The purpose of the chiller is to remove heat from the air and is therefore denoted as option A.
What is a Chiller?This is a type of device which is referred to as type of a cooling system that removes heat by circulating heat-absorbing a refrigerant through a series of mechanisms through which the heat is released.
The result of this process is that the heat in the air is removed as a result of the refrigerant being adequately circulated and then the environment becomes cooler and is therefore the reason why it was chosen as the correct choice.
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You weigh 650 N.
What would you weigh if the Earth were
five times as massive as it is and its radius
were five times its present value?
Answer in units of N.
Answer:
129.95 N
Explanation:
First, you want to find the acceleration due to gravity on this hypothetical planet.
Using the equation [tex]g = G (M/R^2)[/tex] , where G is a constant ([tex]6.67 * 10^{-11}[/tex]), M is mass of the planet, and R is radius of the planet, we can plug in the numbers of earth and then multiply them by whatever the question requires, in this case, 5x.
[tex]g = (6.67 * 10^{-11})(5*(5.97 * 10^{24})) /(5* (6.378 *10^{6}))^{2}[/tex]
g = 1.96 m/s. The acceleration due to gravity on this planet is 1.96 m/s.
Now to find your weight.
First, you want to find your mass.
On earth, your weight is equal to your natural force (Fn)
mg = Fn
m(9.8) = 650 ==> mass = 66.33 kg
Now, to find your weight on this hypothetical planet, multiply your mass by the acceleration due to gravity (g)
M x g
66.33 x 1.96 = 129.95 N
You would weigh 129.95 N
Describing Physical Changes
Define kinetic energy and thermal energy. Describe what
happens to each as the temperature of a substances
increases.
During Physical Changes, kinetic energy and thermal energy. of the material changes as well as temperature of the substances also changes.
What is Physical Changes?Physical changes are those that affect a chemical substance's form but not its chemical content. Physical changes may normally be used to separate compounds into chemical elements or simpler compounds, but they cannot be used to separate mixtures into their component compounds.
When something changes physically but not chemically, it is said to have undergone a physical change. Physical means can be used to undo a physical alteration.
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Q2 The equation of the periodic time of a pendulum
bob is:
T= 2√L/g
2514
Where T is the periodic time. I is the length of the
string.
A Prove that the equation is homogeneous with respect to e base Units
B. Find the base unit of force.
The dimensional relation of the time period bob with its length is shown below.
what is meant by "dimensional analysis"?a method of analysis that represents physical quantities in terms of their fundamental dimensions in the absence of enough data to create precise equations.
What is the purpose of dimensional analysis?Dimensional analysis is a method used in engineering and the physical sciences to reduce physical quantities like acceleration, viscosity, and energy to their three basic dimensions of length, mass, and time (T).
[T]=[M^0 L^0 T^1]
[L]=[M^0 L^1 T^0]
[g]=[M^0 L^1 T^-2]
SQUARE ROOT OF (L/g)=[m0l1t0]/[m0l1t-2]
=[m0l0t1]
= R.H.S.
Hence it's dimensionally correct.
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Which principle is used to make hydraulic machines work
Hydraulic machines work based on the principle of Pascal's Law, which states that the pressure exerted on a confined fluid is transmitted equally in all directions. This means that the pressure applied to one part of a confined fluid is transmitted throughout the entire fluid, regardless of the shape or size of the container. This principle is used in hydraulic machines to transfer force from one point to another by using a fluid, usually oil or water, in a closed system of pipes or cylinders.
The force applied to the small piston of a hydraulic machine is transmitted through the fluid, and it is amplified on the larger piston due to the difference in area between the two pistons. This allows a small force to be amplified into a much larger force, making the machine able to lift or move heavy loads with minimal effort.
This is the basic principle that makes hydraulic systems, such as car brakes, lift, cranes, excavators, and many other machines work.
How can the city with a high relative humidity have so little moisture in the air?
A car is traveling at 14 m/s. By what factor does the car's kinetic energy increase if its speed is doubled to 28 m/s?
If speed of the car is doubled to 28 m/s, the kinetic energy of it will be four times.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.
Kinetic energy is directly proportional to square of the speed of the object.
Hence, if its speed is doubled to 28 m/s, the kinetic energy of it will be four times.
