The three‑dimensional structure of a generic molecule is given. Identify the axial and equatorial atoms in the three‑dimensional structure. What is the shape of this molecule?

Answer:

Your question is complex, because I think you wrote it wrong.

Although in front of this what I can help you is that the carbons are associated between a single, double or triple union.

This depends on whether they are attached to more or less carbons or hydrogens, the carbons have the possibility of joining 4 radicals, both other carbons and hydrogens.

Simple junctions talks about compound organisms called ALKANS.

The double unions, in organic these compounds are called as ALQUENOS.

And as for the tertiary unions, the organic chemistry names them as ALQUINOS.

These compounds that we write, a simple union, the less energy, the less this union, that is why the triple bond is the one that contains the most energy when breaking or destroying it in a reaction.

Explanation:

In a chemical compound the change of these unions if we modified them we would generate changes even in the classifications naming them as well as different compounds and not only that until they change their properties

Answer:

Answer:

The first should be left asis because carbon already has 4 bonds/8 electrons

The second needs to have a double bond to give carbon 4 bonds/8 electrons

The third must have a triple bong between the carbons to give them both 4 bonds/8 electrons

Explanation:

Make sure Hydrogen only has 1 bond/2 electrons at all times. Carbon needs a total of 4 bonds/8 electrons

Answer:

Explanation:

From the question, osmotic pressure exerted by a solution is equal to the MOLARITY multiplied by the absolute TEMPERATURE and the GAS CONSTANT r.

Let P = osmotic pressure,

C = molarity, then

T = absolute temperature

r=gas constant

The Osmotic pressure Equation exerted by a solution [tex]P=C*T*r[/tex]

[tex]P=CTr[/tex]

Then it was required in the question to write an equation that will let you calculate the molarity c of this solution, and this equation should contain ONLY symbols

C= molarity of the solution

P=osmotic pressure

r = gas constant

T= absolute temperature

[tex]C=P/(rT)[/tex]

The equation that will let us calculate the molarity c of this solution = [tex]C=P/(rT)[/tex]

Answer:

Atoms come together to form molecules because of their electrons. Electrons can join (or bond) atoms together in two main ways. When two atoms share electrons between them, they are locked together (bonded) by that sharing. These are called covalent bonds.

Explanation:

Answer:

Electrons

Explanation:

took the test got 100%

Answer:

The mass is 1.4701 grams and the moles is 0.01.

Explanation:

Based on the given question, the volume of the solution is 100 ml or 0.1 L and the molarity of the solution is 0.100 M. The moles of the solute (in the given case calcium chloride dihydride (CaCl2. H2O) can be determined by using the formula,  

Molarity = moles of solute/volume of solution in liters

Now putting the values we get,  

0.100 = moles of solute/0.1000

Moles of solute = 0.100 * 0.1000

= 0.01 moles

The mass of CaCl2.2H2O can be determined by using the formula,  

Moles = mass/molar mass

The molar mass of CaCl2.2H2O is 147.01 gram per mole. Now putting the values we get,  

0.01 = mass / 147.01

Mass = 147.01 * 0.01

= 1.4701 grams.  

The mass should be considered as the 1.4701 grams and the moles should be 0.01.

Since we know that

Molarity = moles of solute/volume of solution in liters

So,

0.100 = moles of solute/0.1000

Moles of solute = 0.100 * 0.1000

= 0.01 moles

Now The mass should be

Moles = mass/molar mass

0.01 = mass / 147.01

Mass = 147.01 * 0.01

= 1.4701 grams.  

hence, The mass should be considered as the 1.4701 grams and the moles should be 0.01.

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Answer:

Explanation:

Given that ;

Compound H is optically active and have a molecular formula of C6H10 and therefore undergo catalytic hydrogenation. Catalytic hydrogenation involves the use Platinum/Nickel to produce C6H12

i.e

[tex]C_6H_{10} +H_2 \to ^{Pt/Ni} \ \ \ C_6H_{12}[/tex]

The proposed H and I structures are shown in the diagrams attached below .

compound H represents  3- methyl cyclopentene

compound I represents methyl cyclopentane

However; 3- methyl cyclopentene posses just only one chiral carbon which is optically active at the third position and it R and S enantiomers are shown in the second diagram below.

