Answer:
0.0244 = 2.44% probability that the mean of the sample would differ from the population mean by greater than 3.4 watts.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of 102, standard deviation of 12:
This means that [tex]\mu = 102, \sigma = 12[/tex]
Sample of 63:
This means that [tex]n = 63, s = \frac{12}{\sqrt{63}}[/tex]
What is the probability that the mean of the sample would differ from the population mean by greater than 3.4 watts?
Below 102 - 3.4 = 98.6 or above 102 + 3.4 = 105.4. Since the normal distribution is symmetric, these probabilities are equal, and thus, we find one of them and multiply by two.
Probability the mean is below 98.6.
p-value of Z when X = 98.6. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{98.6 - 102}{\frac{12}{\sqrt{63}}}[/tex]
[tex]Z = -2.25[/tex]
[tex]Z = -2.25[/tex] has a p-value of 0.0122.
2*0.0122 = 0.0244
0.0244 = 2.44% probability that the mean of the sample would differ from the population mean by greater than 3.4 watts.
You have collected data about the average response time of participants in your study. You are delighted to find that the variable is normally distributed. More than half your respondents take longer than 16 seconds to respond and one third take less than 12 seconds to respond. What is the median response time of your participants
Answer:
15
Step-by-step explanation:
It's 15 because it would be the median (middle) between 16 and 12 if there was more variability in 16 seconds.
Can somebody help me
Answer:
The x interceprs are (-3,0) and (2,0)
Step-by-step explanation:
The reason is that when you plug in a -3 in the left parentheses it would become 0, and any number times 0 would be zero, making the equation equal to zero. The same would be true for the terms in the right parentheses, plugging in a two would make it equal to zero. This would make the entire equation equal to zero, finding you the x intercepts.
Nine Increased by the product of a number and 4 is greater than or equal to -15
Use the variable y for the unknown number
Answer:
9+4y ≥ -15
y ≥ -6
Step-by-step explanation:
Nine Increased by the product of a number
9+4y
is greater than or equal to -15
9+4y ≥ -15
Subtract 9 from each side
9-9+4y ≥ -15-9
4y ≥ -24
Divide by 4
4y/4 ≥ -24/4
y ≥ -6
Three children have some marbles.
Shireen has m marbles.
Nazaneen has three times as many marbles as Shireen.
Karly has 4 more marbles than Shireen.
(a) Write down an expression, in terms of m, for
(i) the number of marbles Nazaneen has,
Here we want to create algebraic expressions for different quantities.
i) Nazaneen has 3*m marbles.
ii) Karly has m + 4 marbles.
a) The given data is:
Shireen has m marbles.
Nazaneen has three times as many marbles as Shireen.
Knowing that Shireen has m marbles, we can conclude that Nazaneen has:
3*m marbles.
Karly has 4 more marbles than Shireen, then Karly has m + 4 marbles.
Then the equations for the number of marbles that each one has are:
Shireen = m
i) Nazaneen has 3*m marbles.
ii) Karly has m + 4 marbles.
If you want to learn more, you can read:
https://brainly.com/question/24327241
solve on calculator 6x+8-8x=-8
Answer:
x = 8
Step-by-step explanation:
6x + 8 - 8x = -8
-2x + 8 = -8
-2x = -8 - 8
-2x = -16
x = 8
Cahrlotte is 19/5 YEARS YONGER THAN RACHEL. 2 YEARS LATER, RACHEL WILL BE THRICE AS OLD AS CHARLOTTE. FIND THEIR AGES SFTER 3 YEARS. (ESTAMATE THE AGE TO THE NEAREST WHOLE NUMBER).
Answer:
Step-by-step explanation:
Charlotte starts at 19 years old.
Rachel starts at 24 years old.
Then two years later, Rachel is 26 and Charlotte is 21. This is not 3 times Charlotte's age.
Do you have all the right info?