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Atoms are typically spaced about 0.2 nm apart (nucleus to nucleus). At that spacing, how many atoms would be found in a line 4.97 inches long?
Atoms are typically spaced about 0.2 nm apart, which means that there are 5 nm in 1 micrometer (1nm = 0.001 micrometer).
To convert inches to micrometres we can use the conversion factor 1 inch = 25.4 micrometres.
So 4.97 inches is equal to 4.97 x 25.4 = 126.988 micrometres
And if we divide 126.988 micrometres by 5 micrometres we get 25.3976
So, there would be 25 atoms in a line 4.97 inches long.
two Forces one of 12 N and another 24 N acts on abody in such away that they make angie 90° with each other Find the resultant a = (1/4)b=(7/5)and C=(-9/2)
According to the question of forces, the resultant a will be 28N.
What is resultant?
Resultant is a term that is used to describe the combined effect of two or more forces acting on an object. It is the vector sum of the individual forces. Resultant force is the single force that replaces the action of several forces acting on a body. Calculating the resultant force of multiple forces can be done by using the components of the forces in the x and y directions, then using basic vector addition to calculate the resultant force. The resultant force is the combination of the individual forces and the magnitude and direction of the resultant force is determined by the direction and magnitude of the individual forces.
The resultant force of the two forces is equal to the square root of the sum of the squares of the magnitudes of the two forces.
Therefore, the resultant force is equal to √(12^2 + 24^2) = 28 N.
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If two objects of in equal mass are struck with the same amount of force, what should the result be according to newtons 2nd Law?
Answer:
According to Newton's second law of motion, the net force acting on an object is equal to the mass of the object multiplied by its acceleration, or F = ma.
If two objects of equal mass are struck with the same amount of force, the acceleration of the two objects should be the same. This is because the net force acting on both objects is the same, and their mass is also the same. Therefore, the acceleration of the two objects will be in proportion to the net force acting on them and will be equal.
How do you get part (c)?
Part (a) Which statement best describes the numbers of protons and electrons in the penny when it is charged as indicated?
Electrons were added, and the number of electrons exceeds the
number of protons. ✔ Correct!
Part (b) How many electrons were transferred in order to create the charge on the penny?
Ne = 6.88 * 109
Ne = 6.880×109electrons ✔ Correct!
Part (c) By what percentage do the transferred electrons change the mass of the penny? (Express your result as a positive percentage for an increase, negative for a decrease.)
The percentage at which the transferred electrons change the mass of the penny is 0 %.
What percentage is the mass of the penny changed?
The percentage at which the transferred electrons change the mass of the penny is calculated by applying the following formula as shown below.
Mathematically, the formula for percentage change is given as;
percentage change = ( New mass - old mass ) / ( old mass ) x 100%
The original mass of the copper penny is given as 2.5 g and when converted to kilogram, the mass becomes 0.0025 kg.
The mass of 1 electron = 9.11 x 10⁻³¹ kg
then, the mass of 6.88 x 10⁹ electrons = ?
= ( 6.88 x 10⁹ ) x ( 9.11 x 10⁻³¹ kg )
= 6.27 x 10⁻²¹ kg
new mass of the penny = 0.0025 kg + 6.27 x 10⁻²¹ kg = 0.0025 kg
The percentage change in the mass of the penny is calculated as follows;
percentage change = ( New mass - old mass ) / ( old mass ) x 100%
percentage change = ( 0.0025 kg - 0.0025 kg ) / ( 0.0025 kg ) x 100%
percentage change = 0 %
Thus, the transferred electron has no effect on the mass of the penny because the mass an electron is almost insignificant.
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Describe how to demonstrate the thermal energy is dissipated from a cup of hot tea
Answer:
Explanation:
1. Place a cup of hot tea on a flat surface.
2. Place a thermometer in the tea and record the temperature.
3. Place a fan in front of the cup of tea and turn it on.
4. Place the thermometer in the tea again and record the temperature.
5. Compare the two temperatures and observe the difference.
6. The difference in temperature is an indication of the thermal energy that has been dissipated from the cup of hot tea.
An object is dropped off a cliff . Assume there is no air resistance, so it accelerates at -9.8m/sec/sec what is the velocity at the end of 2 seconds?
