Based on the specific gravity of granite, the weight density of granite is 174.72 lbs/ft³.
What is specific gravity?The specific gravity of a substance is the ratio of the density of the given substance to that of the ratio of a reference substance usually water.
Specific gravity is also known as relative density of that substance.
Specific gravity is dimensionless since it is the ratio of two similar quantities.
Considering the given data:
The specific gravity of granite is 2.80.
This means that the ratio of the weight density of granite and that of water is 2.80.
The weight density of water = 62.4 lbs/ft³
The weight density of granite = ?
2.80 = weight density of granite/ weight density of water
The weight density of granite = 2.80 * weight density of water
The weight density of granite = 2.80 * 62.4 lbs/ft³
The weight density of granite = 174.72 lbs/ft³
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A boy eating a banana and riding his bike exhibits which energy transformation?
A weather balloon calibrated at 0.00 °C to have a volume of 12.0 L has what volume at -42.0 °C assuming pressure is held constant?
The new volume of a weather balloon initially calibrated at 0.00 °C to have a volume of 12.0 L is 10.15L.
How to calculate volume?The volume of a given gas at a constant pressure can be calculated using the Charles's law equation as follows:
V₁/T₁ = V₂/T₂
Where;
V₁ = initial volumeT₁ = initial temperatureV₂ = final volumeT₂ = final temperatureAccording to this question, a weather balloon is calibrated at 0.00 °C to have a volume of 12.0 L. The new volume at -42.0 °C assuming pressure is held constant can be calculated as follows;
12/273 = V/231
V = 10.15L
Therefore, 10.15L is the volume of the weather balloon.
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Campher freezes in winter or not?
Answer:
Campher freezes are in winter
There are × 10 grains of sand on the beaches.
How many sand grains make up each beach on the planet Earth?
The Earth has approximately (and we're speaking very roughly here) 7.5 x 1018 grains of sand, or seven quintillions, five hundred quadrillion grains, if you assume a grain of sand has an average size, calculate how many grains are in a teaspoon, and then multiply by all the beaches and deserts in the world.
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It's safe to suppose that after walking for around 30 seconds on a beach, you would have likely passed trillions of sand grains.
Assume a beach has medium-sized sand that is typically 0.3mm in diameter. Of course, the majority of beach sand contains some space because the grains are primarily spherical. So, for the time being, let's suppose a 23% porosity. Accordingly, a beach that is 1 square meter in size and 3 meters deep should be able to accommodate around 163 billion grains of sand. It's possible that the porosity will be as high as about 48%, but don't take my word for it; there's a mathematical maximum that I can't quite recall. The depth of sand at the beach can very much be anything up to maybe even 15-20m, and the sand grain size can vary widely. It's safe to suppose that after walking for around 30 seconds on a beach, you would have likely passed trillions of sand grains.
The complete question is -How many grains of sand are there in a given stretch of an average beach?
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write c or p to indicate weather each of the following is a chemical or physical property
Answer:
I think it's c
Explanation:
c seems like the best answer
Answer:
C since that has to be correct.
A beaker of water has an initial mass of 455.2 g. After it has been left uncovered
for several days, some of the water has evaporated. The new mass of the beaker
is found to be 422.55 g using a more precise balance. Choose that value that
expresses the mass of the evaporated water using the correct number of
significant figures.
A) 32.65 g
B) 32.7 g
C) 33 g
D) 32.650 g
The mass of water evaporated is 32.7 g.
What is evaporation?The term evaporation is the movement of the molecules of water from the surface of the water into the atmosphere. The molecules that move are the more energetic molecules that are able to break away from the attractive field of the surface of the water.
We have the original mass of the water as 455.2 g and the mass of the water after evaporation as 422.55 g. The difference between the two according to the right number of significant figures is 455.2 g - 422.55 g = 32.7 g
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For the reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many grams of lead(II) iodide, PbI2, are produced from 81.1 g of potassium iodide, KI?
Taking into account the reaction stoichiometry, 112.61 grams of lead(II) iodide, PbI₂, are produced from 81.1 g of potassium iodide, KI.
