Answer:
There is no force in space.
Explanation:
Weight is the gravitational force acting on the mass as in space there is no gravity so weight appeares as zero
Answer:
It is because of gravity that your weight of a certain mass becomes zero in space.
Explanation:
Please give me concept to solve this.
Answer:
The difference in tension, between adjacent sections of the pull cable at the given conditions is 17.701 kN
Explanation:
We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation
[tex]F_{car}[/tex] = Upward tension force, [tex]Tension_{(upwards)}[/tex] - Downward tension force, [tex]Tension_{(downwards)}[/tex] - Component of the weight of the car along the taut cable
The parameters given are;
Mass of car, m = 2750 kg
Angle of inclination of taut cables, θ = 35°
The upward acceleration of the car, a = 0.81 m/s²
Given that the weight is acting vertically downwards, we have;
Component of the weight of the car along the taut cable = m × g × sin(θ)
∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N
We therefore have;
[tex]F_{car}[/tex] = [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] - 15473.66 N
[tex]F_{car}[/tex] = m × a = 2750 × 0.81 = [tex]T_{upwards}[/tex] - [tex]T_{downwards}[/tex] - 15473.66
∴ [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] = 2750 × 0.81 + 15473.66 = 17701.16 N
Hence the difference in tension, [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.
The amplitude of a particle executing simple harmonic motion is 5cm, while its angular velocity is 10 rads -1 . Calculate the magnitude of the maximum acceleration of the particle.
Answer:
a_max = 50 cm/s^2
Explanation:
To find the magnitude of the maximum acceleration of the particle, you take into account the equation of motion in a simple harmonic motion:
[tex]x=Acos(\omega t)[/tex]
ω: angular velocity = 10 rad/s
A: amplitude = 5 cm
The acceleration is given by:
[tex]a=\omega^2 x[/tex]
and the maximum acceleration is obtained when the cosine function is maximum, that is, when cos(wt) = 1. Then, you have:
[tex]a_{max}=\omega^2 x_{max}=\omega^2A[/tex]
Then, you replace the values of w and A in order to calculate a_max:
[tex]a_{max}=(10rad/s)^2(5cm)=50\frac{cm}{s^2}[/tex]
hence, the maximum acceleration is 50 cm/s^2
i reallllly need someone to answer this quick. it's fine if you can't though
Answer:
The correct order of answers goes:
[tex]\left[\begin{array}{ccc}Ionic\\Electronegativity\\Metallic\\Cation\end{array}\right][/tex]
Explanation:
Ionic - Ionic bonds are formed between a metal and a nonmetal (typically). Nonmetals are typically more electronegative elements because they are seeking to gain electrons to achieve atomic stability while metals want to give up electrons to those elements to become atomically stable. Therefore, the nonmetals are much more electronegative in comparison to the metals.
Electronegativity - Electronegativity is used mathematically to predict the type of bond that will occur between elements. The larger electronegativity has the smaller electronegativity subtracted from it to give us a number that we then apply to ranges within a table and try to decipher what kind of bond will be formed.
Metallic - This plays into both explanations already given. Metallic bonds will form between metals, meaning their electronegativities will be much lower. Higher differences between electronegativities (anything above 1.7) is considered ionic, while anything from 0.1 to 1.69 is considered covalent (these split to make polar and nonpolar covalence).
Cation - Cation is the term for a positively charged ion. It comes from cathode (a scientist completed an experiment with the cathode ray tube where they accelerated positively charged particles throughout it).
A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4u2) N, where u is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revol
A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity [tex]\omega _o = 1 \ rad/s[/tex] and radius from the center of the disc = 300 mm
Answer:
the angular acceleration = 205.706 rad/sec²
Explanation:
GIVEN THAT:
The disc mass = 8 kg
Force = [tex]\dfrac{1}{4} \ \ \theta ^2* N[/tex]
We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:
[tex]\theta = 5 rev * (\dfrac{2 \ \pi * rad}{1 rev}) \\ \\ \theta = 10 \ \pi \ rad[/tex]
Also;
the initial angular velocity [tex]\omega _o = 1 \ rad/s[/tex]
radius from the center of the disc = 300 mm = 0.3 m
Thus; the mass moment about the Inertia can be determined via the following expression;
[tex]I_o = \dfrac{1}{2}*m*r^2[/tex]
[tex]I_o = \dfrac{1}{2}*8*0.3^2[/tex]
[tex]I_o = 0.36 \ kg/m^3[/tex]
Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;
SO:
[tex]\sum M_o = I_o \alpha[/tex]
[tex]F*0.3 = 0.36* \alpha[/tex]
[tex]\dfrac{1}{2}* \theta^2 *0.3 = 0.36* \alpha[/tex]
[tex]\alpha = 0.20836 \ \theta^2 \ rad/sec^2[/tex]
[tex]\alpha = 0.20836 \ (10 \ \pi )^2 \ rad/sec^2[/tex]
[tex]\alpha = 205.706 \ rad/sec^2[/tex]
Hence; the angular acceleration = 205.706 rad/sec²
Njoki planted trees at intervals of 22m apart on the diagonal of a rectangular plot of land that measures 48m by 20m . How many trees did he plant
Answer:
The number of tree is 2Explanation:
the diagonal of the rectangular plot of land can be found using Pythagoras theorem (the diagonal is the hypotenuse)
Given
length of land x= 48m
width of land y= 20m
digonal z= ?
