The length of the longer leg of a right triangle is 13 m more than three times the length of the shorter leg. The length of the hypotenuse is 14 m more than three times the length of the shorter leg. Find the side lengths of the triangle. Length of the shorter leg: 0 m Length of the longer leg: in Length of the hypotenuse:​

Step-by-step explanation:

17. 21⁰ + 31⁰ + ?⁰ = 180⁰

= ?⁰ = 128⁰

18. ?² = 12² + 5²

? = √169

? = 13 TYPO

Answer:

17: 128
18: 13

Step-by-step explanation:

17: 21 + 31 = 52, 180 - 52 = 128.

18: a² + b² = c².
5² = 25
12² = 144
25 + 144 = 169
169 square rooted = 13
C (aka the missing side) = 13

edited to fix 17 from 121 to 128

[tex]\left(\dfrac{(-1)^5}{(-2)^{-3}} \right)^2\\\\\\=\left(\dfrac{-1}{\dfrac{1}{(-2)^3}} \right)^2\\\\\\=\left(-1 \times -8\right)^2\\\\=8^2\\\\=64[/tex]

Answer:

[tex]\huge\boxed{\bf\:64}[/tex]

Step-by-step explanation:

[tex]\left(\frac{(-1)^{5}}{\left(-2\right)^{-3}}\right)^{2}[/tex]

Now, simplify [tex](-1)^{5} = -1[/tex]. Then,

[tex]\left(\frac{-1}{\left(-2\right)^{-3}}\right)^{2}[/tex]

Calculate: [tex](-2)^{-3} = \frac{1}{(-2)^{3}} = - \frac{1}{8}[/tex].

[tex]\left(\frac{-1}{-\frac{1}{8}}\right)^{2}[/tex]

Divide [tex]-1[/tex] by [tex]- \frac{1}{8}[/tex]. The result will be [tex]8.[/tex]

[tex]\left(-\left(-8\right)\right)^{2} \\= 8^{2}[/tex]

Calculate [tex]8[/tex] to its square which is [tex]64.[/tex]

[tex]8^{2}\\=\boxed{\bf\: 64} \: \:\mathrm{(3^{rd} \: option)}[/tex]

[tex]\rule{150pt}{2pt}[/tex]

Answer:The output values are reflected across the x-axis and the input values are reflected across the y-axis.

Step-by-step explanation:

aye man you gotta believe me ;)

The graph of f(x) is transformed into g(x) by reflecting the output values across the x-axis and reflecting the input values across the y-axis.

We have,

f(x) = (1/2)³x

and, g(x) = -(1/2)³⁻ˣ

In f(x), the coefficient 3 in the exponent represents exponential growth.

Now, g(x) = –One-half(3)–x.

Here, the negative sign changes the sign of the output values, reflecting them across the x-axis. This means that the graph will be flipped upside down.

and, the negative exponent also changes the sign of the input values, reflecting them across the y-axis. This means that the graph will be mirrored across the y-axis.

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Answer:

  9990 years

Step-by-step explanation:

The exponential function with given values filled in can be solved for the unknown using logarithms.

__

  Q(t) = 12 = 36e^(-0.00011t)

  1/3 = e^(-0.00011t) . . . . . . divide by 36

  ln(1/3) = -0.00011t . . . . . . take natural logs

  t = ln(1/3)/(-0.00011) . . . . divide by the coefficient of t

  t ≈ 9990 . . . years

Answer:

2 cups of flour

2/3 cup of sugar

1 1/3 cups of chocolate chips

Step-by-step explanation:

3 dozen chocolate chip cookies

3 cups of flour

1 cup of sugar

2 cups of chocolate chips

The recipe is for 3 dozen cookies as stated above.

If you make 2 dozen cookies, then you are making 2/3 of the recipe since 2 is 2/3 of 3.

That means you need 2/3 of all the ingredients.

