Answer:
29.5 days
Explanation:
It is a cycle that lasts nearly 29.5 days.
Answer:
28 days
Explanation:
The cycle is 28 days long.
A car capable of a constant acceleration of
3.72 m/s
2
is stopped at a traffic light. When
the light turns green, the car starts from rest
with this acceleration. At the very same moment, a truck traveling with constant velocity
13.8 m/s passes the car.
As the car’s velocity increases, it will eventually move faster than the truck and later
overtake it. How far from the light will the
car catch up with the truck?
Answer in units of m.
Answer:
sorry we don't understand what about of your question is
Explanation:
sorry we don't have a great weekend
Which two options are forms of potential energy
A nuclear energy
B chemical energy
C sound energy
D thermal energy
E electrical energy
Answer:
e and b
Explanation:
Answer:
D,E
Explanation:
thats what I would say because PE is the energy stored in an object
Calculate the velocity of an object thrown straight up with an initial velocity of 25 m/s at 1.0 seconds.
Answer:
15 m/s
Explanation:
Given:
v₀ = 25 m/s
a = -10 m/s²
t = 1.0 s
Find: v
v = at + v₀
v = (-10 m/s²) (1.0 s) + 25 m/s
v = 15 m/s
A student walks 100 m East and 100 m North. What is their distance traveled?
-- The student's distance traveled is 200 meters.
-- The student's displacement is 141 meters Northeast.
An electric car is being driven through a town at 22 m/s. The kinetic energy of the car is 222640 J. Calculate the mass of the car
Answer:
920 kg
Explanation:
[tex]kinetic \: energy = 222640j \\ \frac{1}{2} mv {}^{2} = 222640 \\ \frac{1}{2} m(22) {}^{2} = 222640 \\ m = 920kg[/tex]
Is sound potential or kinetic energy
Answer:
Sound energy (that is, mechanical vibrational waves passing through an elastic medium) is a combination of kinetic and potential energies. As the wave compresses the medium (storing elastic potential energy) the medium comes to rest (no motion so no kinetic energy).
Explanation:
Hope this helps :D
What is the location for the valence electron(s) for an atom of Barium, Ba?
O 2 electrons in energy level 3
O 2 electrons in energy level 6
O 6 electrons in energy level 2
O 1 valence electron in energy level 6
Answer:
2 electrons in energy level 6
What type of energy is stored in chemical bonds of molecules ?
Answer:
potential energy,
Explanation:
Energy, potential energy, is stored in the covalent bonds holding atoms together in the form of molecules. This is often called chemical energy.
The energy stored on the chemical bonds of molecules is chemical energy. When the chemical bonds are broken, the energy is released.
What is chemical energy?Chemical energy is a form of energy which is stored in the form of chemical bonds. There are various other forms of energy such as electrical energy, mechanical energy, kinetic energy etc.
There are different types of chemical bonds such as ionic bonds, covalent bonds, metallic bonds etc. Each type of bond are of different bond strength and energy.
Molecules are formed by the combination of atoms through chemical bonding. Chemical energy is stored within the bonds and this energy releases when the bond breaks.
To find more on chemical energy, refer here:
https://brainly.com/question/1397271
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A baseball is hit so that it travels straight upward after being struck by the bat. A fan observes that it takes 3.00 s for the ball to reach its maximum height. Find (a) the ball’s initial velocity and (b) the maximum height it reaches.
Answer:
initial velocity is0m/s and final velocity is29.4m/s
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!
Calculate the distance the gecko covers when sprinting from rest to 2 m/s in a time of 1.5 s.
Answer:
1.5 m
Explanation:
a = v/t
a = 2/1,5 = 4/3
x = 1/2 a t² + vt + x
x = 1/2 × 4/3 × 9/4 = 3/2 = 1.5 m
2. (01.02)
Choose the best definition for the following phrase: like terms (1 point)
Options:
A Letter that holds the place for some unknown value in mathematics.
A process where you must look for terms that have identical variable parts and then combine their coefficient
A process where if two things are equal, one can be put in the place of the other and nothing will change
Terms that have identical variable parts
Answer:
A process where you must look for terms that have identical variable parts and then combine their coefficient.
An airplane flies 250.0 km at 300 m/s. How long does this take?
A car slows from 90mi/he to 55mi/hr when it sees the police what's the cars acceleration
Charlotte throws a paper airplane into the air, and it lands on the ground. Which best explains why this is an example of projectile motion?
A). The paper airplane’s motion is due to horizontal inertia and the vertical pull of gravity.
B). A force other than gravity is acting on the paper airplane.
C). The paper airplane’s motion can be described using only one dimension.
