the primary coil of a transformer has 480 turns, and the secondary has 112 turns. when an ac voltage of 28.0 v is applied to the primary, what is the output voltage in the secondary?

The magnitude and direction of the resultant velocity of the car will be 169.70 km/h and 45°.

The quantity which has magnitude, direction and follows the law of vector addition is called a vector.

A car traveling at 120 km/h towards west makes a right turn and travel north without changing its speed.

Then the magnitude (R) will be

R² = 120² + 120²

R² = 28800

R = 169.70 km / h

Then the direction of the resultant velocity will be

tan θ = 120 / 120

tan θ = 1

tan θ = tan 45°

     θ = 45°

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Answer:

Explanation:

missing info .....

Answer:

D. 0.43 A

Explanation:

First you will find the total resistance which is

R=R¹+R²

R=2+12

R= 14 ohms

I = V/R

I = CURRENT

V= VOLTAGE

R = RESISTANCE

I= 6/14

I =0.43 A

The difference between polar covalent bonds and nonpolar covalent bonds using these two molecules - H2 and HCl are HCl is a polar covalent compound because the chloride ion is extra electronegative than the hydrogen ion.

HCl is a polar molecule. This is due to the fact the Chlorine (Cl) atom withinside the HCl molecule is extra electronegative and does now no longer proportion the bonding electrons similarly with Hydrogen (H). But H2 And Cl2 are nonpolar because of comparable electronegativity of each the atoms withinside the molecule H2 And Cl2 .

Hydrogen chloride is a diatomic molecule, such as a hydrogen atom H and a chlorine atom Cl related with the aid of using a polar covalent bond. The chlorine atom is an awful lot extra electronegative than the hydrogen atom, which makes this bond polar.

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Hello!

Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:

[tex]d = 2\pi r[/tex] ← The circumference of the orbit

speed = orbital speed, we will solve for this later

time = period

Therefore:

[tex]T = \frac{2\pi r}{v}[/tex]

Where 'r' is the orbital radius of the satellite.

First, let's solve for 'v' assuming a uniform orbit using the equation:
[tex]v = \sqrt{\frac{Gm}{r}}[/tex]

G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)

m = mass of the earth (5.98 × 10²⁴ kg)

r = radius of orbit (1.276 × 10⁷ m)

Plug in the givens:
[tex]v = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{(1.276*10^7)}} = 5590.983 m/s[/tex]

Now, we can solve for the period:

[tex]T = \frac{2\pi (1.276*10^7)}{5590.983} =\boxed{ 14339.776 s}[/tex]

The magnitude of the average force exerted on the ball by the wall is 225.469 N.

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

Impulse F. t = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

Given is a 3.42 kg steel ball strikes a massive wall at 14.3 m/s at an angle of α = 61.5° with respect to the plane of the wall. It bounces off with the same speed and angle. The ball is in contact with the wall for 0.207 s

Substitute the values into the expression, we get

Impulse = 2 x mvcosθ

Impulse= 2 x 3.42 x 14.3 x cos 61.5°

Impulse = 46.672 kg.m/s

The impact force can be written as

F.t = I

Put the given values, we have

F = 46.672 /  0.207

F = 225.469 N

Thus, the magnitude of force exerted by the wall is 225.469 N

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The amount of current in the blood sample is determined as 0.12 A.

The current in the blood is calculated by applying Ohm's law as shown below;

V = IR

where;

From resistivity chart corresponding to 0.98 g/L, resistance, R = 7.4

I = V/R

I = 0.9 /7.4

I = 0.12 A

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The diagram shows the speed and distance of a free-falling item dropped from rest. In the attachment, there is a graph.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The velocity and the time at the different points are;

A(0 sec ,0 m/sec)

B(1,9.8)

C(2,19.6)

D(3,29.4)

E(4,39.2)

F(5,49.0)

The point is plotted on the graph and get the graph.

The graph is attached in the attachment.

The complete question is;

Velocity and distance of free-falling object dropped from rest are given in the digrame. Draw the velocity-time graph for the given conditions.

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The approximate volume of table tennis ball is  80 cm³

Volume is defined as the amount of space occupied by the three dimensional object. S I unit of volume is m³ or cm³.

To find the volume of tennis ball using graduated cylinder.

Step 1 - Fill the graduated cylinder half or full.

Step 2 - Mark the initial volume of the water i.e. 100 cm³ (Vi)

Step 3  - Put the tennis ball in the graduated cylinder. Some of the water was displaced by the table tennis ball.

Step 4 - Mark the Final volume of the water (Vf) i.e. 180 cm³

Step 5 = Calculate the volume by using Formula

Vb = Vf – Vi = 180 cm³ - 100 cm³ = 80 cm³

Hence the volume of tennis ball (Vb) is 80 cm³

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Answer:

40

Explanation:

Becky's acceleration is 5.45 [tex]ms^2[/tex].

