They want the volume of the family-sized box to be three times the volume of the regular-sized box. However, they want the length of the family-sized box to be the same as the regular-sized box.

If they decide to double the width to create the family-sized box, by what factor must they increase the height?

Answer:

C and D.

Step-by-step explanation:

In option C, they are collecting data about the lengths of fish in a pond.

In option D, they are collecting data about people's favorite show.

Hope this helps!

If not, I am sorry.

[tex]x^2+4x-7=x^2+4x+4-11=(x+2)^2-11[/tex]

Inequalities help us to compare two unequal expressions. The correct option is A.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The complete question is:

The sum of 16 and a number is less than 24. Which of the following inequalities expresses the solution?

x<8

x>8

x=8

x<-8

Given the sum of 16 and a number is less than 24. Let the number be represented by x, therefore,

16 + x < 24

x < 24 - 16

x < 8

Hence, the correct option is A.

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Answer:

x = 3.16

Step-by-step explanation:

x * x = 10

[tex]x^2 = 10[/tex]

square root both sides

[tex]\sqrt{x^2} = \sqrt{10}[/tex]

[tex]x = \sqrt{10}[/tex]

x is appr. 3.16

Answer:

x=  √-10, √ 10

Step-by-step explanation:

The telephone number datatype is text or string

The term is given as:

telephone number

A telephone number contains the following

The optional parts of a phone number makes it difficult to use the numeric datatype for a phone number.

So, we make use of text or string datatype

Also, the phone number cannot be used in calculations.

Hence, the telephone number datatype is text or string

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The telephone number is what type of data

Answer:

parallel

a quadrilateral can be a parallelogram only and only if pair of opposite sides are equal and parallel.

Answer:.20

Step-by-step explanation:

According to what are written in the table the probability for x=-10 is .20

16.39492

Step-by-step explanation:

Total number of plants is p³ +2 ; when p = 3 the number of plants is 29 , Option D is the right answer.

Equation is mathematical statement formed when two algebraic expressions are equated using an equal sign.

It is given that  

Let p represent the original number of plants in her garden.

then  total number of plants in her garden =  p³ +2

the total number of plants if p = 3 is

=3³ +2

= 29

p³ +2 ; when p = 3 the number of plants is 29 , Option D is the right answer.

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Answer:

[tex]\frac{XM}{4y}=u[/tex]

Step-by-step explanation:

First, multiply both sides by M.

X M = 4uy

Now, divide both sides by 4y.

[tex]\frac{XM}{4y} =\frac{4uy}{4y}[/tex]

Therefore,

[tex]\frac{XM}{4y}=u[/tex]

Answer:

Step-by-step explanation:

Note: It seems the question is wrong when it states the relationship of distance. If d is the distance from the ground, at t = 0, we get d = 0 too which means with no time spent, Math Man hits the ground.

It assumed d = t²*0.25 is the distance from the top of the building.

We know the height of the building is 500 meters.

We need to find the value of t, when d = 500 m:

The equation would be y = kx with k being a constant.

Assuming the gravitational force is y and the mass of the body is x. y is directly proportional to the x.

Mathematically,

y = kx where k = constant.

If y = 19.6 Newtons and x = 2 kg, then

k = y/x = 19.6/2 = 9.8.

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Answer:

Mean score for the class B is 66.66

Step-by-step explanation:

Mean : It is the sum (total) of all the values in a set of data, such as numbers or measurements, divided by the number of values on the list.

Mean = sum of all numbers/ total numbers

Given,

mean score of class A = 34.

mean score of both the classes = 55

mean score of class a = sum of marks/total strength of class

                              34   = sum of marks/10

                             340 = sum of marks of class A

similarly,  Mean score of both classes

= ( sum of marks of class A and class B)/(total students in both classes)

= (340 + sum of marks of class B)/ 28  

55 =  (340 + sum of marks of class B)/ 28  

55 × 28 =  (340 + sum of marks of class B)

1540 - 340 = sum of marks of students of class B    

     1200    =  sum of marks of students of class B  

now to find Mean score of class B

sum of marks of students of class B / total students in class B

1200/18 = 66.66 answer  

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It has a period of 2pi

the equation to find the period of a sin/cos function is

[tex]period = \frac{2\pi}{b} [/tex]

y = -2 sin(x) has a normal period of 2pi because the b value in this equation isn't stated, making it equal to 1

the basic equation for a sin function is

[tex]y = a \: \sin(b(x - c) ) + d[/tex]

Let's take this problem step by step:

To find the ordered pair of the system:

 ⇒ must set both equations equal to each other

     ⇒ solve for 'x'

Let's solve:

 [tex]x^2-2x+3=-2x+12\\x^2-2x+2x+3-12\\x^2-9=0\\(x+3)(x-3)=0[/tex]

Let's find the x-values:

 [tex](x+3)=0\\x=-3\\\\(x-3)=0\\x+3[/tex]

Let's find f(x)'s value for each 'x':

 [tex]x=-3\\f(-3)=-2(-3)+12=6+12=18\\\\x=3\\f(3)=-2(3)+12=-6+12=6[/tex]

Answer: (3, 6), (-3,18)

Hope that helps!

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Answer:

Step-by-step explanation:

Answer:

C.  20 ≤ h < 30

Step-by-step explanation:

Median

The value in the middle of the data set when all the data values are placed in order of size.

As this is grouped data, we can only estimate the median.

