Twice a year the Sun’s rays strike Earth north or south of the....

If an object must be slowed quickly, the force applied to it must be greater than that required for gradual slowing. For example, the greater the force applied to a bicycle's brakes, the faster it will slow or stop.

A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate.

Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.

Force is defined as the tendency of a body to modify or change its state as a result of an external cause. When applied force, the body can also change shape, size, and direction.

The same force that was used to accelerate something can be used to slow it down. It will stop faster if more force is applied.

Thus, it can be concluded that it take more force to slow something down than to speed it up.

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Answer:

18.78 m/s.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 50 kg

Initial velocity (u) = 0 m/s

Height (h) of cliff = 18 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

The velocity with which the diver reach the water can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 18

v² = 0 + 352.8

v² = 352.8

Take the square root of both side

v = √352.8

v = 18.78 m/s

Thus, the diver will reach the water with a velocity of 18.78 m/s.

Answer:

1.15*10^-5 kg/m^3

Explanation:

Given data

mass= 1kg

hieght= 40 mm

diameter= 52.5mm

radius= 53.5/2= 26.25mm

The volume of the cylinder

V=πr^2h

V=3.142*26.25^2*40

V=3.142*689.0625*40

V=86601.375 mm^3

Density= mass/volume

Density= 1/86601.375

Density=0.00001154716

Density= 1.15*10^-5 kg/m^3

Hence the density is  1.15*10^-5 kg/m^3

Answer:

What question?

Explanation:

Answer:

C

Explanation:

Answer:five times five is twenty five divded by 10 is 2.5 seconds of acceleration

Answer:

The amount of solid ice remaining after 6 hours is approximately 3.68664 kg

Explanation:

The given parameters are;

The side length of the cube box, s = 3(0) cm = 0.3 m

The thickness of the cube box, d = 5.0 cm = 0.05 m  

The mass of ice in the box, m = 4.0 kg

The outside temperature of the cube box, T₁ = 45°C

The temperature of the melting ice inside the box, T₂ = 0°C

The latent heat of fusion of ice, [tex]L_f[/tex] = 3.35 × 10⁵ J/K/hr/kg

The surface area of the box, A = 6·s² 6 × (0.3 m)² = 0.54 m²

The coefficient of thermal conductivity, K = 0.01 J/s·m⁻¹·K⁻¹

For thermal equilibrium, we have;

The heat supplied by the surrounding = The heat gained by the ice

The  heat supplied by the surrounding, Q = K·A·ΔT·t/d

Where;

ΔT = T₁ - T₂ =  45° C - 0° C = 45° C

ΔT = 45° C

Q = K·A·ΔT·t/d = 0.01 × 0.54 × 45 × 6× 60×60/0.05 = 104976

∴ The  heat supplied by the surrounding, Q = 104976 J

The heat gained by the ice = [tex]L_f[/tex] × [tex]m_{melted \ ice}[/tex] =3.35 × 10⁵ J/kg × [tex]m_{melted \ ice}[/tex]

Therefore, from Q =  [tex]L_f[/tex] × [tex]m_{melted \ ice}[/tex], we have;

Q = 104976 J =  [tex]L_f[/tex] × [tex]m_{melted \ ice}[/tex] = 3.35 × 10⁵ J/kg × [tex]m_{melted \ ice}[/tex]

104976 J = 3.35 × 10⁵ J/kg × [tex]m_{melted \ ice}[/tex]

[tex]m_{melted \ ice}[/tex] = 104976 J/(3.35 × 10⁵ J/kg) ≈ 0.31336 kg

The mass of melted ice, [tex]m_{melted \ ice}[/tex] ≈ 0.31336 kg

∴ The amount of solid ice remaining after 6 hours, [tex]m_{ice}[/tex] = m - [tex]m_{melted \ ice}[/tex]

Which gives;

[tex]m_{ice}[/tex] = m - [tex]m_{melted \ ice}[/tex] = 4.0 kg - 0.31336 kg ≈ 3.68664 kg

The amount of solid ice remaining after 6 hours, [tex]m_{ice}[/tex] ≈ 3.68664 kg.

Answer:

Explanation:

Density=mass÷volume

=45÷3

=15

Answer:

v = 14.5 m/s

Explanation:

The Principle Of Conservation Of Mechanical Energy

In the absence of friction, the total mechanical energy is conserved. That means that

Em=U+K is constant, being U the potential energy and K the kinetic energy

U=mgh

[tex]\displaystyle K=\frac{mv^2}{2}[/tex]

The ball with a mass of m=0.8 kg is thrown straight upward from the zero height reference (h=0) and with some speed (v). The potential energy is zero, but the kinetic speed is given by the equation above.

When the ball reaches its maximum height of h=10.7 m, the speed is zero and all the initial kinetic energy was transformed into potential energy, thus:

[tex]\displaystyle \frac{mv^2}{2}=mgh[/tex]

Simplifying by m:

[tex]\displaystyle \frac{v^2}{2}=gh[/tex]

Solving for v:

[tex]\displaystyle v=\sqrt{2gh}[/tex]

Substituting:

[tex]\displaystyle v=\sqrt{2*9.8*10.7}[/tex]

Calculating:

v = 14.5 m/s

Answer: 9.81 times 3s= 29.43m/s

so 29.43 m/s times 3= 88.29m

Explanation:

Answer:

5Hz

Explanation:

I hope that by stating f you mean frequency

so I think people in this app just like to give answers without explaining so let me try to explain to you why

first of all, you must know the formula

just insert the values in

50 = 10 x frequency

50/10 = frequency

5 = frequency

Answer:

Pressure = 14.71N/m²

Explanation:

Given the following data;

Force = 375N

Area = 25.5m²

To find the pressure;

Pressure = force/area

Pressure = 375/25.5

Pressure = 14.71N/m²

Therefore, the amount of pressure that is being exerted by blood cells is 14.71 Newton per meter square.