[tex]z^2= x^2+y^2\\\\z=\sqrt{ x^2+y^2} \\[/tex]
substituting the values of x and y into the equation we can solve for z
[tex]z=\sqrt{ 48^2+20^2} \\\\z=\sqrt{ 2304+400} \\z=\sqrt{ 2704} \\z=52m\\[/tex]
The diagonal is 52m
Hence since the interval = 22m the number if treee is
[tex]\frac{52}{22} = 2.36\\[/tex]
The number of trees must be whole numbers , the number of tree is 2
If a body of mass 10 kg is pushed with a force of 15N, then the acceleration of the body is
Answer:
1.5m/s2
Explanation:
F=ma
a=F/m
a=15/10
a=1.5m/s2
What would Genaris and her classmates most likely do to
test this idea?
its
Explanation:
they would formulate a new hypothesis with the same dependent variable but a different independent variable as a virginal hypothesis .
50 COINS AMAZING PLEASE HELP ME!!!
Answer:
ok
Explanation:
Ok
Talia is on a trip with some friends. In the first 2 hours , they travel 100 miles. Then they hit traffic and go only 30 miles in the next hour. The last hour of their trip , they drive 75 miles
Answer:
51 miles/hour
Explanation:
Talia is on a road trip with some friends. in the first 2 hours, they travel 100 miles. then they hit traffic and go only 30 miles in the next hour. the last hour of their trip, they drive 75 miles. calculate the average speed of talia’s car during the trip. give your answer to the nearest whole number.
The average speed would be 51 miles/hour.
The average speed of a moving object is defined as the total distance traveled relative to the total time taken fro the journey. Mathematically, it is given as:
total distance traveled/total time taken.
In this case;
Total distance traveled = 100 + 30 + 75 = 205 miles
Total time taken = 2 + 1 + 1 = 4 hours
Therefore;
Average speed = 205/4 = 51.25 miles/hour
To the nearest whole number = 51 miles/hour
What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??
Answer:
F = 37.5 N
Explanation:
It is given that,
Mass of the object is 5 kg
Acceleration of the object is 7.5 m/s²
We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,
F = m
[tex]F=5\times 7.5\\\\F=37.5\ N[/tex]
So, the force acting on the object is 37.5 N.
Apply Newton's first law to music playing on the radio.
Answer: Find the answer in the explanation
Explanation:
The music playing on the radio will be heard through the sound waves coming from the radio.
The travelling wave will obey Newton's first law of motion which state that:
An object or particle will remain at rest or continue its linear motion in a straight line except an external force is applied.
The external force through wind could affect the travelling of the sound waves. Since the wave is longitudinal wave. That is, it needs a medium (air) for its propagation.
what is the capital of Ghana and also Togo.
Answer:Ghana - Accra Togo - Lomé I hope this helps mark me brainlist
Explanation:
Accra is the Capital of Ghana
Accra was founded in the 17th century by the Ga people. It became the capital of the British Gold Coast in 1877 and the capital of Ghana on the formation of the country as an independent state in 1957
Accra Is the Second Most Expensive City in Africa
Accra is known for its colorful textile and used or second-hand clothing markets. Located inside the Makola Market, Kantamanto is the largest trading point in all of Accra.
The capital of Togo is Lomé
Lomé, city, capital of Togo. Lomé lies on the Gulf of Guinea (Atlantic coast) in the extreme southwestern corner of the country. Selected as the colonial capital of German Togoland in 1897, it became important as an administrative, commercial, and transport centre.
It is also the country's chief port, from where it exports coffee, cocoa, copra, and oil palm kernels- Lome
Lomé was founded by the Ewe, an indigenous ethnic group, in 1880. Located on the southwestern Atlantic coast of Togo, Lomé has a long history of trade. In 2000, an estimated 900,000 people resided in Lomé. Europe's “Scramble for Africa” began in 1880.
