The main() module in the starter code below takes integar inputs separated by commas from the user and stores them in a list. Then, it allows the user to manipulate the list using 3 functions:
mutate_list() takes 3 parameters -- a list, index number, and a value -- and inserts the value in the position specified by the index number in the list.
remove_index() takes 2 parameters -- a list and an index number -- and remove the element at the position number indicated by index. It also prints the total number of elements in the list before and after removing the character in this fashion:"Total elements in list = 11
Total elements in list = 10"
reverse_list() takes 1 parameter -- a list -- and returns the list reversed.
Examples:
Example 1:
Enter values in list separated by commas: 1,2,4,63,6,4,22,53,76
[1, 2, 4, 63, 6, 4, 22, 53, 76]
Menu:
mutate list(m), remove (r), reverse_list (R)
Enter choice (m,r,R): m
4,45
[1, 2, 4, 63, 45, 6, 4, 22, 53, 76]
Example 2:
Enter values in list separated by commas: 1,2,4,6,84,3,2,2,76
[1, 2, 4, 6, 84, 3, 2, 2, 76]
Menu:
mutate list(m), remove (r), reverse_list (R)
Enter choice (m,r,R): R
[76, 2, 2, 3, 84, 6, 4, 2, 1]
Example 3:
Enter values in list separated by commas: 12,2,3,5,2,6,2,1,2,333,65
[12, 2, 3, 5, 2, 6, 2, 1, 2, 333, 65]
Menu:
mutate list(m), remove (r), reverse_list (R)
Enter choice (m,r,R): r
Example 4
Total elements in list = 11
Total elements in list = 10
[12, 2, 3, 5, 6, 2, 1, 2, 333, 65]
please use the codes below
def main():
user_list = input("Enter values in list separated by commas: ")
user_list = user_list.split(",")
user_list = [int(i) for i in user_list]
print(user_list)
print("Menu: ")
print("mutate list(m), remove (r), reverse_list (R)")
user_choice = input("Enter choice (m,r,R): ")
if user_choice == 'm':
index_num, v = input().split(",")
index_num = int(index_num)
v = int(v)
mutate_list(user_list, index_num, v)
print(user_list)
elif user_choice == 'r':
index_num = int(input())
remove_index(user_list, index_num)
print(user_list)
elif user_choice == 'R':
new_list = reverse_list(user_list)
print(new_list)
main()

Answers

Answer 1

Find the given attachments

The Main() Module In The Starter Code Below Takes Integar Inputs Separated By Commas From The User And
The Main() Module In The Starter Code Below Takes Integar Inputs Separated By Commas From The User And
The Main() Module In The Starter Code Below Takes Integar Inputs Separated By Commas From The User And

Related Questions

a. A programmer wrote a software delay loop that counts the variable (unsigned int counter) from 0 up to 40,000 to create a small delay. If the user wishes to double the delay, can they simply increase the upperbound to 80,000?
b. If the code contains a delay loop and we noticed that no delay is being created at run-time. What should we suspect during debugging?

Answers

Answer:

Explanation:

The objective here is to determine if the programmer can simply increase the upperbound to 80,000.

Of course Yes, The programmer can simply increase the delay by doubling the upperbound by 80000. The representation can be illustrated as:

( int : i = 0;  i <  40,000; i ++ )

{

  // delay code

}

Which can be modified as:

( int : i = 0;  i <  80,000; i ++ )

{

  // delay code

}

b)  If the code contains a delay loop and we noticed that no delay is being created at run-time. What should we suspect during debugging?

Assuming there is no delay being created at the run-time,

The code is illustrated as:

For ( int : i = 0 ; i < 0 ; i ++ )

{

  // delay code which wont

  //execute since code delay is zero

}

we ought to check whether the loop is being satisfied or not.  At the Initial value of loop variable, is there any break or exit statement is being executed in between loop. Thus, the  aforementioned delay loop wont be executed since the loop wont be executed for any value of i.

Part 1: For this assignment, call it assign0 Implement the following library and driver program under assign0: Your library will be consisting of myio.h and myio.c. The function prototypes as well as more explanations are listed in myio.h. Please download it and accordingly implement the exported functions in myio.c. Basically, you are asked to develop a simple I/O library which exports a few functions to simplify the reading of an integer, a double, and more importantly a string (whole line). In contrast to standard I/O functions that can read strings (e.g., scanf with "%s", fgets) into a given static size buffer, your function should read the given input line of characters terminated by a newline character into a dynamically allocated and resized buffer based on the length of the given input line. Also your functions should check for possible errors (e.g., not an integer, not a double, illigal input, no memory etc.) and appropriately handle them. Then write a driver program driver.c that can simply use the functions from myio library. Specifically, your driver program should get four command-line arguments: x y z output_filename. It then prompts/reads x many integers, y many doubles, and z many lines, and prints them into a file called output_filename.txt. Possible errors should be printed on stderr.

myio.h file

/*
* File: myio.h
* Version: 1.0
* -----------------------------------------------------
* This interface provides access to a basic library of
* functions that simplify the reading of input data.
*/

#ifndef _myio_h
#define _myio_h

/*
* Function: ReadInteger
* Usage: i = ReadInteger();
* ------------------------
* ReadInteger reads a line of text from standard input and scans
* it as an integer. The integer value is returned. If an
* integer cannot be scanned or if more characters follow the
* number, the user is given a chance to retry.
*/

int ReadInteger(void);

/*
* Function: ReadDouble
* Usage: x = ReadDouble();
* ---------------------
* ReadDouble reads a line of text from standard input and scans
* it as a double. If the number cannot be scanned or if extra
* characters follow after the number ends, the user is given
* a chance to reenter the value.
*/

double ReadDouble(void);

/*
* Function: ReadLine
* Usage: s = ReadLine();
* ---------------------
* ReadLine reads a line of text from standard input and returns
* the line as a string. The newline character that terminates
* the input is not stored as part of the string.
*/

char *ReadLine(void);

