The coefficients of friction between the load and the flatbed trailershown are μs = 0.40 and μk = 0.30. Knowing that the speed of the rigis 72 km/h, determine the shortest distance in which the rig can bebrought to a stop if the load is not to shift

Answer:

98

Explanation:

Answer:

friction, air resistance

Explanation:

Answer:

the number of grains in the ball is 274,848

Explanation:

Given that;

diameter = 0.5 mm

so radius r = 0.25 mm

first we determine the volume of the ball using the following equation;

V = 4/3×πr³

we substitute

V = 4/3×π(0.25)³

V =  0.06544 mm³

Now form table 1.1 "Grain sizes" a metal with grain size number of 12 has about 4,200,000 grains/mm³

so;

Number of grains N = 0.06544 × 4,200,000

N = 274,848 grains

Therefore, the number of grains in the ball is 274,848

Answer: C. A stove burner that glows red when it is turned on

Explanation:

I did the quiz

Answer:

26 m southwards.

Explanation:

From a North, East, South, West coordinate plane, moving northwards implies positive distance. While moving southwards implies negative distance.

Thus;

It moves 16 meters northward; d = 16 m

It now moves 22 meters southward; d = -22 m

It moves 12 meters northward; d = 12 m

It moves 32 meters southward; d = -32 m

Thus, total magnitude = 16 - 22 + 12 - 32 = -26 m

Thus, the object travels 26 m southwards.

Answer:

Δp = 620 N.s

Explanation:

       [tex]F = \frac{\Delta p}{\Delta t} (1)[/tex]

       for m= constant, it reduces to F= m*a.

       [tex]\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)[/tex]

Answer:

We know that the gravitational force F between two masses P and Q, that are separated by a distance R is:

[tex]F = G*\frac{P*Q}{R^2}[/tex]

Where G is the gravitational constant.

a) Mass P is doubled, then we have 2*P instead of P, the new force is:

[tex]F' = G*\frac{(2*P)*Q}{R^2} = 2*(G*\frac{P*Q}{R^2} ) = 2*F[/tex]

b) Now R is doubled, then instead of R, we have 2*R:

[tex]F' = G*\frac{P*Q}{(2*R)^2} = G*\frac{P*Q}{4*R^2} = G*\frac{P*Q}{R^2}*(1/4) = F/4[/tex]

c) Now we replace P by 2*P, and Q by 3*Q

[tex]F' = G*\frac{(2*P)*(3*Q)}{R^2} = 2*3*(G*\frac{P*Q}{R^2} ) = 6*F[/tex]

d) The entire mass of the system is increased by a factor of 4, then both of the individual masses are increased by a factor of 4.

Then we need to replace P by 4*P, and Q by 4*Q.

[tex]F' = G*\frac{(4*P)*(4*Q)}{R^2} = 4*4(G*\frac{P*Q}{R^2} ) = 16*F[/tex]

e) Now we replace R by R/2.

[tex]F' = G*\frac{P*Q}{(R/2)^2} = G*\frac{P*Q}{R^2/4}= 4*G\frac{P*Q}{R^2} = 4*F[/tex]

Answer:

146.27 m

Explanation:

From the question given above, the following data were obtained:

Velocity of tourist (vₜ) = 4.65 m/s

Distance travelled by tourist (dₜ) = d

Velocity of bear (v₆) = 5.68 m/s

Distance travelled by bear (d₆) = 32.4 + d

Value of d =?

Next, we shall determine the time taken for tourist and the bear to get to the car.

For the tourist:

Velocity of tourist (vₜ) = 4.65 m/s

Distance travelled by tourist (dₜ) = d

Time (tₜ) =?

vₜ = dₜ / tₜ

4.65 = d/tₜ

Cross multiply

4.65 × tₜ = d

Divide both side by 4.65

tₜ = d / 4.65

For the bear:

Velocity of bear (v₆) = 5.68 m/s

Distance travelled by bear (d₆) = 32.4 + d

Time (t₆) =?

v₆ = d₆ / t₆

5.68 = (32.4 + d) / t₆

Cross multiply

5.68 × t₆ = (32.4 + d)

Divide both side by 5.68

t₆ = (32.4 + d) / 5.68

NOTE: Both the tourist and the bear have the same time. Thus, to obtain the value of d, we shall equate both the time taken for the tourist and the bear together. This is illustrated below:

Time taken by tourist (tₜ) = time taken by the bear (t₆)

tₜ = d / 4.65

t₆ = (32.4 + d) / 5.68

tₜ = t₆

d / 4.65 = (32.4 + d) / 5.68

Cross multiply

d × 5.68 = 4.65 (32.4 + d)

5.68d = 150.66 + 4.65d

Collect like terms

5.68d – 4.65d = 150.66

1.03d = 150.66

Divide both side by 1.03

d = 150.66 / 1.03

d = 146.27 m

Thus, the maximum value of d is 146.27 m

Answer:

the  ratio of r₂/r₁ is 1.37.

