this stationary wave is what we call the first harmonic of the first normal mode of the system. in units of l, the length of the wire, what is λ1, the wavelength of the first harmonic?

Answer:

It can be either a moon or a satellite

Explanation:

a moon is a piece of space debris that orbits a planetdue to the planets gravitational force. Inherently, satellite mimics a moon but it is used for collecting data and etc

Answer:

its Q

Explanation:

Answer:

[tex]2.5m/s^{2}[/tex]

Explanation:

Since the distance ,s = 500m

Initial velocity, u = 0m/s

Final velocity, v = 50m/s

We can one of the kinematics equations to find the acceleration.

[tex]v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}[/tex]

Answer:

S=D÷T

Explanation:

50=0.5÷T

T= 100

Last one!

Perpendicular to the wave's energy

Hope this helps!

When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

Newton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.

The mathematical interpretation of the above law is

Removing the proportionality sign,

Where:

From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

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Gyroscopic wander can be divided into two categories and these are:

Gyroscopic wander can be defined as a movement of the spin axis (axis of rotation) away from a specific fixed direction.

Based on scientific information and records, there are two main types of gyroscopic wander and these include the following:

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The moon's orbital plane is different from that of the earth's orbit around the sun due to which lunar and solar eclipses do not occur every month.

When the moon passes in front of Earth and the sun, it creates a solar eclipse and casts a shadow across the globe.

Only during the new moon phase, when the moon travels squarely between the sun and Earth and casts shadows on its surface, can a solar eclipse occur.

Due to the moon's orbit being five degrees off-center from Earth's orbit around the Sun, lunar eclipses do not happen every month and the Moon often passes above or below the shadow.

Lunar eclipses would happen every month if there were no tilt. Eclipses of the sun and the moon happen equally often.

Hence lunar and solar eclipses aren't coming every month.

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The reason why lunar and solar eclipses do not occur every month is because; the plane of orbit of the moon around the earth is not same as that of earth around the sun.

When the Moon passes between Earth and the Sun, there's solar eclipse while when the earth passes between the Sun and the Moon, casting a shadow on the Moon, there's lunar eclipse.

Hence, because the plane of orbit of the moon around the earth is not same as that of earth around the sun, we do not have lunar and solar eclipses every month.

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In the image below, the focus lines are shown. The step can be done to bring the apple into focus is make the lens rounder. The correct option is A.

The lens is in spherical shape may be diverging or converging.

As light enters the eye, it is focused on the retina. Changing the pupil diameter, regulates the amount of light entering the eye. Changing lens shape will focus the light.

The changes in lens shape needed to maintain focus as the object distance changes.

Thus, the correct option is A.

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Answer:

a?

Explanation:yes it is a

The change in the momentum of the cart,given the data is 0.06 Kgm/s (Option D)

Momentum is defined as the product of mass and velocity. It is expressed as

Momentum = mass × velocity

Change in momentum = mass (final velocity - initial velocity)

From the data given above, the following data were obtained:

Change in momentum = m(v + u) (renounce)

Change in momentum = 0.5 (-0.24 + 0.36)

Change in momentum = 0.5 × 0.12

Change in momentum = 0.06 Kgm/s

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Taking into account the Newton's second law, the amount of force required to keep the object in motion if you ignore the surface friction is 0 N.

In first place, acceleration in a body occurs when a force acts on a body. There are two factors that influence the acceleration of an object: the net force acting on it and the mass of the body.

Newton's second law states that this force will change the speed of an object because the speed and / or direction will change. These changes in velocity are called acceleration.

So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object.

Mathematically, Newton's second law is expressed as:

F= m×a

where:

In this case, you know:

Replacing in Newton's second law:

F= 5 kg× 0 m/s²

Solving:

F= 0 N

Finally, the amount of force required to keep the object in motion if you ignore the surface friction is 0 N.

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Answer:

Weaker, stronger

Explanation:

hope this helped!

Answer:

[tex]\fbox {weaker, stronger}[/tex]

Explanation:

The farther you bring charged objects from each other, the weaker the electrical force between them, and the bigger the charges on the objects, the stronger the electrical force between them.

Proving

Here we need the formula for Coulomb's Law, which is :

[tex]\boxed {F = \frac{1}{4\pi\epsilon_{0}}\times\frac{q_{1}q_{2}}{r^{2}}}[/tex]

As we can see, when the distance increases, the overall force will decrease as they are inversely proportional.