The starting material is  3-methylcyclopentene while the optically inactive product is 1-methyl cyclopentane.

Hydrogenation refers to the addition of hydrogen across the double bond of an unsaturated compound. Hydrogenation results in the formation of a saturated compound having two more hydrogen atoms than the starting material.

The starting material is optically active 3-methylcyclopentene. The R and S enantiomers of the starting material is shown in image (1) attached. The optically inactive product is, 1-methyl cyclopentane is shown in image (2) attached.

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Answer:

219.15 grams

Explanation:

What is the mass of 3.75 moles of NaCI? ( Na= 22.99g/mol, CI= 35.45 g/mol)

Mole of Na = 22.99g

Mole of Cl = 35.45g

For NaCl we have ratio of 1:1, so we have 1 Na for every Cl

So we just add the two together to get the molar mass of NaCl which is

22.99 + 35.45 = 58.44g/mol

And we know we have 3.75 moles of NaCl so we multiply that by the molar mass of NaCl to get our answer

3.75 x 58.44 = 219.15grams

Answer:

D

Explanation:

Color, texture, and density are all physical properties but reactivity is a chemical property so the answer is D.

Answer:

Explanation:

An artifact is found in a desert cave. The anthropologists who found this artifact would like to know its age. They find that the present activity of the artifact is 9.25 decays/s and that the mass of carbon in the artifact is 0.100 kg. To find the age of the artifact, they will need to use the following constants:

r=1.2

The activity of carbon 14 is

[tex]A=A_0e^{\lambda t}[/tex]

where,

[tex]A_0[/tex] is the initial activity of the compound

Solve for t

[tex]-\lambda t=In\frac{A}{A_0}[/tex]

[tex]t=-\frac{1}{\lambda} In(\frac{A}{A_0} )[/tex]

[tex]=-\frac{1}{\lambda} In(\frac{A}{\lambda r(\frac{m_c}{m_a} )} )[/tex]

since,

[tex]A_0=\lambda r(\frac{m_c}{m_a} )[/tex]

[tex]=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )[/tex]

Now, the age of the artifact is

[tex]=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )[/tex]

[tex]=-\frac{1}{1.21\times 10^{-4}} In(\frac{(9.25)(2.32\times 10^{-26}}{1.21\times 10^{-4}(\frac{1}{3.15569\times10^7} )(1.2\times 10^{-12})(0.100)}} )\\\\=6303.4 \ years[/tex]

to two significant figure = 6300 years

Answer:

1.73 M

Explanation:

We must first obtain the concentration of the concentrated acid from the formula;

Co= 10pd/M

Where

Co= concentration of concentrated acid = (the unknown)

p= percentage concentration of concentrated acid= 37.3%

d= density of concentrated acid = 1.19 g/ml

M= Molar mass of the anhydrous acid

Molar mass of anhydrous HCl= 1 +35.5= 36.5 gmol-1

Substituting values;

Co= 10 × 37.3 × 1.19/36.5

Co= 443.87/36.6

Co= 12.16 M

We can now use the dilution formula

CoVo= CdVd

Where;

Co= concentration of concentrated acid= 12.16 M

Vo= volume of concentrated acid = 35.5 ml

Cd= concentration of dilute acid =(the unknown)

Vd= volume of dilute acid = 250ml

Substituting values and making Cd the subject of the formula;

Cd= CoVo/Vd

Cd= 12.16 × 35.5/250

Cd= 1.73 M

Answer:

An orbital is a region in space where there is a high probability of finding an electron.

Explanation:

The orbital is a concept that developed in quantum mechanics. Recall that Neils Bohr postulated that the electron occupied stationary states which he called energy levels. Electrons emit radiation when the move from a higher to a lower energy level. Similarly, energy is absorbed by an electron to move from a lower to a higher orbit.

