perimeter of the rectangle = 2 ( l + b )
2 ( x + x + 5 ) cm 2 ( 2x + 5') cm ( 4x + 10 ) cm
4x + 10 = 40
4x = 40 10 ( transpose 10 to RHS )
x = 30/4 = 7.5 ( divide both sides by 4 )
lenght of the rectangle = x + 5 = 7.5 + 5 = 12.5 cm breadth of the rectangle = x = 7.5 cmATQ
[tex]\\ \sf\longmapsto 2(x+x+5)=40[/tex]
[tex]\\ \sf\longmapsto 2(2x+5)=40[/tex]
[tex]\\ \sf\longmapsto 2x+5=20[/tex]
[tex]\\ \sf\longmapsto 2x=15[/tex]
[tex]\\ \sf\longmapsto x=7.5[/tex]
Length=12.5cmBreadth=7.5cm110 < 2x + 10 pls helppppppp
110<2x+10
Step 1: Flip the equation.
2x+10>110
Step 2: Subtract 10 from both sides.
2x+10−10>110−10
2x>100
Step 3: Divide both sides by 2.
x>50
Step-by-step explanation:
what is 7 × 6 − 6 × 2 ÷ 8 + 99 − 5 ÷ 3 × 4
help me plz
hello, please answer
if
[tex]\frac{a}{b} = \frac{c}{d} = \frac{2}{5}[/tex]
then what is the answer of :
[tex]\frac{a + 3c + 4}{b + 3d + 10}[/tex]
Step-by-step explanation:
[tex]{ \rm{a = c = \frac{2}{5} b}} \\ \\ { \rm{b = d = \frac{5}{2} a}}[/tex]
• Substitute:
[tex]{ \rm{ \frac{a + 3c + 4}{b + 3d + 10} = \frac{ \frac{2}{5} b + \frac{6}{5}b + 4 }{ b + \frac{15}{2} b + 10} }} \\ \\ = { \rm{ \frac{ \frac{8}{5} b + 4}{ \frac{17}{2}b + 10 } }} \\ \\ { \rm{}}[/tex]
I'm having trouble. Can someone answer?
Answer:
okay wait
Step-by-step explanation:
Which expression is equivalent to
Step-by-step explanation:
this is very blurry. please make sure you pick the answer option that is the exact result of the solution here.
to get the full result, we can split the individual multiplications of fractions apart, simplify the individual fractions, and then simply connect them again :
-9/-15 = 3/5
x^‐1/x⁵ = 1/x¹x⁵ = 1/x⁶
y^-9/y^-3 = y³/y⁹ = 1/y⁶
so, by multiplying all 3 parts together again we get
3/(5x⁶y⁶).
I suspect this is the second answer option, but please make sure.
what triangle does the pythagorean theorem relate to
Answer:
Right Triangle
Step-by-step explanation:
I hope this helps!
PLS HELP
First answer- (5,0) (10,0)
Second answer- (0,1//20) (0,20)
PLSSS HELP THIS IS HARD ANYONE
Answer:
b: 8
Step-by-step explanation:
with dilating by 2, the B' figure would be bigger than B
because 4*2 = 8
Simplify (x-4) (x^2 + 3x + 2)
Answer:
x^3-x^2-10x-8
Multiply each term in the first expression by each term in the second expression and combine like terms.
Find the value of x
please helppppp!!!!
Answer:
x = 3
Step-by-step explanation:
The two marked angles form a linear pair, so are supplementary. Their sum is 180°.
(3x +136)° +(5x +20)° = 180°
8x +156 = 180 . . . . . . . . . . . divide by °, collect terms
8x = 24 . . . . . . . . . . . . . . subtract 156
x = 3 . . . . . . . . . . . . . . divide by 8
_____
Additional comment
We suspect the intended answer for the second question is A 25° and 65°. These are possible measures for the acute angles in a right triangle, which must total 90°. No angle will be more than 90° (eliminates C and D), and the two smallest angles must total 90° (eliminates B).
help me pleaseeeeeeeeee
Answer:
See image
Step-by-step explanation:
For this question, you need to know several special relationships about circles. A radius goes from the center of a circle to any point on the circle. All the radii (not a typo, plural of radius is radii) are the same size, their measures are equal; we say they are congruent (the symbol is an equal sign with a ~over it)
In the diagram, OA and OB are congruent because they are radii. AC is a tangent, that means that it touches the circle at exactly one point, in this case at A. So since OA is a radius and AC is a tangent, they are perpendicular to each other (makes 90° angles). Then we can subtract 90 - 72 to find the angle OAB. Angle OAB is 14°. In triangle AOB, which has two sides the same, the opposite angles will also be congruent which means OBA is also 14° (OR you could use the exact same logic for OB perpendicular to BC and subtract, same calculation as before) . Once you have the two 14° angles in the triangle, you can use the fact that all the angles in a triangle add up to 180° So then, 14 + 14 + x =180. Solve this equation to find angle AOB. See image.