/*
* Function: ReadLine
* Usage: s = ReadLine(infile);
* ----------------------------
* ReadLineFile reads a line of text from the input file and
* returns the line as a string. The newline character
* that terminates the input is not stored as part of the
* string. The ReadLine function returns NULL if infile
* is at the end-of-file position. Actually, above ReadLine();
* can simply be implemented as return(ReadLineFile(stdin)); */

char *ReadLineFile(FILE *infile);

#endif

Answers

Answer:

Explanation:

PROGRAM

main.c

#include <fcntl.h>

#include <stdio.h>

#include <stdlib.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <unistd.h>

#include "myio.h"

int checkInt(char *arg);

int main(int argc, char *argv[]) {

  int doubles, i, ints, lines;

  char newline;

  FILE *out;

  int x, y, z;

  newline = '\n';

  if (argc != 5) {

     printf("Usage is x y z output_filename\n");

     return 0;

  }

  if (checkInt(argv[1]) != 0)

     return 0;

  ints = atoi(argv[1]);

  if (checkInt(argv[2]) != 0)

     return 0;

  doubles = atoi(argv[2]);

  if (checkInt(argv[3]) != 0)

     return 0;

  lines = atoi(argv[3]);

  out = fopen(argv[4], "a");

  if (out == NULL) {

     perror("File could not be opened");

     return 0;

  }

  for (x = 0; x < ints; x++) {

     int n = ReadInteger();

     printf("%d\n", n);

     fprintf(out, "%d\n", n);

  }

  for (y = 0; y < doubles; y++) {

     double d = ReadDouble();

     printf("%lf\n", d);

     fprintf(out, "%lf\n", d);

  }

  for (z = 0; z < lines; z++) {

     char *l = ReadLine();

     printf("%s\n", l);

     fprintf(out, "%s\n", l);

     free(l);

  }

  fclose(out);

  return 0;

}

int checkInt(char *arg) {

  int x;

  x = 0;

  while (arg[x] != '\0') {

     if (arg[x] > '9' || arg[x] < '0') {

        printf("Improper input. x, y, and z must be ints.\n");

        return -1;

     }

     x++;

  }

  return 0;

}

myio.c

#include <limits.h>

#include <stdio.h>

#include <stdlib.h>

#include <unistd.h>

char *ReadInput(int fd) {

  char buf[BUFSIZ];

  int i;

  char *input;

  int r, ret, x;

  i = 1;

  r = 0;

  ret = 1;

  input = calloc(BUFSIZ, sizeof(char));

  while (ret > 0) {

     ret = read(fd, &buf, BUFSIZ);

   

     for (x = 0; x < BUFSIZ; x++) {

        if (buf[x] == '\n' || buf[x] == EOF) {

           ret = -1;

           break;

        }

        input[x*i] = buf[x];

        r++;

     }

   

     i++;

   

     if (ret != -1)

        input = realloc(input, BUFSIZ*i);

  }

  if (r == 0)

     return NULL;

  input[r] = '\0';

  input = realloc(input, r+1);

  return(input);

}

int ReadInteger() {

  char *input;

  int go, num, x;

  go = 0;

  do {

     go = 0;

   

     printf("Input an integer\n");

     input = ReadInput(STDIN_FILENO);

     for (x = 0; x < INT_MAX; x++) {

        if (x == 0&& input[x] == '-')

           continue;

        if (input[x] == 0)

           break;

        else if (input[x]> '9' || input[x] < '0') {

           go = 1;

           printf("Improper input\n");

           break;

        }

    }

  } while (go == 1);

  num = atoi(input);

  free(input);

  return num;

}

double ReadDouble(void) {

  int dec, exp;

  char *input;

  int go;

  double num;

  int x;

  do {

     go = 0;

     dec = 0;

     exp = 0;

   

     printf("Input a double\n");

     input = ReadInput(STDIN_FILENO);

     for (x = 0; x < INT_MAX; x++) {

        if (x == 0&& input[x] == '-')

           continue;

        if (input[x] == 0)

           break;

        else if (input[x] == '.' && dec == 0)

           dec = 1;

        else if (x != 0&& (input[x] == 'e' || input[x] == 'E') && exp == 0) {

           dec = 1;

           exp = 1;

        }

        else if (input[x]> '9' || input[x] < '0') {

           go = 1;

           printf("Improper input\n");

           break;

        }

     }

  } while (go == 1);

  num = strtod(input, NULL);

  free(input);

  return num;

}

char *ReadLine(void) {

  printf("Input a line\n");

  return(ReadInput(STDIN_FILENO));

}

char *ReadLineFile(FILE *infile) {

  int fd;

  fd = fileno(infile);

  return(ReadInput(fd));

}

myio.h

#ifndef _myio_h

#define _myio_h

/*

* Function: ReadInteger

* Usage: i = ReadInteger();

* ------------------------

* ReadInteger reads a line of text from standard input and scans

* it as an integer. The integer value is returned. If an

* integer cannot be scanned or if more characters follow the

* number, the user is given a chance to retry.

*/

int ReadInteger(void);

/*

* Function: ReadDouble

* Usage: x = ReadDouble();

* ---------------------

* ReadDouble reads a line of text from standard input and scans

* it as a double. If the number cannot be scanned or if extra

* characters follow after the number ends, the user is given

* a chance to reenter the value.

*/

double ReadDouble(void);

/*

* Function: ReadLine

* Usage: s = ReadLine();

* ---------------------

* ReadLine reads a line of text from standard input and returns

* the line as a string. The newline character that terminates

* the input is not stored as part of the string.