Reaction stoichiometryIn first place, the balanced reaction is:
2 KI + Pb(NO₃)₂ → PbI₂+ 2 KNO₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
KI: 2 molesPb(NO₃)₂: 1 molePbI₂: 1 moleKNO₃: 2 molesThe molar mass of the compounds is:
KI: 166 g/molePb(NO₃)₂: 331.2 g/molePbI₂: 461 g/moleKNO₃: 101.1 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
KI: 2 moles ×166 g/mole= 332 gramsPb(NO₃)₂: 1 mole ×331.2 g/mole= 331.2 gramsPbI₂: 1 mole ×461 g/mole= 461 gramsKNO₃: 2 moles ×101.1 g/mole= 202.2 gramsRule of threeRule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.
That is, what is intended with it is to find the fourth term of a proportion knowing the other three.
If the relationship between the magnitudes is direct, the direct rule of three must be applied using the following formula, being a, b and c known data and x the variable to be calculated:
a ⇒ b
c ⇒ x
So: x= (c×b)÷a
Mass of PbI₂ formedThe following rule of three can be applied: if by reaction stoichiometry 332 grams of KI form 461 grams of PbI₂, 81.1 grams of KI form how much mass of PbI₂?
mass of PbI₂= (81.1 grams of KI× 461 grams of PbI₂)÷ 332 grams of KI
mass of PbI₂= 112.61 grams
Then, 112.61 grams of lead(II) iodide, PbI₂, are produced from 81.1 g of potassium iodide, KI.
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How many grams of Oxygen are in 4 moles of C2H4O2? Show work.
The mass of oxygen in 4 moles of C2H4O2 is 128g.
How to calculate mass?The mass of a substance can be calculated by multiplying the number of moles of the substance by its molar mass.
Molar mass of C2H4O2 = 12(2) + 1(4) + 16(2) = 60g/mol
mass of C2H4O2 = 60g/mol × 4 moles = 240grams
However, the mass of oxygen in the compound can be calculated as follows:
molar mass of oxygen/molar mass of compound × 240 grams
32g/mol ÷ 60g/mol × 240g
= 128g
Therefore, the mass of oxygen in 4 moles of C2H4O2 is 128g.
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How are the separation methods for homogeneous and heterogeneous mixtures compared?
1. A homogeneous mixture could be separated through distillation, while a heterogeneous mixture could be separated through filtration.
2. A homogeneous mixture could be separated through filtration, while a heterogeneous mixture could be separated through distillation.
3. A homogeneous mixture can be separated physically, while a heterogeneous mixture can be separated chemically.
4. A homogeneous mixture can be separated chemically, while a heterogeneous mixture can be separated physically.
The separation methods for homogeneous and heterogeneous mixtures compared are A homogeneous mixture could be separated through distillation, while a heterogeneous mixture could be separated through filtration. The correct option is 1.
What is a homogeneous mixture?A homogeneous mixture is a mixture that contains a substance that remains homogeneous throughout the solution. The solution of salt and water is a homogeneous mixture.
Thus, the correct option is 1. Distillation can be used to separate homogeneous mixtures, while filtering can be used to separate heterogeneous mixtures.
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How many grams of AlCl3 are there in 205 grams of an aqueous solution that is 13.8 % by weight AlCl3.
_____ G AlCl3
28.9 grams of AlCl3 are present in 205 grams of an aqueous solution that is 13.8 % by weight AlCl3.
What is an aqueous solution?
Aqueous is a word used to describe a water-based system. The term aqueous can also refer to a solution or combination in which water serves as the solvent. The type of a substance's chemical bonding determines whether or not it forms an aqueous solution.
When a material dissolves in water, the symbol (aq) is appended to its chemical name. Many ionic chemicals and hydrophilic (water-loving) entities dissolve in water.
Table salt, for example, is dissolved in water and diffuses into ions to generate Na+(aq) and Cl- (aq). Hydrophobic, or water-averse, substances do not dissolve in water or produce aqueous solutions. There will be no dissociation if oil and water are mixed.
The weight of the aqueous solution = is 205 grams.
Percentage of AlCl₃ = 13.8%
Therefore, the weight of AlCl₃ by gram =
13.8% of the solution
= 13.8 % × 205
= 28.9g
Therefore the weight of AlCl₃ in the aqueous solution will be 28.9g
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Please help and explain if possible!
you have a 100.0-mL graduated cylinder containing 50.0 mL of water. You carefully place a 140-g piece of brass (density = 8.56 g/mL) into the water. What is the final volume reading in the graduated cylinder?
