The center of a 1500 kg kg satellite is 9.9 ×10^6 m from Earth’s center. What is the gravitational force between the satellite and Earth?

Materials with high specific heat include materials such as concrete, masonry, adobe, and some types of stone. These materials can be used in walls, floors, or roofs to provide thermal mass and improve indoor comfort, energy efficiency, and sustainability.

Answer:

V = a t      velocity after time t

t = 33.1 / 9.80 = 3.38 sec   (time ball had been falling)

S = 1/2 a t^2 = 55.9 m

So the ball had been falling  for 7 * 8 = 56 m  

The child was 7 floors from the top

Since he was on the eight floor the floors below him were

7 * 8 + 12 = 68 m     total floors below child

68 + 56 = 124 m      total height of building

Total floors in building = 7 + 7 + 1 = 15 floors

PE at top = KE at bottom

KE = m g h = .125 * 9.80 * 124 = 152 Joules

Answer:

(D is correct

1) Since each bulb has a resistance of 3.00 Ω, we can calculate the number of bulbs: n = R/R_bulb = 96 Ω/3.00 Ω = 32 bulbs. There are 32 light bulbs in the circuit.

2) The total resistance is equal to the sum of individual resistances: R_C = 120 Ω - 6 Ω - 18 Ω = 96 Ω. The resistance of bulb C is 96 Ω.

In a series circuit, the total resistance is equal to the sum of individual resistances. Using Ohm's Law, we can find the total resistance:

R = V/I = 120.0 V/1.25 A = 96 Ω

Since each bulb has a resistance of 3.00 Ω, we can calculate the number of bulbs:

n = R/R_bulb = 96 Ω/3.00 Ω = 32 bulbs

Therefore, there are 32 light bulbs in the circuit.

In a series circuit, the total resistance is equal to the sum of individual resistances:

R_eq = R_A + R_B + R_C

Substituting the given values:

120 Ω = 6 Ω + 18 Ω + R_C

Solving for R_C:

R_C = 120 Ω - 6 Ω - 18 Ω = 96 Ω

Therefore, the resistance of bulb C is 96 Ω.

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The displacement is defined as the shortest distance between the starting and ending point along with the direction. Thus, option D is correct.

The displacement is defined as the shortest distance between the starting and ending point. The displacement is the vector quantity. It is also defined as the distance traveled by the object along with a particular direction. The distance is the scalar quantity and the displacement is the vector quantity. The SI unit of distance is a meter. The rate of change of displacement gives rise to velocity and the rate of distance gives rise to distance.

From, the given displacement is defined as the shortest length and direction from a starting and ending point. Thus, the correct option is D.

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Answer:

D. X-rays have more energy than ultraviolet waves.

The length of the pendulum can be calculated using the formula:

T = 2π√(L/g)

Where T is the period of the pendulum, L is the length of the pendulum, and g is the acceleration due to gravity.

We can rearrange this formula to solve for L:

L = gT^2 / (4π^2)

Given that the pendulum takes 43.6 seconds to complete 10 full swings, the period of the pendulum is:

T = (43.6 seconds) / (10 swings) = 4.36 seconds/swing

The acceleration due to gravity is approximately 9.8 m/s^2.

Substituting these values into the formula, we get:

L = (9.8 m/s^2) × (4.36 s/swing)^2 / (4π^2) = 5.51 m

Therefore, the length of the pendulum is 5.51 m.

Answer: L = 4.72 m

Explanation:

t=43.6 seconds, n=10

T= t/n = time period

= 43.6s/10 = 4.36s

t = 2pie square root of L/g

L= length

L = t^2/4pie^2g

4.36^2 x 9.8/4(22/7)^2

L = 4.791 m

L = 4.72 m

The standard kilogram is a physical object which weighs exactly 1 kilogram and is used as the primary reference for the kilogram unit of mass.

