Answer:
A pentagon has no parallel sides
M = { }
N = {6,7,8,9,10}
M n N =
Sound travels at speed of 330 m/s. If a firecracker exploded 3675 m away from you, how long does it take the sound of the explosion to reach you?
Identify the common difference. -6, -3, 0, 3, 6....
Roman is considering buying shares of GHI stock. The stock currently sells for $60 per share. The stock changes in value at 8:00 am each day, either increasing in value by $10 or decreasing in value by $1. The stock will increase in value with 90% probability, and decrease in value with 10% probability. The stock follows a random walk. In three days, what is the probability that GHI is less than $70?
Answer:
The Probability that the GHI is less than $70 in three days is 1% or 0.01
Step-by-step explanation:
Here, we want to find the probability that the GHI is less than $70.
So what we do here is to find the scenarios that could make the $60 less than $70 is three days;
Scenario 1;
Two days decrease and one day increase
That will bring the value to 60 -1-1 + 10 = $68 which is less than 70
Scenario 2;
Three days decrease
That will bring the value to
60-1-1-1 = 57 which is less than 70
Any other possible scenario to make the value of the share less than 70? NO !
For the 1st case scenario;
Two days decrease and one day increase;
The scheduled probabilities will be as follows;
Kindly recall, probability of increase = 90% = 90/100 = 0.9
Probability of decrease = 10% = 10/100 = 0.1
So probability in scenario 1 will be;
P(Two days decrease and one day increase)
= 0.1 * 0.1 * 0.9 = 0.009
Kindly note this can happen in any order and since no order was specified, we do not need to consider other cases
Scenario ii
Three days decrease
That will be;
P(three days decrease) = 0.1 * 0.1 * 0.1 = 0.001
So the addition of both since we will be having either of the two and or means addition in probability will be ;
0.001 + 0.009 = 0.01 = 1%
There are five digits in the number 35,024
A child has a bottle full of pennies, nickels,dimes and quarters. There are twice as many quarters as pennies, four times as many nickels as pennies, and five times as many dimes as nickels. How many more dimes does the child have than quarters?
Answer:19x
Step-by-step explanation:
Take x as the value of pennies
If there are twice as many quarters as pennies then the explanation should be
Pennies =x
Quarters =2x
If there are 4 times as many nickels as pennies then the explanation is
Pennies =x
Nickels =4x
If there are 5 times as many dimes as nickels then the explanation is
Nickels =4x
Dimes=20x
So the values of them all is
Pennies =x
Nickels =4x
Dimes =20x
Quarters =2x
So to get how many more dimes does the child have than quarters you subtract
20x-2x=19x
The Number of dimes the child has more than quarters is; 10 times more.
Let number of pennies be P
Since he has twice as many quarters as pennies, then;
Number of quarters; Q = 2P
Four times as many nickels as pennies. Then;
Number of nickels; N = 4P
five times as many dimes as nickels. Then;
Number of dimes; D = 5N = 5(4P) = 20P
Since number of quarters = 2P
And number of dimes = 20P
Then;
Number of dimes the child has more than quarters is; 20P/2P = 10
Thus, the child has ten times as many dimes as quarters
Read more on proportion at; https://brainly.com/question/25640375
Evaluaters rs + 14s when r = 6 and s 1/4
Answer:
5
Step-by-step explanation:
Plug is 6 for r and 0.25 for s
6(0.25)+14(0.25)
distribute
1.5+3.5=5
Hope this helps
B.s. is parallel to xy what is the value of x
Answer:
A. 85
Step-by-step explanation:
A bus makes a stop at 2:30, letting off 13 people and letting on 5. The bus makes another stop ten minutes later to let off 4 more people. How does the number of people on the bus after the second stop compare to the number of people on the bus before the 2:30 stop?
Answer:14
Step-by-step explanation:
13+5-4=14 No 1 more person got on.
