The SI units for position, velocity, and acceleration are, respectively: Question 11 options: m, m/s, m/s^2 kg, m/s, m^2/s m, m/s, m^2/s kg, m/s, m/s^

Two satellites are placed in geosynchronous orbits, orbits with a period of 24 hours, where each satellite hovers over a spot on the earth's equator. satellite b has three times the mass of satellite a

F(b) = 3 F(a) is the relationship between the magnitudes of the gravitational forces of the earth on the two satellites.

A satellite is a body that orbits a planet, star, or moon. For instance, the fact that Earth circles the sun makes it a satellite. The moon is a satellite as well since it revolves around Earth. The term "satellite" often refers to a device that is sent into space and orbits the Earth or another celestial body.

Given that,

two satellites a and b are placed in geosynchronous orbits, orbits with a period of 24 hours.

Gravitational force is given by,

F = (G × M × m) / r²

Where, G = gravitational constant

M = Mass of the earth

m = mass of the satellite

r = distance between earth and satellite.

So, m(b) = 3 m(a) and r(a) = r(b)

Thus, F(a) = [(G × M × m(a)] / r(a)²

F(b) = [(G × M × m(b)] / r(b)²

or, F(b) = [(G × M × 3m(a)] / r(a)²

or, F(b) = 3[(G × M × m(a)] / r(a)²

or, F(b) = 3 F(a)

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Answer:

The battery is connected to a series-parallel combinationof capacitors.The two rightmost paralle

-35.39dB is the intensity level of the sound for the more distant listener relative to that for the nearer listener

By using the inverse square law,

As one listener is 49.5 times farther away from the source of the sound than the other.

Then Increasing the distance by 49.5 times reduces the intensity by

= 3453.8 times

The intensity level of the sound (in decibels) for the more distant listener relative to that for the nearer listener is:

= 10log(ratio of intensities)

= 10log(1/3453.8)

= 10log(0.000289)

=10 × -3.539

= -35.39dB (The negative sign represents the sound is less intense for the farther listener)

So, the intensity level of the sound (in decibels) for the more distant listener relative to that for the nearer listener is -35.39dB

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The final speed of cars, when the collide and stick together, will be 1.1m/s

Linear momentum is the vector quantity and it happens when a particle moves with some velocity.

Thus, linear momentum = mass × velocity.

For an isolated system, the system's total momentum will remain unchanged.

The expression for the initial momentum is given by

p1=mv1+mv2

here, p is the total initial momentum of the system

it is given that both cars stick together after the collision, so the final velocity of each car will be the same

The expression for the final momentum is given b

pf=mv+mv

So, equating total initial and final momentum

pi=pf

v1+mv2=mv+mv

v=v1+v2/2

Substitute,

v=2.2m/s+0/2

v=1.1m/s

Thus, the final speed of each car is 1.1.m/s

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The read of a scale when a piece of brass is submerged in water (and its apparent weight) can be determined using the following formula: W App = 242N.

Brass weakens and lost its zinc component quite quickly when immersed in water, endangering the metal's structural integrity. Due of its incredible endurance, brass is a superb metal for various applications other than those in which it is submerged in water.

Brass tarnishes when exposed to moisture, whether from being used in the bath or from perspiration on our bodies. This is a very normal occurrence. Jewelry made of brass metal occasionally develops a darker patina as it ages. A coating of the brass is covered in patina, which is a greenish tint.

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1.57 rad/s is the angular velocity of the hoop about its center of mass.

Solution:

Given that

Weight of hoop m = 1.2 kg

radius of  hoop R = 65 cm = 0.65 m

Force = 7 N

Torque on the hoop Τ = F×R        →equation (1)

Where F is applied force on hoop

We also know that

Τ = Iα[tex]R^{2}[/tex]

Where α is the angular acceleration

I is the moment of inertia of hoop

For hoop    I = m[tex]R^{2}[/tex]

T =  (m[tex]R^{2}[/tex])α           →equation (2)

From equation 1 and 2

FR = (m)α

F = mRα

α = F/mR

α = 7/1.2×0.65 = 3.79 rad/s×s

α= 3.79 rad/s×s

We have to calculate distance covered  by center of hoop in 5 s

d = (1/2)at×t                 →equation(3)

Relation between linear acceleration and radius is

a = αR

a = 3.79×0.65

a = 2.46 m/s×s

now from equation (3)

d = 0.5×2.46×4×4

d = 19.68 m

so the  distance covered by center of hoop in 4 s is 19.68 m.