D). A push and a pull are the primary forces acting on the paper airplane.
Explanation:
yes it is the force that is subjected by the force of gravity onlyAnswer:
A. The paper airplane’s motion is due to horizontal inertia and the vertical pull of gravity.
Explanation:
Got it right on edge.
An astronaut holds a rock 100m above the surface of Planet XX. The rock is then thrown upward with a speed of 15m/s, as shown in the figure. The rock reaches the ground 10s after it is thrown. The atmosphere of Planet XX has a negligible effect on the rock when it is in free fall. Determine the acceleration due to gravity of the rock when it is on Planet XX.
Answer:
Explanation:
Using the equation of motion to get the acceleration due to gravoty of the rock on the planet.
S = ut+ 1/2at² where;
S is the distance of the rock above the surface of the planet = 100m
u is the initial velocity = 15m/s
a is the acceleration due to gravity
t is the time taken by the rock to reach the ground = 10s
Since the rock is thrown upward the acceleration due to gravity will be negative i.e a= -g
The equation becomes S = ut- 1/2gt²
Substituting the given value to get the time t
100 = 15(10)- 1/2g(10)²
100 = 150-50g
100-150 = -50g
-50 = -50g
g = -50/-50
g = 1m/s²
Hence the acceleration due to gravity of the rock when it is on Planet XX is 1m/s²
Define what factors allow a population of a species to grow to a certain size and how they relate to carrying capacity
Answer:
Relationship between population size, carrying capacity, and limiting factors is described below.
Explanation:
1. There are four variables which govern changes in population size.
births
deaths
immigration
emigration
A population gains individuals by birth and immigration and loses individuals by death and emigration.
2. Populations vary in their capacity to grow. The maximum rate at which a population can increase when resources are unlimited and environmental conditions are ideal is termed the population's biotic potential.
3. There are always limits to population growth in nature. Populations cannot grow exponentially indefinitely. Exploding populations always reach a size limit imposed by the shortage of one or more factors such as water, space, and nutrients or by adverse conditions such as disease, drought and temperature extremes.
4. The factors which act jointly to limit a population's growth are termed the environmental resistance. The interplay of biotic potential and density-dependent environmental resistance keeps a population in balance.
5. Carrying Capacity
For a given region, carrying capacity is the maximum number of individuals of a given species that an area's resources can sustain indefinitely without significantly depleting or degrading those resources. Determining the carrying capacities for most organisms is fairly straightforward. For humans carrying capacity is much more complicated. The definition is expanded to include not degrading our cultural and social environments and not harming the physical environment in ways that would adversely affect future generations.
6. Population Impact
Homo sapiens is a species possessing a diversity of individual needs. Thus, sub-populations will have different requirements and different impacts on the environment. For example 100 million vegetarians will have a significantly different environmental impact than 100 million meat-eaters. This can be demonstrated by comparing the affect on water supplies by both sub-populations. About 1000 tons of water are needed to produce 1 ton of grain. Almost 40% of all grain is used in meat and poultry production. Add to this the amount of water that goes into the production of meat, and you can see that meat comsumption places more stress on global water supplies than grain consumption.
Hope this helps (: Mark me brainliest if its good to you.
Which SI units would you use for the following measurements?.
Answer:
Where are the measurements?
Explanation:
We can measure the length of the swimming pool by using the SI unit meter, as the length of the swimming pool comes under the fundamental measurement of the dimension which is measured by the standardized international unit of length.
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.
There are three additional units and 7 SI basic units in this system of SI units, the base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole.
As given in the problem we have to find how can we measure the length of the swimming pool,
Due to the fact that the length of the swimming pool falls under the category of a dimension that is fundamentally measured using a standardized international unit of length.
Thus, we can measure the length of the swimming pool by using the SI unit meter,
Learn more about the unit of measurement from here,
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Your question seems incomplete the complete question is,
Which SI units would you use for the following measurements?
the length of a swimming pool
What level of certainty do you have that the sun will rise tomorrow
my certainty is 99.999999% because the earth has been around for about 4 quadrillion years or more and the sun has risen on almost every single one of them, so the odds of the sun not coming up are very very low.
Answer:
100%
Explanation:
A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.
The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.
When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.
Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.
Answer:
[tex]V_0[/tex]
Explanation:
Given that, the range covered by the sphere, [tex]M[/tex], when released by the robot from the height, [tex]H[/tex], with the horizontal speed [tex]V_0[/tex] is [tex]D[/tex] as shown in the figure.
The initial velocity in the vertical direction is [tex]0[/tex].
