a) 92% Confidence interval: (1027.5,1048.5)
b) Sample size = 100
What is Sample size?
The process of deciding how many observations or replicates to include in a statistical sample is known as sample size determination. Any empirical study with the aim of drawing conclusions about a population from a sample must take into account the sample size as a crucial component.
We are given the following in the question:
Sample mean, = 1038
Sample size, n = 25
Alpha, α = 0.08
Population standard deviation, σ = 30
a) 92% Confidence interval:
[tex]$\mu \pm z_{\text {critical }} \frac{\sigma}{\sqrt{n}}$[/tex]
Putting the values, we get,
[tex]$z_{\text {critical }}$[/tex] at [tex]$\alpha_{0.08}=\pm 1.75$[/tex]
[tex]$1038 \pm 1.75\left(\frac{30}{\sqrt{25}}\right)=1038 \pm 10.5=(1027.5,1048.5)$[/tex]
b) In order to reduce the confidence interval by half, we have to quadruple the sample size.
Thus,
Sample size [tex]$=25 \times 4=100$[/tex]
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4. Two equal weights of 20 N are attached to the ends of a thin string which passes over three smooth pegs in a wall arranged in the form of an equilateral triangle with one side horizontal. Find the tension on each peg.
Answer:
Tension in topmost peg = 40rt(5/3)
Tension in other pegs = 40/rt(3)
Explanation:
Note point: I am taking T as a vector quantity and not scalar.
If the tension in the horizontal pegs is T, then the tension in the topmost peg will be T + T.
Lets find the magnitude of the vector T
|T| = 20/cos 30 can be easily seen by drawing FBD
= 40/rt(3)
Then, tension in topmost peg = rt{1600/3 + 1600/3 + (3200/3)*1/2}
= rt{(3200/3)*(5/2)} = rt(8000/3)
if the samples are 10 cm from the axis if the rotor and the ultracentrifuge spins at 6.6×104 rpm , what is the magnitude of the net force on the rotor due to the unbalanced samples?
The magnitude of the net force on the rotor due to the unbalanced samples is 64.4 N.
What is magnitude of a force?The total amount of forces exerted on an object is referred to as the magnitude of force. The strength of the force increases when all the forces are pulling in the same direction. When forces are exerted on an item from different angles, the force's strength reduces.
If the net force acting on an object is zero, then the object is not accelerating and is in a state that we refer to as equilibrium. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object.
radius r = 12 cm = 12 x 10-2 m
Mass : 10 mg = 10 x 10 -6 kg
angular speed ω = 70,000 rpm = 7330.4 rad/sec
The net force is given by :
F = m ω 2r
Substitute the given values in equation
F = (10 * 10[tex](10 * 10^{-6} kg ) * (7330.4rad / s )^{2} * (12 * 10^{-2} m)[/tex]
F = 64.4 N
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(a) Suppose a blood vessel’s radius is decreased to 89 % of its original value by plaque deposits and the body compensates by increasing the pressure difference along the vessel to keep the flow rate constant. By what factor must the pressure difference increase? (b) If turbulence is created by the obstruction, what additional effect would it have on the flow rate?
a). The pressure along the vessel in order to keep the flow rate at constant is 89 pascal.
b). Turbulence try to decreases flow rate, so that the pressure must need to increase after more to compensate at 89%.
The primary unit of stress is the pascal, described because the stress exerted through a pressure of 1 newton perpendicularly upon a place of 1 rectangular metre. In North America, however, the United States Customary System is preferred.
This is primarily based totally on Imperial devices which includes the pound (lb) and inch (in) or foot (ft). First, the resistance of float is inversely associated with the radius of the pipe. In different words, because the radius increases, there's extra room for the fluid to float through, and consequently the float charge increases.
a). Let x be the radius
then [tex]r_{2}[/tex] = x-89
pressure is inversely proportional to radius so, since pressure is constant there will be no change.
