The population of a town is decreasing exponentially according to the formula
P = 7,285(0.97)t, where t is measured in years from the present date. Find the population in 2 years, 9 months. (Round your answer to the nearest whole number.)

Answers

Answer 1

Answer: 6669

Step-by-step explanation:

I hope I did this right... anyways,

t, is represented by years, which is given to us by 2 years and 9 months. Assuming you would put 2.9 for t.

Additionally, as you can't have a decimal for a person, and they've asked for it to be rounded to the nearest whole number, there would be 6669 people in 2 years and 9 months.

The formula used is:

[tex]7285(0.97)^2^.^9[/tex]


Related Questions

Find the area of the shaded regions

Answers

Sector area

Area of whole = 51.313

Area of unshaded = 9.424

Area of shaded = 41.8886

Answer:

40π/3

Step-by-step explanation:

Find the area of the bigger circle:

A = πr² = π(4 + 3)² = 49π

Find the area of 120° sector AOC:

A = 120°/360°*A = 1/3*49π = 49π/3

Find the area of smaller circle:

A = π(3²) = 9π

Find the area of 120° sector of DOB:

A = 120°/360°*9π = 3π

Now find the shaded area, the difference of areas of sectors:

49π/3 - 3π = 40π/3

7 root 3 by 3 minus 3 root 2 by root 15 minus 3 root 2 minus 2 root 5 by root 6 + root 5 ​

Answers

Answer:

Hill doctoral tricot trivial paint Tahiti he who Olney of Accokeek if Dogtown k park pectin rabbit tabernacle numbed.

If we add one unit to the length (l) of a rectangle that has width (w), what is its new area (NA) in terms of its old area (A)?
NA = A x w
NA = A + w
NA = A + l
NA = A

Answers

NA = A + W

By adding one unit to length, we increase the overall area by the width of the rectangle. This is because the formula for the area of a rectangle is A = l x w. So, NA = (l + 1) x w = (l x w) + w = A + w.

37. The trip between 2 towns is exactly 90 miles. You have gone 40% of this distance. How far have
you gone?

Answers

Answer:

36 miles

Step-by-step explanation:

We want to find 40% of 90 miles

40% * 90

.40 * 90

36 miles

Distance=90mliesTravelled distance=40℅

We have to find travelled distance inorder to find this we have to find 40℅ of 90miles

[tex]\\ \Large\sf\longmapsto 90\times 40\℅[/tex]

[tex]\\ \Large\sf\longmapsto 90\times \dfrac{40}{100}[/tex]

[tex]\\ \Large\sf\longmapsto 9\times 4[/tex]

[tex]\\ \Large\sf\longmapsto 36miles [/tex]

If a seed is planted, it has a 90% chance of growing into a healthy plant.

If 6 seeds are planted, what is the probability that exactly 2 don't grow?

Answers

Answer:

[tex]\displaystyle\frac{19,683}{200,000}\text{ or }\approx 9.84\%[/tex]

Step-by-step explanation:

For each planted seed, there is a 90% chance that it grows into a healthy plant, which means that there is a [tex]100\%-90\%=10\%[/tex] chance it does not grow into a healthy plant.

Since we are planting 6 seeds, we want to choose 2 that do not grow and 4 that do grow:

[tex]\displaystyle \frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}[/tex]

However, this is only one case that meets the conditions. We can choose any 2 out of the 6 seeds to be the ones that don't grow into a healthy plant, not just the first and second ones. Therefore, we need to multiply this by number of ways we can choose 2 things from 6 (6 choose 2):

[tex]\displaystyle \binom{6}{2}=\frac{6\cdot 5}{2!}=\frac{30}{2}=15[/tex]

Therefore, we have:

[tex]\displaystyle\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \binom{6}{2},\\\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot 15,\\\\P(\text{exactly 2 don't grow})=\boxed{\frac{19,683}{200,000}}\approx 9.84\%[/tex]

Answer:

[tex] {?}^{?} However, this is only one case that meets the conditions. We can choose any 2 out of the 6 seeds to be the ones that don't grow into a healthy plant, not just the first and second ones. Therefore, we need to multiply this by number of ways we can choose 2 things from 6 (6 choose 2):

