The ideal bond angles marked 1, 2, and 3 in the molecule below are about _______, ______, and ______.

Answer:

B.

Explanation:

Because one or more substances,the reactants are converted into one or more Different substances,the products. Hope this helps

Answer:

Radiocarbon dating is a method used for knowing the exact age of a fossil.

Explanation:

Radiocarbon dating is a fundamental tool for archaeologists use to determine the age of objects. According to new research, it's shown that radiocarbon dating standards cannot always accurate. The reason for it lies in the climatic condition of that particular area. Variations in the radiocarbon affected cite in the Levant region like Israel, Egypt, and Jordan.

The final temperature of the metal block : t=69.5 °C

Given

0.84 g water

Aluminum block = 51 g

Required

The final temperature

Solution

Enthalpy of vaporization of water is 44.0kJ/mol = 2.44 kJ/g=2440 J/g

Q out=Q in

Q releases = Q absorbed

Q water = Q Aluminum

m.Lf = m.cs.ΔT

0.84 x 2440 J/g = 51 x 0.903 J/g C x (t-25)

2049.6=46.053(t-25)

t=69.5 °C

.

Answer:

56g the time to convey he must take care of the full stops and then try to combine the two sentences that the time to convey

Answer:

Change occur in heat energy.

Explanation:

Change occur in the heat energy of molecules during condensation process. The molecules of gas releases its heat energy and converted into liquid state. With this heat energy, they are active and escape from each other but when the heat energy is removed from them, the attractive forces between these gas molecules are formed which convert them into liquid state so change in heat energy occur in the condensation process.

Answer:

3.09 atm

Explanation:

Given that:

Volume of container A = 717 mL

Pressure of container A = 2.80 atm

Volume of container B = 174 mL

Pressure of container B = 4.30 atm

Now, if the valve are being removed and the gases are allowed to mix together; then

The total final pressure can be calculated by using the formula:

[tex]P_f = \dfrac{P_AVA+P_BV_B}{V_A+V_B}[/tex]

[tex]P_f = \dfrac{2.80*717+4.30*174}{717+174}[/tex]

[tex]P_f = \dfrac{2007.6+748.2}{891}[/tex]

[tex]P_f = \dfrac{2755.8}{891}[/tex]

[tex]\mathbf{P_f =3.09 \ atm}[/tex]

The absence of the intermolecular attraction between the atoms or molecules is called an ideal gas.  The pressure of the resultant mixture is 3.09 atm.

The relationship between the pressure and the volume of the gas is given by Boyle's law which states the inverse proportionality relation with the volume.

Given,

The volume of container A = 717 mL

The volume of container B = 174 mL

The pressure of container A = 2.80 atm

The pressure of container B = 4.30 atm

The total final pressure of the ideal gas of the mixture is calculated by:

[tex]\begin{aligned} \rm P_{f} &= \rm \dfrac{P_{A}V_{A}+ P_{B}V_{B}}{V_{A}+V_{B}}\\\\&= \dfrac{2007.6 +748.2}{891}\\\\&= 3.09 \;\rm atm\end{aligned}[/tex]

Therefore, the total pressure of the mixture is 3.09 atm.

Learn more about pressure here:

https://brainly.com/question/13534890

Explanation:

B.Electroplating involves passing an electric current through a solution called an electrolyte. A redox reaction is spontaneous if the standard electrode potential for the redox reaction is positive

Answer:

16480 Kg

Explanation:

From the question given above, the following data were obtained:

Volume of Hydrogen = 200000 m³

Density of Hydrogen = 0.0824 g/L

Mass of Hydrogen (in Kg) =?

Next, we shall convert 200000 m³ to L. This can be obtained as follow:

1 m³ = 1000 L

Therefore,

200000 m³ = 200000 m³ × 1000 L / 1 m³

200000 m³ = 2×10⁸ L

Thus, 200000 m³ is equivalent to 2×10⁸ L.

Next, we shall determine the mass of Hydrogen. This can be obtained as follow:

Volume of Hydrogen = 2×10⁸ L

Density of Hydrogen = 0.0824 g/L

Mass of Hydrogen =?

Density = mass /volume

0.0824 = mass of Hydrogen / 2×10⁸

Cross multiply

Mass of Hydrogen = 0.0824 × 2×10⁸

Mass of Hydrogen = 16480000 g

Finally, we shall convert 16480000 g to kg in order to obtain the desired result. This can be obtained as follow:

1000 g = 1 kg

Therefore,

16480000 g = 16480000 g × 1 kg / 1000 g

16480000 g = 16480 Kg

Thus, the mass of Hydrogen used to fill the airship was 16480 Kg

Answer:

the property that is shared between liquids us called thermometric property your welcome

Answer: an amount of space between two things or people.

