True, the speed of individual particle diffusion is influenced by temperature and particle size, not by concentration.
Prolixity is the tendency of motes to spread out in order to enthrall an available space. feasts and motes in a liquid have a tendency to diffuse from a more concentrated terrain to a lower concentrated terrain. Passive transport is the prolixity of substances across a membrane. This is a robotic process and cellular energy isn't expended. motes will move from where a substance is more concentrated to where it's less concentrated. The rate of prolixity for different substances is affected by membrane permeability.
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calculate the impulse expeirenced when a 70kg person lands on firm ground after jumping from a height of 3.0 m
We know that the work-energy theorem states that the change in energy (in this case, kinetic energy) is equal to the work done on a system.
what is energy ?
Energy is the capacity to do work. It exists in many forms, such as kinetic, potential, thermal, electrical, chemical, nuclear, and mechanical energy. Kinetic energy is energy that is in motion, such as a moving car or the wind. Potential energy is energy that is stored, such as the energy stored in a stretched rubber band or a raised weight.
Thermal energy is the energy of moving molecules, such as the energy in hot water or in the air. Electrical energy is energy associated with the movement of electrons. Chemical energy is the energy stored in the bonds of atoms and molecules. Nuclear energy is energy stored in the nucleus of an atom. Mechanical energy is energy associated with the motion and position of an object.
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A car starts from an initial velocity of 10 m/s and accelerates at 2.5 m/s^2. How long will it take the car to reach a speed of 40 m/s? How far does the car travel during this time?
Answer:
300 km
Explanation:
Vi 10m/s
Vf = 40m/s
a= 2.5 m/s^2
Vf^2 - Vi^2 = 2as
S = (40^2 -10^2)/(2*2.5) = 300 Km
David throws a football into the air with an initial KE of 1000 J. Once the football reaches max height, the gravitational potential energy is 1.2 times the initial KE. What was the initial gravitational potential energy?
Group of answer choices
1000 J
200 J
0 J
2000 J
The initial potential gravitational energy will be 0 joules because the height will be zero.
What is kinetic and potential energy?Potential energy is the energy that is stored in any object of reffred to its height of the base of surface of earth. The object or system is unaffected by external factors like air or height. The power of moving particles within a system or an item is referred to as kinetic energy.
Does potential energy depend on mass?Potential energy is often represented by its height from surface. Height-dependent energy is known as gravitational potential energy. Weight determines the potential energy amount (mass times gravity).
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An insulating sphere of radius a,centered at the origin, has a uniform volume charge density rho.
A spherical cavity is excised from the inside of the sphere.The cavity has radius a\4 and is centered at position h_vector, where|vector of h| < 3/4 a, so that the entire cavity is contained within thelarger sphere. Find the electric field inside the cavity.
Express your answer as a vector interms of any or all of rho,epsilon_0, r_vector, and h_vector
The electric field inside the cavity in terms of ρ, ε₀, r vector, and h vector is ρh/3ε₀.
What is referred to as an electric field?Every point in space has an electric field connected to it when charge, in any form, is present. The strength and direction of the electric field are expressed by the value of E, which is also known as the electric field strength, electric field intensity, or simply the electric field.
The electric field inside the cavity as a vector in terms of ρ, ε₀, r vector, and h vector is,
E'' = E -E' = ρ (h-a/4)/3ε₀ - ρa/4/3ε₀
E'' = E -E' = ρh/3ε₀.
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Objects with masses of 141 kg and 494 kg are separated by 0.396 m. A 74.8 kg mass is placed midway between them.
1 ) Find the magnitude of the net gravitational force exerted by the two larger masses on the 74.8 kg mass.
The value of the universal gravitational constant is 6.672 × 10−11 N · m^2 /kg^2.
Answer in units of N.
2 ) Leaving the distance between the 141 kg and the 494 kg masses fixed, at what distance from the 494 kg mass (other than infinitely remote ones) does the 74.8 kg mass experience a net force of zero?
Answer in units of m.
( 1) The net gravitational force between the 74.8 kg mass is 8.09 x 10⁻⁵ N.
( 2) The distance from the from the 494 kg mass where the middle mass experiences net zero force is 0.258 m.
