the soil for house plants consists of 12 percent water.if someone wants to plants flower that need 28 percent water in the soil, how many litters of water they need to add to 5 kg of soil?

Answers

Answer 1

1.111 liters of water must be added to 5 kilograms of soil.

How much water we need to add in a soil sample

According to the statement, water percentage is equal to the ratio of water mass divided by the total mass of water and dust and multiplied by 100. Then, the initial and final percentages are defined below:

Initial percentage

y / 5 = 0.12                              (1)

Final percentage

(y + x) / (5 + x) = 0.28             (2)

Then, we need to resolve the resulting system of linear equations:

y = 0.6                  (1)

y + x = 1.4 + 0.28 · x

0.72 · x = 1.4 - y

x = 1.944 - 1.389 · y

x = 1.111

We need to add 1.111 kilograms of water. If the density of a kilogram per liter, the volume required in liters is:

V = (1.111 kg) / (1 kg / L)

V = 1.111 L

1.111 liters of water must be added to 5 kilograms of soil.

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Related Questions

A company orders 13 boxed lunches from a deli for $107.25. If each boxed lunch costs the same amount, how much do 19 boxed lunches cost?

Answers

$107.25/13=$8.25

$8.25*19=$156.75

Hope this helps and I hope it’s right lol

Which is greater, 1/10 or 0.009?

Answers

I think it’s 1/10 because 0.009 is less.

It takes Kim nine hours to paint a fence.
Sarawong can paint the same fence in ten
hours. How long would it take them if they
worked together?

Answers

It would take 19 hours

¿Cuánto recorre aproximadamente una rueda que da 60 vueltas si ésta tiene un radio de 0.20 m?
O 75m
O 38m
O 24m
O 1.3m

Answers

La rueda recorre una distancia de 75.420 metros tras 60 vueltas. (Correct choice: A)

Cuánta distancia recorre una rueda que da 60 vueltas?

La rueda se desplaza sobre el suelo mediante un tipo de movimiento conocido como rodadura, en la que la rueda experimenta rotación y traslación, cuyo centro instantáneo de rotación es el punto de contacto entre la rueda y el suelo.

Si no existe deslizamiento de la rueda con respecto al suelo, entonces la distancia recorrida tras una revolución de la rueda (s), en metros, es descrita por la siguiente ecuación:

s = 2π · r         (1)

Donde r es el radio de la rueda, en metros.

Si tenemos que r = 0.20 m, entonces la distancia recorrida es:

s = 2π · (0.20 m)

s ≈ 1.257 m

Asimismo, la distancia recorrida es directamente proporcional al número de revoluciones de la rueda es y la distancia recorrida tras 60 vueltas es determinada por regla de tres simple:

S = 60 vueltas × (1.257 m / 1 vuelta)

S = 75.420 metros

La rueda recorre una distancia de 75.420 metros tras 60 vueltas.

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can someone explain this problem step by step

Answers

step 1: set your equations equal to DEF which is 76 (2x + 12 + 5x - 6 = 76)
step 2: find the x value by simplifying (x = 10)
step 3: find DEG by plugging in x (2(10) + 12 = 32)
step 4: find GEF by plugging in x (5(10) - 6 = 44)
Answer: mDEG = 32 and mGEF = 44

Jane decided that she would spend the rest of her money on taffy about how many pounds of taffy did jade purchase

Answers

you forgot to add the units.

Please solve this help me

Answers

Answer:

2

does that help?

which of the following is a flat surface that extends infinitely, has length and width but does not have depth

Answer:Plane
reason:i took the test and passed​

Answers

A plane is a flat surface that has length and width but no depth and can extend indefinitely.

In two dimensions, a plane has no limits. It has no thickness at all. A coordinate plane is an illustration of a plane. In the coordinate plane, a type of geometric plane, we plot points. A number line that runs up and down forever and one that runs from left to right indefinitely both exist on the coordinate plane. There are many different kinds of planes, including intersecting and parallel ones. In cursive writing, the upper case letter P stands for a plane.

What kinds of planar geometry are there?

