Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 28, \sigma = 7.6[/tex]
What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{20 - 28}{7.6}[/tex]
[tex]Z = -1.05[/tex]
[tex]Z = -1.05[/tex] has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
what is the value of x?
Answer:
solution
Step-by-step explanation:
x=5
y=4
To determine the density of grains, a student uses a 50ml beaker graded by 5ml increments and a scale with 1g absolute uncertainty. The measurement of the volume results in 3 full beakers and 1 beaker filled up to 30ml. Measured mass of a plastic container with all the grains is 185 grams; measured mass of the same container without grains is 65 grams. What is the mass of the grains
Answer:
The mass of the grains = 120 ± 1 g
Step-by-step explanation:
we are given the following:
Total mass of container + grains = 185 grams
Mass of container = 65 grams
Therefore, mass of grains is calculated as follows:
Mass of grains = ( Mass of container + grains) - mass of container
= 185 - 65 = 120 grams.
since the scale has an absolute uncertainty of 1 g, the mass of the grains is written as 120 ± 1 g
In △DEF, d = 25 in., e = 28 in., and f = 20 in. Find m∠F. Round your answer to the nearest tenth.
Answer:
∠F ≈ 43.9°
Step-by-step explanation:
The Law of Cosines is used to find an angle when all triangle sides are known.
f² = d² +e² -2de·cos(F)
cos(F) = (d² +e² -f²)/(2de) = (25² +28² -20²)/(2·25·28) = 1009/1400
F = arccos(1009/1400)
F ≈ 43.9°
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 5% of the employees suffered lost-time accidents last year. Management believes that a special safety program will reduce such accidents to 4% during the current year. In addition, it estimates that 15% of employees who had lost-time accidents last year will experience a lost-time accident during the current year. a. What percentage of the employee will experience a lost-time accident in both years (to 1 decimal)?
Answer:
The percentage of the employee will experience a lost-time accident in both years is 0.0%
Step-by-step explanation:
Let A denote events that employees suffered lost-time accidents during the last year
Let B denote events that employees suffered lost-time accidents during the current year
P(A) = 5% = 0.05
P(B) = 4% = 0.04
P(B | A) = 15% = 0.15
(a) P (A ∩ B) = P(B | A) × P(A)
= 0.15 × 0.05
= 0.0075
= 0.0 (1 decimal place)
The probability that an employee will experience a lost- time accident in both years is 0.0
Which of the given shapes has a larger area?
Answer:
Rectangle
Step-by-step explanation:
Count the units. For the triangle, A=0.5bh. 0.5(4)(6)=A. A=12
Now, for the rectangle, A=bh. A=(3)(5). A=15. The rectangle is larger
Please answer this correctly
Answer:
174
Step-by-step explanation:
l x w
5x20
8x4
6x7
174
Which answer is equivalent to the equation shown below?
7c = 49
A.log7 c = 49
B.c = log49 7
C.logc49 = 7
D.c = log7 49
Answer:
D.
Step-by-step explanation:
The base of a log is also the base of an exponent. So 7 to the c power, our 7 would be the base. To find c, we simply just do log base 7 of 49, which comes out to be 2.
What’s the correct answer for this question?
Answer: 3/20
Step-by-step explanation:
p(A)=the day selected in Monday =1/5
p(B)=student is absent
P(A∩B)=it is Monday AND a student is absent =3/100
Events A and B are independent so
P(A∩B) = P(A) · P(B)
3/100=1/5*p(B)
p(B)=3/20
which rule represents the translation from the pre-image ABCD, to the image, a’b’c’d’
Answer:
Pre-image ABCD has been shifted 2 units right and 1 unit upwards.
Step-by-step explanation:
Coordinates of the points A,B,C and D of the pre-image ABCD,
A(-4, 4), B(-1, 4), C(-5, 1), D(-2,1)
Coordinates of the points A', B', C' and D' of the image A'B'C'D'.
A'(-2, 5), B'(1, 5), C'(-3, 2), D'(0, 2)
Now we choose points A from the pre-image and A' from the image,
A(-4, 4) → A'(-2, 5)
Rule for the translation will be,
A(-4, 4) → A'(-4+2, 4+1)
Or A(x, y) → A'(x+2, y+1)
Therefore, pre-image ABCD has been shifted 2 units right and 1 unit upwards to form image A'B'C'D'.
