The area covered by the roof would be 84.5 square yards.
How to calculate the area covered by the roof of the house?To calculate the area covered by the roof the formula that should be used would be the formula for the area of a square;
That is ;
Area = 2(length×width)
= 2(6.5×6.5)
= 2(42.25)
= 84.5 yards²
Learn more about area here:
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pls I'll mark u BRAINLIEST
(B−A)∪C=(B∪C)−(A−C)
Answer:
(I don't have the complement sign of sets, so I've used "©" to denote compliment)
L.H.S.
(B-A)∪C
= (B∩A©)∪C
= (B∪C)∩(A©∪C)
= (B∪C)∩(A-C)©
= (B∪C)-(A-C) = R.H.S.
(Proved)
HELP ME SOLVE THIS PLEASE
HELPPPPPPPPPPPPPPPP:))))))
Answer:
Step-by-step explanation:
Since T is in Quadrant II, sinT > 0 and cosT < 0.
cotT = -5/12
a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.
Answer:
Step-by-step explanation:
I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):
** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.
** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.
** Due east has an angle measure of 0 degrees
Now let's begin.
We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:
[tex]A_x=50cos(89.75)[/tex] so
[tex]A_x=.22[/tex]
[tex]B_x=200cos(0)[/tex] so
[tex]B_x=200[/tex] and we need to add those results together. Due to the rules for adding significant digits properly, the answer is
[tex]C_x=200[/tex] (and remember I am counting that as 3 sig fig's even though it's only 1).
Now for the y components:
[tex]A_y=50sin(89.75)[/tex] so
[tex]A_y=50[/tex] (which I'm counting as 2 sig fig's)
[tex]B_y=200sin(0)[/tex] so
[tex]B_y=0[/tex] and we need to add those results together.
[tex]C_y=50[/tex]
Now for the resultant magnitude:
[tex]C_{mag}=\sqrt{(200)^2+(50)^2}[/tex] and that gives us a final magnitude of
[tex]C_{mag}=206[/tex] m
Now for the angle:
Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so
[tex]tan^{-1}(\frac{50}{200})=14[/tex]
The girl is 206 meters from her starting point at an angle of 14 degrees
Courtney needs to wrap this gift box, which is 412 inches wide, 6 inches long, and 3 inches tall. What is the surface area of the box?
The seating capacity at a movie theater is 400. For a Monday
afternoon movie, 68% of the seats are filled. About how many
seats are empty?
-.- sorta need this answer quickly, thanks
Which transformation gives the same result as a reflection over the x-axis followed b
a reflection over the y-axis?
Answer:
filtration system is not working
filtration
Sam wants to write an equation to represent a proportional relationship with a constant of proportionality of 6 he write y = 6 + x
Answer:
y = 6x
Step-by-step explanation:
The equation representing a proportional relationship is
y = kx ← k is the constant pf proportionality
Here k = 6 , then
y = 6x ← equation of proportion
Answer:
She is not correct, she would need to have something before the y to know the answer
Step-by-step explanation:
hope this helps :)
A Triangular Park ABC has sides 120 m, 80m and 50m. a gardener has to put a fence all around it and also plant grass inside. How much area does she need to plant? Find the cost of fencing it with barbed wire at the rate of of Rs. 20 per metre leaving a space 3m wide for a gate on one side?
The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
$\sf\underline\bold{Answer:}$
$\sf\small\underline{\underline{Area\: planted\: by\: the\: gardener : 1452.36m^2}}$$\sf\small\underline{\underline{The\:cost\:of\:fencing\:the\:park:Rs.4940}}$$\space$
$\sf\underline\bold{Step-by-Step:}$
$\space$
$\sf\bold{Given(In \:the\:Q):}$
Sides of the triangular park are 120m,80m and 50m.$\space$
$\sf\bold{To \: find:}$
How much area of the park does she need to plant?The cost of fencing the park ?$\space$
$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$
$\space$
$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$
$\space$
Use heron's formula to find the area of the triangle.
$\space$
$\mapsto$ $\sf\small{Heron's\:formula=}$
[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]
$\sf{Where\:s=semi\:perimeter}$$\sf{a,b,c\: = side\:of\:the\:∆}$$\sf\small{Here\:a=120,b=80 \:and\: c=50}$$\space$
$\sf\bold{Now,find\:semi\:parameter:-}$
$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$
$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$
$\space$
$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$
$\sf{Area\:of\:the\:∆:-}$
$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]
$\space$
$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$
$\space$
$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$
$\space$
$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$
______________________________
$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$
$\sf{Cost\:of\:fencing-}$
$\sf{Rate = Rs.20 per \:meter}$ $\sf{Left\:space=3m}$$\space$
$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$
$\sf{= 250-3=247m.}$$\space$
So,total cost of fencing at the rate of Rs.20 per m:-
$\sf\underline\bold\purple{=247\times20=4940}$___________________________________
Find the sum of the second multiple of 9 and the fifth multiple of 6.
