The charges on the proton and electron are typically measured in: Select the correct answer below: volts amperes coulombs daltons

Answers

Answer 1

Answer: columbs

Explanation:

Electrical charge are measured in columbs, usually demoted as C. Hence, the charges on proton and electron will be measured in Coloumbs. It typically measures the amount of electricity conveyed per second by a current of 1 ampere. The other units Given such as ; Volt is used for measuring voltage, which is the pressure in an electrical source. AMPERE is used for measuring the current flowing through an electrical circuit.

Dalton is a unit of mass and is about 1.660 * 10^-27 kg


Related Questions

27. The pressure at A is 9.5 atm and the water velocity is 10 m/s. What is the water velocity at point C

Answers

Answer:

10 m/s

Explanation:

Which type of reaction does this chemical equation represent? 2Na + MgCl2 - 2NaCl + Mg
A. Synthesis
B. Decomposition
C. Single-replacement
D. Double-replacement​

Answers

The answer is in fact c

The type of reaction the chemical equation represent is a decomposition reaction.

What is decomposition reaction?

Decomposition reaction is a type of chemical reaction in which a large compound is broken down or degraded into simpler substances.

Therefore, type of reaction the chemical equation represent is a decomposition reaction.

Learn more about decomposition reaction.

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5.38 An ideal spring has the spring constant k = 440 N/m. Calculate the
distance this spring must be stretched from its equilibrium position for
25 J of work to be done.

Answers

What do you need help on ???? !!mxmzkx You dde e

The spring stretched 0.476 meter from equilibrium position.

The work done is given as,

                             [tex]workdone=\frac{1}{2}kx^{2}[/tex]

Where x is the distance stretched from  equilibrium position.

Given that,   [tex]k=440N/m,W=25J[/tex]

              [tex]25=\frac{1}{2}*440*x^{2} \\\\x^{2} =\frac{100}{440}=0.227\\\\x=\sqrt{0.227}=0.476m[/tex]

Therefore, the spring stretched 0.476 meter from equilibrium position.

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Two firefighters are trying to break through a door. One firefighter is heavy, and the other is light. If they run at the same speed, which one is more likely to break through? Explain.

Answers

Answer:

The Heavier Firefighter

Explanation:

Generally, more massive objects will have more intertia than less massive objects.  As such it takes more force to halt a more massive object if its moving at the same speed as a smaller object. This can also be thought of in the context of Newton's second law. The more force needed to accelerate an object means the more force the object will have.

At equal speed, the firefighter with more weight will have more momentum and exact more force which will cause breakthrough.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

Acceleration is the change in velocity per change in time of motion.

The law can also be written as;

[tex]F = ma = \frac{mv}{t}[/tex]

Also, momentum is given as the product of mass and velocity.

P = mv

Thus, at equal speed, the firefighter with more weight will have more momentum and exact more force which will cause breakthrough.

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A string has its 4th harmonic at 31.5 Hz. What is the fundamental frequency?


Unit= Hz

Answers

Answer:

7.9Hz

Explanation:

Step one:

given data

We are told that the fourth harmonic is at 31.5 Hz

We know that harmonics are a multiple of the fundamental frequency, such that if the fundamental frequency is 25Hz, then the second harmonic is

2nd= 2*25= 50Hz

3rd= 3*25= 75Hz........and so on

Step two:

In this problem, we are told that the 4th harmonic is 31.5Hz, that is

4th= 4*f= 31.5

Divide both sides by 4 to get f

f= 31.5/4

f= 7.9 Hz

Hence the first/fundamental frequency is 7.9Hz

Answer:

its 7.9 tried it on acellus

Explanation:

A pitcher throws a 0.143-kg baseball toward the batter so that it crosses home plate horizontally and has a speed of 42 m/s just before it makes contact with the bat. The batter then hits the ball straight back at the pitcher with a speed of 49 m/s. Assume the ball travels along the same line leaving the bat as it followed before contacting the bat. If the ball is in contact with the bat for 0.005 0 s, what is the magnitude of the average force exerted by the bat on the ball?

Answers

Answer:

200N appox

Explanation:

Step one:

Given data

mass of ball= 0.143kg

initial velocity of ball u= 42m/s

final velocity of the ball= 49m/s

time of impact= 0.005s

Step two

From the relation Ft=mΔv

we can find the average force as

F=mΔv/t

substitute

F=0.143*(49-42)/0.005

F=0.143*7/0.005

F=1.001/0.005

F=200.2

F= 200N appox

The average force is  200N

NEED HELP ASAP!!!!
A car drives around a racetrack for 30 seconds. What do you need to know to
calculate the average velocity of the car?
O A. The slope of the car's velocity-time graph
O B. The total displacement of the car
O C. The area under the position-time graph
O D. The slope of the car's position-time graph

Answers

The answer is B
I rhink

A car drives around a racetrack for 30 seconds. To calculate the average velocity of the car we need to know about distance. from option B and D we can calculate velocity. Therefore option B and D is correct.

