The statement that best describes the line segment drawn in relation to the y-axis is (c) the y-axis is a bisector of the segment drawn.
The transformation rule is given as:
[tex](x,y) \to (-x,y)[/tex]
When the triangle is reflected to form triangle H'A'M', the vertices of triangle H'A'M' would be:
[tex]H'A'M' = (-x,y)[/tex]
So, the distance from point A to the y-axis is equidistant to the distance from point A' to the y-axis.
This, in other words means that the y-axis bisects the line segment AA'.
Hence, the relation between the segment and the y-axis is (c)
Read more about reflection at:
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Answer:
C. The y-axis is a bisector of the segment drawn.
Step-by-step explanation:
what is 7/8 divided by 1/8
Answer:
7
Step-by-step explanation:
Concepts:
Division: a system of distributing a collection of things into equal partsFractions: #s that represent a part of a wholeDividing Fractions: dividing a fraction by another fraction = multiplying the fraction by the inverse (reciprocal) of the other oneInverse Operations: operations that are opposite of each other (e.g. inverse of addition is subtraction)Solving:
1. First, let's set up the equation:
7/8 ÷ 1/8
2. We can get the reciprocal of 1/8 by doing the opposite of division; multiplication. 1/8 becomes 1 · 8, and that's equal to 8.
3. Now, since we know dividing a fraction by another one is exactly the same as multiplying the fraction by the reciprocal of the other, let's multiply 7/8 by the inverse of 1/8, which is 8.
7/8 · 8 = 56/8 = 7
Therefore, 7/8 divided by 1/8 is equal to 7.
Given a triangle MTN, prove that
<m+<t+<n= 180° strictly
use m, T and N with other
Letters in your triangle.
Answer:
[tex]\angle m + \angle t + \angle n = 180[/tex]
Step-by-step explanation:
Required
Show that:
[tex]\angle m + \angle t + \angle n = 180^o[/tex]
To make the proof easier, I've added a screenshot of the triangle.
We make use of alternate angles to complete the proof.
In the attached triangle, the two angles beside [tex]\angle m[/tex] are alternate to [tex]\angle t[/tex] and [tex]\angle n[/tex]
i.e.
[tex]\angle 1 = \angle t[/tex]
[tex]\angle 2 = \angle n[/tex]
Using angle on a straight line theorem, we have:
[tex]\angle 1 + \angle m + \angle 2 = 180[/tex]
Substitute values for (1) and (2)
[tex]\angle t + \angle m + \angle n = 180[/tex]
Rewrite as:
[tex]\angle m + \angle t + \angle n = 180[/tex] -- proved
determine the general term of this sequence -15:-11;-7;,,173
Answer:
UWUNOE BRO HUUZEM HIHUDHS
Step-by-step explanation:
A shopkeeper sold a piece of kurta salwar for rs. 1080 at a loss of 10%.At what price should he sell to gain 10% on it
Answer:
1320 Rs.
Step-by-step explanation:
let cost price=x
loss=10 %
S.P.=x×90/100=9x/10
9x/10=1080
x=1080×10/9=1200 Rs
so C.P.=1200 Rs
gain=10%
S.P.=110/100×1200=1320 Rs
help please help asap :)
Answer:
4x^3
Step-by-step explanation:
20 x^5 + 28 x^4 + 12x^3
4*5*x^5 + 4*7*x^4 + 4*3*x^3
Factor out 4x^3
4x^3 ( 5x^2 + 7x +3)
Art class has 444 tables. There are 999 pencils at each table.
Ava multiplied 4\times94×94, times, 9 to find the total number of pencils.
Finn multiplied 9\times49×49, times, 4 to find the total number of pencils.
Who is correct?
Choose 1 answer:
Answer:
Both Ava and Finn are correct
Step-by-step explanation:
There are 4 tables and 9 pencils at each table
4 ( 9) = 36
9 * 4 = 36
Both Ava and Finn are correct
A 100m mast is supported by six cables in two sets of three cables. They are anchored to the ground at an equal distance from the mast. The top set of three cables is attached at a point 20m below the top of the mast. Each cable in the lower set of three cables is 60m long and is attached at a height of 30m above the ground. If all the cables have to be replaced, find the total length of cable required?
Answer:
60
would be right
Step-by-step explanation:
Total length of cable required is 466.18 m.
What is Pythagoras theorem?Pythagoras theorem states that In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.
According to the question
A 100m mast is supported by six cables in two sets of three cables.
They are anchored to the ground at an equal distance from the mast.
The top set of three cables is attached at a point 20m below the top of the mast.
Each cable in the lower set of three cables is 60m long and is attached at a height of 30m above the ground.