*/

char *ReadLine(void);

/*

* Function: ReadLine

* Usage: s = ReadLine(infile);

* ----------------------------

* ReadLineFile reads a line of text from the input file and

* returns the line as a string. The newline character

* that terminates the input is not stored as part of the

* string. The ReadLine function returns NULL if infile

* is at the end-of-file position. Actually, above ReadLine();

* can simply be implemented as return(ReadLineFile(stdin)); */

char *ReadLineFile(FILE *infile);

Write a function called unzip that takes as parameter a sequence (list or tuple) called seq of tuples with two elements. The function must return a tuple where the first element is a list with the first members of the seq tuple and the second element is a list with the second members of the seq tuple.
This example clarifies what is required:
Ist =[(1, "one"), (2, "two"), (3, "three")]
tup= unzip(Lst) lst tup
print(tup)
#prints ([1, 2, 3], ['one', two','three'7)

Answers

Answer:

Here is the function unzip:

def unzip(lst):

   result= zip(*lst)

   return list(result)

The complete program in Python is given below:

def unzip(lst):

   result= zip(*lst)

   return list(result)

   

lst =[(1, "one"), (2, "two"), (3, "three")]

tup= unzip(lst)

print(tup)

Explanation:

Here zip() function is used in the unzip function. The return type of zip() function is a zip object. This means the function returns the iterator of tuples. This function can be used as its own inverse by using the * operator.

If you do not want to use zip() function then the above program can also be implemented as following which uses a for loop for elements in the given list (lst). This can make a pair of lists (2 tuple) instead of list of tuples:

def unzip(lst):

   output = ([ a for a,b in lst ], [ b for a,b in lst ])

   return output

   

lst =[(1, "one"), (2, "two"), (3, "three")]  

tup= unzip(lst)  

print(tup)

The programs along with their output are attached.

Consider a recurrent neural network that listens to a audio speech sample, and classifies it according to whose voice it is. What network architecture is the best fit for this problem

Answers

Answer:

Many-to-one (multiple inputs, single output)

Explanation:

Solution

In the case of a recurrent neural network that listens to a audio speech sample, and classifies it according to whose voice it is, the RNN will listen to the audio and will give result by doing classification.

There will be a single output, for the classified or say identified person.

The RNN will take a stream of input as the input is a audio speech sample.

Therefore, there will be multiple inputs to the RNN and a single output, making the best fit Architecture to be of type Many-to-one(multiple inputs, single output).

Write a Java program that reads from the user four grades between 0 and 100. The program the, on separate ines, prints out the entered grades followed by the highest grade, lowest grade, and averages of all four grades. Make sure to properly label your output. Use escape characters to line up the outputs after the labels.

Answers

Answer:

import java.util.*;

public class Grade {

   

   public static void main(String[] args) {

     

       Scanner input = new Scanner(System.in);

       double[] grades =  new double[4];

       

       for (int i=0; i<4; i++){

           System.out.print("Enter a grade: ");

           grades[i] = input.nextDouble();

       }

       

       double lowest = grades[0];

       double highest = grades[0];

       double total = 0;

       

       for (int i=0; i<4; i++){

           System.out.println("Grade " + (i+1) + " is: "  + grades[i]);

           

           if(grades[i] >= highest)

               highest = grades[i];

           if(grades[i] <= lowest)

               lowest = grades[i];

           

           total += grades[i];

           

       }

       double average = total/4;

       

       System.out.println("The highest grade is: " + highest);

       System.out.println("The lowest grade is: " + lowest);

       System.out.println("The average is: " + average);

  }

}

Explanation:

Ask the user for the grades and put them in the grades array using a for loop

Create another for loop. Inside the loop, print the grades. Find highest and lowest grades in the grades array using if-structure. Also, add each grade to the total.

When the loop is done, calculate the average, divide the total by 4.

Print the highest grade, lowest grade and average.

It's inventiveness, uncertainty futuristic ideas typically deal with science and technology.what is it?

Answers

Answer:

Engineering and Science

Explanation:

What program is best for teaching young people code?

Answers

I’d probably say scratch, Its great for young people to learn how to code. Lots of things you can do and make with it.

In this assignment you'll write a program that encrypts the alphabetic letters in a file using the Hill cipher where the Hill matrix can be any size from 2 x 2 up to 9 x 9. The program can be written using one of the following: C, C++, or Java. Your program will take two command line parameters containing the names of the file storing the encryption key and the file to be encrypted. The program must generate output to the console (terminal) screen as specified below.Command Line Parameters1. Your program compile and run from the command line.2. The program executable must be named "hillcipher" (all lowercase, no spaces or file extension).3. Input the required file names as command line parameters. Your program may NOT prompt the user to enter the file names. The first parameter must be the name of the encryption key file, as described below. The second parameter must be the name of the file to be encrypted, as also described below. The sample run command near the end of this document contains an example of how the parameters will be entered.4. Your program should open the two files, echo the input to the screen, make the necessary calculations, and then output the ciphertext to the console (terminal) screen in the format described below.Note: If the plaintext file to be encrypted doesn't have the proper number of alphabetic characters, pad the last block as necessary with the letter 'X'. It is necessary for us to do this so we can know what outputs to expect for our test inputs.

Answers

Answer: Provided in the explanation section

Explanation:

C++ Code

#include<iostream>

#include<fstream>

#include<string>

using namespace std;

// read plain text from file

void readPlaneText(char *file,char *txt,int &size){

  ifstream inp;

 

  inp.open(file);

 

  // index initialize to 0 for first character

 

  int index=0;

  char ch;

 

  if(!inp.fail()){

      // read each character from file  

      while(!inp.eof()){

          inp.get(ch);

          txt[index++]=ch;

      }

  }

 

  // size of message

  size=index-1;

}

// read key

int **readKey(char *file,int **key,int &size){

  ifstream ink;

 

  //

  ink.open(file);

      if(!ink.fail()){

         

          // read first line as size

      ink>>size;

     

      // create 2 d arry

      key=new int*[size];

     

      for(int i=0;i<size;i++){

          key[i]=new int[size];

      }

     

      // read data in 2d matrix

      for(int i=0;i<size;i++){

          for(int j=0;j<size;j++){

              ink>>key[i][j];

          }  

      }

  }

  return key;

