The feces of birds and mammals can also be used to assess ecosystem health. Research this methodology and provide two examples of animals used for these studies and the types of materials that are identified in their feces

Answers

Answer 1

Answer:

Birds and leopard

Explanation:

It has been researched and discovered that the feces of birds and animals can be used to determine the state of health of an ecosystem.

For example, it has been discovered that hormones and other substances are excreted through urine and feces. And researchers have discovered from the feces of leopards, that a leopard that has cave or trees where it can hide from hunters are not likely to be stressed out like the one that does not have.


Related Questions

Why is the Copernicus Revolution significant? Check all that apply

Answers

Answer:

Yes. If you're trying to solve a multiple choice question, you'll need to put in the answer choices, but here is what i think.

Explanation:

The Copernican Revolution gives us an important framework for understanding the Universe. The Universe and everything in it can be understood and predicted using a set of basic physical laws. The entire Universe obeys the same physical laws everywhere (and at all times).

This skull belongs to a multituberculate non-therian mammal, Taeniolabis, from the Paleocene. It looks superficially like some rodent skulls. Given that multituberculates diverged before rodents had evolved, would their overall similarity be homologous or convergent

Answers

Answer:

Convergent evolution

Explanation:

Convergent evolution can be described or explained as a process in evolution in biology. It usually occurs when two species from unrelated lines develop the same traits or features. This is believed to have happened due to the fact that they live in similar or related habitats, and have to develop solutions to the same kind of problems.

Therefore, in this case, the type of evolution between the two organisms mentioned is convergent.

What is the function of the seed coat ?

• it protects the new plant.
• it contains food.
• it performs respiration.
• it attracts animals.

Answers

Answer:

It protects the new plant.

It protects the new plant.

Amanda hates her new student ID photo. Her hair looks dry, the extra weight she's gained shows, and her neck looks fat. Amanda's also been feeling very tired and mentally dull. Amanda goes to the clinic where you are working. You draw her blood. The test results show her T4 levels are low and her TSH levels are low. Later she is given a TSH stimulation test in which TSH is injected and the T4 levels are monitored. After TSH injection her 14 levels rise. A) Does Amanda have problems with her pituitary or with her thyroid gland? B) How did you come to your conclusion?

Answers

Answer:

A) Pituitary Gland B)By analysing the given observations in the question.

Explanation:

THS, thyroid stimulating hormone, is an hormone produced by the pituitary gland and in return it stimulates the thyroid gland that produces hormones such as T3 and T4.

We can conclude from the given information that Amanda's thyroid gland does not have a problem with producing and secreting the T3 and T4 hormones when THS is present in her body.

But the low THS levels show that the problem is with her pituitary gland causing her to have low levels of THS.

We can reach this decision by analysing the given information.

I hope this answer helps.

Which of these conditions doesn’t not contribute to the weathering of rock on earth’s surface

Answers

Answer:

The correct answer is

C. Constant high pressure

Explanation:

Constant high pressure is not a factor that causes weathering on the earth surface.

Temperature, air and water affects how a rock changes through time. They have the capacity to cause physical disintegration and chemical decomposition of rocks.

Hope this helps!

- Quinn <3

Mendel used monohybrid crosses to study the inheritance of pea plant characteristics. In one of his classic experiments, Mendel crossed a purple-flowered plant with a white-flowered plant. All of the offspring plants produced purple flowers.
1. Using the symbols P for the purple allele and p for the white allele, provide the following information:
A. What the genotypes of the Parental Generation plants?
Purple parent: White parent:
B. What is the genotype of the F1 generation?
C. Organisms with two copies of the same allele are called
D. Organisms with two different alleles are called
2. When is it necessary to perform a test cross?
3. In rabbits, brown coat (B) is dominant to white coat (b). A rabbit breeder wants to know the genotype of his best looking male brown rabbit using a test cross. He has brown females and white females available to conduct his breeding experiments.
A. What should be the coat color of the female he must use in this test cross?
B. If the test cross produces seven (7) brown rabbits and one (1) white rabbit, what is the genotype of the brown male rabbit?
4. How is Mendel's Law of Independent related to the events of Meiosis?
5. In your own words, state the Law of Segregation
There are other patterns of inheritance that require explanations beyond the predictions of Mendel's Law of Dominance and Segregation. These patterns are known in biology as non-Mendelian inheritance and include:______.
A. Incomplete dominance
B. Codominance
C. Multiple Alleles
D. Pleiotropy (explained in the first assigned video)
E. X-linked inheritance
F. Epistasis
6. Write in the space provided the type of non-Mendelian inheritance from the list above that matches the descriptions or the examples listed below:
1. When a gene has more than two allele variants.(Example)
2. When a single gene or allele controls the expression of 2 or more traits.
3. When offspring show a blended phenotype, a physical appearance intermediate to the phenotype of both parents
4. When an allele is carried in the X chromosome.