Garrett must inspect a bridge that goes over a river. He begins 18 feet above water level to inspect the lighting, descends 32 feet to inspect the base of the bridge underwater, then descends another 4 feet to check on the concrete anchoring the base. Which best represents Garrett’s position with respect to the water level?
Answer:
–18 feet
Step-by-step explanation:
Answer:
-18
Step-by-step explanation:
Is the square root of 85 a rational number
It cost Brody $9.80 to send 196 text messages. How many text messages did he send if he spent $4.20? *
Answer:
84 text messages
Step-by-step explanation:
Set up a proportion and solve:
dollars / texts = dollars / texts
9.8 / 196 + 4.2 / x
9.8 * x = 4.2 * 196
9.8x = 823.2
9.8x / 9.8 = 823.2 / 9.8
x = 84
Brody would have sent 84 messages if he spent $4.20.
What is a Ratio?A ratio indicates the number of times one number contains another.
Given that, the cost of sending 196 text messages is $9.80.
Therefore,
$9.80 = 196 messages
$1 = 196/9.80 messages
$4.20 = (196/9.80)×4.20 messages
$4.20 = 84 messages
Hence, Brody would have sent 84 messages, if he spent $4.20.
To learn more about ratios, click here:
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Obtain an expression that looks like this: 25+ 4 А B. X(S) = + s(s +6) S +6 S
A= ___________
B =____________
Answer:
[tex]A = \frac{2}{3}[/tex]
[tex]B = \frac{4}{3}[/tex]
Step-by-step explanation:
Given
[tex]X(s) = \frac{2s + 4}{s(s +6)}= \frac{A}{s} + \frac{B}{s + 6}[/tex]
Required
Find A and B
The expression can be rewritten as
[tex]\frac{2s + 4}{s(s +6)}= \frac{A}{s} + \frac{B}{s + 6}[/tex]
Take LCM of the right hand side
[tex]\frac{2s + 4}{s(s +6)}= \frac{A(s + 6 )+ Bs}{s(s +6)}[/tex]
Cancel out the denominators
[tex]2s + 4 = A(s + 6) + Bs[/tex]
Open Bracket
[tex]2s + 4 = As + 6A+Bs[/tex]
Reorder
[tex]2s + 4 = As +Bs+ 6A[/tex]
By direct comparison:
[tex]2s = As + Bs[/tex]
[tex]4 = 6A[/tex]
Solving [tex]2s = As + Bs[/tex]
Divide through by s
[tex]2 = A + B[/tex]
Solve for A in [tex]4 = 6A[/tex]
[tex]\frac{4}{6} = A[/tex]
[tex]A = \frac{4}{6}[/tex]
[tex]A = \frac{2}{3}[/tex]
Substitute [tex]\frac{2}{3}[/tex] for A in [tex]2 = A + B[/tex]
[tex]2 = \frac{2}{3} + B[/tex]
[tex]B = 2 - \frac{2}{3}[/tex]
LCM
[tex]B = \frac{6 - 2}{3}[/tex]
[tex]B = \frac{4}{3}[/tex]
Solve for x in the equation x^2- 10x+ 25=35
Answer:
[tex]x = 5 + \sqrt{35} \: \: \:or \: \: \: x = 5 - \sqrt{35} \\[/tex]Step-by-step explanation:
x² - 10x + 25 = 35
Move 35 to the left side of the equation
That's
x² - 10x + 25 - 35 = 0
x ² - 10x - 10 = 0
Using the quadratic formula solve the equation
That's
[tex]x = \frac{ - b\pm \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]From the question
a = 1 , b = - 10 , c = - 10
Substitute the values into the above formula and solve
That's
[tex]x = \frac{ - - 10\pm \sqrt{( { - 10})^{2} - 4(1)( - 10) } }{2(1)} \\ = \frac{10\pm \sqrt{100 + 40} }{2} \\ = \frac{10\pm \sqrt{140} }{2} \\ = \frac{10\pm2 \sqrt{35} }{2} \\ = \frac{10}{2} \pm \frac{2 \sqrt{35} }{2} \\ = 5\pm \sqrt{35} [/tex]
We have the final answer as
[tex]x = 5 + \sqrt{35} \: \: \:or \: \: \: x = 5 - \sqrt{35} \\ [/tex]Hope this helps you
In the function y = a(x – h)2 + k
which variable controls the horizontal shift?