Similarly, as the product of charges is directly proportional to the electrical force produced, as the charges increase, the force increases.

Answer:

your answer would 50 m/s I do believe

The correct answer for the speed of the ball upon resting to it's starting point is [tex]50[/tex] m/s.

Given:

Initial speed: [tex]u = 50[/tex] m/s

To calculate the speed upon resting position, Calculate the time requires to reach starting position:

Time required to reach starting point  = 2 * (Time require to reach the maximum height)

Time required to reach the maximum height:

[tex]v = u+(-a )t[/tex]

Final velocity([tex]v[/tex]) is  [tex]0[/tex] m/s.

Negative sign indicates negative acceleration:

[tex]t= \dfrac{50}{9.8}\\\\ = 5.10[/tex]seconds

Time for start point  = [tex]2 * 5.8[/tex]

[tex]=10.6[/tex] seconds

From equation of motion:

[tex]v= u+at[/tex]

[tex]= 50 -9.8* 10.2[/tex]

[tex]= -50.2[/tex] m/s

Negative sign indicates downward direction.

Speed when ball return is  is [tex]50[/tex] m/s.

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Answer:

no way to tell since the ocean surface is moving too violently it's not possible to determine the reflected angle

Answer:

The value of mass 1, m1= 6/5m

The value of mass 2, m2= 3/5m

Explanation:

case 1:

here tension and the acceleration will be:

for m1;

for m2:

adding the both equations,

2mg - 2T + 2T-mg = 2ma + ma/2

a = 2/5 g

putting the value of a into the equation 1.

mg - T = m* (2/5)g

T = 3/5 ( mg )

now

case 2:

The two identical blocks are released from the rest, the tension remains the same as the case 1.

so,

for m1:

for m2:

adding both equations we get,

2T-m2g + 2m2g - 2T = 0

m2 = m1 / 2

T = m1*g / 2

here we know that

T (case1) = T (case2)

3/5 ( mg ) = m1*g / 2

m1 = 6/5 m

hence

m2 = 3/5 m

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If all the wires have the same diameter, they will all stretch by the same percent. The elasticity does not depend upon the length.

Distance is a numerical representation of the distance between two locations. The distance can refer to a physical length or an estimate based on other factors in physics or common use.

|AB| is a symbol for the distance between two points A and B.

A physiological method for identifying far-off or unseen items using sound waves that the objects reflect back to the source, such as a bat. Each one will enlarge by the same percentage.

Hence, they will all stretch by the same percentage.

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Answer:

The absorption lines will shift to the red (become longer).

This is because of the extra distance that a wavelength λ must travel between the vibrations of the source producing the spectrum.

Note that the Doppler effect of the source is slightly different for light waves than it is for sound waves because sound waves require a medium in which to travel while light waves do not require such a medium (example air).

scalars: distance, speed, time

vectors: displacement, velocity, acceleration

The distance of the cliff from where you are is determined as 3,430 m.

Apply the formula for echo.

v = 2d/t

where;

2d = vt

d = vt/2

d = (343 x 20)/2

d = 3430 m

Thus, the distance of the cliff from where you are is determined as 3,430 m.

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a) 4.9 m

b) 38.3 m/s

c) 33.4 m

The three equations are,

v = u + at

v² = u² + 2as

s = ut + ½at²

According to the question,

Let hold the y-axis in the direction of gravity.

Initial velocity 0 = 0 /,

Initial height ℎ0 = 0 , and finish height ℎ = 75.0

gravitational acceleration = 9.8 /²

a) Determine the distance traveled during the first second.

By third equation of motion

[tex]S_{0} = v_{0} t +\frac{1}{2} gt^{2}[/tex]  where [tex]v_{0}[/tex] =0

then [tex]S_{0} = \frac{gt^{2}}{2} = \frac{9.8*1^{2} }{2} = 4.9 m[/tex]

b) Determine the final velocity at which the object hits the ground

let – velocity of object, when it falling to the ground

– moment falling to the ground, and obtain from condition:

ℎ = ℎ() = 75.0

[tex]v_{f} = v_{0} +gt = gt[/tex]

[tex]h (t_{f} ) = \frac{gt^{2} }{2} = 75.0 m\\t_{f} =\sqrt{\frac{2h_{f} }{g} } \\v_{f}= gt = g \sqrt{\frac{2h_{f} }{g} } =\sqrt{2hg_{f} }= =\sqrt{2*9.8*75.0} = 38.3 m/s[/tex]

c) Determine the distance traveled during the last second of motion before hitting the ground.

