Answer:
B. Matter
Explanation:
When rocks break down and become smaller ex: mountains eventually becoming sand, the matter does not disappear or get destroyed, it becomes smaller particles, but the matter is always preserved.
Hope It Helps!!!
Answer:
matter
Step-by-step explanation:
The conservation of matter states that
matter is neither created nor endorsedHere big matters gets down into smaller pieces
but they are not destroyed
C
An exponential function and a quadratic function are graphed below. Which of the following is true of the growth rate of the
functions over the interval 0≤x≤1?
-1
-1
2
O The exponential grows at half the rate of the quadratic.
O The exponential grows at the same rate as the quadratic.
The exponential grows at twice the rate of the quadratic
The correct answer is option b which is the exponential grows at the same rate as the quadratic.
The complete question is given below with the graph attached:-
An exponential function and a quadratic function are graphed below. Which of the following is true of the growth rate of the functions over the interval
a. The exponential grows at half the rate of the quadratic.
b.The exponential grows at the same rate as the quadratic.
c.The exponential grows at twice the rate of the quadratic.
d.The exponential grows at four times the rate of the quadratic.
What is inequality?Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.
Given an exponential function, say f(x), such that f(0) = 1 and f(1) = 2 and a quadratic finction, say g(x), such that g(0) = 0 and g(1) = 1.
The rate of change of a function f(x) over an interval
a ≤ x ≤ b
is given by
[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]
Thus, the rate of change (growth rate) of the exponential function, f(x) over the interval
0 ≤ x ≤ 1
is given by
[tex]\dfrac{f(1)-f(0)}{1-0}= \dfrac{2-1}{1}=1[/tex]
Similarly, the rate of change (growth rate) of the quadratic function, g(x) over the interval
0 ≤ x ≤ 1
is given by
[tex]\dfrac{g(1)-g(0)}{1-0}=\dfrac{1-0}{1}=1[/tex]
Therefore, the exponential grows at the same rate as the quadratic in the interval .
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In each of problems 5 through 11, find the general solution of the given differential equation
The complete question is
"Find the general solution of the given differential equation
y''-y=0, y1(t)=e^t , y2(t)=cosht
The function [tex]y(t)=e^t[/tex] is the solution of the given differential equation.
The function y(t)=cosht is the solution of given differential equation.
What is a function?
The function is a type of relation, or rule, that maps one input to specific single output.
Given;
[tex]y_1(t) = e^t[/tex]
Given differential equations are,
y''-y = 0
So that,
[tex]y' (t) = e^t, y'' (t) = e^t[/tex]
Substitute values in the given differential equation.
[tex]e^t -e^t=0[/tex]
Therefore, the function [tex]y(t)=e^t[/tex] is the solution of the given differential equation.
Another function;
[tex]y(t)=cosht[/tex]
So that,
[tex]y"(t)=sinht\\\\y"(t)=cosht[/tex]
Hence, function y(t)=cosht is solution of given differential equation.
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what is the area of the triangle formed from (0,1), (0,4), and (4,1)?
Answer:
6 square units
Step-by-step explanation:
base = 4 units
height = 3 units
[tex]\sf \boxed{\bf Area \ of \ triangle = \dfrac{1}{2}*base*height}[/tex]
[tex]\sf =\dfrac{1}{2}*4*3\\\\ = 2*3\\\\ = 6 \ square units[/tex]
[tex]\Large❏ \: \large\begin{gathered} {\underline{\boxed{ \rm {\blue{Area \: of \: triangle \: = \: \frac{1}{2} \: \times \: Base \: × \: Height }}}}}\end{gathered}[/tex]
[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: \frac{1}{2} \: \times \: Base \: × \: Height [/tex]
[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: \frac{1}{2} \: \times \: 4 \: × \: 3 [/tex]
[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: \frac{1}{ \cancel2} \: \times \: \cancel{4} \: ^{\green2} \: × \: 3 [/tex]
[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: 2 \: \times \: 3[/tex]
[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: 6[/tex]
Hence , the area of triangle is 6 units.
Find the gradient of the line shown.
