The+speed+of+light+in+a+certain+type+of+glass+is+50%+slower+than+the+speed+of+light+in+air.+what+is+the+index+of+refraction+for+that+type+of+plastic?

A quasi-equilibrium process is a process during which a system never remains in equilibrium at all times is a - True statement

A quasi-equilibrium process is one in which a system is nearly in equilibrium at all times.

Numerous engineering procedures can roughly be described as quasi-equilibrium processes. When quasi-equilibrium processes are used instead of non-quasi-equilibrium processes, a device's work output is maximized and its work input is minimized.

An illustration of this is the quasi-static expansion of a mixture of hydrogen and oxygen gas, in which the system's volume changes so slowly that the pressure stays constant throughout the system at every instant of the process. A series of physical equilibrium states comprise this idealized process, which is characterized by infinite slowness.

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The velocity function is v = -0.0676cos(2.16 . x - 3.52 . t)

We need to know about vectors function to solve this problem. The velocity is depend on position vector and acceleration. It can be written as

v = dy / dt

where v is velocity, dy is displacement and dt is time interval.

From the question above, we know that

y =  0.0192sin(kx - ωt)

k = 2.16 /m

ω = 3.52 rad/s

Substitute k and ω to y

y =  0.0192sin(kx - ωt)

y =  0.0192sin(2.16 . x - 3.52 . t)

Hence, the velocity is

v = dy / dt

v = d(0.0192sin(2.16 . x - 3.52 . t)) / dt

v = 0.0192 . (-3.52) . cos(2.16 . x - 3.52 . t)

v = -0.0676cos(2.16 . x - 3.52 . t)

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Social media is the example of an external communication.

The procedures in charge of communicating with individuals and groups outside of your organization are known as external communications. Customers, companies, suppliers, partners, investors, government organizations, and law enforcement are a few of these.

Email, brochures, newsletters, posters, advertisements, and other types of multi-media marketing are common examples of external communication that are used to entice clients, partners, and suppliers to engage in profitable business dealings.

External communications' main objective is to convey to the public an important message about the organization's efforts and level of excellence. An aspect of communication that organizations cannot directly control is informal external communication.

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Answer:

Metalloid

Explanation:

Hope this helps!

It is false. The period of a pendulum clock increases if you increase the length of the pendulum.

The time period of a pendulum clock is directly proportional to the square root of the length.

The formula of the time period of a simple pendulum is:

                                       T = 2π√(l/g)

According to the formula, time period T is directly proportional to the square root of length and inversely proportional to gravity. The time period will increase if we increase the length of the pendulum clock.

For example, the time period will increase by two times if we increase the length of the pendulum by four times.

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False, the period of a pendulum clock does not decreases if you increase the length of the pendulum. Their variation is directly proportional.

The square root of the length of a simple pendulum determines its period in a direct proportion. In other words, as length grows, so does the amount of time.

The relationship between two values where their ratio equals a constant number is known as a direct proportion or direct variation. In our case, the two values are.

1. Square root of the length of the pendulum

2. Period of a pendulum

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The number of valence electrons in neutral atoms equals the atom's main group number. A periodic table column can be used to determine an element's main group number.

The position-time graph depicts the movement of an item across time. Time in seconds is traditionally represented on the x-axis, while object location in metres is plotted along the y-axis. The slope of the position-time graph offers vital information about the object's velocity.

Gravity causes objects in free fall to accelerate. As a result, the free fall motion position-time graph must be curved. This means that objects in free fall begin with a moderate velocity and gradually accelerate, as illustrated by the graph's steep downward curve.

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Answer:

Pulse & Heart Rate. Your heart rate is the number of times each minute that your heart beats, which is normally between 60 and 100 times per minute for adults. Your pulse is a way you can feel each time your heart beats

Explanation:

By using sonar echo, the depth of the sea is 222 m.

We need to know about the sonar echo to solve this problem. Sonar detection sends the sound wave through a medium to detect an object. The sound wave needs to travel from the transmitter to the object and then come back to the receiver. It can be determined by

v = 2.s / t

where v is the speed of sound, s is the distance and t is the time interval sound wave released until received.

From the question above, we know that

t = 0.3 s

v = 1480 m/s

By substituting the given parameters, we get

v = 2.s / t

1480 = 2 . s / 0.3

s = 740 . 0.3

s = 222 m

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The peak (+ve half) and trough (-ve half) portions of the waveform signal flatten out or are "Clipped-off" when the input amplitude is too high, forcing the output waveform signal to exceed the power supply voltage rails.