There is 100.0-mL graduated cylinder containing 50.0 mL of water. The final volume reading in the graduated cylinder is 62.7 mL.
What is volume?Volume is the space occupied by the three-dimensional object.
Given,
Density of liquid = 8.56 g/mL
Mass of substance = 109 g
The initial level of the water in the graduated cylinder = 50 .0 ml
To calculate the volume of a substance,
Density = mass / volume
8.56 = 109 / volume
volume = 109 / 8.56
V = 12.7 ml
The final volume reading in the graduated cylinder
50 ml + 12.7 mL = 62.7 mL
Thus, the final volume will be 62.7 mL
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You are conducting the Air Bag Lab with a snack sized ziplock bag (325mL). How many moles of gas would be needed to fill the bag?
0.1329 moles
Air Bag Lab with a snack sized ziplock bag (325mL), moles of gas would be needed to fill the bag
From the above statement, we have got
volume = 325ml
now at STP
Temp = 298 kelvin
pressure = 1 atm
Gas constant R = 0.082057L/mol kelvin
n is the number of moles
now, according to ideal gs equation
PV=nRT
n = PV RT
now put all the numbers in equation
n = 1 ×0.325 ÷0.082× 298
n = 0.1329 moles
One mole is defined as the quantity of a material that equals the number of ions, atoms, molecules, etc. that are present in exactly 12 grams of the C-12 (C = carbon) isotope.The quantity that is equal to Avogadro's number is the mole. To count items at the minute level, we employ the mole notion. The mole was suggested as the seventh basic unit for the quantity of a material in the SI system.To know more about mole
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If 0.459 g of an unknown sugar is dissolved in 100.0 mL of water its osmotic pressure is found to be 0.0824 atm.. If the temperature of the solution was 298 K, what is the molar mass of the sugar (in g/mol)? Give your answer to three sig figs
The molar mass of the sugar is 1350 g/mol.
What is the osmotic pressure?We define the osmotic pressure as the pressure that needs to be applied to effect the movement of the solvent across a semi permeable membrane.
Number of moles of the sugar solution = 0.459 g/MM
Where MM = molar mass
We know that the osmotic pressure is obtained from;
π = icRT
i = Van't Hoff factor
c = concentration
R = molar gas constant
T = temperature
Let us obtain the concentration;
c = π/iRT
c = 0.0824 atm/ 1 * 0.082 * 298
c = 0.0034 M
Now;
Concentration = Number of moles/volume
Volume = 100.0 mL or 0.1 L
0.0034 = 0.459/MM/0.1
0.0034 = 0.459/0.1MM
0.0034 * 0.1MM = 0.459
MM = 0.459/ 0.0034 * 0.1
MM = 1350 g/mol
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A cake recipe calls for 170.0 mL of buttermilk. How many cups is this?
(1.0567 quart = 1
L and 4 cups =
1
quart
A cup is 240 ml and the cake recipe calls for 170.0 ml of milk. It's 2/4 of a cup.
How many mls are in a cup of tea?
the cups have a standard measure of 240ml, that is, if you buy one of these good quality utensils, even if in different places, the measure of 1 cup must always be equivalent to 240ml.
With this information, we can conclude that Ml is the abbreviation milliliter, the smallest unit of measurement for liquids. We start with the liter as the base unit, we must go down to one tenth of a liter, which is deciliter, then 100 tenths of a liter than the centiliter and we go up to one thousand tenths of a liter, which is milliliter. One liter contains one thousand milliliters.
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How many electrons can fill all the p orbits from n = 1 through n = 3?
O 18
O12
0 3
0 6
Answer:6
Explanation: a p orbital can hold 6 electrons
HELP PLEASE!! What happens to the average kinetic energy of a gas when the particles of the gas collide against each other at a constant temperature and volume?
The average kinetic energy remains constant.
The average kinetic energy drastically increases.
The average kinetic energy drastically decreases.
The average kinetic energy gets added to the potential energy.
At constant temperature and volume, the average kinetic energy of the particles remains constant. The correct option is A.
What is kinetic energy?An object's kinetic energy is the energy it has as a result of its motion. It is characterized by the amount of work needed to propel a body of a given mass from rest to a given velocity.