The velocity of an object dropped off a cliff can be calculated using the equation:
v = v0 + at
Given:
v0 = 0 m/s (initial velocity)
a = -9.8 m/s^2 (acceleration due to gravity)
At the end of 2 seconds:
t = 2 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 2 s = -19.6 m/s
The velocity of the object at the end of 2 seconds is -19.6 m/s, downward.
At the end of 5 seconds:
t = 5 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 5 s = -49 m/s
The velocity of the object at the end of 5 seconds is -49 m/s, downward.
At the end of 12 seconds:
t = 12 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 12 s = -117.6 m/s
The velocity of the object at the end of 12 seconds is -117.6 m/s, downward.
It's worth mentioning that in the case of an object falling freely under the influence of gravity alone, the velocity will continue to increase
Select the correct answer. In a given city, the permissible limit of CO (carbon monoxide) in the air is 100 parts per million (ppm). The city monitors the steady rise of CO from various sources annually. In which year (rounded off to the nearest integer) will the CO level exceed the permissible limit? A. 2017 B. 2018 C. 2019 D. 2022
The year that the CO level exceed the permissible limit is C. 2019
What is the permissible limit?In the US, the permissible exposure limit is the maximum level of exposure to a chemical substance or physical agent, such as high levels of noise. The Occupational Safety and Health Administration establishes permissible exposure limits.
The maximum level of a substance to which a person can be exposed is known as the permissible exposure limit (PEL). When carbon monoxide levels in your bloodstream rise, carbon monoxide poisoning happens. Your body replaces the oxygen in your red blood cells with carbon monoxide when there is too much carbon monoxide in the air. Serious tissue damage or even death may result from this.
When gasoline, wood, propane, charcoal, or other fuels are burned, carbon monoxide, an odorless, tasteless gas, results. Appliances and engines that aren't properly ventilated, especially in a room that's tightly sealed or enclosed, can build up dangerous amounts of carbon monoxide.
In this case, the appropriate year is 2019.
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the velocity of a particle is given by v(t) = 20t²-100t+50t. a, when will the acceleration of a particle is zero. b, what is the velocity of the particle when it's acceleration is zero.
Answer:V(t)=20t^2-100t+50t
as we know accl means derivatives of velocity.
a/q,
dv/dt =0
dv/dt=20t^2-100t+50t=0
dv/dt=4t-100+50=0
=>40t-50=0
=>40t=50
=>t=1.25
therfore Vs= 20t^2-100t+50t
Vs=20(1.25625)-125+62.5
Vs=31.25-125+62.5
Vs=-31.25
An iron meteorite melts when it enters the Earth's atmosphere.
If its initial temperature was -105°C outside of Earth's atmosphere, calculate the minimum velocity the meteorite must have had before it entered Earth's atmosphere.
The minimum velocity for the meteorite before entrance into earth's atmosphere is 36.8 m/s.
How to find minimum velocity?To calculate the minimum velocity the meteorite must have had before it entered Earth's atmosphere, the equation for heat transfer is:
Q = mcΔT
Where Q = the heat transferred,
m = the mass of the meteorite,
c = the specific heat capacity of iron, and
ΔT = the change in temperature.
The specific heat capacity of iron is approximately = 0.45 J/g°C.
Temperature of the meteorite changes from -105°C to the melting point of iron, which is approximately = 1535°C.
So: Q = mc(1535 - (-105))
Mass of the meteorite unknown, but we know it is made of iron, so assume a value for the mass, such as 100 g.
Q = 100 x 0.45(1535 - (-105))
Solving for Q:
Q = 67875 J
To calculate the kinetic energy of the meteorite, which is given by the equation: Ek = 1/2mv²
where Ek is kinetic energy,
m = the mass of the meteorite and
v = the velocity of the meteorite.
Therefore, the velocity of the meteorite is given by the following equation: v = √(2Ek/m)
Substituting the values of Ek and m, we get
v = √(2 x 67875/100)
Solving for v:
v = √1357.5
The minimum velocity the meteorite must have had before it entered Earth's atmosphere is approximately 36.8 m/s.
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can you help me with that?
Answer:
no I can’t help you
Explanation:
I can’t help you because I don’t know the answer
Find the value of T₁ and T2 in the figure below. A t 27° T₁ B BRAJE 38° T₂ C 12g N Hint: Apply triangle of forces rule or sine and cosine rules
Answer:
The tension in [tex]T_1[/tex] is 0.1024 Newtons.