[tex]\frac{p_{2} }{p_{1} } =\frac{r_{1 }}{r_{2} } }\\\\\frac{p_{1} }{p_{1} } = \frac{x }{x-89+p } }\\\\\\1 = \frac{x }{x-89 } }\\\\x-89+P=x\\p=89[/tex]
So, pressure =89 pascal
b). Turbulence try to decreases flow rate, so that the pressure must need to increase after more to compensate at 89%.
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In which graph is acceleration the slope?
A. Distance versus time
B. Acceleration versus time
C. Velocity versus time
D. Position Versus time
The graph of the slope's acceleration depicts velocity vs time.
reveals the solution.
The distance an object has travelled over time is displayed on a distance-time graph.
A straight-line graph of the time versus distance results is shown. The Y-axis displays the distance. The X-axis displays a time plot. Velocity changes occur more quickly on the graph with the sharpest slope.
It picks up speed the fastest. The acceleration of an item is shown by the slope of a velocity graph. As a result, the value of the slope at a particular time determines the item's acceleration at that specific instant.
A moving item is shown by a sloped line on a distance-time graph. The object's speed is equal to the gradient or slope of the line on a distance-time graph.
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a tenn watt heater is used to monatomic ideal gas at a constant pressure of during the process teh volum of gas increases by 23
According to the First law of Thermodynamics, the fraction of heat energy required is 3/5, for monoatomic ideal gas.
What is Ideal gas?An ideal gas is one in which there are no intermolecular attraction forces and all collisions between atoms or molecules are entirely elastic. Three state variables—absolute pressure (P), volume (V), and absolute temperature—can be used to describe an ideal gas (T). Kinetic theory can be used to infer their connection.
What is Thermodynamics?Thermodynamics is the study of changes that take place in a region of the universe that we refer to as the system; the rest of the universe is referred to as the surroundings. The system may be cut off from its environment by a physical or conceptual border.
Calculations:
The percentage of the heat energy given that raises the internal energy of an ideal monoatomic gas when it is heated at constant pressure is:
By the first law of thermodynamics
Q=U+W = f/2nRT+P∫dV= f/2nRT+PV
or Q= f/2nRT+nRT(∵PV=nRT)
= 3/2nRT+nRT= 5/2nRT
∴ Fraction of heat energy supplied = U/Q=
(3/2)nRT/(5/2)nRT = 3/5.
Hence, according to the First law of Thermodynamics, the fraction of heat energy required is 3/5, for monoatomic ideal gas.
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Free-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object in a given situation. A free-body diagram is a special example of the vector diagrams that were discussed in an earlier unit. These diagrams will be used throughout our study of physics. The size of the arrow in a free-body diagram reflects the magnitude of the force. The direction of the arrow shows the direction that the force is acting. Each force arrow in the diagram is labeled to indicate the exact type of force. It is generally customary in a free-body diagram to represent the object by a box and to draw the force arrow from the center of the box outward in the direction that the force is acting. An example of a free-body diagram is shown at the right The free-body diagram above depicts four forces acting upon the object. Objects do not necessarily always have four forces acting upon them. There will be cases in which the number of forces depicted by a free-body diagram will be one, two, or three. There is no hard and fast rule about the number of forces that must be drawn in a free-body diagram. The only rule for drawing free-body diagrams is to depict all the forces that exist for that object in the given situation. Thus, to construct free-body diagrams, it is extremely important to know the various types of forces. If given a description of a physical situation, begin by using your understanding of the force types to identify which forces are present. Then determine the direction in which each force is acting. Finally, draw a box and add arrows for each existing force in the appropriate direction; label each force arrow according to its type. If necessary, refer to the list of forces and their description in order to understand the various force types and their appropriate symbols.
A visual, dematerialized, symbolic depiction of the body (a structure, element, or fragment of an element) in which all connecting "parts" have been eliminated is known as a free-body diagram.