The standard kilogram, also known as the international prototype of the kilogram (IPK), is a physical artifact. It is kept at the international bureau of weights and measures and is used as the primary standard for the kilogram unit of mass.

The international prototype of the kilogram (IPK), is a cylindrical shape with a height of 39 mm and a diameter of 39 mm, and it has a mass of exactly 1 kilogram (1000 grams).

Thus, the standard kilogram is a physical object which weighs exactly 1 kilogram and is used as the primary reference for the kilogram unit of mass.

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The given example is a kind of verbal persuasion. So, option B.

Verbal persuasion is defined as inspiring and motivating others through positive words. When athletes are undertaking competitions, it is done by the people those who are not now participating and are being supportive, motivating, and energizing one another.

The verbal persuasion factor highlights the beneficial effects that words may have on someone's sense of self-efficacy.

In order to overcome self-doubt and concentrate on achieving the goal at hand their best effort, people need verbal persuasion from others.

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Three facts I have learned this year in Physical Education are:

a) The importance of stretching before and after exercising.

b) The benefits of cardiovascular exercise.

c) The importance of staying hydrated during exercise.

Firstly, I have learned the importance of stretching before and after exercising. Stretching helps prevent injury and improves flexibility. I will make sure to incorporate stretching into my daily routine, whether it's through a short stretching session in the morning or by taking a few minutes to stretch before and after a workout.
Secondly, I have learned the benefits of cardiovascular exercise. Cardiovascular exercise, such as running or cycling, helps improve heart health and endurance. I will try to incorporate more cardiovascular exercise into my daily routine, such as going for a run or bike ride after work.
Lastly, I have learned the importance of staying hydrated during exercise. Dehydration can lead to fatigue and muscle cramps, so it's important to drink plenty of water before, during, and after exercise. I will make sure to carry a water bottle with me throughout the day and refill it regularly to ensure that I am staying hydrated.
In summary, by incorporating stretching, cardiovascular exercise, and staying hydrated into my daily routine, I hope to improve my overall physical health and well-being.

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Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

Given:

Apparent power (S) = 10 KVA = 10,000 VA

Line voltage (V) = 380 V

Frequency (f) = 50 Hz

Xd = 12 ohms

Xq = 8 ohms

Ra = 1 ohm

Power factor (pf) = 0.8 lagging

Load angle (δ) = 16.15 degrees

(i) Armature current's direct axis and quadrature axis components

We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:

S = 3Vphase Iphase cos(φ)

Iphase = S / (3Vphase cos(φ))

For a lagging power factor, cos(φ) = 0.8, so

Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A

The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current.  Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:

Id = (VL - IaRa) / Xd

Iq = (VL - IaRa) / Xq

where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,

Ia = Iphase / √3 = 10.46 / √3 = 6.03 A

Substituting the given values:

Id = (380 - 6.03 x 1) / 12 = 30.28 A

Iq = (380 - 6.03 x 1) / 8 = 46.92 A

(ii) Excitation voltage of the generator:

The excitation voltage (E) of the generator is given by:

E = Vphase + IqXq

Substituting the given values:

E = 380 + 46.92 x 8 = 765.36 V

Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

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The enthalpy change of the formation for solid iodine trichloride is -74 kJ/mol. This indicates that the formation of solid iodine trichloride is exothermic

The enthalpy change of the formation for solid iodine trichloride (ICl3) can be calculated using Hess's law, which states that the total enthalpy change of a chemical reaction is independent of the route by which the reaction occurs.

First, we need to write the balanced chemical equation for the formation of solid ICl3 from its elements:

I2(s) + 3Cl2(g) → 2ICl3(s)

According to Hess's law, the enthalpy change of this reaction is equal to the sum of the enthalpy changes of the following two reactions:

I2(s) + Cl2(g) → 2ICl(g) ΔH1

ICl(g) + Cl2(g) → ICl3(s) ΔH2

where ΔH1 is the enthalpy change for the reaction between iodine and chlorine to form gaseous iodine trichloride, and ΔH2 is the enthalpy change for the condensation of gaseous iodine trichloride to form solid iodine trichloride.

