The number of moles of 5.96 g of zinc acetate is 00324 . The volume of the solution is 0.25 L. Then the molarity of the solution is 0.16 M.
What is molarity ?Molarity of a solution is a common term used to express the concentration of a solution. It is the the ratio of number of moles of the solute to the volume of solution in liters.
Given that the solution contains 5.965 g of ammonia.
molar mass of zinc acetate = 183.4 g/mol.
no.of moles in 75 g = 75/17 = 4.411 moles.
volume of solution = 250 ml = 0.25 L.
molarity = no.of moles of solute/volume of solution in L.
= 0.032 mole/ 0.25 L= 0.16 M.
Therefore, the molarity of the solution is 0.16 M.
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6. How many molecules in 77.2L of CO₂?
Answer:
divide it by
its molar mass
Explanation:
A 33.41 g piece of copper at 95.6 Celsius was placed in a sample of water at 21.65 Celsius. The temperature of the water increased to 22.87 Celsius. To what mass of water was the cooper added? The specific heat of copper is 0.385 J/g C
Answer:
43.63 g of water.
Explanation:
We can use the equation for heat transfer to solve for the mass of water:
q = cmΔT
where
q = heat transfer
c = specific heat
m = mass
ΔT = change in temperature
The heat transfer from the copper to the water can be expressed as:
q = cmΔT
q = (33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C)
And the heat transfer caused a change in temperature in the water, which can be expressed as:
q = mLΔT
q = (m)(4.18 J/g°C)(ΔT)
Equating the two expressions for heat transfer, we can solve for the mass of water:
(33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C) = (m)(4.18 J/g°C)(22.87°C - 21.65°C)
m = (33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C) / (4.18 J/g°C)(22.87°C - 21.65°C)
m = 43.63 g
So the copper was added to 43.63 g of water.
Metabolism can best be described as
Answer: The sum of all chemical reactions in the body.
Catabolism (breaking down)- releases energy ATP
Anabolism (building up)- Uses energy to synthesize what body needs.
Explanation:
HELP PLEASE!
Based on your Retention factor values for the 5 dye standards, order the dyes from most polar to least polar.
Red #3 - 0.000
Blue #1 - 0.58
Yellow #5- 0.286
Red #40- 0.046
Blue #2- 0.095
Answer:
Red #3 is the most polar, and Blue #1 is the least polar.
Explanation:
To order the dyes from most polar to least polar, we need to look at the retention factor values. The lower the retention factor value, the more polar the molecule. So, based on the given values, the order from most polar to least polar would be:
Red #3 - 0.000
Yellow #5 - 0.286
Blue #2 - 0.095
Red #40 - 0.046
Blue #1 - 0.58
While calculating the ending amounts of product after an
experiment, Jose found that he had made 0.35 moles of
iron. His goal was to make 40 grams of iron, did he reach
his goal?
Yes, Jose reached his goal.
What is the mole?In chemistry, the mole is a unit used to measure the amount of a substance. It is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are atoms in 12 grams of pure carbon-12. This number is known as Avogadro's number and is approximately equal to 6.022 × 10^23.
The concept of the mole is fundamental to many areas of chemistry, including stoichiometry, the study of chemical reactions and their quantitative relationships. It allows chemists to make precise measurements and calculations, and to compare and relate the properties of different substances.
Number of moles in 40 g of iron = 40g/56 g/mol
= 0.7 moles
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What are the different modes of reproduction in organisms, such as asexual and sexual reproduction?
Answer:
Asexual reproduction is a mode of reproduction that occurs without the involvement of sex cells or meiosis. In this type of reproduction, a single organism produces offspring that are genetically identical to the parent. This can happen through methods such as budding, fragmentation, and self-fertilization.
Sexual reproduction, on the other hand, involves the fusion of gametes or sex cells from two different organisms to produce offspring that have genetic material from both parents. This results in offspring with a unique combination of traits and genetic diversity. Some common examples of sexual reproduction include the exchange of sperm and eggs in animals, and the fusion of male and female gametes in plants.
Explanation:
Given the chemical equation: 6 Cs + N₂
-2 CsgN
If the above reaction produces 58.3g of cesium nitride how much of the other substances were involved?
According to law of conservation of mass, if mass of product is 58.3 g the mass of nitrogen is 28 g and that of cesium nitride is 30.3 g which sums up to 58.3 g.