Answer:
48
Step-by-step explanation:
9,18
6,12,18,24,30
18 + 30 = 48
SHORT ANSWER
Question 3
This expression has three restrictions. What are they?
(3x^2-3x/x-2)/(2x-10/x-4)
Answer in a complete sentence.
Answer:
The restrictions are x≠2,4,5
Step-by-step explanation:
First the denominators cannot be zero
x-2 ≠0 so x≠2
Then x-4 ≠0 so x≠4
Also, since we are dividing, when we flip the second expression, the numerator becomes the denominator, so it cannot be zero
2x-10≠0
2x≠10
x≠5
The restrictions are x≠2,4,5
What is the answer please help
Answer:
i don't know sorry
Answer:
a
Step-by-step explanation:
-5 shifts the y-intercept down, and it needs to be outside of the modulus as if its in the modulus, the graph would shift 5 units to the right instead
Rodney and their roommates are making homemade pizza for dinner. Rodney tells his roommates that he would like for his slice to be cut at a 100 degree angle. The pizza has a diameter of 20 inches. To the nearest tenth of an inch, find the area of Rodney's slice of pizza. Approximate pi at 3.14.
Answer:
Area of pizza slice = 87 inches² (Approx.)
Step-by-step explanation:
Given:
Angle cut of pizza = 100°
Diameter of pizza = 20 inches
Find:
Area of pizza slice
Computation:
Area of sector = [Ф / 360][π][r²]
Area of pizza slice = [100/360][3.14][(20/2)²]
Area of pizza slice = [100/360][3.14][(10)²]
Area of pizza slice = [100/360][3.14][100]
Area of pizza slice = [0.2778][3.14][100]
Area of pizza slice = 87.2292
Area of pizza slice = 87 inches² (Approx.)
The domain for f(x) and g(x) is the set of all real numbers.
Let f(x) = x2 + 1 and g(x) = 3x.
Find f · g.
A.
x2 + 3x + 1
B.
3x3 + 3x
C.
3x3 + 3x + 1
D.
x2 + 3x
Answer:
I say it's a
Step-by-step explanation:
I hope this help
7. The total cost to rent a truck is $100 and $0.20 per km.
a. Determine an algebraic model for the relationship between total cost and distance driven. Use C to
represent total cost (S) to rent the truck and d to represent distance driven (km).
Answer:
C = 100 + 0.20d
Step-by-step explanation:
Let
C = Total cost
d = distance driven(km)
$100 = fixed cost
$0.20 = additional cost
The algebraic model of the relationship:
Total cost = fixed cost + (additional cost * distance driven(km))
C = 100 + (0.20 * d)
C = 100 + 0.20d
6 year ago, a mans age was six times the age of his son,4year hence,thrice age will be equal to eight times his son age.find their age. Ans is 36 years and 11 years
Answer:
jsjzbdjwbxjdbwisjsobs9fbe
Step-by-step explanation:
hfkdowwhdbhdvsjsh2ivdusvqvduzvqidv
Answer:
Yeeeeaaahhhh its correct.
Help pls will give brainliest
Answer:
hello,
answer C
Step-by-step explanation:
area of the rectangle=2b*b=2b²
area of the half cercle= [tex]\\\dfrac{\pi*(\frac{c}{2})^2}{2} =\dfrac{\pi*c^2}{8} \\[/tex]
Area in blue= 2b²-πc²/8
Can you help me please please correct my
Answer:
a = m/c
~~~~~~~~~~~~~~~~~~~~~~~
m=ca
divide both sides by c
you get a = m/c
Step-by-step explanation:
Answer:
a = m/c
Step-by-step explanation:
m = ca
divide both sides by c
m/c = ca/c
m/c = a
:.a = m/c
pls help !! :// <333
Answer:
Its that squiglly one on top
Step-by-step explanation:
cuh cuh cuh cuh cuhc
Find the distance between the two points.
(-5,1)
(0,0)
[?]
Enter the number that
goes beneath the
radical symbol.
Answer:
[tex]{26}[/tex]
Step-by-step explanation:
[tex] \sqrt{(0 - ( - 5) ){}^{2} + (0 - 1) {}^{2} } [/tex]
[tex] = \sqrt{ {(5)}^{2} + {( - 1)}^{2} } [/tex]
[tex] = \sqrt{25 + 1} [/tex]
[tex] = \sqrt{26} [/tex]
Answered by GAUTHMATH
Answer:
26
Step-by-step explanation:
(-5, 1) (0, 0)
sqrt(5^2 + (-1^2))
sqrt(25 + 1)
sqrt(26)
So, 26 goes under the radical.
Solve the equation for all values of x.