Explanation:

Given;

magnitude of electric field strength at a distance r₁, E₁ = 300 N/C

magnitude of electric field strength at a distance r₂, E₂ = 160 N/C

Electric field strength is given as;

[tex]E = \frac{kQ}{r^2} \\\\E_1r_1^2 = E_2r_2 ^2\\\\\frac{E_1}{E_2} = \frac{r_2^2}{r_1^2} \\\\\frac{E_1}{E_2} =( \frac{r_2}{r_1})^2\\\\\sqrt{\frac{E_1}{E_2} } = \frac{r_2}{r_1}\\\\\frac{r_2}{r_1} = \sqrt{\frac{300}{160} }\\\\\frac{r_2}{r_1} =1.37[/tex]

Therefore, the  ratio of r₂/r₁ is 1.37.

Answer:

Gravitation Potential Energy and Elastic Potential Energy

Explanation:

PE=abbreviation for potential energy

PE is a mechanical energy like KE is. There are two types of PE in high school physics (do not talk about other PE's like chemical PE).

Elastic PE is like the stored energy for example in a pole vault competition, the Elastic PE is stored in the pole before the vaulter goes over the desired height. (Energy stored in ELASTIC object ONLY) (commonly on the 11th grade regents springs are used to represent elastic PE)

Gravitational PE can be calculated through the formula PE=mgh although some people substitute the PE with a U. (ENERGY STORED IN OBJECT'S HEIGHT)

Answer: 20

Explanation: cause

Explanation:

When two or more atoms link up, they create a molecule. e.g, A molecule of water is made of two atoms of hydrogen (H) and one atom of oxygen (O).

Answer:

Velocity of the box: 10.67 m/s

Explanation:

Recall that impulse is defined as the force applied times the time the force is in action. Then we can obtained the value of the impulse given to the box as:

Impulse = F * time = 33.3 N * 2.35 s = 78.225 kg m/s

then we use the momentum of the box at that precise time to find its velocity recalling that :

Momentum = mass * velocity

Then

78.225 kg m/s = 7.33 kg * v

v = 78.225/7.33  m/s = 10.67 m/s

Answer:

Psychology traces its roots back through recorded history to India, China, the Middle East, and Europe. Buddha and Confucius focused on the powers and origin of ideas. ... The ideas of Bacon and Locke contributed to the development of modern empiricism.

Explanation:

Answer: Location the data and observations collected in your lab guide

Explanation:

Answer:

B. contain hydrogen

C. clouds of gas and dust

E. needed to create a star

Explanation:

A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.

Some of the examples of stars are; Vega, Sun (closest to planet Earth), Antares, Betelgeus, Canopus, etc.

Stars are typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He). The chronological order in which the formation of a star occur are;

1. Gravity pulls gas and dust together to form dense cores.

2. A protostar forms as mass increases.

3. Nuclear fusion begins under high pressure.

Scientists have been able to understand and discover that, gravity pulled materials (low-density cloud of interstellar gas and dust known as a nebula) together forming the planetary bodies in our solar system.

A dark nebula can be defined as an interstellar cloud that is so dense as a result of high concentration of gas and dust and as such it obscures the visible wavelengths of light from stars behind it, thus appearing completely opaque (dark patch) in front of a bright emission nebula or in regions having plenty stars.

The characteristics of a nebulae are;

I. It contain hydrogen.

II. Clouds of gas and dust

III. It is needed to create a star.

Answer:

a. 14000

Explanation:

Given parameters:

Efficiency of the machine  = 70%

Work done on machine  = 20000J

Unknown:

Work done by machine = ?

Solution:

 Efficiency of a machine is determined by;

  Efficiency  = [tex]\frac{Work done by machine}{Work done on machine} x 100[/tex]  

   70  = [tex]\frac{Work done by machine}{20000}[/tex] x 100

   70  = [tex]\frac{work done by machine}{200}[/tex]  

 Work done by machine  = 70 x 200 = 14000J

Answer:

The magnitude of the maximum net force on the object during the motion is 16 newtons.

Explanation:

The position of the mass, measured in meters, within the mass-spring system is:

[tex]x(t) = A\cdot \cos \left(\omega\cdot t \right)[/tex] (1)

Where:

[tex]A[/tex] - Amplitude, measured in meters.