What is law of conservation of mass?According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .
Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.
Mass of cesium nitride= mass of cesium + mass of nitrogen, thus, mass of nitrogen = 14×2=28 g and that of cesium is 58.3-28=30.3 g.
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If 3.21 mol of a gas occupies 56.2 L at 44°C and 793 torr, 5.29 mol of this gas occupies what volume would it be under these conditions?
The 132 L volume would it be under these conditions.
What is volume ?
Space is occupied by every three-dimensional object. Its volume serves as a gauge for this area. The area contained by an object's limits in three-dimensional space is referred to as its volume. Another name for it is an object's capacity.
What is mole ?
A mole is the atom's elementary particle, an ion. The mole of the substance is always related to the Avogadro number. The mole is always associated with the weight or mass of the element or substance. The standard unit of a mole is mol. The mole is a significant factor of the reactant and products to form an equation. A mole calculates the atom, ion, and substance weighs.
Therefore, 132 L volume would it be under these conditions.
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A hole in a steel plate has a diameter of 1.166 cm at 23.00 ∘C
At what temperature is the diameter of the hole equal to 1.164 cm
?
The temperature at which the diameter of the hole is 1.164 cm is approximately 23.00 + 13.63 = 36.63 ∘C.
How did we get the value?The diameter of a hole in a steel plate changes with temperature due to thermal expansion. The amount of expansion is determined by the coefficient of linear expansion of steel, which is around 12x10^-6 per kelvin.
To find the temperature at which the diameter of the hole is 1.164 cm, we can use the formula:
ΔL = L0 * α * ΔT
where ΔL is the change in length, L0 is the initial length, α is the coefficient of linear expansion, and ΔT is the change in temperature.
We can rearrange the formula to solve for ΔT:
ΔT = ΔL / (L0 * α)
Substituting the values:
ΔL = 1.166 - 1.164 = 0.002 cm
L0 = 1.166 cm
α = 12x10^-6 per kelvin
ΔT = 0.002 / (1.166 * 12x10^-6) = approximately 13.63 kelvins
So, the temperature at which the diameter of the hole is 1.164 cm is approximately 23.00 + 13.63 = 36.63 ∘C.
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If you have 24 bun slices, 8 hamburger patties, 10 slices of cheese, 12 pieces of bacon, 10 tomato slices and 10 slices of lettuce, what is the maximum amount of hamburgers you can make?
Answer:
8
Explanation:
because you only have 8 hamburger patties
See question in the picture below , will give brainliest for correct answer
Answer:
2H²+O²--> 2H²O (sry subscripts can't be written on moblie)
Explanation:
the first part of the reaction shows 4 hydrogen atoms and 2 oxygen atoms, and the second formula shows the same
26. Using algebra, find the slope and y-intercept of the lines represented by the following Equations. a. 9x+ 3y = 33
Answer : Slope = -3, intersection = 11
We need to isolate for y here.
From 9x+3y=33, we need to derive a y=mx+b equation.
First, we take away 9x as follows:
9x+3y-9x=33-9x
The positive and negative values of 9x cancel our on the y side, so we are left with 3y=-9x+33
Now we need to get rid of the y coefficient:
(3y)÷3=(-9x+33)÷3
We need to effectuate the division on both sides to cancel out the coefficient, so we are left with y=-3x+11
Answer: y-intercept = y = 11 - 3x
Slope is m = -3
A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store bottles of dimethyl sulfoxide, acetone, diethytamin, tetrahydrofuran, and carbon tetrachloride. The chemist plans to identify the unknown liquid by measuring the density and comparing to known densities. First, from her collection of Material Safety Data Sheets (MSOS), the chemist finds the following information: Next, the chemist measures the volume of the unknown liquid as 0.767 L and the mass of the unknown liquid as 682. g. Calculate the density of the liquid. Round your answer to 3 significant digits. g. cm^-3 Given the data above, is it possible to identify the liquid? yes no If it is possible to identify the liquid, do so. dimethyl sulfoxide acetone diethylamine tetrahydrofuran carbon tetrachloride times 10
Yes, it is possible to identify the liquid, and the density of the liquid is closest to 0.889 g/cm³ so the liquid is most likely tetrahydrofuran.