Flat forms are also known as plane geometric figures, which include 2-dimensional shapes including squares, rectangles, triangles, and circles. Contrarily, 3-dimensional geometric forms such a cone, cube, cuboid, cylinder, etc. are used in solid geometry.

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Answer: freee points?

Step-by-step explanation: You gave the answer to your own question.

What is the point-slope form of the line with slope

2
5
that passes through the point
-
4
,

-
7
?

Answers

The equation, in point-slope form, matches the graphed line is y + 7= 2/5(x - 4)

How to determine what equation, in point-slope form, matches the graphed line?

The point on the line is given as

Point = (4, -7)

The slope (m) of the line is given as

m = 2/5

The linear equation is then represented as

y - y1 = m(x - x1)

So, we have

y + 7= 2/5(x - 4)

Hence, the equation, in point-slope form, matches the graphed line  is y + 7= 2/5(x - 4)

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Which three lengths CANNOT be the lengths of the sides of a triangle?
13 m, 13 m, 12 m
5 m, 10 m, 6 m
24 m, 16 m, 11 m
20 m, 6m, 9 m

Answers

answer: 20m, 6m, 9m

explanation:

the two shortest sides of the triangle need to add up to equal more than the longest side. to find this we can test all the answers:

13, 13, 12: 13+12 = 25 25 > 13 (works)

5, 10, 6: 5+6 = 11 11 > 10 (works)

24, 16, 11: 16+11 = 27 27 > 24 (works)

20, 6, 9: 6+9 = 15 20 > 15 (doesn’t work)

so the answer is the last one.

hope this helped! :)

no need for the top part just the bottom

Answers

Answer:

2a.The difference is that question 1b has been ordered by PEDMAS

2b. The fact that Add(A) comes before Subtract(S).

2c. The order of the subjects in Bidmas.

Step-by-step explanation:

Write an equation to represent the real world problem below.


The area of a rectangle measures 9/14 ft^2. It has a length of 3/7 of a foot and a width of 1 1/2 feet.

Answers

The equation which represents the real world problem involving a rectangle as described in the task content is; 9/14 = 3/7 × 3/2.

What is the equation which represents the real world problem as given in the task content?

It follows from the task content that the equation which represents the real world problem involving a rectangle be determined.

It follows from plane shape measures that the area of a rectangle is;

Area = length × width.

Hence, from the parameters given; we have;

Area = 3/7 × 1 1/2

Area = 3/7 × 3/2

Ultimately, the model according to the given parameters which hold true is;

9/14 = 3/7 × 3/2.

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663 divided by 51 step by step

Answers

Answer:13

Step-by-step explanation:51 goes into 66 one time so 66-51=15

then 153/51=3 so 13

Step-by-step explanation:

51 goes into 66 one time so 66-51= 15 then 153/51 = 3 so 13

Parker has a credit card that has an APR of 21.99%. If Parker’s average daily balance for the month is $742, what is the finance charge? If Parker’s balance at the end of the month is $920, what will the new balance be after including the finance charge?

Answers

The finance charge is $13.60, whereas the new balance at the end of the month is  $933.60

What is the finance charge on the credit card balance?

The finance charge which is the monthly interest payable on the credit card balance is based on the average daily balance for the month, it is determined as the  average daily balance for the month multiplied by the annual percentage rate(APR) divided by 12 , since the requirement is to compute one month finance charge and not for a whole year

finance charge=$742*21.99%/12

finance charge=$13.60

The new balance is the balance at the end of the month plus the finance charge

new balance=$$920+$13.60

new balance=$933.60

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Answer:

13.60

933.60

Step-by-step explanation:

To determine the finance charge, use the formula:

FinanceCharge=APR12×AverageDailyBalance

Substitute 21.99% for the APR, and $742 for the average daily balance, and calculate:

FinanceCharge=0.219912×$742=$13.60

So, the finance charge will be $13.60

Next, determine the new balance by adding the finance charge to the balance at the end of the month:

$920+$13.60=$933.60

The new balance will be $933.60

Adventure Travel has an Adjusted Trial Balance for Year Ended December 31, 20XX with the following account balances:

DEBITS: Cash: 25,000; Accounts Receivable: 15,000; Office Supplies: 4,300; Office Equipment: 29,600

CREDITS: Accumulated depreciation - office equipment: 5,000; Salaries Payable: 2,800; Long-term notes payable: 22,200; Common Stock: 20,000; Retained Earnings: 10,260

DEBIT: Cash Dividends: 1,000

CREDITS: Fees Earned: 75,000

DEBITS: Salaries Expense: 32,800; Rent Expense: 16,800; Depreciation expense - office equipment: 3,960; Advertising expense: 4,000; Office supplies expense: 2,800.