A diagram that changes when the issue is resolved is called a free-body diagram. A free body diagram often includes the following elements:A condensed form of the body (most commonly a box).A coordinate framework.Arrows showing in the direction in which forces operate on the body are used to depict forces.Moments appeared as curved arrows pointing towards the body's acting direction.The specific problem and the presumptions used will determine how many forces are operating on a body. Friction and air resistance are frequently ignored.
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which of the following graphs best predicts the solar energy output in the country in the northern hemisphere in december?
B graphs best predicts the solar energy output in the country in the northern hemisphere in December.
Any form of energy produced by the sun is known as solar energy.
Nuclear fusion occurs in the sun, which is how solar energy is produced. When two hydrogen atoms hit forcefully and combine to form a helium atom at the sun's core, fusion takes place.
This procedure, also referred to as a PP (proton-proton) chain reaction, produces a significant quantity of energy. The sun's core burns around 620 million tons of hydrogen per second. Other stars that like our sun in size experience the PP chain reaction, which supplies them with constant energy and heat. On the Kelvin scale, these stars have a temperature of roughly 4 million degrees (about 4 million degrees Celsius, 7 million degrees Fahrenheit).
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certain minerals are only stable in a small range of temperatures and as such can tell us what temperature the rock metamorphosed at. we call these geothermometry.
Certain minerals are only stable in a small range of temperatures and as such can tell us what temperature the rock metamorphosed at. we call these geothermometry. This statement is false.
The 3 foremost minerals (magnetite, pyrrhotite, and ilmenite) strongly interested in a magnet. Two varieties of rock – serpentine and ironstone are nearly usually magnetic.
As magma or lava cools, those minerals start to shape. At this point, the molten rock has no longer completely solidified, so the magnetic minerals floating inside the molten mass, end up aligned with the magnetic subject.
Water is discovered in interior rocks nearly anywhere, even very deep underneath the earth's floor where it's far particularly warm. The water inside hot rocks may be very warm as well, and when the fluid comes to the earth's floor, it can generate electricity.
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briefly outline the eight trace minerals reviewed in this week's readings, highlighting their primary function in the body and major food sources.
Answer:
college money
Explanation:
The dynamo theory states that Earth's magnetic field is created in the ...
The dynamo theory states that Earth's magnetic field is created in the planet's outer core.
The dynamo theory proposes a mechanism by which a celestial body such as the Earth or a star generates a magnetic field.
Dynamo theory describes the process through which a rotating, convecting and electrically conducting fluid acts to maintain a magnetic field. This theory is used to explain the presence of anomalously long-lived magnetic fields in astrophysical bodies.
There are three requisites for a dynamo to operate:
An electrically conductive fluid medium, Kinetic energy provided by planetary rotation, An internal energy source to drive convective motions within the fluid.
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Use Eq. (9.20) to calculate the moment of inertia of a uniform, solid disk with mass M and radius R for an axis per- pendicular to the plane of the disk and passing through its center
Circular disc's moment of inertia around axis passing through mass and parallel to disc Icm=MR22
Explain about the moment of inertia?The phrase "moment of inertia" in physics refers to the precise calculation of a body's inertia with respect to rotation, or the resistance a body exhibits when a torque is applied to alter its rate of rotation around an axis (turning force).
It is a broad (additive) property: the moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. Because it resists rotational motion, the moment of inertia is referred to as such and not as a moment of force.
Moment of inertia is the propensity of an object to continue rotating at a constant speed or in a condition of rest. More torque is needed to shift this state the higher the moment of inertia.
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Treating the nucleus as a Fermi gas, estimate the time it takes for a typical bound nucleon to cross the nucleus. Now, calculate the time for one revolution of a rigid rotor with j=2, I=5000amu fm2, and A= 208. You may find this helps justify the Nilsson model, where we treat the nucleon as if its orbiting around an essentially stationary rotor.
The time taken for one revolution of a rigid rotor to cross the nucleus is 6,240,000×10⁻¹⁵ sec .