Part(2)

angular velocity of hoop

angular momentum about the center of the hoop

w = v/R

ωt = 2×π

t is  given 4 s

ωt   = 6.28

ω×4= 6.28

ω = 1.57 rad/s

Hence,  1.57 rad/s is the angular velocity of the hoop about its center of mass.

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Ampere. A ____ is one thousandth of an amp. the current utilized for face and scalp treatments is measured in milliamperes.

The electrical potential difference is measured in volts. The force that propels electrons across an electrical circuit to create an electric charge that is measured in amperes is another way to define volt. Amperes are units used to quantify electric current, or even the number of electrons moving across a circuit.

He developed the astatic needle, an indispensable facet of the contemporary astatis galvanometer, that was the first to show that a magnetic field is produced when parallel wires are electrically charged. He is usually acknowledged as the first to develop electromagnetic.

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V1 = (1.2 A)(2 ) = 2.4 volts is the voltage across R1.V2 = (1.2 A)(3 ) = 3.6 volts is the voltage across R2.V3 = (1.2 A)(5 ) = 6.0 volts is the voltage across R3.

We can use Ohm's Law (V = I x R) to determine actual voltage drops over each resistor once we have the amperage for such circuit (remember that the amperage doesn't really change inside a series circuit).

According to Ohm's Law, V=I*R, where V stands for voltage, I for current, and R for resistance.The power loss across each resistor in a series circuit will be inversely correlated with its size.The voltage drop over each resistor in a parallel connection will be equal to the voltage coming from the power source.

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Radio waves have the electromagnetic spectrum's longest wavelengths. Radio waves have wavelengths that are longer than one millimeter.

A waveform signal that is propagated in space or along a wire has a wavelength, which is the separation between two identical points (adjacent crests) in the adjacent cycles.

The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below. The wavelength for 300 GHz is 1 mm, while the wavelength for 30 Hz is 10,000 kilometers.

So,

Radio waves have the electromagnetic spectrum's longest wavelengths. Radio waves have wavelengths that are longer than one millimeter.

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The closest you can be to speaker B and be at a point of perfectly destructive interference- 1.008m.

The wavelength of sound emitted by speakers

= velocity / frequency

= 344 / 172

= 2 m

For destructive interference , path difference is equal to odd multiple of  half the wavelength .

path difference = 2 / 2 = 1 m

d₂ - d₁ = 1 m

d₂ = d₁ + 1 m

d₂ = .008 m + 1

 d₂ = 1.008 m

So, the closest you can be to speaker B and be at a point of perfectly destructive interference- 1.008m.

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The complete question is:

Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 172 HzHz. You are 8.00 mm from speaker A. Take the speed of sound in air to be 344 m/sm/s. What is the closest you can be to speaker B and be at a point of perfectly destructive interference?

First image:cardiac muscle cell.

Second image: elastic cartilage.

Third image: Pseudo-stratified Columnar Epithelium.

Fourth image: cilia.

Cardiac muscle, a kind of striated, involuntary muscle found solely in the heart, is what allows the heart to pump blood.

Cardiac muscle cells are found in the heart's walls, where they may be seen as being striped (or striated) and controlled by an involuntary process.

Cells in cardiac muscle tissue, or the myocardium, respond to electrical signals from the nervous system by contracting and expanding. Together, these cardiac cells create the wavelike, rhythmic contractions that make up the heartbeat.

Part A:

In the first image, the highlighted structure is cardiac muscle cell.

The cartilage type in the second image is elastic cartilage.

In the third image,  the epithelium indicated by the arrows are pseudo-stratified Columnar Epithelium .

In the fourth image the highlighted structures are cilia.

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The complete question is as follows:

The correct option regarding how many times stronger the wave amplitude A of the earthquake was than the standard wave Ao is given by:

A = 39,811 Ao.

How to obtain the ratio of A and Ao?