\displaystyle \binom{6}{2}=\frac{6\cdot 5}{2!}=\frac{30}{2}=15(26)=2!6⋅5=230=15

Therefore, we have:

\begin{gathered}\displaystyle\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \binom{6}{2},\\\\P(\text{exactly 2 don't grow})=\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot \frac{9}{10}\cdot 15,\\\\P(\text{exactly 2 don't grow})=\boxed{\frac{19,683}{200,000}}\approx 9.84\%\end{gathered}P(exactly 2 don’t grow)=101⋅101⋅109⋅109⋅109⋅109⋅(26),P(exactly 2 don’t grow)=101⋅101⋅109⋅109⋅109⋅109⋅15,P(exactly 2 don’t grow)=200,00019,683≈9.84%

[/tex]

Of all the people applying for a certain job 75% are qualified and 25% are not. The personnel manager claims that she approves qualified people 80% of the time, she approves unqualified people 30% of the time. Find the probability that a person is qualified if he or she was approved by the manager The probability is:_______.
Type an integer or decimal rounded to four decimal places as needed)

Answers

Answer:

The probability is: 0.8889.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Approved

Event B: Qualified

Probability of a person being approved:

80% of 75%(qualified)

30% of 25%(not qualified). So

[tex]P(A) = 0.8*0.75 + 0.3*0.25 = 0.675[/tex]

Probability of a person being approved and being qualified:

80% of 75%, so:

[tex]P(A \cap B) = 0.8*0.75[/tex]

Find the probability that a person is qualified if he or she was approved by the manager.

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.8*0.75}{0.675} = 0.8889[/tex]

The probability is: 0.8889.

WILL GIVE BRAINIEST PLEASE WRITE IN ''f(x) = a(b)^x'' ORDERAn industrial copy machine has the ability to reduce image dimensions by a certain percentage each time it copies. A design began with a length of 16 inches, represented by the point (0,16). After going through the copy machine once, the length is 12, represented by the point (1,12).

Answers

Answer:

f(x) = 16*0.75^x

Step-by-step explanation:

first off let's use this coordinate (the one given) :

(0,16)

let's substitute this into the equation with x being 0 and f(x) being 16

16 = a*b^0

*anything to the power of 0 is 1*

so:

a = 16

now use the second coordinate :

(1,12)

and do the same by substituting 1 for x and 12 for f(x), we also know what 'a' is:

12 = 16*b^1

12 = 16 * b

b = 3/4

so :

f(x) = 16*0.75^x

Answer:

f(x) = 16(.75)^x

Step-by-step explanation:

Name
MATH 1342
Lab 12 - Ch.10 - Hypothesis Testing
Critical Thinking, Communication Skills, Empirical/Quantitative Skills
2. A machine is designed to fill jars with 16 ounces of coffee. A quality control inspector
suspects that the machine is not filling the jar with the full 16 ounces. A sample of 20 jars has
a mean of 15.8 ounces and a standard deviation of 0.32 ounce. Is there enough evidence to
support the inspector's claim that the mean number of ounces of coffee in the jars is less than
16? Use a = .05.
1.
Hand H
2.
3.
Critical value(s)
4.
Graph
5.
Test Statistic
6.
P-value
7.
Reject H. or Do Not Reject H.
8.
Conclusion

Answers

1 & 2:The null and alternate hypotheses are

H0 : u = 16 vs Ha: u < 16

The null hypothesis is that the mean is 16 ounces against the claim that it is less than 16 ounces.

3:The significance level is 0.05

4. Critical Value:

The critical region for significance level = 0.05  for one tailed test is z< ± 1.645

5.The test statistic

The test statistic to be used is

z= x- μ/σ/√n

z= 15.8-16/0.32/√20

z= -0.2/ 0.071556

z= -2.7950

6. The p-value ≈ 0.00259 for one tailed test.

7. Reject H0

Since the calculated value of z= -2.7950 is less than z∝= -1.645  we reject the null hypothesis.