What is net gravitational force on the middle mass?The net gravitational force acting on the middle mass is calculated by applying Newton's law of universal gravitation as shown below.
F = ( GmM ) / ( R² )
where;
G is universal gravitation constantm is the mass of the middle massM is the mass of the first massR is the distance of separation between the two massesThe force between the first mass and the middle mass is calculated as;
F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( 0.198² )
F' = 1.8 x 10⁻⁵ N
The force between the third mass and the middle mass is calculated as;
F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.198² )
F'' = 6.29 x 10⁻⁵ N
The net gravitational force on the middle mass;
F (net) = 6.29 x 10⁻⁵ N + 1.8 x 10⁻⁵ N
F ( net ) = 8.09 x 10⁻⁵ N
Let the distance of zero net force from the 141 kg mass = d.
then the distance from the 494 kg mass = 0.396 m - d
F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( d² )
F' = 0.704 x 10⁻⁶ / d²
F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.396 - d )²
F'' = 2.47 x 10⁻⁶ / ( 0.396 - d )²
for zero net force, the two forces must be equal
0.704 x 10⁻⁶ / d² = 2.47 x 10⁻⁶ / ( 0.396 - d )²
0.704 (0.396 - d )² = 2.47d²
(0.396 - d )² = ( 2.47d² ) / ( 0.704 )
(0.396 - d )² = 3.51d²
0.396 - d = √ ( 3.51d² )
0.396 - d = 1.87d
1.87d + d = 0.396
d (1.87 + 1) = 0.396
d (2.87) = 0.396
d = 0.396 / 2.87
d = 0.138 m
The distance from the 494 kg mass = 0.396 - 0.138 m = 0.258 m
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Are you L-O-S-T after Reflection?
1.) A 200-g ball moving toward the right at a speed of 30 cm/ strikes a 400-g ball moving toward the left at an unknown speed, v. After collision they stick together and remain motionless. Find the speed of the 400-g ball before the collision.
2.) A 5kg mass moving to the right at a speed of 10m/s collides with an unknown mass initially moving to the left at the same speed. After collision they both moved to the right at the speed of 4m/s. Find the unknown mass.
Answer:
Q1) -15 cm/s and Q2) 2.143 kg
Explanation:
Q1) mass of the first ball: M1 = 200 g
initial velocity of the first ball: U1 = 30 cm/s
mass of the second ball: M2 = 400 g
initial velocity of the second ball: U2 = X cm/s
final velocity of the first ball: V1 = 0 cm/s
final velocity of the second ball: V2 = 0 cm/s
By using the law of conservation of momentum that states:
initial momentum = final momentum
(M1 x U1) + (M2 x U2) = (M1 x V1) + (M2 x V2)
however as after collision both the bass stick together their masses combine and the move together in the same direction with the same speed.
therefore;
(M1 x U1) + (M2 x U2) = (M1 + M2)(V)
(200 x 30) + (400 x X) = (400 + 200) (0)
6000 + 400X = 800 x 0
6000 + 400X = 0
X = -6000/400
X = -15 cm/s
( the minus sign indicates the opposite direction i.e. left)
Q2) M1 = 5 kg
M2 = X kg
U1 = 10m/s
U2 = -10 m/s ( as its the opposite direction)
V1 = 4 m/s
V2 = 4m/s
using the law of conservation of momentum:
(M1 x U1) + (M2 x U2) = (M1 x V1) + (M2 x V2)
( 5 x 10) + ( X x (-10)) = (5 x 4) + (X x 4)
50 - 10X = 20 + 4X
50 - 20 = 4X + 10X
30 = 14X
30/14 = X
2.143 kg = X
a stretched string has a wave speed v. if the string is replaced by another with half the linear mass density, by what factor will the speed of a wave on the string change?
The wave speed will increase by a factor of the square root of 2, or approximately 1.41.
What is linear mass density?A quantity of any characteristic value per unit of length is defined as having a linear density. Two frequently used examples in science and engineering are linear mass density (titer in textile engineering, the amount of mass per unit length) and linear charge density (the amount of electric charge per unit length).
The speed of a wave on a stretched string is directly proportional to the square root of the tension divided by the linear mass density of the string.