To find the ratio of A and Ao, which states how many times a earthquake measuring R in the Richter scale was stronger than the standard intensity Ao, we have to solve the following logarithmic function:

R = log(A/Ao)

The Richter scale of the earthquake in this problem is given as follows:

R = 4.6.

Hence the ratio of the measures is obtained as follows:

4.6 = log(A/Ao)

The power of 10 is the inverse function of the logarithm, hence if it is applied to both sides of the equation, then we can isolate the ratio A/Ao as follows:

A/Ao = 10^4.6

A/Ao = 39,811.

Applying cross multiplication, the ratio is given as follows:

A = 39,811 Ao.

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Since it detects emissions from fires, the flame emission detector in the example is not a radioactive detector.

Which three main categories of radiation detectors are there?

Radiation detectors come in three primary categories. These include semiconductor detectors, gas ionization detectors, and detectors based on scintillation. The ionization chamber, proportional counter, and Geiger-Müller counter are gas ionization-based detectors.

Is Geiger radioactive in reverse?

A low pressure gas is kept in a copper cylinder in an early Geiger counter type while an electrical current passes through it. When a radioactive particle enters a cylinder, an electric current surge occurs, which is recorded on a counter.

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The average flow-rate of gasoline in cm³/s is 2.78 cm³/s to start the engine while travelling at 100 km/h.

In order to decide the Flow Rate represented as Q, we have to outline each the quantity V and the factor in time it's far flowing beyond represented through t, or Q = V/t. Additionally Flow price and pace are associated through the equation Q = Av wherein A is the cross-sectional vicinity of glide and v is its common pace.

Flow is the quantity of fluid that passes in a unit of time. In water resources, glide is regularly measured in gadgets of cubic toes consistent with second (cfs), cubic meters consistent with second (cms), gallons consistent with minute (gpm), or different numerous gadgets.

From the question : Q = v/A'.................... Equation 1

Where Q = Average flow rate, A' = inverse of Area, v = velocity of the car.

Given: v = 100 km/h, A' = 10 km/L

Substitute this value into equation 1

Q = 100/10

Q = 10 L/h.

Now, we convert L/h to cm³/s.

Since,

1 L = 1000 cm³, and

1 h = 3600 s

Therefore,

Q = 10(1000/3600) cm³/s

Q = 2.78 cm³/s

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Answer:

Explanation:

position:  m

velocity:  m/s

acceleration:  m/s²

The amount of distance that was covered by this person is equal to 4 kilometers.

The displacement from the starting point is equal to 2 kilometers to the right.

In Science, distance can be defined as the amount of ground that is covered (travelled) by a physical body or object over a particular period of time and speed, irrespective of its direction, starting point or ending point.

In this scenario, the total distance covered in a straight line by this person can be calculated by adding the distance he ran towards the right direction to the distance he ran towards the left direction as follows:

Distance = xf + x₀

Distance = 3 + 1

Distance = 4 kilometers.

On the other hand (conversely), the displacement of this person would be calculated by subtracting the distance he covered when running back from the distance he covered when running towards the right direction as follows:

Displacement = xf - x₀

Displacement = 3 - 1

Displacement = 2 kilometers to the right.

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The answer is entropy here. It's quite unlikely that spontaneously air molecules moves exclusively to one half of your room. This can be explained by understanding the concept of entropy and second law of thermodynamics.

Entropy is the measure of disturbance or disorder of universe.

The second law of thermodynamics states that entropy of an isolated system doesn't decrease over time.

The second law of thermodynamics is true because there are very few ways that particles can be concentrated in an area. In most situations, the particles are evenly distributed. Similarly, in a room, the particles are evenly distributed and as particles start moving, there is a nonzero probability of  low entropy state, Most of the time the system will increase in entropy that is increase in disturbance evenly. Hence it is not possible that air molecules will collect in one part of the room and not on the other part.

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The force in newtons needed to stretch the spring from its natural length to a length of 20 m is  104 N

As the metal spring expands and contracts, it deviates from its equilibrium position. The result is a restoring force that tends to push the spring back to its original position. This force is called spring force.

