The "Screaming Swing" is a carnival ride that is - not surprisingly - a giant swing. It's actually two swings moving in opposite directions. At the bottom of its arc, a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. The rider in the other swing is moving in a similar circle at the same speed, but in the exact opposite direction. What is the acceleration, in m/s2 , that riders experience?

Answers

Answer 1

The acceleration, in m/s² , that riders experience is 50.3 m/s²

What is the acceleration, in m/s² , that riders experience?

Since the riders move in a circle, they undergo circular motion and will have a centripetal acceleration.

So, the centripetal acceleration, is given by a = v²/r where

v = speed of rider andr = radius of circle

Given that a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. We have that

v = speed of rider = 34 m/s and r = radius of circle = 46/2 = 23 m

So, substituting the values of the variables into the equation for the acceleration, we have

a = v²/r

a = (34 m/s)²/23 m

a = 1156 m²/s²/23 m

a = 50.26 m/s²

a ≅ 50.3 m/s²

So, the acceleration, in m/s² , that riders experience is 50.3 m/s²

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Related Questions

the model used in studying submarines in different parts of the ocean uses a scale of 1:500. if a submarine is 1,000 m below the surface of the ocean, how far below sea level is the submarine in the model?

Answers

Answer: B 2m

Explanation:

A ball accelerates uniformly at −2.00 m/s2.
If the ball was initially moving at 0.20 m/s and the ball travels for 7.00 s, then what was its final velocity?

Answers

The final velocity of a ball that accelerates uniformly at -2.00m/s² and moved at 0.20 m/s for 7.00 s is 14.2m/s.

How to calculate final velocity?

The final velocity of a moving body can be calculated using the following formula:

a = v - u/t

Where;

a = acceleration (m/s²)v = final velocity (m/s)u = initial velocity (m/s)t = time (s)

According to this question, a ball accelerates uniformly at −2.00 m/s². If the ball was initially moving at 0.20 m/s and the ball travels for 7.00 s, the final velocity is as follows:

-2 = (v - 0.2)/7

-14 = v - 0.2

v = 14.2m/s

Therefore, final velocity of a ball that accelerates uniformly at -2.00m/s² and moved at 0.20 m/s for 7.00 s is 14.2m/s.

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Suppose a particular spectral line has a wavelength of 500 nm in the lab. If you look at the spectrum of star A, you see this line at 480 nm. Star B exhibits this line at 510 nm, and the line is measured to be at 530 nm in star C. Which of the following statements is true?
a. Star A is moving the fastest of the three stars.
b. Star A is the only star moving away from us, star B and star C are both moving towards us (with star C moving towards us the fastest)
c. Star C is moving away from us faster than star B, star A is moving towards us.

Answers

c. Star C is moving away from us faster than star B, star A is moving towards us.

Since objects moving away are redshifted, and the amount of redshift tells us the speed, you can see how to tell the speed and direction of an object just by looking at its spectrum.

an object is dropped from a 32m tall building. How fast will it be going when it strikes the ground?

Answers

The total velocity of the object which is thrown vertically from a building of 32m tall in the presence of the air will be 25.04 m/sec.

How fast will it be going when it strikes the ground if an object is dropped from a 32m tall building. ?

If there is no air resistance means that the air resistance is zero, then the formula of the velocity is given by;

velocity = sqrt(2xgravityxheight)

where v represents velocity, h represents distance , g represents gravitational constant, and m represents meters, so here in this case by putting the values we can get this which is below;

velocity = square(2*(9.8m/sec2)*32m)

velocity = square(627.2 m2/sec2)

velocity = 25.04 m/sec.

So we can conclude that the total velocity of the object which is thrown vertically from a building of 32m tall in the presence of the air will be 25.04 m/sec.

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Music is often used to accompany pictures. What type of music would most likely accompany a photo of a kitten looking lonely and lost in the rain?
A. Staccato, Quick and Lively
B. Fast, Upbeat
C. Slow, Legato, Minor Key
D. Major Key, Light-Hearted

Answers

The most common type of music which will be accompanied by a kitten will be slow, legato, and minor key.

What are the different types of music?