Therefore, if the string is replaced by another with half the linear mass density, the wave speed will increase by a factor of the square root of 2, or approximately 1.41.
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The factor of which the speed of a wave on the string change is square root of the tension divided by the mass per length, the linear density.
What does the wave speed in a stretched string look like?
v = μT, where T is the string's tension and μ is the mass of the string per unit length.
How does wave speed depend on linear density?The linear density of the rope a wave travels through determines its speed. The speed rises as the linear density decreases. The relationship states that the square root of linear density and speed are inversely related. Thus, a doubling or tripling of speed results from a quartering of the linear density.
Wavelength x Frequency = Speed.
Wave speed and wavelength are related by the wave speed equation (Speed = Wavelength x Frequency). The quantity of waves that move in a wave's frequency is measured in waves per second.
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we use radio waves, which travel at the speed of light, to communicate with robotic spacecraft. how long does it take a message to travel from earth to a spacecraft at: a. mars at its closest to earth (about 56 million km)? b. mars at its farthest from earth (about 400 million km)? c. pluto at its average distance from earth (about 5.9 billion km)?
When the robotic spacecraft Mars is 400 million kilometers away from Earth, we communicate with it via radio waves, which move at the speed of light.
Radio waves can they reach Earth?The atmosphere, fortunately, shields life on earth. The surface is also not accessible to infrared and long wavelength radio frequencies. Light, which really is difficult for the air to absorb, close rays, and some magnetic fields make up the electromagnetic waves that we can often view on the ground.
Why move at the same speed as light do radio waves?In reality, radio waves go through space incredibly swiftly. Since radio waves are an electromagnetic wave, they travel at the speed as light. Light travels at a speed of slightly less than 300,000 km/s second. A light beam could circle the Earth's equator more than seven times in a sec at that speed.
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Using two different colors, sketch the paths that the two blocks of ice take during the turn. Assume that friction between the bed of the truck and the ice may be neglected.
To sketch the paths that the two blocks of ice take during a turn draw, mark, and direct the arrows based on centripetal force.
To sketch the paths that the two blocks of ice take during a turn, you can follow these steps:
Draw a rough sketch of the truck and its bed, including the ice blocks.Mark the starting positions of the two ice blocks.Assume that friction between the bed of the truck and the ice may be neglected. This means that the blocks of ice will move in a straight line, following the path of the centripetal force acting on them.Draw the path of the first block of ice, starting from its initial position, and following the direction of the centripetal force.Draw the path of the second block of ice, starting from its initial position, and following the direction of the centripetal force.Use different colors for the two paths, to clearly distinguish between the two.Add any additional details or annotations as necessary, such as the direction of the centripetal force or the angle of the turn.To learn more about friction at
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a student missed a lab investigating the behavior of multiple capacitors in circuits. classmates gave the student the above data that show the charge on the equivalent capacitance in a circuit as additional identical capacitors are added to the circuit, but the classmates did not indicate whether the capacitors were added in series or parallel. what evidence from the data can be used to determine whether the capacitors were added in series or parallel?
The fact that the charge rises as the number of capacitors is increased is proof. Option B is right, so.
Can the addition of the capacitors in series or parallel be determined using evidence from the data?
A student didn't show up for a lab looking at how numerous capacitors behave in circuits. Students in the class supplied the student the information above, which illustrates the effect of adding more identical capacitors to a circuit on its equivalent capacitance, but they did not specify if the capacitors were increased.
Can it be determined whether the capacitors was added in parallel or series using evidence from the data?
A. As capacitors are added, the charge changes.
B. With each subsequent capacitor, the charge doubles.
C. As capacitors are added, the charge grows.
D. There is no evidence in the data to support how the capacitor were added.
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(review) Neatly write out all of the Energy-Interaction diagrams, with the accompanying temperature vs. energy added diagrams, requested in the DL Activity 1.3. Remember that complete Energy- Interaction diagrams always include algebraic expressions of energy conservation. Refer to the Energy-Interaction Model foldout.
Energy-interaction diagrams, also known as energy level diagrams, are graphical representations of the possible energy states of a system and the transitions between them. They are used to describe the behaviour of a system in terms of its energy levels and the interactions that cause transitions between them.
