The Density Of Mercury Is 13600 Kg/M3 At 0 OC. What Would Its Density Be At 166 OC? Coefficient Of Volume Expansion For Mercury Is 182x10-6(O C)The density of mercury is 13600 kg/m3 at 0 oC.What would its density be at 166 oC?Coefficient of volume expansion for mercury is 182x10-6(o C)

B) bouncing

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The moment of the bouncing ball is an analogy for the reflection of light. The correct option is B.

Reflection and refraction are two important properties of light that describe how it interacts with surfaces and passes through materials.

Reflection occurs when light bounces off a surface, changing direction and continuing to travel in a new direction. The angle of incidence (the angle between the incoming light and the surface) is equal to the angle of reflection (the angle between the reflected light and the surface). Reflection is responsible for the formation of images in mirrors, and it is also used in many optical systems, such as telescopes and camera lenses.

Refraction occurs when light passes through a material and changes direction due to a change in speed. This change in direction is caused by the bending of light as it enters a medium with a different refractive index. The amount of refraction that occurs depends on the angle of incidence and the refractive indices of the two materials involved. Refraction is responsible for many optical phenomena, such as the bending of light in lenses, the formation of rainbows, and the distortion of objects viewed through water or glass.

Both reflection and refraction are fundamental concepts in optics and have important practical applications in a wide range of fields, including astronomy, photography, and telecommunications.

Therefore, The moment of the bouncing ball is an analogy for the reflection of light. When a ball bounces, it reflects off a surface and changes direction, just as light reflects off a surface and changes direction during reflection.

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Because it would attempt to draw in all the sides at once, it would probably spiral out of control.

Electrostatics is the study of electric charges in a stationary state (static electricity). Certain materials, like amber, have been known to collect light particles after rubbing since antiquity. The Greek word for amber, v, was used to create the English word "electricity". Electrostatic phenomena are caused by the interactions between electric charges. Such forces are described by Coulomb's law.

Although certain a electrostatic forces are relatively powerful, electrostatically generated forces often appear to small. The gravitational force between two objects is about 36 orders of magnitude weaker than the force between an electron and a to proton, which make up a hydrogen atom.

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(a) a strip welded together from brass on one side and steel on the other Stripe made of two metals.

(b) It flexes.

(c) These metals expand in different ways.

A bimetallic strip is made up of two distinct metals that have been welded together. Different metals expand at various rates when heated. It bends as a result of heat expansion. Thermal expansion refers to the tendency of matter to alter form, area, and volume in reaction to temperature changes.

Because the water vapor flowing out of the nozzle has expanded and cooled, he may hold his palm a few inches above the nozzle.

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The distance Cathy's school is from her house can be calculated by multiplying the rate (1.0 m/s) by the time (2.0 h) that it takes her to walk there.

What is school?

School is an institution for teaching and learning. It is the place where students come to acquire knowledge, skills and values. It is a place where students learn to interact with peers, and to think critically and independently. School is a place where students form bonds with teachers and develop relationships with their peers. School helps students become well-rounded individuals, with a broad understanding of the world and good qualifications to pursue a chosen career. School also provides students with opportunities to explore their interests and passions, and to develop their talents.

Distance = Rate x Time

Distance = 1.0 m/s x 2.0 h

Distance = 2.0 m

Therefore, Cathy's school is 2.0 m from her house.

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The acceleration of cheetah from rest to a speed of 21.0 m/s in 6.75 s is 3.1m/s2.

Given the speed of cheetah (v) = 21m/s

The time of acceleration from rest to given speed (t) = 6.75s

The acceleration of cheetah = am/s^2

We know that acceleration = speed of object/time of acceleration = v/t

Acceleration is the rate of change of velocity. It is the change in speed or direction of an object over a period of time. It is related to speed and time in that it is the rate at which the speed of an object changes over a given amount of time.

then a = 21/6.75 = 3.1m/s^2

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The ball can go a maximum distance of 39.2 meters as long as it doesn't collide with the ceiling while having a speed of 28m/s.