This idea was upturned by the Heisenberg uncertainty principle. This principle state that the momentum and position of a particle can not be simultaneously measured with precision.

Instead of defining a 'fixed position' for the electron, we define a region in space where there is a possibility of finding an electron with a certain amount of energy. This orbital is identified by a set of quantum numbers.

Answer:

three - dimensional space that shows the probability where an electron is most likely to be found

Answer:

N≡N

Explanation:

The image attached shows the nitrogen compounds that are being referred to in the question.

There are certain things we ought to know in order to answer the question accurately.

The bond order of a compound is equal to the number of bonds between two atoms. The greater the bond order, the shorter the bond length between the two atoms.

N≡N has a bond order of three, this is the highest bond order among all the species listed in the question. Hence it has the shortest bond length among the trio. Hence the answer.

The correct answer is D. Hess's law states than the enthalpy of a reaction does not depend on the reaction path

Explanation:

In a chemical reaction, the enthalpy refers to the internal energy in a system and how this increases or decreases during the reaction. According to Hess's law proposed by German Hess in 1940, the enthalpy does not depend on the reaction path or the number of steps in a reaction. This means one reaction of only one step will have the same enthalpy that if the reaction occurs in several steps because the energy that requires all the process is the same. Thus, the "Hess's law states than the enthalpy of a reaction doe s not depend on the reaction path".

Answer: 75 grams sample of chemical X should contain 21.43 grams of carbon

Explanation: The law of definite proportion states that a given chemical compound always contains its component elements in fixed ratio.

From the question, chemical X contains 5.0 grams of oxygen, 10.0 grams of carbon, and 20.0 grams of nitrogen.

Sum up the masses

5.0g + 10.0g + 20.0g = 35.0g

This means, 10.0 grams of carbon are present in 35.0 grams of chemical X.

Now, to the determine the mass of carbon that 75 gram sample of chemical X should contain,

According to the law of definite proportion, the component elements of a given chemical compound are in fixed ratio. Therefore,

If 35.0g of chemical X contains 10.0g of carbon

Then, 75 g of chemical X will contain

(75 × 10) / 35 g

= 21.43 grams

Hence, 75 grams sample of chemical X should contain 21.43 grams of carbon.

Answer:

According to the law of definite proportion, a 75 gram sample of chemical X should contain 21.249 grams of carbon.

Explanation:

The total mass of the sample is equal to the sum of masses of oxygen, carbon and nitrogen. That is:

[tex]m_{tot} = m_{O} + m_{C} + m_{N}[/tex]

If [tex]m_{O} = 5\,g[/tex], [tex]m_{C} = 10\,g[/tex] and [tex]m_{N} = 20\,g[/tex], then:

[tex]m_{tot} = 35\,g[/tex]

According to the law of definite proportion, the following simple rule of three is used:

[tex]m_{C'} = m_{C} \times \frac{m_{tot'}}{m_{tot}}[/tex]

If [tex]m_{C} = 10\,g[/tex], [tex]m_{tot} = 35\,g[/tex] and [tex]m_{tot'} = 75\,g[/tex], then:

[tex]m_{C'} = 10\,g\times \frac{75\,g}{35\,g}[/tex]

[tex]m_{C'} = 21.429\,g[/tex]

According to the law of definite proportion, a 75 gram sample of chemical X should contain 21.249 grams of carbon.

Answer: The digestive system breaks down food into nutrients that are transported by the circulatory system.

Explanation:

An organ system includes the organs which are linked to one another to perform a physiological function in the body of the organism. The digestion is a complex process in which the food is being broken down into sub-components so that it can be assimilated in the body. The digestive system involves the multiple organs like mouth, esophagus, stomach, intestines and others. The food being digested is absorbed in the bloodstream, which circulate in the vital organs of the body like lungs, heart, vascular system hence, the blood becomes the part of the circulatory system.