Is 24 the correct LCD to use for subtracting 6 3/4 - 1 2/6 ? Why or why not?
In your own words, describe how to find the GCF for a set of numbers. Use the numbers 24 and 32 as an example.
Subtract and reduce to lowest terms: 9/10 - 3/10.
PLEASE HELP ASAP
Answer:
Step-by-step explanation:
A
No 24 is not the best number to use for the LCD, although it will work. 12 is much better because it is smaller.
B
Factor each number into it's primes.
24 = 2*2*2*3
32 = 2*2*2*2*2
The highest common factor is 2*2*2 = 8
C
9/10 - 3/10 = 6/10 The denominator remains the same. The numerators get subtracted.
6/10 = 3/5 Two goes into both numerator and denominator of the answer. Therefore you can divide both 6 an 10 by 2
Choose a midsegment of LJK.
A)LO
B)MK
C)OM
D)LN
Answer:
B
Step-by-step explanation:
that's my answer hope it helps ✨
The mid segment can be MK or LO or LN.
What is Mid segment?The line segment that joins the midpoints of two triangle sides is known as a midsegment. Each triangle has three midsegments since a triangle has three sides. A triangle's midsegment is half the length of the third side and runs parallel to the third side of the triangle.
Given:
We know that the Midsegment is generally formed by the mid points of the line.
But, for Mid Segment of LJK we can write
Mid Segment= 1/2 x Triangle Base
= 1/2 x JK (or LK or LJ)
= MK or LO or LN
Hence, the mid segment can be MK or LO or LN.
Learn more about Mid segment here:
https://brainly.com/question/15381486
#SPJ2
I need to understand this better so Can I please get a step by step explanation? i will give brainiest
Answer:
10 inStep-by-step explanation:
The sides r, 10 and 20 are parallel to each other as all three are perpendicular to same line.
The triangles are similar as two sides are on same lines and another one is parallel as described above.
Work out the value of r using ratios of corresponding sides:
(r + 10)/(10 + 20) = r/10(r + 10)/30 = r/10r + 10 = 3r2r = 10r = 5 inNow, find the distance x from the bottom of the cone to the base of the smallest ball, using same method as above:
(x + r)/r = (x + 2r + 10)/10(x + 5)/5 = (x + 20)/102(x + 5) = x + 202x + 10 = x + 20x = 10Plzzzz help meeeeee plzzzzzzz
the answer is 120 because if you multiply 0.40 aka 40% by 300 you will get 120
Answer:
120
Step-by-step explanation:
To find the answer, multiply 300 with 0.40
To confirm this answer, divide 120 by 0.40
What is the domain of the equation shown in the graph?
Question options:
All real numbers
x= ≤ -1
x≥-1
x≤0
Answer:
All real numbers.
Step-by-step explanation:
The domain is the range of values of x.
The graph goes on without bounds to - infinity and positive infinity.
What is the value of the function y= 3x - 1 when x=-1?
-
-8
-4
O 2
06
Need help now
Answer:
-4
Step-by-step explanation:
y=3x - 1 x= -1
y = 3(-1) -1
y = -3 -1
y= -4
PLEASE HELPPPPP!!!
Find the slope and y-intercept of the graph of each question:
1. y=6x+11
(pretty sure 6 is the slope and 11 is the y-intercept... pls correct me if me wrong)
2. y=x+6
(1 is the slope and 6 is the y-intercept??)
Answer:
1. slope = 6, y-intercept = 11
2. slope = 1, y-intercept = 6
Answer:
you are correct
Step-by-step explanation:
6 is the slope and 11 is the y-intercept
1 is the slope and 6 is the y-intercept
Question 3(Multiple Choice Worth 1 points)
(01.05 LC)
Which calculation can be used to find the value of y in the equation y3 = 27?
y=y equals 27 over 3
y=y equals cube root of 27
y=y equals square root of 27 over 3
y=y equals square root of 27
Answer:
y = y is equal to 27 over 3
Step-by-step explanation:
being y3 = 27
the y3 is found by multiplying and is passed to the other side by dividing, becoming y = 27/3
the histogram shows the GPAs of the students in george’s class. Estimate the mean of the data set displayed in the histogram.
Using the histogram, the mean of the data-set is estimated to be of 31.