To find the maximum range of the ball fired from the toy cannon, we can use the equations of motion for a projectile. The maximum range occurs when the projectile lands at the same height from which it was fired. In this case, the ball must not hit the ceiling during its flight, so we need to ensure that the maximum height it reaches is less than the ceiling height.

The time of flight of the projectile can be calculated using the vertical component of the initial velocity and the acceleration due to gravity. Since the initial speed of the projectile is 28 m/s and the angle of elevation is not given, we can assume that the projectile is fired at an angle of 45° with the horizontal, which gives equal vertical and horizontal components of velocity. The vertical component of the initial velocity is therefore:

[tex]v_0_y = v_0 sin45 = 28/\sqrt{2 m/s}[/tex]

The acceleration due to gravity is[tex]-9.8 m/s^2[/tex]

[tex]h = v_0_y * t + (1/2) * g * t^2[/tex]

here,

h is  maximum height reached by the projectile.

At the maximum height, the vertical component of the velocity becomes zero:-

[tex]0 = v_0_y * t + (1/2) * g * t^2[/tex]

[tex]t = (v_0_y / g)[/tex]

Reserving given:-

[tex]t = (28/\sqrt{2 m/s)} / 9.8 m/s^2[/tex]

t = 2.02 s (approx.)

The horizontal range of the projectile can be calculated using the horizontal component of the initial velocity and the time of flight of the projectile.

[tex]v_0_x = v_0 cos45 = 28/\sqrt{2 m/s}[/tex]

The horizontal range:-

[tex]R = v_0_x * t[/tex]

Reserving values:-

[tex]R = (28/\sqrt{2 m/s} ) * 2.02 s[/tex]

R = 39.2 m (approx.)

Therefore, the maximum range of the ball fired from the toy cannon, without hitting the ceiling, is approximately 39.2 meters.

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It would take approximately 81.3 Moons to equal the mass of the Earth.

Iron and oxygen make up the majority of the Earth's mass. Each of these makes up around 32% of the mass of the planet. Calcium, aluminum, and nickel make up roughly 1.5% of the total, followed by magnesium and silicon, which each contribute another 15%.

The mass of the Earth is approximately 5.97 x 10^24 kilograms, while the mass of the Moon is approximately 7.35 x 10^22 kilograms.

To determine how many Moons would be required to equal the mass of the Earth, we can divide the mass of the Earth by the mass of the Moon:

5.97 x 10^24 kg / 7.35 x 10^22 kg = 81.3

Therefore, it would take approximately 81.3 Moons to equal the mass of the Earth.

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Unlocked position. The cam is used to lock the conductor in place, so the locking ring needs to be in the unlocked position in order for the conductor to be passed through the grip head.

A conductor is a person or object that allows the flow of electric current or heat. In electrical systems, a conductor provides a path for the electric current to flow from the power source to the device being powered. In heating systems, a conductor carries the heat from the source to the device or area that needs to be heated. Conductors are typically made of metal, such as copper, aluminum, and silver, as these materials have a higher electrical conductivity than most other materials.

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An elevator is suspended by a cable, descending at constant velocity. Forces are tension force which acts upward and gravity force or elevator's weight, which acts downward.

In physics, tension is described as pulling force transmitted axially by the string, rope, chain, or similar object, or by each end of rod or similar three-dimensional object. Tension can also be described as the action-reaction pair of forces acting at each end of the said elements

Tension force falls under category of contact forces as it can only be exerted when there is a contact between cable and an object of consideration. This kind of force always pulls but never pushes.

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The charge is positive.

We know that a charge can be positive or negative. We can see that the question is showing us the way that we can be able to obtain the magnitude of the charge that is labelled Q1 when we have the charges Q2 and Q3.