Explanation: hope this helps? :)

Answer:

0.9537g is the original mass of Zn in the mixture

Explanation:

We can solve this question using the molar mass of each compound involved:

Mg = 24.305g/mol

MgO = 40.304g/mol

Zn = 65.38g/mol

ZnO = 81.38g/mol

Mg-Zn:

1.0875g = 24.305X + 65.38Y (1)

Where X are moles of Mg and Y moles of Zn

MgO-ZnO:

1.4090g = 40.304X + 81.38Y (2)

(1.4090g - 81.38Y) / 40.304 = X

0.03496 - 2.0192Y = X

Replacing (2) in (1)

1.0875g = 24.305(0.03496 - 2.0192Y) + 65.38Y

1.0875 = 0.8497 - 49.077Y + 65.38Y

0.2378 = 16.303Y

0.01459 moles of Zn = Y

And the mass is:

0.01459 moles of Zn * (65.38g/mol) =

Answer:

Explanation:

quantum number of neptunium is

6

    [tex]L_{11/2}[/tex]

Answer:hydrogen, deuterium, and tritium.

Explanation:

Answer:

The catalyzed reaction will take 2.85 seconds to occur.

Explanation:

The activation energy of a reaction is given by:                                                        

[tex] k = Ae^{-\frac{E_{a}}{RT}} [/tex]

For the reaction without catalyst we have:

[tex] k_{1} = Ae^{-\frac{E_{a_{1}}}{RT}} [/tex]   (1)

And for the reaction with the catalyst:

[tex] k_{2} = Ae^{-\frac{E_{a_{2}}}{RT}} [/tex]   (2)

Assuming that frequency factor (A) and the temperature (T) are constant, by dividing equation (1) with equation (2) we have:                      

[tex] \frac{k_{1}}{k_{2}} = \frac{Ae^{-\frac{E_{a_{1}}}{RT}}}{Ae^{-\frac{E_{a_{2}}}{RT}}} [/tex]

[tex] \frac{k_{1}}{k_{2}} = e^{\frac{E_{a_{2}} - E_{a_{1}}}{RT} [/tex]    

[tex] \frac{k_{1}}{k_{2}} = e^{\frac{59.0 \cdot 10^{3}J/mol - 184 \cdot 10^{3} J/mol}{8.314 J/Kmol*600 K} = 1.31 \cdot 10^{-11} [/tex]    

Since the reaction rate is related to the time as follow:

[tex] k = \frac{\Delta [R]}{t} [/tex]

And assuming that the initial concentrations ([R]) are the same, we have:

[tex] \frac{k_{1}}{k_{2}} = \frac{\Delta [R]/t_{1}}{\Delta [R]/t_{2}} [/tex]

[tex]\frac{k_{1}}{k_{2}} = \frac{t_{2}}{t_{1}}[/tex]

[tex] t_{2} = t_{1}\frac{k_{1}}{k_{2}} = 6900 y*1.31 \cdot 10^{-11} = 9.04 \cdot 10^{-8} y*\frac{365 d}{1 y}*\frac{24 h}{1 d}*\frac{3600 s}{1 h} = 2.85 s [/tex]

Therefore, the catalyzed reaction will take 2.85 seconds to occur.

I hope it helps you!                            

Answer:

See explanation and image attached

Explanation:

Yttrium has many isotopes, the lowest mass number of Yttrium  is 89Y.

Recall that electron capture converts an electron into a proton and then into a neutron with a consequent emission of a neutrino (v).

In electron capture, the mass number of the daughter nucleus remains the same as that of the parent nucleus while the atomic number of the daughter nucleus is less than that of the parent by one unit.

Answer:

[tex]m_{Li_3N}=9.06gLi_3N[/tex]

Explanation:

Hello!

In this case, since the reaction between nitrogen and lithium to obtain lithium nitride is:

[tex]6Li+N_2\rightarrow 2Li_3N[/tex]

Starting by that amount of atoms of lithium, we first need to compute the moles of lithium via the Avogadro's number:

[tex]n_{Li}=4.7x10^{23}atoms*\frac{1molLi}{6.022x10^{23}atoms}=0.78molLi[/tex]

Now, by using the 6:2 mole ratio between lithium and lithium nitride and the molar mass of this product (34.83 g/mol), we can compute the required grams as shown below:

[tex]m_{Li_3N}=0.78molLi*\frac{2molLi_3N}{6molLi}*\frac{34.83gLi_3N}{1molLi_3N} \\\\m_{Li_3N}=9.06gLi_3N[/tex]

Best regards!