The tension in [tex]T_2[/tex] is 0.1157 Newtons.
Explanation:
Lets create a free body diagram showing all of the forces; we need to show the vertical and horizontal components of the tension.
I will attach a picture of my free body diagram. Notice I created 2 new triangles with the adjacent angles of angle A and C from the original picture.
Lets make a list of all the variables we have now. Also lets write down the information we are given.
[tex]A=27\\C=38\\m=12\\g=9.81\\W\\T_{1} \\T_{1x} \\T_{1y}\\T_{2} \\T_{2x} \\T_{2y} \\[/tex]
In this situation the sum of of the vertical tension components must support the weight. To find the vertical components we can use the SIN function.
[tex]sin(x)=\frac{O}{H} \\O=Hsin(x)[/tex]
Therefore we can write that the sum of the forces in the y direction is
[tex]\sum F_y=T_1sin(A)+T_2sin(C)=W[/tex]
This system is in equilibrium; the object should not move along the x-axis. Therefore, the horizontal components of [tex]T_1[/tex] and [tex]T_2[/tex] must then equal each other. To find the horizontal components we can use the COS function.
[tex]cos(x)=\frac{A}{H} \\A=Hcos(x)[/tex]
Therefore we can write that the sum of the forces in the x direction is
[tex]\sum F_x=T_1cos(A)=T_2cos(C)[/tex]
Now we have to equations to help us solve the problem.
[tex]T_1cos(A)=T_2cos(C)[/tex]
[tex]T_1sin(A)+T_2sin(C)=W[/tex]
We do not know the numerical values of [tex]T_1[/tex] and [tex]T_2[/tex] so we will have to manipulate algebraically to solve them.
In the first equation lets solve for [tex]T_1[/tex].
[tex]T_1cos(A)=T_2cos(C)[/tex]
Divide both sides by [tex]cos(A)[/tex].
[tex]T_1=\frac{T_2cos(C)}{cos(A)}[/tex]
Separate the right side into two fractions.
[tex]T_1=\frac{T_2}{1} *\frac{cos(C)}{cos(A)}[/tex]
Use the reciprocal trig identity for cosine.
[tex]sec(x)=\frac{1}{cos(x)}[/tex]
[tex]T_1=\frac{T_2}{1} *cos(C)}*sec(A)[/tex]
[tex]T_1=T_2*cos(C)}*sec(A)[/tex]
Now insert our answer for [tex]T_1[/tex] into the second equation.
[tex]T_2*cos(C)}*sec(A)*sin(A)+T_2*sin(C)=W[/tex]
Solve for [tex]T_2[/tex]. Lets replace each trig function with its own variable to make this easier.
[tex]T_2*cos(C)}*sec(A)*sin(A)+T_2*sin(C)=W[/tex]
[tex]cos(C)=x\\sec(A)=y\\sin(A)=z\\sin(C)=u[/tex]
[tex]T_2*x*y*z+T_2*u=W\\T_2xyz+T_2u=W[/tex]
Now lets solve for [tex]T_2[/tex].
Factor [tex]T_2[/tex] out of each term.
[tex]T_2(xyz)+T_2(u)=W[/tex]
Factor [tex]T_2[/tex] out of each term.
[tex]T_2(xyz+u)=W[/tex]
Divide each side by [tex]xyz+u[/tex].
[tex]T_2=\frac{W}{xyz+u}[/tex]
Lets substitute the trig functions back in for the variables
[tex]T_2=\frac{W}{cos(C)*sec(A)*sin(A)+sin(C)}[/tex]
[tex]W[/tex] is the weight.
The formula for weight is [tex]W=mg[/tex]. Where [tex]m[/tex] is the mass in kilograms.
12 grams is 0.012 kilograms.
[tex]W=0.012*9.81[/tex]
[tex]W=0.11772[/tex]
Numerical Evaluation
Lets evaluate [tex]T_2[/tex].
[tex]T_2=\frac{0.11772}{cos(38)*sec(27)*sin(27)+sin(38)}[/tex]
[tex]T_2=0.11573[/tex]
Lets evaluate [tex]T_1[/tex].