A zookeeper published the following stem-and-leaf plot showing the number of lizards at each major zoo in the country:
∣
0
1
2
3
4
5
6
∣
0
6
8
8
8
0
2
6
6
7
8
1
2
6
6
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
00
10
20
30
40
50
60
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
0
0
0
0
1
0
0
6
2
2
8
6
6
8
6
6
8
7
0
0
8
0
Key:
2
∣
0
=
20
2∣0=202, vertical bar, 0, equals, 20 lizards
How many zoos have more than 26 lizards
How to change unit from feet to cm
to change unit from feet to cm just divide the length value by 30.48......
can somboby help me please
Answer:
x = 8
Step-by-step explanation:
The question had specified that x is equal to 8.
x=8
explanationsplease mark this answer as brainlist
Am I right? Please help me out
Answer:
[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]
Step-by-step explanation:
Given
[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]
Required
Determine [tex]\cos(\theta)[/tex]
We have:
[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]
Split
[tex]\tan(\theta) = -\frac{\sqrt{19}}{\sqrt{17}}[/tex]
tan is calculated as:
[tex]\tan(theta) = \frac{opposite}{adjacent}[/tex]
So:
[tex]Opposite = -\sqrt{19[/tex]
[tex]Adjacent = \sqrt{17[/tex]
And:
[tex]Hypotenuse^2 = Opposite^2 + Adjacent^2[/tex] --- Pythagoras theorem
[tex]Hypotenuse^2 = (-\sqrt{19})^2 + (\sqrt{17})^2[/tex]
[tex]Hypotenuse^2 = 19 + 17[/tex]
[tex]Hypotenuse^2 = 36[/tex]
Take square roots
[tex]Hypotenuse = 6[/tex]
[tex]\cos(\theta) = \frac{Adjacent}{Hypotenuse}[/tex]
[tex]\cos(\theta) = \frac{\sqrt{17}}{6}[/tex]
Since it is in the second quadrant, then:
[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]
There is 60% chance of making $12,000, 10% chance of breaking even and 30% chance of losing $6,200. What is the expected value of the purchase?
Answer:
$5,340
Step-by-step explanation:
Given :
Making a probability distribution :
X : ___12000 ____0 _____-6200
P(X) __ 0.6 _____ 0.1 _____ 0.3
Tge expected value of the purchase si equal to the expected value or average, E(X) :
E(X) = ΣX*p(X)
E(X) = (12000 * 0.6) + (0 * 0.1) + (-6200 * 0.3)
E(X) = 7200 + 0 - 1860
E(X) = $5,340
What is the slope-intercept equation of the line below?
Answer:
y=-5/4x+3
Step-by-step explanation:
y=mx+c
m = (y1-y2)/(x1-x2) =(-2-3)/(4-0) =-5/4
sub the values y=3, x=0 to find c,
3 =-5/4(0) + c
c = 3
square root of v-5=6
[tex] \sqrt{x - 5 = 6}[/tex]
Answer:
I think you mean this :
[tex] \sqrt{x - 5} = 6 \\ = > {( \sqrt{x - 5} })^{2} = {6}^{2} \\ = > x - 5 = 36 \\ = > x = 36 + 5 \\ = > x = 41[/tex]
Or,
Square root of x-5=6 is :
[tex] \sqrt{x - 5} \:=\:\sqrt{6} [/tex]
The slope of the line containing the points (-5, 3) and (-2, 1) is ________.
Answer:
-2/3
Step-by-step explanation:
We can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( 1-3)/(-2 - -5)
= (1-3)/(-2+5)
= -2/3
write your answer as an integer or as a decimal rounded to the nearest tenth
Answer:
123456-6-&55674
Step-by-step explanation:
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dgjjjdeasg JJ is Redding off in grad wassup I TV kitten gag ex TV ex raisin see
recall see
Please help me with this, But I can’t decide if it’s A or B. Please explain !!!
I think it's the letter A.