Add an extra row to the table showing the Cumulative Frequency:

[tex]\begin{array}{|c|c|c|}\cline{1-3} \sf Height & \sf Frequency & \sf Cumulative\:Frequency \\\cline{1-3} \sf 0 \leq h < 10 & 1 & 1 \\\cline{1-3} \sf 10 \leq h < 20 & 9 & 10 \\\cline{1-3} \sf 20 \leq h < 30 & 7 & 17 \\\cline{1-3} \sf 30 \leq h < 40 & 13 & 30 \\\cline{1-3}\end{array}[/tex]

To find which class the median is in, divide the total number of data values by 2:

[tex]\implies \sf \dfrac{n}{2}=\dfrac{30}{2}=15[/tex]

Therefore, there are 15 values less than or equal to the median.

From the table, the 11th to 17th data values are in class 20 ≤ h < 30.  Therefore, the median must be in the 20 ≤ h < 30 class.

Answer:

C (look at explain!)

Step-by-step explanation:

The IQR for male data is 10, the estimated difference between medians is 2, the box plot for males is symmetric and for females, the box plot is left side skewed.

A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.

From the box plot:

Part A:

IQR for males data:

IQR = Q3 - Q1

The estimated value of Q3 is 15 (between 10 and 20)

The estimated value of Q1 is 5 (between 0 and 10)

IQR = 15 -5 = 10

Part B:

= Median(male) - Median(femal)

= 10 - 8

= 2

Part C:

The box plot for males is symmetric and for females, the box plot is left side skewed.

Part D:

There can be holidays for the outliers

Thus, the IQR for male data is 10, estimated difference between medians is 2, the box plot for males is symmetric and for females, the box plot is left side skewed.

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Answer:

c =  68 m

Step-by-step explanation:

To find the hypotenuse 'c' use Pythagorean theorem

       hypotenuse² = base ² + altitude²

                    c²       = 60² + 32²

                               = 3600 + 1024

                               = 4624

                  [tex]\sf c=\sqrt{4624}\\\\ c= \sqrt{2*2*2*2*17*17}=2*2*17\\\\\boxed{\bf c = 68 \ m }[/tex]

2x² + 2x + ? = x

⇒ ? = x - 2x² - 2x

⇒ ? = -2x² - x

Your answer is incorrect because 2x² - x² would mean x² is part of the answer, which is clearly incorrect.

Answer: The domain would be all real numbers.

Step-by-step explanation:

This is not a piecewise function, so it means that the domain, which means all possible x values, is all real numbers, not imaginary.

If you vertically stretch the exponential function f(x)=2^x by a factor of 3, the resulting function will be y = 3*2^x

The standard exponential function is expressed as:

y = ab^x

The value of x determines the nature of a graph whether vertical or horizontal stretch.

If x  > 1, it is a vertical stretch

Given the function f(x) = 2^x, if you vertically stretch the exponential function f(x)=2^x by a factor of 3, the resulting function will be y = 3*2^x

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The reflection is written as:

[tex]g(x) = -3*(1.5)^x[/tex]

And the graph can be seen below.

Here we have the function:

[tex]f(x) = 3*(1.5)^x[/tex]

A reflection across the x-axis is given by:

[tex]g(x) = -f(x).[/tex]

Then, replacing the function f(x) by the actual equation:

[tex]g(x) = -3*(1.5)^x[/tex]

The graph of the function g(x) can be seen below:

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Answer: 19/30 or about 63%

Step-by-step explanation: Add all your marble up so 6+4+5+15 to get the total amount of options or marbles in this case. Now find out how many red and blue marbles you have so 4+15 or 19 now you can divide the red and blue marbles by the total amount of marbles to get your percentage of pulling a red or blue marble from the bag.

Answer:

angle s = 22

angle r = 117

angle q = 41

Step-by-step explanation:

so all of the angles equal to 180 degrees in a triangle

so you add all of t he angles like this:

x+5x+7x+2x-3=180

collect all of the like terms,

8x + 4 = 180

subtract 4 from both sides, which leaves you with 8x = 176

divide both sides by 8 leaving x on its own.

x = 22

angle s = 22

angle r = (5x22)+7 which is 117

angles q = (2x22)-3 which is 41

Answer: B. 55°

Step-by-step explanation: A single line is 180°. There are two of those lines that are both marked, meaning that they are equal. If this is true, then that must be the same for the other side. We would just have to find the angle for that.

180°- 125° = 55°

Therefore, the answer is B. 55°.

I hope this helps! Pls give brainliest!! :)

[tex] \huge\underline{\underline{\boxed{\color{blueviolet}{ANSWER}}}}[/tex]

★ 15 trucks can carry 26,850 kg weight

★ We've to find the weight carried by one truck

[tex]\huge \pink {\overline{ \quad \quad \quad \quad \quad \quad \quad\quad \quad}}[/tex]

[tex] \sf{Number \: of \: trucks = 15 }[/tex]

[tex] \sf{Weight \: carried \: by \: one \: truck = \frac{26,850Kg}{15} }[/tex]

[tex] \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= 1790Kg[/tex]

Therefore , the weight carried by one truck is 1790 kg

Answer + Explanation:

#1 Simplification:

(2x - 3) - (x - 4)

2x - 3 - x + 4

2x - x - 3 + 4

x + 1

#2 Factorization:

16 - 4x²

-4x² + 16

-4(x² - 4)

-4(x² - 2²)

-4(x + 2)(x - 2)