The body retains its kinetic energy after gaining it during acceleration unless its speed changes.
The average kinetic energy of a gas when its particles collide against each other at constant temperature and volume. This is valid as long as as the temperature stays the same.
Thus, the correct option is A.
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Question 5 of 10
What experiment did J. J. Thomson do?
A. He hit metal plates with light.
B. He shot alpha particles through gold foil.
C. He suspended charged oil drops in a chamber.
OD. He sent a cathode ray between electrically charged metal plates.
J.J. Thomson sent a cathode ray between electrically charged metal plate. The aim of the experiment was to find the nature of the particles. The correct option is option D
What precisely was JJ Thomson evaluating?He lighted the metal plates. A gold foil was subjected to an alpha radiation beam by B. C. In a chamber, he suspended charged oil drops. OD. He produced a cathode ray discharge between two electrically charged metal plates. All atoms include tiny, negatively charged subatomic particles that mimic electrons, as demonstrated by J.J. Thomson's cathode ray tube studies. In Thomson's "plum pudding" atom model, a negatively charged "electon" encircled a positively charged "soup."
What was the purpose of JJ Thomson's experiment?He made the decision to attempt to identify the particle's makeup. He sought to calculate their mass and charge by measuring how much they were bent by electrical currents of various intensities because they were too small to have their mass or charge directly ascertained.
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For an Na+ - Cl- ion pair, attractive and repulsive energies EA and ER, respectively,
depend on the distance between the ions r, according to
=−1.436
=7.32×10−6
8
For these expressions, energies are expressed in electron volts per Na+ - Cl- pair, and r
is the distance in nanometers. The net energy EN is just the sum of the preceding two
expressions.
a. Superimpose on a single plot EN, ER, and EA versus r up to 1.0 nm (Use an Excel
worksheet).
b. On the basis of this plot, determine (i) the equilibrium spacing r0 between the Na+
and Cl- ions, and (ii) the magnitude of the bonding energy E0 between the two
ions.
The equilibrium spacing between the ions is 0.24 nm and the bonding energy is 5.3 eV.
The amount of energy required to separate the atoms forming a molecular bond into free atoms is known as bond energy, and it serves as a gauge of the strength of a chemical connection.
For Na⁺ and Cl⁻ ion pair, the attractive and repulsive energies are E(A) and E(R). The energies depend on the distance between the ions r.
We have,
E(A) = ( -1.436 / r )
E(R) = ( 7.32 × 10⁻⁶ / r⁸ )
(a) The plot for E(N), E(R), and E(A) versus r up to 1 nm is attached below.
(b) From the plot,
r(0) = 0.24 nm
E(0) = 5.3 eV
Hence, the equilibrium spacing r(0) between Na⁺ and Cl⁻ ions is 0.24 nm and the bonding energy is 5.3 eV.
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Read the weight shown on this scale, and report the answer with the proper number of digits.
A scale with 10 dashes between each written number. The needle is pointing between the second and third dash from 80, towards 90. There are 9 dashes between 80 and 90.
weight:
lbs
The needle is pointing between the second and third dash from 80, towards 90, that means it could be around 82.5kgs on the scale. therefore, weight in lbs will be 181.88.
The letters "lb" or "lbs" stand in for LBS, which is derived from the Latin word Libra. It is a phrase used internationally to describe an object's weight or mass.On the scale there are 9 dashes which represents whole number count. For example, dash after 80 is for 81, second is for 82, third for 83 and so on. Needle is between 82 and 83 therefore it could be 82.5.You can convert 82.5 kilogrammes to pounds by multiplying the kilogramme amount by the conversion factor, 2.204622622. Thus, to convert 82.5 kilos to pounds, multiply 82.5 by 2.204 to get 181.88 pounds.There the weight on scale is 181.88 lbs.
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Answer:
82.3
Explanation:
If you look close at it, it should be between 82 and 83. Ask which one is it more closer to it should be 82 but not too close or not too far where it would be 82.5. It is in the middle of 82 and 82.5 so what is in between that? It would be 82.3.