Answer:
[tex]m=\frac{M}{\sqrt{1-\frac{v^{2} }{c^{2} } } } \\\\\\m{\sqrt{1-\frac{v^{2} }{c^{2} } }=M[/tex]
[tex]\sqrt{1-\frac{v^{2} }{c^{2} }} =\frac{M}{m} \\\\\\1-\frac{v^{2} }{c^{2} }=\frac{M^{2}}{m^{2}} \\\\\\-\frac{v^{2} }{c^{2} }=\frac{M^{2}}{m^{2}} -1\\\\v^{2}=(-c^{2}) (\frac{M^{2}}{m^{2}} -1)\\\\v=\sqrt{(-c^{2}) (\frac{M^{2}}{m^{2}} -1)} =\sqrt{(c^{2})(-1)(\frac{M^{2}}{m^{2}} -1)} =c\sqrt{(-1)(\frac{M^{2}}{m^{2}} -1)} =c\sqrt{1-\frac{M^{2}}{m^{2}}}[/tex]
I would think it's A ¯\_ (ツ)_/¯
HELP PLEASE!!!
Oak wilt is a fungal disease that infects oak trees. Scientists have discovered that a single tree in a small forest is infected with oak wilt. They determined that they can use this exponential model to predict the number of trees that will be infected after t years.
f(t)=e^0.4t
Question:
Rewrite the exponential model as a logarithmic model that calculates the # of years, g(x) for the number of infected trees to reach a value of x.
The logarithmic model is:
[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]
-------------
We are given an exponential function, for the amount of infected trees f(x) after x years.To find the amount years needed for the number of infected trees to reach x, we find the inverse function, applying the natural logarithm.-------------
The original function is:
[tex]y = f(x) = e^{0.4x}[/tex]
To find the inverse function, first, we exchange y and x, so:
[tex]e^{0.4y} = x[/tex]
Now, we have to isolate y, and we start applying the natural logarithm to both sides of the equality. So
[tex]\ln{e^{0.4y}} = \ln{x}[/tex]
[tex]0.4y = \ln{x}[/tex]
[tex]y = \frac{\ln{x}}{0.4}[/tex]
Thus, the logarithmic model is:
[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]
A similar question is given at https://brainly.com/question/24290183
(b) Two isosceles triangles PQR and PQS are drawn on opposite sides.
of a common base PQ. If PQR = 66° and PSQ = 109°, calculate
the value of RQS.
9514 1404 393
Answer:
101.5°
Step-by-step explanation:
Angle PQS will be the complement of half of angle PSQ, so is ...
∠PQS = 90° -109/2° = 35.5°
Angle RQS is the sum of angles RQP and PQS:
∠RQS = 66° +35.5° = 101.5°
Solve triangles: angle bisector theorem
DAC = BAD.
What is the length of CD?
Round to one decimal place.
Answer:
Step-by-step explanation:
CD/6.5 = 2.6/4.9 This is the result of the angle bisector theorem.
The theorem basically says that the side opposite the angle being bisected is divided the ratio of the sides enclosing the angle.
Multiply both sides of the proportion by 6.5
CD = 2.6 * 6.5 / 4.9
CD = 3.4489
CD = 3.4 rounded.
Suppose the discrete random variable X has the probability distribution below:
X 0 1 2 3 4
P(X) 0.11 0.52 0.19 0.12 0.06
1pt a right parenthesis space F i n d space P left parenthesis X less than 3 right parenthesis
2pt b right parenthesis space F i n d space P left parenthesis X greater or equal than 1 right parenthesis
2pt c right parenthesis space F i n d space mu subscript X
2pt, 1pt d right parenthesis space F i n d space sigma subscript X squared space a n d space sigma subscript X
(a) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.11 + 0.52 + 0.19 = 0.82
(b) P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.52 + 0.19 + 0.12 + 0.06 = 0.89
(c) µ = 0×0.11 + 1×0.52 + 2×0.19 + 3×0.12 + 4×0.06 = 1.5
(d) σ² = (0²×0.11 + 1²×0.52 + 2²×0.19 + 3²×0.12 + 4²×0.06) - µ² = 1.07
σ = √(σ²) ≈ 1.03
Which expression is equivalent to the given expression?
Answer:
a³b
Step-by-step explanation:
(ab²)³/b⁵
= a³b⁶/b⁵
= a³b
Wayne has a rectangular painting. The width of the painting is
5/6
of a foot, and the length is
3/4
of a foot. What is the area of the painting?