Answer: It's D
Step-by-step explanation:
the last one I just took the quiz
Suppose you have a job teaching swimming lesson and get paid $6 an hour you also have a job as a chasier and get pay $8 and hour if you cannot work more than 15 hours a week what are the number you f hours you can work at each job and still make at least $100
Answer:
You can work no more than 10 hours teaching, and must work at least 5 hours cashiering. The remaining hours can be worked at the other job until the goal is reached.
Step-by-step explanation:
The restrictions give rise to two inequalities. If we ...
let x represent teaching hours
let y represent cashiering hours
then the restrictions are ...
x + y ≤ 15 . . . . total hours cannot exceed 15
6x +8y ≥ 100 . . . . you want to earn at least $100
The solution set for these inequalities is a triangular area on a graph with vertices at ...
(x, y) = (10, 5), (0, 12.5), (0, 15)
You must work at least 5 hours cashiering, and the remainder of necessary time at teaching.
Simplify the following expression:
-5[(x^3 + 1)(x + 4)]
Answer:
[tex]-5x^{4} -20x^{3} -5x-20[/tex]
Step-by-step explanation:
[tex]-5[(x^{3} +1)(x+4)][/tex]
Use the FOIL method for the last two groups.
[tex]-5(x^{4} +4x^{3} +x+4)[/tex]
Now, distribute the -5 into each term.
[tex]-5x^{4} -20x^{3} -5x-20[/tex]
Solve.
3^x+1 = 9^ 5x
a. x=3
b. x = 1/3
c. x=9
d. x= 1/9
Answer:
x = 1/9
Step-by-step explanation:
3^ (x+1) = 9 ^ (5x)
Replace 9 with 3^2
3^ (x+1) = 3^2 ^ (5x)
We know that a^b^c = a ^(b*c)
3^ (x+1) = 3^(2 * (5x))
3^ (x+1) = 3^(10x)
The bases are the same so the exponents are the same
x+1 = 10x
Subtract x from each side
x+1-x = 10x-x
1 = 9x
Divide each side by 9
1/9 = 9x/9
1/9 =x
On a piece of paper, graph fx) = 2• (0.5)*. Then determine which answer choice matches the graph you drew.
Answer:
Graph A
Step-by-step explanation:
The common ratio is less than 1, so the graph will be decreasing. The initial value is 2, so the y-intercept will be 2. Graph A fits this criteria.
I hope this helps :))
The graph A is correct.
What is a graph?A diagram (such as a series of one or more points, lines, line segments, curves, or areas) that represents the variation of a variable in comparison with that of one or more other variables.
The equation is,
[tex]y=2(0.5)^{x}[/tex]
Plotting the graph, we get,
Option A
For more references on graph, click;
https://brainly.com/question/17267403
#SPJ5
After the accounts have been adjusted at December 31, the end of the fiscal year, the following balances were taken from the ledger of Pioneer Delivery Services Co.:
Kerry Buckner, Capital. $9,556,300
Kerry Buckner, Drawing 80,000
Wages Expense 1,878,400
Rent Expense 1,415,500
Supplies Expense 125,000
Fees Earned 30,600
Miscellaneous Expense 22,100
Journalize the two entries required to close the accounts.
Help asap giving branlist!!!
Answer:
Option 2
Step-by-step explanation:
The first statement is false because the price for 10 gallons is about $37 from the graph. Using this same reasoning, the third statement is also false. The last statement doesn't make sense because the graph has nothing to do with the amount of miles driven. Therefore, the answer is the second statement. We can prove it by looking at the point (4, 15). This means that it costs $15 for 4 gallons, so then the price for one gallon will be 15 / 4 = $3.75.
Jan's All You Can Eat Restaurant charges $9.10 per customer to eat at the restaurant. Restaurant management finds that its expense per customer, based on how much the customer eats and the expense of labor, has a distribution that is skewed to the right with a mean of $8.10 and a standard deviation of $4.
A. If the 100 customers on a day have the characteristics of the random sample from their customer base, find the mean and standard error of the sampling distribution of the restaurant's sample mean expense per customer.
