The equation of a function and its table of values has been given. Complete the table.

=−2+5

Answer:

jsjzbdjwbxjdbwisjsobs9fbe

Step-by-step explanation:

hfkdowwhdbhdvsjsh2ivdusvqvduzvqidv

Answer:

Yeeeeaaahhhh its correct.

Answer:

The restrictions are x≠2,4,5

Step-by-step explanation:

First the denominators cannot be zero

x-2 ≠0  so x≠2

Then x-4 ≠0  so x≠4

Also, since we are dividing, when we flip the second expression, the numerator becomes the denominator, so it cannot be zero

2x-10≠0

2x≠10

x≠5

The restrictions are x≠2,4,5

The perimeter = sum of all sides

= 120 + 80 + 50

= 250

So 250 - 3

247

Left space for gate

Now cost of fencing = Rs 20/per meter

= 247 × 20

= Rs 4,940

Now the area of the triangular park can be found using heron's formula

S = (a+b+c)/2

S = (120+80+50)/2

S = 250/2

S = 125

Now

Herons formula = √s(s-a)(s-b)(s-c)

√125(125-120)(125-80)(120-50)

√125(5)(45)(70)

√5×5×5×5×5×3×3×5×14

After Making pairs

5×5×5×3√14

375√14

Therefore 375√14m is the area of the triangular park

Must click thanks and mark brainliest

$\sf\underline\bold{Answer:}$

$\space$

$\sf\underline\bold{Step-by-Step:}$

$\space$

$\sf\bold{Given(In \:the\:Q):}$

$\space$

$\sf\bold{To \: find:}$

$\space$

$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$

$\space$

$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$

$\space$

Use heron's formula to find the area of the triangle.

$\space$

$\mapsto$ $\sf\small{Heron's\:formula=}$

[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]

$\space$

$\sf\bold{Now,find\:semi\:parameter:-}$

$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$

$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$

$\space$

$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$

$\sf{Area\:of\:the\:∆:-}$

$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]

$\space$

$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$

$\space$

$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$

$\space$

$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$

______________________________

$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$

$\sf{Cost\:of\:fencing-}$

$\space$

$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$

$\space$

So,total cost of fencing at the rate of Rs.20 per m:-

___________________________________

Answer:

Step-by-step explanation:

If x represents the number of long-sleeved shirts and each of these cost $14, then the expression for that is 14x; likewise for short-sleeved shirts that are represented by y. The expression for short-sleeved shirts that cost $10 apiece is 10y. Putting that together with the fact that they earned less than $200 when selling these at the same time, the inequality is

14x + 10y < 200

Answer:D i just got it right trust mw

Step-by-step explanation:i

Answer:

x³-2x²-4x+8

Step-by-step explanation:

a1=x+2

a2=x²-4⇒q=a2/a1=x-2

⇒a3=q.a2=(x-2).(x²-4)=x³-2x²-4x+8

Answer:

y = 6x

Step-by-step explanation:

The equation representing a proportional relationship is

y = kx ← k is the constant pf proportionality

Here k = 6 , then

y = 6x ← equation of proportion

Answer:

She is not correct, she would need to have something before the y to know the answer

Step-by-step explanation:

hope this helps :)

Answer:

yes, your answers are correct

Answer:

I got that AE^2 = 8EC^2

Step-by-step explanation:

Here's what I did. I probably did this wrong, but this might give you an idea on how to solve it.

First, create equations:

AB = BC = AC = DE = 2EC

BD= BC = EC

Then, I used pythagorean theorem (since AD is perpendicular to BC): AD^2 + DE^2 = AE^2

Substitute: (2EC)^2 + (2EC)^2 = AE^2

Simplify: 4EC^2 + 4EC^2 = AE^2

AE^2 = 8CE^2

Answer:

Step-by-step explanation:

Since T is in Quadrant II, sinT > 0 and cosT < 0.

cotT = -5/12

Answer:

a = m/c

~~~~~~~~~~~~~~~~~~~~~~~

m=ca

divide both sides by c

you get a = m/c

Step-by-step explanation:

Answer:

a = m/c

Step-by-step explanation:

m = ca

divide both sides by c

m/c = ca/c

m/c = a

:.a = m/c

Answer:

There is not enough evidence to support the claim that drug is effective at 1%

Step-by-step explanation:

For this we use the pored test as we have dependent test;

Difference :

10,5,-5,3,-3,4,2,-3,0,10,8,-2,3,-2,5,5,4,0

Hypothesis :

H0 : μd = 0

H0 : μd ≠ 0

The mean of d, dbar = Σd / n = 44 / 18 = 2.44

The standard deviation, Sd = 4.45 (using calculator)

The test statistic, T : dbar / (Sd/√n)

T = 2.44 / (4.45/√18)

T = 2.44 / 1.0488750

T = 2.326

Degree of freedom, df = n - 1 ; 18 - 1 = 17

The Pvalue = 0.0326

α = 0.01

Since Pvalue < α ; we fail to reject H0

Answer:

filtration system is not working

filtration

Answer:

48

Step-by-step explanation:

9,18

6,12,18,24,30

18 + 30 = 48

Answer:

keep the pic clearly

Step-by-step explanation:

keep the pic clearly

Answer:

I say it's a

Step-by-step explanation:

I hope this help

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

[tex]A_x=50cos(89.75)[/tex] so

[tex]A_x=.22[/tex]

[tex]B_x=200cos(0)[/tex] so

[tex]B_x=200[/tex] and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

[tex]C_x=200[/tex] (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

[tex]A_y=50sin(89.75)[/tex] so

[tex]A_y=50[/tex] (which I'm counting as 2 sig fig's)

[tex]B_y=200sin(0)[/tex] so

[tex]B_y=0[/tex] and we need to add those results together.

[tex]C_y=50[/tex]

Now for the resultant magnitude:

[tex]C_{mag}=\sqrt{(200)^2+(50)^2}[/tex]  and that gives us a final magnitude of

[tex]C_{mag}=206[/tex] m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

[tex]tan^{-1}(\frac{50}{200})=14[/tex]

The girl is 206 meters from her starting point at an angle of 14 degrees

Answer:

Its that squiglly one on top

Step-by-step explanation:

cuh cuh cuh cuh cuhc

Answer:

[tex]{26}[/tex]

Step-by-step explanation:

[tex] \sqrt{(0 - ( - 5) ){}^{2} + (0 - 1) {}^{2} } [/tex]

[tex] = \sqrt{ {(5)}^{2} + {( - 1)}^{2} } [/tex]

[tex] = \sqrt{25 + 1} [/tex]

[tex] = \sqrt{26} [/tex]

Answered by GAUTHMATH

Answer:

26

Step-by-step explanation:

(-5, 1) (0, 0)

sqrt(5^2 + (-1^2))

sqrt(25 + 1)

sqrt(26)

So, 26 goes under the radical.

Answer:

The polar coordinates appear in the form (r, θ), where r is the the radius from the center and θ is the angle. To get the radius, do the following.

[tex]r = \sqrt{x^2 + y^2} = \sqrt{1^2 + (-1)^2} = \sqrt{2}\\[/tex]

You can get the angle visually by drawing a point (1, -1) on a graph and seeing that it is 45 degrees from the top right quadrant (you can tell its 45 because both x and y have the same magnitude). Since there are 360 degrees, 360 - 45 = 315.

If you would like to find it mathematically, this is the way to do it

[tex]\theta = atan(y/x) = -45[/tex]

Notice that -45 degrees is just 360 - 45 = 315

Your answer would be

[tex](\sqrt{2}, 315)[/tex]

Answer:

Area of pizza slice = 87 inches² (Approx.)

Step-by-step explanation:

Given:

Angle cut of pizza = 100°

Diameter of pizza = 20 inches

Find:

Area of pizza slice

Computation:

Area of sector = [Ф / 360][π][r²]

Area of pizza slice = [100/360][3.14][(20/2)²]

Area of pizza slice = [100/360][3.14][(10)²]

Area of pizza slice = [100/360][3.14][100]

Area of pizza slice = [0.2778][3.14][100]

Area of pizza slice = 87.2292

Area of pizza slice = 87 inches² (Approx.)

Answer:

The product of 16 and 26 would be 16 * 26

Step-by-step explanation:

This is because "the product of" means multiplication so *. Making it 16 * 26.

Answer:

7i/sqrt(2)

Step-by-step explanation:

so, if I understand correctly, the equation is

(22-16)(2x² + 49) = 0

6(2x² + 49) = 0

that automatically means

2x² + 49 = 0

2x² = -49

x² = -49/2

x = sqrt(-49/2)

a square root of a negative number has no real solution. the solution is in the world of complex and imaginary numbers, which bases on the sqrt(-1) = i.

so, we get

x = sqrt(49/2 × -1) = (7/sqrt(2)) × I = 7i/sqrt(2)

Answer:

C = 100 + 0.20d

Step-by-step explanation:

Let

C = Total cost

d = distance driven(km)

$100 = fixed cost

$0.20 = additional cost

The algebraic model of the relationship:

Total cost = fixed cost + (additional cost * distance driven(km))

C = 100 + (0.20 * d)

C = 100 + 0.20d

Using the definition of the derivative,

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{f(x) - f(-2)}{x - (-2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac6x + 3}{x + 2}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac{6+3x}x}{x + 2}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{6+3x}{x(x + 2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3(x+2)}{x(x + 2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3}{x} = \boxed{-\dfrac32}[/tex]

Answer:

(I don't have the complement sign of sets, so I've used "©" to denote compliment)

L.H.S.

(B-A)∪C

= (B∩A©)∪C

= (B∪C)∩(A©∪C)

= (B∪C)∩(A-C)©

= (B∪C)-(A-C) = R.H.S.

(Proved)

Answer:

a)-2x(x+4x²)+3(x²+2x)

-2x²-8x³+3x²+6x

-2x²+3x²+6x-8x³

x²-8x³+6x

in descending order

-8x³+x²+6x

b)(4x-3)(4x+3)

4x(4x+3)-3(4x+3)

16x²+12x-12x-9

16x²-9

I hope this helps and sorry if it's wrong

Answer:

hello,

answer C

Step-by-step explanation:

area of the rectangle=2b*b=2b²

area of the half cercle= [tex]\\\dfrac{\pi*(\frac{c}{2})^2}{2} =\dfrac{\pi*c^2}{8} \\[/tex]

Area in blue= 2b²-πc²/8