}

// print message

void printText(string txt,char *msg,int size){

  cout<<txt<<":\n\n";

 

  for(int i=0;i<size;i++){

      cout<<msg[i];

  }

}

// print key

void printKey(int **key,int size){

  cout<<"\n\nKey matrix:\n\n";

  for(int i=0;i<size;i++){

      for(int j=0;j<size;j++){

          cout<<key[i][j]<<" ";

      }  

      cout<<endl;

  }

}

void encrypt(char *txt,int size,int **key,int kSize,char *ctxt){

  int *data=new int[kSize];

 

  for(int i=0;i<size;i=i+kSize){  

 

  // read key size concecutive data

      for(int a=0;a<kSize;a++){

          data[a]=txt[i+a]-'a';

      }

     

      // cipher operation

      for(int a=0;a<kSize;a++){

          int total=0;

          for(int b=0;b<kSize;b++){

              total+=key[a][b]*data[b];

          }  

          total=total%26;

          ctxt[i+a]=(char)('a'+total);

      }      

  }

}

int main(int argc,char **argv){

  char text[10000];

  char ctext[10000];

  int **key;

  int keySize;

  int size;

  // input

  key=readKey(argv[1],key,keySize);

  readPlaneText(argv[2],text,size);

  encrypt(text,size,key,keySize,ctext);

 

  // output

  printKey(key,keySize);

  cout<<endl<<endl;

  printText("Plaintext",text,size);

  cout<<endl<<endl;

  printText("Ciphertext",ctext,size);

 

  return 0;

}

cheers i hope this helped !!!

You have observed that Alexander Rocco Corporation uses Alika’s Cleaning Company for its janitorial services. The company’s floors are vacuumed and mopped each night, and the trash is collected in large bins placed outside for pickup on Tuesdays and Fridays. You decide to visit the dumpster Thursday evening after the cleaning crew leaves. Wearing surgical gloves and carrying a large plastic sheet, you place as much of the trash on the sheet as possible. Sorting through the material, you find the following items: a company phone directory; a Windows NT training kit; 23 outdated Oracle magazines; notes that appear to be programs written in HTML, containing links to a SQL Server database; 15 company memos from key employees; food wrappers; an empty bottle of expensive vodka; torn copies of several resumes; an unopened box of new business cards; and an old pair of women’s running shoes. Based on this information, write a two-page report explaining the relevance these items have. What recommendations, if any, might you give to Alexander Rocco management?

Answers

Answer:

Explanation:

Relevance of Thrown Items:

   The thrown items mainly consist of the Windows NT training kit, outdated magazines and some written notes, etc. All these things can be used in the company for training the fresh talent.    These things must be used for the purpose of training fresh people and the things like programs written in HTML must not be dumped like this because they consists of the raw code which can be harmful if gotten into wrong hands.    Hence, the information like this must be taken care of seriously as these can be loopholes into companies down.    Rest of the things like food wrappers, empty bottles, resume copies are all worthless to the company and can be thrown into the dump as soon as possible.The business cards must also be thrown if not important.

Recommendation To Management:

   The management must take these things seriously and must double check the company properties before throwing them into dump. There must be a committe build to check the things that are been going directly to the dump.    They must have the responsibility for checking the things before going to the dump and must filter all the important things from the garbage back to the shelves of the office.Hence, these things must be taken care of so that no harm is to be done to the company.

cheers i hope this helped !!

An introduction to object-oriented programming.
Write a GUI program named EggsInteractiveGUI that allows a user to input the number of eggs produced in a month by each of five chickens. Sum the eggs, then display the total in dozens and eggs. For example, a total of 127 eggs is 10 dozen and 7 eggs.

Answers

Answer:

The csharp program is given below.

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;

namespace WindowsFormsApplication1

{

   public partial class Form1 : Form

   {

       public Form1()

       {

           InitializeComponent();

      }

       private void button6_Click(object sender, EventArgs e)

       {

           int total = (Convert.ToInt32(textBox1.Text) +  Convert.ToInt32(textBox2.Text) + Convert.ToInt32(textBox3.Text) + Convert.ToInt32(textBox4.Text) + Convert.ToInt32(textBox5.Text));

           int dozen = total / 12;

           int eggs = total % 12;

           textBox6.Text = dozen.ToString();

           textBox7.Text = eggs.ToString();

       }

       private void button7_Click(object sender, EventArgs e)

       {

           textBox1.Text = "";

           textBox2.Text = "";

           textBox3.Text = "";

           textBox4.Text = "";

           textBox5.Text = "";

           textBox6.Text = "";

           textBox7.Text = "";

       }

        private void button8_Click(object sender, EventArgs e)

       {

           Close();

       }

    }

}

Explanation:

1. The integer variables are declared for total eggs, number of dozens and number of eggs.

2. The input of each text box is converted into integer by using the Convert.ToInt32() method on the value of that particular text box.

3. All the inputs are added and the sum is assigned to variable, total.

4. The number of dozens are obtained by dividing total by 12 and assigning the value to the variable, dozen.

5. The number of extra eggs are obtained by taking the modulus of total and 12 and the value is assigned to the variable, eggs.

6. The integer values in the variables, dozen and eggs, are converted into string using the ToString() function with that particular value.

dozen.ToString();

eggs.ToString();

7. The text boxes are assigned the respective values of dozens and number of eggs.

textBox6.Text = dozen.ToString();

textBox7.Text = eggs.ToString();

8. Two additional buttons, clear and exit, are also added.

9. The clear button erases the contents of all the text boxes. The Text property of each textbox is set to “” thereby clearing all the text fields.

10. The exit button closes the application using Close() function.

11. The program is made in visual studio and the output is attached.

What’s the best way to figure out what wires what and goes where?

Answers

Try to untangle them, First!
Then the color of the wire must match the color hole it goes in (I’m guessing)
I’m not good with electronics so sorry.

Chris wants to view a travel blog her friend just created. Which tool will she use?