2/3 × 3 dozen chocolate chip cookies

2/3 × 3 cups of flour

2/3 × 1 cup of sugar

2/3 × 2 cups of chocolate chips

We simplify the amounts to:

2 dozen chocolate chip cookies

2 cups of flour

2/3 cup of sugar

1 1/3 cups of chocolate chips

Answer:

694.9

Step-by-step explanation:

Answer:

This is your answer 694.931651315437

Have a good day!

Answer:

[tex]X ≤ P(119)  \rightarrow    P(X < 119.5)[/tex]

Step-by-step explanation:

Given:

n = 504

p = 0.27

To Approximate:

P(x≤119) usimg normal distribution

Solution:

We know that,

[tex]p+q = 1\\q = 1-p\\q = 1 - 0.27 \\ \fbox{q = 0.73}[/tex]

let's find the mean,

[tex]n \cdot p = 500 \times 0.27 \\ n \cdot p = 135 \\ \mu \: = 135[/tex]

let's calculate standard deviation,

[tex] \sigma = \: \sqrt {n \cdot p\cdot q} \\ \sigma \: = \sqrt{504 \times 0.27 \times 0.73} \\ \sigma \: = 9.96[/tex]

Rewriting the equation using continuity correction,

[tex]    P(X ≤ n)  \rightarrow    P(X < n + 0.5) \\     P(X ≤ 119)  \rightarrow    P(X < 119 + 0.5) \\     P(X ≤ 119)  \rightarrow    P(X < 119.5) \\ \fbox{x \: = 119.5}[/tex]

Some more things you must need to know,

standard score is an important part of statistics,

can be derived using formula

[tex]Z = \frac{ x - \mu}{ \sigma} \\ Z = \frac{ 119.5 - 135}{ 9.96} \\ Z= \frac{-15.5}{9.96} \\ \fbox{Z= -1.55}[/tex]

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Answer:

The perimeter of an 30 inch wide = 20inches wide bro

Step-by-step explanation:

[tex] {2x}^{3} + 4 {x}^{2} + 8x \\ \\ 2x( {x}^{2} + 2x + 4)[/tex]

Answer:

-18

Step-by-step explanation:

Simplify: |3 – 10| – (12 / 4 + 2)^2

[tex]|3 - 10| - (\frac{12}{4} + 2)^2\\\\|-7|-(\frac{12}{4} + 2)^2 < == absolute\ numbers\ are\ always\ positive\\\\7-(3+2)^2 < ==add\ numbers\ in\ parenthesis\\\\7-5^2 < ==square\ the\ number\ (5)\\\\7-25 < ==add\ numbers\\\\-18 < ==final\ answer[/tex]

Hope this helps!

Answer:

simplify the matrix:

36,−32,−18,3,−6

Answer:

48°

Step-by-step explanation:

Vertically opposite angles are equal. Angle 7 is vertically opposite to angle 5.

Answer:

The measure of angle 7 is 48 degrees

Step-by-step explanation:

Angle 5 and 7 are opposite angles. Opposite angles are congruent.

Answer:

For 3 pounds, 3 ÷ 1/8 = 54

For 7 pounds, 7 ÷ 1/8 = 56

Answer:

Using the hypergeometric distribution, it is found that there is a 0.4286 = 42.86% probability of getting 2 of the same colour.

The marbles are chosen without replacement, hence the hypergeometric distribution is used to solve this question.

What is the hypergeometric distribution formula?

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

There is a total of 3 + 4 = 7 marbles, hence N = 7.

Of those, 3 are blue, hence k = 3.

2 marbles will be taken, hence n = 2.

Step-by-step explanation:

Answer:

30 degrees

Step-by-step explanation:

inscribed angle angle x encompasses   360 - 120 - 180 = 60 degrees of arc

  this is 2 times the measure if the inscribed angle

 angle B = 30 degrees

Answer:

The tan θ and cos θ values of 17π/12 are illustrations of trigonometry ratios

The values of tan θ and cos θ are 2 + √3 and (√2 - √6)/4, respectively

We have:

θ = 17π/12

Express as sum

θ = 9π/12 + 8π/12

Simplify

θ = 3π/4 + 2π/3

The above becomes

tan(17π/12) = tan(3π/4 + 2π/3)