What are two types of interaction diagrams?There are two types of interaction diagrams- a sequence diagram and the other is a collaboration diagram.
What are the stages of interaction?There are stages of relational interaction in which relationships come together (initiating, experimenting, intensifying, integrating, and bonding) and come apart (differentiating, circumscribing, stagnating, avoiding, and terminating).
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space exploring astronauts want to measure the gravity on a strange planet. they throw a rock upward at 11 m/s and it reaches a height of 10 m. find the acceleration due to gravity on that planet. express as a positive number.
The value of acceleration due to gravity on that planet is -2.2/t m/s.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose direction is determined by the strength of a plumb bob.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose direction is determined by the strength of a plumb bob.
using the equation of motion,
v - v0 = a. t
we know that the velocity at the height where it stops is zero, and time needed to get there is half the time of the whole movement, t' = t/2
⇒ - v0 = a. t/2
⇒ a = -v0.2/t
putting values in the above equation,
⇒ a = - 11 m/s . 2/t
⇒a = -2.2/t m/s
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Help needed!
A force of 6.36 N acts on a(n) 4.9 kg object for 20.4 s. What is the objects change in momentum?
What is the change in velocity?
WU
Change in the momentum of the object with mass 4.9 kg on which force of 6.36 N acts for 20.4 s is 31.164kgm/s and change in velocity is 6.36m/s
As we know Force acting on any object is
F = m.a...........(1)
where m ⇒ mass
and a ⇒ acceleration
Also [tex]a=\frac{v}{t}[/tex]..........(2)
where v ⇒ velocity
t ⇒ time
so equation (1) can be written as:
[tex]F=\frac{m.v}{t}[/tex]..........(3)
Change in Momentum is equal to
p=m.v.......(4)
where m ⇒ mass
v ⇒ velocity
Now as per the question:
Force, F = 6.36 N
Mass, m = 4.9 kg
Time, t = 20.4s
putting the values in equation (3),
we get [tex]6.36=\frac{4.9*v}{20.4}[/tex]
by solving this we get a value of v=6.36m/s
putting the values in equation (4)
we get, Change in momentum
[tex]p=4.9*6.36\\p=31.164kg m/s[/tex]
so the change in velocity is 6.36m/s and change in momentum is 31.164kgm/s
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A stadiuk is filled with 15,811 home-team fans. the home team won all 15,811 fans stand and cheer. assume that each individual fan produces a sound intensity of 10^-5 w/m^2, as heard feom the ground.
what is the total sound intensity level heard on the ground? (in terms of db)
β = 1131 db is the total sound intensity level heard on the ground (in terms of db).
Total intensity heard at the pitching mound is,
I=15811×1.0×10⁻⁵ W/m²
I=15811×10⁻⁵ W/m²
I=15811×10⁻⁵ W/m²
Total intensity heard at the pitching mound is,
β= 10log(I/I₀)
β= 101og(15811×10⁻⁵ W/m² / 1.0×10⁻¹²)
β=1131 db
β = 1131 db
The power carried by sound waves per unit area in a direction perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square metre (W/m2) is the SI unit of intensity, which also covers sound intensity.
The power carried by sound waves per unit area in a direction perpendicular to that region is described as sound intensity, also known as acoustic intensity. The watt per square metre (W/m2) is the SI unit of intensity, which includes sound intensity.
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Two flying fish have an inelastic collision while in mid-flight. one fish has a mass of 0.650 kg and a velocity of 15.0 m/s to the right; the other has a mass of 0.950 kg and a velocity of 13.5 m/s to the left. find the change in their kinetic energy after the collision.
The change in kinetic energy = 212.50 J - 197.458 J = 15.042 J.
What is kinetic energy?Kinetic energy is the energy possessed by an object due to its motion. It is the energy that an object has because of its motion. Kinetic energy is the energy of motion and is equal to one half of the mass of the object times the square of its velocity. Kinetic energy can be converted into other forms of energy, such as electrical, thermal, or chemical energy.
The kinetic energy of the two fish before the collision can be calculated by using the equation K = 1/2mv^2. For the first fish, K = 1/2 (0.650 kg)(15.0 m/s)^2 = 113.125 J. For the second fish, K = 1/2 (0.950 kg)(13.5 m/s)^2 = 99.375 J.