B. Find the probability that the restaurant makes a profit that day, with the sample mean expense being
less than $8.95.
Answer:
Step-by-step explanation:
From the given question;
Given that:
Jan's All You Can Eat Restaurant charges $9.10 per customer to eat at the restaurant.
Distribution is skewed and and has a mean of $8.10 and a standard deviation of $4.
A. If the 100 customers on a day have the characteristics of the random sample from their customer base, find the mean and standard error of the sampling distribution of the restaurant's sample mean expense per customer.
the mean by using the central limit theorem is 8.10
the standard error of the sampling distribution = [tex]\dfrac{\sigma}{\sqrt{n}}[/tex]
the standard error of the sampling distribution = [tex]\dfrac{4}{\sqrt{100}}[/tex]
= 4/10
= 0.4
B.
P(X > $8.95) = P (Z > 8.95 - 8.10/0.4)
P(X > $8.95) = P (Z > 2.1)
P(X > $8.95) = 1 - P (Z < 2.1)
P(X > $8.95) = 1 - 0.9821
P(X > $8.95) = 0.0179
Makeeya only has $25 to spend on a custom T-shirt. It costs $10 for a plain T-shirt, and there is a charge of $$1.50 for each square inch of design added to the T-shirt. Which solution represents the number of square inches of design,x , Makeeya can put on her T-shirt?
Answer:
10 square inches
Step-by-step explanation:
cost of a plain t-shirt = $10
cost of 1 square inch of design addition = $1.50
let there be x square inches of design
then cost of x square inches of design = x*cost of 1 square inch of design
= 1.50*x = 1.5x
Total cost for t-shirt with x square inches of design = cost of a plain t-shirt + cost of x square inches of design = 10 + 1.5 x
It is given that Makeeya has only $25, then total cost which can be afforded by him will be $25 only
Thus,
10 + 1.5 x = 25
=> 1.5x = 25-10 = 15
=> x = 15/1.5 = 10
Thus, Makeeya can put 10 square inches of design on her T-shirt.
Thw sum of 12x^2+9x^2
Answer:
21 x^2
Step-by-step explanation:
12x^2+9x^2
Combine like terms
x^2(12+9)
x^2(21)
21 x^2
The mean of 3 numbers is 4
The two numbers are 1,9
what is the missing number?
Answer:
2
Step-by-step explanation:
1+9+2 = 12
12/3= 4
Answer:2
Step-by-step explanation:9+2+1=12
So 12/3=4
ANSWER=2
Help me, please ?? :)
Answer:
a) 11
b) 16
c) between 5 and 6
d) 16
Step-by-step explanation:
[tex]\text{a. }\quad\sqrt{121}=\sqrt{11^2}=\boxed{11}\\\\\text{b. }\quad 8\sqrt{4}=8\sqrt{2^2}=8\cdot 2=\boxed{16}\\\\\text{c. }\quad\sqrt{35}\ \dots\ \sqrt{25}<\sqrt{35}<\sqrt{36}\\\\\text{ }\qquad\sqrt{5^2}<\sqrt{35}<\sqrt{6^2}\\\\\text{ }\qquad \boxed{5<\sqrt{35}<6}\\\\\text{d. }\quad\dfrac{.8}{.05}=\dfrac{0.80\cdot 20}{.05\cdot 20}=\dfrac{16}{1}=\boxed{16}[/tex]
Lester worked 12 hours last week at the grocery store and earned $93.00. If he continues to earn the same hourly pay, how many additional hours must he work to earn another $62.00?
A. 9 hours
B. 10 hours
C. 11 hours
D. 8 hours
Answer:
8 hours
Step-by-step explanation:
We can use a ratio to solve
12 hours x hours
---------- = ------------
93 dollars 62 dollars
Using cross products
12 * 62 = 93x
Divide each side by 93
12*62/93 = 93x/93
8 = x
8 hours
Please give answer with explanation of formula. Please reply fast I have exam.