Music heals the brain and soul. It should listen at the time of stress. There are different types of music such as slow, fast, and retro music.

When the person is feeling very happy and energetic they usually listen to fast songs. When a person is lost he usually listens slow and Legato music.

In the disco usually fast and upbeat music is played. Algerado is a type of quick and lively music.

Therefore, The most common type of music which will be accompanied by a kitten will be slow, legato, and minor key.

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you notice another ant beginning to walk along a meter stick. curious, you take out a stopwatch and determine the ant’s position on the meter stick. you record the following data: {(0.0 s, 0.0 m), (1.0 s, 0.12 m), (2.0 s, 0.24 m), (3.0 s, 0.36 m), (4.0 s, 0.48 m)}. determine the ant’s speed from the slope of the distance vs. time graph.

Answers

The speed of Ant is  0.12 m / s .

The given data is for Uniform Motion .

Ant ' s speed can be calculated as follows :

Speed = Distance / Time

v = s / t

s ₁ = 0.12 m

t ₁ = 1.0 sec

v ₁ = 0.12 / 1.0

v ₁ = 0.12 m / s

s ₂ = 0.24

t ₂ = 2.0 sec

v ₂ = 0.24 / 2.0

= 0.12 m / s

So , the speed of Ant is  0.12 m / s .

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Question 1
Which of the following is NOT a possible reason for personalty differences?
Culture
Experience
Heredity
Diet

Answers

Answer:

diet

Explanation:

Jupiter has a mass of 1.9 × 1027 kg and in its orbit around the Sun has a speed of 13 km/s. Calculate the kinetic energy possessed by the Jupiter because of its orbit around the Sun. Give your answer to 2 significant figures.

Answers

Answer:

Explanation:

KE = 1/2mv²

KE = 1/2(1.9x1027)(13)

KE = 12683.45 J

KE = 13000 J (2 sig figs)

on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. what is the velocity (speed and direction) of the air relative to the runner?

Answers

Velocity is the rate of change of position of an object. The velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

What is Velocity?

Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.

Given that on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. Therefore, the velocity of the air relative to the runner can be written as,

Relative velocity = √[(Velocity of the jogger)² + (Velocity of the air)²]

                            = √[(5)² + (5)²]

                            = √(25 + 25)

                            = √50

                            = 5√2 m/sec

The direction of the relative velocity is,

The angle of relative Velocity = Tan(θ)

Tan(θ) = Vertical velocity / Horizontal velocity

Tan(θ) = 5/5

Tan(θ) = 1

θ = tan⁻¹(1)

θ = 45°

Since this angle is formed between the two velocities, therefore, the direction of the velocity is southwest.

Hence, the velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

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help me pleaseeeeeee

Answers

The unit conversion of 1.5 x 10⁸ Gm to m =  1.5 x 10¹⁷ m.

The unit conversion of 2.6 x 10⁻⁵ nm =  2.6 x 10⁻²⁰ Mm.

The unit conversion of 2.72 x 10⁻⁵ μm =   2.72 x 10⁻¹¹ m.

The unit conversion of 2.56 x 10⁻³ cm =  2.56 x 10⁻⁸ km.

The unit conversion of 2 hr =  7,200 seconds.

The unit conversion of 2 h 30 min  = 9,000 seconds.

What is unit conversion?

Unit conversion involves the change of unit of a substance from one base to another.

Converting 1.5 x 10⁸ Gm to m

1.5 x 10⁸ Gm = 1.5 x 10⁸ x 10⁹ m = 1.5 x 10¹⁷ m

Converting 2.6 x 10⁻⁵ nm to Mm

2.6 x 10⁻⁵ nm = 2.6 x 10⁻⁵ x 10⁻⁹ x 10⁻⁶ m = 2.6 x 10⁻²⁰ Mm

Converting 2.72 x 10⁻⁵ μm to m

2.72 x 10⁻⁵ μm =  2.72 x 10⁻⁵  x 10⁻⁶ m =  2.72 x 10⁻¹¹ m

Converting 2.56 x 10⁻³ cm to km

2.56 x 10⁻³ cm = 2.56 x 10⁻³ x 10⁻² m x 10⁻³ km/m = 2.56 x 10⁻⁸ km

Converting 2 hours to seconds

2 hr = 2 x 3600 s = 7,200 seconds

Converting 2 h 30min to seconds

2 h 30 min = 7,200 seconds + 1800 s = 9,000 seconds

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A net force of 34 N is applied to accelerate an object at a rate of 2.5m / (s ^ 2) What is the mass of the object?