HTML
Web browser
Text editor
Application software

Answers

Answer:

i think html

Explanation:

Answer:

Web browser

Explanation:

Numbering exception conditions, which often uses hierarchical numbering, in a fully developed use case description is helpful to _______.​ a. ​ tie the exception condition to a processing step b. ​ show which exception conditions are subordinate to other exceptions c. ​ provide an identifier for each exception condition d. ​ tie exception conditions to other diagrams or descriptions

Answers

Answer:

a) tie the exception condition to a processing step

Explanation:

Numbering exception conditions, in a fully developed use case description is helpful to tie the exception condition to a processing step

The fully developed use case description is useful for the documentation of the context, purpose, description, conditions, and workflow of each use case. Activity diagrams give a graphical image of the use case workflow and serve the purpose of illustrating the alternative paths through a business process.

The Fast Freight Shipping Company charges the following rates for different package weights:
2 pounds or less: $1.50
over 2 pounds but not more than 6 pounds: $3.00
over 6 pounds but not more than 10 pounds: $4.00
over 10 pounds: $4.75
Write a program that asks the user to enter the weight of a package and then displays the shipping charges. The program should also do "Input Validation" that only takes positive input values and show a message "invalid input value!" otherwise.

Answers

Answer:

import java.util.Scanner;

public class ShippingCharge

{

   static double wt_2=1.50;

   static double wt_6=3;

   static double wt_10=4;

   static double wt_more=4.75;

   static double charge;

   static double weight;

public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);

   do

   {

 System.out.print("Enter the weight of the package: ");

 weight = sc.nextDouble();

 if(weight<=0)

     System.out.println("Invalid input value!");

}while(weight<=0);

 if(weight<=2)

    charge=wt_2;

else if(weight<=6 && weight>2)

    charge=wt_6;

else if(weight<=10 && weight>6)

    charge=wt_10;

else

    charge=wt_more;

System.out.println("Shipping charges for the entered weight are $"+charge);

}

}

OUTPUT

Enter the weight of the package: 0

Invalid input value!

Enter the weight of the package: 4

Shipping charges for the entered weight are $3.0

Explanation:

1. The variables to hold all the shipping charges are declared as double and initialized.

   static double wt_2=1.50;

   static double wt_6=3;

   static double wt_10=4;

   static double wt_more=4.75;

2. The variable to hold the user input is declared as double.

   static double charge;

   static double weight;

3. The variable to hold the final shipping charge is also declared as double.  

4. Inside main(), an object of Scanner class is created. This is not declared static since declared inside a static method, main().

Scanner sc = new Scanner(System.in);

5. Inside do-while loop, user input is taken until a valid value is entered.

6. Outside the loop, the final shipping charge is computed using multiple if-else statements.

7. The final shipping charge is then displayed to the user.

8. All the code is written inside class since java is a purely object-oriented language.

9. The object of the class is not created since only a single class is involved.

10. The class having the main() method is declared public.  

11. The program is saved with the same name as that of the class having the main() method.

12. The program will be saved as ShippingCharge.java.

13. All the variables are declared as static since they are declared outside main(), at the class level.

Write a Python program that can compare the unit (perlb) cost of sugar sold in packages with different weights and prices. The program prompts the user to enter the weight and price of package 1, then does the same for package 2, and displays the results to indicate sugar in which package has a better price. It is assumed that the weight of all packages is measured in lb. The program should check to be sure that both the inputs of weight and price are both positive values.

Answers

Answer:

This program is written using python

It uses less comments (See explanation section for more explanation)

Also, see attachments for proper view of the source code

Program starts here

#Prompt user for price of package 1

price1 = int(input("Enter Price 1: "))

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

#Prompt user for weight of package 1

weight1 = int(input("Enter Weight 1: "))

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

#Calculate Unit of Package 1

unit1 = float(price1/weight1)

print("Unit cost of Package 1: "+str(unit1))

#Prompt user for price of package 2

price2 = int(input("Enter Price 2: "))

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

#Prompt user for weight of package 2

weight2 = int(input("Enter Weight 2: "))

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

#Calculate Unit of Package 2

unit2 = float(price2/weight2)

print("Unit cost of Package 2: "+str(unit2))

#Compare units

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Explanation:

price1 = int(input("Enter Price 1: ")) -> This line prompts the user for price of package 1

The following while statement is executed until user inputs a value greater than 1 for price

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

weight1 = int(input("Enter Weight 1: ")) -> This line prompts the user for weight of package 1

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

unit1 = float(price1/weight1) -> This line calculates the unit cost (per weight) of package 1

print("Unit cost of Package 1: "+str(unit1)) -> The unit cost of package 1 is printed using this print statement

price2 = int(input("Enter Price 2: ")) -> This line prompts the user for price of package 2

The following while statement is executed until user inputs a value greater than 1 for price

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

weight2 = int(input("Enter Weight 2: ")) -> This line prompts the user for weight of package 2

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

unit2 = float(price2/weight) -> This line calculates the unit cost (per weight) of package 2

print("Unit cost of Package 2: "+str(unit2)) -> The unit cost of package 2 is printed using this print statement

The following if statements compares and prints which package has a better unit cost

If unit cost of package 1 is greater than that of package 2, then package 1 has a better priceIf unit cost of both packages are equal then they both have the same priceIf unit cost of package 2 is greater than that of package 1, then package 2 has a better price

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the same. Be careful not to index beyond the last element. Ex:
Initial scores: 10, 20, 30, 40
Scores after the loop: 30, 50, 70, 40
The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same.
SAMPLE OUTPUT:
#include
int main(void) {
const int SCORES_SIZE = 4;
int bonusScores[SCORES_SIZE];
int i = 0;
bonusScores[0] = 10;
bonusScores[1] = 20;
bonusScores[2] = 30;
bonusScores[3] = 40;
/* Your solution goes here */
for (i = 0; i < SCORES_SIZE; ++i) {
printf("%d ", bonusScores[i]);
}
printf("\n");
return 0;
}

Answers

Answer:

Replace /* Your solution goes here */  with the following lines of code

for(i = 0;i<SCORES_SIZE-1;i++)

{

bonusScores[i]+=bonusScores[i+1];

}

Explanation:

The above iteration starts from the index element (element at 0) and stops at the second to the last element (last - 1).