Over the whole auditory range of frequencies from 20 Hz to 20 kHz, the majority of contemporary audio amplifiers exhibit the same flat frequency response as seen above. The Bandwidth (BW) of an audio amplifier, which is mostly influenced by the circuit's frequency response, is the range of frequencies it can handle. The power in the high frequency band, from 8 to 24 Hz, divided by the power in the low frequency band, from 3 to 5 Hz, is known as the frequency ratio.

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For the expected output waveform from an ideal differentiator circuit having input waveform vin=1sin[(2)1000t] v, the expression can be stated as Vo(t) = -0.09424 cos(2π(1000)t)V.

A waveform is a typically graphic representation of a wave’s shape that describes its properties (such as frequency and amplitude).

Sinusoidal, triangular, and square waveform outputs are all simultaneously available from separate output terminals.

A waveform is only a graphic that aids in our comprehension of sound waves. They track the movement of one air molecule over time.

We can change a waveform’s amplitude to make it louder or quieter, and we can change a waveform’s frequency to change the pitch.

Herein,

Rf = 1.5k

C = 10 nF

Vin = 1sin(2π(1000)t)V

Vo(t) = -Rfc dvin(t)/dt

Vo(t) = -1.5 x 10^3 x 10 x 10^-9 d/dt (1sin(2π(1000)t))

Vo(t) = -15 x 10^-6 x 2π x 1000 [cos(2π(1000)t]

Vo(t) = -94.24 x 10^-3 cos(2π(1000)t)V

Vo(t) = -94.24cos(2π(1000)t) mV

or Vo(t) = -0.09424 cos(2π(1000)t)V

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The resultant voltage is V=23.9mV.

Potential energy is a type of energy, and when differences are taken into account, the definition of potential is potential energy (or potential energy difference) per unit charge or V=E/Q. That matches your equation exactly. The amount of electrical charge transmitted by a potential difference of V volts. Quantity of electric charge (coulombs) x potential difference equals the energy transmitted in joules (volts) Q = electrical charge transported (C), V = p.d., E = energy transfer in joules (J), and V = E/Q. (V)

E=41mj

q=1.71c

The resultant voltage,

E = Q×V

[tex]V = (41\times10^{-3}) / 1.71[/tex]

V = 0.02397

V = 23.9mV

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value of the activation energy (in kj/mol) Ea = 67.8 kJ/mol

k = Ae-Ea/RT

ln k = -Ea/RT + ln A

k = 0.20287

R = 8.314 J/mol-K = 0.008314 kJ/mol-K

T = 45.5ºC + 273 = 318.5K

A = 2.7x1010

Ea = ?

ln (0.20287) = [-Ea / (0.008314)(318.5)] + ln 2.7x1010

-1.596 = (-Ea / 2.648) + 24.02

-25.616 = -Ea / 2.648

Ea = 67.8 kJ/mol

A chemical reaction that has a reaction rate that is linearly dependent on the concentration of just one ingredient is known as a first-order reaction. In other terms, a first-order reaction is a chemical reaction in which only one of the reactants' concentrations is changed and the rate of the reaction changes as a result

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When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet exhibits retrograde motion.

Retrograde motion is the apparent change in movement of any planet in the sky. It is not real such that the planet doesn't make any movement physically in its orbit.

The planet just appears to be in a movement because the relative positions of that planet and our planet, Earth and how these two planets  move around the Sun.

Therefore, Retrograde motion is actually an illusion which is related to the movement of this Earth-based observer.

One familiar example occurs when an individual passes a car on a freeway, the car that passed appears to have moved backwards, relative to that individual.

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By using the torque, the shear stress is 2.36 lb/ft².

We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as

τ = F x r

where τ is torque, F is perpendicular force and r is radius.

Shear stress can be calculated by torque

P = F / A

P = τ / (π.r³)

where P is shear stress, r is the radius.

From the question above, the parameter given are

τ = 200 ft.lb

d = 6 ft

Find the radius

r = 1/2 . d

r = 3 ft

Find the shear stress

P = τ / (π.r³)

P = 200 / (π.3³)

P = 2.36 lb/ft²

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The result of evaluating the following postfix expression 6 4 + * 3 10 +, the result of this postfix expression can be calculated as 13.

We want to find the value of the postfix expression:

6 4 + * 3 10 +

We will start from the left most operation symbol.