Answers

Answer:

F = M a         Newton's Second Law

34 kg m / s^2 = M * 2.5 m / s^2

M = 34 / 2.5 kg = 13.6 kg

How much time in minutes will it take a car driving at 90 km/hr to travel 27 kilometers?

Answers

Answer:

18 minutes

Explanation:

There is a speed and distance calculator online so you can check the answer! :) Have a great day!!! >-<

I use a rope 2.00 m long to swing a 10.0-kg weight around my head. The tension in the rope is 20.0 N. In half a revolution how much work is done by the rope on the weight?

Answers

According to the given assertion, the work done during half revolution also will be equal to zero.

Why is effort done inside a circle equal to zero?

When a body is spun in a circle, the work done equals zero because displacement in circular motion is always perpendicular to the applied force. Also, when a body moves in a circular direction, the centripetal force works along the radius of the circle and is perpendicular to the body's motion.

What is the work-done calculation formula?

The following equation can be used to determine work: Work equals Force x Distance. The joule (J) or Newton meter (N m) is the SI unit for labor. One joule is the amount of work done when one Newton of force pushes an object one meter.

Briefing:

The work done by the centripetal force is always zero since force and instantaneous displacement are always perpendicular. As a result, effort done in half revolution is likewise equal to zero.

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The DEA approves drugs for dispensing in the United States

true or false

Answers

Answer:

false. the DEA does not approve this

Newton's third law explains that for every action force there is an equal and opposite reaction force. In the image below, the arrow represents the force of Earth pulling down on the book. This is also called the force of gravity.



Based on Newton's third law and the force represented by the arrow, what is the reaction force in this scenario?
A.
The force of the book pulling down on the table.
B.
The force of the table pushing up on the book.
C.
The force of the table pushing down on Earth.
D.
The force of the book pulling up on Earth.

Answers

Explanation:

 If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Answer:

The force of the book pulling up on Earth

Explanation:

I did the study island

urgentt i need help What effect does watering plants have on their growth height?

Blank 1: Independent variable

Blank 2: Dependent variable

Blank 3: "If...then..." hypothesis

Answers

Answer:

3

Explanation:

cuz I looked it up

hope you have a good day :)

Which hypothesis cannot be tested experimentally?

Question 13 options:

The average speed of air molecules increases with temperature.


Ghosts are the souls of people who have died.


The structure of any part of the broccoli is similar to the whole structure of the broccoli.


A vegetarian is less likely to be affected by night blindness.

Answers

Ghosts are the souls of people who have died cannot be tested experimentally.

An experiment is a technique used in science to create a discovery, test a theory, or show a known truth. because owing to a lack of technology, we might not be able to analyze souls.Any procedure where measurements are taken and tests are run to support or disprove a hypothesis is referred to as a scientific experiment.The scientific experiment is a component of the scientific method as a whole. This process is a series of sequential processes used to learn new information about any subject.The steps are: making a discovery. posing a query and developing a theory. scientific tests to validate the theory and gather data Analyzing the findings and making judgments presenting the findings

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A car is initially traveling at an unknown velocity. It accelerates constantly
for 5.0 seconds of elapsed time at a rate of 3.0 m/s² to reach a velocity of
30 m/s. What was the initial velocity of the car?
(A) 1.0 m/s
(B) 5.0 m/s
(C) 10 m/s
(D) 15 m/s

Answers

Answer: A

Explanation: No, we put the values S is 200 m and acceleration a is four m per second squared, So this gives us time to equal to 10 seconds

I hope its correct!