Answer:it is o to 10/5 which is 1/
Step-by-step explanation:
What is the approximate value of x in the diagram below
We use Tan in this case:
Tan=(opposite/adjacent)
Tan(36)=23/x
x=23/Tan(36)
x=31.64 length
Hope it helps!
Answer:
x ≈ 31.64
Step-by-step explanation:
Trigonometric ratios
[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]
where:
[tex]\theta[/tex] is the angleO is the side opposite the angleA is the side adjacent the angleH is the hypotenuse (the side opposite the right angle)Given:
sin 36° ≈ 0.588cos 36° ≈ 0.809tan 36° ≈ 0.727The given trigonometric ratios all use the angle of 36°.
From inspection of the given diagram:
x is the side adjacent to the angle of 36°23 is the side opposite to the angle of 36°Therefore, we should use the tan trig ratio.
[tex]\implies \sf \tan(36^{\circ})=\dfrac{23}{x}[/tex]
[tex]\implies \sf x=\dfrac{23}{\tan(36^{\circ})}[/tex]
Substituting the given value for tan 36°:
[tex]\implies \sf x \approx \dfrac{23}{0.727}[/tex]
[tex]\implies \sf x\approx31.64[/tex]
Help asap
What is the end behavior of the following graph
Using limits, it is found that the end behavior of the graph is given as follows:
It rises to the left, and stays constant at y = -4 to the right.
What is the end behavior of a function f(x)?It is given by the limits of f(x) as x goes to infinity.
In this problem, the function is given by:
[tex]f(x) = 4\left(\frac{2}{5}\right)^{x + 3} - 4[/tex]
Hence:
[tex]\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} 4\left(\frac{2}{5}\right)^{x + 3} - 4 = 4\left(\frac{5}{2}\right)^{\infty + 3} - 4 = \infty - 4 = \infty[/tex]
[tex]\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow -\infty} 4\left(\frac{2}{5}\right)^{x + 3} - 4 = 4\left(\frac{2}{5}\right)^{\infty + 3} - 4 = 0 - 4 = -4[/tex]
Hence:
It rises to the left, and stays constant at y = -4 to the right.
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In studies that use more than one data collector, how is the consistency of the data evaluated?.
In order to evaluate consistency in studies with more than one data collector, the Inter-rater reliability is used.
What is the Inter-rater reliability?This is a measure in research that is used to test the data presented by different data collectors, for consistency.
It essentially checks the extent to which the data collected from the different sources agree with each other.
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I’m still not sure how the answer would be D (CBA), couldn’t it also be ACB?
Answer: No it could not be ACB.
Step-by-step explanation:
Angles are named based on the vertex of the angle so this could be referred to as ∠B. The other way to name an angle is by saying the three points, However, when you say the three points the vertex must be in the middle. Hence, the answer is ∠CBA as the middle point of the angle is in the middle of the name.
The x-coordinate of the point (50, 55) is ___________.
The x-coordinate of the point (50, 55) is 50
What is graph?A graph can be defined as a pictorial representation or a diagram that represents data or values.
The distance of point (50, 55) perpendicular to y-axis
Thus, perpendicular distance = 50 units
The x-coordinate of the point (50, 55) is 50
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A child designs a flag in the shape of a rhombus, as shown in the diagram below. Which expression can be used to determine the side length of the rhombus?
Using the cosine ratio, the expression that can be used to determine the side length of the given rhombus is: x = 10/cos 30.
What is the Cosine Ratio?The cosine ratio that can be used to solve a right triangle is, cos ∅ = adj/hyp.
x represents the side of the rhombus as shown in the image attached.
Hypotenuse = x Adjacent = 10 in.∅ = 30cos 30 = 10/x
x(cos 30) = 10
x = 10/cos 30
Thus, the equation that would be used to determine the side length is: x = 10/cos 30
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Answer:
A
Step-by-step explanation:
10/cos 30°
PLEASE HELP ( look at ss to answer )
The direct proportion is shown by table (B)
What is direct proportion?Direct proportion or direct variation is the relation between two quantities where the ratio of the two is equal to a constant value.
Here the second table shows the direct proportion relation.
This is because the ratio of x/y remain same.