For each of the operation symbol, the two integers preceding the operation symbol are the symbols on which the specified operation needs to be performed. Then we have to replace the operational symbol with the two of the following integers as per the result of the operation.

Then we repeat for the left most operation symbol in the remaining string.

Thus, evaluating postfix,

6 4 + * 3 10 +

= 10 * 3 10 +

= 10 * 13

= 0 13

= 13

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The molarity of the solution is 0.0293 m. 1.928 g of kno3 are dissolved in 651 ml of water.

The amount of a substance in a solution stated as an amount of substance per unit volume of solution is known as molar concentration, also known as molarity, quantity concentration, or substance concentration. The most common unit used in chemistry to express molarity is the number of moles per liter, represented by the unit sign mol/L or mol/dm3 in SI units. One molar, or 1 M, of a solution is defined as one mol/L.

The use of molar concentration in thermodynamics is typically not applicable because the volumes of most solutions very minimally change with temperature due to thermal expansion.

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The beam used is a negatively charged electron beam with a velocity of

v = E / B where E is the electric field and B is a magnetic field.

Now indicates that the electric field and the magnetic field are contracted and that the beam passes without deviating, so the electric and magnetic forces must be balanced

        Fe = Fm

        q * E = q * v * B

        v = E / B

this configuration is called speed selector.

The beam used is a negatively charged electron beam with a velocity of v = E / B.

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Although part of the question is missing the complete question is A depiction of a famous scientific experiment is given. Consider how the beam changes when the magnet is off compared to when the magnet is on. A bell-shaped evacuated glass tube with a narrow end and a wide end is connected to a battery at the narrow end. In the center of the tube there is a negatively charged plate above the tube, a positively charged plate below the tube, and a magnet with the field turned off. A beam originating at the narrow end of the tube travels toward the wide end of the tube. With the magnetic field turned off, the beam path bends toward the positively charged plate and ends at the lower half of the wide end of the tube. A bell-shaped evacuated glass tube with a narrow end and a wide end is connected to a battery at the narrow end. In the center of the tube there is a negatively charged plate above the tube, a positively charged plate below the tube, and a magnet with the field turned n. A beam originating at the narrow end of the tube travels toward the wide end of the tube. With the magnetic field turned on, the beam path travels in a straight path to the center of the wide end of the tube. What type of beam was used in this experiment?

Answer:

Greater the acceleration, greater the force

Explanation:

because the speed of the ball will have more force

Answer: 4.5 mL

Explanation:

1000 mL=1 L

0.0045L * 1000 mL/1 L=

0.0045 * 1000/1=

0.0045 * 1000=4.5 mL

The stored energy is [tex]3.83x10^{-6}[/tex] J.

Explanation:

Given that,

One side of square plates = 8.5 cm

Distance = 2.5 mm

Charge = 14 nC

We need to calculate the energy stored

The energy is stored by the electric field between two square plates is defined as, A abrupt release of collected energy, known as "stored energy," has the potential to result in severe harm or even death. Gravitational potential energy, pressurised gases and liquids, stored mechanical energy, and stored electrical energy are only a few examples of the many different types of stored energy.

4 types of stored energies are:

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The final speed of the train after 42 minutes is 90 km/h

We are provided with acceleration, initial speed and time after which final speed is to be found

Let us consider the motion of the train to be in one dimension

Then, formulas of one dimension can be applied to find the final speed.

Let the initial speed of the train be 'u'

Let the final speed of the train be 'v'

Let the acceleration due to gravity be 'a'

Let the time take to reach the speed 'v' be t

Now, as per the data given,

u=55km/h

acceleration due to gravity= 50km/h^2

Time taken, t= 42 minutes

Now as we can see that all units are in km/h, time must also be in hour

As we know that 1 hour= 60 minutes

therefore, 42 minutes= 42/60=7/10= 0.7 hour

Now using the formula v = u +at

v =  u +at

v = 55 + 50 x 0.7

v = 55 +35 = 90 km/hr

Hence, the final speed of the train after 42 minutes is 90 km/h

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2Q charge should it have on its plates.

The electric field between plates is the area or space where the plates' charge influences can be seen.

For example, if a charged particle is placed near any charged plate, the plate exerts an electric force to attract or repel the charged particle.

Either positive or negative charges are present in charged particles.

Since electrons are always negatively charged, a negatively charged particle carries more electrons (negative charges) than protons (positive charges).