Microwave rotational spectroscopy utilizes microwave radiation to quantify the energies of rotational advances for atoms in the gas stage. It achieves this through the communication of the electric dipole snapshot of the particles with the electromagnetic field of the astonishing microwave photon.
To test the unadulterated rotational advances for particles, researchers use microwave rotational spectroscopy. This spectroscopy uses photons in the microwave reach to cause changes between the quantum rotational energy levels of a gas particle.
We know that time taken to complete one revolution of a rigid rotor is
given by the formula J×(J+1)× B × h
where J is rotational quantum number,
B or I is rotational constant
and h or A is value of atomic mass of the nucleus.
So, on putting we get
=>t=2×(2+1)×5000×208
=>t=2×3×5000×208
=>t=6,240,000fm-sec or
=>t=6,240,000×10⁻¹⁵ sec
Hence, required time is 6.240,000×10⁻¹⁵ sec .
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4. The bar has a mass of 10 kg and is subjected to a couple moment of M=50 N·m and a force of P=80 N, which is always applied perpendicular to the end of the bar. The stiffness of spring is k=30 N/m and its free length is 0.5 m. The spring remains in the vertical position due to the roller guide at B. Determine the total work done by all the force acting on the bar when it has rotated downward from (=0( to 90 (. (15 points)
The total work done by all the force acting on the bar when it has rotated downward from 0 to 90° is 4500 N·m.
Solving for total work done:The total work done by all the forces acting on the bar can be calculated using the equation for work done by a torque and a spring force.
m = 10 kg
M= 50 N·m
P=80 N
k=30 N/m
x₀ = 0.5 m
θ = 90°
The work done by the torque is given by:
work_torque = M * θ
where,
M= the couple moment
θ = theta is the angle of rotation (90 degrees).
The work done by the spring force is given by:
work_spring = 1/2 * k * (x² - x₀²)
where,
k = the spring constant
x = the displacement of the spring
x₀ = the free length of the spring.
Since the spring is in a vertical position due to the roller guide at B, it will not displace and x=x₀=0.5m, and no work done by spring force.
Therefore, the total work done by all the forces acting on the bar is:
work_total = work_torque
M * θ = 50 N·m * 90 degrees
= 4500 N·m
Hence, the total work done by all the force acting on the bar is 4500 N·m when it has rotated downward from 0 to 90°.
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an atomic spectrum contains a line with a wavelength centered at 402 nm . careful measurements show the line is really spread out between 401 and 403 nm . estimate the lifetime of the excited state that produced this line.
The lifetime of the excited state that produced this line is 416.66sec if a wavelength ranges from 401nm and 403nm.
For solving this problem we use Rydberg equation whose formula is given by
v=[(1 / λ₁) -1 / λ₂)]×(h×c)
where v is the frequency of the photon,
λ is the wavelength of the photon
h is plank's constant
and c is the speed of light in vacuum
Since we are given λ₁ ,λ₂ as 401nm and 403nm respectively.Also we know that value of h is 6.6ˣ10⁻³⁴(J-sec)/m and c=3ˣ10⁸m/sec
So,putting all values on above formula,we get
=>v=[(1/401)-(1/403)]ˣ(6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)
=>v=[(403-401) ˣ (6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)] / (401 ˣ 403)ˣ(1/10⁻²⁷)
=>v= [[2 ˣ (6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)] ₓ(1/10⁻²⁷)] ˣ (1 / 401 ˣ 403)
=>v=(39.6 ˣ 10) / 161603
=>v = 396/161603
=>v = 0.0024/sec
We know time period is reverse of frequency, so lifetime span is
=>t=1/v
=>t=1/ (0.0024/sec)
=>t=416.66sec
Hence, lifetime of the excited state is 416.66sec.