The total kinetic energy of the two fish before the collision is 212.50 J.
To calculate the change in kinetic energy, we first need to calculate the velocity of the two fish after the collision. To do this, we can use the equation for the conservation of momentum for an inelastic collision, p = m1v1 + m2v2. We know the masses and initial velocities, so solving for the final velocities, we get:
For the first fish, v1 = (0.950 kg)(13.5 m/s) + (0.650 kg)(15.0 m/s) / (0.650 kg + 0.950 kg) = 14.3 m/s.
For the second fish, v2 = (0.650 kg)(15.0 m/s) + (0.950 kg)(13.5 m/s) / (0.650 kg + 0.950 kg) = 13.2 m/s.
Now that we have the final velocities of the two fish, we can calculate the change in kinetic energy by plugging the final velocities into the equation K = 1/2mv^2.
For the first fish, K = 1/2 (0.650 kg)(14.3 m/s)^2 = 105.938 J.
For the second fish, K = 1/2 (0.950 kg)(13.2 m/s)^2 = 91.520 J.
The total kinetic energy of the two fish after the collision is 197.458 J.
Therefore, the change in kinetic energy = 212.50 J - 197.458 J = 15.042 J.
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calculate the energy in kj used by a 55.0-kg woman who does 50 deep knee bends in which her center of mass is lowered and raised 0.400 m. (she does work in both directions.) you may assume her efficiency is 20%
According to the question, 1.132887kcal energy used by a 55.0-kg woman who does 50 deep knee bends in which her center of mass is lowered and raised 0.400 m.
What is the easiest way to define energy?People have figured out how to transform energy from one format to the next and then use it to accomplish tasks, making modern civilization possible.
As we know that-
Mass = 55kg
Knee bend = 55
Efficiency = 20%
Displacement = 0.4m
We will first determine the total Workdone.
Work done = 2n(mgh)
n = 55,
m = 55kg,
g = 9.8m/s²
h = 0.4m
Work done = 2 ×55 × 55 × 9.8 × 0.4
Work done = 23,716J
Considering that the lady completes 20% of her work efficiently;
so,
her energy = 20% of 23,716J
= 4,743.2
= 4.74KJ
Energy = 1.132887kcal
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how does the speed of the rock when it reaches the ground vd compare to the speed of the rock when it is thrown upward vu?
The speed of the rock when it hits the ground vd is greater than the speed of the rock when it is thrown upward vu(vd>vu).
The rock will eventually reach its maximum height above the ground if thrown upward. It will fall back to the ground at the same vertical height at which it was thrown at a speed of 15 m/s. The rock's speed will increase above its initial speed of 15m/s as it continues to fall 100m below its initial vertical position.
Velocity is the rate of change in the position of an object in motion as measured by a specific time standard (e.g., 60 km/h northbound). Velocity is a key concept in kinematics, the branch of classical mechanics that studies body motion.
Velocity is a physical vector quantity that must be defined by both magnitude and direction. Speed is a coherently derived unit whose quantity is measured in the SI (metric system) as meters per second (m/s or ms1). For example, "5 m/s" is a scalar, whereas "5 m/s east" is a vector.
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what is the charge (in nc) on a 1.00-cm-long segment of the wire?
The charge stored in a 1.00-cm-long segment of the wire is 5.6 x 10^6 x 1.00 cm, or 5.6 nC.
What is charge?Charge is an electrical property of matter that either attracts or repels other objects with an electrical charge. This property is due to the presence of electrons, protons and neutrons, which all have different charges. The force of attraction or repulsion between two objects with a charge is known as the Coulomb force. The charge of an object is measured in Coulombs, which is a unit of electric charge.
The charge (in nC) on a 1.00-cm-long segment of the wire depends on the type of wire and the amount of charge stored in it. If the wire is an insulated copper wire, then the charge stored in it is determined by the number of electrons per unit length of the wire. The charge stored in a 1.00-cm-long segment of wire can be calculated by multiplying the number of electrons per unit length of the wire by the length of the wire itself, which is 1.00 cm. For example, if the wire has 5.6 x 10^6 electrons per centimeter, then the charge stored in a 1.00-cm-long segment of the wire is 5.6 x 10^6 x 1.00 cm, or 5.6 nC.