Thus it can be said that the argument of children that the two systems are related is justified by the digestive and circulatory system of the body.

Answer:

Aqueous NaOH:     soluble

Aqueous NaHCO₃: insoluble

Aqueous Na₂CO₃:  soluble

Explanation:

The organic acid is insoluble. Its salt (ionic) is soluble.

The important principle is:

If you have two acids in a flask, the stronger acid (smaller pKₐ) will protonate the weaker one. The stronger acid will become ionic and therefore more soluble.

1. In NaOH

Let's write the formula for 4-nitrobenzoic acid as HA.

The equation for the reaction is

        HA  +  OH⁻ ⇌ A⁻ + H₂O

pKₐ:  7.15     15.7

HA is the stronger acid. It will protonate the hydroxide ion and be converted to the soluble 4-nitrobenzoate ion.

4-Nitrophenol is soluble in NaOH.

2. In NaHCO₃

        HA  +  HCO₃⁻ ⇌ A⁻ + H₂CO₃

pKₐ:  7.15     6.36

HCO₃⁻ is the stronger acid. It will protonate 4-nitrophenol.

4-Nitrobenzoic acid is insoluble in NaHCO₃.

3. In Na₂CO₃

        HA  +  CO₃²⁻ ⇌ A⁻ + H₂CO₃

pKₐ:  7.15    10.33

HA is the stronger acid. It will protonate the carbonate ion.

4-Nitrophenol is soluble in Na₂CO₃.

Answer:

  C

Explanation:

The molecule has 8 carbon atoms joined by 7 C-C bonds.

The first two diagrams show 6 carbon atoms, not 8.

The last two diagrams show line segments representing C-C bonds. Only choice C shows 7 such segments.

The appropriate choice is C.

Answer:

C.

Explanation:

Answer:

a. C > F > Cl

Explanation:

We know that atomic mass of Chlorine is greater than of  Florine than that of carbon. Moreover, in CF2Cl2, therefore, there are two atoms of Cl, F and one atom of C. Therefore, in CF2Cl2 in order of decreasing mass percent composition C > F > Cl. Therefore, the correct option is a.

Answer:

THE HEAT OF THIS REACTION PER MOLE OF SUCROSE IS 4868.75 KJ OF HEAT.

Explanation:

To answer this question:

First calculate the total heat given off by sucrose:

         Total energy/ heat = heat capacity * change in temperature

Heat capacity = 7.50 kJ/ °C

Change in temperature = 20.5 °C

Heat = 7.50 kJ * 20.5 °C

Heat = 153.75 kJ of heat.

Next is to calculate the heat of reaction per mole of the sucrose

Equation of the reaction:

               C12H22011 (s) + 12 O2 (g) ---------> 12 CO2 (g) + 11 H20(l)

Since 1 mole of sucrose will be the molar mass of sucrose, then we should calculate the molar mass of sucrose.

Molar mass of sucrose = ( 12* 12 + 1 * 22+ 16*11) g/mol

Molar mass = 342 g/mol of sucrose

Since 10.8 g of sucrose produces 153.75 kJ of heat, 342 g will produces how many joules of heat?

10.8 g of sucrose = 153.75 kJ of heat

342 g of sucrose = ( 342 * 153.75 kJ / 10.8)

= 52 582.5 kJ / 10.8

= 4868.75 kJ of heat

So therefore, 1 mole of sucrose will produce 4868.75 kJ of heat.

Answer: Ga > Ca > K

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies. The metals tend to get stable by losing electrons to attain noble gas configuration.

[tex]K:19:1s^22s^22p^63s^23p^64s^1[/tex]

[tex]K^+:18:1s^22s^22p^63s^23p^6[/tex]

[tex]Ca:20:1s^22s^22p^63s^23p^64s^2[/tex]

[tex]Ca^{2+}:18:1s^22s^22p^63s^23p^6[/tex]

[tex]Ga:31:1s^22s^22p^63s^23p^64s^23d^{10}4s^24p^1[/tex]

[tex]Ga^{3+}:28:1s^22s^22p^63s^23p^64s^23d^{10}[/tex]

Thus gallium (Ga) loses three electrons, Calcium (Ca) loses 2 electrons and Potassium (K) loses one electron.