Let [tex]g[/tex] be the acceleration due to gravity, which always acts vertically downwards, so, it will not change the horizontal direction of the speed, i.e. [tex]V_0[/tex] will remain constant throughout the projectile motion.
So, if the time of flight is [tex]t[/tex], then
[tex]D=V_0t\; \cdots (i)[/tex]
Now, from the equation of motion
[tex]s=ut+\frac 1 2 at^2\;\cdots (ii)[/tex]
Where [tex]s[/tex] is the displacement is the direction of force, [tex]u[/tex] is the initial velocity, [tex]a[/tex] is the constant acceleration and [tex]t[/tex] is time.
Here, [tex]s= -H, u=0,[/tex] and [tex]a=-g[/tex] (negative sign is for taking the sigh convention positive in [tex]+y[/tex] direction as shown in the figure.)
So, from equation (ii),
[tex]-H=0\times t +\frac 1 2 (-g)t^2[/tex]
[tex]\Rightarrow H=\frac 1 2 gt^2[/tex]
[tex]\Rightarrow t=\sqrt {\frac {2H}{g}}\;\cdots (iii)[/tex]
Similarly, for the launched height [tex]2H[/tex], the new time of flight, [tex]t'[/tex], is
[tex]t'=\sqrt {\frac {4H}{g}}[/tex]
From equation (iii), we have
[tex]\Rightarrow t'=\sqrt 2 t\;\cdots (iv)[/tex]
Now, the spheres may be launched at speed [tex]V_0[/tex] or [tex]2V_0[/tex].
Let, the distance covered in the [tex]x-[/tex]direction be [tex]D_1[/tex] for [tex]V_0[/tex] and [tex]D_2[/tex] for [tex]2V_0[/tex], we have
[tex]D_1=V_0t'[/tex]
[tex]D_1=V_0\times \sqrt 2 t[/tex] [from equation (iv)]
[tex]\Rightarrow D_1=\sqrt 2 D[/tex] [from equation (i)]
[tex]\Rightarrow D_1=1.41 D[/tex] (approximately)
This is in the [tex]3[/tex] points range as given in the figure.
Similarly, [tex]D_2=2V_0t'[/tex]
[tex]D_2=2V_0\times \sqrt 2 t[/tex] [from equation (iv)]
[tex]\Rightarrow D_2=2\sqrt 2 D[/tex] [from equation (i)]
[tex]\Rightarrow D_2=2.82 D[/tex] (approximately)
This is out of range, so there is no point for [tex]2V_0[/tex].
Hence, students must choose the speed [tex]V_0[/tex] to launch the sphere to get the maximum number of points.
Free fall motion is motion in which the only force acting on the body is gravity
The student should launch the sphere at 2·v₀, for the sphere will land at approximately 1.41·D, which is in the 3 point zone
The given parameter are;
The distance covered by the sphere when launched at height, H = D
The velocity with which the ball reaches D = v₀
The current available height of launcher= H/2
The available velocities = v₀, and 2·v₀
Solution:
From H = u·t + (1/2)·g·t², where, initial velocity of the vertical motion of the ball, u = 0 we have;
H = (1/2)·g·t²
∴ The time it takes the ball to drop from H, t = √(2·H/g)
The distance, D = v₀ × √(2·H/g)
When the height is H/2, we get;
t = √(2·H/(2·g)) = √(H/g)
The distance covered, D₁ = v₀ × √(H/g)
Therefore, D = (√2) × v₀ × √(H/g) = (√(2))·D₁
D₁ = D/(√2) ≈ 0.71·D
D₁ ≈ 0.71·D
At speed 2·v₀, we have;
D₂ = 2·v₀ × √(H/g) = √2 × v2 × v₀ × √(H/g) = √2 × v₀ × √(2·H/g) = √2·D₁ ≈ 1.41·D
D₂ ≈ 1.41·D
The 2 point zone = D/2 < x < D = 0.5·D < x < D (Position D₁ ≈ 0.71·D is located here)
The 3 Point Zone = D < x < 3·D/2 = D < x < 1.5·D (Position D₂ ≈ 1.41·D is located here)
Given that at D₂, the ball lands in the 3 Point Zone, the student should launch the sphere at the speed, 2·v₀, so that the ball will land at D₂ ≈ 1.41·D, which is in the 3 Point Zone
Learn more about free fall motion here:
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234 cm …. ________________ meters
Answer:
the answer is 234 cm is 2.34 meters
Scientists have data for the density of gas particles at
different levels of the atmosphere. This diagram shows the
trend in that data.
Which statement describes the pattern in the density of gases in the
atmosphere?