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I have multiple voltage sources of different rating like 5V,6V,1V and 20V draw schematic diagram using these sources to power a light of rating 11 volt
Answer:
add molecules
a projectile is fired at an angle of 55 above the horizontal and has a maximum up[ward vertical diusplacement
A projectile being fired at 55 degrees after the magnitude of the horizontal component of the projectile's displacement is 40.2m
Initial velocity of projectile (v) = 35 m/s
Given Angle (θ)= 55°
Estimating, horizontal components of velocity
[tex]v_{x}[/tex] = v cosθ
= 35 cos 55°
= 20.1 m/s
Calculating the horizontal components of displacement after t = 2
d₂ = [tex]v_{x}t[/tex]
= 20.1 x 2
= 40.2 m
Projectile motion refers to the motion of an object or particle that is launched into a gravitational field, such as from the surface of the Earth, and travels along a curved path while only being influenced by gravity. An object that is fired into the air and only reacts to the acceleration of gravity is called a projectile.
The projectile's path is the name for the object's trajectory. A projectile is any object that is sent into space with only gravity acting on it. The primary force affecting a projectile is gravity. This doesn't mean that other forces don't have an impact; it just means that they have a much smaller one compared to gravity.
Note that the full question is:
A projectile is fired at an angle of 55° above the horizontal with an initial speed of 35.0 m/s. What is the magnitude of the horizontal component of the projectile's displacement at the end of 2 s?
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when light strikes a window pane some rays will be reflected back and forth in between the two glass surfaces. why do these reflected rays not produce visible colored interference fringes?
Yes, and the colors you see will now be the colors your eye perceives when you see the wavelengths producing the interference patterns.
In physics, the wavelengths is the length over which a periodic wave repeats or its spatial period. It is the separation between neighboring wave points that correspond to the same phase, such as two adjacent crests, troughs, or zero crossings. It is a property of both traveling waves and standing waves as well as other spatial wave patterns. The spatial frequency is the wavelength's reciprocal. The Greek letter lambda (), which represents wavelength, is frequently used. When describing modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids, the term wavelength is also occasionally used.
Wavelength is inversely related to frequency for a sinusoidal wave flowing at a constant speed.
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The reflected rays of light do not produce visible colored interference fringes in a window because the glass structure of a window pane prevent.
In the case of the window pane, it is true that the light is still reflected on the front and rear surface of the glass. the reflecting medium need to have a thickness that the that is comparable to the wavelength of light. windows are simply too thick. Due to the structure of glass, No Interference. In the case of thin film both reflected rays belong to the same waveform. light striking a film is partially reflected and partially refracted at the top surface. the refracted ray is partially reflected at the bottom.
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based on what we have discussed, which one of the following waves will lose amplitude as it propagates?
The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases.
What is amplitude?
A periodic variable's amplitude is a gauge of its change over a single period. A non-periodic signal's magnitude in relation to a standard value is its amplitude. There are several definitions of amplitude, which are all functions of the size of the disparities between the variable's extreme values.
The change in pressure that a sound wave causes when it is measured at a particular location is related to the amplitude of the wave. If the amplitude rises, the sound is heard as louder; if it falls, the sound is regarded as quieter.
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44Point Question and Brainliest.
two people need to answer or it won't let me give Brainliest.
During WWII Allied forces dropped food on German-occupied, famine-inflicted Netherlands called Operation Manna and Operation Chowhound. Food was dropped in bags from planes flying low (~ 400 ft). There were no parachutes. From a physics perspective imagine the food hitting the ground and how it would be different if parachutes were attached to the bags of food.
In three to five sentences, explain how the real and imagined scenarios falls compare. Include the effects of gravity, mass, and air resistance.
In the real scenario, the bags of food would have been dropped from the planes without parachutes, so they would have fallen to the ground under the force of gravity.
How will the real and imagined situation compare?The food bags would have been dropped from the planes in the real scenario without parachutes, allowing gravity to bring them to the ground. They would have fallen faster because of the acceleration brought on by gravity. Air resistance would have caused the bags to descend a little more slowly as well. Depending on their mass and speed when they hit the ground, they would have impacted with a specific amount of kinetic energy.