(22 – 16)(2x2 + 49) = 0
Help please
Answer:
7i/sqrt(2)
Step-by-step explanation:
so, if I understand correctly, the equation is
(22-16)(2x² + 49) = 0
6(2x² + 49) = 0
that automatically means
2x² + 49 = 0
2x² = -49
x² = -49/2
x = sqrt(-49/2)
a square root of a negative number has no real solution. the solution is in the world of complex and imaginary numbers, which bases on the sqrt(-1) = i.
so, we get
x = sqrt(49/2 × -1) = (7/sqrt(2)) × I = 7i/sqrt(2)
please help meeeeeeeeeeeeee
Answer:
a)-2x(x+4x²)+3(x²+2x)
-2x²-8x³+3x²+6x
-2x²+3x²+6x-8x³
x²-8x³+6x
in descending order
-8x³+x²+6x
b)(4x-3)(4x+3)
4x(4x+3)-3(4x+3)
16x²+12x-12x-9
16x²-9
I hope this helps and sorry if it's wrong
Just need to know if I answered this correctly please!
Answer:
yes, your answers are correct
You would like to know how effective a diet program is at helping people lose weight. 18 over-weight people are randomly selected to participate in the program. They are weighed before and after the program and the results are listed below. Do these results give evidence that the diet program is effective at the 1% significance level?
Answer:
There is not enough evidence to support the claim that drug is effective at 1%
Step-by-step explanation:
For this we use the pored test as we have dependent test;
Difference :
10,5,-5,3,-3,4,2,-3,0,10,8,-2,3,-2,5,5,4,0
Hypothesis :
H0 : μd = 0
H0 : μd ≠ 0
The mean of d, dbar = Σd / n = 44 / 18 = 2.44
The standard deviation, Sd = 4.45 (using calculator)
The test statistic, T : dbar / (Sd/√n)
T = 2.44 / (4.45/√18)
T = 2.44 / 1.0488750
T = 2.326
Degree of freedom, df = n - 1 ; 18 - 1 = 17
The Pvalue = 0.0326
α = 0.01
Since Pvalue < α ; we fail to reject H0
Số hạng đầu và số hạng thứ 2 của một cấp số nhân lần lượt là x+2 và x^2 -4 số hạng thứ 3 của cấp số nhân này là
Answer:
x³-2x²-4x+8
Step-by-step explanation:
a1=x+2
a2=x²-4⇒q=a2/a1=x-2
⇒a3=q.a2=(x-2).(x²-4)=x³-2x²-4x+8
Find the derivative of f(x) = 6/x at x = -2. (2 points)
Using the definition of the derivative,
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{f(x) - f(-2)}{x - (-2)}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac6x + 3}{x + 2}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac{6+3x}x}{x + 2}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{6+3x}{x(x + 2)}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3(x+2)}{x(x + 2)}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3}{x} = \boxed{-\dfrac32}[/tex]
The soccer team is conducting a fundraiser selling long-sleeved t-shirts for $14 and short-sleeved t-shirts for $10. So far the team has sold less than $200 worth of the two types of t-shirts. Which inequality best represents x, the number of long-sleeved t-shirts they have sold, and y, the number of short-sleeved t-shirts they have sold?
Answer:
Step-by-step explanation:
If x represents the number of long-sleeved shirts and each of these cost $14, then the expression for that is 14x; likewise for short-sleeved shirts that are represented by y. The expression for short-sleeved shirts that cost $10 apiece is 10y. Putting that together with the fact that they earned less than $200 when selling these at the same time, the inequality is
14x + 10y < 200
Answer:D i just got it right trust mw
Step-by-step explanation:i
Which math expression means "the product of 16 and 26"?
16 +26
O 16.26
15 - 26
26-16
Answer:
The product of 16 and 26 would be 16 * 26
Step-by-step explanation:
This is because "the product of" means multiplication so *. Making it 16 * 26.
ILL GIVE POINTS!! PLS HELP !!!
Which set of polar coordinates describes the same location as the
rectangular coordinates (1. - 1)?
A. (sqrt2,315°)
B. (-1,135°) C. (sqrt2,225°)
D. (1,45°)
Answer:
The polar coordinates appear in the form (r, θ), where r is the the radius from the center and θ is the angle. To get the radius, do the following.
[tex]r = \sqrt{x^2 + y^2} = \sqrt{1^2 + (-1)^2} = \sqrt{2}\\[/tex]
You can get the angle visually by drawing a point (1, -1) on a graph and seeing that it is 45 degrees from the top right quadrant (you can tell its 45 because both x and y have the same magnitude). Since there are 360 degrees, 360 - 45 = 315.
If you would like to find it mathematically, this is the way to do it
[tex]\theta = atan(y/x) = -45[/tex]
Notice that -45 degrees is just 360 - 45 = 315
Your answer would be
[tex](\sqrt{2}, 315)[/tex]
Plz help me to find the answer to 4th question..plz help me
Answer:
I got that AE^2 = 8EC^2
Step-by-step explanation:
Here's what I did. I probably did this wrong, but this might give you an idea on how to solve it.
First, create equations:
AB = BC = AC = DE = 2EC
BD= BC = EC
Then, I used pythagorean theorem (since AD is perpendicular to BC): AD^2 + DE^2 = AE^2
Substitute: (2EC)^2 + (2EC)^2 = AE^2
Simplify: 4EC^2 + 4EC^2 = AE^2
AE^2 = 8CE^2