Using an iterative variable, i

It adds the current element (element at i) with the next element; element at i + 1.

The full code becomes

#include<iostream>

using namespace std;

int main(void) {

const int SCORES_SIZE = 4;

int bonusScores[SCORES_SIZE];

int i = 0;

bonusScores[0] = 10;

bonusScores[1] = 20;

bonusScores[2] = 30;

bonusScores[3] = 40;

for(i = 0;i<SCORES_SIZE-1;i++)

{

bonusScores[i]+=bonusScores[i+1];

}

/* Your solution goes here */

for (i = 0; i < SCORES_SIZE; ++i) {

printf("%d ", bonusScores[i]);

}

printf("\n");

return 0;

}

See attachment for .cpp file

Answer:int main() {

const int SCORES_SIZE = 4;

int bonusScores[SCORES_SIZE];

int i;

for (i = 0; i < SCORES_SIZE; ++i) {

cin >> bonusScores[i];

}

for (i = 0; i < SCORES_SIZE-1; ++i){

bonusScores[i] += bonusScores[i+1];

}

for (i = 0; i < SCORES_SIZE; ++i) {

cout << bonusScores[i] << " ";

}

cout << endl;

return 0;

}

Explanation: SCORES_SIZE -1 will prevent the for loop from going past the last value in the array. bonusScores[i] += will add the value of bonusScores[i+1] to the original bonusScores[i].

for example, i = 1; 1 < SCORES_SIZE - 1 ; bonusScores[1] += bonusScores[1+1} becomes{ bonusScores[1] + bonusScores{2];

Can you please at least give me some part of the code. At least how to start it in C++. Thank you!
Project 5: You will design and implement various classes and write a program to manage one of the following a bank, a hospital, a library, a business, an organization, etc.) The program must do the following:
1. Allow the initialization of the different attributes of the objects from the keyboard.
2. Allow the initialization of the different attributes from a file
3. Perform calculations on one (or more) of the attributes (e.g. calculateInterest, generateHospitalBill, calculateCheckedBooks, etc.)
4. Output a report of all objects created. The report called for by requirement 4 should output all information about each object. You will need to take advantage of the capabilities of C++ classes, inheritance and overriding.
Program Design:
1. Create at least one base class. All data members have to be private. Your main function and any function that it calls should use the member functions of this class for all transactions.
2. Create at least two derived class of the base class described in the previous point.
3. The program will maintain arrays of objects that interacts with each other to manage the designated establishment (bank, hospital, library, etc.). Please do not use anything more sophisticated than an array.
4. Keep the program simple. I am interested in whether you can demonstrate basic competence in the use of classes, inheritance, and good design.
5. All data members in the classes must be private. This is to assure that you use the C++ capabilities that this assignment is all about. Do not use any global variables.
6. When the user decides to quit the updated information is saved back to the secondary storage to give the user the option to either start fresh or continue where he/she left off at the beginning of the next execution

Answers

Answer:

Explanation:

The objective of this question is to  compute a program  that involve using  a  C++ code for  designing and implementing  a Bank Account Management Simulator with integrated file storage for saving details to secondary storage.

When writing this code I notice the words are more than 5000 maximum number of characters the text editor can contain, so i created a word document for it. The attached file  to the word document can be found below.

Create a program that asks the user to enter grade scores. Use a loop to request each score and add it to a total. Continue accepting scores until the user enters a negative value. Finally, calculate and display the average for the entered scores.

Answers

Answer:

total = 0

count = 0

while(True):

   grade = float(input("Enter a grade: "))

   if grade < 0:

       break

   else:

       total += grade

       count += 1

       

average = total/count

print("The average is: " + str(average))

Explanation:

*The code is in Python.

Initialize the total and count as 0

Create a while loop that iterates until a specific condition is met inside the loop

Inside the loop, ask the user to enter a grade. If the grade is smaller than 0, stop the loop. Otherwise, add the grade to the total and increment the count by 1.

When the loop is done, calculate the average, divide the total by count, and print it

In this challenge you will use the file regex_replace_challenge_student.py to:
Write a regular expression that will replace all occurrences of:
regular-expression
regular:expression
regular&expression
In the string: This is a string to search for a regular expression like regular expression or regular-expression or regular:expression or regular&expression
Assign the regular expression to a variable named pattern
Using the sub() method from the re package substitute all occurrences of the 'pattern' with 'substitution'
Assign the outcome of the sub() method to a variable called replace_result
Output to the console replace_results
Regular Expression Replace Challenge
The Python statement containing the string to search for the regular expression occurrence is below. search_string=’’’This is a string to search for a regular expression like regular expression or regular-expression or regular:expression or regular&expression’’’
Write a regular expression that will find all occurrences of:
a. regular expression
b. regular-expression
c. regular:expression
d. regular&expression in search_string
Assign the regular expression to a variable named pattern
The Python string below is used for substitution substitution="regular expression"
Using the sub() method from the re package substitute all occurrences of the ‘pattern’ with ‘substitution’
Assign the outcome of the sub() method to a variable called replace_result
Output to the console replace_results
import re
#The string to search for the regular expression occurrence (This is provided to the student)
search_string='''This is a string to search for a regular expression like regular expression or
regular-expression or regular:expression or regular&expression'''
#1. Write a regular expression that will find all occurrances of:
# a. regular expression
# b. regular-expression
# c. regular:expression
# d. regular&expression
# in search_string
#2. Assign the regular expression to a variable named pattern
#The string to use for subsitution (This is provided to the student)
substitution="regular expression"
#3. Using the sub() method from the re package substitute all occurrences of the 'pattern' with 'substitution'
#4. Assign the outcome of the sub() method to a variable called replace_result
#5. Output to the console replace_results

Answers

Answer:

Please follow the code indentation for the python program.