Acceleration = [tex]\frac{v-u}{t}[/tex]

where v= final velocity , u= initial velocity , t= time taken

according to the question :

initial veocity = 0 (it is at stop initially)

final velocity = 30m/s

time taken = 5.5 s

according to the formula acceleration = [tex]\frac{30-0}{5.5}[/tex]=[tex]5.45[/tex]

Hence Becky's acceleration is 5.45 [tex]ms^2[/tex].

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Answer:

D. 20m

Explanation:

this answer is 20 m.

wavelength = velocity / frequency

Answer:

the answer to the question is a reflector

Answer:

-1.35 N

Explanation:

Force due to q1

Force due to q2

Net Force

Answer: See below

Explanation:

Part (a):

As the velocity of the piano is constant, the net force on the piano is zero. The friction is also zero.

Here, F is the force applied by the man towards the inclined plane, mg is the weight of the piano and N is the normal force.

Applying Newton's law we get,

[tex]F = mg\sin \theta[/tex]

Substituting we get,

[tex]F &= \left( {180\;{\rm{kg}}} \right) \times \left( {9.8\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}} \right) \times \sin 19.0^\circ \\ &= 574.3\;{\rm{N}}[/tex]

Therefore, the force is 574.3 N

Part (b)

Here, the force F is applied parallel to the floor.

The friction is zero.

Applying Newton's law we get,

[tex]F\cos \theta &= mg\sin \theta \\ F &= mg\tan \theta[/tex]

Substituting we get,

[tex]F &= \left( {180\;{\rm{kg}}} \right) \times \left( {9.8\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}} \right) \times \tan 19.0^\circ \\ &= 607.4\;{\rm{N}}[/tex]

Therefore, the force is 607.4 N

Answer:

B

Explanation:

i's 100% paset bro.....

The speed by which the spaceprobe travels when all the rocket fuel is used up will be 29.262 m/sec.

According to the law of conservation of linear momentum before the collision is equal to the momentum after the collision. These laws state how momentum gets conserved.

Unit conversion;

1 km/sec = 1000 m/sec

Given data;

Spaceprobe speed  = 1.795 km/s = 1795 m /sec

Probe mass = 635.0 kg

Fuel mass = 4092.0 kg

Expelled propellent velocity = 4.161 km/s = 41461 m/sec

From the momentum conservation principle;

[tex]\rm P_i = P_f \\\\ (m_p+m_f)v_i = m_pV - m_fv_p \\\\ V = \frac{(635+4092)1795+4092 \times 41461}{635} \\\\ V = 280540.7 \ m/sec \\\\ V = 28.05 m/sec[/tex]

Hence, the speed by which the spaceprobe travels when all the rocket fuel is used up will be 29.262 m/sec.

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Answer: A) Ball A

Explanation:

Density = m/v where m is mass and v is volume

This means the greater the mass, the greater the density.

Because of Ball A's greater mass it would have the greater density.

The distance x will the ball land after flies off with a horizontal initial velocity  is 3.0635 m.

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

A small metal ball with a mass of m = 62.0 g is attached to a string of length l = 1.85 m. It is held at an angle of θ = 48.5° with respect to the vertical.

The ball is then released. When the rope is vertical, the ball collides head-on and perfectly elastically with an identical ball originally at rest. This second ball flies off with a horizontal initial velocity from a height of h = 3.76 m, and then later it hits the ground.

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

Kinetic energy  = Potential energy

1/2 mv² =mgh₁

The velocity at the bottom, when the height h = 5m, is

v= √2gh₁...................(1)

The vertical height h₁ = l- lcosθ

h₁ = l- lcosθ

h₁ = 1.85 - 1.85cos48.5°

h₁ =0.6241 m

Putting the values in equation (1), we get

v = √2x 9.81 x0.6241

v = 3.499 m/s

The horizontal distance traveled is

x = vt

x = v x √2h/g

Plug the values, we get

x =  3.499 x √2x3.76 / 9.81

x = 3.0635 m

Thus, the horizontal distance ball travels is  3.0635 m.

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(a) A graph of u as a function of position (r) along the line between the two planets is attached below.

(b) The minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

If an object is lifted, work is done against gravitational force. The object gains energy.

Given are two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as

u(r) = − (Gm /R1 −r) − (Gm / R2 −r) .

This problem takes place far out in space and there are no other massive objects in the vicinity of the two planets

(a) A graph of u (r)  versus position (r) along the line between the two planets is attached in answer.

(b) There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2.

