Answer:
housing, savings, and food
housing, food, and transportation
Explanation:
Given: Family Budget comprises of 23% housing, 21% food, 10% savings, 16% transportation, 12% medical, 13% clothing and 5% emergency fund.
To find: categories that make up more than half of the Hernandez family budget
Solution:
clothing + medical + emergency fund = [tex]13+12+5=30 \%[/tex]
clothing + housing + savings = [tex]13+23+10=46\%[/tex]
housing + savings + food = [tex]23+10+21=54\%[/tex]
housing + food + transportation = [tex]23+21+16=60\%[/tex]
food + transportation + emergency fund = [tex]21+16+5=42\%[/tex]
So, 3 categories that make up more than half of the Hernandez family budget are housing, savings, and food, housing, food, and transportation
Answer:
C and D
Explanation:
Just took the test
1. Describe two advantaged and disadvantages carbon fibre reinforced polymer has over materials such as GRP and Titanium.
2. Describe a disadvantage of CFRP compared to GRP
Answer:
the grp cast is very brittle however CFRP is extremely light and strong
Explanation:
Answer:
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On single-lane roads, _____ before taking a blind curve. A. flash your headlights B. check your rearview mirror C. honk for ten seconds D. slow down to a speed that allows you to see as much as possible
Answer:
A
Explanation:
to notify an incoming vehicle or pedestrian
On single-lane roads : ( D ) slow down to a speed that allows you to see as much as possible________ before taking a blind curve
What is a single lane road ?A single lane road is a road which has traffic moving in both directions on the same lane
On a single-lane road, vehicles moving in both directions make use of a single lane, therefore when in a blind curve you should slow down to a speed that will allow you to see as much as possible an oncoming vehicle.
Hence we can conclude that On single-lane roads : ( D ) slow down to a speed that allows you to see as much as possible before taking a blind curve.
Learn more about single lane roads : https://brainly.com/question/1203719
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John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction of the novel. Write an equation to determine the total number of pages (p)(p)left parenthesis, p, right parenthesis in the novel. John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1
Question:
John read the first 114 pages of a novel, which was 3 pages less than ⅓ of the novel. Write an equation to determine the total number of pages (P)
Answer:
114 = ⅓P - 3
Explanation:
Given
Number of pages read = 114
Total pages in novel = p
The relationship between the pages read by John and the total pages is analysed as follows:
3 less than ⅓ of total pages means:
⅓ of total pages - 3
Recall that P represents the total pages in the novel
So, the expression becomes
⅓ * P - 3
⅓P - 3
This means that the pages read by John is ⅓P - 3
This implies that the equation to determine the number of pages in the novel is
⅓P - 3 = 114
Solving further to get the actual number of pages;
Multiply both sides by 3
3(⅓P - 3) = 114 * 3
3 * ⅓P - 3 * 3 = 114 * 3
P - 9 = 342
Add 9 to both sides
P - 9 + 9 = 342 + 9
P = 351
Hence the number of pages is 351
Answer:
Answers below
Explanation:
1. 114 = 1/3p - 3
2. 351 pages
You are driving on a public road and need to tum your vehicle around. You can use a three-point turn
Whether the road is straight or curved, but not if the road is on a hill.
in place of a U-turn, if there is a sign prohibiting a U-turn.
O Only where U-turns are permitted, and only if the road is too narrow for your vehicle to make a U-turn and you cannot go
around the block.
What’s a pigtail when wiring
Answer:
A pigtail when wiring is technique that is used in connecting a lot of wires together.
Explanation:
A pigtail is a wire that is short in length. It has two ends. One end has a connector while the other end has other wires connected to it.
Pigtail when wiring is the connection of more than one wire in a circuit to another device. Pigtail when wiring helps to extend the length of the wire in a circuit if the wire used it short).
Pigtail when wiring is a technique what helps to keep the circuit organised because it prevents the wires from getting tangled.