Explanation:

Write a program that asks the user to enter either an "African" or a "European" swallow. The programâs behaviour should mimic the program below. If the user enters something øther than "African" or "European", the program shøuld insult the user like the example below.

Sample Output #1:

What kind of swallow?
African
Yes, it could grip it by the husk.

Sample Output #2:

What kind of swallow?
European
A five-ounce bird could not carry a one-pound coconut.

Sample Output #3:

What kind of swallow?
Spanish
You really are not fit to be a king.

Answers

Answer:

The programming language is not stater; However, I'll answer this question using C++.

This program does not use comments (See explanation)

See Attachment for program file

Program starts here

#include <iostream>

using namespace std;

int main()

{

string response;

cout<<"What kind of swallow?\n";

cin>>response;

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

else

{

 cout<<"You really are not fit to be a king.";

}

   return 0;

}

Explanation:

string response; -> A string variable to hold user input is declared

cout<<"What kind of swallow?\n"; -> prompts user for input

cin>>response; -> user input is stored here

The following iteration converts user input to uppercase; so that the program will work for inputs like African, AFRICAN, AFriCAN, etc.

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

The following if statement prints "Yes, it could grip it by the husk." if user input is AFRICAN

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

Otherwise, if user input is EUROPEAN, it prints; "A five-ounce bird could not carry a one-pound coconut."

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

Lastly; for every inputs different from AFRICAN and EUROPEAN, the program displays "You really are not fit to be a king."

else

{

 cout<<"You really are not fit to be a king.";

}

Next, Su wants to explain how the cotton gin separated seeds from cotton. At first, she considers using star bullets for
the steps in this process. But then, she determines that is not the right approach. Which action would most clearly
show the steps in the process in her presentation?
Su should change the type of bullet.
Su should change the size of the bullets.
Su should change the bullets to numbers.
Su should change the color of the bullets.​

Answers

Answer:

change bullets to numbers

Explanation:

100%

Write a function to_pig_latin that converts a word into pig latin, by: Removing the first character from the start of the string, Adding the first character to the end of the string, Adding "ay" to the end of the string. So, for example, this function converts "hello"to "ellohay". Call the function twice to demonstrate the behavior. There is a worked example for this kind of problem.

Answers

Answer:

def to_pig_latin(word):

   new_word = word[1:] + word[0] + "ay"

   return new_word

print(to_pig_latin("hello"))

print(to_pig_latin("latin"))

Explanation:

Create a function called to_pig_latin that takes one parameter, word

Inside the function, create a new_word variable and set it to the characters that are between the second character and the last character (both included) of the word (use slicing) + first character of the word + "ay". Then, return the new_word.

Call the to_pig_latin function twice, first pass the "hello" as parameter, and then pass the "latin" as parameter

Answer:

...huh?

Explanation:

Given main(), define the Team class (in file Team.java). For class method getWinPercentage(), the formula is:teamWins / (teamWins + teamLosses)Note: Use casting to prevent integer division.Ex: If the input is:Ravens133 where Ravens is the team's name, 13 is number of team wins, and 3 is the number of team losses, the output is:Congratulations, Team Ravens has a winning average!If the input is Angels 80 82, the output is:Team Angels has a losing average.Here is class WinningTeam:import java.util.Scanner;public class WinningTeam {public static void main(String[] args) {Scanner scnr = new Scanner(System.in);Team team = new Team();String name = scnr.next();int wins = scnr.nextInt();int losses = scnr.nextInt();team.setTeamName(name);team.setTeamWins(wins);team.setTeamLosses(losses);if (team.getWinPercentage() >= 0.5) {System.out.println("Congratulations, Team " + team.getTeamName() +" has a winning average!");}else {System.out.println("Team " + team.getTeamName() +" has a losing average.");}}}

Answers

Answer:

Explanation:

public class Team {

   private String teamName;

   private int teamWins;

   private int teamLosses;

   public String getTeamName() {

       return teamName;

   }

   public void setTeamName(String teamName) {

       this.teamName = teamName;

   }

   public int getTeamWins() {

       return teamWins;

   }

   public void setTeamWins(int teamWins) {

       this.teamWins = teamWins;

   }

   public int getTeamLosses() {

       return teamLosses;

   }

   public void setTeamLosses(int teamLosses) {

       this.teamLosses = teamLosses;

   }

   public double getWinPercentage() {

       return teamWins / (double) (teamWins + teamLosses);

   }

}

Following are the Java program to define the Team class and calculate its  value:

Class Definition:

class Team //defining the class Team

{

   private String teamName;//defining String variable

   private int teamWins, teamLosses;//defining integer variable

   //defining the set method to set value the input value

   public void setTeamName(String teamName)//defining setTeamName method that takes one String parameter

   {

       this.teamName = teamName;//using this keyword that sets value in teamName

   }

   public void setTeamWins(int teamWins) //defining setTeamWins method that takes one integer parameter

   {

       this.teamWins = teamWins;//using this keyword that sets value in teamWins

   }

   public void setTeamLosses(int teamLosses)//defining setTeamLosses method that takes one integer parameter

   {

       this.teamLosses = teamLosses;//using this keyword that sets value in teamLosses

   }

   //defining the get method that returns the input value

   public String getTeamName() //defining getTeamName method

   {

       return teamName;//return teamName value

   }

   public int getTeamWins()  //defining getTeamWins method

   {

       return teamWins;//return teamWins value

   }

   public int getTeamLosses() //defining getTeamLosses method

   {

       return teamLosses;//return teamLosses value

   }

   public double getWinPercentage()//defining getWinPercentage method

   {              

       return ((teamWins * 1.0) / (teamWins + teamLosses));//using the return keyword that returns percentage value

   }      

}

Please find the complete code in the attached file and its output file in the attached file.