Answer:

- Iron (III) oxide is the limiting reactant.

- [tex]m_{Al_2O_3}=319.9gAl_2O_3[/tex]

- [tex]m_{Fe}=350.4gFe[/tex]

Explanation:

Hello,

In this case, we consider the following reaction:

[tex]2Al + Fe_2O_3 \rightarrow Al_2O_3 +2Fe[/tex]

Thus, for identifying the limiting reactant we should compute the available  moles of aluminium in 268 g:

[tex]n_{Al}=268gAl*\frac{1molAl}{26.98gAl} =9.93molAl[/tex]

Next, we compute the moles of aluminium that are consumed by 501 grams of iron (III) oxide via their 2:1 molar ratio:

[tex]n_{Al}^{consumed}=501gFe_2O_3*\frac{1molFe_2O_3}{159.69gFe_2O_30}*\frac{2molAl}{1molFe_2O_3}=6.27molAl[/tex]

Thus, we notice there are less consumed moles of aluminium than available, for that reason, it is in excess; therefore, the iron (III) oxide is the limiting reactant.

Moreover, the theoretical mass of aluminium oxide is:

[tex]m_{Al_2O_3}=6.27molAl*\frac{1molAl_2O_3}{2molAl} *\frac{101.96gAl_2O_3}{1molAl_2O_3} =319.9gAl_2O_3[/tex]

And the theoretical mass of iron is:

[tex]m_{Fe}=6.27molAl*\frac{2molFe}{2molAl} *\frac{55.845 gFe}{1molFe} =350.4gFe[/tex]

Best regards.

Answer:

Explanation:

in your case ,

Meaured value = 112.3

actual value = 119.5

Absolute error= measured value - actual value

Percent error = [measured value - actual value  / actual value ] x 100

Hope this help you to find the answer

Answer:

The system is not in equilibrium and the reaction must run in the forward direction to reach equilibrium.

Explanation:

The reaction quotient Qc is a measure of the relative amount of products and reagents present in a reaction at any given time, which is calculated in a reaction that may not yet have reached equilibrium.

For the reversible reaction aA + bB⇔ cC + dD, where a, b, c and d are the stoichiometric coefficients of the balanced equation, Qc is calculated by:

[tex]Qc=\frac{[C]^{c}*[D]^{d} } {[A]^{a}*[B]^{b}}[/tex]

In this case:

[tex]Qc=\frac{[H_{2} ]*[I_{2} ] } {[HI]^{2}}[/tex]

Since molarity is the concentration of a solution expressed in the number of moles dissolved per liter of solution, you have:

So,

[tex]Qc=\frac{2.09*10^{-2} *4.14*10^{-2} } {0.280^{2} }[/tex]

Qc= 0.011

Comparing Qc with Kc allows to find out the status and evolution of the system:

If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.

If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

Being Qc=0.011 and Kc=1.80⁻²=0.018, then Qc<Kc. The system is not in equilibrium and the reaction must run in the forward direction to reach equilibrium.

Answer:

In this problem the correct thing would be to use the ideal gas equation.

Explanation:

Well in this exercise we will use the following equation:

(P x V) / T = (p x v) / t

On the right side of the equation we will find the initial values, that is, the values ​​with which the reaction begins and in general they are always the first to write in the problems.

Instead on the left side of the equation, the letters that are in lowercase are the final values, that is to say at the end of the reaction that the values ​​of pressure, temperature and volume are reached.

P is pressing, just like p, T and t are temperature, and V and v are volume.

We use this equation so we consider the behavior of said gas to be an IDEAL gas, a constant volume.