1)H
2)K
3)A
4)X
Answer:
h is the horizontal shift
Step-by-step explanation:
y = a(x – h)^2 + k
This is the equation for a parabola in vertex form
The vertex is ( h,k) and it is shifted from (0,0)
h is the horizontal shift and k is the vertical shift
Answer:
H
Step-by-step explanation:
y=a(x-h)2+ka= Vertical stretch or shrinkage(IaI>1) or (0<a<1) h= Horizontal shift(x-h=0)x=hK= Vertical shifty-value* a+kadd k to the "new: values of yThe measue of the supplement of an angle 20° more than three times the measure of the original angle. Find the measures of the angles.
1. The sum of the measures of the two angles is:
Answer:
x = orgininal angle
3x +20 = supplementary angle
1. x + (3x+20) = 180
2. 4x + 20 = 180
3. 4x = 160
4. x = 40
The orginial angle is 40
The supplementary angle is 140
Step-by-step explanation:
1. define your varibles using the words given
2. add them together to equal 180, because they are supplmentary.
3. combine like terms.
4. subtract 20
5. divide by 4
6. you find x, now plug it back into your variables at the top:
x = 40
3(40) + 20 = 140
Evaluate each expression 9+2(4)
Answer:
your answer is 17
PLZ HELP ASAP!! The volume of prism A is 630 in^3. What is the volume of prism B if it is the same height as prism A and every cross sectional area of prism A is equal to every cross sectional area of prism B at the same level ?
Answer:
[tex]Volume_B = 630in^3[/tex]
Step-by-step explanation:
Given
[tex]Volume_A = 630in^3[/tex]
Required
Determine [tex]Volume_B[/tex]
Volume is calculated as thus:
[tex]Volume = Height * Area[/tex]
From the question, we understand that both prisms have the same height and area;
This implies that
[tex]Volume_B = Volume_A[/tex]
Substitute [tex]630in^3[/tex] for [tex]Volume_A[/tex]
[tex]Volume_B = 630in^3[/tex]
Answer:
e. 630 in³
Step-by-step explanation:
ratio and proportion of volume with the same height:
vol A = 630
h = 21
Vol A = Vol B
h h
630 = Vol B
21 21
Vol B = 630 (21)
21
Vol B = 630 in³
Is 5.14 rational or irrational
Answer:
5.14 is irrational
Step-by-step explanation:
This is irrational because it is a decimal and/or a fraction, and a rational number is a whole number such as 1, 7, 32.
PLEASE HELP!! I WILL AWARD BRAINLIEST AND 50 POINTS!!!!!!!!!!!!!!!!!!!!!! For the given picture: a) List all of the triangles that are already drawn in the picture without changing it. b) For each triangle, list the exterior angle(s) that are already drawn in the picture without changing it. c) For each of the exterior angles in part (b), identify its remote interior angles in the corresponding triangle(s).
Answer:
There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)
1) A) Name of triangle: ABO
B) Exterior AngleS: EAO, BOC and AOD
C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO
2) A) Name of triangle: ABC
B) Exterior Angles:EAC
C) Remote Interior Angles: ABO and BCO
3) A) Name of triangle: DOC
B) Exterior Angles: ODH, DOA, COB, and OCG
C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC
4) A) Name Of triangle: COB
B) Exterior Angles: AOB, DOC, and OBF
C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB
Step-by-step explanation:
There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)
1) A) Name of triangle: ABO
B) Exterior AngleS: EAO, BOC and AOD
C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO
2) A) Name of triangle: ABC
B) Exterior Angles:EAC
C) Remote Interior Angles: ABO and BCO
3) A) Name of triangle: DOC
B) Exterior Angles: ODH, DOA, COB, and OCG
C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC
4) A) Name Of triangle: COB
B) Exterior Angles: AOB, DOC, and OBF
C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB
HELP ASAP!!! help wanted fast
The product of two consecutive negative even integers is 24. What is the smaller of the two numbers?