Answers

Answer:

Explanation:

A. To produce all purple flowers from a cross between purple and white flowers, it means the parents genotype are dominant homozygous purple and the recessive homozygous white ( PP and pp)

B. The F1 generation will possess a phenotype of purple colour with genotype ( Pp )- heterozygous

C. Organisms with two copies of the same allele are called homozygotes

D. Organisms with two different alleles are called heterozygotes

2. When is it necessary to perform a test cross?

This test is only perform when the identity/genotype of one of the parents is unknown then a testcross is carried out.

3.A The coat color of the female he must use is white...a testcross is done with the recessive parents

B. The genotype of the male brown rabbit is Bb to produce a white rabbit.

4. The law of independent assortment amd meiosis relates in that the independent assortment law talks about independent separatíon of gens from each other and in meiosis, it takes into account the independent separation of homologous chromosomes.

5. The law of segregation of genes takes into account that an individual that is diploid possessing 2 copies of a gene/alleles on each homologous chromosome, that each of these alleles segregation or separate into each gametes, as one allele per gamete.

5. Non-Mendelian inheritance includes all listed below

6.

1. When a gene has more than two allele variants - multiple alleles

2. When a single gene or allele controls the expression of 2 or more traits - Pleitropy e.g. as in the ABO blood group

3. When offspring show a blended phenotype, a physical appearance intermediate to the phenotype of both parents: incomplete dominance

4. When an allele is carried in the X chromosome - X linked inheritance

Answer: the biological

Explanation: the biological

Which of the following describes how damaged DNA can lead to a mutation?
A. The damaged DNA stops all protein synthesis by the cell.
B. An error occurs when the damaged DNA is repaired.
C. The segment of DNA that is damaged is transcribed into RNA.
D. The nucleotide sequence of the damaged DNA is restored
perfectly

Answers

Answer:

B.an error occurs when the damaged DNA is repairex

Explanation:

the best answer is B

The damaged DNA can lead to a mutation represent that option b. An error occurs when the damaged DNA is repaired.

Reason for damaged DNA?

In the case when the DNA is damaged so it should be replicated that shows an incorrect base which should be inserted opposite the site of the damaged base in the strand i.e. complementary.

Due to this, it should become the mutation at the coming replication round.

Moreover, the double-strand DNA split might be repaired.

Hence, the option b is correct.

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The
called the pleura.
are enclosed in a membrane
The
are branch-like extensions
found in the lower respiratory system.
Identify the structures labeled in the diagram to
the right
Label A
A
In the 1930s, medical journal
articles linked asbestos to cancer.

Answers

Answer:

Lungs

bronchioles

alveoli

positive impact

Explanation:

Answer:

The -lungs- are enclosed in a membrane called the pleura.

The -bronchioles- are branch-like extensions found in the lower respiratory system.

-alveoli-  Label A

-positive impact- In the 1930s, medical journal articles linked asbestos to cancer.

Explanation:

i have edg too and uhh... i hotpe thos helps :D

love yall <3 alright take care *mwah*

. Which of the following is a function performed by the kidneys?​

Answers

Your kidneys act like a filter to remove wastes and extra fluid from your body. Your kidneys filter about 200 quarts of blood each day to make about 1 to 2 quarts of urine

A cohort of 3000 individuals was chosen to be part of a study on the potential relationship between being infected with hepatitis C virus (HCV) and liver disease. 800 of the cohort members acquire an HCV infection and out of those infected persons 640 develop liver disease. 200 of the remaining cohort members also develop liver disease.
A. What is the relative risk of developing liver disease based on exposure to HCV?
B. What is the odds ratio for developing liver disease based on exposure to HCV?