Using the sum formula, we have:

tan(A + B) = [tan(A) + tan(B)]/[1 - tan(A)tan(B)]

Substitute known values

tan(3π/4 + 2π/3) = [tan(3π/4) + tan(2π/3)]/[1 - tan(3π/4)tan(2π/3)]

Evaluate the expression

tan(3π/4 + 2π/3) = [-1 - √3]/[1 - (-1)(-√3)]

Evaluate the product

tan(3π/4 + 2π/3) = [-1 - √3]/[1 - √3]

Rationalize

[tex]tan(\frac{3\pi}4 + \frac{2\pi}3) = \frac{-1 - \sqrt3}{1 - \sqrt3} * \frac{1 + \sqrt3}{1 + \sqrt3}[/tex]

Evaluate the product

[tex]tan(\frac{3\pi}4 + \frac{2\pi}3) = \frac{-(1 + \sqrt3)^2}{1 - 3}[/tex]

This gives

[tex]tan(\frac{3\pi}4 + \frac{2\pi}3) = \frac{-(1 + 3 + 2\sqrt 3)}{-2}[/tex]

[tex]tan(\frac{3\pi}4 + \frac{2\pi}3) = \frac{-(4 + 2\sqrt 3)}{-2}[/tex]

Divide

[tex]tan(\frac{3\pi}4 + \frac{2\pi}3) = 2 + \sqrt 3[/tex]

So, we have:

tan(17π/12) = 2 + √3

We have:

θ = 17π/12

Express as difference

θ = 9π/4 - 5π/6

The above becomes

cos(17π/12) = cos(9π/4 - 5π/6)

Using the difference formula, we have:

cos(A - B) = cos(A)cos(B) + sin(A)sin(B)

So, we have

cos(17π/12) = cos(9π/4)cos(5π/6) + sin(9π/4)sin(5π/6)

Evaluate

[tex]cos(\frac{17\pi}{12}) = \frac{\sqrt 2}{2} * - \frac{\sqrt 3}{2} + \frac{\sqrt 2}{2} * \frac 12[/tex]

Evaluate

[tex]cos(\frac{17\pi}{12}) = \frac{\sqrt 2}{2} (- \frac{\sqrt 3}{2} + \frac 12)[/tex]

Evaluate the difference

[tex]cos(\frac{17\pi}{12}) = \frac{\sqrt 2}{2} (\frac{1 - \sqrt 3}{2})[/tex]

Expand

cos(17π/12) = (√2 - √6)/4

Hence, the values of tan θ and cos θ are 2 + √3 and (√2 - √6)/4, respectively

Read more about trigonometry ratios at:

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Answer:

78.6

Step-by-step explanation:

Area of  circle = Pi*r^2

r=5

for pi use calculator or pi=3.142

area =Pi*r2=(3.142)*5^2=(3.142)*25=78.55 = 78.6 (1 decimal place which is same with tenth)

100x³²

..................

Hope you enjoy  :)))))))

Answer:

1/13

Step-by-step explanation:

There are 2 red 5's in a standard 52-card deck ( a red 5 of hearts and a red 5 of diamonds ) and then there are 2 black 6's in a 52-card deck ( a black 6 of clubs and a black 6 of spades )

So in total there are 4 cards that we want out of 52.

So the probability of getting a red five or a black six is 4/52 or 1/13

Answer:

Step-by-step explanation:

This is an or question. You can choose either one; both are possible and the smaller probability add.

Red 5: 2/52

There are 26 red cards. 2 of them are 5s (diamonds / hearts). You are still drawing from a complete pack of 52

Black 6: 2 / 52

There are 26 black cards. 2 of them are 6s (Clubs / spades). You are still drawing from a complete pack of 52

2/52 + 2/52 = 4/52

Divide top and bottom by 4

4/4 // 52 /4

1 / 13

Answer: 1/13 or 0.077

Answer:

the answer is 1600

Answer:

[tex]y-7=\frac{4}{3} (x+3)[/tex]

Step-by-step explanation:

Hi there!