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Find the scalar x- and y-components of the following displacements in the xy plane (a)300cm at 127⁰ and (b) 500cm at 220⁰
(a) The scalar x- and y-components of the displacement 300cm at 127⁰ are 259.9cm and 150.8cm respectively.
(b) The scalar x- and y-components of the displacement 500cm at 220⁰ are -400cm and -309.3cm respectively.
Displacement is a physical concept referring to the distance an object moves in a certain direction. It is a vector quantity, meaning it has both magnitude and direction. Displacement is not the same as distance, as distance is the total length traveled, while displacement is the change in position. Displacement can be measured in any unit of length, such as meters, feet, or kilometers.
(a) The scalar x-component of the displacement is 257.7 cm and the scalar y-component of the displacement is 213.3 cm.
(b) The scalar x-component of the displacement is -403.3 cm and the scalar y-component of the displacement is -281.3 cm.
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The scalar x- and y-components of the following displacements in the xy plane (a)300cm at 127⁰ is -202.46 cm and -236.98 cm respectively, (b) 500cm at 220⁰ is -417.51 cm and -132.96 cm respectively.
What do you mean by displacement?It is the difference between the initial and final position of an object and is usually measured in meters or other units of length. It can be calculated by subtracting the initial position vector from the final position vector. In physics, displacement is often used to describe the motion of an object in one dimension, such as along a straight line.
To find the scalar x- and y-components of a displacement in the xy plane, we can use trigonometry. The x-component of the displacement is given by:
x = r * cos(θ)
where r is the magnitude of the displacement and θ is the angle the displacement makes with the x-axis (measured in radians). The y-component of the displacement is given by:
y = r * sin(θ)
where r is the magnitude of the displacement and θ is the angle the displacement makes with the y-axis (measured in radians).
(a) For a displacement of 300 cm at an angle of 127°:
x = r * cos(θ) = 300 cm * cos(127°) = -202.46 cm
y = r * sin(θ) = 300 cm * sin(127°) = -236.98 cm
(b) For a displacement of 500 cm at an angle of 220°:
x = r * cos(θ) = 500 cm * cos(220°) = -417.51 cm
y = r * sin(θ) = 500 cm * sin(220°) = -132.96 cm
Note that in the above examples, the angles are converted from degrees to radians before using them in the trigonometric functions.
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Fighter pilots report that immediately after a burst of gunfire fron their jet fighter, the speed of their aircraft decrease from 265 to 250 km per h. using newton's second and third law to explain the reason for this change in motion
The speed of the aircraft would decrease as force is exerted on it.
What is the Newton second law?
We know that according to the Newton second law, the rate of change of the momentum of the body is directly proportional to the impressed force.
Given that there was a burst of gunfire from their jet fighter, the speed of their aircraft decrease from 265 to 250 km per h, we can see that there was a decrease in the velocity because of the force that has been exerted on the jet by the fire of the bullet.
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a machine has an efficiency of 70%. how much work does the machine do when 20,000 j of work is done on it?
The work done by the machine is 14000 joules if the efficiency of the machine is 70% and the 20,000 Joules work is done on it.
Efficiency of the machine is the ratio of the work done by the machine and the work done on the machine. It is a unitless quantity. In other words, efficiency of a machine is the ratio of output and input of the machine.
Work done on the machine = 20000 J
Efficiency(η%) = 70%
Efficiency(η%) = (Work done by the machine×100)/work done on the machine
70% = (100 × work done)/(work supplied)
70/100 = work done/20000
Work done = (70×20000)/100
Work done = 14000 J
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a truck is accelerating as it speedsdown the highway. one inertial frame of reference is attachedto the ground with its origin at a fence post. a second frameof reference is attached to a police car that is traveling down thehighway at constant velocity. is the momentum of the truckthe same in these two reference frames? explain. is therate of change of the truck's momentum the same in these twoframes? explain.
In the first frame of reference, attached to the ground with its origin at a fence post, the momentum of the truck is given by the product of its mass and velocity.