Use the worked example above to help you solve this problem. An Alaskan rescue plane drops a package of emergency rations to stranded hikers, as shown in the figure. The plane is traveling horizontally at 39.0 m/s at a height of 1.50 102 m above the ground. (a) Where does the package strike the ground relative to the point at which it was released? (b) What are the horizontal and vertical components of the velocity of the package just before it hits the ground? horizontal and vertical (c) Find the angle of the impact.
Answer:
(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact is 77.19°
Explanation:
The parameters given are;
Velocity of the plane, vₓ = 39.0 m/s
Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m
(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;
h = u·t + 1/2×g×t²
Where:
g = Acceleration due to gravity = 9.81 m/s²
u = Initial vertical velocity = 0 m/s
Hence;
1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²
∴ t = √(1500/4.905) = 17.49 s
The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m
The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The vertical velocity, [tex]v_y[/tex], of the package just before landing is given by the relation;
[tex]v_y[/tex]² = u² + 2·g·h
u = 0 m/s
∴ [tex]v_y[/tex]² = 0 + 2×9.81×1500 = 29430 m²/s²
[tex]v_y[/tex] = √29430 = 171.55 m/s
Hence the horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact, θ, is given as follows;
[tex]tan \theta = \dfrac{v_y}{v_x} = \dfrac{171.55}{39.0 } = 4.4[/tex]
∴ θ = tan⁻¹(4.4) = 77.19°.
A lonely child is swinging on a rusty old swing set, as seen in the image provided. If friction does 145 J of work slowing the swing, what is the maximum speed she can reach?
Answer:
2.331
Explanation:
It just the change of Energy from potential (PE) to kinetic (KE)
PE on A = PE on B + KE on B + friction works (Wf)
mg(ha) = mg(hb) + ½mv² + Wf
35 * 9.8 * 1.5 = 35 * 9.8 * 0.8 + ½ * 35 * v² + 145
514.5 = 274.4 + 17.5v² + 145
514.5 - 274.4 - 145 = 17.5v²
17v² = 95.1
v² = 5.434
v =√5.434 = 2.331 m/s
A car starts from rest and develops an acceleration of 2 m/s2. If the distance covered by the car during its motion is 100m, what is the final velocity attained by the car?
Answer:
20
Explanation:
because I am always right yo bro be like me
How does charging by conduction work?
Answer:
During charging by conduction, both objects acquire the same type of charge. If a negative object is used to charge a neutral object, then both objects become charged negatively. ... In this case, electrons are transferred from the neutral object to the positively charged rod and the sphere becomes charged positively.
The mass of a certain man is 250g..
I. What is the weight of the man on earth
ii. What is the weight of the man on the moon
I promise to mark u the brainliest, please help me
Answer:
2,450
400
Explanation:
Pls brainliest me
12.0 V car battery has a voltage drop of 3.4 V when the starter draws 93 A of current. What is the resistance of the starter? O 88 m2 84 mg O 80 m2
Answer:
[tex]R_s = 0.093 \Omega[/tex]
Explanation:
Voltage of the car battery = 12.0 V
Voltage drop in the battery = 3.4 V
The remainder of the voltage is the starter voltage, that is:
Starter voltage = Initial battery voltage - voltage drop
Starter voltage = 12.0 - 3.4
Starter voltage, [tex]V_{s}[/tex] = 8.6 V
Current drawn by starter, [tex]I_s[/tex] = 93 A
According to Ohm's law: [tex]V_s = I_s R_s[/tex]
Starter Resistance, [tex]R_s[/tex] = [tex]V_s/I_s[/tex]
[tex]R_s = 8.6/93\\R_s = 0.093 \Omega[/tex]
how much energy (in kW-h) does a 900 Watt stove use in a week if it is used for 1.5 hours each day?
Answer:
9.45 kWh
Explanation:
Energy = Power × time
E = 900 W × (1.5 h/day × 7 day)
E = 9450 Wh
E = 9.45 kWh
A cork weigh 2.5 gf in air. When tied to a sinker , the total weight is 20 gf in water. If the sinker alone weighs 25gf in water, find the density of the cork
Answer:
0.333
Explanation:
Weight of the sinker in water = 25gf
Weight of cork in air and sinker in water = 25gf + 2.5gf
= 27.5gf
Weight of the cork and sinker in water = 20gf
Loss of weight of cork in water = 27.5- 20 = 7.5gf
Rd of cork = weight of cork in air/ loss of weight of cork in water
= 2.5/7.5
= 1/3
= 0.333
Hence the Relative density of the cork is 0.333
A remote controlled plane accelerates to a velocity of 21.0 m/s while covering a distance of 87.4 m in 6.11 s. What was the plane's initial velocity?