Given;

Natural length=10m

Work done to stretch from 10m to 11m =5.2J

so change in length (x)=1m

Work  done on spring(W) = 1/2 *k *x^2

                                        5.2 =1/2*k*1^2

                                   so, k=10.4N/m

Spring is stretch to 20m  so new x=10m

Force needed to stretch the spring = kx = 10.4 *10= 104 N

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The star is in energy balance when its core energy production matches the amount of energy it radiates into space. This is only true when the star is a main-sequence star with a hydrogen core fusion and when it is a helium core-fusion star. It is out of energy balance at all other times, which is why it is either contracting or expanding.

Stars can squeeze various types of atomic fuel together, and it's through this process that we get almost every element in the universe. Stars contain a lot of mass which has a lot of gravity. The gravity pulls inwards, which could cause a star to collapse in on itself. In a main sequence star, this inward pull is balanced by the outward gas pressure due to the nuclear fusion reactions deep in the star's core. This balance is called hydrostatic equilibrium and stops the main sequence stars from collapsing.

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Carbohydrates are the nutrition that matters most during endurance activity. Your muscles and liver both contain glycogen, which is the body's preferred form of energy storage. These stockpiles run low and exhaustion comes in when you exercise for more than 90 minutes.

What kinds of energy are required by endurance athletes?

For endurance sports, carbohydrates are frequently the preferred fuel source, so they take center stage in many athletes' nutrition programs. An additional source of carbohydrates is typically necessary to maintain peak performance because the body burns through its glycogen reserves, even at a pace below maximum

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The seismic waves of the Caracas earthquake were 3162277,66 times more powerful of the standard seismic waves.

What is seismic waves ?

An acoustic energy wave that moves through the Earth is known as a seismic wave. Large landslides, volcanic eruptions, magma movement, earthquakes, and man-made explosions that release a lot of low-frequency acoustic energy can all cause it.

By using formula given above, M= log(w/w_0), we can find

10^M= w/w_0, it means 10^M.w_0,= w

but M=6.5, so 10^6.5=3162277,66

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Answer:

0.21 brokies

Explanation:

The length of the effort arm of a lever divided by the length of the resistance arm represents the optimal mechanical advantage.

effort force = 445/9.5

= 46.84

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The Radiation Pressure on mirror is 15.944N/m² by normal incidence.

All of the light is reflected by a (perfect) mirror, which results in a twofold momentum transfer and twofold radiation pressure.

The spectral reflectance curve shows which frequencies are reflected and absorbed by various colored objects because different colored objects only reflect a portion of the light.

A completely reflective surface will reflect the photon back, changing its momentum twice as much as if it were to merely absorb it.

Because an absorbing surface warms up and then radiates, the situation becomes slightly more complicated. An isotropic radiation pattern results from perfect thermal transfer. So shape and materials are important for absorbers.

It would be possible to determine the radiation pressure using this, which would be somewhere between that of a perfectly black and perfectly mirrored object. In this case, you would additionally need to be familiar with the object's spectral energy distribution.

Radiation Pressure = Flux/c=24.2 x1.97/2.99

=15.944N/m²

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The string is 16 cm long.

What is time period?

Period of simple is given by the equation

[tex]$T=2 \pi \sqrt{\frac{l}{g}}$[/tex]

It will not depend upon angle and mass of ball.

A student with a stopwatch finds that 17 oscillations take 14 s.

So we can find period for 1 oscillation

[tex]\text { Period, } \mathrm{T}=\frac{14}{17}=0.82 \mathrm{~s}[/tex]

Substituting in equation of period

[tex]\begin{aligned}& T=2 \pi \sqrt{\frac{l}{g}} \\& 0.82=2 \pi \sqrt{\frac{l}{9.81}} \\& l=\frac{0.82^2 \times 9.81}{4 \pi^2}\end{aligned}[/tex]

[tex]l=0.16m[/tex]

The string is 16 cm long.

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The actual distance beneath the surface of the beetle in the medium of polystyrene is 3.24cm.

Polystyrene is a synthetic polymer created from styrene, an aromatic hydrocarbon, as its monomers. Solid or foamed polystyrene are both available.

Refractive Index (Index of Refraction) is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density. The refractive index variable is most commonly symbolized by the letter n or n' in descriptive text and mathematical equations.

The equation which shows the relationship between apparent depth and actual depth is

n= d(actua)/d(apparent)

where d (actual)= actual depth of object

           d(apparent)= apparent depth of object

                    n= refractive index of the medium

d(actual)= n*d(apparent)

d(actual)=1.62*2

             =3.24cm

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The resulting angular acceleration of grindstone assuming negligible opposing friction is [tex]82.616 rad/s^{2}[/tex].