4/2= 7/3.5= 10/5= 11/5.5= 15/7.5 = 2/1
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What is the completely factored form of this polynomial? 2x5 + 12x3 − 54x
Answer:
2x(x^2 - 3)(x^2 + 9)
Step-by-step explanation:
2x^5 + 12x^3 − 54x
2x(x^4 + 6x - 27)
Since -3 + 9 = 6 and -3 x 9 = -27:
2x(x^2 - 3)(x^2 + 9)
Answer:
[tex]2x(x^2-3)(x^2+9)[/tex]
Step-by-step explanation:
Given polynomial:
[tex]2x^5+12x^3-54x[/tex]
Factor out the common term [tex]2x[/tex]:
[tex]\implies 2x(x^4+6x^2-27)[/tex]
To factor the trinomial [tex]x^4+6x^2-27[/tex]:
[tex]\textsf{Let }u=x^2 \implies u^2+6u-27[/tex]
Factor the quadratic by finding two numbers that multiply to -27 and sum to 6: 9 and -3
Rewrite the middle term as the sum of these two numbers:
[tex]\implies u^2+9u-3u-27[/tex]
Factorize the first two terms and the last two terms separately:
[tex]\implies u(u+9)-3(u+9)[/tex]
Factor out the common term (u + 9):
[tex]\implies (u-3)(u+9)[/tex]
Substitute back [tex]u=x^2[/tex]:
[tex]\implies (x^2-3)(x^2+9)[/tex]
Therefore, the factored form of the given polynomial is:
[tex]\implies 2x(x^2-3)(x^2+9)[/tex]
A. 21.50
B. 32.25
C. 30.15
D. 20.75
Answer:
B
Step-by-step explanation:
Similar to the one you asked earlier.
Given from the table
1 Gallon of gas = $2.15
15 gallons of gas = $2.15 x 15
= $32.25 (B)
There were 35 children and 10 adults in a picnic. What is the ratio of children to the total number of people in the picnic?
Answer:
7/9 ( or 7:9)
Step-by-step explanation:
Children = 35
Total people = 35 + 10 = 45
ratio Children / total people = 35/45 = 7/9
On a map of scale 1:20000 the area of a forest is 50cm^2.On another map the area of the forest is 8cm^2.Find the scale of the second map.
Answer:
The answer is 1: 50000... If you look down here↓:
Step-by-step explanation:
With a scale of 1:20000, a unit length on the map represents a length of 20000. So 1 cm^2 = 1 cm* 1 cm which represents 20000*20000 cm^2 will be = 4*10^8 cm^2.
50 cm^2 represents that 4*50*10^8 cm^2 = 200* 10^8 cm^2.
Now, on the other hand, the map has the same. 200* 10^8 is represented by 8 cm^2. So the scale is sqrt [ 200* 10^8 / 8 ] = sqrt [ 25* 10^8 ] = 5* 10^4 = 50000.
Therefore the scale on the second map is 1: 50000.
a list of 8 numbers has a mean of 6. work out the total of the numbers.
Answer:
48
Step-by-step explanation:
The mean of a number is the sum of all the numbers divided by how many numbers there are. We can set up this formula: [tex]mean = \frac{sum}{amountnumbers}[/tex].
When we plug our values into this equation, we get: [tex]6 = \frac{sum}{8}[/tex]. Solving this equation gets us sum = 6 * 8 = 48
Carol measured a straw and wrote down how long it was in inches. pete multiplied carol's straw length by and cut a straw to be that many inches long. joe multiplied carol's straw length by and cut a straw to be that many inches long. which straw belongs to whom?
Answer:
pete
Step-by-step explanation:
i think its pete???
5
6
7 8
10
TIME REMAINING
27:07
Terrence buys a new car for $20,000. The value of the car depreciates by 15% each year. If f(x) represents the value
of the car after x years, which function represents the car's value?
f(x)=20.000(085)*
Answer:
Step-by-step explanation:
Is there answer choices?
If a(x) = 3x 1 and b (x) = startroot x minus 4 endroot, what is the domain of (b circle a) (x)?