[tex]T_1cos(A)=T_2cos(C)[/tex]
[tex]T_1*cos(27)=0.11573*cos(38)\\T_1=0.10235443[/tex]
A rating/review would be much appreciated.
Answer:
T₁ = 102.25 N (2 d.p.)
T₂ = 115.61 N (2 d.p.)
Explanation:
The diagram shows a body of mass 12 kg (weight = 12g N) held in equilibrium by two light, inextensible strings. One string makes an angle of 27° with the positive horizontal and the other string makes an angle of 38° with the negative horizontal.
The body is in equilibrium, so both the horizontal and vertical components of the forces must sum to zero.
Resolving horizontally, taking (→) as positive:
[tex]\implies -T_1 \cos (27^{\circ})+T_2 \cos (38^{\circ})=0[/tex]
[tex]\implies T_1 \cos (27^{\circ})=T_2 \cos (38^{\circ})[/tex]
[tex]\implies T_1=\dfrac{T_2 \cos (38^{\circ})}{ \cos (27^{\circ})}[/tex]
Resolving vertically, taking (↑) as positive:
[tex]\implies T_1 \sin(27^{\circ})+T_2 \sin(38^{\circ})-12\text{g}=0[/tex]
[tex]\implies T_1 \sin(27^{\circ})+T_2 \sin(38^{\circ})=12\text{g}[/tex]
Substitute the found expression for T₁ into the second equation and take g = 9.8 ms⁻²:
[tex]\implies \left(\dfrac{T_2 \cos (38^{\circ})}{ \cos (27^{\circ})}\right) \sin(27^{\circ})+T_2 \sin(38^{\circ})=12\text{g}[/tex]
[tex]\implies T_2 \cos (38^{\circ})\tan(27^{\circ})+T_2 \sin(38^{\circ})=12\text{g}[/tex]
[tex]\implies T_2 \left(\cos (38^{\circ})\tan(27^{\circ})+ \sin(38^{\circ})\right)=12\text{g}[/tex]
[tex]\implies T_2 =\dfrac{12\text{g}}{\cos (38^{\circ})\tan(27^{\circ})+ \sin(38^{\circ})}[/tex]
[tex]\implies T_2=115.614550...\:\text{N}[/tex]
Substitute the found value of T₂ into the equation for T₁ and take g = 9.8 ms⁻²:
[tex]\implies T_1=\dfrac{\left(\dfrac{12\text{g}}{\cos (38^{\circ})\tan(27^{\circ})+ \sin(38^{\circ})}\right) \cos (38^{\circ})}{ \cos (27^{\circ})}[/tex]
[tex]\implies T_1=102.250103...\text{N}[/tex]
Therefore, the value of T₁ and T₂ in the given diagram is:
T₁ = 102.25 N (2 d.p.)T₂ = 115.61 N (2 d.p.)A galvanometer of resistance 50 ohms which gives a full scale deflection for 1M.A is to be adapted to measure current of up to 5A.-calculate tht resistance of the resistor required.- if this resistor is made of a material of cross-sectional area 4*10^-4cm2 and resistivity 2*10^-6cm2 calculate it's length
Answer:
Explanation:
R = (50 ohms x 5A) / 1mA = 250 ohms
The resistance of the resistor is 250 ohms.
The resistivity (ρ) = 2 x 10^-6 cm^2
The cross-sectional area (A) = 4 x 10^-4 cm^2
Therefore, the length (l) = (ρ x R) / A
l = (2 x 10^-6 cm^2 x 250 ohms) / (4 x 10^-4 cm^2)
l = 1.25 cm
Calculate the magnitude of the resultant moment exerted at O, for the configuration given in the Figure. The magnitude of F1 is F1=4N. Provide your answer in Newtons.meters (N.m).
The magnitude of the resultant moment exerted at O, for the configuration given in the Figure is 0.63 Nm.
What is the magnitude of the resultant displacement?
The magnitude of the resultant displacement of the object is calculated by applying the formula of Pythagoras theorem as shown below.
d = √ (dx² + dy² )
where;
dx is the displacement of the object is x directiondy is the displacement of the object is y directiond = √ (0.05² + 0.15² )
d = 0.158 m
The magnitude of the resultant moment exerted at O, for the configuration given in the Figure is calculated by applying the formula for torque or moment.