[tex]t[/tex] - Time, measured in seconds.

[tex]\omega[/tex] - Angular frequency, measured in radians per second.

The acceleration function ([tex]\ddot {x} (t)[/tex]), measured in meters per square second, is obtained by deriving twice (1) in time:

[tex]\dot {x} (t) = -\omega\cdot A\cdot \sin (\omega\cdot t)[/tex]

[tex]\ddot {x} (t) = -\omega^{2}\cdot A\cdot \cos (\omega\cdot t)[/tex] (2)

And the maximum acceleration ([tex]a_{max}[/tex]), measured in meters per square second, experimented by the mass is:

[tex]a_{max} = \omega^{2}\cdot A[/tex] (3)

And the maximum net force ([tex]F[/tex]), measured in newtons, is:

[tex]F = m\cdot a_{max}[/tex] (4)

If we know that [tex]\omega = 2\,\frac{rad}{s}[/tex], [tex]A = 0.80\,m[/tex] and [tex]m = 5\,kg[/tex], then the maximum net force on the object during the motion is:

[tex]a_{max} = \left(2\,\frac{rad}{s} \right)^{2}\cdot (0.80\,m)[/tex]

[tex]a_{max} = 3.2\,\frac{m}{s^{2}}[/tex]

[tex]F = (5\,kg)\cdot \left(3.2\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 16\,N[/tex]

The magnitude of the maximum net force on the object during the motion is 16 newtons.

The magnitude of the maximum net force on the object during the motion will be 16 newtons.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem is;

m is the mass of  5.0 of object kg

x (t ) = A cos(ωt ),

A is the amplitude=  0.80 m

ω is the frequency= 2.0 s-1 .

F is the  magnitude of the maximum net force=?

The position of the mass is given by the equation;

[tex]x(t)= A cos( \omega t)[/tex]]

[tex]\em \dot x= - \omega A sin(\omega t) \\\\ \dot \dot x = - \omega ^2 A cos (\omega t)[/tex]

The maximum acceleration is found as;

[tex]\rm a_{max} = \omega ^2 A \\\\ \rm a_{max} = (2) ^2 \times 0.80 \\\\ \rm a_{max} =3.2 \m/sec^2[/tex]

The value of net force is found as;

[tex]\rm F= m a_{max} \\\\ \rm F= 5 \times 3.2 \\\\\ \rm F=16\ N \\[/tex]

Hence the magnitude of the maximum net force on the object during the motion will be 16 newtons.

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Answer:

Explanation:

The speed will remain unchanged because speed does not depend upon frequency .

So new speed = v

wavelength x frequency = speed

For frequency = 2 f

wavelength = speed / frequency

= v / 2f

So new wavelength = v / 2f .

1. The new wavelength is equal to [tex]\frac{\lambda}{2}[/tex].

2. The new speed is equal to v.

Given the following data:

To determine the new wavelength and new speed are:

Mathematically, the speed of a waveform is calculated by using the formula;

[tex]v = \lambda f[/tex]

Where:

Ideally, the speed of a wave doesn't change when the frequency provided they are both in the same medium.

However, the wavelength would change when frequency changes.

Therefore, the new speed = v.

For new wavelength:

[tex]v = \lambda f=\frac{\lambda}{2} (2f)[/tex]

New wavelength = [tex]\frac{\lambda}{2}[/tex]

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Answer:

For two waves of equal amplitude interfering constructively, the resulting amplitude is twice as large as the amplitude of an individual wave. For 100 waves of the same amplitude interfering constructively, the resulting amplitude is 100 times larger than the amplitude of an individual wave.

Answer:

3k mph

Explanation:

don't take my answer it is wrong

Answer:

Explanation:

Let the velocity of firing be u at angle θ

At maximum height velocity will be equal to horizontal component of initial velocity or vcosθ

So , vtop = v cosθ

At height h/2

vertical component of velocity v₂

v₂² = (usinθ)² - 2 g . h/2

v₂² = u²sin²θ - gh

horizontal component of velocity at height h/2 = u cosθ

velocity at height h / 2

= √ ( u²sin²θ - gh + u² cos²θ)

Given

√ ( u²sin²θ - gh + u² cos²θ) = 2 vtop

u²sin²θ - gh + u² cos²θ = 4 v²top = 4 u² cos²θ

u²sin²θ - gh =  3 u² cos²θ

At height h , vertical component of velocity is zero

0 = u²sin²θ - 2gh

gh = u²sin²θ / 2

u²sin²θ - u²sin²θ / 2  =  3 u² cos²θ

u²sin²θ / 2  = 3 u² cos²θ

Tan²θ = 6

Tanθ = 2.45

θ = 68⁰ .  