The food bags would have been dropped with parachutes attached in the imagined scenario. The bags' descent would have been slowed by the parachutes, lowering the acceleration brought on by gravity. This would have decreased the bags' kinetic energy and speed before they touched the ground. The bags would have encountered air resistance as well, but due to the slower speed, this would have been less noticeable. If the bags had been dropped with parachutes, they would have landed with less force and kinetic energy overall.
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If m1 is 50 kg and has a velocity of 4 m/s, and m2 is 75 kg and has a velocity of -1 m/s, then what would be the final velocity of object 2 if the two objects collide and bounce off of each other and object 1 has a final velocity of -2 m/s?
The final velocity of object 2 is: 3 m/sec
What is the conservation of mass?According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.
According to conservation of mass,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Given that,
m₁ = 50 kg
m₂ = 75 kg
u₁ = 4 m/s
u₂ = -1 m/s
v₁ = -2 m/s
v₂ = ?
Now, putting the values,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)
or, 125 = -100 + 75 v₂
or, 75 v₂ = 225
or, v₂ = 3 m/sec.
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5. A 1500-kg car makes a u-turn with a radius of 25m. If the coefficient of static friction between the tires and the road μs = 0.42, what is the greatest speed the car can have without skidding (m/s)?
The maximum speed of the car was found to be 10.14 ms-1.
Define coefficient of static friction ?
A number that expresses how sticky an object is to its contact surface while it is stationary is known as the coefficient of static friction.
It is the ratio of the normal force imposed on the body to the static friction present between two contact surfaces.
Consider the three categories of dry friction: rolling friction, kinetic friction, and static friction.
Generally speaking, rolling friction and kinetic friction coefficients are lower than the coefficient of static friction.
Because static friction is greater than kinetic friction and rolling friction, this is the case.
This suggests that if an item is immobile, it will take greater effort to start it moving.
Rolling friction often has the least friction since it is greater in kinetic friction than rolling friction.
Fr=μs|n|
g=9.81
Fc=mv^2max/R
mv^2max/R=μsmg
v^2max=μsgR
vmax=√(0.42)(9.81)(25)
=√103.005
vmax =10.14 ms-1
The maximum speed of the car was found to be 10.14 ms-1.
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Wind gusts create ripples on the ocean that have a wavelength of 5.00 cm and propagate at 2.00 m/s. What is their frequency?
The frequency of the wave of the wind gusts is determined as 40 Hz.
What is frequency of a wave?The frequency of a wave is the number of waves that pass a fixed point in a given amount of time. In other words, is the number of cycles completed by a wave in a given time period.
Mathematically, the relationship between frequency, velocity and wavelength of a wave is given as;
v = fλ
f = v / λ
where;
f is the frequency of the wavev is the velocity of the waveλ is the wavelengthf = (2 m/s) / (0.05 m)
f = 40 Hz
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the current i in a long, straight wire is constant and is directed toward the right as in (figure 1). conducting loops a, b, c, and d are moving, in the directions shown, near the wire.
Answer: The directions shown, near the wire is moving anticlockwise
Explanation:
When the current in the wire AB decreases, the magnetic flux linked with the loop (which is out of the page) will decrease. Hence, the current induced in the loop must be anticlockwise to oppose the decrease in magnetic flux.
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A 15.0 kg penguin waddling east at a velocity of 7.0 m/s collides with a stationary 10.0 kg penguin. After the collision the 15.0 kg penguin is traveling at a velocity of 4.2 m/s 20.0o S of E.
a. What is the velocity of the 10.0 kg penguin after collision?
b. is this collision elastic or inelastic?
The velocity of the 10.0kg stationary penguin after collision with a 15.0 kg penguin which has a velocity of 7.0m/s is 4.2m/s and the collision is inelastic.