Answer:
5/8 ft^2
Step-by-step explanation:
The area of a rectangle is given by
A = l*w where l is the length and w is the width
A = 5/6 * 3/4
A = 3/6 * 5/4
A = 1/2 * 5/4
A = 5/8 ft^2
Ivan invests $5,000 into an account with a 3.5% interest that is compounded semi-annually.
How much money will he have in this account if he keeps it for 15 years?
9514 1404 393
Answer:
$8414
Step-by-step explanation:
The compound interest formula is useful for this.
A = P(1 +r/n)^(nt)
where P is the principal invested at annual rate r compounded n times per year for t years. A is the ending balance.
A = $5000(1 +0.035/2)^(2·15) = $5000·1.0175^30 ≈ $8414.00
Ivan will have $8414 in his account after 15 years.
Fisk Corporation is trying to improve its inventory control system and has installed an online computer at its retail stores. Fisk anticipates sales of 84,500 units per year, an ordering cost of $12 per order, and carrying costs of $1.20 per unit.
Required:
a.What is the economic ordering quantity?
b. How many orders will be placed during the year?
c. What will the average inventory be?
d. What is the total cost of ordering and carrying inventory?
Answer: A) Economic ordering quantity ==$1,300
B)Orders placed during the year= 65 orders
C)average inventory= 650units
D)total cost of ordering and carrying inventory= $1,560
Step-by-step explanation:
A) Economic ordering quantity =[tex]\sqrt{2 x Annual demand x ordering cost /carrying cost}[/tex]
=[tex]\sqrt{2 x 84,500 x 12} /1.20[/tex]
=[tex]\sqrt{1,690,000}[/tex]
=$1,300
B)Orders placed during the year= Annual demand ÷ economic order quantity
= $84,500 ÷ 1,300 units
= 65 orders
C)average inventory= Economic order quantity ÷ 2
= 1,300 units ÷ 2
=650units
D)total cost of ordering and carrying inventory
Ordering cost = Number of orders × ordering cost per order
= 65 orders × $12
= $780
Carrying cost = average inventory × carrying cost per unit
= 650 units × $1.20
= $780
The total would be = $780 + $780 = $1,560
The principle
P=6000 A=6810 T=3 years
Answer:
incomplete question
Step-by-step explanation:
that is what is wrong with your question
Answer:
r = 4.3%
Step-by-step explanation:
6810= 6000(x)^3
6810/6000= (x)^3
x = 1.043114431
r = 043114431
Which of the following integrals represents the volume of the solid obtained by rotating the region bounded by the curves y = (x - 2)^4 and 8x - y =16 about the line x= 10?
A. Pi integral^4_2 {[10 - (1/8 y + 2)^2] - [10 - (2 + ^4 squareroot y)^2]} dy
B. Pi integral^16_0 {[10 - (1/8 y + 2)] - [10 - (2 + ^4 Squareroot)]}^2 dy
C. Pi integral^4_2 {[10 - (1/8 y + 2)] - [10 - 2 + ^4 squareroot y)]}^2 dy
D.Pi integral^16_0 {[10 - (1/8 y + 2)]^2 - [10 - 2 + ^4 squareroot y)]^2} dy
E. Pi integral^16_0 {[10 - (1/8 y + 2)^2] - [10 - 2 + ^4 squareroot y)^2]} dy
F. Pi integral^4_2 {[10 - (1/8 y + 2)]^2 - [10 - 2 + ^4 squareroot y)]^2} dy
Answer:
[tex]\displaystyle V = \pi \int _0^{16}\left[10-\left(\frac{1}{8}y-2\right)\right] ^2 - \left[10 - \left(2+y^{{}^{1}\!/\!{}_{4}}\right)\right]^2\, dy[/tex]
Step-by-step explanation:
We want to find the volume of the solid obtained by rotating the region between the two curves:
[tex]y=(x-2)^4\text{ and } 8x-y=16[/tex]
About the line x = 16.
Since our axis of revolution is vertical, we can use the washer method in terms of y.
[tex]\displaystyle V = \pi \int _c^d[R(y)]^2 -[r(y)}]^2\, dy[/tex]
Where R(y) is the outer radius and r(y) is the inner radius.