Total Debits = 135,260; Total Credits = 135,260

You have prepared the Income Statement and the Statement of Retained Earnings, now it is time to prepare the Classified Balance Sheet.

What amount do you report for Total Liabilities? Specify as a whole number.

Answers

The  amount to  report for Total Liabilities of Adventure Travel is $25,000

What are total liabilities?

Total liabilities refer to the obligations of Adventure Travel  which are due for payments in the short term and long-term, in essence, we are considering both current and non-current liabilities such as Salaries Payable and  Long-term notes payable, the former is the current liability since it is due within one year whereas the latter is non-current liability because its repayment date is beyond one year

Total liabilities= Salaries Payable+Long-term notes payable

Salaries Payable=$2,800

Long-term notes payable=$22,200

Total liabilities=$2,800+$22,200

Total liabilities=$25,000

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Find the actual width of a building if the model of the building is 7 cm wide by 58.7 cm long and the actual length of the building is 140.9

Answers

Answer:

16.8

Step-by-step explanation:

Set up a proportion.  

w = width and l = length

I would put the length and the width of the model in the first fraction and the length of the actual building on the right.

[tex]\frac{w}{l}[/tex] =[tex]\frac{w}{l}[/tex]

[tex]\frac{7}{58.7}[/tex] = [tex]\frac{w}{140.9}[/tex]  Multiply both sides of the equation by 58.7 and 140.9 and you get:

140.9(7) = 58.7x

986.3 = 58.7x  Divide both sides by 58.7

16.8023850085 = x  I will round to the nearest tenths' place

16.8

At the movie theatre, child admission is $5.80 and adult admission is $9.30 . On Wednesday, 122 tickets were sold for a total sales of $893.10 . How many child tickets were sold that day?

Answers

The number of child ticket sold on that day is 69.

How to find the number of ticket sold using variables?

At the movie theatre, child admission is $5.80 and adult admission is $9.30 . On Wednesday, 122 tickets were sold for a total sales of $893.10 .

Therefore,

let use variables to represents the number of child and adult tickets sold.

let

variable x = number of child ticket sold

variable y = number of adult tickets sold

Therefore,

5.80x + 9.30y = 893.10

x + y  = 122

multiply equation(ii) by 5.80

5.80x + 9.30y = 893.10

5.80x + 5.80y = 707.6

3.5y = 185.5

y = 185.5 / 3.5

y = 53

Therefore,

x = 122 - 53

x = 69

Hence, the number of child ticket sold on that day is 69.

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A person 54 inches tall is standing 13 feet from a streetlight. If the person casts a shadow 96 inches ​long, how tall is the​ streetlight?

Answers

The required height of the streetlight is 11.5 feet.

Given that,
A person 54 inches tall is standing 13 feet from a streetlight. If the person casts a shadow 96 inches ​long, how tall is the​ streetlight is to be determined.

What is the Ratio?

The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.

Here,
Let the
13 feet = 13 * 12 inch = 156 inches
Ratios of height and distance would be equal
54 / 96 = x / 96 + 156
54 * 252/96 = x
x = 138 inches
x = 11.5 feets

Thus, the required height of the streetlight is 11.5 feet.

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Which expression is equivalent to



A:4x
B:4x+4
C:x^2+7x+10
D:-x^2-5x-6

Answers

The expression equivalent to [tex](x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})][/tex] is  option (A) 4x.

As per the question statement, we are given with an expression  [tex](x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})][/tex].

We are required to simplify the above mentioned expression.

To solve this question, let us simplify the expression, part by part.