Which two are examples of mechanical weathering mentioned in the article? 5 points
freeze thaw, salt wedging
freeze thaw, river erosion
freeze thaw, acid rain
river erosion, salt wedging
Answer:
Freeze thaw, salt wedging
Explanation:
Freeze-thaw weathering occurs when rocks are porous (has holes) or permeable (allows water to pass through). It is an example of Mechanical Weathering.
Another type of mechanical weathering is called salt wedging.
In films, familiar tunes may be associated with particular characters and moods.
A. False, familiar tunes may not be associated with either characters or moods.
B. False, familiar may be associated with characters only
C. False, familiar may be associated with moods only
D. True
Answer:D
Explanation:it is true
What is the formula of trinitrogen heptoxide?
Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.
a
b
C
d
U3VD Question 2
Homework Unanswered
NO
N3O
N₂O₁
Resue
NOT
The molecular formula of trinitrogen heptoxide is written as [tex]N_3O_7[/tex].
How to calculate the molecular formula of Trinitrogen heptoxide:
Tri means three and hept means seven. Therefore,
Trinitrogen means 3 atoms of Nitrogen, thus it is denoted as [tex]N_3[/tex].
Heptoxide means 7 atoms of Oxygen, thus it is denoted as [tex]O_7[/tex].
Consequently, the molecular formula of Trinitrogen heptoxide is [tex]N_3O_7[/tex].
The type and number of each element's atoms in a molecular compound are indicated by the substance's molecular formula. The molecular formula is frequently the same as the empirical formula. Methane's empirical formula is [tex]CH_4[/tex], which is also its molecular formula because it only has one carbon atom.
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Suppose 1.50 g of Cu(s) reacts completely with 5.95 g of HNO3(aq). The reaction produces 4.43 g of Cu(NO3)2(aq), 0.85 g of H2O(l), and an unknown amount of NO2(g). If the reaction obeys the law of conservation of mass, how many grams of NO2(g) are produced?
The mass in grams of NO₂ produced from the reaction, given the data is 2.17 g
What is a chemical equation?Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.
The reactants are located on the left side while the products are located on the right side.
Reactants —> Products
The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.
How to determine the mass of NO₂ producedThe mass of NO₂ produced can be obtained as follow:
Mass of Cu = 1.5 gMass of HNO₃ = 5.95 gMass of Cu(NO₃)₂ = 4.43 gMass of H₂O = 0.85 gMass of NO₂ =?Balanced equation:
Cu + 4HNO₃ --> Cu(NO₃)₂ + 2H₂O + 2NO₂
1.5 + 5.95 = 4.43 + 0.85 + Mass of NO₂
7.45 = 5.28 + Mass of NO₂
Collect like term
Mass of NO₂ = 7.45 - 5.28
Mass of NO₂ = 2.17 g
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An unknown compound is analyzed and found to contain 0.1935 g of carbon, 0.0325 g of hydrogen, and 0.2043 g of fluorine.The molar mass of the compound is 240.23 glmol. a) How many moles of carbon are present in the compound? b) How many moles of hydrogen are present in the compound? c) How many moles of fluorine are present in the compound? d) Determine the empirical formula of the unknown compound. e) What is the molar mass of the empirical formula? What is the molecular formula of the unknown compound?
The molecular formula is [tex]\\C_{7}H_{21} F_{7}[/tex].
What is the empirical formula?The formulas that a compound could have are about three. The empirical formula shows the ratio of the atoms in the compound. The molecular formula shows the actual number of atoms of each element that we have in any particular compound. The structural formula can be used to deduce the arrangement of atoms in the compound.
We can now obtain the empirical formula using;
Mass of carbon = 0.1935 g
Number of moles of carbon = 0.1935 g/ 12 g/mol = 0.016 mole
Mass of hydrogen = 0.0325 g/1 g/mol = 0.0325 moles
Mass of fluorine = 0.2043 g/19 g/mol = 0.011 moles
We now have to divide through by the lowest number of moles ;
C - 0.016 mole/0.011 moles H - 0.0325 moles/0.011 moles F- 0.011 moles /0.011 moles
C – 1 H – 3 F – 1
The empirical formula is [tex]\\CH_{3}F[/tex]
Molar mass of the empirical formula = 12 + 3 + 19 = 34 g/mol
Molecular formula = 34n = 240.23
n = 240.23/34
n = 7
The molecular formula is [tex]\\C_{7}H_{21} F_{7}[/tex].