The charge Q2 can be see to be sandwiched in between Q 1 and Q2. We have seen the solution to the problem in the image that have been attached.

To know if the charge is positive or negative, we look at the sign attached to the magnitude of the charge.

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The value of charge Q1 is - 20 μC.

option A.

The value of charge Q1 is calculated by applying Coulomb's law of electrostatic force.

F = kq₁q₂/r²

where;

F (net) = Q12 + Q23 = 0

The force between charge 1 and 2 is calculated as;

F (12) = ( 9 x 10⁹ x 10 x 10⁻⁶ x Q1 ) / ( 2a)²

F (12) = 22,500 (Q1/a²)

The force between charge 2 and 3 is calculated as;

F (23) =  ( 9 x 10⁹ x 10 x 10⁻⁶ x 5 x 10⁻⁶) / (a)²

F(23) = (0.45) /(a²)

22,500 (Q1/a²) + (0.45) /(a²) = 0

22,500 (Q1/a²)  = -  (0.45) /(a²)

22,500Q1 = -0.45

Q1 = -0.45 / 22,500

Q1 = - 2 x 10⁻⁵ C

Q1 = -20 x 10⁻⁶ C

Q1 = - 20 μC

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The surface area each tire have in contact with the ground is 0.11 m².

The weight of the car is evenly distributed on each wheel, so each wheel supports a force of 1000 kg / 4 = 250 kg.

The force on the tire is transmitted to the ground through the tire's contact patch, which is the surface area of the tire in contact with the ground.

The tire's contact patch can be calculated by dividing the total force on the tire by the pressure of the tire:

Contact patch area = Force on tire / Pressure

= 250 kg  x 9.8 N/kg / (2.2 bar  x 10⁵ Pa/bar)

= 0.11 m²

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The two factors that determine gravitational attraction force are- 1- Mass 2- distance. Gravity is an attractive force, one that attracts all of the matter in the Universe towards all of the other bits of matter in the Universe.

On the size scale of moons, planets, stars, and galaxies, it is an extremely important force, and governs much of the behavior of these objects.

Gravity keeps our feet firmly on the ground, keeps the Moon in orbit around the Earth, keeps the Earth in orbit around the Sun, keeps the Sun in orbit around the center of our Milky Way galaxy.

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

This can be determined by Sir Isaac Newton’s universal law of gravitation (F=Gmm/r2). According to which the gravitational attraction is directly dependent on the mass, while it is inversely dependent on the distance.

Therefore, This means that the force of gravity increases with mass, but decreases with increasing distance between objects.

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Boyajian was looking at a starlight graph in the summer of 2013 and She noticed two dimming episodes from KIC 8462852 were two important data points in the light curve of star KIC 8462852.

The irregular drop and rise in brightness that does not follow a regular or expected pattern. This shift is caused by dust, which might be the result of a collision between two comets or the bursting of one. Another plausible, although less likely, reason is that the star is through unprecedented internal turmoil.

Boyajian was looking at a starlight graph in the summer of 2013 as part of a big data set acquired by the space-based Kepler telescope during its four-year mission to search for Earth-like planets near other stars. Dips in the quantity of light emitted by a star might signal the passage of a planet in front of it. The greater the size of the planet, the greater the light drop.

Boyajian's graph implied the existence of a planet larger than any scientist has ever seen — or something more crazier.She noticed two dimming episodes from KIC 8462852 during the 800th and 1,500th days of observation, when the star's luminosity reduced by 15% and 22%, respectively. A planet nearly 11 times the size of Jupiter of Earth, would result in a 1% drop — implying that whatever is circling KIC 8462852 is significantly larger than our solar system's greatest planet.

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In a Reverse fault, the hanging wall block moves up with respect to the footwall block.