8. Conclusion:

There is enough evidence to  support the inspector's claim that the mean number of ounces of coffee in the jars.

https://brainly.com/question/15980493

Graph

write your answer as an integer or as a decimal rounded to the nearest tenth​

Answers

Answer:

8.6

Step-by-step explanation:

VW = WX / cos (36°)

= 7 / 0.81

= 8.6

Answer:

8.65

Step-by-step explanation:

cos 36° = 7 / VW

VW = 7 /  cos 36°

VW = 8.65

How to multiply
(c+7)(3x-2)

Answers

Answer:

3cx - 2c + 21x - 14

Step-by-step explanation:

( c + 7 ) ( 3x - 2 )

= c ( 3x - 2 ) + 7 ( 3x - 2 )

= c ( 3x ) - c ( 2 ) + 7 ( 3x ) - 7 ( 2 )

= 3cx - 2c + 21x - 14

Answer:

3cx-2c+21x-14

Step-by-step explanation:

try to expand it by multiplying everything in the first brackets by every thing in the second brackets.

c(3x-2)+7(3x-2)

3cx-2c+21x-14

I hope this helps

- 2/3 (2 - 1/5) use distributive property

Answers

Answer:

-6/5

Step-by-step explanation:

- 2/3 (2 - 1/5)

Distribute

-2/3 *2 -2/3 *(-1/5)

-4/3 + 2/15

Get a common denominator

-4/3 *5/5 +2/15

-20/15 +2/15

-18/15

Simplify

-6/5

Find Easy question For yall

Answers

Answer:

V = 64.6

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos V = adj side/ hypotenuse

cos V = 3/7

Taking the inverse cos of each side

cos ^-1 ( cos V) = cos ^-1 (3/7)

V=64.62306

Rounding to the nearest tenth

V = 64.6

Answer:

V=64.6

Step-by-step explanation:

the same thing as other guy, lol

There is a path of width 2.5 m inside around a square garden of length 45m.
(a) Find the area of the path.
(b) How many tiles will be required to pave in the path by the square tiles of length 0.5m? Find it.

Help ! 도와주세요, 제발 :(​

Answers

Answer:

2.5+2.5+45+45

=95.0m

therefore area of the square= 95.0m

45m×0.5=45.5÷95=

Step-by-step explanation:

2.5m

2.5 m tiles are required

[tex]area = 2.5 \times 45 = 192.5 \: squared \: cenimetre \\ \\ no \: of \: tiles = 0.5 \times 0.5 = 0.25 \\ 192.5 \div 0.25 = 770tiles[/tex]

Make x the subject

y = 4(3x-5)/9

Answers

Answer:

3/4y +5/3 = x

Step-by-step explanation:

y = 4(3x-5)/9

Multiply each side by 9

9y = 4(3x-5)/9*9

9y = 4(3x-5)

Divide each side by 4

9/4 y = 4/4 (3x-5)

9/4y = 3x-5

Add 5 to each side

9/4y +5 = 3x-5+5

9/4y +5 = 3x

Divide by 3

9/4 y *1/3 +5/3 = 3x/3

3/4y +5/3 = x

If 2x - 5y – 7 = 0 is perpendicular to the line ax - y - 3 = 0 what is the value of a ?

A) a =2/3

B) a =5/2

C) a = -2/3

D) a = -5/2

Answers

Answer:

D) a = - 5/2

Step-by-step explanation:

2x -5y - 7 = 0

5y = 2x - 7

y = 2/5 x - 7

the slope of this line is therefore 2/5 (factor of x).

the perpendicular slope is then (exchange y and x and flip the sign) -5/2, which is then a and the factor of x.

What is the area of this figure?

Answers

Answer:

22

Step-by-step explanation:

(5x2) + (3x2) + (3x2)

22 square units

Answer from Gauthmath

morgan got 17/20 of the questions on a science test correct. what percent of the questions did she get correct?

Answers

Answer:

85%

Step-by-step explanation:

100% = 20

1% = 100%/100 = 20/100 = 0.2

now, how often does 1% fit into the actual result of 17 ? and that tells us how many %.

17/0.2 = 17/ 1/5 = 17/1 / 1/5 = 5×17 / 1 = 5×17 = 85%

Answer:

17/20×100=

85%

=85%

hope this helps

At a university of 25,000 students, 18% are older than 25. The registrar will draw a simple random sample of 242 of the students. The percentage of students older than 25 in the sample has an expected value of 18% and a standard error of:______.

Answers

Answer:

Standard error of: 2.47%

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

18% are older than 25.