Answer:
D
Step-by-step explanation:
3/40 * 2.5/2.5 = 7.5/100 = 0.075
Los Angeles workers have an average commute of 33 minutes. Suppose the LA commute time is normally distributed with a standard deviation of 15 minutes. Let X represent the commute time for a randomly selected LA worker. Round all answers to 4 decimal places where possible.
a. What is the distribution of X? X N
b. Find the probability that a randomly selected LA worker has a commute that is longer than 38 minutes
c. Find the 80th percentile for the commute time of LA workers. _______ minutes
Answer:
a) N(33,15).
b) 37.33% probability that a randomly selected LA worker has a commute that is longer than 38 minutes
c) 45.6 minutes.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 33, \sigma = 15[/tex]
a. What is the distribution of X?
Normal with mean 33 and standard deviaton 15. So
N(33,15).
b. Find the probability that a randomly selected LA worker has a commute that is longer than 38 minutes
This is 1 subtracted by the pvalue of Z when X = 38. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{38 - 33}{15}[/tex]
[tex]Z = 0.333[/tex]
[tex]Z = 0.333[/tex] has a pvalue of 0.6267.
1 - 0.6267 = 0.3733
37.33% probability that a randomly selected LA worker has a commute that is longer than 38 minutes
c. Find the 80th percentile for the commute time of LA workers.
This is X when Z has a pvalue of 0.8. So it is X when Z = 0.84.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.84 = \frac{X - 33}{15}[/tex]
[tex]X - 33 = 0.84*15[/tex]
[tex]X = 45.6[/tex]
45.6 minutes.
Use Greens Theorem to evaluate integral x^2ydx - xy^2dy, where C is 0 ≤ y ≤ √9-x^2 with counterclockwise orientation
Answer:
Step-by-step explanation:
a circle will satisfy the conditions of Green's Theorem since it is closed and simple.
Let's identify P and Q from the integral
[tex]P=x^2 y[/tex], and [tex]Q= xy^2[/tex]
Now, using Green's theorem on the line integral gives,
[tex]\oint\limits_C {x^2ydx-xy^2dy } =\iint\limits_D {y^2-x^2} \, dA\\\\[/tex]
The diameter of a circle is 5 ft. Find its area to the nearest tenth.
Answer:
A = 19.6 ft²
Step-by-step explanation:
A = πr² Use this equation to find the area of the circle
A = π(2.5)² Multiply
A = π(6.25) Multiply
A = 19.6 ft²
liam is a tyre fitter it takes him 56 minutes to fit 4 tyres to a van
Answer:
Step-by-step explanation:
I am not really sure because u did not finish the question but is u are asking how much time it takes to fit one tyre:
answer is time/tyres
56min./4
14 min. Per type
12 and 3/6 -5 and 2/12
Answer:
7.33333333333 I think. Hope this helped.
• Write this number as a fraction:178.25
Answer: 178 1/4 or 713/4
Step-by-step explanation:
178.25 = 178+0.25 = 178+25/100
gcd(25,100) = 25
178.25 = 178+(25/25)/(100/25) = 178+1/4 = 713/4
Find the value of y when equals zero. -7x+3y=30
Answer:
x = -30/7
Step-by-step explanation:
-7x+3y=30
Let y=0
-7x +0 = 30
Divide by -7
-7x /-7 = 30/-7
x = -30/7
Answer:
[tex]-\frac{30}{7}[/tex]
Step-by-step explanation:
y equals zero => y = 0
-7x+3y=30
-7x +3.0 = 30
-7x + 0 = 30
-7x = 30
-7x/-7 = 30/-7
x = -30/7
Hope this helps ^-^
Two samples are randomly selected from each population. The sample statistics are given below.
n1 = 150 n2 = 275
x1 = 72.86 -x2 = 67.34
s1 = 15.98 s2 = 35.67
The value of the standardized test statistic to test the claim that μ1 > μ2 is _________.
-2.19
2.19
3.15
-3.15
Answer:
Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]
Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]
The statistic is given by:
[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]
And replacing we got:
[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]
And the best option would be:
2.19
Step-by-step explanation:
We have the following info given:
n1 = 150 n2 = 275
[tex]\bar x_1 = 72.86, \bar x_2 = 67.34[/tex]
s1 = 15.98 s2 = 35.67
We want to test the following hypothesis:
Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]
Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]
The statistic is given by:
[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]
And replacing we got:
[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]
And the best option would be:
2.19