Reverse fault is a type of fault in which two blocks of earth's crust move away from each other, resulting in the upper block of crust being pushed up above the lower block. It is the opposite of a normal fault, in which two blocks of crust move towards each other. The reverse fault typically occurs when the Earth’s tectonic plates come together and a compressional force pushes up and over the lower plate. This type of fault is usually seen in regions of convergence between two plates and is common along convergent plate boundaries. The reverse fault is usually accompanied by large earthquakes as the plates move against each other. The reverse fault can also be caused by the bending of the Earth’s crust in response to forces such as erosion, volcanic activity and sedimentation. These forces can cause the crust to buckle and rise, resulting in a reverse fault.

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The amount of charge built up on your fingertip is approximately 10.08 x 10^-5 C.

The spark length of 2 cm is equal to the breakdown field strength in air, so the electric field strength between your fingertip and the doorknob is 3 x 10^6 N/C.

The electric potential difference between the two points is given by the equation:

V = Ed

Where V is the potential difference, E is the electric field strength, and d is the distance between the two points.

In this case, d is equal to 2 cm, so we can calculate the potential difference:

V = (3 x 10^6 N/C) x (2 cm) = 6 x 10^6 N m/C = 6 x 10^6 V

Next, we can calculate the charge q on your fingertip using the formula:

q = CV

Where C is the capacitance of your fingertip.

The capacitance of a sphere is given by the formula:

C = 4πε_0r

Where C is the capacitance, ε_0 is the permittivity of free space, and r is the radius of the sphere.

The diameter of your fingertip is 1.59 cm, so the radius is 0.795 cm. Plugging these values into the formula for capacitance, we get:

C = 4πε_0 * 0.795 cm = 4π * 8.85 x 10^-12 * 0.795 cm = 1.68 x 10^-11 F

Finally, we can calculate the charge on your fingertip by plugging in the values for q and C into the equation:

q = C x V = 1.68 x 10^-11 F x 6 x 10^6 V = 10.08 x 10^-5 C

So the amount of charge built up on your fingertip is approximately 10.08 x 10^-5 C.

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X-rays are used for crystallography because they have a much smaller wavelength than visible light or UV light, making them capable of diffracting off the regular array of atoms within a crystal lattice.

The regularity of the crystal lattice causes the X-rays to undergo constructive interference, creating a diffraction pattern that can be used to determine the structure of the crystal. X-rays are also highly energetic, allowing them to penetrate the surface of the crystal and interact with the atoms in the interior. While other types of electromagnetic radiation could be used, their longer wavelengths and lower energy levels would not be able to penetrate the surface of the crystal or diffract off the atoms in the lattice, making them less effective for crystallography. X-rays are used for crystallography because they have a much smaller wavelength than visible light or UV light, making them capable of diffracting off the regular array of atoms within a crystal lattice.

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The moment of inertia of the 1.5-kg rod rotating about its center is 0.6075 kg*m².

The moment of inertia of a rod rotating about its center can be calculated using the formula:

I = (1/12) * m * L^2

where I is the moment of inertia, m is the mass of the rod, and L is the length of the rod.

In this case, the mass of the rod is 1.5 kg, and the length of the rod is 1.8 m. Plugging these values into the formula, we get:

I = (1/12) * 1.5 kg * (1.8 m)^2

= 0.6075 kg*m^2

Therefore, the moment of inertia of the 1.5-kg rod rotating about its center is 0.6075 kg*m^2.

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An object whose center of gravity is above its base of support will be unstable if a vertical line projected downward from the center of gravity falls outside of the base of support. This statement is true.

The center of gravity of an object is the point at which its weight can be considered to act. If the center of gravity is above the base of support, the object will tend to tip over or fall if the vertical line projected downward from the center of gravity falls outside of the base of support.

If the base of support is not wide enough to counteract this torque, the object will become unstable and tip over.

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Different substances have different reflectivities, or abilities to reflect light.