This means that [tex]p = 0.18[/tex]

Simple random sample of 242 of the students.

This means that [tex]n = 242[/tex]

Standard error:

By the Central Limit Theorem:

[tex]s = \sqrt{\frac{0.18*0.82}{242}} = 0.0247[/tex]

0.0247*100% = 2.47%

Standard error of: 2.47%

Solve for x

X/6 = 10

A) X = 4
B) X = 10
C) X = 16
D) X = 60

Answers

hi  

x/6 = 10

In a equation , you can use every math operation you know as long as you do the same thing on both sides.  

Here we have   x/6 = 10  

But what I want is  x .  

Here X is split in 6.  So  I 'm going to multiplicate all by 6 to find the original amount of X  

In bold operation that are often not written but that you must understand to do that kind of exercices.

So  :  x/6 = 10

      (x/6) *6  = 10 *6

        6x/6 =  60

             x = 60

Determine if the table below represents a linear function. If so, what's the rate of change?

A) No; it's a non-linear function.

B) Yes; rate of change = 4

C) Yes; rate of change = 2

D) Yes; rate of change = 3

Answers

Answer:

A

Step-by-step explanation:

Its not a linear function; there is no consistent rate of change between each of the points.

Find the first five terms to an=2an-1+3, a1=6

Answers

Answer:

a1=6 a2=15 a3=33 a4=69 a5=141

Step-by-step explanation:

an=2an-1+3

We should attempt n=2 to find the second term

a2=2a1+3= 2*6+3=15

n=3 to find the third term

a3=2a2+3= 2*15+3=33

n=4 to find the fourth term

a4=2a3+3=2*33+3=69

n=5 to find the fifth term

a5= 2a4+3=2*69+3= 141

A coffee pot holds 3 3/4 quarts of coffee. How much is this in cups.

Answers

Answer: 15 cups

Step-by-step explanation:

True or False: A line perpendicular to x=7 has a slope of 0

Answers

Answer:

True, I believe

Step-by-step explanation:

Answer:

The answer is yes because its horizontal

If $500 were deposited into an account paying 5% interest, compound monthly, how much would be in the account in 4 years?

Please show me proper work and a good explanation on how you got said answer.

Answers

Answer:

610.48

Step-by-step explanation:

The formula for compound interest is

A = P(1+r/n) ^nt  where

A is the amount in the account

P is the principle

r is the interest rate

n is the number of times the interest is compounded per year

t is the time in years

A = 500(1+.05/12) ^12*4

A = 500(1+.0041666666) ^48

A = 500(1.0041666666) ^48

A = 500*1.220895355

A =610.4476775

Rounding to the nearest cent

A = 610.48

[infinity]
Substitute y(x)= Σ 2 anx^n and the Maclaurin series for 6 sin3x into y' - 2xy = 6 sin 3x and equate the coefficients of like powers of x on both sides of the equation to n= 0. Find the first four nonzero terms in a power series expansion about x = 0 of a general
n=0
solution to the differential equation.

У(Ñ)= ___________

Answers

Recall that

[tex]\sin(x)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n+1}}{(2n+1)!}[/tex]

Differentiating the power series series for y(x) gives the series for y'(x) :

[tex]y(x)=\displaystyle\sum_{n=0}^\infty a_nx^n \implies y'(x)=\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty (n+1)a_{n+1}x^n[/tex]

Now, replace everything in the DE with the corresponding power series:

[tex]y'-2xy = 6\sin(3x) \implies[/tex]

[tex]\displaystyle\sum_{n=0}^\infty (n+1)a_{n+1}x^n - 2\sum_{n=0}^\infty a_nx^{n+1} = 6\sum_{n=0}^\infty(-1)^n\frac{(3x)^{2n+1}}{(2n+1)!}[/tex]

The series on the right side has no even-degree terms, so if we split up the even- and odd-indexed terms on the left side, the even-indexed [tex](n=2k)[/tex] series should vanish and only the odd-indexed [tex](n=2k+1)[/tex] terms would remain.