τ = Fd
where;
F is the applied forced is the resultant displacement at point Oτ = ( 4 N ) x ( 0.158 m )
τ = 0.63 Nm
Thus, the resultant moment is a function of the applied force and the resultant displacement.
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the most powerful ice breaker in the world was built in the former soviet union.The ship is almost 150 m long, and its nuclear engine generates 56 MegaWatts (56 E^6 W) of power. How much work can this engine do in 1.0 hour? (1 Hour = 3600 seconds)
The most powerful ice breaker can work 2.016 × 10 ¹¹ Joule in 1.0 hour.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Power of the nuclear engine = 56 × 10⁶ W.
Time it works = 1 hour = 3600 second
Hence, work done by this engine in 1.0 hour = 56 × 10⁶ × 3600 Joule
= 2.016 × 10 ¹¹ Joule.
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What force causes fluid pressure to vary with depth? Explain why this happens.
The force that causes fluid pressure to vary with depth is the weight of the fluid. As the fluid is a form of matter, it has weight and it exerts a force due to its weight. This force is known as hydrostatic force or pressure.
When the fluid is at rest, the weight of the fluid acts vertically downwards and it exerts pressure on the bottom of the container or on any object submerged in it. The deeper the object is, the more fluid is above it, and the greater the weight of the fluid is, so the greater the pressure is.
This happens because of the concept of Archimedes' principle which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid that the object displaces. So the deeper an object is submerged in a fluid, the more fluid it displaces, and the greater the buoyant force is. This buoyant force also known as the upthrust is what opposes the weight of the fluid and causes the pressure to vary with depth.
4 points
A hydraulic system contains one small piston with a area of 5.33 square inches and one large piston with an area of 10 square inches. If a force of 70 pounds
is applied to the small piston, what will the system pressure be?
A: 99.7 psi
B: 640.3 psi
C: 1,822 psi
D: 13.13 psi
Answer:
C
Explanation:
The system pressure will be equal to 70 pounds divided by the area of the small piston, which is 5.33 square inches. This gives a pressure of 13.13 psi (pounds per square inch).
define microgravity and a condition under which it can be produced.
Answer:
see below
Explanation:
Microgravity is a condition in which the gravitational force experienced by an object is very weak. It is characterized by a very small gravitational acceleration, typically less than one thousandth of that experienced on Earth's surface. The gravitational force experienced in microgravity is so small that it is often neglected in many physical phenomena.
A condition under which microgravity can be produced is by placing an object in a state of freefall. Freefall is the state in which an object is falling under the influence of gravity, but it is not in contact with a solid surface. When an object is in freefall, it experiences a condition of weightlessness, which is similar to microgravity.
One of the ways to produce microgravity is by being in orbit around the Earth, at an altitude of around 200 miles or more, the gravitational pull is weak enough to be considered as microgravity. This can be achieved by using spacecrafts or high-altitude balloons, where the object is in a state of free fall around the Earth, and it experiences microgravity.
Another way to achieve microgravity is by using aircrafts, such as the "vomit comet" that flies in parabolic trajectory, allowing the passengers to experience weightlessness for a few minutes during the flight.
In a position time graph, we plot the _______ of am object or a person against elapsed ________. The person's position is the distance from the __________ ____________. The shape of the graph shows the kind of motiin.
In a position-time graph, we plot the position of an object or a person against elapsed time. The person's position is the distance from the reference point. The shape of the graph shows the kind of motion.
What is a position time graph?A position-time graph is a type of graph used to represent the motion of an object over time. It plots the position of an object on the y-axis and the time elapsed on the x-axis. The position is usually represented as a distance from a reference point, such as the origin of a coordinate system.
The shape of the graph can provide insight into the nature of the object's motion. For example, a straight line on the position-time graph indicates that the object is moving at a constant velocity. A parabolic shape of the graph shows that the object is accelerating, and a curved line on the graph shows that the object is moving at a non-constant velocity.
It's a powerful tool to understand the motion of an object and its dynamics, it allows you to see the relationship between position, velocity and acceleration, and how they change over time.
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An increase in what property of an object causes its interia to increase? Volume velocity acceleration mass
Mass.
Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.
Our missions to Mars have allowed us to observe the skies from the surface of another planet. From a martian point of view, what do you predict we would see in this geocentric solar system, but not in our heliocentric solar system?