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A mixture of N2(g) and H2(g) reacts in a closed container to form ammonia, NH3(g). The reaction ceases before either reactant has been totally consumed. At this stage 1.0 mol N2, 1.0 mol H2, and 1.0 mol NH3 are present.
How many moles of N2 and H2 were present originally?
The moles of [tex]N_2[/tex] and [tex]H_2[/tex] that were present originally in the reaction will be 1.5 moles and 2.5 moles respectively.
Mole ratios in reactionsThe two reactants, [tex]N_2[/tex] and [tex]H_2[/tex], react in a closed container to form [tex]NH_3[/tex]. The normal stoichiometric ratio of the reaction is according to the following equation:
[tex]N_2 (g) + 3H_2 (g) --- > 2NH_3 (g)[/tex]
The stoichiometric ratio of [tex]N_2[/tex], [tex]H_2[/tex], and [tex]NH_3[/tex] is 1:3:2.
This means for every 1 mole of ammonia formed, 0.5 moles of [tex]N_2[/tex] and 1.5 moles of [tex]H_2[/tex] is required.
However, 1 mole of [tex]N_2[/tex] and 1 moles of [tex]H_2[/tex] remained after the reaction has ceased.
Thus, total amount of [tex]N_2[/tex] present originally = 1 + 0.5
= 1.5 moles
Total amount of [tex]H_2[/tex] present originally = 1 + 1.5
= 2.5 moles
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What are two short-term and two long-term storages (aka reservoirs) in the carbon cycle?
Answer:
What are often called carbon sinks like tropical forests only store carbon temporarily. The only real carbon sinks operate by the long term ...
Explanation:
the oceans and atmosphere, and dissolved organic matter is carried in solution by rivers from soils to the sea. This all constitutes the short-term carbon cycle. The word "short-term" is used because the characteristic times for transferring carbon between reservoirs range from days to tens of thousands of years.
In the short-term reservoir, carbon is stored in the atmosphere, oceans and biosphere with the ocean containing the largest amount of carbon. It takes months to centuries to recycle carbon dioxide through the short-term reservoir.
Carbon is stored in four main reservoirs -- oceans (the largest reservoir), geological reserves of fossil fuels, the terrestrial surface (plants and soil, mainly), and the atmosphere.
Using dimensional analysis, convert 250 days to years.
250 days makes 0.68 years
What is conversion factor?The term conversion factor has to do with the factor that could be used to convert a value form one unit of measurement to another. We have to note that these units must be dimensionally correct such that the affected units can cancel out.
We have that;
1 year is made up of 365 days
We now have to set up the dimensions for the conversion of 250 days to years.
Thus;
250 days * 1 year/365 days
= 0.68 years
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At 25 °C, the vapor pressure of pure benzene (C6H6) and pure toluene (C7H8) are 95.1 and 28.4 mmHg, respectively. A solution is prepared that has equal masses of C6H6 and C7H8. Determine the total vapor pressure above this solution.
The total pressure of the solution is 123.5 mmHg
What is the total vapor pressure above this solution?We know that the total pressure of a system is the sum of the individual partial pressures of the components of the mixture. This is the postulation of the Daltons law of partial pressure.
Having said that, the total vapor pressure above this solution is the sum of the vapor pressures of pure benzene and pure toluene. If this is established, it now follows that;
Total pressure = pressure of pure benzene + pressure of pure toluene
= 95.1 + 28.4 mmHg = 123.5 mmHg
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Sodium-24 has a half-life of 14.8 hours. How much of a 152.0 mg sodium-24 sample will remain after 3.7 days?
The mass of sodium that remains is 2.38 g
What is the remaining sodium?
We know that radioactivity refers to the spontaneous disintegration of the sample leading to the emission of radiation. The half life is the time taken for only half of the number of atoms in the sample to remain.
We know that;
No = amount of sodium initially present
N = amount of sodium after time t
t1/2 = half life of sodium
t = time taken for t amount remain
No = 152.0 mg
N = ??
t1/2 = 14.8 hours
t = 3.7 days or 88.8 hours
Using
N/No = (1/2) ^t/t1/2
N/152 = (1/2) ^88.8/14.8
N = (1/2) ^88.8/14.8 * 152
N = 2.38 g
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