We are given the point (-3, 7)

We want to write the equation of the line containing that point, in point slope-form, and that is also parallel to 4x-3y=7

Parallel lines contain the same slope

So first, let's find the slope of 4x-3y=7

To do that, we can convert the line from standard form (ax+by=c) to slope-intercept form (y=mx+b, where m is the slope, and b is the y intercept)

To do that, we need to isolate y on one side

So start by subtracting 4x from both sides

4x-3y=7

-4x      -4x

________________

-3y=-4x+7

Divide both sides by -3

y=[tex]\frac{4}{3}x[/tex]- [tex]\frac{7}{3}[/tex]

Since 4/3 is in the place of where m should be, the slope of the line is 4/3

It is also the slope of our new line, which we are trying to find

As stated earlier, we want to write this line in point-slope form, which is [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point

This is where the point we were given earlier comes in. We simply need to substitute our values (of the point and the slope) into the formula to find the equation.

First, with the slope; substitute 4/3 as m in the equation

[tex]y-y_1=\frac{4}{3} (x-x_1)[/tex]

Now substitute -3 as [tex]x_1[/tex] in the equation

[tex]y-y_1=\frac{4}{3} (x--3)[/tex]

We can simplify this to:

[tex]y-y_1=\frac{4}{3} (x+3)[/tex]
Now substitute 7 as [tex]y_1[/tex] into the equation

[tex]y-7=\frac{4}{3} (x+3)[/tex]

Hope this helps!

Answer:

see explanation

Step-by-step explanation:

under a reflection in the y- axis

a point (x, y ) → (- x, y )

applying this rule to the given points , then we obtain

[tex]\left[\begin{array}{ccc}-3&-6&-3\\-3&3&3\\\end{array}\right][/tex]

Prime factorization is the process of finding the prime numbers, which are multiplied together to get the original number

So you can use the factor tree to find the GCF and LCM

The solution is, Prime factorization is the process of finding the prime numbers, which are multiplied together to get the original number

Prime factorization is a process of writing all numbers as a product of primes. So, for example, say if we have something like the number 20. We can break that down into two factors. We can say, “well, that's 4 times 5.” And notice, 5 is a prime number.

here, we have,

we need to explain how prime factorization is useful to find the greatest common factor and least common multiple.

now, we know that,

gcf is: Greatest Common Factor. The highest number that divides exactly into two or more numbers. It is the "greatest" thing for simplifying fractions.

and,

lcm is : LCM denotes the least common factor or multiple of any two or more given integers. For example, L.C.M of 16 and 20 will be 2 x 2 x 2 x 2 x 5 = 80, where 80 is the smallest common multiple for numbers 16 and 20.

so, we have,

Prime factorization is the process of finding the prime numbers, which are multiplied together to get the original number.

So you can use the factor tree to find the GCF and LCM.

Hence, The solution is, Prime factorization is the process of finding the prime numbers, which are multiplied together to get the original number.

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Answer:21%

Step-by-step explanation:21%

Answer:

[tex]\frac{3\sqrt{2}+2\sqrt{3}}{6}[/tex] or [tex]\frac{\sqrt{2}}{2}+\frac{\sqrt{3}}{3}[/tex]

Step-by-step explanation:

[tex]\sin\frac{3\pi}{4}-\tan\frac{5\pi}{6}\\\\\sin\frac{3\pi}{4}-\frac{\sin\frac{5\pi}{6}}{\cos\frac{5\pi}{6}}\\ \\\frac{\sqrt{2}}{2}-\frac{\frac{1}{2} }{-\frac{\sqrt{3}}{2}}\\ \\\frac{\sqrt{2}}{2}+\frac{1}{\sqrt{3}}\\ \\\frac{\sqrt{2}}{2}+\frac{\sqrt{3}}{3}\\ \\\frac{3\sqrt{2}}{6}+\frac{2\sqrt{3}}{6}\\ \\\frac{3\sqrt{2}+2\sqrt{3}}{6}[/tex]

Answer:

The answer is:

B. c¹⁰/d¹⁰