A. -6
B. -5
C. -4
D. -2
E. 4
Answer:
The smaller one is -6, the bigger one is -4.
Step-by-step explanation:
Answer:
A. -6
Step-by-step explanation:
10 times as many as 1 hundred is _____ hundreds are _____thousands.
10 hundreds or 1 thousand.
Further explanation
This question is related to place values.
10 times as many as a number is 10 multiplies the number.
Hence, 10 times as many as 1 hundred is
\boxed{ \ 10 \times 1 \ hundred \rightarrow \boxed{ \ 10 \ hundreds \ } \ }
Furthermore, 10 hundreds have the same meaning as 1 multiplies 10 hundreds which can produce 1 thousand.
\boxed{ \ 1 \times 10 \ hundred \rightarrow \boxed{ \ 1 \ thousand \ } \ }
Quick steps
Part-1
\boxed{ \ 10 \times 1 \ hundred = X \ hundred \ }
\boxed{ \ 10 \ hundred = X \ hundred \ }
Thus, \boxed{\boxed{ \ X = 10 \ }}
Part-2
\boxed{ \ 10 \times 1 \ hundred = Y \ thousand \ }
\boxed{ \ 10 \times 100 = Y \ thousand \ }
\boxed{ \ 1,000 = Y \ thousand \ }
\boxed{ \ 1 \ thousand = Y \ thousand \ }
Thus, \boxed{\boxed{ \ Y = 1 \ }}
- - - - - - -
Conclusions
10 times as many as 1 hundred is _10_ hundreds or _1_ thousand.
Learn more
9 ten thousands divided by 10 (in unit form) brainly.com/question/4786449
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Keywords: 10 times as many as 1 hundreds, hundreds, thousands, place value, operations, multiply, equal, blank, quick steps
Mendel crossed peas having round seeds and yellow cotyledons (seed leaves) with peas having wrinkled seeds and green cotyledons. All the F1 plants had round seeds with yellow cotyledons. Based on this cross, what is the probability that an organism in the F2 generation will have round seeds and green cotyledons and be true breeding? Mendel crossed peas having round seeds and yellow cotyledons (seed leaves) with peas having wrinkled seeds and green cotyledons. All the F1 plants had round seeds with yellow cotyledons. Based on this cross, what is the probability that an organism in the F2 generation will have round seeds and green cotyledons and be true breeding? 1/16 1/32 1/8 1/4
Answer:
1/16
Step-by-step explanation:
This question involves two distinct genes; one coding for seed shape and the other for cotyledon color. The alleles for round seeds (R) and yellow cotyledons (Y) are dominant over the alleles for wrinkled seed (r) and green cotyledon (y) respectively.
In a cross between a truebreeding (i.e. same alleles for both genes) pea having round seeds and yellow cotyledon (RRYY) and a truebreeding pea having wrinkled seeds and green cotyledon (rryy), the F1 offsprings will all possess a heterozygous round seed and yellow cotyledon (RrYy).
The F1 offsprings (RrYy) will produce the following gametes: RY, Ry, rY, and ry. Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in a ratio 9:3:3:1.
According to the question, 3/16 of the F2 offsprings will possess round seeds and green cotyledons, however, only 1 of them will be truebreeding i.e. RRyy. Hence, 1/16 of the F2 offsprings will be truebreeding for round seeds and green cotyledons.