From the above equation we get,

[tex]\sqrt{2*75*9.8*1} - \frac{9.8*1^{2} }{2} = 38.3 -4.9 = 33.4 m[/tex]

Therefore,

a) 4.9 m is the distance traveled during the first second.

b) 38.3 m/s is the final velocity at which the object hits the ground

c) 33.4 is the distance traveled during the last second of motion before hitting the ground.

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Squeezing the clutch lever to slow down is best to be done when approaching a curve and is denoted as option C.

This is a mechanical device which used in the engagement and disengagement of transmission system in a vehicle.

Slowing down will give the driver more time to maneuver the curves so as to prevent accident. This is why it is imperative to squeeze the clutch in such road condition.

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Answer:

6/5  * R

Explanation:

The 3 in series sum to 3R for one branch of the parallel circuit

 the 2 in series sum to 2R  for the other side of the parallel circuit

now find the equivalent R of the parallel circuit with 3R and 2R

 here is one way

   Requiv = 1 / ( 1/(3R) + 1/(2R) ) =

                  1/ ( 5/(6R) ) =

                    6R/5  

the equiv resistance = 6/5  * R

Answer:

40kg

Explanation:

w=m×

w=400n

g=10

m=?

400/10=m×10/10

m=40

According to the research, the agonic line is the line joining all places of zero variation.

It is a term that refers to the zero declination isogon, that is, it joins the points that do not have magnetic declination.

This line crosses the magnetic and geographic poles of the Earth's surface from which they are aligned and along which there is no magnetic variation.

Therefore, we can conclude that according to the research, the agonic line is the line joining all places of zero variation.

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Answer:

1.76 seconds/cycle

Explanation:

Frequency is   10 cycles / 17.6 seconds

PERIOD is  1/frequency = 17.6 seconds/10 cycles = 1.76 s/c    

          cycle is a vibration , so the unit may be  1.76 second / vibration

Answer:

B

Explanation:

That is solar energy and the sun will be releasing energy constantly for the rest of its life, meaning renewable

Since we assume the accelerations are constant, the instantaneous acceleration is the same as the average acceleration, so in the first 6.80 seconds we have

[tex]\alpha_1 = \alpha_{\rm ave} = \dfrac{\Delta \omega}{\Delta t} = \dfrac{8.70\frac{\rm rev}{\rm s}}{6.80\,\rm s} \approx 1.28 \dfrac{\rm rev}{\mathrm s^2}[/tex]

In this time, the tub undergoes an angular displacement of

[tex]\theta_1 = \dfrac12 \alpha_1 (6.80\,\mathrm s)^2 \approx 29.6\,\mathrm{rev}[/tex]

In the next 19.0 seconds the tub has acceleration

[tex]\alpha_2 = \dfrac{-8.70\frac{\rm rev}{\rm s}}{19.0\,\rm s} \approx -0.458 \dfrac{\rm rev}{\mathrm s^2}[/tex]

and in this time, the tube undergoes an additional displacement of

[tex]\theta_2 = \left(8.70\dfrac{\rm m}{\rm s}\right)(19.0\,\mathrm s) + \dfrac12 \alpha_2 (19.0\,\mathrm s)^2 \approx 82.7\,\mathrm{rev}[/tex]

So the tub completes [tex]\theta_1+\theta_2 \approx \boxed{112\,\mathrm{rev}}[/tex].

the distance is the first 80m+the second 80m she came back. So the distance is 160m. but the displacement is 0, because she came back by the direction she went.

Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force between them the power of the gravitational pressure among gadgets relies upon on factors, mass and distance. the pressure of gravity the loads exert on every other.

Gravitational pressure -an appealing pressure that exists among all items with mass; an item with mass draws every other item with mass; the value of the pressure is immediately proportional to the loads of the 2 items and inversely proportional to the rectangular of the gap among the 2 items.

Since the gravitational pressure is immediately proportional to the mass of each interacting items, greater large items will entice every different with a more gravitational pressure. So because the mass of both item increases, the pressure of gravitational appeal among them additionally increases.

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