The battery standby duration (in hours) of a new model of cell phone is known to be normally distributed. Ten pieces of such new model of cell phone supplied from the manufacturer are randomly chosen and the actual standby durations are recorded as below:
48.2 47.8 45.6 47.2 49.3
51.2 44.2 45.4 49.2 43.6

The manufacturer claimed that this new model of cell phone has the mean battery standby duration of longer than 46.5 hours. Test at 1% significance level if this claim is true.

Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2) , Given volume and lateral area: r = 2 * V / A_l , Given base area: r = √(A_b / (2 * π)) , Given lateral area and total area: r = √((A - A_l) / (2 * π)) .

Answer:

No, because they are parallel.

Step-by-step explanation:

The lines [tex]p[/tex] and [tex]m[/tex] will not intersect, so Kevin is not correct.

It is given that planes A and B intersects. The plane A contains the line p, m and n on its plane. The lines p and m are parallel to each other. They are identical and move in the same direction.

Since the line p and m are parallel, they will not meet each other at any point because parallel lines does not intersect or meet at a point, they run parallelly along each other.

So, line p and m will not intersect.

Thus the answer is " No, because they are parallel."

Answer:

Step-by-step explanation:

no, because they are parrallel.

Answer:

y = 6x

Step-by-step explanation:

The equation representing a proportional relationship is

y = kx ← k is the constant pf proportionality

Here k = 6 , then

y = 6x ← equation of proportion

Answer:

She is not correct, she would need to have something before the y to know the answer

Step-by-step explanation:

hope this helps :)

Answer:

i don't know sorry

Answer:

a

Step-by-step explanation:

-5 shifts the y-intercept down, and it needs to be outside of the modulus as if its in the modulus, the graph would shift 5 units to the right instead

Answer:

C = 100 + 0.20d

Step-by-step explanation:

Let

C = Total cost

d = distance driven(km)

$100 = fixed cost

$0.20 = additional cost

The algebraic model of the relationship:

Total cost = fixed cost + (additional cost * distance driven(km))

C = 100 + (0.20 * d)

C = 100 + 0.20d

Answer:

jsjzbdjwbxjdbwisjsobs9fbe

Step-by-step explanation:

hfkdowwhdbhdvsjsh2ivdusvqvduzvqidv

Answer:

Yeeeeaaahhhh its correct.

Answer:

There is not enough evidence to support the claim that drug is effective at 1%

Step-by-step explanation:

For this we use the pored test as we have dependent test;

Difference :

10,5,-5,3,-3,4,2,-3,0,10,8,-2,3,-2,5,5,4,0

Hypothesis :

H0 : μd = 0

H0 : μd ≠ 0

The mean of d, dbar = Σd / n = 44 / 18 = 2.44

The standard deviation, Sd = 4.45 (using calculator)

The test statistic, T : dbar / (Sd/√n)

T = 2.44 / (4.45/√18)

T = 2.44 / 1.0488750

T = 2.326

Degree of freedom, df = n - 1 ; 18 - 1 = 17

The Pvalue = 0.0326

α = 0.01

Since Pvalue < α ; we fail to reject H0

Answer:

(I don't have the complement sign of sets, so I've used "©" to denote compliment)

L.H.S.

(B-A)∪C

= (B∩A©)∪C

= (B∪C)∩(A©∪C)

= (B∪C)∩(A-C)©

= (B∪C)-(A-C) = R.H.S.

(Proved)

Answer:

Its that squiglly one on top

Step-by-step explanation:

cuh cuh cuh cuh cuhc

Answer:

The polar coordinates appear in the form (r, θ), where r is the the radius from the center and θ is the angle. To get the radius, do the following.

[tex]r = \sqrt{x^2 + y^2} = \sqrt{1^2 + (-1)^2} = \sqrt{2}\\[/tex]

You can get the angle visually by drawing a point (1, -1) on a graph and seeing that it is 45 degrees from the top right quadrant (you can tell its 45 because both x and y have the same magnitude). Since there are 360 degrees, 360 - 45 = 315.

If you would like to find it mathematically, this is the way to do it

[tex]\theta = atan(y/x) = -45[/tex]

Notice that -45 degrees is just 360 - 45 = 315

Your answer would be

[tex](\sqrt{2}, 315)[/tex]

Answer:

I got that AE^2 = 8EC^2

Step-by-step explanation:

Here's what I did. I probably did this wrong, but this might give you an idea on how to solve it.

First, create equations:

AB = BC = AC = DE = 2EC

BD= BC = EC

Then, I used pythagorean theorem (since AD is perpendicular to BC): AD^2 + DE^2 = AE^2

Substitute: (2EC)^2 + (2EC)^2 = AE^2

Simplify: 4EC^2 + 4EC^2 = AE^2

AE^2 = 8CE^2

Answer:

The product of 16 and 26 would be 16 * 26

Step-by-step explanation:

This is because "the product of" means multiplication so *. Making it 16 * 26.