To calculate the density of the unknown liquid, we use the formula:
Density = Mass / Volume
Substituting the given values, we get:
Density = 682. g / 0.767 L
Density = 888.5 g/L
Rounding to three significant digits, the density of the unknown liquid is 889 g/L.
Using the information provided in the question, we can compare the density of the unknown liquid to the known densities of the listed chemicals. The densities (in g/cm³) of the chemicals are:
Dimethyl sulfoxide: 1.092
Acetone: 0.790
Diethylamine: 0.707
Tetrahydrofuran: 0.889
Carbon tetrachloride: 1.594
Comparing the density of the unknown liquid to the known densities, we see that it is closest to the density of tetrahydrofuran, which is 0.889 g/cm³. Therefore, it is likely that the unknown liquid is tetrahydrofuran.
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Given the reactant amounts specified in the chemical equation, determine the limiting reactant for each:
a.
b.
c.
5. For each reaction in the problem above, determine the amount in moles of excess reactant that remains.
Information 1: There are 2.0 moles of HCl. It contains 2.5 moles of NaOH.
Data 2 reveals a 2.5 mole concentration of zinc.
What is limiting agent?HCl has a molecular weight of six.
Fe(OH)3 makes up 4.0 moles, according to Data 3.
It contains 6.5 moles of H2SO4.
Answer (A) (A)
Below is a display of the suggested response.
HCl+NaOH→NaCl+H2O
1 mole of HCl and 1 mole of NaOH combine in the procedure described above.
To calculate how many moles of NaOH are needed to react with 2 mol of HCl, see the formula below.
NaOH=1mol1mol×2mol=2mol
NaOH is, however, just 2.5 moles accessible.
NaOH therefore acts as the excess reactant and HCl as the limiting reactant.
In light of this, HCl is the reaction's limiting reactant.
In response (B),
Below is a display of the suggested response.
Zn+2HCl→ZnCl2+H2
One mole of zinc reacts with two moles of HCl in the mechanism described above.
Thus, it can be determined from the calculations below how many moles of HCl are needed to react 2.5 mol of zinc.
HCl=2mol1mol×2.5mol=5mol
In contrast, there are 6 moles of HCl available.
The excess reactant in the reaction is therefore HCl, whereas the limiting reactant is Zn.
Consequently, Zn serves as the reaction's limiting reactant.
Answer (C) (C)
Below is a display of the suggested response.
2Fe(OH)3+3H2SO4→Fe2(SO4)3+6H2O
In the reaction mentioned above, 3 moles of H2SO4 and 2 moles of Fe(OH)3 react.
Thus, the calculation below determines how many moles of H2SO4 are necessary for four moles of Fe(OH)3 to react entirely.
H2SO4=3mol2mol×4mol=122mol=6mol
However, there is a limited supply of H2SO4 is 6.5 mol.
The limiting reactant in the reaction is therefore Fe(OH)3, while the excess reactant is H2SO4.
In light of this, Fe(OH)3 is the reaction's limiting reactant.
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how (as per the Le Chateliers principle) an equilibrium is re-established when a change is imposed in terms of concentration, volume, pressure, and temperature
a brass rod, a copper rod, an iron rod and a lead rod went into water with wax on top, which one rusted first if lead stayed on the longest and copper for the least
A brass rod, a copper rod, an iron rod and a lead rod went into water with wax on top, an iron rod will rust first if lead stayed on the longest and copper for the least.
What is rust?Rust is an iron oxide, which is a typically reddish-brown oxide created by the catalytic interaction of iron with oxygen in the absence of water or air moisture. Rust is often connected with the corrosion of refined iron and is composed of hydrous iron(III) oxides (Fe2O3nH2O) with iron(III) oxide-hydroxide (FeO(OH), Fe(OH)3).
Given enough time and the presence of oxygen and water, any iron mass may ultimately rust completely. A brass rod, a copper rod, an iron rod and a lead rod went into water with wax on top, an iron rod will rust first if lead stayed on the longest and copper for the least.
Therefore, an iron rod will rust first if lead stayed on the longest and copper for the least.
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Defend the argument that creep feeding is beneficial to newborns.
Answer:
Creep feeding can help them make the transition without such a setback, and it can also help them begin to produce the enzymes needed to digest nonmilk proteins.