What is velocity ?

Velocity is "rate of change of displacement with respect to time".

i.e. v= dx/dt. it is also defined as displacement over time.

i.e. v=Displacement/Time. Velocity shows how much distance can be covered in unit time. It's SI unit m/s. Dimension of velocity is  [M⁰ L¹ T⁻¹].

Option A) The slope of the car's velocity-time graph.

it gives Velocity/time. we can not find average velocity with this data.

Option B) The total displacement of the car.

when we know displacement and time, we can calculate velocity. therefore this option is correct.

Option C) The area under the position-time graph.

This gives position×time, which is useless to find velocity.

Option D) The slope of the car's position-time graph.

this gives velocity of the car. Therefore this option is correct.

Hence option B and D is correct, we can calculate average velocity from them.

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I need help, please.

Answers

Answer:

sorry I don't know it

Explanation:

Activity

Many characters portrayed in the media suffer from psychological disorders. For example, piglet from Winnie the Pooh has generalized anxiety

disorder and Elsa from the movie Frozen has agoraphobla. Similarly, Identify at least four characters from movies or television shows and

describe the disorders the characters suffer from in the stories.

Answers

Answer:

Explanation:

Belle from beauty and the beast has what they call Stockholm syndrome.

Spongebob from Spongebob square pants has what is called Williams-Beuren syndrome

Ariel from the Little Mermaid has what they call Disposophobia.

Alice from Alice in the wonderland has what is called schizophrenia

Scar from the Lion King has what is known as anti social personality disorder.

Like the question suggested, many characters suffer different types of disorder, and I've just listed out a few

What is force? In physics class eleven​

Answers

Answer:

Explanation:

In Physics, force is defined as: The push or pull on an object with mass that causes it to change its velocity. Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a directionForce is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction. The direction towards which the force is applied is known as the direction of the force and the application of force is the point where force is applied.

The Force can be measured using a spring balance. The SI unit of force is Newton(N).

A wave is described by y(x,t) = 0.1 sin(3x + 10t), where x is in meters, y is in centimeters and t is in seconds. The angular wave number is:

Answers

Answer: 3 radians/meter.

Explanation:

The general sinusoidal function will be something like:

y = A*sin(k*x - ω*t) + C

Where:

A is the amplitude.

k is the wave number.

x is the spatial variable

ω is the angular frequency

t is the time variable.

C is the mid-value.

The rule that we can use to solve this problem, is that the argument of the sin( ) function must be in radians (or in degrees)

Then if x is in meters, the wave-number must be in radians/meters, so when these numbers multiply the "meters" part is canceled.

Then for the case of the function:

y(x,t) = 0.1 sin(3x + 10t)

Where x is in meters, the units of the wave number (the 3) must be in radians/meters. Then the angular wave number is 3 radians/meter.

Angular wave number is measured in rad/s. the angular wave number in the given equation is 10 rad/s.

Angular wave number:

It is the number of wavelengths per unit distance. It is also known as angular frequency.  It is measured in rad/s.

For given equation,

[tex]\bold{y(x,t) = 0.1 sin(3x + 10t)}[/tex]

Angular wave number  is the parameter which is multiplied by time (t). So, it is the number 10,  this will be measured in rad/s.  

Therefore, the angular wave number in the given equation is 10 rad/s.

To know more about angular wave number, refer to the link:

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Tim, with mass 73.1 kg, climbs a gymnasium rope a distance of 4.6 m. The acceleration of gravity is 9.8 m/s 2 . How much potential energy does Tim gain? Answer in units of J.​

Answers

Answer:

3,295.348Joules

Explanation:

Potential Energy = mass * acceleration due to gravity * height

Given the following

Mass = 73.1kg

Acceleration due to gravity = 9.8m/s²

Distance (Height) = 4.6m

Substitute into the formula;

Potential Energy = 73.1 * 9.8 * 4.6

Potential Energy = 3,295.348Joules

Hence Tim gain 3,295.348Joules of energy

17. Calculate the amount of gravitational potential energy at the top of one 4 points hill. The mass of the coaster is 500 kg. The height from the hill to the valley is 59.6 m. Use 9.81 m/s^2 as the acceleration due to gravity. Record your calculations in joules. (Hint: Gravitational PE = mgh)

A. 292.338 m/s^2

B. 3037 J

C. 82.3 kg

D. 292,338 J​

Answers

Answer: D. 292,338 J

This is the correct answer :)

Choose all the answers that apply.

Which of the following characteristics are found in flowering plants?