As the truck is accelerating, its velocity is changing and therefore its momentum is also changing. The rate of change of the truck's momentum in this frame is equal to the force acting on the truck.
In the second frame of reference, attached to the police car that is traveling at a constant velocity, the truck is moving at a relative velocity with respect to the police car.
The momentum of the truck in this frame is still given by the product of its mass and velocity, but now the velocity is relative to the police car. The momentum of the truck will be different in this frame of reference.
The rate of change of the truck's momentum is not the same in these two frames. In the first frame, the rate of change of momentum is equal to the force acting on the truck.
However, in the second frame, the truck is moving with a constant velocity relative to the police car, so the rate of change of momentum is zero.
In summary, in the first frame of reference attached to the ground, the truck is accelerating and its momentum is changing, while in the second frame of reference attached to the police car, the truck is moving at a constant velocity relative to the police car, so its momentum is different but the rate of change of momentum is zero.
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two space capsules, of equal mass, are put into orbit 30.0 m apart. the gravitational force between them is 2.0 x 10-7 n. a.) what is the mass of each capsule? b.) what is the initial acceleration given to each capsule by this force? c.) why does this acceleration change?
The object is pulled by the gravitate attraction, which causes it to curve away from a straight line of motion and nearly towards to the center of earth 2.0 х 10-7 n.a.
If the centers of two 15 kg balls are 35 m apart, what is the gravity between them?8. The Force of Gravity What gravitational force exists between two parcels weighing 15 kg and spaced 35 cm apart? What percentage of the volume of one package does this make up? The gravitational pull is 8.210 10 and 0.82 components per million of the mass since the weight is milligrams 147 N.
Why the moon's gravity should be the same for a world that is twice as big?The Earth has a stronger gravitational force than the moon, thus to start answering your question merely because Earth is a larger planet. The rising and lowering of the tides is a result of the moon's gravity, which also has an impact on Earth. But the story doesn't end there.
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what is the tension in the chain (for the same angle)
The tension in the chain for the same angle is 533.37 N.
What is he speed of each seat?The speed of each seat is determined by treating the system as a simple harmonic motion.
Apply the law of conservation of mechanical energy as shown below.
kinetic energy of each seat at the bottom = potential energy of each seat at the top
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √ ( 2gh )
where;
h is the vertical displacement of the childreng is acceleration due to gravityThe vertical displacement of the seats is calculated from the length of the chain as follows;
h = L cos (24.4)
The speed of each seat is calculated as follows;
v = √ ( 2g L cos (24.4) )
v = √ ( 2 x 9.8 x 2.54cos (24.4) )
v = 6.73 m/s
The tension in the chain is calculated by applying the formula for centripetal force as follows;
T = mv²/r
where;
m is the total mass suspended by the chain = 10 kg + 63.6 kg = 73.6 kgv is the speed of each seat = 6.73 m/sr is the radius of the platform = (12.5 m) / (2) = 6.25 mT = ( 73.6 x 6.73² ) / ( 6.25 )
T = 533.37 N
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The complete question is below:
An amusement park ride consists of a rotating circular platform 12.5 m in diameter from which 10 kg seats are suspended at the end of 2.54 m massless chains. When the system rotates, the chains make an angle of 24.4° with the vertical. The acceleration of gravity is 9.8 m/s^2..
If a child of mass 63.6 kg sits in a seat, what is the tension in the chain (for the same angle)? Answer in units of N.
assuming the water is at rest, is the magnitude of the force of the water on the left side of the volume greater than, less than, or equal to the magnitude of the force of the water on the right side of the volume? explain your reasoning. 3. based on your answer to question a2, is the pressure at point b greater than, less than, or equal to the pressure at point c?
Assuming the water is at rest, then the magnitude of the force of the water on the left side of the volume is equal to the magnitude of the force of the water on right side of the volume. Pressure at point c will be greater than that of point b.
According to the pascal's law, the pressure applied on a confined fluid will be transmitted in all the direction, at every point, and on the wall of the container, without any change in the magnitude. Moreover, the pressure applied at a particular depth will be same in all direction. So if we assume that the water is at rest, and the area of left and right walls are equals, then the force will also be equal on both the walls.