Whether it is an elastic or nonelastic collision is the momentum of the system will remain the same, which is also known as the law of conservation of momentum
m1v1+m2v2 = m1u1+m2u2
where,
m1 = mass of the first object
m2= mass of the second object
v1= velocity of the first object before the collision
v2=velocity of the second object before the collision
u1=velocity of the first object after collision
u2=velocity of the second object after collision
So,
15×7 +10×0 = 15×4.2 +10×u2
⇒105 = 63 + 10×u2
⇒u2 = 4.2
Since in this whole process the loss of kinetic energy is happening via the form of heat, light, and sound so it is an inelastic collision
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What are the units used to measure mass and weight?; Are mass and weight measured in the same units?; What unit is mass measured in kilograms pounds Newton's?
Kilogram are the units used to measure mass and weight. The same units are used to measure mass and weight. A body's mass can be thought of as a measurement of its amount of matter.
And the SI unit of mass is Kilogram (kg). Weight is a measurement of how much gravity is pulling on a body. Weight is calculated using the method w = mg. Each item in physics has a unit that establishes its common measurement. Consequently, a physical quantity like mass has a unit as well. In International systems, SI, the mass is measured in Kilograms symbolised by symbol kg. Weight in this context is a vector quantity denoted by N and measured in Newton.
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protons having a kinetic energy of 5.20 mev are moving in the positive x-direction and enter a magnetic field of 0.0550 t in the z-direction, out of the plane of the page, and extending from x. 0→x=1m as shown in Fig.
a. Calculate the y-component of the protons' momentum as they leave the magnetic field.
b. Find the angle ϕ between the initial velocity vector of the proton beam and the velocity vector after the beam emerges from the field. Ignore relativistic effects and note that 1eV=1.60×10−19J.
a) The y-component of the protons' momentum as they leave the magnetic field is 8.8 x 10-21 kg m/s
b) The angle ϕ between the initial velocity vector of the proton beam and the velocity vector after the beam emerges from the field is 9.812821°
Since are given with the kinetic energy of 5.20 Mev (8.32X 10^-13J), and a magnetic field of 0.0550 t in the z-direction.From the diagram we can see that, p(Y) =mv sin θ
=> sin θ =1/R , where R = mv/eB
=>sin θ = eB/mv
=>eB= mv sin θ
=> Py(the momentum) = eB =1.60×10−19J*0.0550 = 8.8 x 10-21 kg m/s .In the second case, sin θ = eB/mv, since the kinetic energy is 5.20 Mev
=>1/2 mv² = 5.20 mev = 8.33132e⁻¹⁹
=> v = √(2* 8.33132e-19 / 1.6 x10⁻²¹) = 32.27 m/s²
Now sin φ = eB/mv
=>sin φ = 8.8 x 10-21/ 1.6 x10^-21* 32.27 = 0.17043
=>φ = sin-1(0.17043) = 9.812821°
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Which of the following statement is true of ATP? A. ATP stands for adenosine triphosphate
B. ATP consists of one adenosine atom and three phosphate atoms
C. ATP consists of one adPOenosine atom and two phosphate atoms
D. The breakdown of ATP provides the energy needed to fuel muscle contraction
The one that is accurate is that when the phosphate is broken down into ADP, ATP releases energy.
Does ATP save its energy in glucose form?The energy that cells need is produced through the breakdown of glucose. More energy cannot be stored by ATP molecules than is released by the cells. In actuality, ATP doesn't retain as much energy as a glucose molecule. See the equation in the question; roughly 38 ATP molecules are produced for every glucose molecule.
How does ATP store energy?The cell stores extra energy by reattaching a free phosphate molecule to ADP, converting it back into ATP. This extra energy can come from the breakdown of food that has been ingested or, in the case of plants, energy produced during photosynthesis.
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calculate the acceleration due to gravity on the surface of the sun. you can find the relevant data in appendix c of the text.