Suppose a game show called Bayesian Boxes has the contestant sample one marble from a box and guess what type of box it is. When the contestant picks a box, the chance of each box type for this round is as follows: Type A: 75%, Type B: 20%, and Type C: 5% The chance of drawing a red marble from Type A is 2%, from Type B is 25%, and from Type C is 98%. The contestant selects a box and draws a marble. What is the chance of drawing a red m
Answer:
P(C/R) = 0.4298
Step-by-step explanation:
Missing word "arble, what is the chance it came from box Type C? (Give the decimal answer rounded to at least four places )"
Solution:
Given that P(A) = 75% = 0.75
P(B) = 20% = 0.20
P(C) = 0.05
The chance of drawing a Red marble fro,
P(R/A) = 2% = 0.02
P(R/B) = 25% = 0.25
P(R/C) = 98% = 0.98
If he select Box A than the probability of Red marble drawing
= P(A) * P(R/A)
= 0.75 * 0.02
= 0.015
If he select Box B than the probability of Red marble drawing
= P(B) * P(R/B)
= 0.20 * 0.25
= 0.5
If he select Box C than the probability of Red marble drawing
= P(C) * P(R/C)
= 0.98 * 0.05
= 0.049
So total probability of drawing Red marble is
P(R) = 0.015 + 0.050 + 0.049
P(R) = 0.114
If the Contestant draw a Red marble. Probability that it comes from box type (C) using Boyes theorem is
P(C/R) = {P(C) * P(R/C)} / P(R)
P(C/R) = 0.049 / 0.114
P(C/R) = 0.429824
P(C/R) = 0.4298
PLEASE HELPPPPPPPPPP The ratio of picnic tables to garbage cans
in a new national park should be 8:3.
The park design shows plans for picnic
tables in a small campground and a
large campground. How many garbage
cans should there be in each campground?
so, here’s the work. Try to change it a bit so it doesn’t look like you copied lol
h(x) = 4x + 5
g(x) = 3x + 5
Find (h + g)(-2)
Answer:
[tex]-4[/tex]
Step-by-step explanation:
So we have the two functions:
[tex]h(x)=4x+5\text{ and } g(x)=3x+5[/tex]
And we want to find:
[tex](h+g)(-2)[/tex]
This is the same as:
[tex]h(-2)+g(-2)[/tex]
Let's substitute them for their functions:
[tex]=(4(-2)+5)+(3(-2)+5)[/tex]
Multiply:
[tex]=(-8+5)+(-6+5)[/tex]
Add:
[tex]=-3-1[/tex]
Subtract:
[tex]=-4[/tex]
And we're done!
number 3 please solve and explain
Answer: -12.5
Step-by-step explanation:
x(2y-3) and x=2.5 and y=-1
so you fix in the figures so it will turn to
2.5(-2-3)
so then you open the brackets with 2.5
-5-7.5
Answer: -12.5
13. The perimeter P (in yards) of a soccer field is represented by the formula P = 24 + 2w,
where & is the length (in yards) and w is the width (in yards).
a. Solve the formula for w.
P= 330 yd
b. Find the width of the field.
c. About what percent of the field
is inside the circle?
doc
10 yd
- 100 yd
Answer:
[tex]w = \frac{1}{2}(P - 24)[/tex]
[tex]w = 153\ yards[/tex]
Step-by-step explanation:
Given
[tex]P = 24 + 2w[/tex]
Require
Solving (a):
[tex]P = 24 + 2w[/tex]
Subtract 24 from both sides
[tex]P-24 = 24-24 + 2w[/tex]
[tex]P-24 = 2w[/tex]
Divide both sides by 2
[tex]\frac{1}{2}(P - 24) = \frac{2w}{2}[/tex]
[tex]\frac{1}{2}(P - 24) = w[/tex]
[tex]w = \frac{1}{2}(P - 24)[/tex]
Solving (b):
Substitute 330 for P un the expression in (1)
[tex]w = \frac{1}{2}(330 - 24)[/tex]
Evaluate the bracket
[tex]w = \frac{1}{2}(306)[/tex]
[tex]w = 153\ yards[/tex]
Question c; seem irrelevant
1) (−12) + 7 what is the answer to this problem
