 1/216. Thus, the probability of a 6 appearing in the upward face at least once is 1/216.