First, We are considering the part (x² + 6x + 8), which can be rewritten as

[tex][( (x^{2} + 6x + 9) - 1][/tex]...(1)

Now, [tex](x^{2} +6x +9)=[(x)^{2} +(2*x*3)+(3)^{2}][/tex]...(2)

Comparing [tex][(x)^{2} +(2*x*3)+(3)^{2}][/tex] with the standard form of

[(a + b)² = (a² + 2ab + b²)], we get, (a = x) and (b = 3).

Therefore, [tex][(x^{2} +6x +9)=(x+3)^{2}][/tex], then,

[tex][( (x^{2} + 6x + 9) - 1] = [(x+3)^{2} -1]\\or, (x^{2} + 6x + 8)=[(x+3)^{2}-(1)^{2}][/tex]...(3)

Again, comparing [tex][(x+3)^{2}-(1)^{2}][/tex] with the standard expansion of

[(c²- d²) = (c + d)(c -d)], we get, [(x + 30 = c] and (d = 1).

Therefore, [tex][(x+3)^{2}-(1)^{2}]=[(x+3+1)(x+3-1)][/tex]

[tex]or, (x^{2} + 6x + 8) = (x+4)(x+2)[/tex].

Using the simplified value of (x² + 6x + 8) in the expression  [tex](x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})][/tex], we get,

[tex](x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=(x+2)+[4x-\frac{(x+4)(x+2)}{(x+4)} ]\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=(x+2)+[4x-(x+2)]\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=(x+2)+[(4x-x)-2]\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=(x+2)+(3x-2)\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=[(x+3x)+(2-2)]\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=4x[/tex]

Expression: Mathematical statements, that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between are known as expressions

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pls answer just alittle bit helps alot​

Answers

A’ = {2,4,6}
B’={1,3}
C’={3,5}
A’ n B’={null}
A’u B’ ={1,2,3,4,6}
A’u B={2,4,5,6}
A u B’ ={1,3,5}
A n B’ ={1,3}
(A n C)’ = {null}
(A u B)’ = {null}



Not too sure but that should be correct

12 is a multiple of 3 and 6

Answers

Yes, 12 is a multiple of 3 and 6.

3•4=12 and 6•2=12.
Answer:
Mhm!! 12 is a multiple of 3 and 6.

Explanation:
3*4=12
2*6=12

How much pure acid should be mixed with 5 gallons of a 70% acid solution in order to get a 90% solution?

Answers

Answer:

You will need 10 gallons of pure acid to mix with 5 gallons of a 70% acid solution to get a 90% solution.

Step-by-step explanation:

.70(5) + x = .90(x + 5)  I want to multiply both sides by 100 to clear the decimal

70(5) + 100x = 90(x + 5) Distribute the 70 and the 90

350 + 100x = 90x + 450  Subtract 90x from both sides

350 + 10x = 450  Subtract 350 from both sides

10x = 100  Divide both sides by 10

x = 10

Julia bought a blouse for $18.25 and a skirt for $22.40. If she received a 10% discount for the skirt and the sales tax rate is 7.25%, how many dollars did she pay?

Answers

well, let's take a looksie, hmmm she got the skirt for 22.40, but but but, she got a discount of 10% on that hmmm how much will that be?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{10\% of 22.40}}{\left( \cfrac{10}{100} \right)22.40}\implies 2.24~\hfill \underset{\textit{sale price for the skirt}}{\stackrel{22.40~~ - ~~2.24}{20.16}}[/tex]

so now, if we add the price of her blouse that'd be a total of 18.25 + 20.16 = 38.41, from that she paid a tax of 7.25%, so

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7.25\% of 38.41}}{\left( \cfrac{7.25}{100} \right)38.41} ~~ \approx ~~ 2.78~\hfill \underset{final~price}{\stackrel{38.41~~ + ~~2.78}{\approx \text{\LARGE 41.19}}}[/tex]

Two boats leave a port at the same time and travels five kilometer per hour on a bearing of 460 degrees the other travels at 9km/hr on a bearing of 127degrees how far are the apart

Answers

Step-by-step explanation:

460=100 degrees

therefore a 27 degree distance between speeds

a^2=b^2+c^2-2bc cos A

a^2=9^2+5^2-2(5)(9)cos 27

=45.8

a=6.77 km/h away

I think you wrote 460 wrong also you can't calculate distance if you don't have the time they have travelled for so I gave you a speed.