If we observe the skies from the surface of another planet, we can see heliocentric solar system, that is, all the planets are rotating around the sun.
What is heliocentric solar system?The Heliocentric model is an astronomy theory that places the Sun at the centre of the cosmos, with the Earth and other planets revolving around it. In the past, geocentrism, which put the Earth at its center, was countered by heliocentrism.
Aristarchus of Samos first offered the idea that the Earth revolves around the Sun in the third century BC after being influenced by a theory put forth by Philolaus of Croton (c. 470 – 385 BC).
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Explain what is meant by resolution of an instrument
A. Explain the difference between procision and
accuracy of a measurment.
B. During experiment to find the stiffness constant of a
spring, the following graph was obtained. By comparing
the theoretical equation to that of a straight line y=mx+c find the string constant.
The resolution of an instrument is the smallest increment of measurement that can be reliably distinguished. It is a measure of the precision of the instrument.
What is resolution?
Resolution is the process of making a decision or reaching an agreement about a problem or dispute. It is the act of solving a problem or coming to an agreement. It is a process of defining the problem, gathering relevant information, analyzing the data, generating possible solutions, evaluating the solutions, and selecting the most appropriate option.
Accuracy is the degree to which a measured value corresponds to the true value of the quantity being measured. In the example given, the resolution of the instrument would be the smallest increment of the measurement of the stiffness constant of the spring that could be reliably distinguished. The accuracy of the measurement would be determined by comparing the theoretical equation to that of a straight line y=mx+c to find the string constant.
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A body lifts up a book from the floor to the table. The mass of the box is 300 g and the height of the table is 80 cm. Find the work done by the boy when the acceleration due to gravity is 10 ms-2.
The work done by the boy against the gravitational force is 240000J.
What is the work done?Lifting an object against gravity generates potential energy for the object-Earth system. The change in gravitational potential energy, ΔPEg, is calculated as ΔPEg = mgh, where h is the height increase and g is the acceleration due to gravity.The gravitational pull of the Earth, denoted by g, is the net acceleration imparted to objects by the combined effect of gravitation and centrifugal force.Here given that,
Mass of the box (m) = 300 g
Height of table (h) = 80cm
Acceleration due to gravity (g) = 10 m/s²
Work done against gravitational force will be calculated by formula,
W = mgh
By substituting the values,
= 300 x 10 x 80
= 240000J
Therefore the work done by the boy is 240000J.
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1. You start your bicycle ride at the top of a hill. You coast down the hill at a constant acceleration of 2.00 m/s2. When you get to the bottom of the hill, you are moving at 18.0 m/s, and you pedal to maintain that speed. If you continue at this speed for 1.00 min, how far will you have gone from the time you left the hilltop?
Answer:
Explanation:
In order to determine how far you will have gone after 1.00 min, we need to calculate the distance traveled while coasting down the hill and the distance traveled while pedaling.
To calculate the distance traveled while coasting down the hill, we can use the equation:
distance = initial velocity * time + (1/2) * acceleration * time^2
Since you start at the top of the hill with an initial velocity of 0 m/s, and we know that the acceleration is 2.00 m/s^2, and time is unknown. we can solve for time using the final velocity equation:
velocity = acceleration * time + initial velocity
18 = 2*t + 0
t = 9 sec
Now we have time and acceleration, we can calculate distance.
distance = 0 * 9 + (1/2) * 2 * 9^2
distance = 81 m
Now we know how far you have traveled while coasting down the hill, we can calculate the distance traveled while pedaling.
We know that you are pedaling to maintain a constant speed of 18.0 m/s for 1.00 min, so we can use the formula:
distance = speed * time
distance = 18 * 1*60 = 1080 m
Therefore, in total, you have traveled 1080 + 81 = 1161 m from the time you left the hilltop.
why the density of an unknown substance in a mixture can be used to identify the substance?
Answer:
Explanation: You may figure out what it is by calculating the density of a substance to be identified and comparing the result to a table of known densities.
Density is also a helpful property since it bridges the gap between the mass and volume of a material. Density=mass/volume. Assume you're tasked with identifying an unknown material. The mass of the material may be calculated using a scale. The volume can be determined by dropping the object into a graduated cylinder containing a known volume of water and measuring the new volume. The density is calculated by dividing the mass by the volume and comparing it to a list of known densities.
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