Answer:
7.61 m/s
Explanation:
Given:
Δx = 87.4 m
v = 21.0 m/s
t = 6.11 s
Find: v₀
Δx = ½ (v + v₀) t
87.4 m = ½ (21.0 m/s + v₀) (6.11 s)
v₀ = 7.61 m/s
71.6
Δx = 87.4 m
v = 21.0 m/s
t = 6.11 s
Find: v₀
Δx = ½ (v + v₀) t
87.4 m = ½ (21.0 m/s + v₀) (6.11 s)
v₀ = 7.61 m/s
please answer this question first one to answer the right answer will be marked brainiest
Answer: Force per unit area. Explanation: P = 25/20. P = 5/4 Pascal or 1.25 Pascal
Explanation: is this what you were looking for
Se realiza un experimento en el que se mide el alargamiento de un muelle debido a la acción de una pesa; se trata de comprobar la ley de Hooke. Los datos que se han obtenido son: Medición 1 2 3 4 5 Alargamiento 42.0 48.4 51.3 56.3 58.6 Masa 2 4 6 8 10 El coeficiente de determinación es:
Answer:
m = 1,975 m / kg , b = 38.05 m
Explanation:
In this experiment, the elongation is plotted against the applied mass
getting a straight line
y = m x + b
where b would be the initial length of spring let's calculate the slope for which we use two well separated points
m = (56.3 -48.4) / (8 - 4)
m = 1,975 m / kg
the equation remains
y = 1,975 x + b
for x = 2 kg y = 42.0 m
we substitute in the equation
42 = 1,975 2 + b
b = 42 - 3.95
b = 38.05 m
Hi can someone help with this:
1) The volume of a gas is 4 m3 when its pressure is 200 kPa. Assuming the temperature does not change, calculate its pressure when the volume is 3 m3 .
2) The pressure of a gas is 1.8 × 105 Pa when its volume is 80 cm3 . Its temperature is constant. Calculate its volume when the pressure becomes 1.2 × 105 Pa.
I'd appreciate if there was working shown
Answer:
2.67 x10 power5 PascalExplanation:
pv=nRT n, R,T--constantso, p1v1=p2v2
p2=p1xv1/v2
What does the phrase "1 meter per second per second" means? A. The velocity of an object can increase by 1 meter per second, for every minute of time measured. B. The velocity of an object can increase by 1 meter per second, for every second of time measured. C. The velocity of an object can increase by 1 meter per second.
Explanation:
"1 meter per second per second" means acceleration of an object. It is equal to the rate of change of velocity. Its SI unit is [tex]m/s^2[/tex].
It is simply given by :
[tex]a=\dfrac{dv}{dt}[/tex]
dv is change in velocity
dt is small interval of time
"1 meter per second per second" means that the velocity of an object can increase by 1 meter per second.
A frisbee is flying through the air. Which forces are acting on it (choose 3)
Answer:
The force acting on it is lift
The pressure exerted by 15m of liquid is 1500pa.The acceleration due to gravity g=10m/s^2.Calculate the density liquid.
Answer:
1500 divided by 150(15m x 10m/s^2) = 10
Rhodes research indicates that people are generally accurate in guessing the ages of unfamiliar persons based on their faces. This research has important implications for
The available options are:
A. bartenders serving alcohol
B. students identifying their professors.
C. Doctors diagnosing cases of schizophrenia.
D. eyewitnesses identifying suspects from a lineup.
Answer:
A. bartenders serving alcohol
Explanation:
This is because of the underage rule concerning sale of alcohol. Thus, there are occasional period in which underage person or a minor will want to buy alcohol, and without necessarily asking for the birth certificate or ID card that contains Age information, it is therefore, necessary for bartenders to be able to tell the age of their unfamiliar customers, by mere looking at them, so as not to sell to a minor.
Hemce, Rhodes research in guessing the age of unfamiliar person has important implications for BARTENDERS SERVING ALCOHOL, because it will guide them to determine Underage or Minor, that want to buy alcohol from them.
what is mercury barometer
When is the magnitude of the acceleration of a mass on a spring at its maximum value?
A.
when the mass has a speed of zero
B.
when the mass is moving upward
C.
when the mass has no displacement
D.
when the mass is 1
2 x
Answer:
D
Explanation:
Now we know that Force is the rate of change of momentum meaning
F= mv/t
But
mv/t = Ke
v/t = ke/m
a= ke/m
Where a is acceleration
K is constant of proportionality of tension on a spring
e is the extension substended by a string.
From the formula of acceleration we can see that as mass decreases acceleration increases so we can see that m = 1
We would have a maximum value of acceleration.
The Answer Is....:
D.