Answer:

[tex]n_{P_2O_5}^{max}=1.4molP_2O_5[/tex]

Explanation:

Hello!

In this case, since the reaction between phosphorous and oxygen to form diphosphorous pentoxide is:

[tex]2P+\frac{5}{2}O_2\rightarrow P_2O_5[/tex]

Thus, since phosphorous is in excess and oxygen and diphosphorous pentoxide are in a 5/2:1 mole ratio, we can compute the maximum moles of product as shown below:

[tex]n_{P_2O_5}^{max}=112 gO_2*\frac{1molO_2}{32.00gO_2}*\frac{1molP_2O_5}{5/2molO_2}\\\\ n_{P_2O_5}^{max}=1.4molP_2O_5[/tex]

Best regards!

Answer:

6

Explanation:

Answer:

Explanation:

1 % w/v of  phenolphthalein di-phosphate (PPP)

will contain 1 gram of  phenolphthalein di-phosphate (PPP) in 100 mL of solution

750 mL solution will contain 7.5 g of PPP

750 mL solution will contain 7.5 / 478 moles  of PPP

750 mL solution will contain .0157 moles  of PPP

So 7.5 g of PPP or .0157 mole of PPP will be needed .

Mass of water vapor produced : 0.90 g

Given

0.10 g of hydrogen reacted with 0.80 g of oxygen

Required

mass of water vapor produced

Solution

Reaction

2H₂ + O ⇒ 2H₂O

If we refer to the law of conservation of mass which states that the mass before and after the reaction is the same, then the mass of water vapor formed as a product is:

mass reactants = mass products

mass of Hydrogen + mass of Oxygen = mass of water vapor

0.1 g + 0.8 g = 0.90 g

Or we can also solve by using stochiometry (using the concept of moles) to find the mass of water vapor

Answer:

wow 15 points is alot

Explanation:

Answer:

No.

Explanation:

He also created a telescope and formula for universal gravity.

Answer: B) metals, non-metals, metalloids

An example of a metal is iron. A non-metal example is oxygen, which is a gas at STP (standard temperature and pressure).

A metalloid is a bit of a mix between a metal and non-metal element. It's sorta like an element that has both properties of metals and non-metals, or it's in a murky gray area. An example of a metalloid would be silicon.

Answer:

50 mol

Explanation:

Mass of methane = 800 g

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂      →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 800 g/ 16 g/mol

Number of moles = 50 mol

Now we will compare the moles of methane and carbon dioxide from balanced chemical equation.

                CH₄        :         CO₂

                   1           :          1

                 50          :        50

Answer:

[tex]m_{Fe}=171.7gFe[/tex]

Explanation:

Hello!

In this case, since we have 245 of iron (III) oxide, we first need to compute the moles contained there:

[tex]n_{Fe_2O_3}=245gFe_2O_3*\frac{1molFe_2O_3}{159.7gFe_2O_3} =1.54molFe_2O_3[/tex]

Now, as 1 mole of iron (III) oxide is related to 2 moles of iron, due to iron's subscript in the molecule, we get the moles of iron itself:

[tex]n_{Fe}=1.54molFe_2O_3*\frac{2molFe}{1molFe_2O_3} =3.08molFe[/tex]

And the mass is computed based on the atomic mass of iron:

[tex]m_{Fe}=3.08molFe*\frac{55.8gFe}{1molFe} \\\\m_{Fe}=171.7gFe[/tex]

Best regards!

Answer:

Explanation:

18 gram of water contains 2 g of hydrogen

3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .

44 gram of carbon dioxide contains 12 g of carbon

7.691 gram of carbon dioxide will contain 12 x 7.691 / 44 = 2.1 g of carbon .

So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .

= .465 g of oxygen .

moles of Carbon = 2.1 / 12 = .175

moles of hydrogen = .347 / 1 = .347

moles of oxygen = .465 / 16 = .029

Ratio of moles of carbon , oxygen and hydrogen ( C,O,H )

= 0.175 : 0.029 : 0.347

= .175/ .029 : 1 : .347 / .029

= 6 : 1 : 12

So empirical formula = C₆H₁₂O

Let the molecular formula be [tex](C_6H_{12}O)_n[/tex]

molecular weight = n ( 6 x 12 + 12x 1 + 16)

= 100 n

Given 100 n = 100.1

n = 1

Molecular formula = C₆H₁₂O.

Answer:

Most likely phosphorus, antimony, arsenic, boron, indium or gallium. The wiring is composed mainly of copper, gold, and silver.