1. seeds
2. cones
3. reproduction by spores
4. vascular tissue
5. fruit

Answers

Seeds And Reproduction By Spores

Answer:

Seeds And Reproduction By Spores

Explanation:

Did on Odyssey


1. The directional movement of ions by facilitated diffusion through protein channels is determined by

Answers

Answer:

The electrochemical gradient of the ion that is being transported.

Explanation:

Facilitated diffusion through protein is defined as a form of facilitated transport whereby passive movement of ions along concentration gradients are guided by the presence of other ions.

Thus, the electrochemical gradient of the ion being transported is what facilitates it

Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near 15.m. Calculate the frequency of these radio waves. Round your answer to 2 significant digits.

Answers

Answer:

20 MHz

Explanation:

Since speed of radio waves = speed of light = c and for a wave, v = fλ where v = speed of wave, f = frequency and λ = wavelength.

Given that λ = 15 m and v = c = 3 × 10⁸ m/s

f = v/λ

substituting the values of the variables into the equation, we have

f = v/λ = 3 × 10⁸ m/s ÷ 15 m

= 0.2 × 10⁸ Hz

= 2 × 10⁷ Hz

= 20 × 10⁶ Hz

= 20 MHz

A marksman holds a rifle with a mass of 2.57 kg loosely, so it can recoil freely. He fires a bullet with a mass of 3.65 g horizontally with a velocity relative to the ground of 318.4 m/s. What is the final kinetic energy in J of the rifle

Answers

Answer:

KE = 0.262 J

Explanation:

given data

rifle with  mass  Mr = 2.57 kg

bullet with mass Mb = 3.65 g

velocity relative to the ground Vb = 318.4 m/s

solution

we get here final KE of rifle that is express as

KE = 0.5 × Mr × (Vr)²    ..............1

here Vr is

Mb × Vb = Mr × Vr         .........2

put here value

3.65 × [tex]10^{-3}[/tex]  × 318.4 = 2.57 × Vr

Vr = 0.452 m/s

now put value in eq 1 we get

KE = 0.5 × 2.57 × (0.452)²

KE = 0.262 J

a tool for studying motion is called?

Answers

Answer:

phytochemical

Explanation:phytochemical is a tool for studying motion

A 235 kg crate is pulled across a horizontal surface with a force of 760 N applied at an

angle of 30° above the horizontal. Determine the horizontal component of the applied

force

Answers

Answer:

658.16N

Explanation:

Step one:

given data

mass m= 235kg

Force F= 760N

angle= 30 degrees

Required

The horizontal component of the force

Step two:

The horizontal component of the force

Fh= 760cos∅

Fh=760cos30

Fh=760*0.8660

Fh=658.16N

Calculate the work needed to lift a block weighing 4 Newton’s a distance of 10 meters. Help me please.

Answers

Answer:

W = 40 J

Explanation:

The work done by a force is defined as the dot product of the force and displacement of the object. Therefore, the following formula can be used to find the work done:

[tex]W = F.d = Fd Cos\theta\\[/tex]

where,

W = Work Done = ?

F = Force = Weight of Block = 4 N

d = distance lifted = 10 m

θ = angle between force and displacement = 0°

Therefore,

[tex]W = (4\ N)(10\ m)(Cos\ 0^{0})[/tex]

W = 40 J

A generator transforms?

Answers

A generator transforms mechanical energy into electrical energy

So B.

g 2. _______The property(ies) of a thermal system is (are)(A) temperature or (B) internal energy or (C) work.

Answers

Answer:

(A) temperature

Explanation:

Given that thermal properties of a material are those properties that can be observed or felt when the heat is added to the material.

Hence, in this case, the correct answer is "Temperature."

On the other hand, the internal energy is not a thermal property but rather an extensive property that cannot be assessed directly.

Also, work is not a thermal property but rather a process quantity.

A woman of mass 50 kg is swimming with a velocity of 1.6 m/s. If she stops stroking and glides to a stop in the water, what is the impulse of the force that stops her?

Answers

Answer:

– 80 Ns.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 50 kg

Initial velocity (u) = 1.6 m/s

Final velocity (v) = 0 m/s

Impulse (I) =?

Impulse is simply defined by the following equation:

I = Ft = m(v – u)

I = 50 (0 – 1.6)

I = 50 (–1.6)

I = – 80 Ns

Thus, the impulse of the force that stopped her is – 80 Ns.

NOTE: The negative sign indicates that the net force is in opposite direction to her movement.

