The number of pledges that Melissa collected for this year's charity walk is 8 less than half the number of pledges she collected last year. Which expression represents the number of pledges she collected this year?

Answer:

2 + 2 + 2 + 2 + 2 + 2 = 4 × 3

Step-by-step explanation:

the sequence is 25/4(4/5)^x

plug in 10 for x to get your solution:

25/4(4/5)^10=4^9/5^8

Answer:

the answer is 6

hope it helps

Answer:

SAS

Step-by-step explanation:

ok so there is one angle and 2 sides

Answer:

-23

Step-by-step explanation:

6×-4 -1.... (6)(-4)-1

-24-1.....-24-1

-23

Answer:

14

Step-by-step explanation:

Answer/Step-by-step explanation

1. When adding real numbers with the same sign the sum will have the same sign as the numbers added.

2. When adding real numbers with different signs you subtract the lesser absolute value from the greater one. The sum will then have the same sign as the number with the greater absolute value.

3. There are a couple of properties of addition:

The additive commutative property tells us that the order in which you add the numbers does not change the sum.

4. And the additive associative property tells us that it also that the order in which we group three or more numbers does not affect the sum.

5. The additive identity property tells us that the sum of a number and 0 is always the number.

6. And the additive inverse property tells us that if you add a number with its opposite you will always get 0

Answer: 1.92

Step-by-step explanation:

Formula to find the mean absolute deviation:

[tex]MAD =\sum^{n=i}_{n=1}\dfrac{|x_i-\overlien{x}|}{n}[/tex]

, where [tex]\overline{x}=[/tex] mean , [tex]x_i's[/tex] = data values, n= number of data values.

Given data: 5,9,7,0,3,5,5

n= 7

Mean:

[tex]\overline{x}=\dfrac{5+9+7+0+3+5+5}{7}\\\\=\dfrac{34}{7}[/tex]

MAD = [tex]\dfrac {|5-\dfrac{34}{7}|+|9-\dfrac{34}{7}|+|7-\frac{34}{7}|+|0-\dfrac{34}{7}|+|3-\dfrac{34}{7}|+|5-\dfrac{34}{7}|+|5-\dfrac{34}{7}|}{7}[/tex]

[tex]=\dfrac{\frac17+\frac{29}{7}+\frac{15}{7}+\frac{34}{7}+\dfrac{13}{7}+\frac17+\frac17}{7}\\\\=\dfrac{\frac{94}{7}}{7}\\\\=\dfrac{94}{49}\approx1.92[/tex]

Hence, the  mean absolute deviation of 5,9,7,0,3,5,5 is 1.92(approx)

Answer:

A , E, F

Step-by-step explanation:

Three statements are true based on the graph the correct options are D, E,F

If the object is going linearly, and at a constant speed, then the speed of that object is given by the distance it traveled to the time it took to travel that distance.

If the object traveled D distance in T units of time, then that object's speed is

[tex]Speed = S = \dfrac{\: Distance \: traveled}{\: Time \: taken} = \dfrac{D}{T} \: \rm unit \: length/unit \: time[/tex]

For option D, we can see in the graph the bus has completed 200 miles of distance between the 2nd and 3rd hour. So, there are more than 3hours remaining, and option D is correct

For option E, it is clear from the graph that after 4 hours the distance traveled by the bus is 130miles

For option F; the distance traveled in first 4 hours= total distance from home - remaining distance after 4 hours

310-130=180miles

time= 4hours

speed=distance/time

speed= 180/4= 45miles per hour

hence, D, E,F are true

Learn more about average speed here:

https://brainly.com/question/12322912

#SPJ6

Answer:

0 is the answer

Step-by-step explanation:

Answer:

It is 0 i did -3 and got a 0% on the answer so yeah have a good one

In other words its 0

Answer:

12 Miles

Step-by-step explanation:

27 - 3 = 24

24 ÷ 2 = 12

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

Part a) Is x = 0 a solution to both inequalities

FOR  -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

Part b) Is x = 4 a solution to both inequalities

FOR  -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

solving -2x < 10

[tex]-2x\:<\:10[/tex]

Multiply both sides by -1 (reverses the inequality)

[tex]\left(-2x\right)\left(-1\right)>10\left(-1\right)[/tex]

Simplify

[tex]2x>-10[/tex]

Divide both sides by 2

[tex]\frac{2x}{2}>\frac{-10}{2}[/tex]

[tex]x>-5[/tex]

[tex]-2x<10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}[/tex]

solving -6 < -2x

-6 < -2x

switch sides

[tex]-2x>-6[/tex]

Multiply both sides by -1 (reverses the inequality)

[tex]\left(-2x\right)\left(-1\right)<\left(-6\right)\left(-1\right)[/tex]

Simplify

[tex]2x<6[/tex]

Divide both sides by 2

[tex]\frac{2x}{2}<\frac{6}{2}[/tex]

[tex]x<3[/tex]

[tex]-6<-2x\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<3\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:3\right)\end{bmatrix}[/tex]

Thus, the two intervals:

[tex]\left(-\infty \:,\:3\right)[/tex]

[tex]\left(-5,\:\infty \:\right)[/tex]

The intersection of these two intervals would be the solution to both inequalities.

