The subtraction problem 4/5 - 2/7 can be rewritten as the addition problem _[blank].
Enter your answer as the expression that correctly fills in the blank.
Enter fractions formatted like this: 3/14

Answer:In his equation height is given by h(t) and t represents time. The shape of this equation is that of a downward facing parabola because the coefficient of the first term is negative. Therefore, the maximum height is found by determining the vertex of the parabola which is given by b/2a or 50/(16*2). Thus after, 1.5625 seconds the ball reaches it maximum height of 44 feet (plug 1.5625 into formula.)

Notice that the formula has a constant of 5 in it meaning that the ball was throw up at a 5 foot starting position above the ground. Thus, for the ball to hit the ground h(t) = -5. So, what is the value of t that gives that value? Here we just use the quadratic formula and find that t = 3.31 seconds. That makes sense doesn't it? 2*1.5625 would get the ball back to the starting position ( 3.125 sec) and the ball needs another .185 sec to fall the last 5 feet. What speed is that in MPH? That would be 5/.185*(3600/5280) = 18.4 MPH. That is a lot slower than a 95 MPH fast ball.

Step-by-step explanation:

Answer:

candies bought = 3

price of 1 candy = $2.50

price of 3 candies =$(3*2.50)

Step-by-step explanation:

byeeee

Answer:

.9 inches

Step-by-step explanation:

Set up and solve this proportion:

[tex] \frac{1.2}{400} = \frac{x}{300} [/tex]

[tex]400x = 360[/tex]

[tex]x = .9[/tex]

[tex]5x+y=35 \implies 15x+3y=105 \\ \\ \implies (15x+3y)+(7x-3y)=105+27 \\ \\ 22x=132 \\ \\ \boxed{x=6} \implies 7(6)-3y=27 \\ \\ -3y=-15 \\ \\ \boxed{y=5}[/tex]

In linear equation, n = 15 is the value of equation .

What in mathematics is a linear equation?

What is the linear equation's formula?

A linear equation has the slope-intercept form y = mx + b. Variables in the equation are x and y. When x is 0, the integers m and b provide the line's slope (m) and the value of y. (b).

-17 = 1/5n - 20

- 17 + 20 = 1/5n

3 = n/5

n = 15

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Answer:

The answers to the question in reference to the graph are mentioned below.

Step-by-step explanation:

It is given that we need to find the mentioned questions alongside the graphs of the functions;

Now, let us consider the first question given herein;

Now, let us consider the second part of the question;

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20 is the value in the given data set which have a relative frequency of 30%.

Given,

The data set as,

10, 20, 20, 50, 30, 20, 10, 50, 60, 70.

We have to find the value from the above given data set which have a relative frequency of 30%.

Relative frequency = (subgroup count / total count) × 100

Here, 20 is the most repeating value. So we can calculate with it.

There are three 20's in the set.

So, subgroup count = 3

Total count = 10

Then,

Relative frequency = (3/10) × 100 = 30

Hence, we can conclude that 20 is the value in the given data set which have a relative frequency of 30%

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The number of large rolls that could be made from Rosa's dough is 4 numbers.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the number of large rolls that can be made from Rosa's dough, hence:

(3/4)x = 3 3/5

(3/4)x = 18/5

x = 4.8

The number of large rolls that could be made from Rosa's dough is 4 numbers.

The inequality that shows the number of shirts that Lisa buys is given as 15x + 35 ≤ 137

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Answer:

21 dollars

Step-by-step explanation:

Cents ÷ 100 = Dollars

2100 ÷ 100 = 21

Hope this helped! (๑>◡<๑) xx

The animal is 150 inches tall .

Scale Factor = ( scale / actual )

Given : Scale Factor = ( 1 / 30 )

To find : the actual height of animal .

Let t be the actual height of animal .

Therefore Scale Factor comes out to be ( 5 / t ) .

Equating both the scale factors and hence finding the value of t ,

( 1 / 30 ) = ( 5 / t )

t = 150 inches .

Therefore , the animal is 150 inches tall .

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The unit rate problem is discussed above and the unit rate of speed according to problem is 50 kilometers per hour.

What is the unit rate method ?

The unit rate method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

The real world situation can be as follows ;

A police officer who believes you were speeding stops you. You say that it took you exactly seven hours to travel 350 kilometers across the state. To determine if you were over speeding, the policeman must perform the necessary calculations. He requires to find out the unit rate.

Let's solve it to find out that at what unit rate of speed you were travelling.

We know that unit rate meant we need to find out the distance we have travelled in 1 hour.