Reflectivity, also known as reflectance, is a measure of how much light is reflected by a substance compared to how much is absorbed or transmitted. It is a property of a material that depends on its chemical composition, physical structure, and surface properties. For example, a shiny metal surface such as a polished aluminum surface has a high reflectivity, meaning it reflects a large portion of the incident light. This is because metals have a smooth surface and free electrons that can move freely in response to the electromagnetic waves of the incident light, which results in a high reflectivity. On the other hand, a rough or matte surface such as paper has a low reflectivity, meaning it absorbs or scatters most of the incident light. This is because the rough surface causes light to reflect in different directions, and the material has a more complex internal structure that allows for absorption of the incident light. Different substances can also have different colors due to their reflectivity. For example, a red apple appears red because it absorbs most colors of light except for red, which it reflects. Similarly, a blue object appears blue because it reflects mostly blue light and absorbs other colors.

In summary, reflectivity is a property of a material that determines how much light is reflected compared to how much is absorbed or transmitted. Different substances have different reflectivities due to differences in their chemical composition, physical structure, and surface properties.

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They left the Carolina's to join the Iroquois Confederacy this statement about the Native Americans in Carolina is true

In North Carolina, particularly in the eastern region of the colony, a smallpox outbreak decimates the Indian population. Cherokee populations are down by 50% as a result of the outbreak. Indians from the Waxhaw tribe, ravaged by smallpox, leave their homes in modern-day Union County and join the Catawba.

Due to their frequent geographical movements in pursuit of food and other resources, the earliest residents of North Carolina were nomads. Like their forefathers, archaic humans lived nomadic lifestyles.

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Lens of digital camera must be moved approximately 99.4 meters farther away from the flower to focus on the tree.

To change the focus of the camera from a flower 1.5 m away to a tree 100 m away, we need to move the lens to adjust the distance between the lens and the image sensor. This adjustment changes the focal length of the lens and allows the camera to focus on objects at different distances.

The focal length of the lens, f, is related to the distance between the lens and the image sensor, d, by the thin lens equation:

[tex]1/f = 1/d_o + 1/d_i[/tex]

where [tex]d_o[/tex] :object distance (lens to object distance), and [tex]d_i[/tex] : image distance (lens to image sensor distance).

For the original focus on the flower, we have:

f = 5.7 mm,

[tex]d_o[/tex]= 1.5 m, [tex]d_i[/tex] = ?

Using the thin lens equation, we can solve for d_i:

[tex]1/5.7 mm = 1/1.5 m + 1/d_i[/tex]

[tex]d_i[/tex] = 5.9 mm

The image sensor is 5.9 mm away from the lens when the camera is focused on the flower.

For the new focus on the tree, we have:

f = 5.7 mm

[tex]d_o[/tex] = 100 m, [tex]d_i[/tex] = ?

Using the thin lens equation again, we can solve for d_i:

[tex]1/5.7 mm = 1/100 m + 1/d_i[/tex]

[tex]d_i[/tex]= 5.77 mm

To change the focus of the camera from the flower to the tree, we need to move the lens by a distance Δd such that the new image distance is 5.77 mm. We can use the thin lens formula to find the new object distance:

[tex]1/5.7 mm = 1/d_o + 1/5.77 mm[/tex]

[tex]d_o[/tex] = 100.9 m

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The magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away is 0.341 * [tex]10^{-9}[/tex] C.

Each location in space where a charge exists in any form can be considered to have an electric field attached to it. The electric force per unit charge is another name for an electric field. Variable magnetic fields or electric charges are frequently the cause of electric fields. Volts per metre (V/m), a unit used in the SI, is used to express electric field strength. The force acting on the positive charge is assumed to be exerted in the direction of the pitch. The electric field is directed radially inwards towards negative point charge and radially outwards from positive charge.

Electric field = 1.20 n/c

r= 1.60 m

[tex]E=\frac{q}{4\pi E_{o}*r^{2} } \\q=4\pi E_{o}*E*r^{2} \\=\frac{(1.20 n/c)((1.60m)^{2} }{8.99*10^{9}N.\frac{m^{2} }{C^{2} } } \\=0.341*10^{-9} C[/tex]

Therefore, the magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away is 0.341 * [tex]10^{-9}[/tex] C.