Angular acceleration can be defined as the temporal rate at which angular velocity changes. The standard unit of measurement is radians per second square. It is also called rotational acceleration. It is a numerical representation of the variation in angular velocity over time.

A pseudoscalar, angular acceleration, exists. If the angular speed rises counterclockwise, the sign of angular acceleration is taken to be positive; if it grows clockwise, it is taken to be negative. Angular acceleration makes it easier to the motion of rotating objects.

The symbol for angular acceleration in SI units is alpha ([tex]\alpha[/tex]), and it is expressed as radians per second squared ([tex]rad/s^{2}[/tex]).

We know that,

Force on grindstone, F = 288 N

Radius of grindstone, r = 0.275 m

Mass of grindstone, m = 92.2 kg

The grindstone's angular acceleration must be determined. The relationship between torque and angular acceleration in rotational motion is given by:

τ = I x α

α = τ/I

I is the moment of Inertia of solid disk.

I =[tex]\frac{mr^{2}}{2}[/tex]

τ represents the torque exerted

τ = F x r

Thus

[tex]\alpha = \frac{Fr}{\frac{mr^{2}}{2}}[/tex]

[tex]\alpha = \frac{2Fr}{{mr^{2}}}[/tex]

[tex]\alpha = \frac{2(288) F}{(92.2 kg) (0.275^{2} m^{2} )}}[/tex]

[tex]\alpha = 82.616 rad/s^{2}[/tex]

Thus, we can conclude that the angular acceleration of the grindstone is 82.616 [tex]rad/s^{2}[/tex].

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The general equation of simple harmonic motion is

y = a cos (? t )or y = a sin (? t )

but here y = a cos (? t )...because at t=0 amplitude is maximum

Here amplitude 'a '= 0.01 m

m = 0.3 kg

x = 0.02 m

Force constant k is given by,

k = mg / x = 0.3 x 9.8/ 0.02 = 147 N/m

The time period of oscillation is given by ,

T = 2 ? ?( m / k )

? = 2 ? / T = ? ( 147 / 0.3 )

? = 22.1

then y = (0.01m) cos (22.1 t )

In physics, a force is a power that can change the motion of an item. A force can purpose an object with mass to alternate its pace. Pressure also can be described intuitively as a push or a pull. A force has both value and path, making it a vector quantity.

A pressure is a push or a pull and it affects our each day lives because without force, people might not be capable of open and near stuff or lift up our arms or legs.

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The second average force act at a time interval of 1.1s(1dp)

Impulse of a force is defined as the product of the average force and the time interval for which the force acts on the body.

It is measured in Nm and it is a vector quantity.

impulse is given as force ×time

let F1 represent the first average force and F2 be the second average force.

the time interval for the first average force is 3.2 seconds, therefore the average time interval for the second force will be 3.2/3= 1.1s(1dp)

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With the knowledge of mathematics and with the use of formula, the time interval will be 1.07 s

Impulse can be defined as the product of force and time. Impulse is the same as change of momentum.

Given that one average force has a magnitude that is three times as large as that of another average force. That is,

F = 3f  ....... (1)

If both forces produce the same impulse of 3 N.m. The average force acts for a time interval of 3.2 s. For what time interval does the other average force act?

Impulse = force × time

If both forces produce the same impulse of 3 Nm

For first average force F,

3 = F × T

F = 3/T

For second average force f

3 = f × t

f = 3/t

Substitute both F and f into equation 1

F = 3f

3/T = 3(3/t)

Given that t = 3.2 s

Then, 3/T = 9/3.2

Cross multiply

9T = 9.6

T = 9.6/9

T = 1.07 s

Therefore, the first average force will act for time interval of 1.07 s

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A star's color mostly indicates its surface temperature. However, it could also be used to estimate the age of the star.

There are several types of stars according to their colors which include the following;

The O-class stars are often blue in color and they are the hottest while the M-class stars are red in color and their temperatures are very low compared to the others, making them the coldest type of stars.

The color of the star is not a major factor in the estimation of the age of the star though it could be used sometimes.

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