That is why the given pressures require an atmosphere to pass, which is another unit used to press the pressure ... Much needed in this equation! An atmosphere is equivalent to 760 millimeters of mercury ...

Then the final and initial pressures would be:

initial pressure: 1.15 atm

final pressure: 1.38 atm

In this way you already have the values ​​to be able to solve in the equation your unknown that would be the final temperature:

Considering that the volume is constant, we cancel it from the equation, 1.15 atm would be in the value of P and 1.38 in the value of p ... In this way it considers that 20 degrees Celsius is the initial temperature or ses T, we would only have to clear the t.

Answer:

The correct answer is 4.502 g per ml.

Explanation:

Based on the given question, the sum of the mass of mesitylene and barium together is 148.792 grams. The mass of barium given is 77.240 grams. Therefore, the mass of mesitylene will be,  

Mass of mesitylene = Total mass - Mass of barium

= 148.792 - 77.240

= 71.552 grams

The density of mesitylene is 0.86370 g per ml. To calculate the volume of mesitylene, the formula to be used is,  

Volume = mass / density. Now, putting the values we get,  

Volume = 71.552 / 0.86370 = 82.8436 ml.  

As the total volume is 100 ml, therefore, the volume of Ba will be,  

Volume of Ba = 100-82.8436 = 17.1564 ml

The density of Ba at 20 degree C can be calculated by using the formula,  

Density = mass / volume. Now putting the values we get,  

Density = 77.240 g / 17.1564 ml  

= 4.502 g per ml

Answer:

56.4 m

Explanation:

volume increases by factor of 6, i.e [tex]\frac{V2}{V1}[/tex] = 6

Initial temperature T1 at bottom of lake =  5.24°C = 278.24 K

Final temperature T2 at top of lake = 18.73°C = 291.73 K

NB to change temperature from °C to K we add 273

Final pressure P2 at the top of the lake = 0.973 atm

Initial pressure P1 at bottom of lake = ?

Using the equation of an ideal gas

[tex]\frac{P1V1}{T1}[/tex] = [tex]\frac{P2V2}{T2}[/tex]

P1 = [tex]\frac{P2V2T1}{V1T2}[/tex] = [tex]\frac{0.973*6*278.24}{291.73}[/tex]

P1 = 5.57 atm

5.57 atm = 5.57 x 101325 = 564380.25 Pa

Density Ρ of lake = 1.02 g/[tex]cm^{3}[/tex] = 1020 kg/[tex]m^{3}[/tex]

acceleration due to gravity g = 9.81 [tex]m/s^{2}[/tex]

Pressure at lake bottom = pgd

where d is the depth of the lake

564380.25 = 1020 x 9.81 x  d

d = [tex]\frac{564380.25}{10006.2}[/tex] = 56.4 m

Answer: -2.373  x 10^-24J/K(particles

Explanation: Entropy is defined as the degree of randomness of a system which is a function of the state of a system and depends on the number of the random microstates present.

The entropy change for a particle in a system  depends on the initial and final states of a system and is given by Boltzmann equation as  

S = k ln(W) .

where S =Entropy

K IS Boltzmann constant ==1.38 x 10 ^-23J/K

W is the number of microstates available to the system.

 The  change in entropy is given as

S2 -S1 = kln W2 - klnW1

dS = k ln (W2/W1)

where w1 and w2 are initial and final microstates

from the question, W2(final) = 0.842 x W1(initial), so:

= 1.38*10-23 ln (0.842)

=1.38*10-23  x -0.1719

= -2.373  x 10^-24J/K(particles)

According to the ideal gas law, when the temperature of a gas doubles, its volume doubles as well (Option B).

The ideal gas law relates the pressure, volume, number of moles and temperature of an ideal gas.

Let's consider the equation of the ideal gas law.

P . V = n . R .T

V = n . R . T / P

As we can see, there is a direct relationship between the volume and the temperature. Thus, if the temperature doubles, the volume will double as well.

According to the ideal gas law, when the temperature of a gas doubles, its volume doubles as well (Option B).

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