The enthalpy change for the first reaction is given as ΔH1 = +14 kJ/mol, and the enthalpy change for the second reaction is given as ΔH2 = -88 kJ/mol. Therefore, the enthalpy change of the formation for solid iodine trichloride can be calculated as:

ΔHf°(ICl3,s) = ΔH1 + ΔH2

= (+14 kJ/mol) + (-88 kJ/mol)

= -74 kJ/mol

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After analysing the given data we conclude that the given statement is considered true.

The greater the power rating in the electrical appliance, the larger energy is applied every second. And hence longer the usage time, the more electrical energy is consumed.
A process through which measures  the maximum amount of power that can be applied with a specific tool or device is known as power rating . It is placed in a series to keep the user safe and apply  prevention of the tool or device from becoming damaged.
The power rating generally results from a combination of the maximum power requirements of the electrical load on the consumption side during discharging and the most frequently appearing excess power on the input power during charging.
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On two planets with the same size, mass, and direction of travel, your weight will be the same on both planets. Option A.

The weight of an object depends on its mass and the strength of the gravitational force acting on it.

Since planets A and B have the same size and mass, their gravitational forces will be the same. Therefore, an object placed on either planet will experience the same gravitational force and hence the same weight.

The speed of the planets has no effect on the weight of an object on them. Therefore, options (B), (C), and (D) are incorrect.

In other words, you would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

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Answer:

To gain momentum before the jump is made

Answer:

unicellular

Explanation:

it's a archea so its unicellular

The distance between two consecutive nodes on this standing wave if the two waves traveling in the same medium is half of the wavelength.

The standing wave is defined as a stationary wave in which a combination of two waves moves in opposite directions with the same amplitude and same frequency. This phenomenon results in Interference. When two waves are superimposed the output waves are added up to each other and cancel out each other.

From the given, the two waves traveling in the same medium and having the same wavelength (λ) interfere to create the standing wave. The distance between two consecutive nodes is half of the wavelength and hence the distance is λ/2.

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At the given instant, the radial acceleration of the particle moving clockwise in a circle of radius 2.5 m is 21.650 m/s², its speed is 11.625 m/s, and its tangential acceleration is 12.5 m/s².

In circular motion, there are three important quantities: radial acceleration, tangential acceleration, and speed.

At the given instant, the radial acceleration (ar) can be calculated as:

ar = a cosθ

ar = 25 m/s² × cos30°

ar = 25 × 2/3

ar = 21.650 m/s²

The speed of the particle (V) can be calculated as:

V = r ×θ'

θ' = sqrt(rar/r)

θ' = sqrt(2.5×21.650/2.5)

θ' = sqrt(21.65)

θ' = 4.65 rad/s

V = r × θ'

V = 2.5 × 4.65

V = 11.625 m/s

The tangential acceleration (aθ) can be calculated as:

aθ = a sinθ

aθ = 25 m/s² ×sin30°

aθ = 25 × 1/2

aθ = 12.5 m/s²

Therefore, The particle is traveling clockwise in a circle with a radius of 2.5 m, its tangential acceleration is 12.5 m/s², its speed is 11.625 m/s, and its radial acceleration is 21.650 m/s².

I think the actual question is,

The figure shows( find at the bottom of this answer) the total acceleration and velocity of a particle moving clockwise in a circle of radius 2.5 m at a given instant of time. At this instant, find:

(a) the radial acceleration,

(b) the speed of the particle and

(c) its tangential acceleration.

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The Hagen-Poiseuille equation may be used to determine the blood flow rate that is maximum on average at 37°C in an artery with a radius of 2.25 mm. According to this equation, the volumetric flow rate of a laminar flow is equal to the fourth-power product of the vessel's radius (r) and the pressure difference (P) divided by the fluid's viscosity ().