Split up both series on the left into even- and odd-indexed series:

[tex]y'(x) = \displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} + \sum_{k=0}^\infty (2k+2)a_{2k+2}x^{2k+1}[/tex]

[tex]-2xy(x) = \displaystyle -2\left(\sum_{k=0}^\infty a_{2k}x^{2k+1} + \sum_{k=0}^\infty a_{2k+1}x^{2k+2}\right)[/tex]

Next, we want to condense the even and odd series:

• Even:

[tex]\displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2k+2}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2(k+1)}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=0}^\infty a_{2k+1}x^{2(k+1)}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=1}^\infty a_{2(k-1)+1}x^{2k}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty (2k+1)a_{2k+1}x^{2k} - 2 \sum_{k=1}^\infty a_{2k-1}x^{2k}[/tex]

[tex]=\displaystyle a_1 + \sum_{k=1}^\infty \bigg((2k+1)a_{2k+1} - 2a_{2k-1}\bigg)x^{2k}[/tex]

• Odd:

[tex]\displaystyle \sum_{k=0}^\infty 2(k+1)a_{2(k+1)}x^{2k+1} - 2\sum_{k=0}^\infty a_{2k}x^{2k+1}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2(k+1)}-2a_{2k}\bigg)x^{2k+1}[/tex]

[tex]=\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2k+2}-2a_{2k}\bigg)x^{2k+1}[/tex]

Notice that the right side of the DE is odd, so there is no 0-degree term, i.e. no constant term, so it follows that [tex]a_1=0[/tex].

The even series vanishes, so that

[tex](2k+1)a_{2k+1} - 2a_{2k-1} = 0[/tex]

for all integers k ≥ 1. But since [tex]a_1=0[/tex], we find

[tex]k=1 \implies 3a_3 - 2a_1 = 0 \implies a_3 = 0[/tex]

[tex]k=2 \implies 5a_5 - 2a_3 = 0 \implies a_5 = 0[/tex]

and so on, which means the odd-indexed coefficients all vanish, [tex]a_{2k+1}=0[/tex].

This leaves us with the odd series,

[tex]\displaystyle \sum_{k=0}^\infty \bigg(2(k+1)a_{2k+2}-2a_{2k}\bigg)x^{2k+1} = 6\sum_{k=0}^\infty (-1)^k \frac{x^{2k+1}}{(2k+1)!}[/tex]

[tex]\implies 2(k+1)a_{2k+2} - 2a_{2k} = \dfrac{6(-1)^k}{(2k+1)!}[/tex]

We have

[tex]k=0 \implies 2a_2 - 2a_0 = 6[/tex]

[tex]k=1 \implies 4a_4-2a_2 = -1[/tex]

[tex]k=2 \implies 6a_6-2a_4 = \dfrac1{20}[/tex]

[tex]k=3 \implies 8a_8-2a_6 = -\dfrac1{840}[/tex]

So long as you're given an initial condition [tex]y(0)\neq0[/tex] (which corresponds to [tex]a_0[/tex]), you will have a non-zero series solution. Let [tex]a=a_0[/tex] with [tex]a_0\neq0[/tex]. Then

[tex]2a_2-2a_0=6 \implies a_2 = a+3[/tex]

[tex]4a_4-2a_2=-1 \implies a_4 = \dfrac{2a+5}4[/tex]

[tex]6a_6-2a_4=\dfrac1{20} \implies a_6 = \dfrac{20a+51}{120}[/tex]

and so the first four terms of series solution to the DE would be

[tex]\boxed{a + (a+3)x^2 + \dfrac{2a+5}4x^4 + \dfrac{20a+51}{120}x^6}[/tex]

Write the inequality shown in this graph.

Answers

Answer:

y > -1/2 x + 4

Step-by-step explanation:

Equation of a line : (y-y1)/(y2-y1) = (x-x1)/(x2-x1)

(y-4)/(2-4)= (x-0)/(4-0)

(y-4)/-2 = x/4

(-y+4)/2 = x/4

-y+4 = 1/2 x

-y = 1/2 x - 4

y = -1/2 x + 4

the solutions of the inequality are the points above this line, so

y > -1/2 x + 4

How many unit cubes are on each layer of the cube?