Explanation:
For the following equation, assume you started with 15.6g potassium (K). How many moles of potassium oxide would be produced assuming you had unlimited oxygen? ____ K + ____ O2 → _____ K2O
According to the stoichiometry of the given chemical equation, 0.2 moles of potassium oxide would be produced assuming you had unlimited oxygen.
What is stoichiometry?Stoichiometry is defined as the determination of proportions of elements or compounds in a chemical reaction. The relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given equation,156 g potassium gives 188.4 g potassium oxide, thus, 15.6 g will give 15.6×188.4/156=18.84 g potassium oxide which is 18.84/94.2= 0.2 moles.
Thus, 0.2 moles of potassium oxide would be produced assuming you had unlimited oxygen.
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The acid ionization constant, Ka, for propanoic acid, C2H5COOH, is 1.3x10-5.(a) Calculate the hydrogen ion concentration, [H+], in a 0.20-molar solution of propanoic acid.(b) Calculate the percentage of propanoic acid molecules that are ionized in the solution in (a).(c) What is the ratio of the concentration of propanoate ion, C2H5COO-, to that of propanoic acid in a buffer solution with a pH of 5.20?(d) In a 100.-milliliter sample of a different buffer solution, the propanoic acid concentration is0.35-molar and the sodium propanoate concentration is 0.50-molar. To this buffer solution,0.0040 mole of solid NaOH is added. Calculate the pH of the resulting solution
(a) The hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M. (b) 0.57%. (c) The ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.
(a) The balanced equation for the ionization of propanoic acid is:
C2H5COOH + H2O ⇌ C2H5COO- + H3O+
The equilibrium expression for this reaction is:
Ka = [C2H5COO-][H3O+] / [C2H5COOH]
At equilibrium, the concentration of propanoic acid that has ionized to form propanoate ion and hydronium ion is equal to the concentration of propanoic acid that has not ionized, so we can assume that [C2H5COO-] ≈ [H3O+]. Let x be the concentration of hydronium ion in the solution. Then the equilibrium expression becomes:
Ka = x^2 / (0.20 - x)
Solving for x, we get:
x = sqrt(Ka * (0.20 - x)) = sqrt(1.3x10^-5 * 0.20) = 1.14x10^-3 M
Therefore, the hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M.
(b) The percentage of propanoic acid molecules that are ionized in the solution is given by:
% ionization = [H3O+] / [C2H5COOH] x 100%
% ionization = (1.14x10^-3 / 0.20) x 100% = 0.57%
(c) The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:
pH = pKa + log([C2H5COO-] / [C2H5COOH])
At pH 5.20, the hydronium ion concentration is 10^-5.20
= 6.31x10^-6 M.
Using the equilibrium expression for propanoic acid and the fact that [C2H5COO-] + [C2H5COOH] = total buffer concentration,
we can solve for the ratio of the concentrations of propanoate ion to propanoic acid:
Ka = [C2H5COO-][H3O+] / [C2H5COOH]
[C2H5COO-] = Ka[C2H5COOH] / [H3O+]
[C2H5COO-] = (1.3x10^-5)([C2H5COOH]) / (6.31x10^-6)
[C2H5COO-] / [C2H5COOH]
= 2.68
Therefore, the ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.
(d) When solid NaOH is added to the buffer solution, it reacts with the propanoic acid to form propanoate ion and water:
C2H5COOH + NaOH → C2H5COO- + H2O + Na+
The number of moles of propanoic acid that react with NaOH is equal to the number of moles of NaOH that were added. The new concentration of propanoic acid is:
0.35 M - (0.0040 mol / 0.100 L) = 0.346 M
The new concentration of propanoate ion is:
0.50 M + (0.0040 mol / 0.100 L) = 0.54 M
The new concentration of hydronium ion can be calculated using the equilibrium expression.
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5SO2 + 2MnO4- + 2H205SO42- + 2Mn2+ + 4H+ Calculate the number of grams of SO2 in a sample of air if 7.37 mL of 0.008 M KMnO4 solution are required for the titration.