So,

Unit speed = 350 / 7 km per hour

or

Unit speed = 50 kilometers per hour

Police man will check with the limit of speed and if he find that you were not over speeding , then he would allow you to go further.

Therefore , the unit rate problem is discussed above and the unit rate of speed according to problem is 50 kilometers per hour.

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Answer:  Draw a straight line through (0, 16) and (1, 14)

The graph is below.

=========================================================

Explanation:

There are at least two approaches we can take

-----------------

Method 1

Plug in x = 0 to find that....

y = -2x+16

y = -2(0)+16

y = 16

The point (x,y) = (0,16) is on the line. This is the y intercept

Repeat similar steps for x = 1

y = -2x+16

y = -2(1)+16

y = 14

The point (1, 14) is also on the line

Plot the points (0, 16) and (1, 14). Then draw a straight line through them to complete the graph for y = -2x+16

You only need 2 points at minimum to draw a linear graph.

The graph is shown below. Ignore the stuff in red.

-----------------

Method 2

Compare y = -2x+16 to the form y = mx+b

The y intercept is where the graph crosses the y axis. In this case, it's at the location (0, 16)

Start at this point and move down 2 units and to the right 1 unit to arrive at (1, 14) which is another point on the line.

The stuff in red shows this motion of "down 2, right 1"

note that slope = -2 = -2/1 = rise/run

rise/run = -2/1

rise = -2 = go down 2

run = 1 = go to the right 1

-----------------

Side note: You can use a graphing tool like Desmos or GeoGebra to graph quickly. I used GeoGebra to make the diagram below. Though it's handy to have practice to do it by hand.

Using the Empirical Rule, the percentages are given as follows:

a) 99.7%.

b) 49.85%.

c) 0.15%.

It states that, for a normally distributed random variable:

In this problem, we have that:

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Answer: 12328 is the answer

Step-by-step explanation:

You put the 536 on top and 23 on the bottom and you multiply 3 first to get 1608 then you multiply 2 to get 10720. You add these two numbers and you get 12328 as your answer! :D

The product of 23 multiplied by 536 is 12,328.

We have,

The concept used to find the product of 23 multiplied by 536 is basic multiplication.

Start with the rightmost digit of the bottom number (536), which is 6.

Multiply 6 by the top number (23). We have 6 multiplied by 3, which equals 18.

Write down the rightmost digit of the result (8) under the line.

Carry over the remaining digit, which is 1, to the next column.

Now, multiply the carried-over digit (1) by the top number (23). We have 1 multiplied by 3, which equals 3.

Add the carried-over digit (1) to the result (3), which gives us 4.

Write down the rightmost digit of this new result (4) next to the previous digit (8), giving us 48.

Finally, multiply the leftmost digit of the bottom number (5) by the top number (23). We have 5 multiplied by 3, which equals 15.

Write down this result (15) shifted one place to the left, giving us 150.

Add the two partial products: 48 + 150 = 198.

Therefore,

The product of 23 multiplied by 536 is 198.

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Answer:

[tex]\frac{12}{4} = \frac{3}{1}[/tex]

Step-by-step explanation:

[tex]\frac{12\div4}{4\div4}=\frac{3}{1}[/tex]

Hope this helps!

Answer:

12 = 3

4      1

Step-by-step explanation:

hope the helps

[tex]\textit{sum of all interior angles}\\\\ S=180(n - 2) ~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n=5 \end{cases}\implies S=180(5-2)\implies S=540 \\\\[-0.35em] ~\dotfill\\\\ 105+118+75+130+x~~ = ~~540\implies 428+x=540\implies x=112[/tex]

Based on the current price of gas per gallon, and the fact that it was cheaper the year before, the percent decrease in price is 31%

First, find the price of gas last year:

=Current price of gas + Decrease in price

= 3.20 + 1.43

= $4.63

The percent of decrease in price can be found by the formula:

= Change in gas price / Price of gas last year x 100%

= 1.43 / 4.63 x 100%

= 0.30885529157667386609071274298056 x 100%

= 31%

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The domain of this function is all the real numbers except - 7 / 3 and 23 / 3.

In accordance with function theory, the domain of a function is a set of x-values such that y-values exist. Herein we find that the given function is a rational function whose denominator includes an absolute value function. The numerator is a linear equation.

Therefore, the domain of the function is all real numbers except those x-values such that denominator is equal to zero. We need to solve the following expression in two cases:

|3 · x - 15| = 8

For x ≥ 5:

3 · x - 15 = 8

3 · x = 23

x = 23 / 3

For x < 5:

- 3 · x + 15 = 8

- 3 · x = - 7

x = - 7 / 3

Then, the domain of this function is all the real numbers except - 7 / 3 and 23 / 3.

