The population of a town increased by 20% between 1989 and 1995. If the
population increased again by 10% from 1995 till 2003, what is the percentage increase in the
population between 1989 and 2003?

Answer:

32 percent

Explanation:

Assume the town's population in 1989 is 100. In 1995 it will be 120. There's a 10% increase (12) from 1995 to 2003 so the population in 2003 is 132. The percentage increase from 1989 (100) to 2003 (132) is (132-100) / 100 = .32 or 32 percent.

The percentage increase in the population between 1989 and 2003 will be 32%.

The quantity of anything is stated as though it were a fraction of a hundred.

The population of a town increased by 20% between 1989 and 1995. If the population increased again by 10% from 1995 till 2003.

Then the percentage increase in the population between 1989 and 2003 will be

Let x be the population in 1989.

Then the population in 1995 will be

⇒ 1.2 x

Then the population in 2003 will be

⇒ 1.2 × 1.1 × x

⇒ 1.32x

Then the percentage will be

P = (1.32x - x) / x × 100

P = 0.32 × 100

P = 32%

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