The range of the projectile is given by R =  v²sin2θ / g

g = gravitational acceleration of Earth

If g = g(p) for planet , range  R =  v²sin2θ / g(p)..................(1)

The gravitational force of attraction = weight force

Gm² /d² = m g(p)

g(p) = Gm/d².........................(2)

For R = d/3, from equation (1), we have

d/3 =  v²sin2θ / g(p)

Plug the expression for g(p) , we get

v = √ [Gm/3dsin2θ ]

For velocity to be minimum, sin2θ =1

So, the minimum velocity will be

v = √ [Gm/3d]

Thus, the minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

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When Angel hits a ball with the ball. As the action is a ball as it is hitted. The reaction force is the force exerted on another ball.

Newton’s third law of motion describes the two forces, action and reaction forces. This states that for every action force, there is an equal and opposite reaction force.

As Angel hits a ball with another ball, the action is the ball as it is hit. The ball exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat, which is known as the reaction force.

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Answer:

Case 1: Balancing length when cell is shunted l1 = 150 cm = 1.5 m, Value of shunt = R = 5 ohm. Case 2: Balancing length when cell is shunted l1 = 175 cm = 1.75 m, Value of shunt = R = 10 ohm. Example 06: A cell balances against a length of 250 cm on potentiometer wire when it is shunted by a resistance of 10 ohms

The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.

The Brundtland Commission was set up with the intention to achieve sustainable development. The tenure of the commission lasted from 1984 to 1987.

The commission identified the pillars of sustainable growth as economic growth, environmental protection, and social equality. The committee opined that environmental problem emanates from poverty in the southern region and reckless consumption of resources in the northern region.

The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.

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Answer:

ways can carry either __machanical___ or electromagnetic energy

Explanation:

This case is inertia.

Mass is directly proportional to inertia

Answer:

Explanation:

Force:

⇒ Mass × Acceleration

Work Done:

⇒ Force × Distance

Calculations:

⇒ Force = 0.0083 × 7000 N

⇒ Work done = 0.0083 × 7000 × 5.8 × 10^4 Joules

The final velocity of the projectile when it strikes the ground below is 198.51 m/s.

The time taken for the projectile to fall to the ground is calculated as follows;

h = vt + ¹/₂gt²

where;

265 = (185 x sin45)t + (0.5)(9.8)t²

265 = 130.8t + 4.9t²

4.9t² + 130.8t - 265 = 0

solve the quadratic equation using formula method,

t = 1.89 s

vyf = vyi + gt

where;

vyf = (185 x sin45) + (9.8 x 1.89)

vyf = 149.322 m/s

vxf = vxi

where;

vxf = 185 x cos(45)

vxf = 130.8 m/s

vf = √(vyf² + vxf²)

where;

vf = √(149.322²  +  130.8²)

vf = 198.51 m/s

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The side of this cube will be 2.9996 cm. The net force on the solid cube is acting upward.

What is buoyancy force?

A fluid exerts an upward force against the weight of a partly or completely submerged item. The weight of the overlying fluid causes pressure to rise with depth in a column of fluid.

Given data;

Actual weight.W=0.714 N

Apparent weight,W'=0.450 N

The density of water,ρ=1000 kg/m³

The net force on the solid cube is;

Apparent weight = actual weight - buoyancy force

Buoyancy force = Actual weight - apparent weight

F=W-W'

F = 0.714 - 0.450

F= 0.264 N

The buoyancy force(F) is found as;

F = ρgV

0.264 = 1000 × 9.81 × V

V=2.69 × 10⁺⁵

The volume of a cube is found as;

V=a³

2.69 × 10⁺⁵ m³=a³

a=0.02996 m

As we know that 1 m = 100 cm

a=2.996 cm

Hence, the side of this cube will be 2.9996 cm.

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Answer:

2kg brick

Explanation:

2kg brick at 25 degrees.

Answer: A 2kg brick at 20*C

Explanation:

One support of the behavioral perspective is how  B. F. skinner’s ideas have brought to light how the environment and learning influence personality.

The behavioral perspective on personality and individual variations places an emphasis on quantifiable behaviors influenced by the environment and the results that follow.

The theoretical aim of behaviorism is the prediction and control of behavior given its natural science methodology.

Skinner's theories have made it clear how learning and the environment affect personality, which is one argument in favor of the behavioral approach.

One support of the behavioral perspective is how  B. F. skinner’s ideas have brought to light how the environment and learning influence personality.

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The net force on q2 will be 1.35 N

A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.

Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.

We have to find the net force on q2

At first we will find Force due to q1

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²

F = 450 × 10⁻³

F₁ = 0.45 N (+)

Now we will find Force due to q2

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²

F = 1800 × 10⁻³

F₂ = 1.8 N (-)

So net force (F) will be

F = F₂ - F₁

F = 1.8 - 0.45

F = 1.35 N

Hence the net force on q2 will be 1.35 N

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