A car going initially with a velocity 13.5 m/s accelerates at a rate of 1.9 m/s2 for 6.2 s. It then accelerates at a rate of minus2.5 m/s2 until it stops. What is the total time from the start of the first acceleration until the car is stopped? (Write your answer to two decimal places and do not write unit)

Answers

The total time from the start of the first acceleration until the car is stopped is 16.31 s

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

How to determine the final velocity in the first 6.2 s Initial velocity (u) = 13.5 m/sAcceleration (a) = 1.9 m/s²Time (t) = 6.2 s Final velocity (v) = ?

a = (v – u) / t

1.9 = (v – 13.5) / 6.2

Cross multiply

v – 13.5 = 1.9 × 6.2

v – 13.5 = 11.78

Collect like terms

v = 11.78 + 13.5

v = 25.28 m/s

How to determine the time taken for the car to stop Initial velocity (u) = 25.28 m/sFinal velocity (v) = 0 m/sAcceleration (a) = -2.5 m/s² Time (t) =?

a = (v – u) / t

Thus,

t = (v – u) / a

t = (0 – 25.28) / -2.5

t = -25.28 / -2.5

t = 10.112 s

How to determine the total timeTime for accelerating = 6.2 sTime for decelerating = 10.112 sTotal time =?

Total time = 6.2 + 10.112

Total time = 16.31 s

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1. An object is thrown straight up into the
air with an initial velocity of 20m/s. For how
long will the ball be in the air?
9.81s
O4s
O 18s
O 80s

Answers

If the ball is thrown straight up into the air with an initial velocity of 20m/s, it will be in the air for 4.08 s

a = v / t

a = Acceleration

v = Velocity

t = Time

v = 20 m / s

a = 9.81 m / s²

t = 20 / 9.81

t = 2.04 s

This is the time taken to reach the farthest height the ball will raise. It takes the equal amount of time to reach the point from where it was thrown from.

T = 2t

T = Total time taken

T = 2 * 2.04

T = 4.08 s

Therefore, the ball will be in the air for 4.08 s

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Felix steals second base running at a speed 4.2 m/s. He slides into second base at a speed of

Answers

The resultant displacement such that Felix steals second base running at a speed 4.2 m/s and slides into second base at a speed of 5.8 m/s is 10 meters.

What is average velocity?

Average velocity is a physical quantity which refers to the average of the velocity it takes to compete certain displacement.

It is calculated by adding two velocities and dividing by net time taken.

What is displacement?

Displacement is a physical quantity which refers to the shortest possible distance between two points. Displacement drawn is generally a straight line until space curvature starts.

Given:

Speed in first base = 4.2 m/s

Speed in second base = 5.8 m/s

Time taken for first base = 0.5 seconds

Time taken for second base = 1.5 seconds

Average velocity = (4.2+5.8)/2

Average velocity = 5 m/s

Total time taken = 2 seconds

Average displacement = average velocity × total time taken

Average displacement = 5 × 2

Average displacement = 10 meter

Therefore, resultant displacement such that Felix steals second base running at a speed 4.2 m/s and slides into second base at a speed of 5.8 m/s is 10 meter.

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A rocket, initially at rest, steadily gains speed for 3.30s while traveling upwards
60.0m.
What was the rocket's final speed?
unit

Answers

Answer:11 2.5 Motion Equations for Constant Acceleration in One Dimension

Explanation:

How many seconds would it take to travel 20 miles at an average velocity of (25miles)/(hour)?

Answers

36.7 feet per second


The arrows in the figure represent the
gravitational force between marbles that have
equal mass.
How should the force arrows look if a marble
that has greater mass replaces one of these
marbles?
A. Both arrows should be drawn longer.
B. Both arrows should stay the same length.
C. The arrow from the marble with less mass
should be longer than the other arrow.
D. The arrow from the marble with less mass
should be shorter than the other arrow.

Answers

Option D. The arrow from the marble with less mass should be shorter than the other arrow if a marble that has greater mass replaces one of these marbles.

Force arrows are used to show both the magnitude and direction of forces. The length of the arrow corresponds to the magnitude of the force, longer arrows indicate forces of greater magnitude. The direction of the arrow corresponds to the actual direction of the force.

For example if a man pushes a block then the force exerted by that man and the direction of force can be represented as shown in the picture.

Since given figure shows marbles of equal mass therefore the arrows are equal. Further if the marble is replaced by the heavier marble than the arrow size will definitely change.