One set of guy wires (1 upper and one lower have two right triangles which can solve
The lower right triangle
a = distance from the pole to guy tie point
b = 30 m
c = 60 m the lower guy wire (the hypotenuse)
Using Pythagoras theorem
[tex]a^{2} +30^{2} =60^{2}[/tex]
⇒ [tex]a^{2} = 3600 - 900[/tex]
⇒ [tex]a^{2} =2700[/tex]
⇒ [tex]a = \sqrt{2700}[/tex]
⇒ [tex]a = 51.96[/tex] m from the pole to the tie point.
The other triangle using upper guy wire as the hypotenuse (h) tied to a point on the pole 80 m from the ground (20 m from the top) and also 50m from the tie point.
Using Pythagoras theorem
[tex]h^{2} =(51.96)^{2} +80^{2}[/tex]
⇒ [tex]h^{2}=2700+6400[/tex]
⇒ [tex]h^{2}=9100[/tex]
⇒ [tex]h = \sqrt{9100}[/tex]
⇒ [tex]h = 95.39[/tex] m , the length of the upper guy wire
For one set of guy wires (1 upper & 1 lower):
= 95.39 + 60
= 155.39 m
For 3 sets of guy wires :
= 3(155.39)
= 466.18 m of wire required
Hence, total length of cable required is 466.18 m.
Find out more information about Pythagoras theorem here
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Help pls will give brainliest
Answer:
b
Step-by-step explanation:
area of triangle = 1/2 x c x d =cd/2
area of semicircle = 1/2 x π x r^2 = 1/2 x π x (a/2)^2 = 1/2 x π x a^2/4 =πa^2/8
area of shape = area of triangle + area of semicircle
A force of 80 N is exerted on an object on a frictionless surface for a distance of 4 meters. If the object has a mass of 10 kg, calculate its velocity
Answer:
V = 8 m/s
Step-by-step explanation:
Assuming that the object was at rest, so μ = 0
Equations
F=ma - Newtons 2nd law
[tex]v^{2} = u^{2} + 2a[/tex]Δx - 4th kinematic equatioin
Step 1 - find "a"
F=m/a
a=F/m
a=80/10
a=8m/s^2
Step 2 - find "v"
v^2 = 0 + 2 * 8 * 4
v^2 = 64
v=8m/s
Help me with my work plz.
Answer:
(√366 - 3)/24
Step-by-step explanation:
Given the following:
cos∝ = √3/8 and sinβ = √3/3
Sin(∝-β) = sin∝cosβ - cos∝sinβ
Get sin∝
Since cos∝ = √3/8
adj = √3
hyp = 8
opp = √8² - (√3)²
opp = √64 - 3
opp = √61
Recall that sin∝ = opp/hyp
sin∝ = √61/8
Get cosβ
Since sinβ = √3/3
opp = √3
hyp = 3
adj =√3² - (√3)²
adj = √9-3
adj = √6
Recall that cosβ = adj/hyp
cosβ = √6/3
Substitute the gotten values into the formula
Sin(∝-β) = sin∝cosβ - cos∝sinβ
Sin(∝-β) = ( √61/8)(√6/3)- (√3/8)(√3/3)
Sin(∝-β) = √366/24 - √9/24
Sin(∝-β) = (√366 - 3)/24
At noon, Garrett left Magnolia and headed North at 10 kph. At 2 p.m., Ben left Magnolia and headed North. If Ben was 15 km ahead of Garrett at 7 p.m., how fast was Ben
traveling?
Choose one answer.
O
a. 17 kph
o
b. 12 kph
c. 21 kph
Ο Ο
d. 16 kph
Answer:
Step-by-step explanation:
This is simple, but the extra numbers given in the form of the specific times might throw you off.
If Garrett leaves at noon and at 7 Ben is some distance ahead of him, that means that Garrett has been driving for 7 hours. Ben left at 2, so at 7 pm he has been driving for 5 hours. That's part of what's confusing. We'll put that in a table to hopefully make things easier:
d = r * t
G 7
B 5
We also know that Garrett is driving at 10 km/h, so:
d = r * t
G 10 * 7
B r 5
The r is because Ben's rate is our unknown. Look at the top of the table. That is the formula we are going to use to solve this problem: d = rt.
If Garrett drives for 7 hours at 10 km/hr, then the distance he has traveled is 70 km (that's found by multiplying the rate of 10 km/h by the time of 7 hours). Ben's rate, along those same lines of reasoning, is 5r. Fill that in:
d = r * t
G 70 = 10 * 7
B 5r = r * 5
Ok now the table is filled out. Let's look at the rest of the problem. It says that at 7 pm Ben's distance is 15 km more than Garrett's distance. The words "more than" indicate addition. In words that is
"Ben's distance is Garrett's distance plus 15 km" which translates to, mathematically speaking:
5r = 70 + 15 and
5r = 85 so
r = 17
Ben's rate is 17 km/h, choice a.
The lengths of the sides of a triangle are 3, 3, 312. Can the tangle be a right triangle?