Therefore, there must be fewer electrons than protons in order for charged particles to be positive.

A plate becomes positively or negatively charged when charged particles are placed on it, and a charged plate generates an electric field all around it.

Gauss's law is shaped by the surface.

Calculating the area of shapes with a defined geometry is simple.

The Gauss's law equation can be written as the surface charge density divided by the medium's electric permittivity in the case of a sphere or rectangular plate.

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As an object's mass increases, the gravitational force grows (also called the gravity force). The gravitational force rapidly decreases as the distance between masses increases.

Greater gravitational forces will be used to attract heavier objects because the gravitational force is directly proportional to the mass of both interacting objects. Therefore, the gravitational attraction between two objects grows as their respective masses do as well.

The masses of the two objects and their separation from one another will determine how much gravitational force there is between them. Each object's mass and gravitational force are inversely proportional. This implies that an object's gravitational force increases with mass.

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Answer: Block A - 19.3

Block B - 0.64

Block C - 0.70

Block D - 0.917

Block E - 3.53

Explanation: i hope this helps you a little

A typical water bed with a volume of 28 cubic feet has a weigh of: 1792 pounds

To solve this problem the we have to do the conversion of units with the given information.

Information about the problem:

By using the conversion factor we have:

m(water bed)= 28 ft³ * 64 pounds / 1ft³

m(water bed)= 1792 pounds

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

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Answer:

[tex]0.70\; {\rm kg}[/tex].

Explanation:

If an object of mass [tex]m[/tex] is travelling at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object would be [tex]p = m\, v[/tex].

In this question, both momentum [tex]p[/tex] and velocity [tex]v[/tex] are given, and mass [tex]m[/tex] needs to be found. Hence, rearrange the equation [tex]p = m\, v[/tex] and solve for [tex]m\![/tex]:

[tex]\begin{aligned} m &= \frac{p}{v} \\ &= \frac{3.22\; {\rm kg \cdot m \cdot s^{-1}}}{4.6\; {\rm m\cdot s^{-1}}} \\ &= 0.70\; {\rm kg}\end{aligned}[/tex].

Therefore, the mass of this ball would be [tex]0.70\; {\rm kg}[/tex].

Answer:

E = - dΦ / dt

(b) would be the correct answer

The average velocity of the ball is 1.14 m/s.

Since there is no height given, we can assume that the ball was rolling on a non-inclined surface.

Distance covered by the ball = 18 meters

Time taken by the ball = 15.7 seconds

The velocity of the ball = Distance / Time taken

Velocity= 18/15.7

Velocity= 1.14 m/s

and since there is no initial velocity given, it is the average velocity of the ball.

The distance traveled divided by the time passed is the definition of an object's average speed. Average velocity can be calculated as the displacement divided by the time. Velocity is a vector quantity. The straight line average velocity formulae are invalid for broad scenarios involving non-constant acceleration, hence this definition must be used directly.

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The minimum initial velocity u = 58.3°

(v0) min = 9.76 m/s

Coordinate System: The coordinate system will be set so that its origin coincides with the ball’s initial position.

x-Motion: Here (v0) = v0 cos u x0 and x = 6 m Thus,                

 (+)     x = [tex]x_{0}[/tex] + (v0)xt

           6 = 0 + (v0 cos u)t

           t = 6/v0 cos u                                       (1)          

y-Motion: Here (v0)x = v0 sin u, ay = -g = -9.81m/s  and y0 = 0  

   ( A + c B)    y = y0 + (v0)y t +1/2 [tex]a_{y}[/tex][tex]t^{2}[/tex]

                      3 = 0 + v0 (sin u)t + 1/2 (-9.81) [tex]t^{2}[/tex]

                       3 = v0 (sin u)t - 4.905[tex]t^{2}[/tex]               (2)

Substituting Eq. (1) into Eq.(2) yields

        v0 = [tex]\sqrt[2]{\frac{58.86}{sin 2u - cos2 u} }[/tex]                                       (3)

From Eq. (3), we notice that is minimum when is

maximum. This requires [tex]\frac{df(u)}{du}[/tex]

[tex]\frac{df(u)}{du}[/tex] = 2 cos2u + sin2u = 0

tan2u = -2

2u = 116.57°

u = 58.28° = 58.3°

Substituting the result into Eq.(2), we have

(v0)min = [tex]\sqrt[2]{\frac{58.86}{sin 116.57° - cos2 58.28°} }[/tex]

(v0)min =  9.76 m/s

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