Answers

Answer:

Relative risk = percentage of disease after exposition/percentage of disease without exposition

= (800/3000) / (200/3000)

= 26,66 % / 6,66 % = 400 % 

Odds ratio = odds of disease after exposition/odds of disease without exposition

= (800/3000) / (200/3000)

= 0.2666 / 0.0666 = 4  

Explanation:  

The relative risk estimates the probable outcome in the exposed group in regard to the expected outcome in the non-exposed group. A relative risk of 400 % is indicative of 4 times the average risk.  On the other hand, the odds ratio estimates the association between the exposure and the outcome for a particular disease.

Both the relative risk and the odds ratio are estimated in a very similar mode, however, the first is calculated as percentages.

The genetics of a-thalassemia are similar to narrow sense heritability in that there is a gradation of phenotype, with each allele seeming to contribute equally to the trait. However, there are also differences from narrow sense heritability. In particular, as you can see from your answers above, it is difficult to predict offspring phenotype based only on parental phenotype. What two aspects of HBA1 and HBA2 combine to offset what would otherwise appear to be narrow sense heritability of a-thalassemia?

Answers

Answer:

In strict mode, the narrow-sense heritability is the proportion of the additive genetic variance that contributes to the total of the phenotypic variance. This value can be associated with the inheritance of the a-thalassemia .

Explanation:

A-thalassemia is a genetic disorder caused by mutations affecting four different genes that encode alpha-globin, thus affecting the hemoglobin production process and, consequently, oxygen transport. The mode of inheritance of the a-thalassemia may be associated with narrow sense heritability since the phenotype is manifested by gradation, i.e., each allele might contribute in similar mode to this genetic condition.

Identify the structure represented in the picture . Then, identify the parts labeled A—D.

Answers

Given structure is that of a virus, which includes the viral capsid, nucleic acid, etc.

A= spike

B= Envelop

C= Nucleic acid

D= Capsid

What are Viruses?

Small infectious agents known as viruses can multiply only in the living cells of other animals. They are composed of genetic material, which can be DNA or RNA, encased in a protein shell called a capsid. Some viruses also have a lipid-based outer coat.

Because they cannot perform metabolic functions on their own and require a host cell to reproduce, viruses are not considered living organisms. They spread infection to various living things including bacteria, plants, animals and people.

A virus replicates its genetic material and forms new viral particles when it infects a host cell using the host cell's machinery. This can lead to the death of the host cell and result in the spread of the virus to other cells of the host.

Therefore, given structure is that of a virus, which includes the viral capsid, nucleic acid, etc.

A= spike

B= Envelop

C= Nucleic acid

D= Capsid

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Katie wants to make ball-and-stick models of the four macromolecules. She has colored balls for each of the elements in these molecules, including the following.

Answers

Answer:

I don't really understand what the question is, but I'm pretty sure you're asking for which molecules that will be needed; Carbon, Hydrogen, Oxygen, Nitrogen, Phosphorus

Explanation:

-Carbohydrate consists mainly of Carbon, Hydrogen, Oxygen, simple sugars have the basic formula of (CH2O)n. Some modification can be made to the sugar, but the main formula consists only with Carbon, Hydrogen, Oxygen.

-Proteins consists mainly of Carbon, Hydrogen, Oxygen, and Nitrogen for the amide groups. Some amino acid will need Sulfur for it's R Group.

-Fats consists mainly of Carbon, Hydrogen, and Oxygen just like Glucose.

-Nucleic Acids consists mainly of Carbon, Hydrogen, Oxygen, Nitrogen, and Phosphorus for the backbone of the Nucleic Acid. Nitrogen will be needed for the Nitrogenous Base.

I hope this is the answer you're looking for!