[tex]\left(-\infty \:,\:3\right)[/tex]  and [tex]\left(-5,\:\infty \:\right)[/tex]

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

FOR  -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

Answer:

Kindly check attached picture

Step-by-step explanation:

Given the data:

Year of Incidence 1936 1937 1938 1939 1940 1941 1942 1943 1944 1945 1946

Number of Incidences (percent) 0.9 0.8 0.8 1.3 1.4 1.2 1.7 1.8 1.6 1.5 1.5

The year of incidences were represented as 1 to 11 for each consecutive year. WITH YEAR on the x and number of incidences on the y. Axis.

Answer:

A ;
This is the picture in case it may be labelled a different letter!

☆

EDGE2023 Good Luck :3

Answer:

66 degrees

Step-by-step explanation:

angle M=angle P

so:

15x-18=13x-8

reducing:

2x=10

x=5

angles M & P each are 57 degrees

180-57-57=angle L

66 degrees

1. coefficient

2. constant

3. variable

4. equation

5. inequality

6. two - step

-- let me know if you have any questions regarding this.

Answer:

It's either 400 or 1,200.

Step-by-step explanation:

Other people are saying 400, I got 1,200 by multiplying 1,600 to 0.75 which gave me that answer. I do not know how other people got 400.

Answer:

270

Step-by-step explanation:

108 divided by 24 is 4.5. 4.5 is how many gallons per hour. then, 4.5 times 60 equals 270.

Answer:

if 90% = $36

100%= ?

100%×$36

90%

3600 = $40

90

Step-by-step explanation:

you use the method of cross multiplying

Answer:

C

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

They just don't :)

Answer:

False

Step-by-step explanation:

Trust me

Answer:

x = 18

Step-by-step explanation:

[tex](7x - 7) \degree = (6x + 11) \degree \\ (exterior \: alternate \: \angle s) \\ \\ 7x - 7 = 6x + 11 \\ \\ 7x - 6x = 11 + 7 \\ \\ x = 18[/tex]

Step-by-step explanation:

y = kx, where k is a real constant.

When x = 0.4, y = 4.

=> (4) = (0.4)k, k = 10.

Hence when x = 5,

y = kx = (10)(5) = 50.

The answer is 50.

[tex]7x +3 = 2x - 4 \\ 7x - 2x = - 4 - 3 \\ 5x = - 7 \\ x = \frac{ - 7}{5} \longrightarrow - \frac{7}{5} [/tex]

[tex]7 ( - \frac{7}{5} )+ 3 = 2( - \frac{7}{5} ) - 4 \\ - \frac{49}{5} + 3 = - \frac{14}{5} - 4 \\ - \frac{49}{5} + \frac{15}{5} = - \frac{14}{5} - \frac{20}{5} \\ - \frac{34}{5} = - \frac{34}{5} [/tex]

The equation is true for the value of x. Therefore the answer is x = -7/5

[tex] \large \boxed{x = - \frac{7}{5} }[/tex]

Answer:

5

Step-by-step explanation:

Answer:

x = 10

Step-by-step explanation:

DE is the midsegment joining the midpoints of BC and AC respectively.

Therefore, by the property of midsegment of a triangle,

DE will be parallel and half of the measure of the third side of the triangle.

DE = [tex]\frac{1}{2}(AB)[/tex]

5 = [tex]\frac{x}{2}[/tex]

x = 10 units

Answer:

number 7:Sometimes  We can have two acute angles, 20 and 30, 20+30=50, which is still acute,   We can have two acute angles, 45 and 45, 45+45=90, which is neither acute nor obtuse. We can have two acute angles, 80 and 80, 80+80=160, which is obtuse.acute angles are less than 90 degrees. However, they can sometimes equal obtuse angles. For example, two acute angles measures of 70 degrees and 30 degrees are both acute. Add them together they equal 100 degrees, which is obtuse. some examples:  40° and 30° are acute angles  40° + 30° = 70°, which is an acute angle  60° and 30° are acute angles  60° + 30° = 90°, which is a right angle  50° and 70° are acute angles  50° + 70° = 120°, which is an obtuse angle.

number 8 :Since the intercepted arc LN is the diameter of the circle, its measure is 180 degrees, so m<LMN = 90

Conclusion: the sum of two acute angles is sometimes an acute angle.