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The cross-sectional area in 10⁻⁶ m of a cylindrical rod has a length of 36 cm and a diameter of 2.4 mm is 4.5216 x 10⁻⁶ m².

Cross Sectional Area of a Cylinder = π x R2 where π is a constant (3.14159265), which is the rate of the circumference to periphery of a circle, while R is the compass of the cylinder. So all you need to know, to be suitable to calculate the cross sectional area, is its compass. The forecourt of the compass, multiplied by π, shall give you the value of the cross sectional area. The unit of cross sectional area will depend on the length unit used for compass dimension. Since π is dimensionless, the unit for area could be meter2, cm2 or indeed ft2.

We're given a spherical rod whose cross-sectional area will be in the form of circle.

To calculate the area of circle, we use the equation:

Area = [tex]\pi r^2[/tex]

where,

r = radius of rod

r = 2.4 /2 = 1.2 x 10⁻³ m

 (Conversion factor: 1 m = 1000 mm)

Putting values in above equation, we get:

Area = [tex]\pi r^2[/tex]

= 3.14 x (1.2 x 10⁻³)²

= 4.5216 x 10⁻⁶ m²

Therefore, the cross sectional area of cylinder rod is 4.5216 x 10⁻⁶ m².

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A tree is placed cm from the converging mirror, and the radius of curvature is 20 cm. The distance of the image is 30 cm.

A converging mirror is also known as a concave mirror, whose inner side has a reflecting surface. They are called converging mirror because it converges all parallel beam of light incident on them.

u = -15cm, object distance

R = -20cm (Converging mirror)

f = R/2 = -10 cm focal length

1/v + 1/u = 1/f

1/v + 1/-15 = 1/-10

1/v – 1/15 = -(1/10)

1/v = 1/15 – 1/10 = (2 -3)/30 = - (1/30)

v = - 30 cm

Therefore, the image is formed 30 cm in front of the mirror.

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The strength of the electric field needed if the electron is to emerge from an exit hole 1. 0 cm away from the entrance hole, travelling at right angles to its original direction is [tex]\frac{-K}{(q(.01*cos45))} = E[/tex].

The electric field needs to bring vertical velocity to zero and horizontal velocity to what the vertical velocity was. We need to find what E-field is required to bring the vertical velocity to zero without having to worry about the horizontal velocity, I think.

Vi = [tex]\frac{(2\frac{K}{m} )1}{2 }[/tex]

d = 0.01*cos45

0 = [tex](\frac{2K}{m} )+2a*.01*cos45[/tex]

 [tex]\frac{-K}{(m(.01*cos45)) } =a[/tex]

Now finding acceleration in terms of E

qE=ma

[tex]q\frac{E}{m} = a[/tex]

Combining them:

[tex]\frac{-K}{(m(.01*cos45))}[/tex]= [tex]q\frac{E}{m}[/tex]

[tex]\frac{-K}{(q(.01*cos45))}[/tex]=E

Therefore, when we go through this we get 17655 [tex]\frac{N}{C}[/tex], which seems close (right order of magnitude).

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The correct question is:

A problem of practical interest is to make a beam of electrons turn a 90∘ corner. This can be done with the parallel-plate capacitor shown in the figure (Figure 1). An electron with kinetic energy 2.0×10−17 J enters through a small hole in the bottom plate of the capacitor. What strength electric field is needed if the electron is to emerge from an exit hole 1.0 cm away from the entrance hole, travelling at right angles to its original direction?

When a capacitor has charge q, it recovers energy u₁, and when it holds charge 16q, it stores energy u₂. u₂/u₁ has a value of 256.

Energy (E) stored in capacitor:-

[tex]U = (1/2) * C * V^2[/tex]

here U is energy,

C is capacitance, and

V is voltage across the capacitor.