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Which wave type is a surface wave?
O mechanical
O radio
O light
O electromagnetic

Answers

The answer is B have a good day

Match the particles with their characteristics,

subatomic particles with a positive charge

subatomic particles with a negative charge

subatomic particles with no charge

made of atoms

neutrons

-

>

electrons

protons

molecules

Answers

Any of the different self-contained units of matter or energy that are the building blocks of all matter are considered subatomic particles, also known as elementary particles.

Match the particles with their characteristics.

Subatomic particles with a positive charge. - Protons.Subatomic particles with a negative charge. - Electrons.Subatomic particles with no charge. - Neutrons.Made of atoms. - Molecules.

The heavier constituents of the atom's small, but incredibly compact nucleus, the positively charged protons and the electrically neutral neutrons, are subatomic particles, as are the negatively charged, practically massless electrons that make up the majority of the atom's size.

In 1911, Rutherford demonstrated that the majority of an atom's mass is contained in its tiny nucleus, at the center of the atom, revealing the fundamental structure of the atom. Rutherford proposed that the nucleus of the atom, which is dense and positively charged, orbits the lighter, negatively charged electrons in a manner similar to how the planets do around the Sun.

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In 8.0 seconds a truck accelerates 5.7 m/s² to 57.7 m/s. How fast was the car going before it accelerated? (Round to one decimal place ex
14.1)

Answers

Answer:

12.1 m/s

Explanation:

If the car is gaining 5.7 meters per second of speed for 8 seconds then we need to multiply 5.7 by 8. this gives us 45.6

Now all we need to do is subtract 45.6 from 57.7. This is 12.1

If metal cube of side 10 cm at temperature 27° are putted on oven at temperature 227° if expansion Coefficient is 0.000011 c^-1 find the extension volume

Answers

The expansion volume of the metal cube is determined as 2.2 cm³.

Volume of expansion of the metal cube

The volume of expansion of the metal cube is calculated as follows;

ΔV = V₀αΔT

where;

V₀ is the initial volume of the metal cubeΔT is change in temperatureα is expansion coefficient

ΔV = (10 cm)³ x (0.000011)(227 - 27)

ΔV = 2.2 cm³

Thus, the expansion volume of the metal cube is determined as 2.2 cm³.

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I need to sketch force diagram
This problem is already solved

Answers

The free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

What is free body diagram?

Free body diagram refers to the formation of a system showing all the possible forces that are being exerted on the body isolating it from the surrounding.

What is system and surrounding?

System refers to the object of inspection i.e. the thing that is being noted down a system can be anything from an object to multiple objects and even surrounding whereas surrounding is everything else that is not a part of the system.

We have been already given all the required inputs that will help us to create a free body diagram including:

Friction force on the body being = 12 Newton

Weight of the body = 15 Newton

Normal acting on the body = 9 Newton

To create the free body diagram we simply isolate or from the surrounding and consider it to be a system then help of the vectors we will create the system consisting of the body and all the possible forces that acting on it.

We now draw the vectors for friction force weight of the body and normal acting on the body to get our required free body diagram.

Therefore, the free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

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Two construction workers are attempting to pull a slab of concrete off of the ground. Each of the workers are pulling up with a force of 225 N, while the
slab of concrete applies a gravitational force of 400 N in the opposite direction, remaining stationary.
If the pulling forces applied to the slab of concrete are assigned a positive value, what is the net force of the scenario, and in which direction will the slab
of concrete move?
(1 point)
O -50 N, the slab will remain stationary
O-175 N; the slab will remain stationary
O 50 N; the slab will move upward
O 175 N; the slab will move upward

Answers

The net force of the scenario, and in which direction will the slab of concrete move 50 N the slab will move upward.

What is the gravitational force?

Newton's universal law of gravitation states that the force of attraction between any two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Briefing:

The forces acting on the slap concrete are three, namely:

400 N of gravitational force

225 N of pulling force was used by one construction worker.

225 N of pulling force was used by two construction worker.

Thus, the force that results can be calculated as follows:

225 + 225 - 400 = 50 N

50 N of positive force is the outcome. The slab will therefore rise, as a result.

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