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the linear equation tangent at x = -2 is:

y = 123.33*x + 226.74

To get the slope of the line we need to evaluate the first derivative in x = -2, we get:

f'(x) = 3√(2 - 4x) + (-12/2)*3x*(2 - 4x)^(-1/2)

Evaluating in x = -2 we get:

f'(-2) = 3√(2 - 4*-2) + (-12/2)*3*-2*(2 - 4*-2)^(-1/2) = 123.33

Then the line is something like:

y = 123.33*x + b

And the line must pass through:

f(-2) = 3*(-2)*√(2 - 4*(-2)) = -18.97

So the line must pass through the point (-2,  -18.97)

Replacing that in the linear equation:

-18.97 = 123.33*2 + b

-19.92 + 123.33*2 = b = 226.74

Then we conclude that the linear equation tangent at x = -2 is:

y = 123.33*x + 226.74

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Using the Fundamental Counting Theorem, there is a 0.7143 = 71.43% probability that the code either starts with an 'A' or ends with an even digit.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem, we have that the code has:

Hence the number of codes is:

N = 14 x 5 x 14 x 5 x 14 x 5 = 343,000.

The number of codes starting with an A is:

Na = 5 x 14 x 5 x 14 x 5 = 24,500.

The number of codes ending with an even digit(0, 2 or 4) is:

Ne = 14 x 5 x 14 x 5 x 14 x 3 = 205,800.

The number of codes starting with an A and ending with an even digit is:

Nae = 5 x 14 x 5 x 14 x 3 = 14,700.

The number of desired outcomes is:

24500 + 205800 + 14700 = 245,000.

Hence the probability is:

245,000/343,000 = 0.7143.

0.7143 = 71.43% probability that the code either starts with an 'A' or ends with an even digit.

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Answer:

Option D) 6.8 × 10⁻²

Answer:

D

Step-by-step explanation:

Answer: A

Step-by-step explanation:

Answer: 12,186.96

Step-by-step explanation:

The value of the x in the given geometry figure is  108° .

The labelled diagram of the figure is given below.

From the figure , we can see that ∠OEA = ∠BOF as they are vertically opposite angles .

Hence ∠BOF = x

∠OFT and ∠BOF are linear pair , so on adding them , we will get sum 180°

∠OFT + ∠BOF = 180°

 72° + x = 180°

        x = 108°

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Answer:

  x° = 22°

Step-by-step explanation:

You want the measure of the angle marked x° in the figure with two parallel lines and a "bent" transversal.

Extending the upward-sloping line in the figure as shown in the attachment results in a triangle against the top horizontal line.

The angle on the right side of that triangle corresponds to the one marked 50°, so has the same measure. It is one of two "remote interior angles" whose sum is the measure of the exterior angle marked 72°. The other "remote interior angle" making up that sum is the vertical angle to the one marked x°.

So, we have ...

  x° +50° = 72°

  x° = 22° . . . . . . . . subtract 50°

__

Additional comment

You can do a "sanity check" on this answer by considering some extreme cases. If the 72° angle is reduced to 50°, the top leg of the "72°" angle would be horizontal. That would effectively reduce x to 0. Similarly, if the 72° angle were made to be 180°, then the value of x would be supplementary to the 50° angle. In other words, x is the difference between the one marked 72° and 50°, or 22°.

Answer:

15m⁹

Step-by-step explanation:

-3m² × -5m⁷ multiply bases (-3×-5=15). when multiplying bases you add exponents (2+7=9)

= 15m⁹

Answer: 88.4 centimeters

Step-by-step explanation:

Let's make a proportion:

412 m - 82.4 cm

442 m - x cm

Hence,

[tex]\displaystyle\\x=\frac{442*82,4}{412} \\\\x=\frac{442*82.4}{82.4*5} \\\\x=\frac{442}{5}=\\\\x=\frac{88,4*5}{5}=\\\\x=88,4\ cm[/tex]

Answer:

False

Step-by-step explanation:

This applies perfectly when x and y are negative.

What if both x and y are positive??

x=4, y=3.

4>3 which is true

but |4|<|3| = 4<3 ==> not true.