It also takes into account the length (L) of the vessel. The highest average blood flow rate in an artery with a radius of 2.25 mm may be computed using the information provided as follows: Q = (2.25^4 * ΔP) / (2.084*10^-3 * L) Q = (2.25^4 * ΔP) / (2.084*10^-3 * L) Q = (2.25^4 * ΔP) / (2.084*10^-3 * L) Q = (2.25^4 * ΔP) / (2.084*10^-3 * L)

Consequently, the highest average blood flow rate at  Therefore, the greatest average speed of blood flow at 37∘C in an artery of radius 2.25 mm is equal to (2.25^4 * ΔP) / (2.084*10^-3 * L).

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Answer:

It could be both Joules or Watts, Watts for electrical measurements and Joules for power measuremnets.

Hope this helps :)
Pls brainliest...

The heating time constant is 13 seconds and the steady state temperature is 38°C.

To find the heating time constant and steady state temperature, use the formula:

ΔT = P × R × (1 - e^(-t/τ))

where ΔT = temperature rise, P = power, R = thermal resistance, t = time, τ = heating time constant, and e = natural logarithmic constant.

Let's use the given information to solve for τ:

ΔT1 = 25°C (for the first 25 minutes)

ΔT2 = 40°C (for the second 25 minutes)

t = 25 + 25 = 50 minutes

The temperature rise over the entire 50 minutes is:

ΔT = ΔT1 + ΔT2 = 25°C + 40°C = 65°C

The average power can be calculated as:

P = ΔT / (t × R)

Assume that the power output is the rated power of the motor. Let's assume that the rated power is 100 W.

Then, solve for R:

R = ΔT / (t × P) = 65°C / (50 min × 100 W) = 0.13 °C/W

Now, solve for the heating time constant:

τ = R × C

where C = thermal capacitance. Value of C is unknown, but make an assumption that the thermal time constant is on the order of minutes to hours. Let's assume that C = 100 J/°C.

Then, τ = 0.13 °C/W × 100 J/°C = 13 seconds

Finally, solve for the steady state temperature:

ΔT = P × R

T_ss = T_amb + ΔT = 25°C + 100 W × 0.13°C/W = 38°C

Therefore, the heating time constant is 13 seconds and the steady state temperature is 38°C.

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Answer:

same power source

can have more than 1 light bulb in a circuit

requires a source of energy

Explanation:

Answer:

Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.

To increase a car's acceleration, the engineers should consider decreasing the car's mass and/or increasing the force that the engine provides. Therefore, options A and D are the correct answers.

Acceleration is directly proportional to the net force acting on an object and inversely proportional to its mass. This means that a smaller mass or a larger force will result in a greater acceleration. Therefore, reducing the mass of the car will require less force to achieve the same acceleration, or the same force will result in a greater acceleration.

To decrease the mass of the car, the engineers could consider using lighter materials for the car's body and frame or removing unnecessary components. On the other hand, to increase the force that the engine provides, the engineers could consider upgrading the engine or increasing the fuel intake.

Option B, which suggests decreasing the force that the engine provides, would have the opposite effect and result in a slower acceleration. Option C, which suggests increasing the mass of the car, would also have the opposite effect and require more force to achieve the same acceleration.

Option E, which suggests increasing the top velocity the car can travel, is not directly related to acceleration. Top velocity refers to the maximum speed that a car can reach, whereas acceleration refers to the rate of change of velocity. While increasing the car's top velocity may indirectly affect acceleration, it is not a direct solution to increasing acceleration.

Option A and D.

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A person with a low prejudice profile is likely to reject negative stereotypes. Option A.

A person with a low prejudice profile is likely to reject negative stereotypes and not make assumptions about individuals based on their group membership.

This is because a person with a low prejudice profile is more likely to have a positive attitude toward diverse groups and recognize that individuals within a group can vary widely in their abilities, attitudes, and behaviors.