Use these uncertainties to estimate the biggest and smallest possible values you could get for gravity:
g (low) = 2h / ( t + Δt )²
g(high) = 2h / ( t - Δt )²
What is a simple definition of gravity?The force that pulls items toward the center of a planet and other entity is called gravity. Each of the planets are kept in orbits around the sun by gravity.
Briefing:First, choose an area where you can dump your small thing. Drop from a height that is sufficient to reduce the relative proportion of time needed to start and stop the stopwatch but not excessive enough to start affecting the outcome due to air resistance One narrative is a decent middle ground.
The fall distance of the object is measured in meters. The entire course uses metric measurements only!
At least twenty times, time the thing falling.
Use the relationship to get the earth's acceleration owing to gravity (derived from calculus))
g = 2h / t2
where t is the median fall time and h is the fall height.
To calculate your random uncertainty, use your spread in t values:
Δt = (largest duration – lowest duration) / 2.
g (low) = 2h / ( t + Δt )²
g (high) = 2h / ( t - Δt )²
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a 31000-kg open railroad car, initially coasting at 0.925 m/s with negligible friction, passes under a hopper that dumps 120000 kg of scrap metal into it.
The final velocity of the loaded freight car is [tex]$0.182 \mathrm{~m} / \mathrm{s}$[/tex].
What is Velocity?
Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time
The mass of freight car, m₁ = 31000-kg
Velocity of freight car, u₁ = 0.925 m/s
Mass of hopper, m₂ = 120000 kg
(a) Let[tex]$v$[/tex] is the final velocity of the loaded freight car. Initial momentum of the car before the dump, [tex]$p_i=31000 \mathrm{~kg} \times 0.925 \mathrm{~m} / \mathrm{s}=28,675 \mathrm{~kg}-\mathrm{m} / \mathrm{s}$[/tex]
Final momentum, [tex]$p_f=(31000 \mathrm{~kg}+ 120000 \mathrm{~kg}) v=1,51,000\mathrm{v}$[/tex]
According to the conservation of momentum,
initial momentum = final momentum
[tex]25500 \mathrm{~kg}-\mathrm{m} / \mathrm{s}=140000 \mathrm{v}$$v=0.182 \mathrm{~m} / \mathrm{s}$[/tex]
So, the final velocity of the loaded freight car is [tex]$0.182 \mathrm{~m} / \mathrm{s}$[/tex].
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A rotating wheel accelerates at a constant rate from an angular speed of 24 rad/s to 36 rad/s in a time interval of 3 s. What is the angle in radians through which the wheel rotates?
The angle in radians through which the wheel rotates is [tex]14207.511^{\circ}[/tex].
What is angular velocity?
In physics, angular velocity or rotational velocity, also known as angular frequency vector, is a pseudovector representation of how fast the angular position or orientation of an object changes with time.
Given
initial angular velocity [tex]$\omega_1=25 \mathrm{rad} / \mathrm{s}$[/tex]
Final Angular velocity [tex]$\omega_2=36 \mathrm{rad} / \mathrm{s}$[/tex]
time interval [tex]$t=3 \mathrm{~s}$[/tex]
using
[tex]$$\begin{aligned}& \omega_2=\omega_1+\alpha t \\& 36=25+2 \\& \alpha=1.5 \mathrm{rad} / \mathrm{s}^2\end{aligned}$$[/tex]
(b)Average angular speed [tex]$\frac{\Delta \theta}{\Delta t}$[/tex]
[tex]$$\begin{aligned}& \theta=\omega_1 t+\frac{1}{2} \alpha t^2 \\& \theta=25 \times 8+\frac{1}{2} \times 1.5 \times 8^2 \\& \theta=200+48=248 \mathrm{rad}\end{aligned}$$[/tex]
average angular speed [tex]$=\frac{\Delta \theta}{\Delta t}$[/tex]
[tex]=\frac{248}{8}=31 \mathrm{rad} / \mathrm{s}$$[/tex]
(c)Angle rotated =248 radians
(d)angles in degree [tex]$=14207.511^{\circ}$[/tex]
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