In the lab, metabolic poisons can be used to study ATP synthesis and oxygen consumption. Many of these poisons have – or have had – other uses, from diet aids to animal poisons to antibiotics. Poison Action oligomycin binds to F0F0 and blocks the proton channel cyanide inhibits cytochrome oxidase by reacting with heme a3 trifluorocarbonylcyanide phenylhydrazone (FCCP)(FCCP) increases membrane proton permeability rotenone blocks electron transfer at NADHNADH dehydrogenase (NAD−Q(NAD−Q oxidoreductase) bongkrekic acid binds to inward‑facing site of ATP‑ADP translocase Classify the metabolic poisons as electron transport inhibitors, uncoupling agents, ATP synthase inhibitors, or transport inhibitors.

Answers

Answer:

Electron transport inhibitors: Cyanide, Rotenone

Uncoupling agents: trifluorocarbonylcyanide phenylhydrazone (FCCP)(FCCP)

ATP synthase inhibitors: Oligomycin

Transport inhibitors: Bongkrekic acid

Explanation:

Electron transport inhibitors: Cyanide, Rotenone

Cytochrome oxidase also known as complex IV in the electron transport chain, carries electrons from cytochrome c to oxygen. It is a large enzyme having 13 subunits. Subunit  1 contains  two heme groups , a and a3. Electrons are tranferred from heme a to oxygen bound to heme a3. The reaction of cyanide with heme a3 blocks this process of eleron transport

.Rotenone blocks electron transfer at NADH dehydrogenase (NAD−Q(NAD−Q oxidoreductase) by preventing electron transfer from Fe-S center to ubiquinone.

Uncoupling agents: trifluorocarbonylcyanide phenylhydrazone (FCCP)(FCCP)

The transfer of electrons  from NADH through the respiratory chain to molecularoxygen is coupled to proton pumping from the inner mitochondrial matrix to the intermembrane space. This generates a proton motive force which is utilized in ATP synthesis. Trifluorocarbonylcyanide phenylhydrazone (FCCP)(FCCP) increases membrane proton permeability, causing protons to leak back into the mitochondrial matrix, thereby uncoupling the processs of ATP synthesis and proton flux.

ATP synthase inhibitors: Oligomycin

ATP synthase is the enzyme rensponsible for ATP synthesis. It has two functional domains,: F₁ and F₀. Oligomycin binds to F₀ and blocks the proton channel preventing rotation of the F₁ subuni, thus, preventing ATP synthesis from ADP.

Transport inhibitors: Bongkrekic acid

Adenine  nucleotide translocase is a transport protein that  transports free ADP from the cytoplasm into the mitochondrial matrix, while ATP produced from oxidative phosphorylation is transported from the mitochondrial matrix to the cytoplasm o the cell.

Bongkrekic acid inhibits Adenine nucleotide translocase, thus preventing ATP from leaving the mitochondria and starving cells of needed energy.

Which of these statements are accurate? Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group from ATP to a hexose. Hexokinase transfers the terminal phosphate of ATP to carbon 3 of glucose. The conformational shift that occurs when glucose, but not water, enters the active site prevents water from hydrolyzing ATP. Hexokinase consists of two domains, or lobes, that come together when glucose and the MgATP2–MgATP2– complex are bound. Most kinases require the presence of a monovalent metal ion cofactor to prevent ATP hydrolysis. Hexokinase is found in the mitochondrial membrane.

Answers

Answer:

A. The conformational shift that occurs when glucose, but not water, enters the active site prevents water from hydrolyzing ATP. True

B. Hexokinase consists of two domains, or lobes, that come together when glucose and the MgATP2–MgATP2– complex are bound. True  

C. Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group from ATP to a hexose. True

Explanation:

A. Hexokinase suffers and conformational changes by binding glucose in a reaction that prevents ATP hydrolysis.

B. Hexokinase is an enzyme with two domains that function by binding to the substrate (i.e., glucose). The region linking both protein domains is responsible for the catalytic activity.

C. Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group from ATP to a hexose. During the first stage of glycolysis, the hexokinase transfers one phosphorous group from magnesium-ATP (Mg-ATP) to one hexose molecule, such as fructose, mannose or glucose.