Eating 2500 Cal every day a friend of mine maintains a stable weight of 70 kg. One day, after eating 3500 Cal, he decided to do extra exercise to avoid gaining weight. He was doing jumps: he leaves the ground with a speed of 3.3m/s at every jump. Assuming that his body turns energy to mechanical work with a 25 % efficiency, how many jumps he will have to make

Answers

Answer:

2721

Explanation:

First, we find the change in calories

E = E(taken) - E(daily)

E = 3500 - 2500

E = 1000 cal

Next, we use the efficiency to find the available metabolic energy

E' = n.E, where n = efficiency

E' = 0.25 * 1000

E' = 250 cal

Converting this cal to J, we have

1 cal = 4.18 J

250 cal = 250 * 4.18 J

250 cal = 1045 kJ

Given that the final velocity is 0, we use equation of motion to find the height, h attained

u² = 2gh

h = u²/2g

h = 3.3² / 2 * 9.81

h = 10.89 / 19.62

h = 0.56 m

Potential energy, E = mgh

E = 70 * 9.8 * 0.56

E = 384 J

Total number of jumps, n =

n = 1045 / 384

n = 2721 jumps

A spring has an elastic constant of 8.75 x 103 N/m. What is the magnitude of the force required to stretch this spring a distance of 28.6 cm from its equilibrium position?

Answers

Given :

A spring has an elastic constant of 8.75 x 10³ N/m.

To Find :

The magnitude of the force required to stretch this spring a distance of 28.6 cm from its equilibrium position.

Solution :

We know, force required to stretch a spring of spring constant k and distance x is given by :

[tex]F = \dfrac{kx^2}{2}[/tex]

Putting all given values, we get :

[tex]F = \dfrac{8.75\times 10^3 \times 0.286^2}{2}\\\\F = 357.86\ N[/tex]

Hence, this is the required solution.

A satellite is launched to orbit the Earth at an altitude of 2.25*107 m for use in the Global Positioning System (GPS). Take the mass of the Earth to be 5.97*1024 kg and its radius 6.38*106 m.
What is the orbital period of this GPS satellite?

Answers

Answer:orbital period of this GPS satellite, T= 48,874.4 s

Explanation:

Altitude (h)= 2.25 X 10^7 m

Radius of the Earth  ( r)=6.38 X 10^6 m

The distance from center of the Earth to the point is given as  

R = r +h

6.38 x 10^6 m+ 2.25 x 10^7 m

=28,880,000=2.888 x 10^7m

Also, Mass of the Earth  =5.97 x 10^24 kg  

and Gravitational Universal Constant

= 6.67 x 10^-11N.m2/kg2

Orbital period  T

=   2π

=2 X 3.142[tex]\sqrt{ (2.888 x 10^7m)^3 /6.67 x 10^-11N.m2/kg2 X 5.97 x 10^24 kg}[/tex]

2X 3.142 [tex]\sqrt{60,491088.9}[/tex]

= 2X 3.142 X 7,777.60

T= 48,874.4 s

A tennis player's racket applies an average force of 200. newtons to a tennis ball for 0.025 second. The average force exerted on the racket by the tennis ball
is

Answers

Answer:

200N

Explanation:

The average force exerted on the racket by the tennis ball is equal to 200 Newton.

Given the following data:

Average force = 200 NewtonTime = 0.025 seconds

To determine the average force exerted on the racket by the tennis ball, we would apply .Newton's Third Law of Motion.

Newton's Third Law of Motion states that for every action there must exist an equal but opposite reaction. Thus, Newton's Third Law of Motion is a law based on action-reaction force pairs.

In this scenario, the tennis ball would exert the same magnitude of average force on the racket in accordance with Newton's Third Law of Motion.

Average force = 200 Newton

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If the melanin lines on the wing are spaced 2.0 μm apart, what is the first-order diffraction angle for green light (λ = 550 nm)?

Answers

This question is incomplete, the complete question is;

The wings of some beetles have closely spaced parallel lines of melanin, causing the wing to act as a reflection grating. Suppose sunlight shines straight onto a beetle wing.

If the melanin lines on the wing are spaced 2.0 μm apart, what is the first-order diffraction angle for green light (λ = 550 nm)?

Answer:

the first-order diffraction angle for green light is 15.96°

Explanation:

Given the data in the question;

from diffraction theory;

nλ = dsin∅

where n is the diffraction order ( 1st order = 1 )

λ is the wavelength ( 550 nm  = 550 × 10⁻⁹ m)

d is the grating spacing ( 2.0 μm = 2.0 × 10⁻⁶ m )

∅ is the diffraction angle ( ? )

so we substitute

nλ = dsin∅

sin∅ = nλ / d

sin∅ = (1 × 550 × 10⁻⁹ m) / 2.0 × 10⁻⁶ m

sin∅ = 0.275

∅ = sin⁻¹(0.275)

∅ = 15.96°

Therefore, the first-order diffraction angle for green light is 15.96°

Describe a grand challenge in today's society?

Answers

Hunger, homelessness, etc

how many times can the earth revolve around the sun in the time it takes Jupiter to revolve around the sun once?????????

Answers

Answer:

Jupiter fully revolves around the sun in about 11.9 Earth years, where as Earth fully revolves around it in a year.

Explanation:

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