Answer:
0.09536 g of SO2 in the sample of air
Explanation:
The first step is to convert the volume of KMnO4 solution to moles. This can be done using the formula:
moles = Molarity x volume (in liters)
So,
moles = 0.008 M x (7.37 mL) x (1 L/1000 mL)
= 0.0000596 moles
Next, we need to find the ratio of moles of SO2 to moles of KMnO4 in the balanced equation:
5SO2 + 2MnO4- + 2H205SO42- + 2Mn2+ + 4H+
From the equation, it can be seen that 2 moles of KMnO4- react with 5 moles of SO2. So,
moles of SO2 = (moles of KMnO4) x (5 moles of SO2 / 2 moles of KMnO4)
= 0.0000596 x (5/2)
= 0.0001495 moles
Finally, to convert moles of SO2 to grams, we can use the formula:
grams = moles x molar mass
Since the molar mass of SO2 is 64 g/mol,
grams = 0.0001495 x 64
= 0.09536 g
So, there are 0.09536 g of SO2 in the sample of air.
A compound contains C, H, I, S and has a molar mass of 229 g/mol. The sample has six times as much C
as H by mass. What is the molecular formula?
The molecular formula of the compound is CI4H12S4.
How to find the molecular formula of the compoundLet's assume that we have 6 grams of the compound, which means that 1 gram of the compound contains 1/6th of the total amount of the compound.
We are given that the compound contains C, H, I, S, and has a molar mass of 229 g/mol. Let's use x, y, z, and w to represent the number of moles of C, H, I, and S in one mole of the compound, respectively.
From the information given in the problem, we can set up the following system of equations:
x + y + z + w = 1 (since the sum of the mole fractions must equal 1)
12x = y (since the compound has six times as much C as H by mass)
To find the molecular formula of the compound, we need to determine the values of x, y, z, and w that satisfy these equations and give a molar mass of 229 g/mol.
The molar mass of the compound can be calculated as:
M = 12x + y + 127z + 32w
Substituting y = 12x from the second equation, we get:
M = 13x + 127z + 32w
We know that the molar mass of the compound is 229 g/mol, so we can set up the equation:
229 = 13x + 127z + 32w
We also know that x + y + z + w = 1, so we can substitute y = 12x, giving:
x + 12x + z + w = 1
13x + z + w = 1
We can solve these equations simultaneously to get:
x = 0.061
z = 0.504
w = 0.069
Substituting these values into the equation for the molar mass, we get:
M = 13(0.061) + 127(0.504) + 32(0.069) = 229
Therefore, the molecular formula of the compound is CI4H12S4.
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Cu has only two naturally occurring isotopes 63cu and 65cu if the aromic mass of cu is 63.546 then the natural abundance of the 63cu isotope will be approximately
Answer: i answerd 34cu i got coreect hopefully you get it corecct!!!!!!!
Explanation:
How is the molar mass of a compound similar to its formula mass?
How is the molar mass of a compound different from its formula mass?
Answer:
the fromu;la is 50
Explanation:
becuase it is soooopo understand
Answer:
The molar mass of a compound is similar to its formula mass in that both represent the sum of the atomic masses of all the elements in the compound. The formula mass is the total atomic mass of the elements in the chemical formula of a compound, while the molar mass is the mass of one mole of the compound.
The molar mass of a compound is different from its formula mass in that the molar mass is a unit of measurement for the amount of substance, whereas the formula mass is simply a numerical value representing the total atomic mass of the elements in the compound. The molar mass is expressed in units of grams per mole (g/mol), whereas the formula mass is expressed in atomic mass units (amu). Additionally, the molar mass takes into account the Avogadro's constant, which is the number of entities in one mole of a substance, whereas the formula mass does not.
Explanation:
ALLEN
Explain why phosphorus is a non-conductor of electricity.
An aqueous solution containing 35.5 g of an unknown molecular (non-electrolyte) compound in 158.6 g of water was found to have a freezing point of -1.4 ∘C.
An aqueous solution containing 35.5 g of an unknown molecular (non-electrolyte) compound in 158.6 g of water was found to have a freezing point of -1.4 ∘C. Therefore, 3.3 × 10² g/mol is the molecular mass.
What is molecular mass?The quantity of fill with a molecule is referred to as its molecular mass. It is also known as molecular weight.
It is computed by multiplying the mass for every atom by the amount of atoms belonging to the element that the molecule contains. Water, for example, is composed of two hydrogen atoms and one oxygen atom.
ΔT = i × Kf × m
m = ΔT / i × Kf
m = (1.4°C) / 1 × (1.86 °C/m) = 0.70 m
moles of solute = m × kg of solvent = 0.70 mol/kg × 0.1500 kg = 0.11 mol
M = 35.9 g/0.11 mol = 3.3 × 10² g/mol
Therefore, 3.3 × 10² g/mol is the molecular mass.