The mean, given an histogram, is the sum of the halfway points of each interval multiplied by it's relative frequency.In this problem, the intervals and relative frequencies are:
The first interval has halfway point 23 and relative frequency [tex]\frac{4}{30}[/tex].The second interval has halfway point 28 and relative frequency [tex]\frac{8}{30}[/tex].The third interval has halfway point 33 and relative frequency [tex]\frac{14}{30}[/tex].The fourth interval has halfway point 38 and relative frequency [tex]\frac{4}{30}[/tex].Hence, the mean is:
[tex]E(X) = 23\frac{4}{30} + 28\frac{8}{30} + 33\frac{14}{30} + 38\frac{4}{30} = \frac{23(4) + 28(8) + 33(14) + 38(4)}{30} = 31[/tex]
For more on mean of histograms, you can check https://brainly.com/question/24651197
Alex wants to buy the same number of stamps and envelops. Stamps are sold in packs of 14 and envelops are sold in the packs of 10.
What is the least number of each he could buy to have the same number of stamps and envelops?
Please show work
Answer:
70
Step-by-step explanation:
the least common multiple of 10 and 14 will be the answer
the prime factorization of 10 is 2 and 5
the prime factorization of 14 is 2 and 7
so you can multiply the number in common, 2, by the ones not common, 5 and 7
2 x 5 x 7 = 70
write a linear function f with given values.
Answer:
given slope of 2 and a y intercept of 0
f(x) = 2x
Please solve this .
The graph shows the linear function. I hope this helps.
3. There are 12 red balloons and 14
blue balloons in the bouquet.
What is the ratio of red balloons to blue balloons?
Answer:
6:7
Step-by-step explanation:
Divide 12 and 14 by 2 to simplify the ratio.
Answer: 6:7
Step-by-step explanation:
The number of red balloons in 12 and the number of blue ones is 14, which can be written as 12:14. 12:14 can be simplified to 6:7
y = 5x + 1
Table down below
Help!
Answer:
Answers below
Step-by-step explanation:
-32 -> -7.4
0 -> 1
20 -> 5
Which of the following is true of the location of the terminal side of an angle, Theta, whose sine value is One-half? Theta has a reference angle of 30° and is in Quadrant I or II Theta has a reference angle of 30° and is in Quadrant I or IV Theta has a reference angle of 60° and is in Quadrant I or II Theta has a reference angle of 60° and is in Quadrant I or IV.
The sine of the angle theta is given by the ratio of the opposite leg to the hypotenuse side of the right triangle formed by the terminal segment.
The true location of the terminal side of the angle θ is given by the option; Theta has a reference angle of 30° and is in Quadrant I or II.Reasons:
The given parameters are;
The sine value of the given angle = One-half
Required: To select the true statement of the location of the terminal side.
Solution:
Given that sin(θ) = 0.5, we have;
The sine of an angle is positive in Quadrant I and Quadrant II
Given that the value of sin(θ) is positive, we have θ is in Quadrant I or Quadrant IIThe reference angle, is the angle formed between the angle's terminal side and x-axis
By trigonometric ratios, considering the reference angle, we have;
θ = arcsin(0.5) = 30°
Therefore;
The option that gives the true location of the terminal side of an angle, that have a sine value of One-half is; Theta has a reference angle of 30° and is in Quadrant I or II.
Learn more about trigonometric ratios here:
https://brainly.com/question/2398899
Answer:
a
Step-by-step explanation:
edge
What is the slope of the line?
Answer:
(1,1)
Step-by-step explanation:
Let f(x) = x2 − 16. Find f−1(x)
Answer:
[tex]f^{-1}(x)=\pm\sqrt{x+16}[/tex]
Step-by-step explanation:
[tex]f(x)=x^2-16[/tex]
To find the inverse of this function, temporarily the f(x) with a y (or whatever else you want) and then solve for the x.
[tex]y=x^2-16\\y+16=x^2\\x=\pm\sqrt{y+16}[/tex]
Now, you can swap the variables again and write the function.
[tex]f^{-1}(x)=\pm\sqrt{x+16}[/tex]
Plzzzz help mee plzzzzz plzzzzz
Answer:
1. B
2. Seven Hundred thousand nine hundred and four
Step-by-step explanation:
PLZ HELP DUE TODAY BRAINLIEST AND 100 POINTS
5(2.2y+1)-3
11y+5-y
11y+2
Answer:
Step-by-step explanation:
Remove the brackets
5*2.2y + 5 - 3
11y + 5 - 3
11y + 2
The answer is the last one.
[tex]\\ \rm\rightarrowtail 5(2.2y+1)-3[/tex]
Solve in between the brackets
[tex]\\ \rm\rightarrowtail 5(4y+1)-3[/tex]
[tex]\\ \rm\rightarrowtail 20y+5-3[/tex]
[tex]\\ \rm\rightarrowtail 20y+2[/tex]
[tex]\\ \rm\rightarrowtail 2(10y+1)[/tex]
