Triangle LMN is dilated by a factor of 1.25 to create triangle PQR what is the length of PQ A 20 cm B 18.75 cm C 17 cm di 12 cm

Answer:

1/24 (fraction form)

hope this helps

Answer:

The correlation coefficient is approximately -0.9949

Step-by-step explanation:

The given data is presented as follows;

[tex]\begin{array}{lcl}x&&y\\-10&&2\\-8&&-3\\-1&&-15\\-4&&-10\\-6&&-6\\-7&&-5\\-5&&-8\\-3&&-13\\-2&&-14\\-9&&-1\end{array}[/tex]

The correlation coefficient, r is given as follows;

[tex]r = \dfrac{\sum(x_i - \overline x) \cdot (y_i - \overline y)}{\sqrt{\sum (x_i- \overline x)^2\times \sum (y_i- \overline y)^2 } }[/tex]

From MS Excel, we have;

∑([tex]x_i - \overline x[/tex])·([tex]y_i - \overline y[/tex]) = -155.5

∑([tex]x_i - \overline x[/tex])² = 82.5

∑([tex]y_i - \overline y[/tex])² = 296.1

Therefore, r = -155.5/(√(82.5 × 296.1)) ≈ -0.9949

The correlation coefficient, r ≈ -0.9949

Answer:

Step-by-step explanation:

The enlargement of a comic will be very similar to the original. Everything is larger but in the same proportion. The difference is if the original is enlarged so much that the individual pixel in the original comic becomes visible; causing the enlargement to be "pixelated."

If a comic is drawn using a grid, that may reduce pixelation because you can line up things with the grid.

If the comic's size is reduced, then again it will look similar but everything is smaller and in the same proportion. There will not be any pixelation effect.

Answer:

1-[tex]\frac{2 }{\pi }[/tex] = 1- .64 = .36 = 36%

[tex](4\sqrt{2}) ^{2} = 32\\[/tex]

[tex]\pi 4^{2}[/tex]= 16[tex]\pi[/tex]

[tex]\frac{32}{16\pi }[/tex]= [tex]\frac{2 }{\pi }[/tex]

Step-by-step explanation:

Answer:

[tex]344 {cm}^{2} [/tex]

Step-by-step explanation:

[tex]area \: of \: the \: square \\ = 40cm \times 40cm \\ = 1600 {cm}^{3} \\ [/tex]

[tex]area \: of \: the \: circle \\ = \pi {r}^{2} \\ = 3.14 \times {(20)}^{2} \\ = 3.14 \times 400 \\ = 1256 {cm}^{2} \\ [/tex]

[tex]area \: of \: shaded \: region \\ = 1600 {cm}^{2} - 1256 {cm}^{2} \\ = 344 {cm}^{2} \\ [/tex]

Answer:

449 100

Step-by-step explanation:

0.2% × 450000÷ 100=900

450000-900= 449 100

Answer:

Step-by-step explanation:

The answer is 449100 pounds .

Step-by-step explanation:

I can give you a formula SOH-Sinø=Opposite\Hypotenuse

CAH-Cos=Adjacent\Hypotenuse

TOA-Tan=Opposite\Adjacent

Answer:  [tex]\frac{19}{6} : \frac{17}{6}[/tex]

Step-by-step explanation:

Let us first represent the ratio.

3[tex]\frac{1}{6} : \frac{17}{6}[/tex]

Now we need to convert 3[tex]\frac{1}{6}[/tex] into a improper fraction.

[tex]\frac{19}{6} : \frac{17}{6}[/tex]

Now it is in its simplest form.

The final answer is  [tex]\frac{19}{6} : \frac{17}{6}[/tex]

Answer: x= 6 +/- root of 7

Step-by-step explanation:

1. Expand the left hand side: e.g, 3^2 = 3×3 =9

(x-6)(x-6) = 7

2. Multiply the brackets first by "separating" one of them, and take 7 to the left hand side:

x(x-6) - 6(x-6) =7

x^2 - 6x -6x +36-7=0

Simplify by adding like terms

x^2 -12x +29=0

3.Now your equation is in the form ax^2+bx + c =0, it means you can use the quadratic formula which is x= [-b +/- root of (b^2 - 4ac)]÷ 2a

Then SUBSTITUTE where:

a=1

b= -12

c=29

Therefore, x should be 6+ root of 7 OR 6- root of 7

Answer:

uhhhh okay thank you for removing my answer

Step-by-step explanation:

Answer:

y =1/2x -4

Step-by-step explanation:

x1 y1  x2 y2

2 -3  4 -2

(Y2-Y1) (-2)-(-3)=   1  ΔY 1

(X2-X1) (4)-(2)=    2  ΔX 2

slope=   1/2    

B= -4          

Y =0.5X -4    

Answer:

Step-by-step explanation:

-185

Answer:

2[tex]\sqrt{10\\}[/tex]

Step-by-step explanation:

Because this is a right triangle, we have:

[tex]x^{2} + 3^{2} = 7^{2} (Pytago)\\x^{2} + 9= 49\\x^{2} =40\\x=\sqrt{40} \\x=2\sqrt{10}[/tex]

Answer:

Step-by-step explanation:

(4, -6) is in quadrant IV , (quadrant 4)

Answer:

On the graphing calculator, use the function normCdf, where

It will result in normCdf(-9999,210,250,46) ≈ 0.192269 or 19.2269%

Answer:

C

Step-by-step explanation:

Given 2 secants from an external point to the circle, then

The product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant , that is

ML × KM = MN × MR, substitute values

7 × KM = 6(6 + 8)

7 KM = 6 × 14 = 84 ( divide both sides by 7 )

KM = 12 → C

Answer:

C.) 12

Step-by-step explanation:

I got it correct on founders edtell

Answer:

Answer:

Step-by-step explanation:

Let the initial number of people on the boat be x:

x - 26 - 22 = 74

x -48 = 74

x = 74 + 48

x = 122

Answered by  G a u t h m a t h

Answer:

t f dis say mane ion speak italian

Step-by-step explanation:

Step-by-step explanation:

gjfjdjjfu from Florida for Christmas and technology center and technology and technology

Answer:

SSS Postulate

Step-by-step explanation:

The first says 2 sides are the same

The second says 2 sides are the same

The last says 2 sides are the same

Side side side

SSS Postulate

Answer:

1050 + (150)times the amount of jobs they do for you during that winter, for A. 0 + (200)times the amount of jokes they do for you during that winter, for B.

Step-by-step explanation:

Boom I would choose B because it would be cheaper, since we do most of the snow removal ourselves.

Answer:

So, we need to find irrational numbers between the given pairs.

Remember that the sum between an irrational number and an rational number is irrational.

For example, for the first case, we want a irrational number between:

3.14 and pi:

pi = 3.14159265.... is irrational

pi - 0.0001 = 3.14159265... - 0.0001 = 3.14149265...

So this number:

3.14149265...

is an irrational number larger than 3.14 and smaller than pi.

Second cacse:

3.33 and 1/3

(here the range would be actually:

1/3 = 0.33 and 3.33

So we want an irrational number larger tan 0.33 and smaller than 3.33

here we can just use pi = 3.141592...

third case:

e^2 and √5

Firs let's write these numbers so we can see how they look.

e^2  =7.389...

√5 = 2.236

So we want a number larger than 2.236... and smaller than 7.389...

Again, here we can use pi = 3.141592...

2.236... < 3.141592... < 7.389...

final case:

√(64/2) and √16

we have:

√(64/2) = 5.65

√16 = 4

So we want an irrational number larger than 4 and smaller than 5.65

Again, let's use our beloved number pi.

we have that:

pi + 1  is an irrational number:

pi + 1 = 3.14159265... + 1.0 = 4.14159265....

This number, 4.14159265..., is irrational, is larger than 4 and is smaller than 5.65, so we found the irrational number between the given pair of numbers.

Answer:

3.33 and 1/3

Step-by-step explanation:

2 occurred 3times

[tex]\\ \sf\longmapsto S=6\times 3=18[/tex]

[tex]\\ \sf\longmapsto |S|=18[/tex]

Now

[tex]\\ \sf\longmapsto E=No\:of\:times\: 2\:occured[/tex]

[tex]\\ \sf\longmapsto |E|=3[/tex]

we know

[tex]\boxed{\sf P(E)=\dfrac{|E|}{|S|}}[/tex]

[tex]\\ \sf\longmapsto P(E)=\dfrac{3}{18}[/tex]

[tex]\\ \sf\longmapsto P(E)=\dfrac{1}{6}[/tex]

Answer:

Step-by-step explanation:

quadratic equation is 4(x+2)(x+5)=0

4(x²+5x+2x+10)=0

4x²+28x+40=0

Answer:

f(x) = 4(x+2)(x+5)

Step-by-step explanation:

The quadratic function is

f(x) = a(x-b1)(x-b2)  where a is a coefficient and b1 and b2 are the zeros

f(x) = a(x --2)(x--5)

f(x) = a(x+2)(x+5)

The leading coefficient is a and we know a =4

f(x) = 4(x+2)(x+5)

The 3rd option is correct

Answer:

D.

Step-by-step explanation:

The line will be a straight line and will go through AB in the center. Therefore, it will be the perpendicular bisector.

Answer:

[tex]\frac{400}{3} \pi[/tex]

Step-by-step explanation:

Formula for Cone: π[tex]r^{2}\frac{h}{3}[/tex]

Since we have all the components, we can find the volume of the cone.

R = 10

H = 4

π[tex]10^{2}\frac{4}{3}[/tex]

10×10 = 100

100π[tex]}\frac{4}{3}[/tex]

[tex]}\frac{4}{3}[/tex]×100

4       100          400

---  ×   -----    =    ------

3          1              3

Answer: [tex]\frac{400}{3} \pi[/tex]

Hope this helped.

Find the volume of a cone with radius 10 feet and height of 4 feet.

Given Data :

Radius = 10 feet

Height = 4 feet

Formulae :

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \star \: \blue{ \underline{ \overline{ \green{ \boxed{ \frak{{ \sf V}olume_{(Cone)} = \pi {r}^{2} \frac{h}{3}}}}}}}[/tex]

Putting the values we get

[tex] \frak{ Volume_{(Cone)} = 3.14 × (10)² × \frac{4}{3} }[/tex]

[tex] \frak{Volume_{(Cone)} = 3.14 × 100 × \frac{4}{3} }[/tex]

[tex] \frak{Volume_{(Cone)} = 314 \times \frac{4}{3} }[/tex]

[tex] \frak{Volume_{(Cone)} = 418.67 \: ft³ }[/tex]

Henceforth, the volume is 418.67 ft³