The composite function (boa)(x) is equivalent to √3x-3
Composite functionGiven the following functions
a(x) = 3x +1
b(x) = √x - 4
To determine the composite function (boa)(x)
b(a(x) = b(3x +1)
Substitute 3x + 1 into b(x) to have:
(boa)(x)= √(3x + 1) - 4
(boa)(x) = √3x-3
Hence the composite function (boa)(x) is equivalent to √3x-3
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1.1 divided by 1.54 simplified
Answer:
1•4
Step-by-step explanation:
1•54÷1•1
1•54
1•1
divide by 10 both side with can move decimal
15•4
11
=my answer is 1•4.
Answer:
The correct answer for algebraic expression 1.54÷1.1 is = 1.4.
Step-by-step explanation:
this is question based on simple algebra -
Simple Algebraic equations - An algebraic equation can be defined as a mathematical statement in which two expressions are set equal to each other. The algebraic equation usually consists of a variable, coefficients and constants. we can apply many operations on algebraic equations like addition, subtraction, multiplication, division and raising to a power, and extraction of a root.
these equations are two algebraic expressions that are joined together using an equal to ( = ) sign. An algebraic equation is also known as a polynomial equation because both sides of the equal sign contain polynomials
so in the question algebraic operation used to solve is simple division.
therefore here in question we have to divide 1.54 with 1.1,
using the concept written above,
let the value of division be 'x'
we can write 1.54/1.1 = x
by dividing and multiplying the equation by 100 to remove the decimals.
(1•54/ 1•1)×100/100 = x
154/110 = x
now by simple division,
1.4 = x answer
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If f(x) = 2x - 6 and g(x) = x - 2x², find the value of f(2) + g(-3)
Answer:
-23
Step-by-step explanation:
f(2)= 2*2-6 = -2
g(-3)= -3-2*9 = -21
---> f(2)+G(-3)= -2-21 = -23
Answer: -23
Step-by-step explanation:
f(2) + g(-3) means that we will substitute 2 as x into the function f, and add that to -3 substituted as x into function g.
First, we will find the substituted and simplified values of these functions.
f(x) = 2x - 6
f(2) = 2(2) - 6
f(2) = -2
[tex]-----[/tex]
g(x) = x - 2x²
g(-3) = (-3) - 2(-3)²
g(-3) = -21
Lastly, we can add them.
f(2) + g(-3)
-2 + -21
-23
40 points, please help lol
The simplified expression of [tex]x^{-2/3} . x^{6/7}[/tex] is [tex]x^{4/21}[/tex]
How to simplify an expression?The expression [tex]x^{-2/3} . x^{6/7}[/tex] can be simplified as follows:
using law of indices,
xⁿ . xᵇ = xⁿ⁺ᵇ
Therefore,
[tex]x^{-2/3} . x^{6/7}[/tex] = [tex]x^{-2/3 + 6/7}[/tex]
[tex]x^{-2/3 + 6/7} = x^{ -14+18/ 21}[/tex]
[tex]x^{-2/3 + 6/7} = x^{ -14+18/ 21} = x^{4/21}[/tex]
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5-4-3-2
16
6/ +
77?1?
x
Which is the general form of the equation of the circle
shown?
Ox²+²+4x-2y-4 = 0
Ox+y+4x-2y + 2 = 0
Ox² + y² 4x +2y-4 = 0
Ox² + y² 4x + 2y + 2 = 0
Answer:
1st option
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
here (h, k ) = (- 2, 1 ) and r = 3 , then
(x - (- 2) )² + (y - 1)² = 3² , that is
(x + 2)² + (y - 1)² = 9 ← expand factors using FOIL
x² + 4x + 4 + y² - 2y + 1 = 9
x² + 4x + y² - 2y + 5 = 9 ( subtract 9 from both sides )
x² + 4x + y² - 2y - 4 = 0 , that is
x² + y² + 4x - 2y - 4 = 0 ← in general form
Answer:
[tex]\textsf{1)} \quad x^2+y^2+4x-2y-4=0[/tex]
Step-by-step explanation:
Equation of a circle
[tex](x-a)^2+(y-b)^2=r^2[/tex]
where:
(a, b) is the centerr is the radiusFrom inspection of the graph:
center of the circle = (-2, 1)radius of the circle = 3Substitute the found values into the formula:
[tex]\implies (x-(-2)^2+(y-1)^2=3^2[/tex]
[tex]\implies (x+2)^2+(y-1)^2=9[/tex]
Expand and simplify:
[tex]\implies (x+2)^2+(y-1)^2=9[/tex]
[tex]\implies x^2+4x+4+y^2-2y+1=9[/tex]
[tex]\implies x^2+y^2+4x-2y+5=9[/tex]
[tex]\implies x^2+y^2+4x-2y-4=0[/tex]
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Need help (pic included)
Answer:
(-4,-2)
x=-4
y=-2
Step-by-step explanation:
-3x-4y=20
3(x-10y=16)=3x-30y=48
The reason I multiplied 3 to the second equation is for when we add the equations together the x will cancel out.