The accountant for Jean’s Dress Shop prepared the following cash budget. Jean’s desires to maintain a cash cushion of $10,000 at the end of each month. Funds are assumed to be borrowed and repaid on the last day of each month. Interest is charged at the rate of 1 percent per month.

Answers

The completion of Jean's Dress Shop's cash budgets for the following months is as follows:

Cash Budget                                     July            August        September

Section 1: Cash receipts  

Beginning cash balance               $25,000      $10,000        $10,000

Add cash receipts                           90,000      100,000        120,300

Total cash available                     $115,000     $110,000      $130,300

Section 2: Cash payments  

For inventory purchases              $82,750        $70,115       $87,076

For S&A expenses                         27,250         30,280          30,716

For interest expense                               0                 50                54.45

Total budgeted disbursements $110,000     $100,445      $117,846.45

Section 3: Financing activities  

Surplus (shortage)                        $5,000     $9,555       $12,453.55

Borrowing (repayments)                5,000   455        ($2,453.55)

Ending cash balance                  $10,000       $10,000       $10,000

What is the Cash Budget?

The Cash Budget is an estimate of an entity's cash flows (cash outflows and cash inflows) over a specific period.

The Cash Budget can be prepared monthly, quarterly, semi-annually, or yearly.

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Question Completion:

Complete the cash budget by filling in the missing amounts.

Cash Budget                                     July            August        September

Section 1: Cash receipts  

Beginning cash balance               $25,000  

Add cash receipts                           90,000      100,000        120,300

Total cash available                     $115,000    $

Section 2: Cash payments  

For inventory purchases              $82,750        $70,115        $87,076

For S&A expenses                         27,250         30,280           30,716

For interest expense                               0        

Total budgeted disbursements $110,000  

Section 3: Financing activities  

Surplus (shortage)                        $5,000  

Borrowing (repayments)                5,000  

Ending cash balance                  $10,000        $10,000     $10,000

Simpliy. 24v^4/54v^6 PLease help me ​

Answers

Answer:

0.00001338081

Step-by-step explanation:

24v^4=33176v

54v^6=24794911296

33176v/24794911296v

The two v's cancel out so you have:

331776/24794911296

331776/24794911296=0.00001338081

So, your answer is 0.00001338081.

can anyone tell me what 10(3-8) is in Distributive Property

Answers

Answer:

30 - 80 or -50

Step-by-step explanation:

To distribute numbers, you multiply the term outside of the parentheses with each term inside.

10(3 - 8)

10(3) - 10(8)

30 - 80

10(3-8)
10•3=30
10•8=80
30+80=120

Hopefully this helps

Find the x-intercept and y-intercept from the graph below.

Answers

Answer: ur answer is the 3rd option

Step-by-step explanation:

get smart :)

Answer: the answer is c

Step-by-step explanation: i did it

What is the area in square inches of the shape 2.1 and 6.8

Answers

Answer:

A=7.14

that is the correct answer for this question

Write equivalent fractions for 11/12 and 17/18
using the least common denominator.

Type the fractions, using a slash ( / ) to separate the numerator and denominator.

Answers

The equivalent fraction for [tex]\frac{11}{12}[/tex] and [tex]\frac{17}{18}[/tex] is [tex]\frac{22}{24}[/tex] and [tex]\frac{34}{36}[/tex] respectively.

What is an equivalent fraction?

There are two or more fractions that are equivalent even if their numerators and denominators are different. For instance, 1/2 is the same as (or equal to) 25/50 or 500/1000. Every time, the fraction is written as "one half" in its simplest form.

The equivalent fraction for [tex]\frac{11}{12}[/tex] is -

[tex]\frac{11}{12}[/tex] × [tex]\frac{2}{2}[/tex] =[tex]\frac{22}{24}[/tex]

The equivalent fraction for 17/18 is -

[tex]\frac{17}{18}[/tex] × [tex]\frac{2}{2}[/tex] = [tex]\frac{34}{36}[/tex]

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