 

False statements:

- Most kinases require the presence of a monovalent metal ion cofactor to prevent ATP hydrolysis. False: In canonical kinases, conserved amino acids bind to divalent metal ions before the transference of the phosphate group to their substrates.

- Hexokinase is found in the mitochondrial membrane. False: Hexokinase is found in the cytosol.

- Hexokinase transfers the terminal phosphate of ATP to carbon 3 of glucose. False: Hexokinase catalyzes the transfer of the terminal phosphate ATP to form glucose 6-phosphate.

Why do rocks on the ocean floor form a pattern of magnetized stripes?

Answers

Answer: D trust me on this

Explanation:

the rocks contain iron that points in different directions depending on earths polarity

The polarity of Earth affects the iron in the rocks, which points in various ways, so rocks on the ocean floor form a pattern of magnetized stripes.

How form a pattern of magnetized stripes?

The idea of paleomagnetism, according to which the arrangement of the earth's tectonic plates depends on the iron present in magma, is one of the theories explaining seafloor spreading. The positive and negatively charged ions are represented by the stripes.

The magnetic strips, also known as magnetic anomalies, are identified by white and black strip patterns. They have ions that are positively and negatively charged. As a result, the magma magnetizes with the Earth's magnetic field when it emerges from the ridges.

Therefore, the polarity of Earth affects the iron in the rocks, which points in various ways.

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Why do you find glucose in the filtrate but not formed elements of the blood (erythrocytes, leukocytes, and
platelets)?​

Answers

Answer:

Formed elements of the blood are too large to fit through the filtration slits of the filtration membrane. ... Nephron tubules cannot reabsorb large proteins and cells that enter the filtrate.

you have selected the following prediction to test: Previously thinned forests will have higher tree survival than adjacent forests that were not thinned. Now you need to define the key variables that you will use to test this prediction. For the following variables, sort them as independent variables, dependent variables, or variables that should be controlled (held constant)1. thinning or no thinning before the fire elevation of the site 2. dominant tree species 3. tree survival rate after the fire A. Independent variableB. Dependent variable C. Controlled variable

Answers

Answer:

A. Independent variable 2. dominant tree species

B. Dependent variable  3. tree survival rate after the fire

C. Controlled variable 1. thinning or no thinning before the fire elevation of the site

Explanation:  

A. An independent variable doesn't undergo changes during the experiment because it is not conditioned by other variables in the experiment. In this example, dominant tree species represent a variable that is independent of the experiment itself.

B. A dependent variable is those that you need to measure and depends on the other factors in the experiment. In this example, tree survival is dependent on the factors that affect the results (i.e. humidity in the trees, presence of resinous material in the trees that are non-combustible, etc.)

C. A controlled variable is those that we use to observe an expected outcome in the experiment and therefore it is used to compare with the test group. In this case, thinning or no thinning are used as positive and negative controls, respectively, because they enable their comparison with the test group in the experiment.  

what is 9 + 10??? VERY IMPORTANT

Answers

Answer:

9 + 10 = 19

the answer is = 19

Different protists use cilia, _______, or pseudopodia to move.

Answers

Answer:

Different protists use cilia, flagella , or pseudopodia to move.

How can you determine the optimum pH of an enzyme?

Answers

The optimal pH can be measured by looking at enzyme activity verses pH. Enzyme activity will increase up to a certain pH; above that pH, the enzyme activity will begin to fall.

You can determine the optimum pH of an enzyme by graphing its pH activity and studying the results.

Enzymes each perform differently in distinct environments. Some require lower pH to function, while others achieve maximum performance at higher pH levels.  

This relationship between the productivity of the enzyme and the pH can be studied and graphed. Once done, we can expect this graph to look like a parabola, increasing steadily until maxed, then gradually decreasing back to zero at the other extreme. The vertice of this parabola will give us the optimum pH for the enzyme.

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. What was Sharon’s experience with the experimental drug?
a) she suffered severe side effects b) she had few side effects c) it made her very sick

Answers

Answer:

imagine being on brainly

Explanation:

The table below compares three galaxies the information about galaxies is correct in

Answers

Answer:

A. Column 1

Explanation:

The information in column 1 is correct for all galaxy but information in coulmn 2 and Column 3 has some incorrect information about Elliptical galaxy.