By listing positives about the ethnic group, this person can acknowledge the group's strengths and challenge any negative stereotypes that may exist.

Options (a), (b), and (c) do not reflect a low prejudice profile and may perpetuate negative stereotypes or avoid the conversation altogether.

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A. The work done, given that the distance is 10 meters is 11756.08 Joules

B. The power necessary to do the work is 195.93 W

First, we shall convert 44 pound to Kg. Details below:

1 pound = 0.4536 Kg

Therefore,

44 pound = 44 × 0.4536

44 pound = 19.96 Kg

Finally, we shall determine the work done. Details below:

Work done (Wd) = force (F) × distance (d)

Work done (Wd) = 1175.608 × 10

Work done (Wd) = 11756.08 Joules

The power necessary to do the work can be obtain as follow:

Power is defined according to the following formula:

Power = Work done / time

P = Wd / t

P = 11756.08 / 60

Power = 195.93 W

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Answer:

The sweepers motion adds torque to the stone's angular momentum.

Explanation:

This is due to angular momentum law.

If a piece of metal at the bottom of a beaker is 0.50m below the eye, and water is poured into the cylinder to a depth of 0.24m, Then the metal appears closer by 0.38m.

To calculate how much closer the metal appears, we can use the lens maker's formula, which relates the object distance, image distance, and focal length of a lens or in this case, the refractive index of water.

The formula is:

1/f = (n - 1) x (1/R1 - 1/R2)

where f is the focal length, n is the refractive index of the medium (water in this case), R1 is the radius of curvature of the first surface of the medium (in this case, the bottom surface of the beaker), and R2 is the radius of curvature of the second surface of the medium (in this case, the air-water interface at the top of the water level).

Assuming the radius of curvature of both surfaces is large and the surfaces are nearly flat, we can approximate R1 and R2 as infinity, so the formula simplifies to:

1/f = (n - 1) x (1/R2)

Since the piece of metal is at the bottom of the beaker, it acts as the object, and the eye acts as the observer. Initially, the object distance is the distance from the bottom of the beaker to the eye, which is 0.50m.

When water is poured into the beaker to a depth of 0.24m, the new object distance is the distance from the bottom of the beaker to the water level, which is 0.50m - 0.24m = 0.26m.

To calculate the image distance, we can use the thin lens equation:

1/f = 1/o + 1/i

where o is the object distance, and i is the image distance.

Solving for i, we get:

i = (1/f - 1/o)^-1

Since we know that the object distance o is 0.26m, we just need to calculate the focal length f using the lens maker's formula.

1/f = (n - 1) x (1/R2) = (4/3 - 1) x (1/0.24m) = 1/0.72m

f = 0.72m

Plugging in the values, we get:

i = (1/0.72m - 1/0.26m)^-1 = 0.12m

Therefore, the metal appears closer by 0.50m - 0.12m = 0.38m.

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The effective capacitance of the following combination with capacitors C₁, C₂, C₃, C₄, C₅ = 100μF is 350 μF.

Capacitors are the energy storage device in the form of electrical energy. The amount of charge (Q) stored in the capacitors is linearly proportional to the applied Voltage (V). Capacitance equals the ratio of charge and voltage. The unit of capacitance is Farad (F). Capacitors are connected in series and parallel connections. In series connections, the capacitance is 1/C(eff) = 1/C₁ + 1/C₂. In parallel connections, the effective capacitance C(eff) = C₁ + C₂.

From the figure,

The capacitances, C₁, C₄, C₂ are parallelly connected whereas C₃ and C₅ are in series connections.

C(eff) = C₁ + C₂ + C₄ = 100 + 100 + 100 = 300 μF

The capacitance C₅ and C₃ are in series connections, then

1/C(eff) = 1/C₅ + 1/C₃ = 1/100 + 1/100 = 2/100 = 1/50

C(eff) = 50  μF

The effective capacitance = 300 + 50 = 350  μF.

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