Answer:

filtration system is not working

filtration

Using the definition of the derivative,

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{f(x) - f(-2)}{x - (-2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac6x + 3}{x + 2}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac{6+3x}x}{x + 2}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{6+3x}{x(x + 2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3(x+2)}{x(x + 2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3}{x} = \boxed{-\dfrac32}[/tex]

Answer:

x³-2x²-4x+8

Step-by-step explanation:

a1=x+2

a2=x²-4⇒q=a2/a1=x-2

⇒a3=q.a2=(x-2).(x²-4)=x³-2x²-4x+8

Answer:

here I'm confused that whether the selling price is Rs.9,200 or Rs.9.200

any ways you can take the help of below procedure

Step-by-step explanation:

here,

let marked price be X

discount(d)=20%

VAT=15%

SP with VAT= 9200

now,

SP without VAT= SP - VAT of SP

= 9200-15/100 ×9200

= 9200- 1380

=Rs. 1380

again,

SP= MP - D of MP

or,7820= x- 20/100 × x

or, 7820× 100 = 100x- 20x

or,782000=80x

or, 782000/80=X

or, X= 9775.

hence MP is Rs 9775

Answer:

B. 64:25

Step-by-step explanation:

the ratio of the surface areas =

(8)² : (5)² = 64 : 25

Answer:

Area of pizza slice = 87 inches² (Approx.)

Step-by-step explanation:

Given:

Angle cut of pizza = 100°

Diameter of pizza = 20 inches

Find:

Area of pizza slice

Computation:

Area of sector = [Ф / 360][π][r²]

Area of pizza slice = [100/360][3.14][(20/2)²]

Area of pizza slice = [100/360][3.14][(10)²]

Area of pizza slice = [100/360][3.14][100]

Area of pizza slice = [0.2778][3.14][100]

Area of pizza slice = 87.2292

Area of pizza slice = 87 inches² (Approx.)

Answer:

Step-by-step explanation:

If x represents the number of long-sleeved shirts and each of these cost $14, then the expression for that is 14x; likewise for short-sleeved shirts that are represented by y. The expression for short-sleeved shirts that cost $10 apiece is 10y. Putting that together with the fact that they earned less than $200 when selling these at the same time, the inequality is

14x + 10y < 200

Answer:D i just got it right trust mw

Step-by-step explanation:i

Answer:

I say it's a

Step-by-step explanation:

I hope this help

Answer:

Step-by-step explanation:

Since T is in Quadrant II, sinT > 0 and cosT < 0.

cotT = -5/12

Answer:

The restrictions are x≠2,4,5

Step-by-step explanation:

First the denominators cannot be zero

x-2 ≠0  so x≠2

Then x-4 ≠0  so x≠4

Also, since we are dividing, when we flip the second expression, the numerator becomes the denominator, so it cannot be zero

2x-10≠0

2x≠10

x≠5

The restrictions are x≠2,4,5

Answer:

yes, your answers are correct

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

[tex]A_x=50cos(89.75)[/tex] so

[tex]A_x=.22[/tex]

[tex]B_x=200cos(0)[/tex] so

[tex]B_x=200[/tex] and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

[tex]C_x=200[/tex] (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

[tex]A_y=50sin(89.75)[/tex] so

[tex]A_y=50[/tex] (which I'm counting as 2 sig fig's)

[tex]B_y=200sin(0)[/tex] so

[tex]B_y=0[/tex] and we need to add those results together.

[tex]C_y=50[/tex]

Now for the resultant magnitude:

[tex]C_{mag}=\sqrt{(200)^2+(50)^2}[/tex]  and that gives us a final magnitude of

[tex]C_{mag}=206[/tex] m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

[tex]tan^{-1}(\frac{50}{200})=14[/tex]

The girl is 206 meters from her starting point at an angle of 14 degrees

The perimeter = sum of all sides

= 120 + 80 + 50

= 250

So 250 - 3

247

Left space for gate

Now cost of fencing = Rs 20/per meter

= 247 × 20

= Rs 4,940

Now the area of the triangular park can be found using heron's formula

S = (a+b+c)/2

S = (120+80+50)/2

S = 250/2

S = 125

Now

Herons formula = √s(s-a)(s-b)(s-c)

√125(125-120)(125-80)(120-50)

√125(5)(45)(70)

√5×5×5×5×5×3×3×5×14

After Making pairs

5×5×5×3√14

375√14

Therefore 375√14m is the area of the triangular park

Must click thanks and mark brainliest

$\sf\underline\bold{Answer:}$

$\space$

$\sf\underline\bold{Step-by-Step:}$

$\space$

$\sf\bold{Given(In \:the\:Q):}$

$\space$

$\sf\bold{To \: find:}$

$\space$

$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$

$\space$

$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$

$\space$

Use heron's formula to find the area of the triangle.

$\space$

$\mapsto$ $\sf\small{Heron's\:formula=}$

[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]

$\space$

$\sf\bold{Now,find\:semi\:parameter:-}$

$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$

$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$

$\space$

$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$

$\sf{Area\:of\:the\:∆:-}$

$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]

$\space$

$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$

$\space$

$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$

$\space$

$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$

______________________________

$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$

$\sf{Cost\:of\:fencing-}$

$\space$

$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$

$\space$

So,total cost of fencing at the rate of Rs.20 per m:-

___________________________________

Answer:

a = m/c

~~~~~~~~~~~~~~~~~~~~~~~

m=ca

divide both sides by c

you get a = m/c

Step-by-step explanation:

Answer:

a = m/c

Step-by-step explanation:

m = ca

divide both sides by c

m/c = ca/c

m/c = a

:.a = m/c

Answer:

48

Step-by-step explanation:

9,18

6,12,18,24,30

18 + 30 = 48