Answer:

2.61 atm

Ley de Boyle

Explanation:

[tex]P_1[/tex] = Presión inicial = 0.96 atm

[tex]P_2[/tex] = Presión final

[tex]V_1[/tex] = Volumen inicial = 95 mL

[tex]V_2[/tex] = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

[tex]\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}[/tex]

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.

Answer:

See the explanation below,

Explanation:

Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.

[tex]P=m*v[/tex]

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

A)

[tex]P = 10000*0\\P=0[/tex]

B)

[tex]P=100*5\\P=500[kg*m/s][/tex]

C)

[tex]P=1200*15\\P=18000[kg*m/s][/tex]

D)

[tex]P=15*1000\\P=15000[kg*m/s][/tex]

From higher to lower momentum

C,D,B,A

Answer:

Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages. Absolute dating is used to determine a precise age of a fossil by using radiometric dating to measure the decay of isotopes, either within the fossil or more often the rocks associated with it.

Answer: The more massive one will have larger kinetic energy.

Explanation:

We know that when we drop an object, the acceleration of the object will be equal to the gravitational acceleration.

a(t) = -9.8m/s^2

And to get the velocity, we need to integrate over time, to get:

v(t) = (-9.8m/s^)*t + v0

Where v0 is the initial speed of the object.

You can see that the mass of the object does not affect the velocity of it.

Then when we drop two marbles of different masses from the same height, we know that the final velocity of them will be equal.

Now, we also know that the kinetic energy can be written as:

K = (m/2)*v^2

where m is the mass, and v is the velocity.

Then the kinetic energy of the marble with less mass can be written as:

k = (m/2)*v^2

And the kinetic energy for the more massive one is:

K = (M/2)*v^2

And we know that both of them have the same velocity, and M is larger than m, then we can conclude that the marble with larger mass will have larger kinetic energy.

Answer:

0m/s²

Explanation:

The acceleration of the given body whose motion has been described will be zero.

This is because the body moves with a constant velocity.

Acceleration is defined as the rate of change of velocity with time.

Since in this problem, the velocity is not changing per time, then the acceleration would be zero.

A body moving steadily implies that such body is not changing its motion by the virtue of its velocity and even direction.

Answer:

Resistivity = 231.481 K Ohm

Yes, Intrinsic Silicon is the semiconductor.

Explanation:

Solution:

At 300K:

Let suppose mobility of electron in intrinsic semiconductor = [tex]M_{e}[/tex]

Mobility of electron in intrinsic semiconductor is:

[tex]M_{e}[/tex]  = 1300 [tex]cm^{2}[/tex]/volt.sec

Let suppose mobility of hole in intrinsic semiconductor = [tex]M_{h}[/tex]

[tex]M_{h}[/tex] = 500 [tex]cm^{2}[/tex]/volt.sec

We know that, intrinsic silicon semiconductor has equal number of holes and electrons. So,

At 300 K

Intrinsic Carrier Concentration = 1.5 x [tex]10^{10}[/tex]/[tex]cm^{3}[/tex] = C

And,

Conductivity of intrinsic Silicon is:

σ = C x ([tex]M_{h}[/tex] + [tex]M_{e}[/tex]) e

e = 1.6 x [tex]10^{-19}[/tex] C

So, plugging in the values, we get:

σ = C x ([tex]M_{h}[/tex] + [tex]M_{e}[/tex]) e

σ = 1.5 x [tex]10^{10}[/tex] x (500 + 1300) x 1.6 x [tex]10^{-19}[/tex]

σ = 4.32 x [tex]10^{-6}[/tex]

So, now we can find the resistivity.

Resistivity = 1/σ

Resistivity = 1/ 4.32 x [tex]10^{-6}[/tex]

Resistivity = 231.481 K Ohm

Yes, Intrinsic Silicon is the semiconductor.

The strength of the electric field is 1.10×10^4 N/C.

The data is sent to us.

r = d/2 = 0.1/2 = 0.05 m, d = 10 cm = 0.1 m, and z = 17 cm = 0.17 m

Q = 40 nC = 40×10^-9 C

A) in the middle of the two circles

Since the electric fields created by the two rings are directed in opposite directions, there is no electric strength.

B) midway down the left ring

Electric strength is equal to the sum of the electric fields created by the left and right rings.

Electric strength is equal to E leftring + E rightring, which equals 0 plus kQz/(r2 + z2).

Electric strength = k×Q×z/(r^2 + z^2)^

Electric strength = 9×10^9×40×10^-9×0.17/(0.05^2 + 0.17^2)

Electric strength= 1.10×10^4 N/C

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