Answer:

there is no momentum

Explanation:

if an object is at rest there is no momentum to build, no speed, no acceleration it does not move unless force is acted upon it.

Answer:

the answer is b

wjejehebe ehshw es

Answer:

The magnitude of third force is 74.4 N and direction of third force  is 72.8 degrees South.

Explanation:

Let F1, F2 and F3 are three forces exerted on an object.

[tex]\theta_1=90^{\circ}[/tex]

[tex]\theta_2=60^{\circ}[/tex]

[tex]|F_1|=33 N[/tex]

[tex]|F_2|=44 N[/tex]

We have to find the direction and magnitude of third force i.e F3.

[tex]F_{1x}=33cos(90^{\circ})=0 N[/tex]

[tex]F_{1y}=33sin(90^{\circ})=33 N[/tex]

[tex]F_{2x}=44cos(60^{\circ})=22 N[/tex]

[tex]F_{2y}=44 sin(60^{\circ})=22\sqrt{3}=38.11 N[/tex]

Now,

x-component of  resultant

[tex]R_x=F_{1x}+F_{2x}=0+22=22 N[/tex]

y-component of resultant

[tex]R_y=F_{1y}+F_{2y}=33+38.11=71.11 N[/tex]

[tex]|R|=\sqrt{R^2_x+R^2_y}[/tex]

[tex]|R|=\sqrt{(22)^2+(71.11)^2}=74.4 N[/tex]

[tex]\theta=tan^{-1}(\frac{R_y}{R_x})[/tex]

[tex]\theta=tan^{-1}(\frac{71.11}{22})=72.8^{\circ}[/tex] South

Hence, the magnitude of third force is 74.4 N and direction of third force  is 72.8 degrees South.

The magnitude and direction of the third force is;

F3 = 74.44 N

θ3 = 72.81° in the south direction

We are given;

F1 = 33 N

F2 = 44 N

θ1 = 90°

θ2 = 60°

Let the third force be F3 which will serve as the resultant

Let's first find the x and y component of the forces.

F1x = F1 cos θ1

F1x = 33 × cos 90

F1x = 0 N

F1y = F1 sin θ1

F1y = 33 × sin 90

F1y = 33 N

F2x = F2 cos θ2

F2x = 44 × cos 60

F2x = 22 N

F2y = F2 sin θ2

F2y = 44 × sin 60

F2y = 38.11 N

Thus, the resultant of the x component is;

F3x = F1x + F2x

F3x = 0 + 22

F3x = 22 N

The resultant of the y component is;

F3y = F1y + F2y

F3y = 33 + 38.11

F3y = 71.11 N

Thus, magnitude of resultant of the F3 force is;

F3 = √((F3x)² + (F3y)²)

F3 = √(22² + 71.11²)

F3 = 74.44 N

The direction of the resultant of F3 is;

θ3 = tan^(-1) F3y/F3x

θ3 = tan^(-1) 71.11/22

θ3 = 72.81° in the south direction

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Answer:

When two players are running full speed at each other on a football field they build up their momentum

Answer:

The orbital radius is approximately 42,259 kilometers.

Explanation:

From Newton's Law of Gravitation we find that acceleration experimented by the satellite ([tex]a[/tex]), measured in meters per square second, is defined by:

[tex]a = \frac{G\cdot M}{r^{2}}[/tex] (1)

Where:

[tex]G[/tex] - Gravitational constant, measured in cubic meters per kilogram-square second.

[tex]M[/tex] - Mass of Earth, measured in kilograms.

[tex]r[/tex] - Orbital radius, measured in meters.

By supposing the satellite rotates at constant speed and in a circular path, we find that acceleration is entirely centripetal and can be defined in terms of period, that is:

[tex]\frac{4\pi^{2}\cdot r}{T^{2}} = \frac{G\cdot M}{r^{2}}[/tex]

[tex]4\pi^{2}\cdot r^{3} = G\cdot M\cdot T^{2}[/tex]

[tex]r^{3} = \frac{G\cdot M\cdot T^{2}}{4\pi^{2}}[/tex]

[tex]r = \sqrt[3]{\frac{G\cdot M\cdot T^{2}}{4\pi^{2}} }[/tex]

Where [tex]T[/tex] is period, measured in seconds.

If we know that [tex]G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]M = 5.98\times 10^{24}\,kg[/tex] and [tex]T = 86400\,s[/tex], then orbital radius of the satellite is:

[tex]r = \sqrt[3]{\frac{\left(6.674\cdot 10^{-11}\,\frac{m^{2}}{kg\cdot s^{2}} \right)\cdot (5.98\times 10^{24}\,kg)\cdot (86400\,s)^{2}}{4\pi^{2}} }[/tex]

[tex]r \approx 42.259\times 10^{6}\,m[/tex]

[tex]r \approx 42.259\times 10^{3}\,km[/tex]

The orbital radius is approximately 42,259 kilometers.

Answer:

Acceleration.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

[tex]a = \frac{v - u}{t}[/tex]

Where,

a is acceleration measured in [tex]ms^{-2}[/tex]

v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]

t is time measured in seconds.

The S.I unit for measuring acceleration is meters per seconds square (m/s²).

Hence, 10 m/s^2 is an example of acceleration.