Hence, the answer is false

Answer:

Hello,

Answer 207

Step-by-step explanation:

[5, 29, 47, 61, 83, 225]

[5, 29, 41, 67, 83, 225]

[5, 23, 47, 61, 89, 225]

[5, 23, 41, 67, 89, 225]

[2, 5, 7, 43, 61, 89, 207]

[2, 3, 5, 47, 61, 89, 207]

[2, 3, 5, 41, 67, 89, 207]

import sys

#-------------------------------------------------------

def see(txt,arr):

   print (txt,"=",end =" ")

   for i in range(1,10 ):

       if arr[i]:

           print (i,end=" ")

   print ()

#-------------------------------------------------------

def libre(p):

   if p==0:

       return True

   if p<10:

       a=p

       if not(used[a]):

           return True

   else:

       a=p//10

       b=p%10

       if not(used[a]) and not(used[b] ):

           return True

   return False

#-------------------------------------------------------

def store(p):

# on ne stock pas 0

   global used

   #print ("in store ",p)

   if p==0:

       return

   if p<10:

       used[p]=True

   else:

       a=p//10

       b=p%10

       used[a]=True

       used[b]=True

   return            

def isSol():

   global mini,k,mini_set,all_mini_set

   for i in range(1,10):

       if not used[i]:

           return False

   s=i_1+i_2+i_3+i_4+i_5+i_6+i_7+i_8+i_9

   if s <= mini[0]:

       if s < mini[0]:

           k=k+1

       mini[0]=s

       mini[1]=i_1

       mini[2]=i_2

       mini[3]=i_3

       mini[4]=i_4

       mini[5]=i_5

       mini[6]=i_6

       mini[7]=i_7

       mini[8]=i_8

       mini[9]=i_9

       a_set=sorted(set([i for i in mini if i >0] ))

       if (a_set not in all_mini_set):

           mini_set=a_set.copy()

           all_mini_set.append(a_set)

           print (a_set)

       #print (mini,end="")

       """

       see("used ",used)

       see("sav_9",sav_9)

       see("sav_8",sav_8)

       see("sav_7",sav_7)

       see("sav_6",sav_6)

       see("sav_5",sav_5)

       see("sav_4",sav_4)

       see("sav_3",sav_3)

       see("sav_2",sav_2)

       see("sav_1",sav_1)

       """

       #if k>2:

       #    sys.exit(0)

   return True

#-------------------------------------------------------

#╚ 0 : ne pas utiliser

jeu=[

    [],

    [0,13, 17, 19, 31, 41, 61, 71],

    [0,2,23,29],

    [0,3,13,23,31,37,43,53,73,83],

    [0,41,43,47],

    [0,5,53,59],

    [0,61,67],

    [0,7,17,37,47,67,71,73,79,97],

    [0,83,89],

    [0,19,29,59,79,89,97]

    ]

print ("-------------------------------------------")

for i in range(10):

   print (jeu[i])

print ("-------------------------------------------")

mini=[1000]+[0 for i in range(1,10) ]

mini_set={}    

all_mini_set=[]

used=[False for i in range(10 )]

sav_1=used.copy()

k=0

for i_1 in jeu[1]:

   used=sav_1.copy()

   if libre(i_1):

       store(i_1)

       sav_2=used.copy()

       for i_2 in jeu[2]:

           used=sav_2.copy()

           if libre(i_2):

               store(i_2)

               sav_3=used.copy()

               for i_3 in jeu[3]:

                   used=sav_3.copy()

                   if libre(i_3):

                       store(i_3)

                       sav_4=used.copy()

                       for i_4 in jeu[4]:

                           used=sav_4.copy()

                           if libre(i_4):

                               store(i_4)

                               sav_5=used.copy()

                               for i_5 in jeu[5]:

                                   used=sav_5.copy()

                                   if libre(i_5):

                                       store(i_5)

                                       sav_6=used.copy()

                                       for i_6 in jeu[6]:

                                           used=sav_6.copy()

                                           if libre(i_6):

                                               store(i_6)

                                               sav_7=used.copy()

                                               for i_7 in jeu[7]:

                                                   used=sav_7.copy()

                                                   if libre(i_7):

                                                       store(i_7)

                                                       sav_8=used.copy()

                                                       for i_8 in jeu[8]:

                                                           used=sav_8.copy()

                                                           if libre(i_8):

                                                               store(i_8)

                                                               sav_9=used.copy()

                                                               for i_9 in jeu[9]:

                                                                   used=sav_9.copy()

                                                                   if libre(i_9):

                                                                       store(i_9)

                                                                       isSol()

                                                               used=sav_9.copy()

Answer: 50/100=0.5

100/10=10

Step-by-step explanation:

50/100=

1/2=0.5

100/10=

10^2 / 10^1 =

10^(2-1)=

10^1=10

50/100=0.5

100/10=10