Answer:
Yes it can be right angle triangle
x+x+y+y+z+z=24
b+x+x+y+z=21
b+b+y+y=28
x+x+x+y+z=23
ASAP PLEASE
what numbers do the variables stand for
all x’s have the same numbers
all b’s have the same numbers
all y’s have the same numbers
all z’s have the same numbers
Answer:
b = 7/2
x = 11/2
y = 21/2
z = -4
Step-by-step explanation:
2x + 2y + 2z = 24
x + y + z = 12
b + 2x + y + z = 21
2b + 2y = 28
b + y = 14
3x + y + z = 23
we can start anywhere by transforming these equations in a way that always one variable is excised by others.
so, e.g.
b = 14 - y
14 - y + 2x + y + z = 21
2x + z = 7
z = 7 - 2x
3x + y + 7 - 2x = 23
x + y = 16
16 + z = 12
z = -4
-4 = 7 - 2x
-11 = -2x
11 = 2x
x = 11/2
11/2 + y = 16
y = 16 - 11/2 = 32/2 - 11/2 = 21/2
b = 14 - 21/2 = 28/2 - 21/2 = 7/2
Can anyone help please with the question please
Answer:
f(x) -5x
g(x) -85x²
f(x) . g(x)
-90x
Answer:
36x³ + 25x² + 12x + 2
Step-by-step explanation:
f(x) × g(x)
= (- 4x - 1)(- 9x² - 4x - 2)
Each term in the second factor is multiplied by each term in the first factor
- 4x(- 9x² - 4x - 2) - 1 (- 9x² - 4x - 2) ← distribute parenthesis
= 36x³ + 16x² + 8x + 9x² + 4x + 2 ← collect like terms
= 36x³ + 25x² + 12x + 2
instructions Find m<DCB
===========================================================
Explanation:
Your teacher shows that minor arc BD is 129 degrees. Recall that any minor arc is always less than 180 degrees.
Let's say that we had point A at the center of the circle. This would mean angle DAB is 129 degrees. This central angle subtends or cuts off minor arc BD.
Now focus entirely on quadrilateral DABC. The goal is to find the unknown angle C. The angle A was found earlier at 129 degrees. The angles B and D are 90 degrees each since tangents are perpendicular to the radius at the point of tangency.
We have this so far
A = 129B = 90C = unknownD = 90Adding all four angles of any quadrilateral will always get us 360 degrees. It's similar to how adding the angles of a triangle gets us 180 degrees. In fact, any quadrilateral can be cut into two triangles (aka the process of triangulation). So adding two triangles gets us 180+180 = 360 more or less.
--------------
Anyways, the four angles A,B,C,D must add to 360. So,
A+B+C+D = 360
129+90+C+90 = 360
C+309 = 360
C = 360-309
C = 51
--------------
As a shortcut, note how B+D = 90+90 = 180
Also note that A+C = 360-(B+D) which becomes A+C = 180
So, C = 180-A = 180-129 = 51
Find the length of the segment indicated. Round to the nearest 10th if necessary
(10 points help plz )
solue for x
X(3 + X) = 3x + x²
Answer:
here,
3x-3x=
[tex] {x}^{2} - {x}^{2} [/tex]
x=0
Need help asapppppppppp
A whole number has the first four odd prime numbers as its factors. What is the smallest value this whole number could be?
a. 1 155
b. 945
c. 105
d. 210
Answer:
3×5×7×11=1155
a.1155 the answer
3×5×7×11=1155
What are prime factors?A natural number other than 1 whose only factors are 1 and itself is said to have a prime factor. In actuality, the first few prime numbers are 2, 3, 5, 7, 11, and so forth.
Given
3×5×7×11=1155
To learn more about prime factors refer to:
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Instructions: Find the missing side. Round your answer to the nearest
tenth.
63°
19
х
X =
Answer:
x = 37.3
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp/ adj
tan 63 = x /19
19 tan 63 =x
x=37.28959
To the nearest tenth
x = 37.3
What is the surface area of a square prism with sides that measure 8 units?
Answer:
384 square units
Step-by-step explanation:
Square prism = Cube
Formula for finding the surface area of a cube = L x L (6)
Surface area = 8 x 8 (6)
Surface area = 64(6)
Surface area = 384 square units
Answer:
384 units squared
Step-by-step explanation:
Square 8 and then multiply by 6.
Which line is parallel to the line given below?
x - 3y = 24
a. y = -x + 3
b. y = -3x - 1
c. y = 3x + 8
d. y=-x-4
Answer:
x - 3y = 24
B. y = -3x - 1
Step-by-step explanation:
Hope it helped.
° ° °
The diagram below represents which percent?
An area model with 4 shaded sections and 1 unshaded section.