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which of the following has a larger mass (2 mole of water) or (2 mole of carbon dioxide) or( 2 mole of ozone )
Answer:
The mass of 2 moles of water is greater than the mass of 2 moles of carbon dioxide, which is greater than the mass of 2 moles of ozone.
2 moles of water has a mass of approximately 36 grams, whereas 2 moles of carbon dioxide has a mass of approximately 44 grams, and 2 moles of ozone has a mass of approximately 48 grams.
ALLEN
Part 6 Computation (12 points) 1. Calculate the average atomic mass of Iron using the chart provided. (6pts) Isotopic symbol 54Fe 56Fe 57 Fe 58Fe Natural Abundance (%) 5.8 91.7 2.2 0.3
Answer:
84.066 amu
Explanation:
The average atomic mass of iron can be calculated using the following formula:
Average atomic mass = (54Fe * 0.058 + 56Fe * 0.917 + 57Fe * 0.022 + 58Fe * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)
Plugging in the numbers, we get:Average atomic mass = (54 * 0.058 + 56 * 0.917 + 57 * 0.022 + 58 * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)
Average atomic mass = (31.12 + 51.592 + 1.254 + 0.174) / (0.058 + 0.917 + 0.022 + 0.003)
Average atomic mass = 84.066 / (0.058 + 0.917 + 0.022 + 0.003)Average atomic mass = 84.066 / 1
Average atomic mass = 84.066So, the average atomic mass of Iron is 84.066 atomic mass units (amu).
Which crop did texas farmers produce the most of in the years after the civil war?.
In the years after the civil war texas farmers produced cotton the most among all crops,
The Importance of Cotton in Texas Agriculture After the Civil WarIn the years following the Civil War, cotton was the most important cash crop in Texas and the primary source of income for many farmers. Texas had favorable climatic conditions and fertile soils that were well-suited for cotton cultivation. Additionally, the demand for cotton was high both domestically and internationally, which made it a lucrative crop for farmers. As a result, cotton production in Texas increased significantly in the years after the Civil War, with the state becoming one of the largest cotton producers in the country. However, this dependence on a single crop also left farmers vulnerable to market fluctuations and crop failures, which led to economic hardship and debt for many.
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The dosage of an asthma drug is 7 mg/kg of body mass. Calculate the dosage, in milligrams, required for a 43 lb child.
The dosage of an asthma drug is 7 mg/kg of body mass. The required dosage for the 43 lb child is 32.2 mg.
What do you mean by drugs?
Drugs are substances intended for use in the diagnosis, cure, mitigation, treatment, or prevention of disease or to otherwise enhance physical or mental well-being.
An asthma drug is a medication used to treat asthma symptoms. Common types of asthma drugs include bronchodilators, corticosteroids, and anti-inflammatory drugs.
So,
43 lbs = 19.5 kg
7 mg/kg x 19.5 kg = 136.5 mg
136.5 mg = 32.2 mg (rounded to the nearest tenth)
Hence, the required dosage for the 43 lb child is 32.2 mg.
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Calculate the atomic mass of element "X", if it has 2 naturally occurring isotopes with the following masses and natural abundances: X-45 44. 8776 amu 32. 88% X-47 46. 9443 amu 67. 12%
46.2648
Explanation:Atomic mass describes the number of protons and neutrons in an atom.
Percent Abundance
Percent abundance is the percentage of atoms within a sample that have a specific mass number. The reason that different atoms within a sample would have different mass numbers is that they are different isotopes. For example, if the isotope Cl-35 has a percent abundance of 75%, then 75% of all Chlorine atoms within a sample will have a mass number of 35. Percent abundance refers to the likelihood of an isotope occurring in a natural sample. Percent abundance does not take into account artificial samples of elements.
Finding Atomic Mass
The atomic mass of an element is found through the mass of isotopes and their percent abundances. The formula for atomic mass is:
m₁*p₁ + m₂*p₂In this formula, the m is the mass of the isotope and p is the percent abundance. The percent abundance should be expressed as a decimal for all calculations. Now, plug in the values and solve.
(44.8776 * 0.3288) + (46.9443 * 0.6712)Rounded to 4 decimal places, this equals 46.2648. This means that the atomic mass of element "X" is 46.2648 amu.