If point c is deeper than the point b then the pressure on the point c will be greater than that of point b. As pressure = ρgh, where ρ is the density of water, h is the depth of a particular point.
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A 1200-kilogram car traveling at 10. Meters per second is brought to rest in 0. 10 second. What is the magnitude of the average force that acted on the car to bring it to rest? A)1. 2 x 103N B )1. 2 x 10?N © 1. 2 x 105 N D) 1. 2 x 10°N
The average force that acted on the car to bring it to rest is 1.2 × 10⁵ Newton.
What is force?
The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
The average force that acted on the car to bring it to rest is = - Change in momentum of the car/time interval
= (initial momentum - final momentum)/time interval
= (1200 kg × 10 m/s)/0.10 second
= 1.2 × 10⁵ Newton
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two cars come to a stop from the same initial speed, one braking gently and the other braking hard.
Which car converts more kinetic energy to internal energy (for example, thermal energy in the brakes)?
o the car that braked hard o the car that braked gently
o Cars convert an equal amount of kinetic energy.
o It's impossible to determine.
According to the law of conservation of energy, the car that apply hard brakes will convert more kinetic energy to thermal energy. Hence option 'a' is correct.
Describe kinetic energy.Kinetic energy is any energy that an object gains as a consequence of motion. To accelerate an object, some force must be supplied to it. For apply a force, we must put more effort. After work is completed, energy is transmitted to the object, which then moves at a constant speed.
How can kinetic energy be used?Running and pacing. When moving air strikes the blades of a windmill, it creates rotation, which ultimately results in the production of energy. When moving water's kinetic energy strikes a turbine at a hydroelectric facility, it is transformed into mechanical energy.
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a 15.0 g rubber bullet hits a wall with a speed of 145 m/s. if the bullet bounces straight back with a speed of 110 m/s, what is the change in momentum of the bullet?\
When a 15.0 g stray bullet traveling at 145 m/s strikes a wall, if it returns in a straight line at a speed of As a result, the as same is 4.93 N.
What do writing bullet mean?A line of the article is a literary device that is used to describe an item in some kind of a list. A centered dot (•), which is a common symbol for a bullet point, is just one of many other symbols and characters that can be employed in bulleted lists. Even numbers and/or letters can be used in some bulleted lists.
Calculation
We know that force F = dP/dt where dP/dt = rate of change of momentum and P = momentum = mv
Now, F = dP/dt = dmv/dt = vdm/dt + mdv/dt
Now since we have 5.6 g bullets, m = 5.6 g = 0.0056 kg, dm/dt = rate of change of mass of bullet hitting superman per second = mass of one bullet × rate of change of bullet = 0.0056 kg/bullet × 110 bullets/min = 0.0056 kg/bullet × 110 bullets/min × 1 min/60 s = 0.0103 kg/s, v = speed of bullet = 480 m/s and dv/dt = 0.
So, F = vdm/dt
= 0.01027 kg/s × 480 m/s
= 4.929 kgm/s²
= 4.929 N
≅ 4.93 N
So, the average force is 4.93 N
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does kepler's law of equal areas imply that gravity varies inversely with the square of the distance
Kepler's law of equal areas imply that gravity varies inversely with the square of the distance. (false)
What is Kepler's law?Kepler's laws of planetary motion are rules in astronomy and classical physics that describe how the planets move within the solar system. They were mostly developed by the German astronomer Johannes Kepler.
Also whose analysis of the observations of the astronomer Tycho Brαhe from the 16th century allowed him to publish his first two law in 1609 and a third law nearly ten years later, in 1618. Kepler never assigned a number to these laws or made a special distinction between them and his other discoveries.
The conservation of orbital angular momentum L is a direct result of Kepler's law of equal areas.
That law is:
[tex]\dfrac{\mathrm{d}A}{\mathrm{d}t}=\dfrac{1}{2m}L[/tex]
where, dA is the area which is swept out by the radius [tex]\vec{r}[/tex] and is the object's mass m in a time dt.
Since L is conserved, the radius vector's sweep of area A over time t is unaffected by the distance from the central object (the sun).
The gravitational force, which is the primary force and is directed toward the object, causes L to remain constant.
None of these facts imply that gravity varies inversely with distance squared, so the given statement is false.
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