Class definition:

Defining the class "Team".Inside the class two integer variable "teamWins, teamLosses" and one string variable "teamName" is declared.In the next step, the get and set method is defined, in which the set method is used to set the value, and the get method is used to return the value.

Find out more about the Class here:

brainly.com/question/17001900

You have recently resolved a problem in which a user could not print to a particular shared printer by upgrading her workstation's client software. Which of the following might be an unintended consequence of your solution?

a. The user complains that word-processing files on her hard disk take longer to open.
b. The user is no longer able to log on to the network.
c. The shared printer no longer allows users to print double-sided documents.
d. The shared printer no longer responds to form-feed commands from the print server.

Answers

Answer:

B - The user is no longer able to log on to the network

Explanation:

Consider the following skeletal C-like program:
void fun1(void); /* prototype */
void fun2(void); /* prototype */
void fun3(void); /* prototype */
void main() {
int a, b, c;
. . .
}
void fun1(void) {
int b, c, d;
. . .
}
void fun2(void) {
int c, d, e;
. . .
}
void fun3(void) {
int d, e, f;
. . .
}
Given the following calling sequences and assuming that dynamic scoping is used, what variables are visible during execution of the last function called? Include with each visible variable the name of the function in which it was defined
a. main calls funl; funl calls fun2; fun2 calls fun3
b. main calls fun1; fun1 calls fun3
c. main calls fun2; fun2 calls fun3; fun3 calls funl
d. main calls fun1; funl calls fun3; fun3 calls fun2.

Answers

Answer:

In dynamic scoping the current block is searched by the compiler and then all calling functions consecutively e.g. if a function a() calls a separately defined function b() then b() does have access to the local variables of a(). The visible variables with the name of the function in which it was defined are given below.

Explanation:

a. main calls fun1; fun1 calls fun2; fun2 calls fun3

Solution:

Visible Variable:  d, e, f         Defined in: fun3Visible Variable: c                  Defined in: fun2 ( the variables d and e of fun2 are not visible)Visible Variable: b                  Defined in: fun1 ( c and d of func1 are hidden)Visible Variable: a                  Defined in: main (b,c are hidden)

b. main calls fun1; fun1 calls fun3

Solution:

Visible Variable:  d, e, f          Defined in: fun3 Visible Variable:  b, c              Defined in: fun1 (d not visible)Visible Variable:  a                 Defined in: main ( b and c not visible)

c. main calls fun2; fun2 calls fun3; fun3 calls fun1

Solution:

Visible Variable:  b, c, d         Defined in: fun1 Visible Variable:  e, f              Defined in: fun3 ( d not visible)Visible Variable:  a                 Defined in: main ( b and c not visible)

Here variables c, d and e of fun2 are not visible .

d. main calls fun1; fun1 calls fun3; fun3 calls fun2

Solution:

Visible Variable: c, d, e        Defined in: fun2Visible Variable:  f                Defined in: fun3 ( d and e not visible)Visible Variable:  b              Defined in: fun1 ( c and d not visible)Visible Variable: a                Defined in: main ( b and c not visible)

Write a program in python that can compare the unit (perlb) cost of sugar sold in packages with different weights and prices. The program prompts the user to enter the weight and price of package 1, then does the same for package 2, and displays the results to indicate sugar in which package has a better price. It is assumed that the weight of all packages is measured in lb. The program should check to be sure that both the inputs of weight and price are both positive values.

Answers

Answer:

weight1 = float(input("Enter the weight of first package: "))

price1 = float(input("Enter the price of first package: "))

weight2 = float(input("Enter the weight of second package: "))

price2 = float(input("Enter the price of second package: "))

if weight1 > 0 and price1 > 0 and weight2 > 0 and price2 > 0:

   unit_cost1 = price1 / weight1

   unit_cost2 = price2 / weight2

   

   if unit_cost1 < unit_cost2:

       print("Package 1 has a better price.")

   else:

       print("Package 2 has a better price.")

else:

   print("All the entered values must be positive!")

Explanation:

*The code is in Python.

Ask the user to enter the weight and the price of the packages

Check if the all the values are greater than 0. If they are, calculate the unit price of the packages, divide the prices by weights. Then, compare the unit prices. The package with a smaller unit price has a better price.

If all the entered values are not greater than 0, print a warning message

If you were required to give a speech identifying the risks of using computers and digital devices, which group of items would you include?

Answers

Camera and Mic

These 2 things are the most likely things to get you in trouble. Unless you have a 100% protected device, and honestly even if you do, cover up the camera and close your mic. This will definitely save you later.

Larry sees someone he finds annoying walking toward him. Larry purposely looks away and tries to engage in conversation with someone else. Which type of eye behavior is Larry using?
a. mutual lookingb. one-sided lookingc. gaze aversiond. civil inattentione. staring

Answers

Answer:

one-sided looking

Explanation:

Larry purposely looks away

Assume passwords are selected from four character combinations of 26 lower case alphabetic characters. Assume an adversary is able to attempt passwords at a rate of 1 per second. Assuming feedback to the adversary flagging an error as each incorrect character is entered, what is the expected time to discover the correct password

Answers

Answer:

Given:

Passwords are selected from 4 characters.

Character combinations are 26 lower case alphabetic characters.

Passwords attempts by adversary is at rate of 1 second.

To find:

Expected time to discover the correct password

Explanation:

Solution:

4 character combinations of 26 alphabetic characters at the rate of one attempt at every 1 second = 26 * 4 = 104

So 104 seconds is the time to discover the correct password. However this is the worst case scenario when adversary has to go through every possible combination. An average time or expected time to discover the correct password is:

13 * 4 = 52

You can also write it as 104 / 2 = 52 to discover the correct password. This is when at least half of the password attempts seem to be correct.

What did Aristotle teach?

Answers

Philosophy, I beleive. He tought Sikander liturature and eloquence, but his most famous teachings were of philosophy.

Aristotle taught the world science. He was considered the best scientists of his time.

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