A. They are evenly dense throughout the atmosphere.
B. They are less dense near the top of the atmosphere.
C. They are densest near the middle of the atmosphere.
D. They are least dense in the atmosphere near sea level.
Answer:B. They are less dense near the top of the atmosphere
Explanation:
1.
Which of the following process is /are evaporation process
A plane's average speed between two cities is 625 km/hr. If the trip takes 2.5 hours, how far does the plane fly?
Answer: 1,562.5 Km
Explanation: If it takes one hour to travel 625 kilometers, then, in two and a half hours, you should travel 1,562.5 Kilometers because of 625x2.5=1562.5 kilometers
25 POINTS! ANSWER CORRECTLY FOR BRAINLIEST!
Which of these is a type of climate?
A. Foggy
B. Overcast
C. Thunderous
D. Tropical
(I honestly think its foggy but I want other peoples opinions)
Answer:
d. tropical
Explanation:
Tropical climates are characterized by constant high temperatures
2. A ball is released from a vertical height of 20 cm. It rolls down a "perfectly
frictionless" ramp and up a similar ramp. What vertical height on the second
ramp will the ball reach before it starts to roll back down?
Answer:
20 cm
Explanation:
Given that a ball is released from a vertical height of 20 cm. It rolls down a "perfectly frictionless" ramp and up a similar ramp. What vertical height on the second ramp will the ball reach before it starts to roll back down?
Since it is perfectly frictionless, the Kinetic energy in which the ball is rolling will be equal to the potential energy at the edge of the ramp.
Therefore, the ball will reach 20 cm before it starts to roll back down.
the acceleration due to gravity on earth is 9.8 m/s^2. The force acting on an object on earth is 22 newtons. What is the mass of this object on earth?
Explanation:
solution ,
[tex]a = 9.8m \div {s}^{2} [/tex]
[tex]f = 22 \: newton[/tex]
[tex] M= \: ?[/tex]
Now,
f=Ma
or,
f/a=M
or,
22/9.8=M
or,
2•24=M
or,
M=2.24kg
A textbook is dropped from a second floor window and falls to the ground. What happens to the acceleration as the book falls to the ground
-the acceleration increases
-the acceleration decreases
-the acceleration remains constant *
Answer:
The correct option is;
The acceleration remains constant
Explanation:
The acceleration is due to the force of gravitational attraction between the text book and the Earth
According to Newton's law of gravitation, there is an attractive force between all objects given by the following relation;
F = G×M₁×m₂/r²
Where;
G, M₁, m₂, and r are constant such that we have;
G×M₁/r² = Constant = The acceleraton due to gravity, g
F = g×m₂
So the acceleration of the textbook as it is being attracted by the force of gravity towards the ground (Earth) is remains constant.
A car drives 10km with a speed of 72 km/hr and then runs out of gas. Then you walk 2km for the next 30 min
until you find a gas station.
Given :
A car drives 10 km with a speed of 72 km/hr and then runs out of gas.
Then you walk 2 km for the next 30 min until you find a gas station .
To Find :
The average speed of whole journey .
Solution :
Average speed is given by :
[tex]v_{avg}=\dfrac{\text{Total distance covered}}{\text{Total time taken}}\\\\v_{avg}=\dfrac{10+2}{\dfrac{10}{72}+\dfrac{1}{2}}\\\\\\v_{avg}=18.78\ km/hr[/tex]
Hence , this is the required solution .
Sal sprinted 40 m to the right in 5.5s what is his average velocity
Answer: 7.27 m/s
Explanation:
To win the game, a place kicker must kick a
football from a point 52 m (56.8672 yd) from
the goal, and the ball must clear the crossbar,
which is 3.05 m high. When kicked, the ball
leaves the ground with a speed of 26 m/s at
an angle of 31.5◦ from the horizontal. The acceleration of gravity is 9.8 m/s2.
By how much vertical distance does the ball clear the crossbar?
Answer in units of m.
Answer:
1.86 m
Explanation:
First, find the time it takes to travel the horizontal distance. Given:
Δx = 52 m
v₀ = 26 m/s cos 31.5° ≈ 22.2 m/s
a = 0 m/s²
Find: t
Δx = v₀ t + ½ at²
52 m = (22.2 m/s) t + ½ (0 m/s²) t²
t = 2.35 s
Next, find the vertical displacement. Given:
v₀ = 26 m/s sin 31.5° ≈ 13.6 m/s
a = -9.8 m/s²
t = 2.35 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (13.6 m/s) (2.35 s) + ½ (-9.8 m/s²) (2.35 s)²
Δy = 4.91 m
The distance between the ball and the crossbar is:
4.91 m − 3.05 m = 1.86 m