Since the same capacitor is used in both cases, we can assume that the capacitance C is constant. Therefore, the ratio of energy stored is given by the ratio of the voltage squared:

[tex](u_2/u_1) = (V_2^2 / V_1^2)[/tex]

To find V2 and V1:-

C = q/V

here q is charge stored on the capacitor.

For the first case, the capacitor holds charge q, so the voltage across the capacitor is:

V₁ = q/C

The energy stored is:

[tex]U_1 = (1/2) * C * V_1^2 = (1/2) * q^2 / C[/tex]

For the second case, the capacitor holds charge 16q, so the voltage across the capacitor:-

[tex]V_2 = 16q / C[/tex]

The energy stored is:

[tex]U_2 = (1/2) * C * V_2^2 = (1/2) * (16q)^2 / C[/tex]

Reserving these values into the ratio formula:-

[tex](u_2/u_1) = (V_2^2 / V_1^2) = [(16q / C)^2 / (q / C)^2][/tex]

= [tex](16^2 * q^2 / q^2)[/tex]

= 256

Therefore, the ratio [tex]u_2/u_1[/tex] is 256.

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When two surfaces experience friction with each other, the particles on the surfaces are affected in two ways: movement and spacing. The particles on the surfaces move against each other, creating a force that resists the motion of the two surfaces. This force is known as friction. At the same time, the particles on the surfaces are also pushed apart, creating a small gap between the two surfaces. This gap is known as the coefficient of friction, and it affects the amount of friction that is experienced between the two surfaces.

Each element's spectra are distinct because each element has a different amount of electrons and hence various energy levels.

Astronomers can identify not only the element, but also the temperature and density of that element in the star, using spectral lines. The spectral line can also inform us about the star's magnetic field. The line's width can tell us how rapidly the material is travelling. This teaches us about the winds in the stars. Because the emission spectrum differs for each element of the periodic table, it may be used to establish the composition of a substance. One example is astronomical spectroscopy, which involves analyzing received light to determine the composition of stars. Since various elements contain varying quantities of protons and varied numbers and configurations of electrons, their spectra differ. Differences in spectra indicate variances in the amount of energy absorbed or released by atoms when their electrons travel between energy levels.

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Answer:

Q = C M ΔT    where C is specific heat in cal / gm*deg C

C (Fe) = .11

C (Al) = .22

obviously ΔT has to be twice as great for Iron (Fe) as for (Al) for the same amount of heat to be transferred

ΔT = Q /(C * M)      where ΔT is the change in temperature

a) iron would have the higher final temperature

If bulb B  is replaced with a short circuit, it will effectively bypass the circuit that includes bulb A. As a result, the current in the circuit will increase, which may cause the bulb A to become brighter.

A circuit is a closed path or loop through which electrical current can flow. It is made up of various components that work together to allow the flow of electricity. The basic components of a circuit include a power source, such as a battery or generator, wires or conductors that carry the current, and various other components such as switches, resistors, capacitors, and diodes, which help to control and modify the flow of electricity.

When a circuit is closed, the electrical current flows from the power source through the components and back to the power source. This flow of electricity is usually measured in amperes (amps) and is controlled by the voltage of the power source and the resistance of the components in the circuit.

Circuits can be either series circuits, where the components are arranged one after the other in a single loop, or parallel circuits, where the components are arranged in multiple branches, allowing the current to flow through each component independently. Circuits are used in a wide range of electrical and electronic devices, from simple household appliances to complex computer systems and telecommunications networks.

If bulb B is replaced with a short circuit, it will effectively bypass the circuit that includes bulb A. As a result, the current in the circuit will increase, which may cause the bulb A to become brighter. However, it's also possible that the increased current could cause bulb A to burn out or even damage the circuit itself. In general, it's not recommended to create a short circuit intentionally as it can be dangerous and potentially cause damage to the electrical system.

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