6
3
12
9

Answers

Answer:

6

Step-by-step explanation:

Remember: Each layer has 6 cubes. Step 3 Count the cubes. cubes Multiply the base and the height to check your answer. So, the volume of Jorge's rectangular prism is cubic centimeters. if wrong very sorry

Answer:

9

Step-by-step explanation:

took the test

I need help ASAP please

Answers

Answer:

yes how can I help you???

plz help with this:)

Answers

9514 1404 393

Answer:

  -4

Step-by-step explanation:

The point (x, y) = (0, 0) is on the line, so it represents a proportional relation. Any ratio of y to x will be the slope. The choice that makes this computation easiest is ...

  x = 1, y = -4

  y/x = -4/1 = -4

The slope of the line is -4.

F(x) = x +3; G(x) = 2x^2 -4 Find (f*g)(x)

Answers

9514 1404 393

Answer:

  (f·g)(x) = 2x^3 +6x^2 -4x -12

Step-by-step explanation:

The distributive property is used to find the expanded form of the product.

  (f·g)(x) = f(x)·g(x) = (x +3)(2x^2 -4) = x(2x^2 -4) +3(2x^2 -4)

  = 2x^3 -4x +6x^2 -12

  (f·g)(x) = 2x^3 +6x^2 -4x -12

Other Questions
Quentin's faith teaches that God commands everyone to give at least ten percent of their income to the poor. Quentin usually gives fifteen percent. According to divine command theory, Quentin's action is __________. obligatory supererogatory impermissible neutral It is the way to convey a message,an idea,a picture,or speech that is received and understood clearly and correctly by the person for whom it is sent. FitWear Inc, a sporting goods footwear and apparel company, features photographs of celebrities wearing its brand of clothing and sports gear, FitWear Inc. launched a commercial for its new line of football cleats. This commercial featured famous football Stars because the company believes that celebrities can influence customers' buying decisions. In this case, the football stars served as A. aspirational reference groups B. opinion leaders C, decision makers D. nonaspirational reference groups Brownley Company has one service department and two operating (production) departments. Payroll Department costs are allocated to the two operating departments in proportion to the number of employees in each. Listed below are the operating data for the current period: Department Direct Expenses No.of Employees Payroll $ 26,000 Milling 80,000 52 Assembly 109,600 78 The total cost of operating the Milling Department for the current period is: rev: 12_17_2020_QC_CS-243789 Multiple Choice $90,400. $95,600. $10,400. $15,600. $80,000. Consider an economy with two agents, Amy and Becky, and two goods, x and y. Amy's utility function is U_A(x,y)=x_Ay_A, and Becky's utility function is U_B=\min\{4x_B,y_B\}. Amy and Becky's endowments are both \omega_A=\omega_B=(4,1). Suppose that the contract curve in this economy can be represented as y_A=mx_A. Find m. The length of a rectangle is 4 meters longer than the width. If the area is 22 square meters. find the rectangles dimensions. The width is what? The length is what? i have 17 coins. N of them are nickels and the rest are dimes. write an expression in two different ways for the amount of money that i have. (Hint: one is the other simplified) what is the difference between logo, crest, badges and insignia 1. In a certain training institution, there are 1000 ful-time and 600 part-time students, if a sample survey to be conducted to see how they budget their time by taking 320 students, how many students from full time and part-time are selected as sample respondent? You own a portfolio equally invested in a risk-free asset and two stocks (If one of the stocks has a beta of 1 and the total portfolio is equally as risky as the market, what must the beta be for the other stock in your portfolio balance the equation:2Na+3H2O-2NaOH+H2 A map is drawn to a scale of 1 cm to x m. A plot of land with an area of 28 hectares is represented by an area of 112 cm?. Find the value of x. (1 hectare = 10 000 m) six boys each have the same number of sweets.the total number of sweet is 78. how many sweet did each boy have? President George Washington took the oath of office on April 30,1789.Abraham Lincoln was sworn in as president on March 4, 1861. These events are an example of how do you solve this Samia created the following tables of values for a linear system. She concluded that there is nosolution to the system what do you mean by trigonometry need help refer to picture 1/109/10QFind the perimeter of the rectangle pictured above. Give your answer as a reduced mixed number. Last year there were 45 memebers of the tennis club at Marks Middle school. This year although the number of boys increeased by 20%, the number of girls decresed by 20%, the total numbers decresed by 1. Find how many boys anf girls are in the tennis club this year.