Answer:
25%
Step-by-step explanation:
1 ÷ 4 = 0.25
0.25 x 100 = 25 = 25%
Find the coordinates of the image of a triangle with vertices A(0, – 3), B(3, 0), and
C(-7, 4) under a rotation of 90° clockwise about the origin.
Answer:
A'(-3,0), B'(0,-3) and C'(4,7)
Step-by-step explanation:
We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).
We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.
90° clockwise about the origin
Rule:[tex](x,y)\rightarrow (y,-x)[/tex]
Using the rule
The coordinates of A'
[tex]A(0,-3)\rightarrow A'(-3,0)[/tex]
The coordinates of B'
[tex]B(3,0)\rightarrow B'(0,-3)[/tex]
The coordinates of C'
[tex]C(-7,4)\rightarrow C'(4,7)[/tex]
Hence, the vertices of image of triangle is given by
A'(-3,0), B'(0,-3) and C'(4,7)
what is the measure of angle k?
Answer:
Hence the answer is Letter B.
Step-by-step explanation:
° ° °
find the measure of the indicated angle to the nearest degree
Answer:
Step-by-step explanation:
Given that sin 0 = 21/29, what is the value of cose, for 0° <0<90°? please help
Answer:
3rd option
Step-by-step explanation:
Using the identity
sin²x + cos²x = 1 ( subtract sin²x from both sides )
cos²x = 1 - sin²x ( take the square root of both sides )
cosx = ± [tex]\sqrt{1-sin^2x}[/tex]
Given
sinθ = [tex]\frac{21}{29}[/tex] and 0 < θ < 90 , then
cosθ
= [tex]\sqrt{1-(\frac{21}{29})^2 }[/tex]
= [tex]\sqrt{1-\frac{441}{841} }[/tex]
= [tex]\sqrt{\frac{400}{841} }[/tex] = [tex]\frac{\sqrt{400} }{841}[/tex] = [tex]\frac{20}{29}[/tex]
Step 1: –10 + 8x < 6x – 4
Step 2: –10 < –2x – 4
Step 3: –6 < –2x
Step 4: ________
Answer:
-6/-2<-2x/-2
divide both sides by-2 to remain with the x variable on one side
I hope this helps
find the value of x give reasons to justify your solutions b ∈ ac, d ∈
help asap please!! will award brainliest
Answer:
x = 27°
Step-by-step explanation:
180° - 72° = 108°
108° / 4 = 27°
72° + (27° * 4) = 180°
Hope it helps!
For all of the Following use the function LaTeX: P\left(x\right)\:=\:\left(x+3\right)^2+2 . My original vertex is
Answer:
A) Q(x) = (x + 3)² + 5, and the vertex is (-3, 5)
B) R(x) = (x - 3)² + 2, and the vertex is (3, 2)
C) S(x) = (x - 1)² - 5, and the vertex is (1, -5)
Step-by-step explanation:
The given function is P(x) = (x + 3)² + 2
The given function is a parabolic function in vertex form, f(x) = a·(x - h)² + k, and vertex, (h, k)
By comparison, the vertex of the function P(x) = (x + 3)² + 2 is (-3, 2)
A) A function f(x) translated α units UP gives
f(x) (translated α units UP) → f(x) + α
A translation of the function 3 units UP is given by adding 3 to the given function as follows;
Q(x) = P(x) + 3
∴ Q(x) = (x + 3)² + 2 + 3 = (x + 3)² + 5
Q(x) = (x + 3)² + 5, and the vertex by comparison to f(x) = a·(x - h)² + k, and vertex, (h, k) is (-3, 5)
B) A function f(x) translated b units RIGHT gives;
f(x) translated b units right → f(x - b)
∴ P(x) = (x + 3)² + 2 translated 6 units RIGHT gives;
P(x) = (x + 3)² + 2 (translated 6 units RIGHT) → R(x) = (x + 3 - 6)² + 2 = (x - 3)² + 2
R(x) = (x - 3)² + 2, and the vertex by comparison is (3, 2)
C) A function translated α units DOWN and b units RIGHT is given as follows;
[tex]f(x) \ translated \ by\ \dbinom{b}{a} \rightarrow f(x - b) - a[/tex]
Therefore, the given function, P(x) = (x + 3)² + 2, translated 7 units DOWN and 4 units RIGHT gives;
[tex]P(x) = (x + 3)^2 + 5 \ translated \ by\ \dbinom{4}{-7} \rightarrow P(x - 4) - 7 = S(x)[/tex]
S(x) = P(x - 4) - 7 = (x + 3 - 4)² + 2 - 7 = (x - 1)² - 5
[tex]P(x) = (x + 3)^2 + 5 \ translated \ by\ \dbinom{4}{-7} \rightarrow (x - 1)^2 - 5= S(x)[/tex]
S(x) = (x - 1)² - 5, and the vertex by comparison is (1, -5)