-3x-4y=20
+ 3x-30y=48
-34y=68
Divide -34 from both sides.
y=-2
To find x you need to plug in -2 for y into one of the equations.
x-10y=16
x-10(-2)=16
Remember a negative times a negative equals a positive.
x+20=16
Subtract 20 from both sides.
x=-4
Hope this helps!
If not, I am sorry.
Someone please help with this!!
Answer:
A
Step-by-step explanation:
Comment (and answer)
Both start with the plus x axis as one of the arms. The other arm of 110o goes anti clockwise until it is 30 degrees into the second quadrant.
The answer can be found by using 110 - 360 = negative angle.
So 110 - 360 = - 250 which goes clockwise from the plus x axis. The answer must be A.
Make sure you understand the concept of clockwise and anti clockwise. If you don't know, ask your teacher, write it down, and try not to forget it. The distinction comes up a lot.
How much is the bill for a person who used 700 kWh in a month?
Answer:
700 kWh which is more than 200 so
0.10(x - 200) + 30
0.10( 700 -200)+ 30
0.10( 500) + 30
50 + 30
80
$80
Which can be represented as set of ordered pairs?
A. Expression
B. Relation
C. Equation
D. All of the choices
Answer:
D.All of the choice
Step-by-step explanation:
D.All of the choice
Given the function f(x) below, evaluate 3f(-2) + f(1).
if z ≤-3
3z²-2z if -3
-2√2-1
if x > 0
7x-2
f(x) = 3x² - 2x
pls help
Answer: 45
Step-by-step explanation: I used a graphing calculator and input all the equations and all the restraints, and I found that you can’t use the first equation since x has to be less than or equal to -3, and the question calls for x to be -2. So, in the second equation, there’s a point (-2, 16) and in the third equation there’s a point (1, -3). You know you have to use these two points since in the second equation, the restraint only lets you use numbers greater than -3 or less than 0, which cannot be one, and in the third equation, the restraint only lets you use numbers greater than 0, which can’t be -2. I hope that made some sense. So then, with substitution the equation would be 3(16)+(-3) which equals 45. 3(16)=48. 48-3+=45
if cos^4+cos^2=1 prove that cot^4a-cot^2a=1
Step-by-step explanation:
We can solve this kind of trigonometric problem
easily by the followings method :
Given :
cos^4a + cos^2a = 1
or, cos4^a = 1 - cos^2a
Therefore; cos^4a = sin^2a
Again,
To prove: cot^4a - cot^2a = 1
L.H.S = Cot^4a - cot^2a
= Cos^4a÷ sin^4a - Cos^2a ÷ sin^2a
= Sin^2a ÷ Sin^4a - cos^2a ÷ Sin^2a
= 1 ÷ Sin^2a - cos^2a ÷ Sin^2a
= 1 - cos^2a ÷ Sin^2a
= Sin^2a ÷ Sin^2a
= 1 = R.H.S proved.
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The graph below have the same shape.what is the equation of the blue graph?
Answer:
g(x) = (x - 5)²
Step-by-step explanation:
This is an example of the transformation of functions.
In this example, we see the graph f(x) has been moved 5 in the positive direction on the x-axis.
Due to the fact that we are working with the x-axis, our transformation will be placed inside the bracket, and it will do the opposite of what we expect.
This means that our transformation will be set out in this format:
[tex]g(x) = f(x-5)[/tex]
We know that:
[tex]f(x) = x^2[/tex]
Therefore,
[tex]g(x) = f(x-5) = (x-5)^2[/tex]
So, [tex]g(x) = (x-5)^2[/tex].