Information about spiral galaxy is correct in all three columns that spiral galaxy has pinwheel shape and made up of several stars, dust and gas particles hold together by gravitational force.

Elliptical galaxy has round or oval shape and made up of mostly old stars and do not have much gas and dust particles which are hold together by gravitation force and not by electrical force.

Irregular galaxy has no defined shape as of spiral and elliptical and are made up of large amount of gas and dust and forms new stars which allow them to look brighter.

Hence, information in coulmn 1 is correct for all the galaxy.

Answer:

Column 1

Explanation:

Which of the following statements about cell differentiation is true?

A. Cell differentiation occurs only in adult organisms
B. Cell differentiation cannot be affected by the environment
C. Cells differentiate because the dna in each cell of an organism is different
D. Cells differentiate because different areas of the dna are activated in each cell type.

Answers

Answer:

I think is B, Cell differentiation cannot be affected by the enviroment

which feature of a membrane describes wether molecules can cross the membrane​

Answers

Answer:

Permeability

Explanation:

Membranes are semi-permeable that only certain things can come cross on its own. This feature of permeability describes whether molecules can cross the membrane​

What causes an ecosystem to move from a primary successional stage towards a relatively-stable mature ecosystem?

Answers

Answer:

The correct answer is "secondary succession, an ecological succession step where an area previously occupied by living beings is disrupted".

Explanation:

In ecological succession, an ecosystem changes and develops through a series of steps. The first step, is the primary successional stage where rocks or other sedimentary structures are colonized by microorganisms. The second step, where the ecosystems changes towards a relatively-stable mature stage, occurs when an area previously occupied by living beings is disrupted. This step is named secondary succession, and the most clear example of this phenomena occurs when wildfire clears oak and hickory forests.

Plants combine carbon dioxide and water to make what
substance?
O A. Glucose
O B. Ammonia
O C. Peptide
O D. Nitrogen
SUBMIT

Answers

Answer:

A. glucose right good brilliant

Congenital hyperinsulinism is a rare condition in which infants experience frequent episodes of hypoglycemia. Based on the functions of the two main hormones that control blood sugar homeostasis, which of the following would be effective at treating the hyperinsulinemia?
A. Glucagon
B. Glucocorticoids
C. Preventing insulin release or production
D. All of the choices are correct.

Answers

Answer:

Any  treatment which involves reduction in the levels of insulin to curb excessive influx of glucose into the cells from the blood  will be an ideal treatments.

Glucagon, which converts excess glucose to glycogen. Glucocorticoids induces insulin resistance thus raises glucose levels.

suppressing insulin release will be another option.

Therefore all options are correct.

Explanation:

Difference between Squamous epithelium and Stratified epithelium. (Pls answer quick) ​

Answers

Answer:

squamous epithelium consists of a single layer of flat cells. It is found in lungs,heart and blood vessels.It allows the movement of materials across it.

stratified epithelium has many layer of flat cells.It is present in lining of oesophagus and mouth and also over the skin

In a simple epithelium the cells form a single layer and are all attached to the basement membrane. A stratified epithelium consists of multiple layers of cells in which only the basal layer is attached to the basement membrane. Hope it helps

what is is a specific version of a gene on a homologous chromosome that has a corresponding version of a similar gene on a homologous chromosome. For example, hair color gene (ie. red from mom) will be on one homologous chromosome and a possibly different version of hair color gene (ie. black from dad) will be on the other corresponding homologous chromosome.

Answers

Answer:

This statement is partially true.

Explanation:

There are many phenotypic features that display a quantitative mode of inheritance and exhibit a continuous range of variation.  Hair color is controlled by different genes that work together to express this trait. In consequence, this trait has a polygenic mode of inheritance, where a particular phenotype depends on both additive and dominance genetic effects. The most important gene associated with the hair color is Melanocortin 1 Receptor (MC1R), which is involved in the biosynthesis pathway that controls the synthesis of melanin.

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