First, solve each equation in terms of y:
[tex]\displaystyle x_1 = \frac{1}{8}y+2\text{ and } x_2 = y^{{}^{1}\! /\! {}_{4}}+2[/tex]
From the diagram below, we can see that the outer radius R(y) is (10 - x₁) and that the inner radius r(y) is (10 - x₂). The limits of integration will be from y = 0 to y = 16. Substitute:
[tex]\displaystyle V = \pi \int_0^{16}\left[\underbrace{10-\left(\frac{1}{8}y+2\right)}_{R(y)}\right]^2 - \left[\underbrace{10-\left(y^{{}^{1}\!/\!{}_{4}}+2\right)}_{r(y)}\right]^2\, dy[/tex]
Thus, our volume is:
[tex]\displaystyle V = \pi \int _0^{16}\left[10-\left(\frac{1}{8}y-2\right)\right] ^2 - \left[10 - \left(2+y^{{}^{1}\!/\!{}_{4}}\right)\right]^2\, dy[/tex]
*I labeled the diagram incorrectly. Let R(x) be R(y) and r(x) be r(y).
Help please if you know, thanks
Answer:
xsqrt(2)
Step-by-step explanation:
sqrt(a) / sqrt(b) = sqrt(a/b)
sqrt(22x^6) / sqrt(11x^4)
sqrt(22x^6/11x^4)
sqrt(2x^2)
We know sqrt(ab) = sqrt(a) sqrt(b)
sqrt(x^2) sqrt(2)
xsqrt(2)
A ball is thrown from an initial height of
1 meter with an initial upward velocity of
1 m/s. The ball's height h
(in meters) after t
seconds is given by the following. h=1+30t-5t^2
Find all values of t
for which the ball's height is 11
meters.
Round your answer(s) to the nearest hundredth.
Answer:
Step-by-step explanation:
If we are looking for the times that the ball was 11 meters off the ground, we sub in 11 for the height on the left and solve for t:
[tex]11=-5t^2+30t+1[/tex] and
[tex]0=-5t^2+30t-10[/tex] and factor this however it is you are factoring in class to solve for t to get
t = .35 seconds and t = 5.6 seconds
Because the ball reaches this point in its way up and then passes it again on its way down, the ball will have 2 times at this height.
Solve for a.
5a + 2 - 7-8 = 0
What is the root? If there is no root, choose none.
Answer:5
Step-by-step explanation: root5a+2 +7a-8 = 0
squaring both side
5a+2=7a-8
8+2=7a-5a
10=2a
a=5
Answer:
[tex]\sqrt{5a+2}-\sqrt{7a-8}=0[/tex]
Isolate a square root on the left-hand side
[tex]\sqrt{5a+2} =\sqrt{7a-}8+0[/tex]
Eliminate the radical :-
[tex]5a+2 = 7a-8[/tex]
Solve:-
[tex]2a -10 = 0[/tex]
Add 10 to both sides, then Divide both sides by 2:-
[tex]a = 5[/tex]
OAmalOHopeO
Fill in the blank by performing the indicated elementary row operation(s).
6
1
5
-6R2+R
1
-5
0
Answer 7 Points
Keybo
<
Prev
In this question, we are given a matrix, and we have to perform the given operation.
The matrix is:
[tex]\left[\begin{array}{ccc}6&-1&|5\\1&-5&|0\end{array}\right][/tex]
The following operation is given:
[tex]R_1 \rightarrow -6R_2 + R_1[/tex]
In which [tex]R_1[/tex] is the element at the first line and [tex]R_2[/tex] is the element at the second line.
Updating the first line:
[tex]R_{1,1} = -6*1 + 6 = 0[/tex]
[tex]R_{1,2} = -6*-5 - 1 = 30 - 1 = 29[/tex]
[tex]R_{1,3} = -6*0 + 5 = 5[/tex]
Thus, the filled matrix will be given by:
[tex]\left[\begin{array}{ccc}0&29&|5\\1&-5&|0\end{array}\right][/tex]
For another example where row operations are applied on a matrix, you can check https://brainly.com/question/18546657
